Which iniquality is represented by the graph? If you can do the top ones thanks too:) please show work if there is any:)
Answers
You can treat the sign like an equals sign but remember one rule;
If you ever multiply or divide both sides of the equation by a negative number, swap the sign (if it's ≤, then make it ≥ and vice versa);
So, for the questions above:
29.
-x/2 ≤ -4
-x ≤ -8
x ≥ 8
30.
I'm unsure what's being asked for this question.
31.
For these graphs, just look at whether the direction of the line from its origin (the small circle part) is going up the number line to the larger numbers or towards the smaller (more negative) numbers;
In this case, the line starts at 10 and goes up the number line;
The circle that denotes the start of the line is unshaded, this means the inequality being represented is a > or <, not a ≥ or ≤, which is shown by a circle that is shaded;
Looking at the line (representing x-values) therefore, we can determine the inequality it represents is:
x > 10;
so now we just need to rearrange the options given and see which is the same as x > 10;
In this case it is option A:
x/5 - 6 > -4
x/5 > 2
x > 10
Related Questions
Which choices are real numbers? Check all that apply.
A. (-131072)^1/7
B. (-531441)^1/12
C. (-1024)^1/5
D. (-256)^1/8
Answers
[tex] \sqrt{x} [/tex]
That can be written as
x^(1/2)
...and when you take an even root of a negative number, there is no real answer. (2 is an even number).
Looking at the answer choices here, we can see that B and D use even roots, so they will give non-real answers.
So, A and C are the answer choices to select.
The real numbers are:
A. [tex]\((-131072)^{1/7}\)[/tex]
C. [tex]\((-1024)^{1/5}\)[/tex]
These have odd roots, resulting in real numbers.
To determine which of the given expressions are real numbers, we need to check if the roots of negative numbers are defined within the set of real numbers.
A. [tex]\((-131072)^{1/7}\)[/tex]
The expression [tex]\((-131072)^{1/7}\)[/tex] is the 7th root of [tex]\(-131072\)[/tex]. Since 7 is an odd number, the 7th root of a negative number is defined and is a real number.
So, [tex]\((-131072)^{1/7}\)[/tex] is a real number.
B. [tex]\((-531441)^{1/12}\)[/tex]
The expression [tex]\((-531441)^{1/12}\)[/tex] is the 12th root of [tex]\(-531441\)[/tex]. Since 12 is an even number, the 12th root of a negative number is not defined within the set of real numbers.
So, [tex]\((-531441)^{1/12}\)[/tex] is not a real number.
C. [tex]\((-1024)^{1/5}\)[/tex]
The expression [tex]\((-1024)^{1/5}\)[/tex] is the 5th root of [tex]\(-1024\)[/tex]. Since 5 is an odd number, the 5th root of a negative number is defined and is a real number.
So, [tex]\((-1024)^{1/5}\)[/tex] is a real number.
D. [tex]\((-256)^{1/8}\)[/tex]
The expression [tex]\((-256)^{1/8}\)[/tex] is the 8th root of [tex]\(-256\)[/tex]. Since 8 is an even number, the 8th root of a negative number is not defined within the set of real numbers.
So, [tex]\((-256)^{1/8}\)[/tex] is not a real number.
Summary:
- A. [tex]\((-131072)^{1/7}\)[/tex] is a real number.
- B. [tex]\((-531441)^{1/12}\)[/tex] is not a real number.
- C. [tex]\((-1024)^{1/5}\)[/tex] is a real number.
- D. [tex]\((-256)^{1/8}\)[/tex] is not a real number.
how to factor 6x^2+5x+1
Answers
State whether the given measurements determine zero, one, or two triangles. b = 84°, b = 28, c = 25
Answers
Using the cosine formula:
SinB/b = SinC/c
Sin84°/28 = SinC/25
SinC = (Sin84°)(28)/25
C = 62.6° 0r 117.4°
When B = 84°, it is not possible for C = 117.4°
so, angles of triangles did not exceed 180°
it means there is only one triangle
Help with geometry...
Answers
[tex]\bf \textit{distance between 2 points}\\ \quad \\ \begin{array}{lllll} &x_1&y_1&x_2&y_2\\ % (a,b) A&({{ 1}}\quad ,&{{ 2}})\quad % (c,d) G&({{ -4}}\quad ,&{{ 2}})\\ B&({{ 2}}\quad ,&{{ 3}})\quad % (c,d) H&({{ -3}}\quad ,&{{ 3}})\\ C&({{ 3}}\quad ,&{{ 1}})\quad % (c,d) G&({{ -2}}\quad ,&{{ 1}}) \end{array}\qquad % distance value d = \sqrt{({{ x_2}}-{{ x_1}})^2 + ({{ y_2}}-{{ y_1}})^2}\\\\[/tex]
[tex]\bf -------------------------------\\\\ AG=\sqrt{(-4-1)^2+(2-2)^2} \\\\\\ BH=\sqrt{(-3-2)^2+(3-3)^2} \\\\\\ CG=\sqrt{(-2-3)^2+(1-1)^2}[/tex]
and doing the distances from ABC to DEF
[tex]\bf \textit{distance between 2 points}\\ \quad \\ \begin{array}{lllll} &x_1&y_1&x_2&y_2\\ % (a,b) A&({{ 1}}\quad ,&{{ 2}})\quad % (c,d) D&({{ 1}}\quad ,&{{ -1}})\\ B&({{ 2}}\quad ,&{{ 3}})\quad % (c,d) E&({{ 2}}\quad ,&{{ 0}})\\ C&({{ 3}}\quad ,&{{ 1}})\quad % (c,d) F&({{ 3}}\quad ,&{{ -2}}) \end{array}\qquad % distance value d = \sqrt{({{ x_2}}-{{ x_1}})^2 + ({{ y_2}}-{{ y_1}})^2}[/tex]
[tex]\bf -------------------------------\\\\ AD=\sqrt{(1-1)^2+(-1-2)^2} \\\\\\ BE=\sqrt{(2-2)^2+(0-3)^2} \\\\\\ CF=\sqrt{(3-3)^2+(-2-1)^2}[/tex]
now... the ABC to JKL... surely you'd know how to do... the same way, just use the distance formula
Mario and Luigi want to purchase some extra controllers for their friends.each controller costs 29.99. Use an algebraic expression to describe how much they spend in total,before sales tax,based on purchasing the console(299.00)the number of games(59.99 each) and the number of extra controllers
Answers
What is the answer??
Answers
hope this helps!
I spent 20% of my weekly income on food. What was my weekly income if I spent $186 ?
Answers
hmm
percent means parts out of 100
20%=20/100=2/10=1/5
and 'of' means multipoly
20% of income=186
1/5 times income=186
times both sides by 5/1
income=930
weekly income was $930
If I spent $186. Then my weekly income will be $930.
What is the percentage?The quantity of anything is stated as though it were a fraction of a hundred.
I spent 20% of my weekly income on food.
If I spent $186.
Then my weekly income will be
Let x my weekly income.
0.2x = $186
x = $930
More about the percentage link is given below.
https://brainly.com/question/8011401
#SPJ5
The perimeter of a square is in p inches. Write expressions, in terms of p, for the length of the side of the square and the area of the square.
Answers
if the side length is p then the perimiter (distance around) is 4 times the length of the side or 4 times p or 4p
the area is side times side but since all sides are equal length, side^2 is the aera
perimiter=4p
area=p²
Write the sum using summation notation, assuming the suggested pattern continues. -9 - 3 + 3 + 9 + ... + 81
Answers
Honestly I believe this is correct:
∑ 15 at the top, n =0 (-9+6n)
Solve log 1/100 = log(10^x+2)
A.) x= 0
B.) x= -2
C.) x= -4
D.) x= 4
Answers
What conjecture can you make about the sum of the first 30 odd numbers
Answers
The sum of the first 30 odd numbers is equal to the square of 30. To find the sum, we can use a formula for the sum of an arithmetic series. Plugging in the values, we get a sum of 900.
Explanation:Conjecture: The sum of the first 30 odd numbers is equal to the square of the 30. To prove this conjecture, we can use a formula for the sum of an arithmetic series which is given by: S = n/2(2a + (n-1) d), where S is the sum of the series, n is the number of terms, a is the first term, and d is the common difference. In this case, the first term a is 1, the common difference d is 2 (since we are adding odd numbers), and the number of terms n is 30. Plugging in the values, we have: S = 30/2(2(1) + (30-1)2) = 15(2 + 58) = 900. Thus, the sum of the first 30 odd numbers is 900, which is equal to the square of 30.
Learn more about conjecture here:https://brainly.com/question/33833070
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Find the measure of the central angle with a radius of 18 inches and the area of a sector measuring 40.5π square inches.
Answers
Bob is driving along a straight and level road toward a mountain. At some point on his trip, he measures the angle of elevation to the top of the mountain and finds it to be 21°44'. Find the height of the mountain to the nearest foot if Bob is 13,428.7 feet from the center of the mountain at the base.
A. 5453 ft
B. 5353 ft
C. 53,534 ft
D. 535,342 ft
Answers
h = 13428.7 * tan 21 44
Height = 5353 feet
Answer:
Option B is the correct answer.
Step-by-step explanation:
The arrangement is given in the below figure.
We have height of the mountain = x
We also have
[tex]tan(21^044')=\frac{x}{13428.7}\\x=5352.98ft[/tex]
Height of the mountain to the nearest foot = 5353 ft
Option B is the correct answer.
Add 43.688 + 127.859?
Answers
43.688
+127.859
________
171.547
When a researcher needs to compare means for a variable grouped into two categories based on some less-than interval variable, an _ in appropriate?
Answers
When a researcher needs to compare means for a variable grouped into two
categories based on some less-than interval variable, a t-test is appropriate.
To add, The analysis of two populations means through the use of
statistical examination is called a t-test. Small sample sizes commonly
use a t-test with two
samples. What statisticians call as test statistics are
identified as t-values. A systematized value that is calculated from sample
data during a hypothesis test is called a test statistic. The procedure that
calculates the test statistic compares your data to what is expected under the null
hypothesis.
You already have an experience with the basic principles behind a t-test if you’ve
tried to communicated with a distracted teenager.
A hypothesis is only tentative: to make sure it's valid, you have to ___________.
Answers
Which equation illustrates the additive inverse property?Select one of the options below as your answer:A. c + d = d + cB. c × d = d × cC. -c + (-c) = 0D. d + (-d) = 0
Answers
The correct option is A
c + d = d + c
I hope that helps!
so answer is
d + (-d) = 0 (last choice)
The graph of a linear equation may not be a straight line.
A. True
B. False
Answers
-Stormie
One eighth of the students in the seventh grade are in the school band there are fourty four students in the school band find the number of students in the seventh grade
Answers
x = 44 * 8
x = 352 total 7th grade students <===
Question 6 jessica drive 380 miles using 14 gallons of gas. at this rate, how many gallons of gas would she need to drive 418 miles
Answers
A diner asked its customers, 'Did you cook dinner last night?' The results on the survey are shown in the table below: Male Female Cooked dinner 305 279 Did not cook dinner 152 459 What is the probability that one of the customers chosen from this survey was a female and cooked dinner? 0.23 0.38 0.47 0.61
Answers
Answer:
0.23
Step-by-step explanation:
How long does it take to drive 160 miles at 70mph?
Answers
time=[Distance]/[Speed]
Distance=160 miles
Time=70 mph
thus;
time=160/70
=2 2/7 hours
Final answer:
To calculate the travel time to drive 160 miles at 70mph, use the formula Time = Distance ÷ Speed. The result is approximately 2.2857 hours, or about 2 hours and 17 minutes.
Explanation:
To calculate how long it takes to drive 160 miles at a constant speed of 70 miles per hour (mph), you can use the basic formula for time, which is Time = Distance ÷ Speed.
Distance to be traveled is 160 miles.
Speed of travel is 70 mph.
By plugging the numbers into the formula, we get:
Time = 160 miles ÷ 70 mph = 2.2857 hours.
To convert this time into minutes, we multiply by 60 (the number of minutes in an hour), so:
2.2857 hours × 60 minutes/hour = 137.1428 minutes, which is approximately 2 hours and 17 minutes.
There is a state soccer tournament with 128 teams competing for 1st place. Each week, half of the teams get eliminated. How many teams remain after 6 weeks?
A.
16
B.
8
C.
4
D.
2
Answers
Week 0 (start; initial): 128 TEAMS
Week 1: 64 teams
Week 2: 32 teams
Week 3: 16 teams
Week 4: 8 teams
Week 5: 4 teams
Week 6: 2 teams
You can also solve for this using a common ratio.
[tex]A_0 = 128[/tex]
[tex]A_1 = A_0(0.5) = 128(0.5)[/tex]
[tex]A_2 = A_1(0.5) = 128(0.5)^{2}[/tex]
[tex]A_3 = A_2(0.5) = 128(0.5)^{3}[/tex]
[tex]A_n = 128(0.5)^{n}[/tex]
[tex]A_6 = 128(0.5)^{6} = 2[/tex]
Thus, after 6 weeks, there will only be 2 teams left.
Factor out the largest possible term.
12x^5-4x^2+16x^3= ?
(Please include steps if you can)
Answers
---------------------------------------------------------------------
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Work Shown:
The GCF of the coefficients 12,-4,16 is 4
The GCF of the variable terms is x^2 since this is the smallest variable term that is found in each of x^5, x^2 and x^3
Overall, the GCF is 4x^2.
Factor each term in terms of the GCF
12x^5 = (12)*(x^5)
12x^5 = (4*3)*(x^3*x^2)
12x^5 = (4x^2)*(3x^3) <--- call this equation (1)
-------------
4x^2 = (4x^2)*(1) <--- call this equation (2)
-------------
16x^3 = (4*4)*(x^2*x)
16x^3 = (4x^2)*(4x) <--- call this equation (3)
-------------
Using those individual factorizations, we can apply the distributive property to factor out the GCF
12x^5 - 4x^2 + 16x^3
(4x^2)*(3x^3) - 4x^2 + 16x^3 ... substitute equation (1)
(4x^2)*(3x^3) - (4x^2)*(1) + 16x^3 ... substitute equation (2)
(4x^2)*(3x^3) - (4x^2)*(1) + (4x^2)*(4x) ... substitute equation (3)
4x^2*(3x^3 - 1 + 4x) ... use the distributive property
Therefore, 12x^5 - 4x^2 + 16x^3 factors to 4x^2*(3x^3 - 1 + 4x)
This means, 12x^5 - 4x^2 + 16x^3 = 4x^2*(3x^3 - 1 + 4x) is a true equation for all real numbers x.
In the triangle below, what ratio is cos θ?
Answers
Answer:
[tex]cos(theta)=\frac{5}{13}[/tex]
Ratio is 5:13
Step-by-step explanation:
We are given with right angle triangle with side lengths
cos theta ratio is adjacent side divide by hypotenuse
In the triangle , adjacent side for theta is 5 and hypotenuse is 13
[tex]cos(theta)=\frac{adjacent}{hypotenuse}[/tex]
[tex]cos(theta)=\frac{5}{13}[/tex]
0=2x+3(3x-4)-(-x+14)
Fraction answer need help!!!
Answers
Follow BEDMAS
0=2x+9x-12-(-x+14)
0=2x+9x-12+x-14
Add like terms
0=11x-12+x-14
0=12x-12-14
0=12x-26
Flip the eqaution
12x-26=0
Move -26 across the equal sign
12x=0+26
12x=26
x=26/12
x=13/6
Hope this helps! A thanks/brainiest answer would be appreciated :)
HELP PLEASE! GIVING BRAINLIEST ANSWER. (TRIGONOMETRY)
What is the rate of change from x = 0 to x = pi over 2?
8 over pi
pi over 8
-8 over pi
-pi over 8
Answers
The correct option is A )[tex]\frac{8}{\pi }[/tex]
To find the rate of change of a function from x = 0 to x = \\frac{\\pi}{2}, we need to apply the concept of the average rate of change.
This is essentially the change in the function's value divided by the change in x. Assume the function we are analyzing is y = f(x).
Step-by-Step Solution:
Identify the interval: [tex][0, \frac{\pi}{2}].[/tex]Calculate the function values at the endpoints: f(0) and[tex]f{\frac{\pi}{2})[/tex].Calculate the average rate of change using the formula:Average Rate of Change =[tex]\frac{f(\frac{\pi}{2}) - f(0)}{\frac{\pi}{2} - 0}[/tex]
When x = 0, f( x ) = - 4,
When x = π / 2, f( x ) = 0
Average Rate of Change =[tex]\frac{0- (-4)}{\frac{\pi}{2} - 0}[/tex]
Average Rate of Change =[tex]\frac{8}{\pi }[/tex]
The correct option is A )[tex]\frac{8}{\pi }[/tex]
Find AB if AP and HQ are altitudes and ΔABC ~ ΔHGI
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so, "x" is either 7 or 3, but the segment HQ is larger then 3, thus it cannot be 3
what's the segment AB? well, 10 - x.
Find the complete perimeter of the sector that intercepts arc AC.
Round to the nearest hundredth.
Answers
Calculate for the circumference of the circle with the equation,
C = 2πr
where C is circumference and r is radius. Substitute the known value for r,
C = 2π(7) = 43.98
Then, multiply the obtained value by the ratio of the angle intercepted and the whole revolution.
Arc = 43.98 x (45°/360°)
Arc = 5.5
The whole perimeter of the sector includes the arc and 2 radii. Hence, the equation for the whole perimeter is,
Perimeter = Arc + 2r
Substituting the values,
Perimeter = (5.5) + 2(7)
Perimeter = 19.50
ANSWER: 19.50 units
ΔZAP has coordinates Z (−1, 5), A (1, 3), and P (−2, 4). A translation maps point Z to Z' (1, 1). Find the coordinates of A' and P' under this translation.
Answers
To solve this problem, we should first identify the number of units that point Z was translated. The number of units of movement of point Z should be similar to the number of units of movement of points A and P.
Let us say that the movement is Δx and Δy for horizontal and vertical translations respectively.
From Z to Z’:
Δx = 1 – (-1) = 2
Δy = 1 - 5 = - 4
Therefore the translation is in the form of (x + 2 , y – 4). Points A and P then becomes:
A’ = (1 + 2 , 3 – 4)
A’ = (3, -1)
P’ = (-2 + 2, 4 – 4)
P’ = (0, 0)
Answers:
A’ = (3, -1)
P’ = (0, 0)
Answer:
Step-by-step explanation:
lets be honest whos reading this when theres an expert answer