» A cylinder has a height of 13 millimeters and a radius of 11 millimeters. What is its
volume? Use a 3.14 and round your answer to the nearest hundredth.

To find the values of the two numbers, we can set up a system of equations based on the given information and then solve for x and y. The first number is 16 and the second number is 22.

Let's represent the first number as x and the second number as y.

We can set up two equations based on the given information.

The first equation is: x = y - 6

The second equation is: 6x = 4y + 8

Now we can solve this system of equations to find the values of x and y.

Substituting the first equation into the second equation, we get: 6(y - 6) = 4y + 8

Simplifying, we get: 6y - 36 = 4y + 8

Bringing like terms together, we have: 6y - 4y = 8 + 36

Combining like terms, we get: 2y = 44

Dividing both sides by 2, we have: y = 22

Now substitute y = 22 back into the first equation: x = 22 - 6

Simplifying, we get: x = 16

Therefore, the first number is 16 and the second number is 22.

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Answer:

Step-by-step explanation:

answer 76800

length- 20

width- 12

20x12=240

240x320(people)= 76800

The population of given Rectangleville is 76800.

The area of Rectangle is length times of width.

Given that Rectangleville's limits form a perfectly rectangular shape whose length is 20 kilometers and width is 12 kilometers

length is 20 km

width is 12 km

Area of rectangleville = Length × width

=20x12

=240 square kilometer.

Now  It has a population density of 320 people per square kilometer

We need to find the population.

To find this we need to multiply two hundred forty with three hundred twenty.

240x320

= 76800

Hence, the population of given Rectangleville is 76800.

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Answer:

61/495

Step-by-step explanation:

Answer:

$51.75

Hope this helps!

(Please mark brainliest!)

Answer:

Step-by-step explanation:

A. $51.75

To determine whether there is enough evidence to reject the claim of the state Department of Transportation, a hypothesis test needs to be performed. The null hypothesis (H0) is that the mean wait time is 6 minutes or less, while the alternative hypothesis (H1) is that the mean wait time is greater than 6 minutes. Using a one-sample t-test, the test statistic is calculated and compared to the critical value obtained from the t-distribution table or calculator. In this case, the test statistic is greater than the critical value, indicating that there is enough evidence to reject the null hypothesis.

To determine whether there is enough evidence to reject the claim of the state Department of Transportation, we need to perform a hypothesis test.

Hypotheses:

Let:

μ be the mean wait time for various services at different locations.

The null hypothesis (H0) is that the mean wait time (μ) is 6 minutes or less:

H0: μ ≤ 6
The alternative hypothesis (H1) is that the mean wait time (μ) is greater than 6 minutes:

H1: μ > 6

Test statistic:

We will use a one-sample t-test since the population standard deviation is unknown.

The test statistic (t) is calculated using the formula:

t = (Xbar - μ)/(s/√(n))

Where:

Xbar is the sample mean - 10.3 minutes,

μ is the claimed mean - 6 minutes,

s is the sample standard deviation - 8.0 minutes, and

n is the sample size - 34.

Critical value:

To find the critical value, we need to determine the rejection region using the significance level (alpha) of 0.01 and the degrees of freedom (df) which is n - 1 = 33.

From the t-distribution table or calculator, the critical value for a one-tailed test at alpha = 0.01 and df = 33 is approximately 2.449.

Conclusion:

The test statistic (t) = (10.3 - 6)/(8.0/√(34)) = 3.720.

Since the test statistic (t) = 3.720 > 2.449 (the critical value), we have enough evidence to reject the null hypothesis.

Therefore, we can conclude that there is sufficient evidence to reject the claim of the state Department of Transportation at alpha = 0.01.

Answer:

45°-(315°) = 360°

-315°-45°=-360°

Second part: WOULD

Step-by-step explanation:

Trust me I gotchu

Subtracting angles involves accounting for the directions implied by their positive or negative signs. The subtraction of 45°-(-315°) equates to an addition, giving a resultant angle of 360°. Conversely, -315° – 45° provides a resultant angle of -360°.

The question involves the mathematical concept of angles, specifically, subtracting them. Here, we are dealing with angles of 45° and -315°. When subtracting angles, consider the directions indicated by the positive and negative signs. A positive angle is measured counterclockwise from the initial side to the terminal side, while a negative angle is measured clockwise.

So, for 45°-(-315°), you're essentially adding 45 and 315 because subtracting a negative number becomes the addition of the positive equivalent. This gives you a resultant angle of 360°.

And in the case of -315° – 45°, you're subtracting 45 from -315 which gives you a resultant angle of -360°.

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Answer:

The 99% confidence interval for the mean height of all men recruits between the ages 18 and 24 is between 69.44 inches and 69.96 inches.

Step-by-step explanation:

We have that to find our [tex]\alpha[/tex] level, that is the subtraction of 1 by the confidence interval divided by 2. So:

[tex]\alpha = \frac{1-0.99}{2} = 0.005[/tex]

Now, we have to find z in the Ztable as such z has a pvalue of [tex]1-\alpha[/tex].

So it is z with a pvalue of [tex]1-0.005 = 0.995[/tex], so [tex]z = 2.575[/tex]

Now, find the margin of error M as such

[tex]M = z*\frac{\sigma}{\sqrt{n}}[/tex]

In which [tex]\sigma[/tex] is the standard deviation of the population and n is the size of the sample.

[tex]M = 2.575\frac{2.8}{\sqrt{772}} = 0.26[/tex]

The lower end of the interval is the sample mean subtracted by M. So it is 69.7 - 0.26 = 69.44 inches

The upper end of the interval is the sample mean added to M. So it is 69.7 + 0.26 = 69.96 inches

The 99% confidence interval for the mean height of all men recruits between the ages 18 and 24 is between 69.44 inches and 69.96 inches.

Step-by-step explanation:

-13 > x - 43

-13 + 43 > x

30 > x

Answer:

because I said one is the best number

Step-by-step explanation:

[tex](2x^2-6x^3+4)+(2x^3+3x^2+4)[/tex]

Since this is addition, you can just easily combine the terms.

[tex](2x^2+3x^2)+(-6x^3+2x^3)+(4+4)[/tex]

[tex]5x^2 -4x^3+8[/tex]

Now, all we have to do is put it in standard form meaning the exponents have to go in descending order. Largest exponent to smallest exponent.

[tex]-4x^3+5x^2+8[/tex]

So, this is your answer in standard form.

The length of side DE in the right triangle shown is 4.24 units.

We can use the Pythagorean Theorem to solve for the length of DE, since we know the lengths of the other two sides.

The Pythagorean Theorem states that in a right triangle, the square of the hypotenuse is equal to the sum of the squares of the other two sides.

The hypotenuse of the triangle is DE, and the other two sides are DF and EF. We know that DF = EF = 3 units. Therefore, we can set up the following equation:

[tex]DE^2 = DF^2 + EF^2[/tex]

Substituting in the known values, we get:

[tex]DE^2 = 3^2 + 3^2[/tex]

[tex]DE^2 = 9 + 9[/tex]

[tex]DE^2 = 18[/tex]

Taking the square root of both sides, we get the length of DE:

DE = √18

DE ≈ 4.24 units

Therefore, the length of side DE in the right triangle shown is 4.24 units.

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Question

Answer:

Step-by-step explanation:

6 /2

=3

Good luck honey!

Answer:

4

Step-by-step explanation:

1 mile = 1.6 km

1 km = 1000 m

1.6 * 1000 = 1600, So to swim 1 mile, she must swim 1600 m

She has already swam 60 lengths which is 1500 m because 60 (the number of lengths)*25 (the length of the pool) = 1500.

1600 (the amount she needs to swim) - 1500 (the amount she has already swam) = 100.

She needs to swim 100 m more, which is 4 lengths because 100/25 = 4.

Answer:

40 bricks

Step-by-step explanation:

3 1/2×8

=28

56×20

=1,120

1,120÷28

=40 bricks

Answer:

1) b. an experimental study

2) a. μ1=μ2=μ3

3) a. MSE

4) MSTR =85.735

5) value of the F-statistics =7.472

6) b. 0.004

7) a. We reject the null hypothesis

8) b. Yes

Step-by-step explanation:

See the attached image

Answer:

(a)Yes, it is an exponential function.

(b)[tex]P(t)=200\cdot 2^{t/20}[/tex]

Step-by-step explanation:

(a)A population grows exponentially if it increases by a common ratio(called the growth ratio). We can see from the given information that the population of E.coli doubles every 20 minutes, therefore it is an exponential growth with a growth ratio of 2.

(b)The population, P(t) at any time t of an initial population, [tex]P_o[/tex]  with a growth ratio of r over a period k can be modeled using the function:

[tex]P(t)=P_o\cdot r^{t/k}[/tex]

In this Case:

[tex]P_o[/tex]=200

Growth rate,r=2

Growth Period,k=20 minutes

Therefore, the equation that models the function is:

[tex]P(t)=200\cdot 2^{t/20}[/tex] , t is in minutes

Jenny is correct that E. coli growth can be modeled with an exponential function, characterized by doubling in population size at regular time intervals. An equation representing this growth is N(t) = N0 x 2^(t/20), where N0 is the initial amount of E. coli and t is time in minutes.

I agree with Jenny, the E. coli growth can indeed be modeled with an exponential function. This is supported by the fact that the E. coli population doubles after each consistent time period (20 minutes). In an exponential growth model, the rate of increase of a population is proportional to the current population size, which means as the population gets larger, it grows at an even faster rate.

Part B: Equation of Exponential Growth:

The exponential growth model for a population starting with N0 individuals and a growth rate r can be described by the equation N(t) = N0ert, where N(t) is the population at time t, N0 is the initial population size, e is the base of the natural logarithm, and r is the growth rate per unit time. For E. coli, with a doubling time of 20 minutes, the growth rate can be calculated using the doubling formula: Td = ln(2)/r, solving for r gives r = ln(2) / 20 minutes. The continuous exponential growth equation can be simplified to a discrete model for this case: N(t) = N0 * 2(t/20), where t is given in minutes.

Answer:

51.02 metres

Step-by-step explanation:

The pictorial representation of the problem is attached.

We are required to find the distance from the worker to the top of the pole, |DA| in the diagram.

In Triangle ABC

[tex]Tan 68^\circ =\frac{|AB|}{|BC|}\\Tan 68^\circ =\frac{|AB|}{31}\\|AB|=31 X Tan 68^\circ=72.73m[/tex]

In Triangle BCD

[tex]Tan 35^\circ =\frac{|BD|}{|BC|}\\Tan 35^\circ =\frac{|BD|}{31}\\|BD|=31 X Tan 35^\circ=21.71m[/tex]

The distance, |DA| =|AB|-|BD|

=72.73-21.71

=51.02 metres

The distance from the worker to the top of the pole is 51.02 metres.

Answer:

Hello dear, your question might not be complete, but if you want to know the expanded notation form for the numbers given, here they are;

(1). 20 + 3.

(2). 10 + 9.

(3). 100 + 0 + 0

Step-by-step explanation:

Expanded notation can simply be defined as the depiction of numbers or digits for what they are really are that is to say the representation of the values of numbers or digits. The numbers can be shown or represented from ones, through to hundreds and many more.

For the numbers given in this question, below are the expanded notation form;

(1). 20 × 1 + 3 × 1 = Expanded Factors Form.

20 + 3 = Expanded Notation Form.

(2). 10 ×1 + 9 × 1 = Expanded Factors Form.

10 + 9 = Expanded Notation Form.

(3). 100 × 1 + 0 × 10 + 0 × 1 = Expanded Factors Form.

100 + 0 + 0 = Expanded Notation Form.

Step-by-step explanation:

Let me know if it's all right! Good luck

Answer:

405

Step-by-step explanation:

To find sample size, use the following equation, where n = sample size, za/2 = the critical value, p = probability of success, q = probability of failure, and E = margin of error.

[tex]n=\frac{(z_{\frac{\alpha }{2} })^{2} *p*q }{E^2}[/tex]

The values that are given are p = 0.84 and E = 0.03.

You can solve for the critical value which is equal to the z-score of  (1 - confidence level)/2.  Use the calculator function of invNorm to find the z-score.  The value will given with a negative sign, but you can ignore that.

(1 - 0.9) = 0.1/2 = 0.05

invNorm(0.05, 0, 1) = 1.645

You can also solve for q which is 1 - p.  For this problem q = 1 - 0.84 = 0.16

Plug the values into the equation and solve for n.

[tex]n =\frac{(1.645)^2*0.84*0.16}{(0.03)^2}\\n= 404.0997333[/tex]

Round up to the next number, giving you 405.

Answer:

Check the explanation

Step-by-step explanation:

Cost of over reserving full cost tickets, Co = $440 ( empty seats as we cannot get even the discounted revenue)

Cost of under reserving Cu = 770-440 = $330 ( because you sell more discounted tickets)

Now critical ratio = Cu / (Cu+Co) = 330/770 = 0.42857

Now for above critical ratio ,z = -0.18 ( refer standard normal distribution table)

Optimal protection level = mean +z*standard deviation = 100-0.18*25 = 95.5 = 96

The possible costs include: all the above. You may need to provide compensation to passenger and make alternative travel arrangements. Also passenger won't be happy by over booking and their will be loss of good will.

Answer:

Step-by-step explanation:

Let the cost of a bag of popcorn=p

Let the cost of a drink=d

Mason spends a total of $45.75 on 3 bags of popcorn and 6 drinks.

Christian spends a total of $71.50 on 6 bags of popcorn and 4 drinks.

The required system of equations is:

Multiply the first equation by 2 to eliminate p

6p+12d=91.5

6p+4d=71.50

Subtract

8d=20

d=20/8=$2.5

Substitute d=2.5 into any of the equations to obtain p.

6p+12d=91.5

6p+12(2.5)=91.5

6p=91.5-12(2.5)

6p=91.5-30

6p=61.5

Divide both sides by 6

p=$10.25

Therefore:

Answer:

Ermm here I graphed it :)

Sorry for dark mode..

Answer:

The answers below ._.

Step-by-step explanation:

A secant is a line that intersects a circle in exactly two points. When a tangent and a secant, two secants, or two tangents intersect outside a circle then the measure of the angle formed is one-half the positive difference of the measures of the intercepted arcs.

The formation of secant lines that intersect within a circle is related when a secant and a tangent or two tangents intersect each other outside a circle.

A secant line is a straight line that connects two points on a curve. The secant line approaches a tangent line when the two points are drawn together.

So, If a tangent and a secant, or two tangents intersect at the exterior side of a circle, the angle created has a measure equal to one-half the positive difference between the intercepted arcs' measures.

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Answer:

-6

Step-by-step explanation:

simplify

Answer:

95

Step-by-step explanation:

yeah

Answer:

0.8

Step-by-step explanation:

the opposite of a negative is the positive version of the number

Answer:

the opposite of -0.8 is 0.8

Step-by-step explanation:

opposite of a negative number is the same number but positive or vice verse

Answer:

B…

Step-by-step explanation:

Answer:

16 cakes

Step-by-step explanation:

If you do 6 divided by 3/8, you would get 16, which is the amount of cakes that Kevin will be able to make.

Answer:

We conclude that the percentage of employed workers who have registered to vote exceeds the percentage of unemployed workers who have registered to vote.

Step-by-step explanation:

We are given that 513 employed persons and 604 unemployed persons are independently and randomly selected, and that 287 of the employed persons and 280 of the unemployed persons have registered to vote.

Let [tex]p_1[/tex] = percentage of employed workers who have registered to vote.

[tex]p_2[/tex] = percentage of unemployed workers who have registered to vote.

So, Null Hypothesis, [tex]H_0[/tex] : [tex]p_1\leq p_2[/tex]      {means that the percentage of employed workers who have registered to vote does not exceeds the percentage of unemployed workers who have registered to vote}

Alternate Hypothesis, [tex]H_A[/tex] : [tex]p_1>p_2[/tex]     {means that the percentage of employed workers who have registered to vote exceeds the percentage of unemployed workers who have registered to vote}

The test statistics that would be used here Two-sample z test for proportions;

                          T.S. =  [tex]\frac{(\hat p_1-\hat p_2)-(p_1-p_2)}{\sqrt{\frac{\hat p_1(1-\hat p_1)}{n_1}+\frac{\hat p_2(1-\hat p_2)}{n_2} } }[/tex]  ~ N(0,1)

where, [tex]\hat p_1[/tex] = sample proportion of employed workers who have registered to vote = [tex]\frac{287}{513}[/tex] = 0.56

[tex]\hat p_2[/tex] = sample proportion of unemployed workers who have registered to vote = [tex]\frac{280}{604}[/tex] = 0.46

[tex]n_1[/tex] = sample of employed persons = 513

[tex]n_2[/tex] = sample of unemployed persons = 604

So, the test statistics  =  [tex]\frac{(0.56-0.46)-(0)}{\sqrt{\frac{0.56(1-0.56)}{513}+\frac{0.46(1-0.46)}{604} } }[/tex]

                                       =  3.349

The value of z test statistics is 3.349.

Now, at 0.05 significance level the z table gives critical value of 1.645 for right-tailed test.

Since our test statistic is more than the critical value of z as 3.349 > 1.645, so we have sufficient evidence to reject our null hypothesis as it will fall in the rejection region due to which we reject our null hypothesis.

Therefore, we conclude that the percentage of employed workers who have registered to vote exceeds the percentage of unemployed workers who have registered to vote.