Answers
1000mm= 1m
65mm= 0.065m
To convert m to mm, move the decimal three places to the right.
4.92m= 4920 mm
3mm= 0.003m
65mm. = 0.065m
4.92 m. = 4920mm
3 mm. = 0.003m
Related Questions
For which values of p and q does the following equation have infinitely many solutions?
PX + Q = 46x +23
A) p = 46 & q = 23
B) p = -46 & q = 23
C) p=-46 & q = -23
D) p= 46 & q = -23
(Select all that may apply)
Answers
p x + q = 46 x + 23
p x - 46 x = 23 - q
x ( p - 46 ) = 23 - q
x = ( 23 - q ) / ( p - 46 )
This equation has infinitely many solutions for :
23 - q = 0 and p - 46 = 0
or: q = 23 and p = 46
Answer : A ) p = 46 & q = 23
Sarah is a news anchor. She works 55 hours a week, but she is only on-air about 19% of those hours. Approximately how many hours is Sarah on-air each week?
Answers
Hope this helped! :D
A chemical plant takes in 5 1/2 million gallons of water from a local river and discharges 3 2/3 million back into the river. How much water does not go back into the river?
Answers
1. Shade in the American prairie as it was in the 1800s on this map, or use the space below the map to describe the location of the American prairie as it was in the 1800s.
Answers
Answer:
Step-by-step explanation:
Identify the initial value and rate of change for the graph shown below.
Initial value: 5.5, rate of change: negative 3 over 4.
Initial value: 4, rate of change: negative 3 over 4.
Initial value: negative 3 over 4., rate of change: 4
Initial value: negative 3 over 4., rate of change: 5.5
Answers
Answer:
The initial value is 4 and the rate of change is tex]\frac{-3}{4}[/tex]
Step-by-step explanation:
The initial value is the y intercept of the given line.
Y intercept is the point where the graph crosses y axis
y intercept is (0,4) so initial value is 4
Rate of change is the slope
To find rate of change we use formula [tex]\frac{y_2-y_1}{x_2-x_1}[/tex]
Pick two points from the graph
(0,4) and (4,1)
Rate of change = [tex]\frac{1-4}{4-0}=\frac{-3}{4}[/tex]
9.744 divided by 0.87
Answers
O is the center of the circle. Assume that lines that appear to be tangent are tangent. What is the value of x? 23 78.5 337 314
Answers
Final answer:
To find the value of x in the given ellipse equation centered at (4.619, 5.425), substitute the expressions for x and y and rearrange the tangent equation to solve for x, resulting in x = 78.5.
Explanation:
To find the value of x, you are given the information related to the center and the major axis of the ellipse. First, substitute the given expressions for x and y into their respective places in the equation.
Then, using the equation for a tangent to an ellipse, rearrange it to match the form provided. This rearranged equation will give you the needed value of x.
By following the steps outlined and applying the given information correctly, you can determine that the value of x is 78.5.
shade the region in the xy plane that is described by the inequalities 3x-y-7<0 and x+5y+3>=0
Answers
For line 3x-y-7 <0, let's disregard < first and change it to =, such that 3x-y-7=0. Rearranging, y=3x-7. If you plot this equation, that would be the blue line in the equation. To know which of side of the line is the solution, you substitute a random point into the equality. For example, let's use point (5,20).
3x-y-7<0
3(5)-20-7<0
-12<0, this is true. Therefore, all the space to the left of the blue line is a solution (blue region).
We do the same for the other equation (orange line). Let's use the same point (5,20) to test.
x+5y+3≥0
5+5(20)+3≥0
108≥0, this is true, Therefore, everything above the orange line is a solution (orange region).
The overlapped area of the two shaded regions is presented as green in the picture. This is the exact solution of this system of linear equations.
Today is Jack’s birthday and Jill’s birthday. Jack is five and Jill is nine.
1. How many years ago was Jill twice as old as Jack?
2. When Jack is three quarters as old as Jill, how old will Jill be?
3. When Jill was three times as old as Jack, how old was Jack?
4. When Jill is four times as old as Jack is today, how old will Jack be?
Answers
Final answer:
The problem involves simple arithmetic and algebra to work out the relationship between ages at different times. Jill was twice as old as Jack 1 year ago. The other parts of the problems are under-determined or have errors that prevent firm conclusions.
Explanation:
Let's solve each problem step by step:
How many years ago was Jill twice as old as Jack? Let's call the number of years ago y. Jill's age y years ago = 9 - y, and Jack's age y years ago = 5 - y. The equation based on the problem is 9 - y = 2(5 - y). Solving this equation, y = 1. So, Jill was twice as old as Jack 1 year ago.
When Jack is three quarters as old as Jill, how old will Jill be? Let's call Jill's future age f. Jack's future age will be 3/4 * f. We know Jack is currently 5 years old, so 5 + x = 3/4(f + x), where x is the number of years till that happens. To find the value of f and x, we need one more equation or piece of information, which is not provided.
When Jill was three times as old as Jack, how old was Jack? To find this out, we set up an equation similar to the first problem: let's call the number of years ago z. So (9 - z) = 3(5 - z), solving for z gives us z = 4.5, but since they can't be half years old, we must consider whole years; thus, this situation hasn't occurred given their current ages or an error exists in the problem.
When Jill is four times as old as Jack is today, how old will Jack be? Jack is currently 5. So, when Jill is four times that age, she will be 5 * 4 = 20 years old. We cannot determine how old Jack will be at that time without knowing the difference in time between now and then.
Ahmad has scored 11, 25, 27, 25, and 25 points in his five basketball games so far. How many points does he need to score in his next game so that his average (mean) is 23 points per game?
Answers
(113 + x) / 6 = 23
113 + x = 23 * 6
113 + x = 138
x = 138 - 113
x = 25 <== he needs a 25
Simplify 8(x + 6) - 10. 8x - 4 8x + 28 8x + 38
Answers
8x + 48 - 10
8x + 38 <------------- answer
8x + 38 should be the answer...not sure.
Mildred brought 1 cent stamps,32 cent stamps, and 33 cent stamps for $21.80. The number of 1 cent stamps exceed the number of 33 cent stamps by 50. The number of 32 cents was 10 less than twice the number of 33 cents stamps. How many of each kind did she buy? Mildred brought 1 cent stamps,32 cent stamps, and 33 cent stamps for $21.80. The number of 1 cent stamps exceed the number of 33 cent stamps by 50. The number of 32 cents was 10 less than twice the number of 33 cents stamps. How many of each kind did she buy?
Answers
0.01x + 0.32y + 0.33z = 21.80
x = z + 50
y = 2z - 10
0.01(z + 50) + 0.32(2z - 10) + 0.33z = 21.80
0.01z + 0.5 + 0.64z - 3.20 + 0.33z = 21.80
0.98z - 2.7 = 21.8
0.98z = 21.8 + 2.7
0.98z = 24.5
z = 24.5 / 0.98
z = 25 <=== 33 cent stamps
x = z + 50
x = 25 + 50
x = 75 <=== 1 cent stamps
y = 2z - 10
y = 2(25) - 10
y = 50 - 10
y = 40 <== 32 cent stamps
Mildred bought 480 1 cent stamps, 410 32 cent stamps, and 520 33 cent stamps.
Explanation:Let's solve this problem using a system of equations.
Let's use the variables x, y, and z to represent the number of 1 cent stamps, 32 cent stamps, and 33 cent stamps respectively that Mildred bought. We can write the following equations based on the information given:
x + y + z = 2180 (since the total cost was $21.80)
x = z + 50 (since the number of 1 cent stamps exceed the number of 33 cent stamps by 50)
y = 2z - 10 (since the number of 32 cent stamps was 10 less than twice the number of 33 cents stamps)
Let's solve this system of equations:
Substitute the value of x from equation 2 into equation 1: (z + 50) + y + z = 2180Substitute the value of y from equation 3 into equation 1: z + 50 + (2z - 10) + z = 2180Simplify and solve for zSubstitute the value of z into equation 2 to find xSubstitute the value of z into equation 3 to find yAfter solving the system of equations, we find that Mildred bought 480 1 cent stamps, 410 32 cent stamps, and 520 33 cent stamps.
o quociente entre a soma de soma de dois numeros e um deles e igual a 3. O inverso do dobro da soma deles e igual a 1/6 quais sao os numeros?
Answers
and "The inverse of double the sum of them and equal to 1/6"1/2(a+b)=1/6 it's will be second equation in our system.
Attention at parenthesis.
System(a+b)/b=31/2(a+b)=1/6
by the first equation:(a+b)/b=3a+b=3ba=2b --- we will use this equation for second equation in system
1/2(2b+b)=1/61/3b)=1/63b=6b=2 and a=2b, that's mean a=1.The answer is pair (1;2)
Renaldo will write 3/20 as a decimal. Which of the following methods should he use?
Please hurry and answer this
Answers
Answer:
Multiply the fraction by StartFraction 5 over 5 EndFraction to get a denominator of 100 and then write the numerator as hundredths using a decimal point.
Step-by-step explanation:
sorry im 3 years late but help me out by giving brainliest.
How many quarts in a gallon
Answers
A direct variation function contains the points (–9, –3) and (–12, –4). Which equation represents the function?
y = –3x
y = – x/3
y = x/3
y = 3x
Answers
Slope = y2-y1 / x2-x1
-4+3/ -12+9
-1/-3
1/3 is the slope of this equation.
You do not have to go any further to find b or the y-intercept because it appears that b or the y-intercept is 0 in this case.
y= 1/3x or in other words y= x/3
f(x) = 3x + 10x and g(x) = 4x – 2, find (f – g)(x)
Answers
The question seeks the derivatives of a function, but cannot be answered accurately due to the lack of specific information about the function provided.
The question asks to find the first, second, and third derivatives of a given function f(x). However, further details needed to answer the question, such as the specific form of the function f(x), are not provided in the question itself. Therefore, without the explicit function f(x), we cannot proceed to accurately calculate the requested derivatives.
Combine and simplify the following radical expression. 2 over 3 times cubed root of 5
Answers
Final answer:
The radical expression ⅓∛5 simplifies to 2/3 × cubed root of 5, and cannot be simplified further since 5 is a prime number.
Explanation:
To combine and simplify the given radical expression, 2 over 3 times cubed root of 5, we first understand that the expression is in the form ⅓∛5, which can also be written as ⅓(5¹³). To simplify this, we use the fact that raising a number to a fractional power is the same as taking a root of the number. In this case, since the exponent is 1/3, we are taking the cubed root of the number 5.
Therefore, the expression simplifies to:
2/3 × 5¹³ = 2/3 × ∛5
No further simplification is possible since 5 is a prime number and cannot be broken down into smaller roots that can be easily calculated. The final simplified form of the expression remains 2/3 × ∛5.
Final answer:
To combine and simplify the expression 2/3 * 5^(1/3), rewrite 5^(1/3) as the cube root of 5 and multiply it by 2/3. The resulting expression (2/3) * (cube root of 5) cannot be simplified further.
Explanation:
To combine and simplify the expression 2/3 * 5^(1/3):
We can rewrite 5^(1/3) as the cube root of 5.
Multiplying 2/3 by the cube root of 5 gives us (2/3) * (cube root of 5).
Since there are no common factors between 2 and 3, we cannot simplify the expression any further.
Therefore, the combined and simplified radical expression is (2/3) * (cube root of 5).
Polygons EFHG and E′F′H′G′ are shown on the following coordinate grid: A coordinate grid is shown from positive 6 to negative 6 on the x-axis and from positive 6 to negative 6 on the y-axis. A polygon EFHG is shown with vertex E on ordered pair 2, 2, vertex F on ordered pair 2, 4, vertex H on ordered pair 3, 5 and vertex G on ordered pair 3, 1. A polygon E prime F prime H prime G prime is shown with vertex E prime on ordered pair negative 1, 2, vertex F prime on ordered pair negative 3, 2, vertex H prime on ordered pair negative 4, 3, and vertex G prime on ordered pair 0, 3. What set of transformations is performed on EFHG to form E′F′H′G′?
Answers
All choices involve a rotation by 90° or 270° counterclockwise about the origin.
consider a rotation by 90° counterclockwise. Each point P(a, b) can be rotated 90° cwise about the origin to form P"(a",b") :
by drawing the right angle POP", such that |PO|=|OP"|.
or by plotting each P"(a",b") so that (a",b")=(-b, a)
for example if G(3, 1) is mapped to G(-1, 3) by either of the procedures described.
check picture 2.
EFHG is mapped to E′'F'′H'′G′'.
In order to map E′'F'′H'′G′' to E'F′H'G′, we need to translate the figure 1 unit right.
Answer:
"A 90-degree counterclockwise rotation about the origin followed by a translation 1 unit to the right"
Answer:
A 90-degree counterclockwise rotation about the origin followed by a translation 1 unit to the right
Step-by-step explanation:
i took the test
The population of a type of local dragonfly can be found using an infinite geometric series where a1 = 65 and the common ratio is 1/6. Find the sum of this infinite series that will be the upper limit of this population.
Answers
The common ratio is denoted as r. For values of r<1, the sum of the infinite series is equal to
S∞ = A₁/(1-r), where A1 is the first term of the sequence. Substituting A₁=65 and r=1/6:
S∞ = A₁/(1-r) = 65/(1-1/6)
S∞ = 78
Find x if ABCD is a square and angle C = 1/2 x – 5.
Answers
any angle in a square = 90 degrees
so C=1/2x-5 has to equal 90
90=1/2x-5
95 = 1/2x
190=x
check (1/2)190-5 = 90
x = 190
A restaurant charges $100 to rent its banquet room for an event. It also charges $15 to serve dinner to each quest. Write an equation for the total cost of the banquet room in terms of the number of guests. Define your variables. What is the total cost of the banquet room for 20 guests?
Answers
t = 15n + 100 <== ur equation
for 20 guests...n = 20
t = 15(20) + 100
t = 300 + 100
t = 400 <== cost for 20 guests
Answer:
The total cost function is C (x) = 15x + 100 and the cost of a banquet for 20 guests is $ 400
Step-by-step explanation:
Let's suppose,
X: Number of guests
C (x) = total cost
CF (x) = fixed cost
CV (x) = variable cost
C (x) = CV (x) + CF (x)
For the situation presented,
CF (x) = 100
CV (x) = 15x
With this information, the function that provides the total cost is given by the expression:
C (x) = 15x + 100.
When there are 20 guests, the total cost of the banquet is:
C (20) = 15 (20) + 100 = 300 + 100 = 400
Conclusion: The total cost function is C (x) = 15x + 100 and the cost of a banquet for 20 guests is $ 400
Hunter bought a package of 24 pencils for $3.12. Write and solve an equation to determine the cost of each pencil in the package
Answers
p = 3.12 / 24
p = 0.13
answer
the cost of each pencil in the package = $0.13
The cost of each pencil in the package is $0.13.
What is Equation?Two or more expressions with an Equal sign is called as Equation.
Given that a Hunter bought a package of 24 pencils for $3.12.
We have to find the cost of each pencil.
Let x be the cost of each pencil.
A pack of 24 pencils is three point one two
24x=3.12
Divide both sides by 24
x=3.12/24
Three point one two divided by twenty four.
x=0.13
Hence, the cost of each pencil in the package is $0.13.
To learn more on Equation:
https://brainly.com/question/10413253
#SPJ2
In how many different ways can you answer a multiple choice test that has 5 questions and 3 choices for each answer? 15 125 243
Answers
Answer:
The correct option is 3. The total number of different ways to answer a multiple choice test is 243.
Step-by-step explanation:
Total number of questions is 5. Each question has three options.
Total number of ways to answer the first question is 3.
Similarly, the number of ways to answer each question is 3.
Total number ways to answer a multiple choice test is
[tex]3\times 3\times 3\times 3\times 3=3^5=243[/tex]
Therefore the correct option is 3. The total number of different ways to answer a multiple choice test is 243.
Which type of transformation is shown?
reflection
translation
rotation
dilation
Answers
It didn't move and stay the same either, so we know it isn't a translation.
It didn't change size, so it is not a dilation.
However, we can see that it turned - or rotated - so therefore it is a rotation.
A pair of equations is shown below:
y = 6x − 4
y = 5x − 3
Part A: In your own words, explain how you can solve the pair of equations graphically. Write the slope and y-intercept for each equation that you will plot on the graph to solve the equations. (6 points)
Part B: What is the solution to the pair of equations? (4 points)
Answers
Linear equations are written in the format y = mx+b, where m represents the slope/slope intercept and b represents the y-intercept.
---------------------------------------------------------------------------------------------------------------
Part A
the slope and y-intercept
y = mx +b
m - the slope; b- y-intercept
therefore;
y = 6x - 4
m = 6; b = -4
y = 5x - 3
m = 5; b = -3
The coordinates of the point where the lines are crossed are the solution to the system of linear equations.
How to graph the lines:
y = 6x - 4
y-intercept (0; -4)
for x = 1 ⇒ y = 6 · 1 - 4 = 6 - 4 = 2 ⇒ (1; 2)
y = 5x - 3
y-intercept (0; -3)
for x=1 ⇒ y = 5 · 1 - 3 = 5 - 3 = 2 ⇒ (1; 2)
***look at the img for graph reference***
Part B: x = 1; y = 2
Abdul is choosing a 3 letter password from the letters A,B,C,D, and E. The password cannot have the same letter repeated in it. How many such passwords are possible?
Answers
there are 5 letters
1st letter can be any 5
2nd letter can be any 5 -1 = 4
3rd letter can be any 5 -2 = 3
5*4*3 = 60 different combinations
Periodic tune-ups are important because they
Answers
An item is regularly priced at $69. Ashley bought it on sale for 35% off the regular price.
Answers
65% of 69=0.65 times 69=44.85
the price she paid was $44.85
Answer:
$22.75
Step-by-step explanation:
35% of 65 dollars is $22.75
What is the ratio of the circumference for two circles with areas of 6pi m^2 and 150 pi m^2
A.1:50
B.1:5
C.1:10
D.1.25
Answers
= 4.3416:21.7080
= 1:5
B
To find the ratio of circumferences, we first determine the radii from the given areas using the formula A = πr². Then, we use C = 2πr to get the circumferences and compare them, which results in a final ratio of 1:5.
Explanation:To find the ratio of the circumferences of the two circles with areas of 6pi m^2 and 150 pi m^2, we first need to determine the radii of the circles. The area of a circle (A) is given by the formula A = πr². Solving for the radius (r) gives us r = √(A/π).
For the first circle:
A = 6π m²
So the radius is r1 = √(6π/π)r1 = √6 m
For the second circle:
A = 150π m²
So the radius is r2 = √(150π/π)r2 = √150 m
Now we can find the circumferences using the formula C = 2πr.
For the first circle:
C1 = 2π√6 m
For the second circle:
C2 = 2π√150 m
Finally, to find the ratio of the circumferences, C1/C2, we get:
(2π√6)/(2π√150)
After simplifying, we are left with the ratio √6/√150. This simplifies to √(6/150) which is √(1/25) or 1/√25. And since √25 is 5, we have a final ratio of 1:5.