Answer:
Aluminum, Zinc, Silver
Explanation:
Several exceptions apply to the Roman numeral assessment: Aluminum, Zinc, Silver. Although they belong to the transition metal category, these metals do not exist in one ion.
Groups 1 and 2 elements on the periodic table, known as alkali and alkaline earth metals respectively, form metal ions that do not require Roman numerals in their names because they have fixed oxidation states. Transition metals often have variable charges, necessitating Roman numerals in names, except for silver, zinc, and cadmium which have fixed charges.
Explanation:The question focuses on which groups of elements on the periodic table form metal ions that do not require Roman numerals in their names. These are primarily the Group 1 (I) elements, also known as alkali metals, and Group 2 (II) elements, known as alkaline earth metals. These groups form cations through the loss of their outer shell electrons, which come from the s orbital and are removed very readily.
In contrast, most transition metals (Groups 3-12) can form more than one cation with different ionic charges, requiring the use of Roman numerals to distinguish between these charges in their names. However, there are exceptions among transition metals like silver (Ag+), zinc (Zn²+), and cadmium (Cd²+) which have fixed charges and do not require Roman numerals for naming.
Consider the reaction below.
21- (aq) + Cl2(g)—>2014(aq) +12(aq)
Which half reaction correctly describes the reduction that is taking place?
© C12(g) +2 ->2014 (aq)
C12(g) +-->2014 (aq)
21+ (aq) — > 2(aq) + 2e7
21+ (aq) —
> 12(aq) + e
Answer:
Refer to pic above
Explanation:
Cl's oxidation state reduces from 0 in Cl2 to - 1 in Cl-.
For the given reaction the reduction reaction is Cl[tex]_2[/tex] + 2e⁻→ 2Cl⁻. Therefore, the correct option is option C.
What are oxidation and reduction?
Any chemical process in which a participating chemical species' oxidation number changes is known as an oxidation-reduction reaction, often known as a redox reaction. The phrase refers to a broad range of processes. Many oxidation-reduction processes are as frequent and well-known as fire, metal corrosion and disintegration, fruit browning, respiration, and photosynthesis—basic life processes.
These three processes have two things in common: (1) they are coupled, meaning that every oxidation reaction results in a subsequent reduction; and (2) they involve a typical net chemical change, meaning that an atom or electron moves through one unit of matter to the other. For the given reaction the reduction reaction is Cl[tex]_2[/tex] + 2e⁻→ 2Cl⁻
Therefore, the correct option is option C.
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Choose the balanced equation for the reaction. Au3+(aq) + Cu+(aq) → Au(s) + Cu2+(aq) Au(s) + Cu2+(aq) → Au3+(aq) + Cu+(aq) Au3+(aq) + 3Cu+(aq) → Au(s) + 3Cu2+(aq) Au(s) + 3Cu2+(aq) → Au3+(aq) + 3Cu+(aq) b Use the standard reduction potentials for the galvanic cell to determine E°.
Final answer:
The balanced reaction between Au3+(aq) and Cu+(aq) that forms Au(s) and Cu2+(aq) is Au3+(aq) + 3Cu+(aq) → Au(s) + 3Cu2+(aq). To determine the standard cell potential, the standard reduction potentials of the associated half-reactions should be used to evaluate spontaneity.
Explanation:
The question at hand involves galvanic cells and the balancing of redox reactions.
For the balanced equation for the reaction between Au3+(aq) and Cu+(aq), the chemically accurate version is:
Au3+(aq) + 3Cu+(aq) → Au(s) + 3Cu2+(aq)
Standard Reduction Potentials and Galvanic Cell Potential
To determine the standard cell potential (E°), you would reference the standard reduction potentials of the half-reactions:
Oxidation: Cu(s) → Cu2+(aq) +2e−
Reduction: Au3+(aq) + 3e− → Au(s)
By adding the reduction potentials of these half-reactions together, one can ascertain whether the reaction is spontaneous under standard state conditions. Specifically, if the standard cell potential (E°) is positive, the reaction is spontaneous.
If the molar heat of fusion of water is 6.01
kJ
mol
, how much heat energy was required to melt 2 kg of ice?
Answer : The heat energy required to melt 2 kg of ice was, 667.7 kJ
Explanation :
First we have to calculate the moles of ice.
[tex]\text{Moles of ice}=\frac{\text{Given mass ice}}{\text{Molar mass ice}}=\frac{2kg}{18g/mol}=\frac{2000g}{18g/mol}=111.1mol[/tex]
Now we have to calculate the heat energy.
As, heat energy required to melt 1 mole of ice = 6.01 kJ
So, heat energy required to melt 111.1 mole of ice = 111.1 × 6.01 kJ
= 667.7 kJ
Therefore, the heat energy required to melt 2 kg of ice was, 667.7 kJ
A biochemist carefully measures the molarity of glycerol in of photobacterium cell growth medium to be . Unfortunately, a careless graduate student forgets to cover the container of growth medium and a substantial amount of the solvent evaporates. The volume of the cell growth medium falls to . Calculate the new molarity of glycerol in the photobacterium cell growth medium. Round each of your answers to significant digits.
Note:
The Complete Question
A biochemist carefully measures the molarity of glycerol in 913 mL of photobacterium cell growth medium to be 81.3 μM. Unfortunately, a careless graduate student forgets to cover the container of growth medium and a substantial amount of the solvent evaporates. The volume of the cell growth medium falls to 11.1 mL. Calculate the new molarity of glycerol in the photobacterium cell growth medium. Round each of your answers to 3 significant digits.
Answer:
669 μM
Solution:
[Find the attachment]
Dr. Terror has developed a new alloy called Ultranomium. He is testing a bar that is 1.25 m1.25 m long and has a mass of 382 g.382 g. Using a carbon‑dioxide infrared laser, he carfully heats the bar from 20.6 ∘C20.6 ∘C to 288 ∘C.288 ∘C. Answer the two questions below, using three significant digits. Part A: If the bar absorbs 89300 J89300 J of energy during the temperature change, what is the specific heat capacity ( cc ) of the Ultranomium?
Answer:0.8742j/g°C
Explanation: SOLUTION
GIVEN
length of bar=1.25m
mass 382g
temperature= 20°C to 288°C
Q=89300J
Specific Heat Capacity will be calculated using
Q=mC∆T
where
C = specific heat capacity
Q = heat
m = mass
Δ T = change in temperature
C=Q/ m∆T
=89300/382X(288-20.6)
=0.8742j/g°C
4. If an experimental value for a given observation was 415 nm while the theoretical value
was 435.8 nm, what is the percent error of the observation?
Answer: % error of observation is 4.77%
Explanation:
Given:
Observation value = 415nm
theoretical value= 435.8nm
Percent error of observation = theoretical value- observation value/ theoretical value x 100 %
= 435.8-415/435.8= 0.04772 x 100 = 4.77%
therefore % error of observation is 4.77%
Antifreeze is used in car engines. It is produced by a local manufacturer, but they’ve run out of an ingredient: ethane (C2H6). As a junior scientist, you know you can produce ethane by reacting sulfuric acid with diethyl zinc gas. The local manufacturer will pay $1.25 per gram of ethane you produce. If you have 45.00 mL of 8.00 M H2SO4 and 30.00 mL of Zn(CH3CH2)2, what is the maximum amount of money you can make?
Answer:
Maximum amount of money = $21.95
Explanation:
Required reaction:
H2SO4 + Zn(CH3CH2)2 -------------> 2 C2H6 + ZnSO4
No.of moles of H2SO4= (45 x 10-3 L) x (8 M) = 0.360 mol
No.of moles of Zn(CH3CH2)2 = (30 x 1.205) / (123.50 g/mol) = 0.2927 mol
Here H2SO4 is in excess amount and Zn(CH3CH2)2is the limiting reagent.
Hence, Maximum no.of moles of ethane that can be produced = 2 * 0.2927 mol = 0.484 mol
Hence, Mass of ethane that can be produced = 0.484 mol x 30 g/mol = 17.56 g
Therefore,Maximum amount of money that you can make :
Maximum amount of money = (17.56 g) x ($1.25 /g)
Maximum amount of money = $21.95
What volume would 32.0 g of NO2 gas occupy at 3.12 atm and 18.0 Celsius
Answer:
Volume of 32.0 g [tex]NO_{2}[/tex] at 3.12 atm and 18.0 [tex]^{0}\textrm{C}[/tex] is 5.33 L.
Explanation:
Molar mass of [tex]NO_{2}[/tex] = 46.0055 g/mol
So, 32.0 g of [tex]NO_{2}[/tex] = [tex]\frac{32.0}{46.0055}[/tex] mol of [tex]NO_{2}[/tex] = 0.696 mol of [tex]NO_{2}[/tex]
Let's assume [tex]NO_{2}[/tex] behaves ideally.
Then [tex]P_{NO_{2}}V_{NO_{2}}=n_{NO_{2}}RT[/tex] , where P, V, n, R and T represents pressure, volume, number of moles, gas constant and temperature (in kelvin scale) respectively.
Here [tex]P_{NO_{2}}[/tex] = 3.12 atm, [tex]n_{NO_{2}}[/tex] = 0.696 mol, R = 0.0821 L.atm/(mol.K) and T = (273+18.0)K = 291 K
So, [tex]V_{NO_{2}}=\frac{n_{NO_{2}}RT}{P_{NO_{2}}}[/tex]
or, [tex]V_{NO_{2}}=\frac{(0.696mol)\times (0.0821\frac{L.atm}{mol.K})\times (291K)}{3.12atm}[/tex]
or, [tex]V_{NO_{2}}=5.33L[/tex]
So, volume of 32.0 g [tex]NO_{2}[/tex] at 3.12 atm and 18.0 [tex]^{0}\textrm{C}[/tex] is 5.33 L.
The Volume of NO₂ is 542.8L
What is Ideal Gas Law ?Ideal Gas Law relates the macroscopic property of gas , It states that the product of pressure and volume of 1 mole of a gas is equal to the product of absolute temperature and universal gas constant.
For n mole of gas,
PV = nRT
In the question it is given that mass of NO₂ is 32 g
P = 3.12 atm
T = 18°Celsius = 291 K
Volume = ?
n = m/M = 32/46 = 0.7
3.12 * V = 0.7*0.0821*291
V = 5.36 L
Therefore the Volume of NO₂ is 5.36L
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Are the following statements true or false? (a) Formal charges represent an actual separation of charges. true false (b) ΔH o rxn can be estimated from the bond enthalpies of reactants and products. true false (c) All second-period elements obey the octet rule in their compounds. true false (d) The resonance structures of a molecule can be separated from one another in the laboratory. true false
Answer:
Explanation:
A) Formal charges represent an actual separation of charges.(FALSE)
(B) ΔHo rxn can be estimated from the bond enthalpies of reactants and products.(TRUE)
C)All second-period elements obey the octet rule in their compounds(FALSE).
(D)The resonance structures of a molecule can be separated from one another in the laboratory.(FALSE)
Bond enthalpy which is also reffered to as bond energy is the amount of energy that is required to break one mole of a bond.
taking the single bond between Oxygen and Hydrogen into considerationthe bond energy between their single bond is 463 kJ/mol.
formal charge is used for the comparison of the number of electrons present around an atom in a particular molecule with the number of electrons present around a neutral
Final answer:
Formal charges do not represent actual charge separation, ΔH°rxn can be estimated using bond enthalpies, not all second-period elements obey the octet rule, and resonance structures cannot be physically separated.
Explanation:
Addressing the truthfulness of the given statements:
Formal charges represent an actual separation of charges is false. Formal charges are a way of computing the charge distribution within a Lewis structure and do not represent an actual charge separation.ΔH°rxn can be estimated from the bond enthalpies of reactants and products is true. This is a common method for estimating the change in enthalpy for a reaction.All second-period elements obey the octet rule in their compounds is false. While many do, there are exceptions, such as boron, which can have incomplete octets.The resonance structures of a molecule can be separated from one another in the laboratory is false. Resonance structures are theoretical concepts that represent different ways of drawing the same molecule and cannot be separated.On a hot summer day in Florida, Sarah was having a picnic with her family. She took a glass, which had been sitting in the Sun, and filled it with ice cubes from a cooler. Then she added cold lemonade from a thermos jug. Which of the following describes one direction in which heat will flow?
A.From the ice cube to the glass.
B. From the lemonade to the glass.
C. From the lemonade to the ice cube.
D. From the ice cube to the lemonade.
The objects will exchange thermal energy, until thermal equilibrium is reached. This means until their temperatures are equal. Here the direction in which heat will flow is from the lemonade to the glass. The correct option is B.
What is heat flow?The transfer of heat energy from an object or substance to another because of the difference in the temperature between them is defined as the heat flow. The flow of heat occurs from an object of higher temperature to an object of lower temperature.
The heat flows from hot objects to cold objects by several processes such as radiation, conduction and convection. However evaporation allows an object to lose the heat even if the surrounding medium in which it is immersed is hotter than the object itself.
Here lemonade has higher temperature than the glass. So heat flows from lemonade to the glass.
Thus the correct option is B.
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14 H+ + 6 Fe2+ + Cr2O72- . 2 Cr3+ + 6 Fe3+ + 7 H2O This reaction is used in the
titration of an iron solution. What is the concentration of the iron solution if it takes 45.20 mL
of 0.1000 M Cr2O72- solution to titrate 50.00 mL of an acidified iron solution?
a.
0.5424 M
b.
0.1000 M
c.
1.085 M
d.
0.4520 M
e.
0.2712 M
Answer:
Option A 0.5424 M
Explanation:
To do this, let's write the reaction again and see the mole ratio:
14H⁺ + 6Fe²⁺ + Cr₂O₇⁻ ---------> 2Cr³⁺ + 6Fe³⁺ + 7H₂O
According to this reaction, we have a mole ratio between the dicromate and iron of 1:6. In other words, 6 moles of dicromate reacts with only 1 mole of iron, therefore we can use the following expression:
nFe = 6 * nCr₂O₇
This is a REDOX reaction, where Iron is being oxidized while cromium is being reduced. Now, we have the concentrations and volume, let's express the moles in function of concentration and volume:
M₁V₁ = 6M₂V₂
Replacing the given data above and solving for concentration of iron (M₁)
M₁ = 6 * 45.20 * 0.1 / 50
M₁ = 0.5424 M
This is the concentration of the iron solution
Give the formula for the alkyne containing 40 hydrogens
Answer:
Molecular formula is C21H40
Explanation:
Use the formula CnH2n-2
That is the alkyne formula
The formula for the alkyne containing 40 hydrogens is C21H40. This is further explained below.
What is Molecular formula?Generally, Molecular formula is simply defined as a chemical formula that shows how many atoms of each element there are in each molecule of a material.
In conclusion, Using the alkyne formula which is C_nH2n-2.
We have C21H40 as the alkyne containing 40 hydrogens.
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c. What predictions can you make about ΔH, ΔS, and ΔG for the general reaction A(s) + 2B(g) 3C(g) + D(g) + heat? What conclusions can you make about the spontaneity of the reaction? Explain your reasoning. (4 points)
d. The reaction 2NO2(g) N2(g) + 2O2(g) is spontaneous at all temperatures, yet it hardly happens under normal conditions. How can this be? (2 points)
ANSWER:
C.
1) Entropy (∆S) is spontaneous
2) Enthalpy (∆H) is not spontaneous
3) Gibbs free energy (∆G) is spontaneous
Therefore the reaction will be spontaneous at high temperature.
D.
Because Nitrogen is favourable to be produced under high temperature, and oxygen under low temperature. Which favours the product side of the equation. But when at a room temperature, which means the temperature is neither low nor high, the product side won't be favoured, and the reaction will not be spontaneous.
EXPLANATION:
C.
1) Entropy is the measure of disorderliness in a system, which increase more in gaseous substances, because the molecules of gases are not stable
Because almost all the reacting substances are in their gaseous state, the entropy of the reaction will be high. Therefore entropy will be positive, which makes the entropy of the system spontaneous.
2) Enthalpy is the measure of heat change in the system. Since their is an intake of heat in the system, therefore the reaction is endothermic and ∆H will be positive. Enthalpy of a system can only be spontaneous in an Exothermic reaction, where ∆H is negative. Therefore Enthalpy is not spontaneous.
3) Gibbs free energy is equal to the change in enthalpy minus the product of temperature and change in entropy. Since entropy and enthalpy are positive, the Gibbs free energy will be negative, which shows that the reaction can be spontaneous if some conditions are met. ∆G will be spontaneous because it is negative.
Therefore in summary, the reaction will favour the product side more, if the temperature of the system is increased, which will make the reaction to become more spontaneous.
D.
2NO2(g) --> N2(g) + 2O2(g)
This reaction is not spontaneous under atmospheric pressure and room temperature (normal conditions) because, Nitrogen can only be produced very fast at a high temperature, while oxygen production is preferable in a low temperature. For the reaction to favour the product side, the temperature should be increased or decreased. Because an increase or a decrease in the temperature will favour either nitrogen or oxygen, which are the product side of equation. This means that the reaction should not be spontaneous if you wish to achieve an equal proportion of the products.
HELP MY TEST IS TIMED: A sample of methane gas is 22.8 L at 313 Kelvin and 4.00 atm. What will its pressure be at 341 K and constant volume?
3.7 atm
4.4 atm
2.4 atm
.15 atm
Answer:
option B.
Explanation:
Given,
Volume,V₁ = 22.8 L
T₁ = 313 K
P₁ = 4 atm
T₂ = 341 K
P₂ = ?
Volume is constant.
Using ideal gas law
[tex]\dfrac{P_1}{T_1}=\dfrac{P_2}{T_2}[/tex]
[tex]\dfrac{4}{313}=\dfrac{P_2}{341}[/tex]
[tex]P_2 = \dfrac{4}{313}\times 341[/tex]
[tex]P_ 2 = 4.36\ atm[/tex]
Pressure of the tank is equal to 4.36 atm.
Hence, the correct answer is option B.
A student adds solid KCl to water in a flask. The flask is sealed with a stopper and thoroughly shaken until no more solid KCl dissolves. Some solid KCl is still visible in the flask. The solution in the flask is A) saturated and is at equilibrium with the solid KCl B) saturated and is not at equilibrium with the solid KCl C) unsaturated and is at equilibrium with the solid KCl D) unsaturated and is not at equilibrium with the solid KCl
Answer:
Option (A) saturated and is at equilibrium with the solid KCl
Explanation:
A saturated solution is a solution which can not dissolve more solute in the solution.
From the question given above, we can see that the solution is saturated as it can not further dissolve any more KCl as some KCl is still visible in the flask.
Equilibrium is attained in a chemical reaction when there is no observable change in the reaction system with time. Now, observing the question given we can see that there is no change in flask as some KCl is still visible even after thorough shaking. This simply implies that the solution is in equilibrium with the KCl solid as no further dissolution occurs.
A 500L tank contains helium gas at 1.50 atm. What is the pressure of the gas in torr
Consider an electrolytic cell with a platinum anode and a silver cathode in a 1.0 M AgNO3(aq) solution.
a) (3 pts) What species can be reduced in this solution? Which species is preferentially reduced? Write the reduction half- reaction. (Note that oxyanions like nitrate are not commonly reduced in aqueous electrolysis due to kinetic reasons.)
b) (2 pts) Which species is oxidized during the electrolysis? Write the oxidation half-reaction. Note that acid will form as a byproduct of the oxidation.
c) (2 pts) Write the overall electrolysis reaction in net ionic and molecular forms.
d) (2 pts) Determine the external electric potential needed for the electrolysis under standard conditions.
e) (5 pts) If the electrolysis is carried out for 1.00 hour using 1.00 A current, how many grams of metal will be deposited at the cathode and how many liters of gas will form at the anode at 1.00 atm pressure and 25°C?
Answer:
Check the attached image below
Explanation:
The step by step solution to the question above can be seen in the attached image below.
Which disease is most likely to cause each effect?
Destruction of red blood cells:
Shaking hands or feet:
Streaks of pus in the throat area:
Inability of the immune system to fight off pathogens:
Answers:
Though no result is wholesome without further tests and observed symptoms, these diseases could be causative for the following symptoms:
Explanation:
Destruction of red blood cells: AnaemiaShaking hands or feet: Parkinson's disease, Sclerosis, Peripheral neuropathyStreaks of pus in the throat area: Glandular fever, tonsillitisInability of the immune system to fight off pathogens: HIV?AIDS, Leukemia.What is the enthalpy change during the process in which 100.0 g of water at 50.0 °C is cooled to ice at –30.0 °C?
(Use the specific heats and enthalpies for phase changes)
Answer:
60.1 kJ
Explanation:
Enthalpy change ΔH = m x Δt x cρ
Given that:
100 grams water = 5.56 moles water
The enthalpy change needed to raise 100 g water from 50°C to 0°C is calculated as :
ΔH = 100g x ( 0-50) x 4.18J/gC = -2.09 X 10⁴ Joules
The Freezing water
ΔH = ΔH fusion * mol
ΔH fus for water is = 6.01 kJ/mol
ΔH = 6.01 kJ/mol × 5.56 moles = -33.4 kJ (since heat is released when water freezes)
Finally, The enthalpy Change during the process pf changing the ice from 0°C to -30.0°C is:
ΔH = m x Δt x cp
= 0.100 kg × (-30 -0)°C × 2.00 × 10³ J/kgC
= - 6 × 10³ J
Total heat lost = -2.09 × 10⁴ J + (-33.4 × 10³ J) + (-6 × 10^3J)
= - 6.01 × 10⁴ J
= 60.1 kJ
The enthalpy change during the process in which 100.0 g of water at 50.0 °C is cooled to ice at -30.0 °C is -60.570 kJ, involving three energy changes: cooling water from 50°C to 0°C, transition from water to ice, and cooling from 0°C to -30°C.
Explanation:The calculation of the enthalpy change in converting 100.0 g water at 50.0 °C to ice at -30.0 °C involves calculating energy changes at different stages: cooling water from 50°C to 0°C, changing water at 0°C to ice at 0°C (enthalpy of fusion), and cooling ice from 0°C to -30°C. Below is step be step calculation.
Cooling of water: Using the formula Q = m * C * ΔT (where Q is energy, m is mass, C is specific heat, and ΔT is temperature change), we calculate: Q1 = 100.0 g * 4.18 J/(g*K) * -50.0 K = -20900 J. Water to ice: Enthalpy of fusion for water is 334 J/g, so Q2 = 100.0 g * -334 J/g = -33400 J. Cooling of ice: The specific heat of ice is 2.09 J/(g*K), Q3 = 100.0 g * 2.09 J/(g*K) * -30.0 K = -6270 J.
The total enthalpy change is therefore Q total = Q1 + Q2 + Q3 = -20900 J - 33400 J - 6270 J = -60570 J, or -60.570 kJ.
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Which isoelectronic series is correctly arranged in order of increasing radius?
A) K+ < Ca2+ < Ar < Cl
B) < Ar < K+ < Ca2+
C) Ca2+ < Ar < K+ < Cl
D) Ca2+ < K+ < Ar < Cl
E) Ca2+ < K+ < Cl- < Ar
Answer:
D) Ca2+ < K+ < Ar < Cl-
Explanation:
The isoelectronic series is correctly arranged in order of increasing radius is option D. Ca2+ < K+ < Ar < Cl.
Arranging of isoelectronic series:Since k+, Ca2+, Cl- and Ar represent the same kind of e- (18) due to this the positive charge increased. The size should be decreased due to the net attraction on outer e- increased and a negative charge should increase the size because the electronic repulsion should be increased.
Therefore, the option d is correct.
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please help which one is it
Answer:
d:more dense and falls
Explanation:
warm air Rises around cold air bc of its lower density. and when you have a lower density fluid or sum the lower density fluid rises and the higher density falls
Answer:
Explanation:
I have the same question
What are some advantages to use the Hydro kinetic energy? White might be some disadvantages?
Answer:
Here are some advantages.
Explanation:
Hydropower is fueled by water, so it's a clean fuel source, meaning it won't pollute the air like power plants that burn fossil fuels, such as coal or natural gas.
Hydroelectric power is a domestic source of energy, allowing each state to produce their own energy without being reliant on international fuel sources.
The energy generated through hydropower relies on the water cycle, which is driven by the sun, making it a renewable power source, making it a more reliable and affordable source than fossil fuels that are rapidly being depleted.
Impoundment hydropower creates reservoirs that offer a variety of recreational opportunities, notably fishing, swimming, and boating. Most water power installations are required to provide some public access to the reservoir to allow the public to take advantage of these opportunities.
Some hydropower facilities can quickly go from zero power to maximum output. Because hydropower plants can generate power to the grid immediately, they provide essential back-up power during major electricity outages or disruptions.
In addition to a sustainable fuel source, hydropower efforts produce a number of benefits, such as flood control, irrigation, and water supply.
Some advantages of Hydro kinetic energy is, it can be used to drive turbines and generate electricity.
What is hydro kinetic energy?Hydro kinetic energy is the energy derived from the motion of falling water.
The energy (Hydro kinetic energy) can be converted into mechanical energy of turbine which is in turn converted into electrical energy.
Some advantages of Hydro kinetic energyIt is can be used to generate electricityIt is can be used to power some machines like, turbine, etc.Some disadvantage of Hydro kinetic energyIt can lead to loss of water that would have been used for irrigation or other purposes.Learn more about Hydro kinetic energy here: https://brainly.com/question/26038602
1. Calculate the concentration of hydronium ion of both buffer solutions at their starting pHs. Calculate the moles of hydronium ion present in 20.0 mL of each buffer. 2. A change of pH by 1 unit means a change in hydronium ion concentration by a factor of 10. Calculate the number of moles of NaOH that would theoretically be needed to decrease the moles of hydronium you calculated in
To calculate the concentration of hydronium ion and the moles in a buffer solution, use the formula [H3O+] = 10^(-pH) and Moles = Concentration x Volume.
Explanation:The concentration of hydronium ion can be calculated using the formula:
[H3O+] = 10^(-pH)
For example, if the starting pH is 4.74, then the concentration of hydronium ion is 10^(-4.74) M
The moles of hydronium ion present in 20.0 mL of the buffer can be calculated using the formula:
Moles = Concentration x Volume
Assuming the concentration of hydronium ion is 10^(-4.74) M, then the moles of hydronium ion in 20.0 mL is (10^(-4.74) M) x (20.0 mL / 1000) L.
The lead-containing reactant(s) consumed during recharging of a lead-acid battery is/are ________. The lead-containing reactant(s) consumed during recharging of a lead-acid battery is/are ________. PbSO4 (s) only Pb (s) only PbO2 (s) only both PbO2 (s) and PbSO4 (s) both Pb (s) and PbO2 (s)
Answer:
PbSO4 (s) only
Explanation:
The formula CH3CH2CH2CH2CH2CH2 represents an
Answer:
alkene
Explanation:
Since the end only has CH2 it would be an alkene.
Alkene means their is a double bond present.
Carbon always wants 4 bonds (4-2=2) Therefore this shows us that it is a double bond, known as an alkene.
Also,
alcohol = OH
alkane = single bond
alkene = double bond
alkyne = triple bond
- Hope this helps! Please let me know if you want further explanation.
The chemical formula CH3CH2CH2CH2CH2CH2 represents a type of hydrocarbon known as hexane, a straight-chain alkane with six carbon atoms commonly used as a solvent in labs and a constituent in gasoline.
Explanation:The formula CH3CH2CH2CH2CH2CH2 represents a hydrocarbon named Hexane. Hexane is a straight-chain alkane with six carbon atoms. The general formula for an alkane is CnH2n+2, which in the case of hexane explains the presence of 14 hydrogen atoms. Hexane is commonly used as a solvent in laboratories and a constituent in gasoline.
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convert 1.21 kg to grams
Answer:
1210 grams
Explanation:
Message me for extra info.
snap- parkguy786
Answer:
1210
Explanation:
a sample of oxygen occupies 75 L at 1 atm. If the volume double what is the new pressure of oxygen in atm
Answer:
[tex]P_2=\frac{1}{2} \text{ atm}[/tex]
Explanation:
Considering ideal gas situation and initial condition as 1 and final condition as 2 all other conditions being constant we get
[tex]P_1V_1=P_2V_2[/tex]
Here P1 = 1 atm , V1= 75L, also, V2=2V1 = 2×75 L =150 L
using above equation we have
[tex]1\times75=150\times P_2\\P_2=\frac{75}{150} = \frac{1}{2} \text{ atm}[/tex]
Ethanol is added to gasoline because the oxygen it contains improves gasoline's burning efficiency. Its combustion reaction is given below. CH3CH2OH(l) + 3O2(g) → 2CO2(g) + 3H2O(g) ∆H = - 1236 kJ a) Is this an exothermic or endothermic reaction? _______________ b) If 15.3 grams of pure ethanol is completely converted to products, calculate how much heat is absorbed or released, in: (1) kJ and in (2) kcal c) If 42.7 g of water vapor is produced, how much heat, in kJ, is absorbed or released?
Answer:
A) The reaction is exothermic reaction
B) 46 gm CH3CH2OH = 1236KJ
15.3 gm ch3ch2OH = 1236/46 x 15.3
= 411.10 KJ..........released
therefore 1 KJ = 0.239 K cal
so, 411.10 x 0.239 kcal
= 98.2529 .................. released
c) 54 gm of H2O produced = 1236KJ
so, 42.7 gm H2O produced = 1236/54 x 42.7KJ
= 977.35 KJ released.
Explanation:
Draw the products of the acid-base reaction between stearic acid and OH-
Answer:
Products are stearate anion and water.
Explanation:
Stearic acid is a 18-carbon chain molecule containing -COOH group. IUPAC name of stearic acid is octadecanoic acid.
Molecular formula of stearic acid is [tex]C_{17}H_{35}CO_{2}H[/tex].
When [tex]OH^{-}[/tex] is added into stearic acid, [tex]OH^{-}[/tex] removes a proton ([tex]H^{+}[/tex]) from acidic -COOH group and forms stearate anion and water as products.
The balanced acid-base reaction is given as:
[tex]C_{17}H_{35}CO_{2}H+OH^{-}\rightleftharpoons C_{17}H_{35}CO_{2}^{-}+H_{2}O[/tex]
Structure of products are given below.
Question 51 pts A breathalyzer is a device used to estimate the blood alcohol content of a suspected drunk driver by measuring the amount of alcohol in one's breath. The fuel cell breathalyzer employs the reaction below: CH3CH2OH(g)+O2(g)→HC2H3O2(g)+H2O(g) When a suspected drunk driver blows his or her breath through the fuel-cell breathalyzer, the device measures the current produced by the reaction and calculates the percent alcohol in the breath. How many moles of electrons are transferred per mole of ethanol, CH3CH2OH, in the reaction?
Answer:
Four moles of electrons
Explanation:
The reactions in a breathalyzer are redox reactions. Fuel cell breathalyzers consists of fuel cells with platinum electrodes. The current produced depends on the amount of alcohol in the breath. Detection of alcohol involves the oxidation of ethanol to ethanoic acid. The two half cells set in the process are;
Anode;
C2H5OH(aq) + 4OH^-(aq) ----------> CH3COOOH(aq) + 3H2O(l) + 4e
Cathode;
O2(g) + 2H2O(l) +4e--------> 4OH^-(aq)
Hence four electrons are transferred in the process.