Volunteers at Sams school use some of the student councils savings for a special project. They buy 7 backpacks for $8 each and fill each backpack with paper and pens that cost $5. By how much did the student councils savings change because of this project

Answers

Answer 1

7 backpacks for $8 = $56

7 lots of paper and pens for $5 each = $35

56 + 35 = $91

The student Council savings decreased by $91.

Related Questions

Which of the follow is NOT equivalent to -9-8
A. -9+-8
B. -8+-9
C. -17
D. -8-9

Answers

I think the answer is E) neither

A. -9+8=-1
B: -8-9=-17
C: -17
D. -8-9=-17
Answer is A, because -9+8=-1.

What is the LCM of 4,8,14?

Answers

The LCM of 4,8,14 is 56

M of 4 are 4,8,12,16,20,24,28,32,36,40,44,48,52,56
M of 8 are 8,16,32,48,56,64
M of 14 are 14,28,42,56

I hope this helps you

Answer:

The LCM of 4, 8, and 14 = 56

Step-by-step explanation:

Find and list multiples of each number until the first common multiple is found. This is the lowest common multiple.

Multiples of 4:

4, 8, 12, 16, 20, 24, 28, 32, 36, 40, 44, 48, 52, (56), 60, 64

Multiples of 8:

8, 16, 24, 32, 40, 48, (56), 64, 72

Multiples of 14:

14, 28, 42, (56), 70, 84

Hope this helps!

What relationship do the ratios of Sin X and Cos y share ?

Answers

https://brainly.com/question/6360856

The sine of the measure of an angle in a right triangle, is the ratio of the opposite side of that angle, to the hypotenuse.

The cosine of the measure of an angle in a right triangle, is the ratio of the adjacent side of that angle, to the hypotenuse.

According to these, we have:

[tex]\displaystyle{ \sin(x^{\circ})= \frac{6}{10} [/tex]

and

[tex]\displaystyle{ \sin(y^{\circ})= \frac{6}{10} [/tex].

Thus, the ratios of both are identical [tex]( \frac{6}{10} \ and \ \frac{6}{10} )[/tex]

The ratios of sin (x) and cos (y) are both identical [tex](\frac{6}{10}\; and\; \frac{6}{10})[/tex].

RIGHT TRIANGLE

A triangle is classified as a right triangle when it presents one of your angles equal to 90º. A math tool applied for finding angles or sides in a right triangle is trigonometric ratios.

The main trigonometric ratios are:

[tex]sin(\alpha )=\frac{opposite\;side}{hypotenuse} \\ \\ cos(\alpha )=\frac{adjacent\;side}{hypotenuse}\\ \\ tan(\alpha )=\frac{sin (\alpha )}{cos(\alpha } =\frac{opposite\;side}{adjacent\;side}[/tex]

The question asks the sin x and cos y, for solving this you should apply the trigonometric ratios. Therefore,

[tex]sin (x)=\frac{opposite\; side}{hypotenuse} =\frac{6}{10}[/tex]

and

[tex]cos (y)=\frac{adjacent\; side}{hypotenuse} =\frac{6}{10}[/tex]

Learn more about trigonometric ratios here:

brainly.com/question/11967894

#SPJ5

What value of x makes the equation below true?

6x - 9 = 39

A. 13

B. 5

C. 8

D. 24

Answers

The answer is C. eight

6x - 9 = 39
6x = 48
x = 8

hope this helps , give brainliest

3 divided by what equals 5

Answers

It’s 0.6 because temper three can’t equally go into five.

3 divided by what equals 5
1st step: Write this as an algebraic equation
3/x=5
2nd step: Multiply by x on both sides
3=5x
3rd step: Divide both sides by 5
3/5=x
So your answer is 3/5 or 0.6

A keycode must contain 2 letters and 3 numbers. The letters may be any letter of the alphabet. The numbers should be any number from 0 to 9. How many different keycode combinations are there?

Answers

The English alphabet contains 26 letters (a, b, c, ...y, z).

The digits from 0 to 9 are a total of 10.

A keycode contains 2 letters, and 3 numbers, for example:

AB 598; MM 139; NT 498; ...

So there are 26 possible choices for the first letter, which can combined with any of the 26 possible choices for the second letter, so there are a total of

26*26=676 possible pairs of letters.

Similarly, the 10 possible choices for the first number, which can be combined with the 10 possible choices for the second number, and the 10 possible choices for the third number make a total of :

10*10*10=1,000 possible triples of numbers.

Any of the 676 possible pairs of letters can be combined with any of the possible 1,000 triples of numbers. This makes a total of

676*1,000=676,000 keycodes.

Answer: 676,000

Answer:

There is 676,000 combinations

Step-by-step explanation:

VOTE ME FOR BRAINILEST

How many terms are in the arithmetic sequence 7, 0, −7, . . . , −175?

Answers

so hmmm 7, 0, -7.... what the dickens is going on? hmmm is really dropping each time by 7, so, 7-7, 0, and 0-7, -7 and so on.

so, the "common difference" is then -7, and our first term is 7, now, who's -175? let's check.

[tex]\bf a_n=a_1+(n-1)d\qquad \begin{cases} n=n^{th}\ term\\ a_1=\textit{first term's value}\\ d=\textit{common difference}\\ ----------\\ d=-7\\ a_1=7\\ a_n=-175 \end{cases} \\\\\\ -175=7+(n-1)(-7)\implies -175=7+7-7n \\\\\\ 7n=14+175\implies 7n=189\implies n=\cfrac{189}{7}\implies n=\stackrel{terms}{27}[/tex]

A grey squirrel population was introduced in a certain county of Great Britain 35 years ago. Biologists observe that the population doubles every 7 years, and now the population is 60,000.
(a) What was the initial size of the squirrel population?

Answers

if this occurred over a span of 35 years and the population doubles every 7 years, we can divide 35 by 7 to find how many times the population has doubled, which would be 5 times. If we divide 60,000 by 2 (or multiply by 1/2) 5 times, you would get the answer, which would be 1,875.

Final answer:

To find the initial size of the grey squirrel population, we used the exponential growth formula. After calculating, we determined that the initial population size was 1,875 squirrels.

Explanation:

The student asked how to find the initial size of a grey squirrel population that doubles every 7 years and now has a population of 60,000 after 35 years.

To calculate the initial population size, we'll use the formula for exponential growth: P(t) = P0 × (2t/T), where P(t) is the population at time t, P0 is the initial population size, 2 is the base because the population doubles, t is the number of years, and T is the time it takes for the population to double.

The problem gives us 35 years (t) and a doubling time (T) of 7 years. Plugging these into the equation, we have 60,000 = P0 × (235/7). Simplifying, we get 60,000 = P0 × 25 or 60,000 = P0 × 32. Dividing both sides by 32, we find the initial population size is 1,875 squirrels.

Thus, the initial size of the grey squirrel population was 1,875.

Tammy's take-home pay is $800 a month. She spends 7% of her take-home pay on her cell phone bill. How much is Tammy's monthly cell phone bill? A. $76 B. $69 C. $56 D. $109

Answers

56$ hope that helped also.......................

Answer:56

Step-by-step explanation:

During strenuous exercise, an athlete can burn 12 calories per minute on a treadmill and 8.5 calories per minute on an elliptical machine. If an athlete uses both machines and burns 325 calories In a 30- minute workout, how many minutes does the athlete spend on each machine?

Answers

Hope it helps 10 mins on the elliptical and 12 on the treadmil

The athlete spends 20 minutes on the treadmill and 10 minutes on the elliptical machine. This is determined by setting up and solving a system of linear equations based on the calorie burn rate of each machine and the total calories burned during the workout.

To solve the problem of how many minutes an athlete spends on each machine during their workout, we must set up a system of linear equations. The athlete burns 12 calories per minute on a treadmill and 8.5 calories per minute on an elliptical machine. In a 30-minute workout, the athlete burns a total of 325 calories. Let's denote the time spent on the treadmill as t minutes and the time spent on the elliptical machine as e minutes.

The total time spent on both machines is 30 minutes: t + e = 30The total calories burned is 325: 12t + 8.5e = 325

We now have two equations and two unknowns, which can be solved simultaneously.

Subtract the second equation from 12 times the first equation to eliminate eSolve the resulting equation for t to find the number of minutes on the treadmillSubstitute the value of t in the first equation to find the number of minutes on the elliptical machine

Using these steps, we find that:

12t + 12e = 360 (by multiplying the first equation by 12)12t + 8.5e = 325 (second equation as is)Subtracting these equations, we get 3.5e = 35Solving for e, we find that e = 10 (the athlete spends 10 minutes on the elliptical machine)Plugging e = 10 into the first equation, we find that t = 20 (the athlete spends 20 minutes on the treadmill)

Therefore, the athlete spends 20 minutes on the treadmill and 10 minutes on the elliptical machine during their 30-minute workout.

suppose you have 192 marbles in groups of 15 marbles each. find the number of groups of marbles that you have. write the quotient with the remainder written as a fraction. explain what the fraction part of your answer means

Answers

192 ÷ 15 = 12 and 8/10 (simplified: 4/5)
the fraction ia there because ( i think) 8 people have one less marble

Expanded form of 6985062 using exponential notation

Answers

6,000,000 +900,000 +80,000 +5,000 +0 +60 +2

[tex] \frac{dx}{dt} = \frac{t^{2}+3tx+ x^{2} }{ t^{2} } [/tex]

Answers

[tex]\dfrac{\mathrm dx}{\mathrm dt}=\dfrac{t^2+3tx+x^2}{t^2}[/tex]
[tex]\dfrac{\mathrm dx}{\mathrm dt}=1+\dfrac{3x}t+\dfrac{x^2}{t^2}[/tex]

Let [tex]x(t)=ty(t)[/tex], so that [tex]\dfrac{\mathrm dx}{\mathrm dt}=t\dfrac{\mathrm dy}{\mathrm dt}+y[/tex].

[tex]t\dfrac{\mathrm dy}{\mathrm dt}+y=1+3y+y^2[/tex]
[tex]t\dfrac{\mathrm dy}{\mathrm dt}=1+2y+y^2=(1+y)^2[/tex]
[tex]\dfrac{\mathrm dy}{(1+y)^2}=\dfrac{\mathrm dt}t[/tex]
[tex]\implies-\dfrac1{1+y}=\ln|t|+C[/tex]
[tex]\implies y+1=-\dfrac1{\ln|t|+C}[/tex]
[tex]\implies yt=x=-t-\dfrac t{\ln|t|+C}[/tex]

What is the product in simplest form?

−89⋅56

Answers

The product would be -4984.

The answer in siplest form is -

Are the functions linear or nonlinear? Column A Column B 1. 72 = x3 + y 2. y + 1 = 5(x – 9) 3. 7y + 2x = 12 4. 4y = 24 A. linear B. nonlinear

Answers

A linear function is given in the form [tex]y = mx + c[/tex] where [tex]m[/tex] and [tex]c[/tex] are both constant

Function 1:

72 = x³ + y ⇒ rearranging to make 'y' the subject we have
y = -x³ + 72
This function has 'x³' not 'x', so this function is non-linear
---------------------------------------------------------------------------------------------------------------

Function 2:

y + 1 = 5(x - 9) ⇒ Multiplying out and simplify like terms
y + 1 = 5x - 45
y = 5x - 45 - 1
y = 5x - 46
This form is exactly the same with y = mx + c so the function is a linear function
----------------------------------------------------------------------------------------------------------------

Function 3

7y + 2x = 12
7y = 12 - 2x
7y = -2x + 12
y = ⁻²/₇ x + ¹²/₇

This function does follow the form of linear function so it is a linear function
------------------------------------------------------------------------------------------------------------

Function 4

4y = 24
y = 24/4
y = 6

This function does not have the 'x' term, it means the function is non-linear

Answer:

72=x3+y: nonlinear

y+1=5(x−9): linear

7y + 2x = 12: linear

4y = 24: linear

I know because I took the k12 test.

Divide (67 gallons 2 quarts)÷3

A) 21 gallons 1 quart
B) 22 gallons 3 quart
C) 21 gallons 3 quart
D) 22 gallons 1 quart
E) NONE

Answers

the answer is e none of the above

E) None is correct.

To solve this problem, we need to divide the total volume of 67 gallons 2 quarts by 3.

Convert the total volume to only quarts since both gallons and quarts are involved in the problem. There are 4 quarts in a gallon.

67 gallons = 67 * 4 quarts = 268 quarts

Add the additional 2 quarts: 268 quarts + 2 quarts = 270 quarts

Divide the total quarts by 3 to find the result:

270 quarts ÷ 3 = 90 quarts

Convert the result back to gallons and quarts. Since there are 4 quarts in a gallon:

90 quarts ÷ 4 = 22 gallons with a remainder of 2 quarts

Find the minimum length of u × v when u = 5 j and v is a position vector of length 4 in the xy-plane.

Answers

length 8 that starts atthe origin and rotates in the xy-plane. Find the maximumand minimum values of the length of the vector u× v.

a woman walks in and steals 100 from a register. 5 minutes later uses the same 100 to buy merchandise from that same store and buys 70 worth of merchandise with that same 100. he gives her 30 in change. how much did the store lose

Answers

she took 100, the store has - 100
she went back and bough
70 bucks in stuff, the store has - 70

yes, she took the $100 bill and gave it, got back $30, that means she only kept $30 from the original bill.

the store however, lost the original $100 bill plus the $70 in merchandise, so they have -$170.

Solve the equation. What does “m” equal?

Answers

The answer is on the paper as an attachment.

Factor the polynomial. x2 - 6x + 9 A) (x - 9)(x - 1) B) (x - 3)(x + 3) C) (x + 9)(x + 1) D) (x - 3)(x - 3)

Answers

x² - 6x +9
x -3
x -3

D) (x - 3) (x -3) is your answer

To check, do your FOIL
x(x) = x^2
x(-3) = -3x
-3(x) = -3x
-3(-3) = 9
x^2 -6x +9 True

hope this helps

Hello there!

[tex]x^2 -6x+9 =(x-3)(x-3) The correct answer is option D[/tex]

-----------------
I added a picture that will help you in the future and I recommend you to memorize them. At least, write them in your notebook.

~Credit to google image~

5836197 to the nearest hundred

Answers

5836200 because it's rounded

The answer to the question is 5,836,200

What is the simplified expression for the expression below? 1/2(8x+4)+1/3(9-3x)

Answers

1/2(8x + 4) + 1/3(9 - 3x)

Simplify.

4x + 2 + 3 - x

Combine like terms.

(4x - x) + (2 + 3)

Simplify.

3x + 5

~Hope I helped!~

Answer:

3x + 5

Step-by-step explanation:

Jenny drove 1,255 miles last week. She drove 187 miles on Monday. On Tuesday, she drove 53 more miles than on Monday, on Wednesday she dove 26 more miles than on Tuesday. How many more miles did Jenny drove on Monday and tuesday together than on Wednesday and Thursday together?

Answers

The answer should be 401

If x2 - 4 = 45, then x could be equal

Answers

Here is your answer: First write the equation: x2-4=45 Then add 4 on both sides: 45+4=49 x2=49 Then divide two on each side: 49/2=24.5 =24.5

The answer would be 24 I believe

"example 1: the radius of a circle is 3 inches. what is the area?"

Answers

= 28.26 in thats your answer

A pro shop in a bowling center decreases the price of a urethane bowling ball by 22% to a sale price of $88.14. What is the former price

Answers

88.14/.78=$113 is you Answer

1x - .22x = 88.14
.78x = 88.14

divide by .78 x = 113

The bird house in your friend's yard casts a shadow that is 14 feet long. Your friend is 5 feet tall and casts a shadow that is 3.5 feet long. What is the height of the bird house?

Answers

3.5/5=14/x 20ft tall

How much greater is the area of a square with a side length of 9 inches than the area of a circle with a radius of 3 inches?

Answers

The area of the square is 81 sq in, and the area of the circule is (3.14)(3 in)^2, or approx 3.14(9) sq in, or approx 28.27 sq in.

Subtract: 81 sq in - 28.27 sq in = approx. 52.73 sq in.

The difference is 52.73 sq in; the square is larger, the circle smaller.

Find the ratio and simplify. In this triangle, find the ratio of the shortest side to the longest. A triangle has three sides with lengths 15.2, 5.6, 14.1

Answers

well, the shortest will be 14.1 clearly, and the longest of all three is 15.2.

let's check the ratio from shortest to longest.

[tex]\bf 14.1\implies \cfrac{141}{10}\qquad \qquad\qquad 15.2\implies \cfrac{152}{10} \\\\\\ \cfrac{shortest}{longest}\qquad 14.1:15.2\qquad \cfrac{14.1}{15.2}\implies \cfrac{\quad \frac{141}{10}\quad }{\frac{152}{10}}\implies \cfrac{141}{10}\cdot \cfrac{10}{152} \\\\\\ \cfrac{141}{152}[/tex]

A section of a roller coaster track forms a parallelogram ABCD. If m∠ABC = 72°, what is m∠DAB? A) 72° B) 108° C) 144° D) 216°

Answers

check the picture below.

Answer: Option 'B' is correct.

Step-by-step explanation:

Since we have given that

A section of a roller coaster track forms a parallelogram ABCD.

If m∠ABC = 72°

We need to find the m∠DAB,

Since ABCD is a parallelogram .

So, "Sum of interior angles on the same side is supplementary":

[tex]m\angle ABC+m\angle DAB=180\textdegree\\\\72\textdegree+m\angle DAB=180\textdegree\\\\m\angle DAB=180\textdegree-72\textdegree\\\\m\angle DAB=108\textdegree[/tex]

Hence, Option 'B' is correct.

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