One part of a freely swinging magnet always points
a. east.
b. to Earth’s geographic north pole.
c. toward Earth’s core.
d. to Earth’s magnetic pole in the Northern Hemisphere.

Answer:

1.5x10^8

Explanation:

The characteristics of series circuits, we can find that the current in the two resistances the same, the answer is:

Electric circuits are a system formed by resistors, capacitors and coils, through which the electric current flows, these circuits can be classified:

In this case it is indicated that we have a series circuit, for which all the current must flow through the path, consequently all the current of the circuit must pass through the two resistors.

In conclusion, using the characteristics of series circuits, we find that the current in the two resistances the same, the answer is:

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The Earth's soft putty-like Asthenosphere carries the Lithosphere (which is like a giant jig-saw puzzle fit around the Earth), and the giant continents on its back.

Lithosphere floats on the top of Asthenosphere

The earth crust is made up of tectonic plates and these tectonic plates are always in flow. Together the earths crust and mantle beneath it is called lithosphere. On the other hand the area beneath the mantle is called the asthenosphere. Actually lithosphere is solid in nature and asthenosphere is semi solid or liquid nature. The lithosphere floats on the asthenosphere.

McCarthyism refers to the practice of making accusations of subversion or treason without proper regard for evidence.

It also refers to the use of unfair investigatory or accusatory methods in order to suppress opposition or stifle political dissent. The term originates from the actions of U.S. Senator Joseph McCarthy, particularly in the years 1950 to 1954, when he was chairman of the Senate Permanent Subcommittee on Investigations.

During this time, McCarthy became the most visible public face of a period of intense anti-communist suspicion inspired by the tensions of the Cold War. His controversial and aggressive tactics, which included public accusations of disloyalty and treason without substantial evidence, led to the term McCarthyism being coined to describe such behavior.

The term has since taken on a broader meaning, not confined to the historical context of McCarthy's activities, and is used to describe demagogic, reckless, and unsubstantiated accusations, as well as guilt by association and the harassment of political opponents.

Given

Weight of the block A, Wa = 20 lb, weight of block B Wb = 50 lb. Applied force to block A, P = 6lb, coefficient of static friction µs = 0.4, coefficient of kinetic friction µk = 0.3. If a force P is applied to the body, no relative motion will take place until the applied force is equal to the force of friction Ff, which is acting opposite to the direction of motion. Magnitude of static force of friction between block A and block B, Fs = µsN, where N is reaction force acting on block A. Now, resolve the forces Fx = max. P = (mA + mB)a,

6 = (20 / 32.2 + 50 / 32.2)a

2.173a = 6

A = 2.76 ft/s^2

To check slipping occurs between block A and block B, consider block A:

P – Ff = mAaA

6 – Ff = 1.71

Ff = 4.29 lb

And also,

N = wA. We know static friction,

Fs = µsN

Fs = 0.4 x 20

Fs = 8lb

Frictional force is less than static friction. Ff < Fs

Therefors, acceleration of block A, aA = 2.76 ft/s^2, acceleration of block B aB = 2.76 ft/s^2

Between blocks 'a' and 'b', the coefficients of friction come into play. If the force transmitted from block 'b' to 'a' is greater than the maximum static friction, block 'a' will move and its acceleration can be calculated.

The smooth surface implies there is no friction between block 'b' and the surface. However, there is friction between blocks 'a' and 'b'. Hence, the given coefficients of static and kinetic friction, μs = 0.4 and μk = 0.3 would apply there. If the force 'p' was applied to block 'b', since there is no friction between 'b' and the surface, 'b' would move freely with acceleration a = F/m (F: applied force, m: mass of the block).

For block 'a', the acceleration would depend on whether the frictional force is able to resist the force being applied through block 'b'. The static friction is given by μs * N (N: Normal force - equal to the weight of block 'a' in this case), which has to be overcome to set the block motion. Once it starts moving, kinetic friction, given by μk * N, comes into effect. If the force transmitted from block 'b' to 'a' is greater than the maximum static friction, block 'a' will start to move and its acceleration can be calculated by subtracting the kinetic friction from the transmitted force and dividing by the mass of block 'a'.

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The loudness of a sound is related to the amplitude of the sound wave. The correct answer is amplitude and the correct option is option (4).

Amplitude refers to the maximum displacement of particles in a medium from their rest position as a sound wave passes through it. In simpler terms, it measures the strength or intensity of the sound wave. A larger amplitude corresponds to a louder sound, while a smaller amplitude corresponds to a softer sound.

Wavelength, frequency, and velocity are other properties of sound waves, but they are not directly related to the loudness of the sound.

Wavelength is the distance between two consecutive points in a sound wave, frequency represents the number of complete cycles of the wave that occur in one second (measured in hertz), and velocity is the speed at which the sound wave travels through a medium. These properties can affect other characteristics of the sound wave, such as pitch or timbre, but they do not directly determine the loudness.

Therefore, The loudness of a sound is related to the amplitude of the sound wave. The correct answer is amplitude and the correct option is option (4).

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Superman must apply a horizontal force of approximately 4963.33 N to the boulder to achieve the desired acceleration of 12.8 m/s^2. This calculation is based on the weight of the boulder and the given acceleration due to gravity.

To determine the horizontal force that Superman must apply to the boulder to achieve the given horizontal acceleration, we first need to calculate the mass of the boulder. Since the weight of the boulder (W) is given by the formula W = mg, where m is the mass of the boulder, g is the acceleration due to gravity (9.80 m/s2), and W is the weight (3800 N), the mass of the boulder (m) can be calculated as follows:

m = W / g = 3800 N / 9.80 m/s2 = 387.76 kg (rounded to two decimal places).

Now that we know the mass, we can find the horizontal force (F) needed to achieve the horizontal acceleration (a) using Newton's second law, F = ma. Substituting the known values results in:

F = m * a = 387.76 kg * 12.8 m/s2 = 4963.33 N.

So, Superman must apply a horizontal force of approximately 4963.33 N to provide the boulder with the desired acceleration of 12.8 m/s2.

The relationship between acceleration, velocity and radius is given as:

a = v^2 / r

Since we are given a diameter of 45 m, hence the radius is 22.5 m.

a = (16 m/s)^2 / 22.5 m

a = 11.38 m/s^2

In 2 significant figures:

a = 11 m/s^2

A greyhound running around a semicircular racetrack at a constant speed is experiencing centripetal acceleration due to its changing direction, which, in this case, is approximately 5.71 m/s² or 0.58g.

A greyhound running around a semicircular racetrack at a constant speed is not accelerating in the linear sense. However, because its direction is continually changing, it is experiencing centripetal acceleration. Centripetal acceleration can be calculated by the formula a = v^2/r, where v is the speed, and r is the radius of the circular path. Plugging in the given values, we obtain an acceleration of approximately 5.71 m/s²

To find the acceleration in units of g, we need to divide this value by the acceleration due to gravity, which is approximately 9.80 m/s². Therefore, the dog's acceleration is approximately 0.58g. In conclusion, the greyhound experiences a centripetal acceleration of about 5.71 m/s², which is equivalent to 0.58g, when it is running around the turns at the given speed.

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We can answer this question by looking at Newton's second law:

[tex]F=ma[/tex]

which can be rewritten as

[tex]a=\frac{F}{m}[/tex]

where F is the force experienced by the rocket, m is its mass, a is its acceleration. In the rocket's case, the mass of the rocket decreases (because the fuel in the tank decreases), while the force remains constant, so the ratio F/m increases, and therefore the acceleration of the rocket increases.

Therefore, the correct answer is

D - The acceleration increases because the mass decreases.

The total resistive force against the car, boat, and trailer is 910 N. The force experienced in the hitch between the car and the trailer is 728 N.

This is a classic problem that involves applying Newton's second law and the concept of net force. Newton's second law states that Force = mass * acceleration. Let's begin with the first part of the question.

Given that the car has a mass of 1100 kg and it accelerates at 0.550 m/s2, and uses a force of 1900 N, we realize that this force is not just accelerating the car, but also overcoming some resistance. The total force exerted by the car is the sum of the force to overcome the resistance and the force to accelerate both the car and the trailer. We calculate this total force as follows:

Force_moving = (Mass_car + Mass_trailer) * Acceleration

Force_moving = (1100 kg + 700 kg) * 0.550 m/s2

Force_moving = 990 N

The resistive force then is the difference between the force the car exerts on the road and the force needed to move: Force_resistance = Force_exerted – Force_moving = 1900 N – 990 N = 910 N

In the second part of the question, we’re asked to figure out the force in the hitch between the car and the trailer, if 80% of the resisting forces are experienced by the boat and trailer. We simply take 80% of the resisting force:

Force_hitch = 0.80 * Force_resistance = 0.80 * 910 N = 728 N

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The total resisting force to the motion of the car, boat, and trailer is 910N. The force in the hitch between the car and the trailer, experiencing 80% of the resisting force, is 728N.

The subject of this question pertains to Newton's Second Law of Motion, which states that the acceleration of an object is directly proportional to the net force acting on it and inversely proportional to its mass.

(a) We can use this equation to calculate the total a total force that resists the motion of the car, boat, and trailer: F = ma. Here, F is the net force, m is the total mass (car + boat + trailer), and a is the acceleration. Plugging in the given values (F = (1100kg + 700kg) * 0.550m/s²), we find the net force is 990 N. Since the car is exerting a force of 1900 N, the force resisting the motion can be found by subtracting this net force from the force exerted by the car (1900N - 990N), which gives 910 N.

(b) If 80% of the resisting forces are experienced by the boat and trailer, then the force on the hitch would be 80% of the total resisting force, i.e., 0.8 * 910 N = 728 N.

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Final answer:

The work done by the force can be calculated using the formula: Work = Force * Distance. The magnitude of the force can be found using trigonometry, and then the work is calculated by multiplying the force by the distance moved. The work done by the force ƒ is 15.32 Joules.

Explanation:

The work done by the force ƒ can be calculated using the formula:

ƒ = Fd

where F is the magnitude of the force and d is the distance moved. In this case, the force ƒ is equal to the horizontal component of the applied force. We can find this component using trigonometry:

ƒ = Fcosθ

where θ is the angle between the force and the horizontal direction. Substituting the given values, we have:

ƒ = (20 N)cos(59.9°)

ƒ = (20 N)(0.539)

ƒ = 10.78 N

Now we can calculate the work done by the force ƒ using the formula:

Work = ƒd

where d is the distance moved. In this case, the distance moved is 1.42 m. Substituting the values, we have:

Work = (10.78 N)(1.42 m)

Work = 15.32 J

Therefore, the work done by the force ƒ is 15.32 Joules.

To find the period of a wheel that rotates 5.75 times per second, use the formula T = 1/f, resulting in a period of 0.174 seconds.

To find the period of the motion for a wheel that rotates 5.75 times every second, we can use the relationship between frequency (f) and period (T). The frequency is the number of revolutions per second, which we're given as 5.75 revolutions per second. The period is the time it takes to complete one revolution. The formula that relates frequency and period is T = 1/f.

Plugging in the given frequency:

T = 1/5.75

Calculating this gives us:

T = 0.174 s

Therefore, the period of this motion, which is the time it takes the wheel to make one complete revolution, is 0.174 seconds.

The equation relevant to use here is:

v^2 = v0^2 + 2 a d

where,

v is final velocity = ?

v0 is intial velocity = 193.8 m/s

a is acceleration = 13.5 m/s^2

d is distance = 2370 m

v = sqrt [193.8^2 + 2 (13.5) 2370]

v = 318.67 m/s

Magnitudes of vector e max and vector b max for electromagnetic waves at top of the Neptune's atmosphere are 23.76V/m and 17.92×10⁻⁸ T respectively.

The magnetic field is the field in the space and around the magnet in which the magnetic field can be filled.

The maximum magnetic field experienced at the top of the Neptune's atmosphere can be given as,

[tex]B_{max}=\sqrt\dfrac{2\mu_oI}{c}[/tex]

Here, (μ₀) vacuum permeability, (I) is the intensity, and (c) speed of light in vacuum.

As the sun delivers an average power of 1.499 w/m2 to the top of Neptune's atmosphere. Thus, the b max is,

[tex]B_{max}=\sqrt{\dfrac{4\pi\times10^{-7}\times1.499}{3\times10^8}}\\B_{max}=7.92\times10^{-8}[/tex]

Now the value of E max is,

[tex]E_{max}=B_{max}\times c\\E_{max}=7.92\times10^{-8}\times 3\times10^{8}\\E_{max}=23.76\rm\; V/m[/tex]

Thus, the magnitudes of vector e max and vector b max for electromagnetic waves at the top of the atmosphere are 23.76V/m and 17.92×10⁻⁸ T respectively.

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The planet's orbital distance is approximately 0.028 astronomical units (AU).

The orbital distance of a planet can be calculated using Kepler's Third Law. Kepler's Third Law states that the square of the orbital period of a planet is proportional to the cube of its average distance from the Sun. In this case, the planet has an orbital period of 63 days, which is approximately 0.1726 years. The sun's mass is approximately 1 solar mass. We can use these values to solve for the planet's orbital distance.

Using the formula for Kepler's Third Law, we have:

T^2 = (4*pi^2*a^3)/G*M

Where T is the orbital period, a is the orbital distance, G is the gravitational constant, and M is the mass of the Sun.

Plugging in the values we have:
T^2 = (4*pi^2*a^3)/(6.67430 × 10^-11 m^3 kg^-1 s^-2 * 1 solar mass)

Simplifying the equation, we can solve for a:
a^3 = (T^2 * G * M)/(4*pi^2)

Taking the cube root of both sides, we find:
a = ((T^2 * G * M)/(4*pi^2))^(1/3)

Let's plug in the values:
a = ((0.1726^2 * 6.67430 × 10^-11 m^3 kg^-1 s^-2 * 1 solar mass)/(4*pi^2))^(1/3)

a ≈ 0.028 AU

Therefore, the planet's orbital distance is approximately 0.028 astronomical units (AU).

Answer:

Golgi apparatus.

Explanation:

The driver's average speed up to that point in the journey is 90 km/h, calculated by dividing the distance traveled, 270 km, by the time spent, 3 hours.

To find the driver's average speed at a given point during the trip, we divide the total distance traveled by the total time spent traveling. In this case, the driver has traveled 270 km in 3 hours. Using the formula for average speed, which is average speed = total distance / total time, we can calculate the average speed as follows:

average speed = 270 km / 3 hours = 90 km/h.

Therefore, the driver's average speed at this point in the journey is 90 km/h. This calculation doesn't take into account the remaining distance to the destination, which is 150 km away.