The acceleration due to gravity on planet X is one fifth that on the surface of the earth. If it takes 4.1 s for an object to fall a certain distance from rest on earth, how long would it take to fall the same distance on planet X? Answer in units of s.

The kinetic energy of this vehicle in kilojoules is about 6.053 × 10² kiloJoules

Let's recall Kinetic Energy formula as follows:

[tex]Ek = \frac{1}{2}mv^2[/tex]

Ek = Kinetic Energy ( Joule )

m = mass of the object ( kg )

v = speed of the object ( m/s )

Let us now tackle the problem !

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Given:

mass of car = m = 1423 kg

speed of car = v = 105.0 km/h = 29¹/₆ m/s

Asked:

kinetic energy of car = Ek = ?

Solution:

We will use Kinetic Energy formula as follows:

[tex]Ek = \frac{1}{2}mv^2[/tex]

[tex]Ek = \frac{1}{2}(1423)(29\frac{1}{6})^2[/tex]

[tex]Ek \approx 6.053 \times 10^5 \texttt{ Joules}[/tex]

[tex]Ek \approx 6.053 \times 10^2 \texttt{ kiloJoules}[/tex]

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The kinetic energy of this vehicle in kilojoules is about 6.053 × 10² kiloJoules

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Grade: High School

Subject: Physics

Chapter: Dynamics

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Keywords: Gravity , Unit , Magnitude , Attraction , Distance , Mass , Newton , Law , Gravitational , Constant

The man's upward acceleration is found using Newton's second law, calculating the man's weight and combining that with the force he exerts on the rope. The resulting net force is divided by his mass, giving a result inclusive of gravity. Subtracting gravity's acceleration gives his actual upward acceleration, 5.15 m/s².

The subject of the question falls under the domain of Physics, specifically Newton's second law of motion. The 72.0-kg man throwing the rope over the tree and pulling down with a force of 371 N creates a force that works against his weight. To find the acceleration, we use the equation: net force = mass x acceleration (Net F = ma).

First, calculate the man's weight. Weight is the force due to gravity and is calculated as mass x gravity. So the man's weight is 72.0 kg x 9.80 m/s² = 705.60 N.

The force the man exerts on the rope is 371 N. But remember, he is pulling down, so his force and gravity are working together. Thus, the net force is 371 N (the man's pull) + 705.60 N (the man's weight) = 1076.60 N.

Then, to find the acceleration, we rearrange the equation to a = net force/mass. So, this becomes 1076.60 N / 72.0 kg = 14.95 m/s². But this includes the acceleration due to gravity. So to get the upward acceleration, we subtract gravity: 14.95 m/s² - 9.80 m/s² = 5.15 m/s² upward. Therefore, the man's upward acceleration due to his pull is 5.15 m/s².

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The Bohr Atom wavelength is shorter when an electron moves from the n = 2 to the n = 3 energy level than when it moves from the n = 2 to the n = 4 energy level.

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The density of a [tex]36 g[/tex] object with a volume of [tex]15 cm^{3}[/tex] is [tex]2.4 g/cm^{3}[/tex].

Density of substance is defined as its mass per unit volume. Density gives information about how tightly the substance is packed together. The formula for density is

[tex]\rho = \frac{m}{V}[/tex]

Where,

[tex]\rho =[/tex]density

[tex]m =[/tex]mass

[tex]V =[/tex]volume

Unit of density is grams per cubic centimetre.

One of the most common uses of density is in how different materials interact when mixed together.

Given

[tex]m = 36 g[/tex]

[tex]V = 15 cm^3[/tex]

The density of substance is

[tex]\rho = \frac{m}{V}\\\rho = \frac{36}{15}\\\rho = 2.4 g/cm^3[/tex]

Hence, The density of a substance is [tex]2.4 g/cm^3[/tex].

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Answer:

the answer is 5.0

Explanation:

Answer:

Reverse osmosis

Explanation:

In order to purify the water which has been contaminated with salt and microorganisms, reverse osmosis will be the best way. In reverse osmosis a pressure is applied on the salt side of the impure water using a pump. Doing this prompts the pure water to leave the salt side so pure water moves another side of the semi permeable membrane. The semi permeable also filters the microorganisms. Hence, pure water can be obtained easily from this impure sample. The RO at our houses use this process to purify water.

Newton's First Law states that an object will remain at rest or in uniform motion in a straight line unless acted upon by an external force. It may be seen as a statement about inertia, that objects will remain in their state of motion unless a force acts to change the motion. Any change in motion involves an acceleration, and then Newton's Second Law applies. The First Law could be viewed as just a special case of the Second Law for which the net external force is zero, but that carries some presumptions about the frame of reference in which the motion is being viewed. The statements of both the Second Law and the First Law here are presuming that the measurements are being made in a reference frame which is not itself accelerating. Such a frame is often referred to as an "inertial frame". The statement of these laws must be generalized if you are dealing with a rotating reference frame or any frame which is accelerating.

Newton's First Law contains implications about the fundamental symmetry of the universe in that a state of motion in a straight line must be just as "natural" as being at rest. If an object is at rest in one frame of reference, it will appear to be moving in a straight line to an observer in a reference frame which is moving by the object. There is no way to say which reference frame is "special", so all constant velocity reference frames must be equivalent.

Two of Newton's laws of motion are: the first law, stating that an object at rest stays at rest and an object in motion stays in motion at a constant velocity unless acted upon by an external force; and the second law, which describes how a force on an object results in an acceleration proportional to that force and inversely proportional to the object's mass.

Isaac Newton’s contributions to science include the formulation of three fundamental laws of motion that describe the relationship between a body and the forces acting upon it, and the body’s motion in response to these forces. The first two of Newton's laws are:

Newton’s first law, also known as the law of inertia, states that every object will continue to be in a state of rest or move at a constant speed in a straight line unless it is compelled to change that state by an outside force. This law emphasizes the tendency of objects to resist changes to their state of motion unless acted upon.

The change of motion of a body, as described by Newton’s second law, is proportional to and in the direction of the force acting on it. This law introduces the concept of acceleration, indicating that a force results in an acceleration of an object, and that acceleration is dependent on the object’s mass.

TO solve this problem, we simply have to find for the temperature of saturated water when the external pressure is 31 kPa. When the atmospheric pressure above a liquid equals its vapour pressure, then that liquid will boil. From the tables, the temperature at 31 kPa is about:

70 °C

Hydrogen bonds in water lead to the expansion of ice, allowing it to float and serve as insulation in bodies of water.

Hydrogen bonds are crucial in water's unique properties: When water freezes, it expands due to hydrogen bonding, creating a less dense solid form compared to its liquid state. This expansion allows ice to float on water, insulating the liquid below and allowing life to exist.

Answer:

0.143

Explanation:

m = F/a

   = (4.719 N)/(33 m/s²)

   = 0.143 kg

The statement that contradicts with the big bang theory is Over time, distant galaxies move progressively closer to Earth.

In 1927, the Belgian Catholic priest Georges Lemaître proposed an expanding model for the universe to explain the observed redshifts of spiral nebulae, and calculated the Hubble law. Hence he laid the foundation of Big Bang Theory according to which the universe is expanding. There is no such statement that says about the contraction of all heavenly bodies towards the earth.

Answer:

P = 4.0794 atm or  413,345.2 Pa

Explanation:

Given

Mass m = 14.0 g

Volume 3.5 L

Temperature T = 75° C = 75 + 273 = 348 K

Known Values

Molar mass of CO = 28 g/mol

Universal gas constant R = [tex]0.082057 L.atm/mol.K[/tex]

Solution

Number of moles in 14 g of CO is

[tex]\\n=\frac{mass}{molar.mass} \\\\n = \frac{14}{28} \\\\n = 0.5 mole[/tex]

[tex]PV = nRT\\\\P = \frac{nRT}{V} \\\\P = \frac{0.5 \times 0.082057 \times 348}{3.5} \\\\P = 4.0794 atm\\\\P = 4.0794 \times 101325\\\\P = 413,345.2 Pa[/tex]

The energy an object has as a result of motion is known as kinetic energy. A force must be applied to an object in order to accelerate it. We must put in effort in order to apply a force. After the work is finished, energy is transferred to the item, which then moves at a new, constant speed.

Kinetic energy, which may be seen in the movement of an object, particle, or group of particles, is the energy of motion. Any moving item uses kinetic energy, such as a person walking, a baseball being thrown, a piece of food falling from a table, or a charged particle in an electric field.

Explaination

Work may be bad, yes. -ve Work is considered to be completed when the system is functioning well and when your force is bearing fruit. When you exert force and the work is completed in the direction you intended, the work is considered successful. However, if there is an opposing force and the object moves in the opposite direction from where it was supposed to go, then the work done by U is negative but the work done by the opposing force is said to be positive.  If the object does not move and remains in place, then 0 work is done. force = work * The travel distance spose Because of the job you made, the object should move a short distance.

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An object travels 8 meters in the first second of travel, 8 meters again during the second of travel, and 8 meters again during the third second. Its acceleration would be 0 m / s² , therefore the correct answer is option A.

The rate of change of the velocity with respect to time is known as the acceleration of the object. Generally, the unit of acceleration is considered as meter/seconds².

As given in the problem if an object travels 8 meters in the first second of travel, 8 meters again during the second of travel, and 8 meters again during the third second, then we have to find its acceleration ,

As the object is covering an equal distance in an equal interval of time its acceleration would be zero.

Thus , the correct answer is option A.  

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Answer:

D. A reactant

Explanation:

The displacement of the jogger is 20m.

The displacement of the jogger can be calculated using the formula for the circumference of a circle. The circumference of a circle is given by the formula: C = 2πr, where r is the radius of the circle. In this case, the radius is 10m, so the circumference is 2π(10m) = 20πm.

Since the jogger runs halfway around the circular path, the distance traveled is half the circumference of the circle. Therefore, the jogger travels a distance of 10πm. However, the question asks for the displacement, which is a vector quantity that represents the change in position from the starting point to the ending point. In this case, since the jogger runs halfway around the circle, the displacement is the diameter of the circle, which is equal to twice the radius. Therefore, the displacement of the jogger is 2(10m) = 20m.

The displacement of a runner who runs halfway around a circular path with a radius of 10m is 20 meters, as the displacement is the diameter of the circle.

The question pertains to physics, specifically involving concepts of displacement and circular motion. When a runner runs halfway around a circular path with a radius of 10m, their displacement is the straight-line distance from their starting point to the point directly opposite on the circle. Since displacement is a vector quantity, it does not take the path into consideration, but rather the shortest distance between two points.

In this case, the runner's displacement forms a straight line that passes through the center of the circle, effectively forming the diameter. The length of the diameter can be calculated using the radius of the circle, which is given as 10m. The displacement, in this case, would therefore be twice the radius, which is 20 meters.