Where does f(x) = 3x2 – 11x – 4 intersect the x-axis? The negative x-intercept is at ( , 0). The positive x-intercept is at ( , 0).
Answers
The function f(x) = 3x^2 - 11x - 4 is a quadratic equation; the negative x-intercept is at (-1/3,0) and the positive x-intercept is at (4,0)
What is the x-intercept?The x-intercept of a function is the point where the function crosses the x-axis
Check below on how to determine the x-intercept
The function is given as:
f(x) = 3x^2 - 11x - 4
Next, we plot the graph of the function
From the attached graph, the function crosses the axis at:
(-1/3,0) and (4,0)
Hence, the negative x-intercept is at (-1/3,0) and the positive x-intercept is at (4,0)
Read more about x-intercept at:
https://brainly.com/question/3951754
Related Questions
An omelet station uses 3 eggs to make each omelet. What is the cost for the total number of eggs in a single omelet if a case of 30 dozen eggs has an as-purchase cost of 32.40?
Answers
A direct variation function contains the points (2, 14) and (4, 28). Which equation represents the function?
Answers
so, in short, what's the equation of the line that runs through 2,14 and 4,28?
[tex]\bf \qquad \qquad \textit{direct proportional variation}\\\\ \textit{\underline{y} varies directly with \underline{x}}\qquad \qquad y=kx\impliedby \begin{array}{llll} k=constant\ of\\ \qquad variation \end{array}\\\\ -------------------------------\\\\ \begin{array}{lllll} &x_1&y_1&x_2&y_2\\ % (a,b) &({{ 2}}\quad ,&{{ 14}})\quad % (c,d) &({{ 4}}\quad ,&{{ 28}}) \end{array}[/tex]
[tex]\bf slope = {{ m}}= \cfrac{rise}{run} \implies \cfrac{{{ y_2}}-{{ y_1}}}{{{ x_2}}-{{ x_1}}}\implies \cfrac{28-14}{4-2}\implies \cfrac{14}{2}\implies 7 \\\\\\ % point-slope intercept \stackrel{\textit{point-slope form}}{y-{{ y_1}}={{ m}}(x-{{ x_1}})}\implies y-14=7(x-2) \\\\\\ y-14=7x-14\implies y=7x[/tex]
we know that
A relationship between two variables, x, and y, represent a direct variation if it can be expressed in the form [tex]\frac{y}{x}=k[/tex] or [tex]y=kx[/tex]
In this problem we have
Points [tex](2,14)[/tex] and [tex](4,28)[/tex]
so
Find the value of k
First point
[tex]\frac{14}{2}=k[/tex]
[tex]k=7[/tex]
Second point
[tex]\frac{28}{4}=k[/tex]
[tex]k=7[/tex]
the function is
[tex]y=kx[/tex] --------> substitute the value of k
[tex]y=7x[/tex]
therefore
the answer is
[tex]y=7x[/tex]
In this problem with a single point was sufficient to calculate the equation, since in a direct variation the line passes through the origin, it is not necessary to use the formula of the slope
will mark brainliest!!
solve this system of linear equations. separate the x- and y- values with a coma. 9x=27-9y
20x=71-9y
Answers
9x = 27-9y
20x=71-9y
Let's use the "elimination through addition/subtraction method.
Multiply the first equation by -1 so as to obtain +9y:
-9x = -27 + 9y
20x= 71- 9y
--------------------
Add these 2 equations together:
-9x = -27 + 9y
20x= 71- 9y
--------------------
11x = 44
Solve this for x: x = 44/11 = 4.
Now find y by subst. 4 for x in either of the original equations.
Using the second equation:
20x=71-9y
20(4) = 71 - 9y
80-71 = -9y
9 = -9y. Then y = -1.
The solution set is (4,-1).
What is the mean of the high temperatures, in degrees Fahrenheit, for the week? Show your work.
Answers
-14 is the sum, divided by 7 = -2
The mean is -2.
can someone please help with transformations of parent functions
Answers
[tex]\bf \bullet \textit{ stretches or shrinks horizontally by } {{ A}}\cdot {{ B}}\\\\ \bullet \textit{ flips it upside-down if }{{ A}}\textit{ is negative}\\ \left. \qquad \right. \textit{reflection over the x-axis} \\\\ \bullet \textit{ flips it sideways if }{{ B}}\textit{ is negative}\\ \left. \qquad \right. \textit{reflection over the y-axis}[/tex]
[tex]\bf \bullet \textit{ horizontal shift by }\frac{{{ C}}}{{{ B}}}\\ \left. \qquad \right. if\ \frac{{{ C}}}{{{ B}}}\textit{ is negative, to the right}\\\\ \left. \qquad \right. if\ \frac{{{ C}}}{{{ B}}}\textit{ is positive, to the left}\\\\ \bullet \textit{ vertical shift by }{{ D}}\\ \left. \qquad \right. if\ {{ D}}\textit{ is negative, downwards}\\\\ \left. \qquad \right. if\ {{ D}}\textit{ is positive, upwards}\\\\ \bullet \textit{ period of }\frac{2\pi }{{{ B}}}[/tex]
that said, compressing vertical |x| by a factor of 4, means A = 4, thus is 4|x|.
What value of x is in the solution set of 2(3x – 1) ≥ 4x – 6?
Answers
It can be convenient to subtract the right side of the inequality from both sides.
... 2(3x -1) -(4x -6) ≥ 0
... 2x +4 ≥ 0 . . . . . . . . . collect terms
... x +2 ≥ 0 . . . . . . . . . . divide by the coefficient of x
... x ≥ -2 . . . . . . . . . . . . add the opposite of the constant
Any value of x that is at least -2 will be in the solution set.
The diagram shows a square of side 7 cm with two quadrants drawn inside. Find the area of the shaded region. (take pi= 22/7)
Answers
A = r ² π - a²
where: r = d/2 = 7√2 / 2
A = ( 7√2 / 2 )² · 22/7 - 7²
A = 49 · 2 / 4 · 22/7 - 49
A = 49/2 · 22/7 - 49
A = 7 · 11 - 49
A = 77 - 49
Answer: A (shaded) = 28
Sally's soccer team won 68% of the games they played.if they won 17 games, how many did they play?
Answers
Then 0.68x = 17. Mult. both sides by 100: 68x = 1700.
Divide 68 into 1700 to obtain x, the number of games played: x = 25
The team plays in 25 games.
Answer: The total number of games played are 25
Step-by-step explanation:
Let the total number of games played be 'x'
We are given:
Number of games won = 17
Percentage of games won = 68 %
Calculating the total number of games:
[tex]68\% \text{ of x}=17[/tex]
So,
[tex]\frac{68}{100}\times x=17\\\\x=\frac{17\times 100}{68}=25[/tex]
Hence, the total number of games played are 25
Javier had $305 in his bank account. His bank charges a fee of $7.50 each month that a balance is below $500. If he makes no other deposits or withdrawals, how much money is in Javier’s account at the end of three months?
Answers
305 - 22.50 = 282.50
Answer: [tex]\$282.5[/tex]
Step-by-step explanation:
Given : Javier had $305 in his bank account.
His bank charges a fee of $7.50 each month that a balance is below $500.
If he makes no other deposits or withdrawals, then the amount of deductions in Javier’s account at the end of three months will be :-
[tex]\$7.50\times3=\$22.5[/tex]
Now, the amount of money in Javier’s account at the end of three months :-
[tex]\$305-\$22.5=\$282.5[/tex]
Determine whether each of these sets is the power set of a set, where a and b are distinct elements.
a.∅
c.{∅,{a},{∅,a}}
Answers
(No part b?)
c. Also not the power set of any set, because any power set must have [tex]2^n[/tex] elements, where [tex]n[/tex] is the cardinality of the original set. The cardinality of this set is 3, but there is no integer [tex]n[/tex] such that [tex]2^n=3[/tex]. This set would be a power set if [tex]\{\varnothing\}[/tex] (that is, the set containing the empty set) were a member of it.
Find the probability that in a family of 4 children there will be
a.at least 1 boy
b.at least 1 boy and at least 1 girl
c.out of 2000 families with 4 children each how many would you expect to have 1 or 2 girls. assume that the probability of a male birth is 1/2.
Answers
Mary invests £12000 in a saving account. The account pays 1.5% compound interest per year. Work out the value of her investment after 2 years.
Answers
To find the value of Mary's investment after 2 years in a saving account with compound interest, we can use the compound interest formula. Substituting the given values into the formula gives us £12363.61.
Explanation:To calculate the value of Mary's investment after 2 years, we can use the compound interest formula: A = P(1 + r/n)^(nt), where:
A is the final amountP is the principal amount (initial investment)r is the annual interest rate (as a decimal)n is the number of times the interest is compounded per yeart is the number of yearsIn this case, the principal amount is £12000, the annual interest rate is 1.5% (0.015 as a decimal), and the number of times the interest is compounded per year is 1. Plugging these values into the formula, we get:
A = 12000(1 + 0.015/1)^(1*2)
Simplifying this, we get:
A = 12000(1.015)^2
Calculating further, we get:
A ≈ 12000(1.030225) ≈ £12363.61
Therefore, the value of Mary's investment after 2 years is approximately £12363.61.
Its number 15. Thank you
Answers
Factoring like this is simply the distributive property in reverse. We can check if we did the factoring right by distributing the outer term x back into the inner terms
Let's multiply the outer x by each of the inner terms (a, b and d)
x times a = ax
x times b = bx
x times d = dx <--- the result should be d and not dx
-----------------------------------------------------------------------------
Here is the proper way to solve for x. We first need to move the d over, which is done by subtracting d from both sides. Once all of the x terms are on one side, we can finally factor out the x. Then after that we divide both sides by the quantity (a+b)
k = ax + bx + d
k - d = ax + bx + d - d
k - d = ax + bx
k - d = x(a + b)
(k - d)/(a + b) = x(a + b)/(a + b)
(k - d)/(a + b) = x
x = (k - d)/(a + b)
The final answer is
x = (k - d)/(a + b)
which can be written as
[tex]x=\frac{k-d}{a+b}[/tex]
If you choose to use the first option, then make sure you use parenthesis as shown. The parenthesis are important to make sure that you divide all of "k-d" over all of "a+b" as one big fraction.
Determine which of these relations are transitive. the variables x, y, x', y' represent integers.
Answers
Find the specified element in the inverse of the given matrix
Answers
you didn't show a matrix.
the components of the matrix are the elements.
and the elements of the inverse matrix are the elements of the inverse matrix
1)
so if matrix A is 1 4 1
2 5 2
3 6 3
2)
14114
25225
36336
3)
15 24 12
15 12 24
4)
[A]=(15+24+12=51)-(15+12+24=51)
[A]=0
5)
52 23 25
63 23 36
41 11 14
63 33 36
41 12 14
52 12 25
6)
15-12 6-6 12-15
12-6 3-3 6-12
8-5 2-2 5-8
7)
3 0 -3
6 0 -6
3 0 -3
8)
(+)3 (-)0 (+)-3
(-)6 (+)0 (-)-6
(+)3 (-)0 (+)-3
=
3 0 -3
-6 0 6
3 0 -3
9)
3 -6 3
N= 0 0 0
-3 6 -3
10) the inverse of [A]= 1/|A|*[N]
which is in this case ⁻A= 0
because |A|=0
The three tools the Federal Reserve uses to enact monetary policy are:
Answers
Hey there! Hope this helps!
Why do you round 117290 up to 120000
Answers
James covers a distance of 8 meters in the first second of a 100 meter race. Then, he sprints at a speed of 9 meters per second. How far is James from the finish line 9 seconds after the race has started? a. 11 c. 28 b. 20 d. 80
Answers
9 seconds after the race....so there are 8 seconds that he is sprinting 9 meters per second.....(8 * 9) = 72 meters....plus the 8 meters for the 1st second = (72 + 8) = 80 meters....
and if it is 100 meter race, and he has ran 80 meters, then that leaves 20 meters from the finish line....answer is D
Answer:
Option b. 20 meters
Step-by-step explanation:
James covers a distance of 8 meters in the first second of 100 meter race.
Then, he sprints at a speed of 9 meters per second.
We have to find how far is James from the finish line 9 seconds after the start of the race.
James covers distance in first second = 8 meters.
Time remaining in 9 seconds after running 8 meter = 9 - 1 = 8 seconds.
In another 8 seconds James covers the distance = speed × time
= 9 × 8 = 72 meters
Total distance covered in 9 seconds = 8 + 72 = 80 meters
Distance remaining in 100 meter race after 9 seconds = 100 - 80 = 20 meters.
James is 20 meters far from the finish line 9 seconds after the race has started.
Option b. 20 meters is the answer.
Explain how to solve 2x + 7 = 15
Answers
Please help me to Evaluate P(6,2)
Answers
The value of the permutation [tex]_6P_2[/tex] equals 30.
The notation P(n,r) represents the number of permutations of r elements taken from a set of n distinct elements.
The formula for permutations is expressed as:
[tex]P(n,r) = \frac{n!}{(n-r)!}[/tex]
Given the permutations:
[tex]_6P_2[/tex]
n = 6 and n = 2:
Plug these into the above formula:
[tex]P(n,r) = \frac{n!}{(n-r)!}\\\\P(n,r) = \frac{6!}{(6-2)!}\\\\P(n,r) = \frac{6!}{4!}\\\\P(n,r) = \frac{6*5*4*3*2*1}{4*3*2*1}\\\\P(n,r) = \frac{6*5}{1}\\\\P(n,r) = 30[/tex]
Therefore, the value of [tex]_6P_2[/tex] is 30.
what is 5.62 rounded to?
use all place values.
Answers
Evaluate the line integral c y3 ds,
c.x = t3, y = t, 0 ≤ t ≤ 3
Answers
Take [tex]u=1+9t^4[/tex] so that [tex]\mathrm du=36t^3\,\mathrm dt[/tex]. Then
[tex]\displaystyle\int_{\mathcal C}y^3\,\mathrm dS=\frac1{36}\int_{u=1}^{u=730}\sqrt u\,\mathrm du=\frac{730^{3/2}-1}{54}[/tex]
The sutton police department must write, on average, 6 tickets a day to keep department revenues at budgeted levels. suppose the number of tickets written per day follows a poisson distribution with a mean of 6.5 tickets per day. interpret the value of the mean.
Answers
If λ = the average number of event occurring within the given interval, then
[tex]P(k \, events) = e^{-\lambda } ( \frac{\lambda ^{k}}{k!} )[/tex]
For the given problem,
λ = 6.5, average number of tickets per day.
k = 6, the required number of tickets per day
The Poisson distribution is
[tex]P(k \, tickets/day)=e^{-6.5} ( \frac{6.5 ^{k}}{k!} )[/tex]
The distribution is graphed as shown below.
Answer:
The mean is λ = 6.5 tickets per day, and it represents the expected number of tickets written per day.
The required value of k = 6 is less than the expected value, therefore the department's revenue target is met on an average basis.
Present 5 mixed numbers that add up to the whole number 10.
Answers
4 1/3 + 5 2/3 = 10
6 1/4 + 3 3/4 = 10
9 3/5 + 2/5 = 10
2 8/10 + 7 1/5 = 10
hope this helps
Tickets for rides at the fair cost $0.75 each you can also buy a roll of 25 tickets for $15 what is the cost of each ticket if you buy a roll of tickets
Answers
all you need to do is take the cost and divide it by the number of tickets.
$15 ÷ 25 tickets = $0.60 per ticket
Final answer:
The cost per ticket when buying a roll of 25 tickets for $15 at the fair is $0.60, which is less than the single ticket price of $0.75.
Explanation:
The student has asked about the cost of each ticket if bought in a roll at a fair. To find the cost per ticket when purchasing a roll of 25 tickets for $15, you simply divide the total cost of the roll by the number of tickets in the roll.
Cost per ticket = Total cost of the roll / Number of tickets in the roll
Cost per ticket = $15 / 25
Cost per ticket = $0.60
Therefore, when buying a roll of tickets, the cost of each ticket is $0.60, which offers a saving compared to the single ticket price of $0.75.
sum of the interior angle measures of the polygon with 9 sides
Answers
The sum of interior angles for any polygon is:
(n - 2) x 180
Where 'n' is the number of sides.
In this case, the polygon is a nonagon, which has 9 sides.
Substitute the value in:
(9 - 2) x 180 = ?
Solve:
Sum of interior angles = 1260°.
Hope This Helps You!
Good Luck :)
- Hannah ❤
Answer: 1260
Step-by-step explanation:
The sale price of an item is $45 after a 40% discount is applied. What is the original price of the item?
Answers
$45/60% = $75 was the original sales price.
The original price of the item is $75.
Suppose the original price of the item =x
Discount =40%
What is the percentage?The percentage is the value per hundred.
Given discounted price or sale price of the item =$45
This means [tex]x-\frac{x*40}{100} =45[/tex]
[tex]\frac{60x}{100} =45[/tex]
[tex]\frac{3x}{5} =45[/tex]
[tex]x=75[/tex]
So, the original price of the item =$75
Hence, the original price of the item is $75.
To get more about the percentage visit:
https://brainly.com/question/24304697
How many real solutions does the system have Y=-3x-3 Y=x^2-3x+5
Answers
Y= x^2 -3x + 5 has no real solutions because b^2 - 4ac, the discriminant, is less than zero.
To obtain the solutions for both, you'll have to solve them for x. The first equation is linear, so obtaining a solution there is fairly straightforward, and you're guaranteed to get one real solution there. The second equation is a little more involved, and we'll need the quadratic formula to settle that one out. You might remember from earlier math classes that the quadratic formula gives you a way to quickly find the roots of a particular quadratic equation. Here's the full thing:
[tex]x= \frac{-b\pm\sqrt{b^2-4ac}}{2a} [/tex]
For the sake of this question, the only part we're concerned with is the [tex]b^2-4ac[/tex] bit, which is referred to as the descriminant of the quadratic. If [tex]b^2-4ac \geq 1[/tex], we'll have two real solutions, since we'll need to evaluate the square root of the term for both positive and negative outcomes. If [tex]b^2-4ac=0[/tex], we only have one real solution, since adding and subtracting 0 from the [tex]-b[/tex] term have the same effect. If [tex]b^2-4ac \ \textless \ 0[/tex], we have no real solutions; the discriminant is nested inside a square root, and taking the square root of a negative number only produces imaginary results.
With that in mind, let's look at the discriminant of [tex]x^2-3x+5[/tex].
Looking at the coefficients and constant, we have a=1, b=-3, and c=5, which makes our discriminant
[tex](-3)^2-4(1)(5) = 9-20=-11[/tex]
-11 is less than 0, so we have no real solutions to the second equation. This means that our first equation is the only one with a real solution, so the total number of real solutions for the system is 1.
which algebraic expression represents the "phrase the quotient of -8 and the sum of a number and three"
A -8/g+3
B 8/g+3
C -8+g/3
D -8/g +3
Answers
-8
-------------------------- This most closely resembles answer choice "A."
n + 3
I have used "n" instead of "g" here.
The algebraic expression represents the given phrase is -8/(g+3). Therefore, option A is the correct answer.
The given phrase is "the quotient of -8 and the sum of a number and three".
We need to identify which algebraic expression represents the given phrase.
What is an algebraic expression?Algebraic expressions are the mathematical statement that we get when operations such as addition, subtraction, multiplication, division, etc. are operated upon on variables and constants.
Let the unknown number be g.
Now, the quotient of -8 and the sum of a number and three=-8/(g+3)
The algebraic expression represents the given phrase is -8/(g+3). Therefore, option A is the correct answer.
To learn more about an expression visit:
brainly.com/question/16804733.
#SPJ2
The formula f=5280m can be used to convert a measurement of f feet to an equivalent measurement m miles. If an airplane flies at 21,120 feet above the ground, how much is that in miles?
A. 4 miles
B. 5.3 miles
C. 111, 513, 600 miles
D. 132, 620, 600 miles
Answers
21,120/5280=4