graph of the quadratic function f(x)=‒(x+4)(x‒6) is shown on the coordinate grid below.
Which statement is not true?
A.
The maximum of this function occurs when y=25.
B.
The function increases in the interval 1 to 6.
C.
The has a zero at (‒4,0).
D.
The function positive in the interval ‒4 to 6.
Answers
Answer:
Option B is not true.
Step-by-step explanation:
The quadratic function is f(x) = -(x + 4)(x - 6)
Now we check each option given
Option A.
It is clear from the graph function is maximum at y = 25.
TRUE.
Option B.
Function increases in the interval 1 to 6.
Let's check this at x = 2 and x = 3
f(2) = -(2 + 4)(2 - 6)
= -(6)(-4)
= 24
f(3) = -(3 + 4)(3 - 6)
= - (7)(-3)
= 21
So we find this function is decreasing in this interval.
So the given option is FALSE.
Option C.
The function has a zero at (-4, 0)
f(-4) = -(-4 + 4)(-4 + 6) = 0
So the function has a zero at (-4, 0).
Option is True.
Option D.
The function is positive in the interval -4 to 6
f(x) = -(x + 4)(x - 6)
f(-3) = -(-3 + 4)(-3 - 6)
= -(1)(-9)
= 9
f(0) = -(0 + 4)( 0 - 6)
= 24
Therefore, this function is positive in this interval so the option is TRUE.
Option B is not true.
Related Questions
What percent is 6 out of 30? 2% 6% 20% 30%
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family drinks 1 3/4 gallons of milk every 4 1/2 days what is the unit rate of milk per day
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which gives us a quotient of about 0.39 gallons of milk for one day.
Michael sold his house for $548,900, which was 160% of the amount he paid for it. Calculate the amount he paid for the property.
Answers
45+5/6x=50
need to find x and math for x
Answers
5/6x = 50 - 45
5/6x = 5
5x = 5 * 6
5x = 30
x = 6
hope that helps, God bless!
The solution of expression is, x = 6
We have to give that,
An expression to simplify as,
⇒ 45 + 5/6x = 50
Now, Simplify the expression by combining like terms,
⇒ 45 + 5/6x = 50
Subtract 45 on both sides,
⇒ 45 + 5/6x - 45 = 50 - 45
⇒ 5/6x = 5
Multiply by 6 on both sides,
⇒ 5x = 5 × 6
⇒ 5x = 30
Divide by 5 on both sides,
⇒ x = 30/5
⇒ x = 6
So, The solution is, x = 6
To learn more about the mathematical expression visit:
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What relationship do the ratios of Sin X and Cos y share ?
Answers
The sine of the measure of an angle in a right triangle, is the ratio of the opposite side of that angle, to the hypotenuse.
The cosine of the measure of an angle in a right triangle, is the ratio of the adjacent side of that angle, to the hypotenuse.
According to these, we have:
[tex]\displaystyle{ \sin(x^{\circ})= \frac{6}{10} [/tex]
and
[tex]\displaystyle{ \sin(y^{\circ})= \frac{6}{10} [/tex].
Thus, the ratios of both are identical [tex]( \frac{6}{10} \ and \ \frac{6}{10} )[/tex]
The ratios of sin (x) and cos (y) are both identical [tex](\frac{6}{10}\; and\; \frac{6}{10})[/tex].
RIGHT TRIANGLEA triangle is classified as a right triangle when it presents one of your angles equal to 90º. A math tool applied for finding angles or sides in a right triangle is trigonometric ratios.
The main trigonometric ratios are:
[tex]sin(\alpha )=\frac{opposite\;side}{hypotenuse} \\ \\ cos(\alpha )=\frac{adjacent\;side}{hypotenuse}\\ \\ tan(\alpha )=\frac{sin (\alpha )}{cos(\alpha } =\frac{opposite\;side}{adjacent\;side}[/tex]
The question asks the sin x and cos y, for solving this you should apply the trigonometric ratios. Therefore,
[tex]sin (x)=\frac{opposite\; side}{hypotenuse} =\frac{6}{10}[/tex]
and
[tex]cos (y)=\frac{adjacent\; side}{hypotenuse} =\frac{6}{10}[/tex]
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Caroline bought 20 shares of stock at 10 ½, and after 10 months the value of the stocks was 11 ¼. If Caroline were to sell all her shares of this stock, how much profit would she make? A. $210 B. $10 C. $15 D. $225
Answers
20 shares at 11 1/4 (or 11.25) = 20 * 11.25 = 225
so the profit made would be : 225 - 210 = $ 15 <==
A section of a roller coaster track forms a parallelogram ABCD. If m∠ABC = 72°, what is m∠DAB? A) 72° B) 108° C) 144° D) 216°
Answers
Answer: Option 'B' is correct.
Step-by-step explanation:
Since we have given that
A section of a roller coaster track forms a parallelogram ABCD.
If m∠ABC = 72°
We need to find the m∠DAB,
Since ABCD is a parallelogram .
So, "Sum of interior angles on the same side is supplementary":
[tex]m\angle ABC+m\angle DAB=180\textdegree\\\\72\textdegree+m\angle DAB=180\textdegree\\\\m\angle DAB=180\textdegree-72\textdegree\\\\m\angle DAB=108\textdegree[/tex]
Hence, Option 'B' is correct.
Tammy's take-home pay is $800 a month. She spends 7% of her take-home pay on her cell phone bill. How much is Tammy's monthly cell phone bill? A. $76 B. $69 C. $56 D. $109
Answers
Answer:56
Step-by-step explanation:
"example 1: the radius of a circle is 3 inches. what is the area?"
Answers
What is the product in simplest form?
−89⋅56
Answers
The answer in siplest form is -
How many terms are in the arithmetic sequence 7, 0, −7, . . . , −175?
Answers
so, the "common difference" is then -7, and our first term is 7, now, who's -175? let's check.
[tex]\bf a_n=a_1+(n-1)d\qquad \begin{cases} n=n^{th}\ term\\ a_1=\textit{first term's value}\\ d=\textit{common difference}\\ ----------\\ d=-7\\ a_1=7\\ a_n=-175 \end{cases} \\\\\\ -175=7+(n-1)(-7)\implies -175=7+7-7n \\\\\\ 7n=14+175\implies 7n=189\implies n=\cfrac{189}{7}\implies n=\stackrel{terms}{27}[/tex]
Complete each statement regarding an angle θ and its reference angle theta hat using radian measure. (Assume 0 ≤ θ < 2π. Give your answers in terms of θ.) (a) If θ is in QI, then theta hat = . (b) If θ is in QII, then theta hat = . (c) If θ is in QIII, then theta hat = . (d) If θ is in QIV, then theta hat = .
Answers
The reference angle is simply the acute angle between the terminal side and the x-axis
The terminal angles in the four quadrants are
[tex]\bar \theta = \theta[/tex].[tex]\bar \theta = \pi - \theta[/tex].[tex]\bar \theta = \theta - \pi[/tex].[tex]\bar \theta = 2\pi - \theta[/tex]The given parameters are:
[tex]\theta \to[/tex] reference angle
[tex]\bar \theta \to[/tex] terminal angle
(a) If the reference angle is in the first quadrant
In the first quadrant, the x-axis is at [tex]0\ rad[/tex]
So, the terminal angle is:
[tex]\bar \theta = \theta - 0[/tex]
[tex]\bar \theta = \theta[/tex]
(b) If the reference angle is in the second quadrant
In the second quadrant, the x-axis is at [tex]\pi \ rad[/tex],
While the reference angle is between [tex]\frac{\pi}{2}[/tex] and [tex]\pi \ rad[/tex]
It means that, we have to subtract the reference angle from the x-axis
So, the terminal angle is:
[tex]\bar \theta = \pi - \theta[/tex]
(c) If the reference angle is in the third quadrant
Here, the x-axis is still at [tex]\pi \ rad[/tex],
But the reference angle is between [tex]\pi \ rad[/tex] and [tex]\frac{3}{2}\pi[/tex]
It means that, we have to subtract the x-axis from the reference angle.
So, the terminal angle is:
[tex]\bar \theta = \theta - \pi[/tex]
(d) If the reference angle is in the fourth quadrant
Here, the x-axis is at [tex]2\pi \ rad[/tex]
And the reference angle is between [tex]\frac{3}{2}\pi[/tex] and [tex]2\pi \ rad[/tex]
It means that, we have to subtract the reference angle from the x-axis.
So, the terminal angle is:
[tex]\bar \theta = 2\pi - \theta[/tex]
See attachment for illustration of terminal angles
Read more about terminal angles at:
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Final answer:
When dealing with angles in radians and their reference angles, each quadrant has a specific relationship for determining the reference angle based on the given angle θ.
Explanation:
Radian Measure with Reference Angles:
If θ is in QI, then θ hat = θ
If θ is in QII, then θ hat = π - θ
If θ is in QIII, then θ hat = θ - π
If θ is in QIV, then θ hat = 2π - θ
What value of x makes the equation below true?
6x - 9 = 39
A. 13
B. 5
C. 8
D. 24
Answers
6x = 48
x = 8
hope this helps , give brainliest
Find the ratio and simplify. In this triangle, find the ratio of the shortest side to the longest. A triangle has three sides with lengths 15.2, 5.6, 14.1
Answers
let's check the ratio from shortest to longest.
[tex]\bf 14.1\implies \cfrac{141}{10}\qquad \qquad\qquad 15.2\implies \cfrac{152}{10} \\\\\\ \cfrac{shortest}{longest}\qquad 14.1:15.2\qquad \cfrac{14.1}{15.2}\implies \cfrac{\quad \frac{141}{10}\quad }{\frac{152}{10}}\implies \cfrac{141}{10}\cdot \cfrac{10}{152} \\\\\\ \cfrac{141}{152}[/tex]
anyone help me please!
A stereo listed for $350 is on sale for 20% off the list price. The sales tax is 6%. What total price does a customer pay for the stereo if she/he buys it on sale?
1 $324.00
2 $259.00
3 $262.20
4 $296.80
5 $301.00
Answers
then you need add 6% onto the price
Im not sure if youre supposed to calculate 6% of the original price or the price with 20% off
tax of normal price + discounted price= $301
tax of discounted price + discounted price= $296.60
Your answer should be E since $301 is an answer choice
Outlet malls sell goods _____
Answers
1. at a discount
2. add all the items together at their sales cost then add salves tax
3. $26.75
4. $66.23
What is 129,543 rounded to the nearest ten thousand
Answers
hope this helps
3 divided by what equals 5
Answers
1st step: Write this as an algebraic equation
3/x=5
2nd step: Multiply by x on both sides
3=5x
3rd step: Divide both sides by 5
3/5=x
So your answer is 3/5 or 0.6
Jenny drove 1,255 miles last week. She drove 187 miles on Monday. On Tuesday, she drove 53 more miles than on Monday, on Wednesday she dove 26 more miles than on Tuesday. How many more miles did Jenny drove on Monday and tuesday together than on Wednesday and Thursday together?
Answers
Which of the follow is NOT equivalent to -9-8
A. -9+-8
B. -8+-9
C. -17
D. -8-9
Answers
B: -8-9=-17
C: -17
D. -8-9=-17
Answer is A, because -9+8=-1.
[tex] \frac{dx}{dt} = \frac{t^{2}+3tx+ x^{2} }{ t^{2} } [/tex]
Answers
[tex]\dfrac{\mathrm dx}{\mathrm dt}=1+\dfrac{3x}t+\dfrac{x^2}{t^2}[/tex]
Let [tex]x(t)=ty(t)[/tex], so that [tex]\dfrac{\mathrm dx}{\mathrm dt}=t\dfrac{\mathrm dy}{\mathrm dt}+y[/tex].
[tex]t\dfrac{\mathrm dy}{\mathrm dt}+y=1+3y+y^2[/tex]
[tex]t\dfrac{\mathrm dy}{\mathrm dt}=1+2y+y^2=(1+y)^2[/tex]
[tex]\dfrac{\mathrm dy}{(1+y)^2}=\dfrac{\mathrm dt}t[/tex]
[tex]\implies-\dfrac1{1+y}=\ln|t|+C[/tex]
[tex]\implies y+1=-\dfrac1{\ln|t|+C}[/tex]
[tex]\implies yt=x=-t-\dfrac t{\ln|t|+C}[/tex]
What is the simplified expression for the expression below? 1/2(8x+4)+1/3(9-3x)
Answers
Simplify.
4x + 2 + 3 - x
Combine like terms.
(4x - x) + (2 + 3)
Simplify.
3x + 5
~Hope I helped!~
Answer:
3x + 5
Step-by-step explanation:
During strenuous exercise, an athlete can burn 12 calories per minute on a treadmill and 8.5 calories per minute on an elliptical machine. If an athlete uses both machines and burns 325 calories In a 30- minute workout, how many minutes does the athlete spend on each machine?
Answers
The athlete spends 20 minutes on the treadmill and 10 minutes on the elliptical machine. This is determined by setting up and solving a system of linear equations based on the calorie burn rate of each machine and the total calories burned during the workout.
To solve the problem of how many minutes an athlete spends on each machine during their workout, we must set up a system of linear equations. The athlete burns 12 calories per minute on a treadmill and 8.5 calories per minute on an elliptical machine. In a 30-minute workout, the athlete burns a total of 325 calories. Let's denote the time spent on the treadmill as t minutes and the time spent on the elliptical machine as e minutes.
The total time spent on both machines is 30 minutes: t + e = 30The total calories burned is 325: 12t + 8.5e = 325We now have two equations and two unknowns, which can be solved simultaneously.
Subtract the second equation from 12 times the first equation to eliminate eSolve the resulting equation for t to find the number of minutes on the treadmillSubstitute the value of t in the first equation to find the number of minutes on the elliptical machineUsing these steps, we find that:
12t + 12e = 360 (by multiplying the first equation by 12)12t + 8.5e = 325 (second equation as is)Subtracting these equations, we get 3.5e = 35Solving for e, we find that e = 10 (the athlete spends 10 minutes on the elliptical machine)Plugging e = 10 into the first equation, we find that t = 20 (the athlete spends 20 minutes on the treadmill)Therefore, the athlete spends 20 minutes on the treadmill and 10 minutes on the elliptical machine during their 30-minute workout.
How much greater is the area of a square with a side length of 9 inches than the area of a circle with a radius of 3 inches?
Answers
Subtract: 81 sq in - 28.27 sq in = approx. 52.73 sq in.
The difference is 52.73 sq in; the square is larger, the circle smaller.
If x2 - 4 = 45, then x could be equal
Answers
a woman walks in and steals 100 from a register. 5 minutes later uses the same 100 to buy merchandise from that same store and buys 70 worth of merchandise with that same 100. he gives her 30 in change. how much did the store lose
Answers
she went back and bough
70 bucks in stuff, the store has - 70
yes, she took the $100 bill and gave it, got back $30, that means she only kept $30 from the original bill.
the store however, lost the original $100 bill plus the $70 in merchandise, so they have -$170.
A scuba diver swimming at the Deppe shown, and then swim 0.5 feet toward the surface every three seconds. What is the location of the scuba diver, relative to the surface, after 15 seconds?
Answers
after 15 seconds = your answer
3 x 5 = 15
0.5 x 5 = your answer
your answer = 2.5
2.5 is your answer
hope this helps
5836197 to the nearest hundred
Answers
A pro shop in a bowling center decreases the price of a urethane bowling ball by 22% to a sale price of $88.14. What is the former price
Answers
.78x = 88.14
divide by .78 x = 113
Divide (67 gallons 2 quarts)÷3
A) 21 gallons 1 quart
B) 22 gallons 3 quart
C) 21 gallons 3 quart
D) 22 gallons 1 quart
E) NONE
Answers
E) None is correct.
To solve this problem, we need to divide the total volume of 67 gallons 2 quarts by 3.
Convert the total volume to only quarts since both gallons and quarts are involved in the problem. There are 4 quarts in a gallon.
67 gallons = 67 * 4 quarts = 268 quarts
Add the additional 2 quarts: 268 quarts + 2 quarts = 270 quarts
Divide the total quarts by 3 to find the result:
270 quarts ÷ 3 = 90 quarts
Convert the result back to gallons and quarts. Since there are 4 quarts in a gallon:
90 quarts ÷ 4 = 22 gallons with a remainder of 2 quarts