PLEASE HELP!!! Will give brainliest!

Answer: The answer is (C) 120 sq. units.

Step-by-step explanation: We are given to find the area of a trapezoid with bases of lengths 8 units and 16 units and height of 10 units.

We know that the area of the trapezoid with 'a' and 'b' as lengths of the bases and height 'h' is given by

[tex]A=\dfrac{1}{2}(a+b)h.[/tex]

Here, a = 8 units, B = 16 units and h = 10 units.

Therefore, the area of the given trapezoid will be

[tex]a\\\\=\dfrac{1}{2}(a+b)h\\\\=\dfrac{1}{2}\times(8+16)\times 10\\\\=24\times 5\\\\=120~\textup{sq. units.}[/tex]

Thus, the correct option is (C).

The answer is for the equation...

V/(1+rt)

It is written as a fraction... and the V goes on top and the (1+rt) goes on the bottom. Make sure that the V is a capital.

Then the amount of principal is 2,307.69

Using the formula given, we find that:

------------------

Item a:

The future value formula is given by:

[tex]V = p + prt[/tex]

Solving for p:

[tex]p + prt = V[/tex]

[tex]p(1 + rt) = V[/tex]

[tex]p = \frac{V}{1 + rt}[/tex]

------------------

Item b:

The principal is:

[tex]p = \frac{V}{1 + rt} = \frac{3000}{1 + 5(0.06}} = 2307.69[/tex]

The principal will be of $2,307.69.

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A number system is defined as a system of writing to express numbers. between 9 and 10  positive integers is the square root of 85 is there.

A number system is defined as a system of writing to express numbers.

We need to find the two consecutive positive integers  which have square root of 85 in between.

Firstly we need to know meaning of consecutive numbers.

Numbers which follow each other continuously in the order from smallest to largest are consecutive numbers.

Let us take some perfect square numbers

1,4,16,25,36,49,64,81,100

We know that square root of 81 is 9

square root of 100 is 10

square root of 85 is in between 9 and 10

Hence between 9 and 10  positive integers is the square root of 85 is there.

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Answer-

[tex]\boxed{\boxed{(x+2)^4=x^4+8x^3+24x^2+32x+16}}[/tex]

Solution-

Given expression is [tex](x+2)^4[/tex]

Applying Binomial Theorem

[tex]\left(a+b\right)^n=\sum _{i=0}^n\binom{n}{i}a^{\left(n-i\right)}b^i[/tex]

Here,

a = x, b = 2 and n = 4

So,

[tex]\left(x+2\right)^4=\sum _{i=0}^4\binom{4}{i}x^{\left(4-i\right)}\cdot \:2^i[/tex]

Expanding the summation

[tex]=\dfrac{4!}{0!\left(4-0\right)!}x^4\cdot \:2^0+\dfrac{4!}{1!\left(4-1\right)!}x^3\cdot \:2^1+\dfrac{4!}{2!\left(4-2\right)!}x^2\cdot \:2^2+\dfrac{4!}{3!\left(4-3\right)!}x^1\cdot \:2^3+\dfrac{4!}{4!\left(4-4\right)!}x^0\cdot \:2^4[/tex]

[tex]=\dfrac{4!}{0!\left(4\right)!}x^4\cdot \:2^0+\dfrac{4!}{1!\left(3\right)!}x^3\cdot \:2^1+\dfrac{4!}{2!\left(2\right)!}x^2\cdot \:2^2+\dfrac{4!}{3!\left(1\right)!}x^1\cdot \:2^3+\dfrac{4!}{4!\left(0\right)!}x^0\cdot \:2^4[/tex]

[tex]=1\cdot x^4\cdot \:1+4\cdot x^3\cdot \:2+6x^2\cdot \:4+4\cdot x\cdot \:8+1\cdot 1\cdot \:16[/tex]

[tex]=x^4+8x^3+24x^2+32x+16[/tex]

Answer:

The answer to this question can be viewed in the images attached.

Hope it helps. Thanks

The answer is A. The net pay is correct.

Answer:

Area and Side length of a rhombus.

Step-by-step explanation:

1. Area and side length of a rhombus - This is least proportional as they are inversely proportional.

2. Distance and time when speed is constant is proportional.

Distance = speed x time

When speed is constant, the distance increases with respect to speed.

3. Total cost and the number of movie tickets purchased.

As the number of tickets purchased increases, the cost also increases.

4. Hours worked and money earned

When the number of hours increases, the money earned also increases.

Nper = 11*2 = 22 (indicates the period over which interest payments are made)

PMT = 1000*10.3%*1/2 = 51.5 (indicates sem-annual interest payments)

PV = 1000*95% = 950 (indicates the current selling price of the bonds)

FV = 1000 (indicates the face value of bonds)

Rate = ? (Indicates YTM)

YTM = Rate(Nper,PMT,PV,FV)*2 = Rate(22,51.5,-950,1000)*2 = 11.098% or 11.10%

Answer is 11.098% or 11.10%.

Answer:

Step-by-step explanation:

(4x - 4y)(2x + y) =

4x(2x + y) - 4y(2x + y) =

8x²+4xy-8xy-4y²=

8x²-4y²-4xy

Factorise term

4(2x²-y²-xy)

PLEASE MARK BRAINLIEST.

Answer:  The correct option is (B) [tex]1\dfrac{1}{2}.[/tex]

Step-by-step explanation:  Given that Alice had [tex]4\dfrac{1}{4}[/tex] pounds of walnuts at the beginning of the week. At the end of the week, she had [tex]2\dfrac{3}{4}[/tex] pounds.

We are to find the quantity of walnuts that she had used.

We have

The quantity of walnuts that Alice has is

[tex]q_1=4\dfrac{1}{4}=\dfrac{17}{4}~\textup{pounds}[/tex]

and the quantity of walnut that she had at the end of the week is

[tex]q_2=2\dfrac{3}{4}=\dfrac{11}{4}~\textup{pounds}.[/tex]

Therefore, the quantity of walnut that she has used is given by

[tex]Q=q_1-q_2=\dfrac{17}{4}-\dfrac{11}{4}=\dfrac{6}{4}=\dfrac{3}{2}=1\dfrac{1}{2}.[/tex]

Thus, the required quantity of walnut that she has used is [tex]1\dfrac{1}{2}~\textup{pounds}.[/tex]

Option (B) is CORRECT.

Answer:

Amanda's method is linear because the number of minutes increased by an equal number every week.Step-by-step explanation:I took the test and got it right.

Amanda          

Billy1st week       10                   52nd week      20                  10 3rd week       30                  204th week       40                  40A)

Amanda's method is linear because the number of minutes increased by an equal number every week.common difference is 10.1st week      0 + 10 = 102nd week   10 + 10 = 203rd week    20 + 10 = 304th week    30 + 10 = 40Billy's method is exponential:5(2)^x1st week   5(2⁰) = 5(1) = 52nd week  5(2¹) = 5(2) = 103rd week   5(2²) = 5(4) = 204th week   5(2³) = 5(8) = 40Mark

Answer:

Step-by-step explanation:

Remember that in a isosceles trapezoid, its angles on the base are always congruent.

Also, we know by definition that the sum of interior angles of a trapezoid is equal to 360°, so

[tex]2(2x)+2(10x+24)=360\\4x+20x+48=360\\24x=360-48\\x=\frac{312}{24}\\ x=13[/tex]

Therefore, the right answer is D.

Answer: 13

a p e x confirmed

There are approximately 72 orange balls in the bag.

We have,

Let's assume the number of orange balls in the bag is x.

Given that more than half of the balls are painted orange, we have the inequality:

x > 144/2

x > 72

Now, let's consider the probability of drawing two balls of the same color:

The probability of drawing two orange balls.

= (x/144) * ((x-1)/(144-1))

= (x(x-1))/(144*143)

The probability of drawing two blue balls.

= ((144-x)/144) * ((144-x-1)/(144-1))

= ((144-x)(143-x))/(144*143)

Given that the probability of drawing two balls of the same color is the same as the probability of drawing two balls of different colors, we can set up the equation:

(x(x-1))/(144143) = ((144-x)(143-x))/(144143)

Simplifying the equation:

x(x-1) = (144-x)(143-x)

x^2 - x = 144143 - 287x + x^2

288x = 144143

x = (144*143)/288

x ≈ 72

Therefore,

There are approximately 72 orange balls in the bag.

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Answer:

(K-h) (x) = 4(x-2)

Step-by-step explanation:

The cost of producing x soccer balls in thousands of dollars is represented by h (x) = 5x + 6

Revenue generated is represented by K(x) = (9x-2)

Them ( K-h) (x) will represent

         ( K-h )x = cost of revenue - production

                     = profit

         ( K-h )x = K(x) - h(x)

                     = (9x-2) - (5x + 6)

                     = (9x - 5x) - (2+6)

                     = 4x - 8

Profit = (K-h) (x) = 4(x-2)

Answer:

Option C

The area of the doghouse is [tex]66.5\ ft^{2}[/tex]

Step-by-step explanation:

we know that

The area of trapezoid is equal to

[tex]A=\frac{1}{2}(b1+b2)h[/tex]

where

b1,b2 are the parallel bases of trapezoid

h is the height of trapezoid

in this problem we have

[tex]b1=7\ ft[/tex]

[tex]b2=7+5=12\ ft[/tex]

[tex]h=7\ ft[/tex]

substitute

[tex]A=\frac{1}{2}(7+12)7=66.5\ ft^{2}[/tex]

For the parent function y = f(x), the vertical stretching or compression of the function is a f(x). 

If | a | < 1 (a fraction between 0 and 1), then the graph is compressed vertically by a factor of a units.
If | a | > 1, then the graph is stretched vertically by a factor of a units.

For values of a that are negative, then the vertical compression or vertical stretching of the graph is followed by a reflection across the x-axis.

Yes,  Y = 0.3x^2 is correct!!

Answer:

its 12.94%

Step-by-step explanation

divide total km by time

6561 / 9 = 729 km per hour

208 is 65 percent of 320.

A percentage is a number that tells us how much out of 100 and can also be written as a decimal or a fraction.

A percentage is a number that tells us how much out of 100 and can also be written as a decimal or a fraction, To change the percentage to a fraction, just put the percentage number in the numerator and 100 in the denominator.

We can write a percentage in the form of fraction as well.

For example :- 10%, 78%, 56%, 98%

Given that, what is percent of 320 is 208,

Using the concept of percentage,

Divide 208 by 320 and multiply it by 100

= 208 / 320 x 100

= 0.65 x 100

= 65%

Hence, 208 is 65 percent of 320.

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To find the smallest poster area with a fixed printed area of 388 square centimeters, calculate optimized values for the width and height of the printed area, considering the margins, and derive the poster's dimensions by adding the margins to these values.

To find the dimensions of the poster with the smallest area given a fixed printed area, we should first determine the dimensions of the printed area. We know that the printed area is 388 square centimeters and that the margins do not change. Let's denote the width of the printed area as w and the height as h.

The area of the printed material is given by Area = w × h = 388 cm². The total width of the poster would be w + 2×(8 cm) (since there are two side margins), and the total height would be h + 2×(4 cm) (since there are top and bottom margins).

To minimize the area of the poster, we need to minimize the function for the total area of the poster A(w,h) = (w + 16)(h + 8). As the printed area is fixed, we can express h in terms of w using h = 388/w and substitute this into the function to get A(w) = (w + 16)((388/w) + 8).

Taking the derivative dA/dw and setting it to zero, we find the optimal value for w, and consequently, we calculate h. The dimensions of the poster that minimize the total area can then be determined by adding the margins to these optimized values of w and h.

Final answer:

The function f(x) =[tex]x^4 + 4x^2[/tex]  is factored using the difference of squares method to achieve its linear factorization. The final factorization over complex numbers is f(x) = x * x * (x + 2i) * (x - 2i).

Explanation:

To write a linear factorization of the function f(x) = [tex]x^4 + 4x^2[/tex]  to find the factors of the polynomial that are linear, meaning each factor will be of the form (x - c) where c is a constant.

First, notice that the given polynomial is a quadratic in form, where [tex]x^2[/tex] is our variable. This gives us [tex]f(x) = (x^2)2 + 4(x^2)[/tex]which resembles the sum of squares [tex]a^2 + 2ab + b2 = (a + b)^2.[/tex] However, we only have [tex]a^2 + 2ab[/tex], with b being 2, and a being  [tex]x^2[/tex].

To create a perfect square, we can write it as a difference of squares by adding and subtracting 4: [tex]f(x) = (x^2 + 2)^2 - (2)^2[/tex]. This can be factored further using the difference of squares formula, giving us[tex]f(x) = (x^2 + 2 + 2)(x^2 + 2 - 2)[/tex] which simplifies to [tex]f(x) = (x^2 + 4)(x^2).[/tex]

The linear factorization can be found by recognizing that x2 is already a product of linear factors x * x. Since  [tex]x^2[/tex] + 4 cannot be factored over the real numbers, we need to use complex numbers to factor it further.

Using the sum of squares, we get  [tex]x^2[/tex] + 4 = (x + 2i)(x - 2i), resulting in the final linear factorization over the complex numbers: f(x) = x * x * (x + 2i) * (x - 2i).

We are given the two constraints:

x ≥ 5 and y ≥ 10

Now the other constraint must of course be based on the sum of the two. It was given that the budget is $5000 so the sum must be greater than that, that is:

500 x + 150 y ≤ 5000

To solve for the length and width of the rectangle, equations were set up based on the given perimeter and the relation between length and width. The width was found to be 8 cm, and substituting this into the length formula gave a length of 19 cm.

The question concerns finding the length and width of a rectangle given that the length is 5 cm less than three times the width and the perimeter is 54 cm. To solve this, let's denote the width of the rectangle as 'w' and the length as 'l'. The relationship between the length and width can be expressed as 'l = 3w - 5 cm'. The perimeter (P) of a rectangle is given by P = 2l + 2w, and substituting our expressions in terms of 'w' into the formula gives us 2(3w - 5) + 2w = 54. Simplifying and solving for 'w' gives us the width. Subsequently, we can substitute this width into the equation for length to find 'l'.

So, let's start by setting up the equation:
2(3w - 5) + 2w = 54
6w - 10 + 2w = 54
8w - 10 = 54
8w = 64
w = 8 cm

Now we substitute w = 8 cm into the length formula:
l = 3(8) - 5
l = 24 - 5
l = 19 cm

Therefore, the width of the rectangle is 8 cm and the length is 19 cm.

Answer:

it would cancel eachother out so infinite

Step-by-step explanation: