What is 3,000 + 600 + 90 + 7 in standard form

➷ It would be [tex]-2\sqrt{6}[/tex]

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Answer:

The correct options are 1 and 2.

Step-by-step explanation:

The vertices of triangle are S(-4,4), T(-1,4), R(-1,1).

If triangle translated 2 units left,

[tex](x,y)\rightarrow (x-2,y)[/tex]

and then reflected over the y-axis,

[tex](x-2,y)\rightarrow (-x+2,y)[/tex]

The relation between image and preimage is

[tex](x,y)\rightarrow (-x+2,y)[/tex]                          ..... (1)

The vertices of image are

[tex]S(-4,4)\rightarrow S'(6,4)[/tex]

[tex]T(-1,4)\rightarrow T'(3,4)[/tex]

[tex]R(-1,1)\rightarrow R'(3,1)[/tex]

Therefore the vertices of image are S'(6,4),T'(3,4), R'(3,1).

1. A reflection over the y-axis and then a translation 2 units right is defined as

[tex](x,y)\rightarrow (-x+2,y)[/tex]

It is equivalent to relation 1, therefore option 1 is correct.

2. A 180 rotation about the origin, then a translation 2 units right, and then a reflection over the x-axis is defined as

[tex](x,y)\rightarrow (-x+2,y)[/tex]

It is equivalent to relation 1, therefore option 2 is correct.

3. A reflection over the y-axis and then a translation 2 units left is defined as

[tex](x,y)\rightarrow (-x-2,y)[/tex]

It is not equivalent to relation 1, therefore option 3 is incorrect.

4. A 180 rotation about the origin, then a translation 2 units left, and then a reflection over the x-axis is defined as

[tex](x,y)\rightarrow (-x-2,y)[/tex]

It is not equivalent to relation 1, therefore option 4 is incorrect.

5. A reflection over the x-axis and then a translation 2 units right is defined as

[tex](x,y)\rightarrow (x+2,-y)[/tex]

It is not equivalent to relation 1, therefore option 5 is incorrect.

6. A reflection over the x-axis and then a translation 2 units left is defined as

[tex](x,y)\rightarrow (x+2,-y)[/tex]

It is not equivalent to relation 1, therefore option 6 is incorrect.

Therefore the correct options are 1 and 2.

Answer:

1 and 2 are the correct answers.

Step-by-step explanation:

perpendicular means negative reciprocal so it would be -1/3

Answer:

slope = 0

Step-by-step explanation:

x = 3 is a vertical line parallel to the y- axis with undefined slope.

A line perpendicular to x = 3 is a horizontal line parallel to the x- axis with a slope of zero.

The surface area of a rectangular prism is SA = 2wl + 2lh + 2hw

Answer:

There is no prism

Step-by-step explanation:

The slope is undefined because it is a vertical line

Answer:

Step-by-step explanation:

The vertical line equation has the form x = a (a - any real number).

The vertical line has an undefined slope.

We have x = -4. It's a vertical line. Therefore, the slope is undefined.

3^2 = 9

3^4= 81

9 x 81 = 729

Your answer is 729 . Good luck (:

Answer:

Step-by-step explanation:

5^2(72-45)/5

25(27)/5

675/5

135

Final answer:

The evaluated expression of 5 to the second power (72 - 45) divided by 5 is 135. This is found by subtracting inside the parentheses, squaring the number 5, multiplying these results, and finally dividing by 5.

Explanation:

Evaluating the Expression

To evaluate the expression 5 to the second power (72 - 45) divided by 5, we follow the order of operations, often remembered by the acronym PEMDAS (Parentheses, Exponents, Multiplication and Division, Addition and Subtraction). First, we calculate the value within the parentheses:

72 - 45 = 27

Next, we raise 5 to the second power (also known as squaring a number):

52 = 5 × 5 = 25

Now, we multiply this result by the value we found within the parentheses:

25 × 27 = 675

Last, we divide by 5:

675 ÷ 5 = 135

Therefore, the evaluated expression is 135.

Answer:

the answer is 3/4

Step-by-step explanation:

Answer:

The correct answer is 3/4

Step-by-step explanation:

1/2+1/4=3/4

Answer:

The line y = 5x - 13, looks slanted right upwards

Step-by-step explanation:

To easily solve this question, we use a graphing tool, or a calculator to plot the graph.

Please see image below.

From looking at the graph, we know that the function is slanted right upwards.

Answer:

d). f(x)=-1/2x +6 (see attachment)

Step-by-step explanation:

I'm pretty sure the answer is D

Answer:

The answer is D

Step-by-step explanation:

To find the slope you do y2-y1/x2-x1. This will leave you with 3/1 which is equivalent to 3.

Answer:

A

Step-by-step explanation:

This is an even polynomial because both ends end up. This means the degree of the polynomial is even. This means b and c are not solutions since their degrees are odd.

To determine between A and D look at the x-intercepts. The x-intercepts of a polynomial graph have a special relationship with its equation. The x-intercepts are the solutions or roots of the factors. This means that when each factor is set equal to 0 and solved, its solution is an x-intercept. Here the x-intercepts are x = -1, 0,3. This means the factors are x(x+1)(x-3).

Notice at x = -1, the function touches but does not cross? This means the factor has an even exponent on it.

So the expression is likely x(x+1)^2 (x-3).

Since only one factor has an exponent, the answer is A.

[tex]\bold{Hey\ there!}[/tex]

[tex]\bold{Good\ luck\ on\ your\ assignment\ \& \ enjoy\ your\ day!}[/tex]

~[tex]\frak{LoveYourselfFirst:)}[/tex]

Answer:

Step-by-step explanation:

Two negatives make a positive, so -(-4) = +4. On a number line, -(-4) would be located 4 units to the right of 0.

The statement "It is 4 units to the right of 0" best describes the location of −(−4) on a number line.

When you have a double negative like −(−4), it becomes positive, so −(−4) is equal to 4, and it is 4 units to the right of 0 on the number line.

The statement "It is 4 units to the right of 0" accurately describes the location of −(−4) on a number line. When dealing with a double negative like −(−4),

it effectively becomes a positive value. In this case, −(−4) simplifies to 4. Therefore, the point −(−4) is located at the position corresponding to the number 4 units to the right of the origin, which is represented by 0 on the number line.

Moving to the right on the number line means increasing the numerical value, so, as a result, −(−4) is found 4 units to the right of 0.

This concept highlights the fundamental principle that negating a negative value results in a positive value, and the position of that positive value is to the right of the origin on the number line.

For similar question on number line.

https://brainly.com/question/24644930

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Final answer:

Explanation of values of t for which the given expression can be factored into binomials.t = 0; pairs of binomials: (x) and (3x + 8)

t = 1; pairs of binomials: (x + 1) and (3x + 8)

t = 2; pairs of binomials: (x + 2) and (3x + 4)

Explanation:

Values of t for which 3(x²) + tx + 8 can be factored into binomials: To factor this expression, we need to identify values of t that allow the expression to be split into two binomials that, when multiplied, give the original expression.

t = 0; pairs of binomials: (x) and (3x + 8)

t = 1; pairs of binomials: (x + 1) and (3x + 8)

t = 2; pairs of binomials: (x + 2) and (3x + 4)

Answer:

If it is a cube, the answer would be 76.7 .

Step-by-step explanation:

Answer:

Not entirely positive of about the answers, but all of the values would equal 15

First Y = 5

First X = 15

Second X = -3

Answer:

x / y

0/5

15/0

-3/6

Step-by-step explanation:

Answer:

20

Step-by-step explanation:

Answer:

i got 15.5

Step-by-step explanation:

Answer:

The pressure is [tex]20\ psi[/tex]

Step-by-step explanation:

we know that

A relationship between two variables, x, and y, represent an inverse variation if it can be expressed in the form [tex]y*x=k[/tex] or [tex]y=k/x[/tex]

In this problem we have

[tex]V*P=k[/tex]

where

V is the volume of a gas at a constant temperature

P is the pressure

we have

For [tex]V=100\ in^{3}[/tex],[tex]P=25\ psi[/tex]

step 1

Find the value of k

substitute the values of V and P

[tex]100*25=k[/tex]

[tex]k=2,500[/tex]

The equation is equal to  [tex]V*P=2,500[/tex]

step 2

Find the pressure when the volume is 125 cubic inches

For [tex]V=125\ in^{3}[/tex]

substitute in the equation and solve for P

[tex]125*P=2,500[/tex]

[tex]P=2,500/125=20\ psi[/tex]

Answer:

(A) [tex]x=60^{\circ}[/tex]

Step-by-step explanation:

Given: It is given that the circle P is circumscribed about quadrilateral ABCD and ∠BCD=120°.

To find: The value of x

Solution: It is given that the circle P is circumscribed about quadrilateral ABCD and ∠BCD=120°.

Now, we know that the sum of opposite angles in a cyclic quadrilateral is 180°, therefore

[tex]{\angle}BAD+{\angle}BCD=180^{\circ}[/tex]

substituting the given values, we get

[tex]x+120^{\circ}=180^{\circ}[/tex]

[tex]x=60^{\circ}[/tex]

Thus, the value of x is 60°.

Hence, option A is correct.

Answer: 60

Step-by-step explanation:

Answer:

$8.25

Step-by-step explanation:

We first need to find the amount of money we give the cashier

20+10 = 30

We give the cashier 30 dollars

Our bill was 21.75

30.00

-21.75

---------------

We need to borrow

2 10.00

-2 1  .75

---------------

We need to borrow

2 9. 10 0

-2 1  .7  5

---------------

We need to borrow

2 9. 9  10

-2 1  .7  5

---------------

  8 .2   5

We will get $8.25 back from the cashier

Answer:

Step-by-step explanation:

I gave total $20+$10= $30

$30-$21.75= $8.25

Answer:

C. x = -5.6 and x = -1.4

Step-by-step explanation:

The quadratic formula is [tex]x=\frac{-b+/-\sqrt{b^2-4ac} }{2a}[/tex]. Here a=1, b=7, and c=8.

Substitute and you'll have:

[tex]x=\frac{-b+/-\sqrt{b^2-4ac} }{2a} =\frac{-7+/-\sqrt{7^2-4(1)(8)} }{2(1)}=\frac{-7+/-\sqrt{49-32} }{2)}[/tex]

[tex]\frac{-7+/-\sqrt{17} }{2}=\frac{-7+/-4.1 }{2}= -1.4, -5.6[/tex]

Answer:

a is the _amplitude_(Length of the blades)_

The vertical shift, k, is the _Mill shaft height_

[tex]a = 15\ ft\\\\k = 40\ ft[/tex]

[tex]y = 15sin(\frac{\pi}{10}t) + 40[/tex]

Step-by-step explanation:

In this problem the amplitude of the sinusoidal function is given by the length of the blades.

[tex]a = 15\ ft[/tex]

The mill is 40 feet above the ground, therefore the function must be displaced 40 units up on the y axis. So:

[tex]k = 40\ ft[/tex]

We know that the blades have an angular velocity w = 3 rotations per minute.

One rotation = [tex]2\pi[/tex]

1 minute = 60 sec.

So:

[tex]w = \frac{3(2\pi)}{60}\ rad/s[/tex]

[tex]w = \frac{\pi}{10}\ rad/s[/tex]

Finally:

a is the _amplitude_(Length of the blades)_

The vertical shift, k, is the _Mill shaft height_

[tex]a = 15\ ft\\\\k = 40\ ft[/tex]

[tex]y = 15sin(\frac{\pi}{10}t) + 40[/tex]

Answer:

a is the length of the blade

the vertical shift , k, is the height of the windmill

a= 15 k= 40

the period is 20 seconds

b = pi/10

y=15sin(π/10t)+40

Step-by-step explanation:

you would move the decimal to the right four times giving you 782000

answer: D

explanation:

volume is equal to length * surface area.

surface of a tube base is a circle, so it' surface are can be calculated as:

[tex]\pi \: {r}^{2} [/tex]

where r is a radius

[tex] r \: = \frac{1}{2} diameter[/tex]

so you calculate volume V as:

[tex]v \: = \pi( {r}^{2} ) \times length \: = \pi \times \frac{1}{4} \times {diameter}^{2} \times length[/tex]

[tex]v = 3.14 \times \frac{1}{4} \times 4 \times 4 \times 24 = 301.44[/tex]

so the answer is D

Answer: 3 classes

If we removed 5 students from each of the classrooms, we would be able to keep the 18 classes and give them exactly 30 students. However, we would also have the leftover students to put into classrooms.

If there are 18 classrooms with 5 extra students from each, we can use 18*5 to find how many total students we have.

18 * 5 = 90.

If each class size is 30, we need to divide 90 by 30 to find how many classes we need.

90 / 30 = 3 classes

Therefore, to reduce the class size to 30 students per class, 3 new classes must be formed.

To reduce the class size from 35 students to 30 students in a school with 18 classes, we need to calculate the total number of students and then determine how many new classes are needed.

1. **Total number of students:**

  [tex]\[ \text{Total students} = 18 \text{ classes} \times 35 \text{ students/class} = 630 \text{ students} \][/tex]

2. **Number of classes required with 30 students per class:**

 [tex]\[ \text{Required classes} = \frac{630 \text{ students}}{30 \text{ students/class}} = 21 \text{ classes} \][/tex]

3. **New classes to be formed:**

  [tex]\[ \text{New classes} = \text{Required classes} - \text{Current classes} = 21 - 18 = 3 \text{ classes} \][/tex]

Answer:   [tex]\bold{x^{\frac{1}{3}}}[/tex]

Step-by-step explanation:

[tex]\sqrt[6]{x^2} =x^{\frac{2}{6}}=x^{\frac{1}{3}}[/tex]

Answer:

4.5 * 10^-11

Step-by-step explanation:

the reason why is there is 11 zeros in front of the 45

hope this helps :)

The area of the copy would be 36 in x16in

The area of the copy of the photograph, with doubled dimensions of 12 inches by 8 inches, is 96 square inches, which is four times the area of the original photograph.

To find the area of a copy of a photograph with dimensions that are double the original, you first find the new dimensions. Since the original photograph is 6 inches by 4 inches, doubling both the length and the width gives us dimensions of 12 inches by 8 inches for the copy.

The area of a rectangle is found by multiplying the length by the width. Therefore, the area of the copied photograph is 12 inches x 8 inches, which equals 96 square inches. This is four times the area of the original photograph since the scale factor for both the length and the width is 2, and the area scales with the square of the scale factor (22).

In conclusion, the area of the copied photograph is 96 square inches. This calculation demonstrates that when you change the linear dimensions of a figure by a scale factor, the area changes by the square of that scale factor.

Answer:

Step-by-step explanation:

House?

Number of hours left to work(x) = 15 hours - (3 hours/day)x

Note how this Number of hours decreases steadily from its initial value (15 hours) at the rate of 3 hours/day.  The domain of x is [0,5].

By slope intercept form, the number of days that the Rebecca should volunteer exists 5 days.

The "equation of the straight line exists y = mx + c this form exists named slope intercept form".

Rebecca must complete 15 hours of volunteer work. She does 3 hours each day.

The linear equation exists in slope intercept form exists y = mx + c, where 'm' exists the slope straight line and 'c' exists y-intercept.

y = 15 hours - 3 hours/day x days

y = 15 - 3x ............(1)

To find y-intercept put x=0 in (1) we get,  

y = 15 - 3(0)

 = 15

y = 15

which exists the amount of volunteer hours.

Rebecca must complete at day 0.

0 = 15 - 3x

3x = 15

x = 5 [Number of days Rebecca would have to volunteer]

Therefore, utilizing slope intercept form, the number of days that the Rebecca should volunteer exists 5 days.

To learn more about slope intercept form refer to:

brainly.com/question/9682526

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