You have exactly 10 minutes to get to class for
your big test on lateral numbers! Your friend Gus
(who’s weirdly in to this sort of thing) says that class
is exactly 10,000 feet away. Let’s say you travel to
class at a rate of r feet/minute. You would like to get
there a few minutes early. More specifically, let’s say
you will arrive t minutes early.
a) Write an equation that relates r and t.
Evaluate BC for A = 5, B = -4, and C = 2.
Answer: -8
Step-by-step explanation: Substitute the value of the variable into the expression and then simplify you should get the answer -8
BC= (-4)(2)=-8
On anne's bicycle, the ratio of pedal turns to rear-wheel turns in second gear is 4 to 7. if her rear wheel turns 875 times per mile,how many times does she turn the pedal in one mile?hint:set up and solve as a propportion to find x.
Find the percent change from 48 to 228. Tell whether it is a percent increase or decrease. If necessary, round your answer to the nearest percent.
if a project will take 35 employees 2,940 hours to complete, how many hours will each employee have to work?
Find the equation of the circle with center at the origin that contains the point ( 12 , 9 ) (12,9).
what is the equation of the graphed line in point-slope form?
a. y – 1 = (x + 3)
b. y – 1 = (x – 3)
c. y + 1 = (x – 3)
d. y + 1 = (x + 3)
Answer:
[tex]y-1 = \frac{2}{3}(x-3)[/tex]
Step-by-step explanation:
To find the equation of graphed line we pick two points from the line
(3,1) and (-3,-3)
Equation of a line is y=mx+b
where 'm' is the slope and b is the y intercept
slope [tex]m= \frac{y2-y1}{x2-x1} =\frac{1+3}{3+3} = \frac{2}{3}[/tex]
we use point slope formula
y-y1= m(x-x1)
here point(x1,y1) is (3,1) and slope m = 2/3
Plug in all the value
[tex]y-1 = \frac{2}{3} (x-3)[/tex]
The ______ is the total area drained by a river and its tributaries.
what is the solution to 7ln(x+2.8)=11.2
What numbers have the absolute value of 1/2
To maximize learning, a ________ should be presented on a(n) ________ schedule.
To maximize learning, a CS + UCS should be presented on a(n) continuous schedule.
In here, CS means conditional stimulus while UCS is the unconditioned stimulus. Taking for example, let us imagine that the smell of food is the unconditioned stimulus, the feeling of hunger in response to that specific smell is a unconditioned response, and then the sound of the whistle is the conditioned stimulus.
What is the perimeter of a polygon with vertices at
(−1, 3) , (−1, 6) , (2, 10) , (5, 6) , and (5, 3) ?
Enter your answer in the box. Do not round any side lengths.
we know that
the perimeter of a polygon is the sum of the length sides
in this problem we have five vertices
so
the polygon has five sides
Let
[tex]A(-1,3)\\B(-1,6)\\C(2,10)\\D(5,6)\\E(5,3)[/tex]
the perimeter is equal to
[tex]P=AB+BC+CD+DE+AE[/tex]
The formula to calculate the distance between two points is equal to
[tex]d=\sqrt{(y2-y1)^{2}+(x2-x1)^{2}}[/tex]
Step 1
Find the distance AB
[tex]A(-1,3)\\B(-1,6)[/tex]
substitute the values in the formula
[tex]d=\sqrt{(6-3)^{2}+(-1+1)^{2}}[/tex]
[tex]d=\sqrt{(3)^{2}+(0)^{2}}[/tex]
[tex]dAB=3\ units[/tex]
Step 2
Find the distance BC
[tex]B(-1,6)\\C(2,10)[/tex]
substitute the values in the formula
[tex]d=\sqrt{(10-6)^{2}+(2+1)^{2}}[/tex]
[tex]d=\sqrt{(4)^{2}+(3)^{2}}[/tex]
[tex]dBC=5\ units[/tex]
Step 3
Find the distance CD
[tex]C(2,10)\\D(5,6)[/tex]
substitute the values in the formula
[tex]d=\sqrt{(6-10)^{2}+(5-2)^{2}}[/tex]
[tex]d=\sqrt{(-4)^{2}+(3)^{2}}[/tex]
[tex]dCD=5\ units[/tex]
Step 4
Find the distance DE
[tex]D(5,6)\\E(5,3)[/tex]
substitute the values in the formula
[tex]d=\sqrt{(3-6)^{2}+(5-5)^{2}}[/tex]
[tex]d=\sqrt{(-3)^{2}+(0)^{2}}[/tex]
[tex]dDE=3\ units[/tex]
Step 5
Find the distance AE
[tex]A(-1,3)\\E(5,3)[/tex]
substitute the values in the formula
[tex]d=\sqrt{(3-3)^{2}+(5+1)^{2}}[/tex]
[tex]d=\sqrt{(0)^{2}+(6)^{2}}[/tex]
[tex]dAE=6\ units[/tex]
Step 6
Find the perimeter
the perimeter is equal to
[tex]P=AB+BC+CD+DE+AE[/tex]
substitute the values
[tex]P=3+5+5+3+6=22\ units[/tex]
therefore
the answer is
the perimeter of the polygon is [tex]22\ units[/tex]
Why might algebra tiles not be a good tool to use to factor x2 + 18x + 80? Explain.
Algebra tiles would not be a good tool to use to factor the trinomial because you would need to drag an x-squared tile, 18 x-tiles, and 80 plus tiles. That is a total of 99 tiles. It would take a lot of time to drag that many tiles on the board and there might not be enough space to hold all of them. You would also need to determine how to arrange all those tiles to make a rectangle. Since 80 is a multiple of 10, you might recognize that 10 and 8 are the factors that add to 18, which would give you the values to use in the X method.
Which of the following is equivalent to [tex]( \frac{1}{2} ) ^{-2t} [/tex]
[tex](( \frac{1}{2}) ^{2} ))\ x^{t} [/tex]
[tex] \frac{1 ^{t} }{2 ^{2} } [/tex]
[tex](2 ^{2} ) ^{t} [/tex]
[tex]2 ^{2} * 2^{t} [/tex]
Which value can fill in the blank in the function f(x)=|x| to make it's graph wider than that of the parent function, f(x)=|x|
To widen [tex]\( |x| \)[/tex]'s graph, use [tex]\( f(x) = |ax| \)[/tex] where [tex]\( a > 1 \),[/tex] stretching horizontally by multiplying [tex]\( x \) by \( a \).[/tex]
To make the graph of the function [tex]\( f(x) = |x| \)[/tex] wider than that of the parent function [tex]\( f(x) = |x| \)[/tex], we need to stretch the graph horizontally.
In the absolute value function [tex]\( f(x) = |x| \)[/tex], the "wideness" of the graph is determined by the coefficient of [tex]\( x \)[/tex], which affects the slope of the graph. When the coefficient of [tex]\( x \)[/tex] is greater than 1, the graph becomes wider, and when it's less than 1, the graph becomes narrower.
So, to make the graph wider, we can introduce a coefficient [tex]\( a \)[/tex] to the [tex]\( x \)[/tex]term inside the absolute value function. The function becomes [tex]\( f(x) = |ax| \), where \( a \)[/tex] is a positive constant greater than 1.
For example, if [tex]\( a = 2 \)[/tex], the function becomes [tex]\( f(x) = |2x| \)[/tex]. This means every \( x \) value in the function is multiplied by 2 before taking the absolute value. As a result, the graph stretches horizontally, making it wider than the parent function.
In conclusion, to make the graph wider than the parent function [tex]\( f(x) = |x| \)[/tex], we can use the function [tex]\( f(x) = |ax| \)[/tex], where [tex]\( a \)[/tex] is a positive constant greater than 1.
Let g(x)=2x and h(x)=x^2+4
(g o h)(0)
How many seconds are there in (a) one hour and thirty-five minutes and (b) one day?
Which expressions are equivalent to ? Check all that apply.
To determine if expressions are equivalent, we simplify them or substitute variables with actual values to see if they yield the same result. We simplify by eliminating terms where possible, grouping like terms, and applying mathematical operations.
Explanation:Without the original mathematical expressions, it's difficult to provide direct answers to your question. Normally, we determine whether expressions are equivalent by simplifying them using algebraic rules or substituting variable with actual values to see if they produce the same results.
For example, the expressions 2(3 + 5) and 6 + 10 are equivalent because they both simplify to 16. We identify equivalent expressions by simplifying which includes eliminating terms where possible, grouping like terms, and applying mathematical operations.
Ultimately, the exact process may vary depending on the complexity and specific form of the expressions in question.
Learn more about Equivalent here:https://brainly.com/question/34140345
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The expressions equivalent to [tex]$\sqrt[3]{128}^x$[/tex] are (c) [tex]$(4 \sqrt[3]{2})^x$[/tex] and (d) [tex]$\left(4\left(2^{\frac{1}{3}}\right)\right)^x$[/tex] due to their compatible structures with the original expression.
To determine which expressions are equivalent to [tex]$\sqrt[3]{128}^x$[/tex], let's simplify the given expression first:
[tex]\[\sqrt[3]{128}^x = 2^x \times \sqrt[3]{2}^x\][/tex]
Now, let's compare this with the provided options:
a. [tex]$128^{\frac{x}{3}}$[/tex] - Not equivalent.
b. [tex]$128^{\frac{3}{x}}$[/tex] - Not equivalent.
c. [tex]$(4 \sqrt[3]{2})^x$[/tex] - Equivalent, as [tex]$4 = 2^{\frac{3}{2}}$[/tex].
d. [tex]$\left(4\left(2^{\frac{1}{3}}\right)\right)^x$[/tex] - Equivalent, as [tex]$2^{\frac{1}{3}} = \sqrt[3]{2}$[/tex].
e. [tex]$(2 \sqrt[3]{4})^x$[/tex] - Not equivalent.
Therefore, the expressions (c) [tex]$(4 \sqrt[3]{2})^x$[/tex] and (d) [tex]$\left(4\left(2^{\frac{1}{3}}\right)\right)^x$[/tex] are equivalent to [tex]$\sqrt[3]{128}^x$[/tex].
Solve for 8x please
please show work along with answer:
[tex] \frac{1 + \tan(x) }{1 + \cot(x) } [/tex]
What is the value of x? The triangle is similar.
Which algebraic expression has a term with a coefficient of 3?
the correct answer is option (b) 3x² - 7.
The coefficient is the numerical factor in front of the variable. Let's calculate the coefficient for each option:
a) The coefficient of x in 2x is 2, not 3.
b) The coefficient of x² in 3x² is 3, which matches our requirement.
c) The coefficient of x in 4x is 4, not 3.
d) There is no x term in x³ + 2, so the coefficient for x is 0.
Therefore, the correct answer is option (b) 3x² - 7.
In option (b), the term with the coefficient of 3 is 3x². The coefficient of this term is indeed 3 because it's the number multiplied by x squared. The other terms in the expression do not have a coefficient of 3.
In options (a) and (c), the coefficients for the x terms are 2 and 4, respectively, which do not match the requirement.
Option (d) doesn't have an x term; it only has x raised to the power of 3 (x³), and the coefficient for this term is 0.
So, by process of elimination and calculation, we determine that option (b) is the correct answer with the term 3x² having a coefficient of 3.
complete question
Which algebraic expression has a term with a coefficient of 3?
a) 2x + 5
b) 3x² - 7
c) 4x - 3
d) x³ + 2
Ashley is making cookies. the recipe calls for 3/4 of a cup of sugar. she needs to make five batches of cookies. how many cups of sugar does ashley need?
I need help from a math genius
y=x+2;x=-3 solve each system by graphing step by step
How do you solve rearranging equations
Which formula gives the coordinates of the midpoint of the segment connecting points (a,
b.and (c, d)?
Answer:
Formula that gives coordinates of the mid point of the segment connecting is [tex](\frac{a+c}{2},\frac{b+d}{2})[/tex]
Step-by-step explanation:
Given point are ( a , b ) and ( c , d )
To find : Coordinates of the mid point of the segment connecting given points.
We know that if point are [tex](x_1,y_1)\:\:and\:\:(x_2,y_2)[/tex]
then coordinate of the midpoints given by [tex](\frac{x_1+x_2}{2},\frac{y_1+y_2}{2})[/tex]
So, Coordinates of the given points = [tex](\frac{a+c}{2},\frac{b+d}{2})[/tex]
Therefore, Formula that gives coordinates of the mid point of the segment connecting is [tex](\frac{a+c}{2},\frac{b+d}{2})[/tex]
He measure of an angle is 78° less than the measure of its complement. what is the measure of the angle?
Alex sells cars at Keith Palmer Ford. He earn$400 a week plus $150 per car he sells. if he earn $1450 last week, how many cars did he sell? brainly
Find the length of the arc subtended by a central angle of 30degrees on a circle of radius 2 feet