What particles are responsible for nearly all the mass of an atom?

Answer:

The moving car transfers Kinetic Energy to the parked car

Explanation:

Options are not supplied here but I have previously answered this question in a test and these options were supplied.

A) The moving car transfers kinetic energy to the parked car.

B) Kinetic energy in the moving car disappears.

C) Kinetic energy in the parked car is created.

D) The parked car transfers kinetic energy to the moving car.

A) This option provides us with the true outcome, the moving car transfers Kinetic energy to the parked car. This is in agreement with the law of conservation of energy. A transference of energy is the outcome of this event.

B) Kinetic energy cannot disappear, this is because according to the law of conservation of energy, energy can neither be created nor destroyed.

If energy disappears, this would imply that energy is destroyed which is not agreeable.

C) Kinetic energy in the parked car is created... Just like the option B above, and according to the above stated law, energy can neither be created nor destroyed. It is also not agreeable here that energy is created.

D) Energy can be transferred but, "a parked car indicates that the car only has potential energy" and as such cannot transfer kinetic energy to the moving car since it does not possess kinetic energy.

Final answer:

To find the velocity of a quarter dropped from a tower after 10 seconds, we use the formula for velocity in free fall, resulting in a final velocity of 100 m/s.

Explanation:

The question is about determining the velocity of a quarter dropped from a tower after 10 seconds. To solve this, we use the formula for velocity in free fall, v = gt, where g is the acceleration due to gravity (approximated as 10 m/s²) and t is the time in seconds. In this case, after 10 seconds, the velocity can be calculated as follows:

g = 10 m/s² (approximation of the acceleration due to gravity)

t = 10 seconds

Substitute the values into the formula: v = gt = 10 m/s² × 10 s = 100 m/s.

Therefore, the velocity of the quarter after falling for 10 seconds is 100 m/s.

Answer:

Work done on the box is 490 joules.

Explanation:

It is given that,

Mass of the box, m = 5 kg

Initial speed of the box, u = 0

Acceleration of the box, [tex]a=2\ m/s^2[/tex]

Time taken, t = 7 s

The force is calculate using the product of mass and acceleration. It is given by :

F = ma

[tex]F=5\ kg\times 2\ m/s^2=10\ N[/tex]

Let d is the distance covered by the box. Using the equation of motion as :

[tex]d=ut+\dfrac{1}{2}at^2[/tex]

[tex]d=\dfrac{1}{2}\times 2\ m/s^2\times (7\ s)^2[/tex]

d = 49 m

The product of force and distance is equal to the work done on the box. It is given by :

[tex]W=F\times d[/tex]

[tex]W=10\ N\times 49\ m[/tex]

W = 490 joules

So, the work done on the box is 490 Joules. Hence, this is the required solution.

The net work done on the box weighing 5.0 kg and accelerated from rest by a force across a floor is 490 Nm.

Given the following data:

To find the net work done on the box:

First of all, we would determine the force acting on the box:

[tex]Force = Mass[/tex] × [tex]acceleration[/tex]

[tex]Force = 5[/tex] × [tex]2[/tex]

Force = 10 Newton

Next, we would use the second equation of motion to determine the distance traveled by the box:

[tex]S = ut+ \frac{1}{2}at^2[/tex]

Where:

Substituting the given parameters into the formula, we have;

[tex]S = 0(7)+ \frac{1}{2}(2)(7^2)\\\\S = 0 + 49[/tex]

Distance, S = 49 meters.

Now, we can determine the net work done on the box:

[tex]Work\; done = Force[/tex] × [tex]distance[/tex]

[tex]Work\; done = 10[/tex] × [tex]49[/tex]

Work done = 490 Nm

Therefore, the net work done on the box is 490 Nm.

Answer: the boat is more dense in salt water

Explanation:

The statement is false; objects fall toward Earth at roughly 9.8 m/s² due to gravity, not centripetal force. Gravity is a force that causes objects to accelerate towards the Earth, while centripetal force relates to circular motion.

The statement that objects fall toward Earth at a rate of 9.8 m/s because of centripetal force is false. Objects in freefall near the Earth's surface accelerate downwards at approximately 9.8 m/s² due to the force of gravity, not centripetal force. Centripetal force is related to the circular motion of an object and is the force that acts on an object moving in a circular path, directed towards the center around which the object is moving.

It is important to note that the acceleration of 9.8 m/s², commonly represented as g, is somewhat an approximation. This value can slightly vary depending on the distance from the center of the Earth and the density of the Earth's crust in different locations. Nonetheless, for most practical purposes, especially in educational environments, g is considered to be a constant value.

Newton's Universal Theory of Gravity explains that this acceleration due to gravity is expected because the force of gravity, and thus the acceleration of an object, is inversely proportional to the square of its distance from the center of the Earth. Objects at or near the Earth's surface, like falling apples, typically experience this acceleration of 9.8 m/s².

the answer is water and plants

Hydrogenated oil, derived from plants, is used to produce margarine. The hydrogenation process converts liquid vegetable oils into solid or semi-solid fats, making them more stable for use in products like margarine.

The natural resource used to produce margarine is hydrogenated oil. Hydrogenation is a chemical process that converts liquid vegetable oils into solid or semi-solid fats, which are more stable. Margarine is made by reacting these oils (from plants like sunflowers, canola, or soy) with hydrogen. This is in the presence of a catalyst, usually a metal. The hydrogenation process solidifies the oils and changes their nutritional profile.

While water can be a component in the production process and plants are the source of the vegetable oils used, it's the hydrogenated oil that is the primary ingredient.

Butter, on the other hand, is not used in the production of margarine as it is an animal product and margarine is created as a plant-based alternative to it.

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The plane's speed in relation to the speed of sound, called Mach number, can be determined by dividing the plane's speed by the speed of sound.

The speed of a plane in relation to the speed of sound, often referred to as Mach number, is determined by dividing the plane's speed by the speed of sound. An airplane flying at the speed of sound would thus be flying at Mach 1. If the plane is flying faster than the speed of sound, it is considered to be supersonic. For instance, if the speed of the plane is 662 m/s, that would be Mach 2 as it is twice the speed of sound which is 331 m/s.

Therefore, to find the plane's speed in terms of the speed of sound, you would divide the plane's speed by 331 m/s.

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To express the plane's speed in terms of the speed of sound, we use the Mach number. If the speed of sound in air is 340 m/s, a plane traveling at Mach 2.00 is moving at 680 m/s (2 x 340 m/s).

The speed of sound in air is variable, depending on temperature and atmospheric pressure but is approximately 340 m/s at sea level at 21°C. When we talk about aircraft speeds, we often refer to their speed in terms of their Mach number, which is the ratio of the object's speed to the speed of sound. For instance, an aircraft flying at Mach 1 is traveling exactly at the speed of sound for those conditions, while Mach 2 indicates it is traveling twice the speed of sound. Therefore, if the speed of sound is 340 m/s and a plane is traveling at Mach 2, its speed is simply calculated by doubling the speed of sound, which gives us a velocity of 680 m/s. This is why an observer might hear a sonic boom without seeing the plane: it has passed by before the sound reaches the observer. Changes in air temperature also affect the speed of sound, so when a supersonic aircraft transitions from warmer to colder air, adjustments in velocity must be made to maintain the same Mach number due to the changed speed of sound.

Distance is the length of the path traveled, while displacement is the straight-line distance between the initial and final position, considering both magnitude and direction.

Distance is the length of the path traveled by an object, while displacement is the straight-line distance from the initial to the final position, regardless of the path taken. Displacement includes both magnitude and direction, whereas distance only considers magnitude.

For example, if a person walks 5 meters to the east and then 3 meters to the west, their displacement would be 2 meters to the east, as it considers the overall change in position. However, the total distance traveled would be 8 meters, as it accounts for the entire path traveled.

It is important to note that displacement is a vector quantity, meaning it has both magnitude and direction, while distance is a scalar quantity with only magnitude.

A. The time to catch up to the empty box car is about 2.8 s

B. The distance traveled to reach the box car is about 14 m

Acceleration is rate of change of velocity.

[tex]\large {\boxed {a = \frac{v - u}{t} } }[/tex]

[tex]\large {\boxed {d = \frac{v + u}{2}~t } }[/tex]

a = acceleration ( m/s² )

v = final velocity ( m/s )

u = initial velocity ( m/s )

t = time taken ( s )

d = distance ( m )

Let us now tackle the problem !

Given:

Acceleration of car = a = 3.8 m/s²

Initial Velocity of car = u = 0 m/s

Velocity of train = vt = 5.0 m/s

Unknown:

A . Time Taken = t = ?

B. Distance = d = ?

Solution:

Firstly, we calculate for the distance traveled by the car until it reaches a maximum speed of 8 m / s.

[tex]v^2 = u^2 + 2ad_1[/tex]

[tex]8^2 = 0^2 + 2(3.8)d_1[/tex]

[tex]64 = 7.6d_1[/tex]

[tex]\boxed {d_1 = \frac{160}{19} ~ m}[/tex]

Next , we find time taken for the car to reach this maximum speed

[tex]v = u + a t[/tex]

[tex]8 = 0 + 3.8t'[/tex]

[tex]t' = 8 \div 3.8[/tex]

[tex]\boxed {t' = \frac{40}{19} ~ s}[/tex]

When trains and cars meet, then

[tex]d_{train} = d_{car}[/tex]

[tex]v_t \times t = d_1 + v_{max} \times (t - t')[/tex]

[tex]5t = \frac{160}{19} + 8(t - \frac{40}{19})[/tex]

[tex]5t = \frac{160}{19} + 8t - \frac{320}{19}[/tex]

[tex]5t = -\frac{160}{19} + 8t[/tex]

[tex]8t - 5t = \frac{160}{19}[/tex]

[tex]3t = \frac{160}{19}[/tex]

[tex]t = \frac{160}{19} \div 3[/tex]

[tex]t = \frac{160}{57} ~ s[/tex]

[tex]\large {\boxed {t \approx 2.8 ~ s} }[/tex]

[tex]d_{car} = -\frac{160}{19} + 8t[/tex]

[tex]d_{car} = -\frac{160}{19} + 8 \times \frac{160}{57} [/tex]

[tex]d_{car} = \frac{800}{57} ~ m[/tex]

[tex]\large {\boxed {d_{car} \approx 14 ~ m} }[/tex]

Grade: High School

Subject: Physics

Chapter: Kinematics

Keywords: Velocity , Driver , Car , Deceleration , Acceleration , Obstacle , Speed , Time , Rate

What is the quality of the sound of a fire truck’s siren when it moves away from a stationary hearer?

Its Low Pitched

Answer:

The pitch increases.

Explanation:

According to the Doppler effect, the apparent frequency of the waves is different when there is relative motion between the source and the observer. When the source and observer approach, the apparent frequency (pitch) increases whereas it decreases when they recede away.

Thus, when a fire truck moves towards a stationary hearer, the pitch of the siren appears to increase.

84 becuse if you do the equation right the results will conglude in 84 kj

M = 4 kg

s = 4.186 kJ/Kg °C

10°C to 15°C.

ᐃ t = 15°C. - 10°C

           = 5°C

Q= msᐃt

  = 4*4.186*5°C

  = 83.72 kJ

"Heat is the transfer of kinetic energy from one medium or object to another, or from an energy source to a medium or object. Such energy transfer can occur in three ways: radiation, conduction, and convection."

"The quantity of heat required to raise the temperature of one gram of a substance by one Celsius degree. The units of specific heat are usually calories or joules per gram per Celsius degree."

Know more about heat here

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Final answer:

The problem is a high school level physics kinematics question. It requires setting up two kinematic equations representing the motion of both cyclists and solving for the time when the second cyclist catches up.

Explanation:

The student is asking about the time it will take for a second cyclist to catch up to the leader in a race, given the leader's constant velocity and the second-place cyclist's velocity and acceleration. This is a physics problem involving kinematics, specifically equations of motion.

To solve this problem, you need to set the distances traveled by both cyclists equal to each other and solve for time. Since the first cyclist is moving at a constant velocity, the distance he travels can be represented by d1 = v1*t, where d1 is the distance, v1 is the velocity, and t is time. For the second cyclist with acceleration, you can use the formula d2 = v2*t + 0.5*a*t2, where d2 is the distance, v2 is the initial velocity, a is the acceleration, and t is the time.

Since the second cyclist has to cover an additional 11.4 m to catch up, we modify the equation for d2 to d2 = v2*t + 0.5*a*t2 + 11.4. Now you set d1 equal to d2 and solve for t using quadratic formula or other methods to find when both distances are the same, indicating the second cyclist has caught up.

Answer:

When there is an outlier in the data set, the dot plot or histogram will be skewed. In a skewed representation, the mean is pulled up or down toward the tail of the data. Therefore, skewed data affects the mean more than the median.

Explanation:

The dot plot or histogram will be skewed.

Answer:

lever

Explanation:

Answer:

meter and kilogram

Explanation:

As we know that there are seven fundamental SI units which are used to fine derived units

these are as following

1). Mass - Kilogram

2). Length - meter

3). Time - Seconds

4). Electric Current - Ampere

5). Amount of substance - Moles

6). Intensity of light - Candela

7). Temperature - Kelvin

Answer:

9.08

Explanation:

To calculate the mass of water that evaporates, we apply energy conservation between the heated iron block and the water. Heat transfers from the iron to the water until the water boils and some evaporates. Specific heat capacities and latent heat values are needed for a numerical solution.

To calculate the mass of water that boiled off when a 5kg block of iron is heated to 800℃ and placed in a tub containing 2 liters of water at 15℃, we apply the concept of conservation of energy. The heat lost by the iron block will be equal to the heat gained by the water, which will result in water reaching its boiling point and some of it evaporating. The specific heat capacity of water, the heat of vaporization of water, and the specific heat capacity of iron are crucial to these calculations.

We can denote the mass of water that evaporates as m, and calculate the heat required to raise the temperature of the remaining water from 15℃ to 100℃ and convert the m grams of water at 100℃ into steam. However, we need additional data such as the specific heat capacities and the latent heat of vaporization for water to provide a concrete answer. Without the specific values, we can only describe the methodology.

Answer:

amber

Explanation:

The term "electric" was coined from the word amber. This was when the Greeks found out that many materials become electric when they were rubbed with certain electric materials. In fact, there were two types of electric charge.

When amber was rubbed with fur, the material possessed what was known as resinous electricity. On the other hand, when the material was rubbed against silk, it acquired what was known as vitreous electricity.

Thus, it was thought that electricity was produced by friction of amber.

By breaking the problem into vertical and horizontal components, we determined the time the ball was in the air and used it to calculate the horizontal velocity. The ball was rolling off the desk at approximately 0.66 m/s. This involves understanding projectile motion in physics.

To determine how fast the baseball was rolling off the desk, we need to use principles of projectile motion. We can break the motion into horizontal (x-direction) and vertical (y-direction) components.

Vertical (y-direction) Analysis:

Horizontal (x-direction) Analysis:

Therefore, the ball was rolling off the desk at approximately 0.66 m/s.