in circle p what is the measure of arc ab

Answer:

Step-by-step explanation:

For all Plato users.

C=(-4,-4)

E = (4,-2)

-4 +4 = 0/2 =0

-4+-2 = -6/2 = -3

(0,-3)

Answer:

1. 19.2

Step-by-step explanation:    

Please find the attachment.

Since we know that radius is perpendicular to tangent of a circle. So AB will be perpendicular to BC at c and DC is perpendicular to CB at C.

Now we will construct a perpendicular line to radius AB at point E from the center of our small circle. Since we have two right angles at point B and C so we will also have right angles at point E and D as well.    

Length of CD is is 7 so length of BE will be 7 as well and length of EA will be 10-7=3. Length of DE will be equal to length BC that is 19.

Now we have formed a right triangle and now we will use Pythagoras theorem to find the length of AD.  

[tex](AD)^{2}=(DE)^{2}+(EA)^{2}[/tex]    

Upon substituting our values in above formula we will get,

[tex](AD)^{2}=(19)^{2}+(3)^{2}[/tex]

[tex](AD)^{2}=361+9[/tex]

[tex](AD)^{2}=370[/tex]

Upon taking square root of both sides of our equation we will get,

[tex]AD=\sqrt{370}[/tex]  

[tex]AD=19.2353840616713448\approx 19.2[/tex]

Therefore, the length of AD will be 19.2 and 1st option is the correct choice.

Final answer:

The total resistance in a series circuit is found by summing the resistances of individual components. For the given resistors of 3+j5 ohms, 5-j8 ohms, and 6+j4 ohms, the total resistance is 14+j1 ohms.

Explanation:

In a series circuit, the total resistance (Rtotal) is the sum of the individual resistances. We have three resistors with complex resistance values: R1 = 3 + j5 ohms, R2 = 5 - j8 ohms, and R3 = 6 + j4 ohms. Adding these together will give us:

Rtotal = R1 + R2 + R3

Calculate the real parts of each resistor and the imaginary parts separately:

Real part = 3 + 5 + 6 = 14 ohms,
Imaginary part = j5 - j8 + j4 = j1 ohm.

Thus, the total resistance in the circuit is Rtotal = 14 + j1 ohms.

Three other ordered pairs with θ between −360° and 360° that name the same point as (3, 135°) are (−243, −45°), (−177, −15°), and (315, 495°).

The ordered pairs (−243, −45°), (−177, −15°) and (315, 495°) all name the same point as (3, 135°) with θ between −360° and 360°.

To find these ordered pairs, you can add or subtract 360° to the given angle of 135° while keeping the x-coordinate constant at 3.

For example, you could subtract 360° from 135° to get −225° and combine it with the x-coordinate of 3 to get the ordered pair (3, −225°).

Answer: B. 36

Step-by-step explanation: Trust me!

Answer:

-7

Step-by-step explanation:

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Answer:

-7

Step-by-step explanation:

We are given that   a function

[tex]y=-2+5 sin(\frac{\pi}{12}(x-2))[/tex]

We have to find the minimum value of y.

We know that range of sin x is [-1,1].

[tex]-1\leq sin(\frac{\pi}{12}(x-2))\leq 1[/tex]

[tex]-5\leq 5sin(\frac{\pi}{12}(x-2))\leq 5[/tex]

[tex]-5-2\leq -2+5sin(\frac{\pi}{12}(x-2))\leq 5-2[/tex]

[tex]-7\leq -2+5sin(\frac{\pi}{12}(x-2))\leq 3[/tex]

[tex]-7\leq y\leq 3[/tex]

Maximum value of y=3

Minimum value of y=-7

Hence, the minimum value of given function =-7

Answer:

60 odd numbers

Step-by-step explanation:

A normal dice has 6 different sides numbered from 1 to 6, each side has the same probability of appearing when you roll the dice, i.e., in the long run each number will appear 1/6 of the times. We have three different odd numbers in a normal dice each will appear 1/6 of the times in the long run. Therefore, in the long run we hope to get 3/6 = 1/2 of the times an odd number and rolling the dice 120 times will produce about 120(1/2) = 60 odd numbers.

The correct answer is C: Rhombus. This is how you find your answer: desmos.com because you just plant in the ordered pair into the program and it plots out the shape for you. The only thing you need to know is your shapes and you should be set.

Answer:

45 Fake Dollars

Step-by-step explanation:

4x5=20

d=20+25

d=45 Fake Dollars

Answer:

45

Step-by-step explanation:

Answer:

The correct statement is:

On average, the height of a garden gnome varies 3.2 inches from the mean of 6 inches.

Step-by-step explanation:

We are given a data of 11 gardens as:

2   9    1    23    3    7    10    2    10    9     7

Now on removing the outlier i.e. 23 (since it is the very large value as compared to other data points) the entries are as follows:

x         |x-x'|        

2          4              

9          3              

1           5              

3          3              

7           1                

10         4              

2           4              

10          4              

9           3              

7            1              

Now mean of the data is denoted by x' and is calculated as:

[tex]x'=\dfrac{2+9+1+3+7+10+2+10+9+7}{10}\\\\x'=\dfrac{60}{10}\\\\x'=6[/tex]

Hence, Mean(x')=6

Now,

∑ |x-x'|=32

Now mean of the absolute deviation is:

[tex]\dfrac{32}{10}=3.2[/tex]

This means that , On average, the height of a garden gnome varies 3.2 inches from the mean of 6 inches.

Answer:

[tex]f(x)\rightarrow +\infty\text{ as }x\rightarrow -\infty[/tex]

[tex]f(x)\rightarrow +\infty\text{ as }x\rightarrow +\infty[/tex]

Step-by-step explanation:

Given polynomial function is,

[tex]f(x)=3x^4+2x^2-x[/tex]

Since, the end behavior of a polynomial is same as the end behavior of leading term,

Here, the leading term = [tex]3x^4[/tex]

[tex]\text{As }x\rightarrow -\infty[/tex]

The leading term is positive,

[tex]\text{While, as }x\rightarrow +\infty[/tex]

The leading term is positive,

Hence, the end behavior of the given polynomial is,

[tex]f(x)\rightarrow +\infty\text{ as }x\rightarrow -\infty[/tex]

[tex]f(x)\rightarrow +\infty\text{ as }x\rightarrow +\infty[/tex]

⇒ In the graph of f(x), both ends will go upward.

Answer:both ends go down !

Step-by-step explanation:

To calculate the number of traffic lights needed for a town with 6 streets intersecting each other, you can use the formula Number of traffic lights = Number of intersections. In this case, 15 traffic lights are needed.

A traffic light is needed at each intersection. How many traffic lights are needed if there are 6 streets in the town?

To determine the number of traffic lights needed for 6 streets, we use the formula: Number of traffic lights = Number of intersections. In a town with 6 streets, each street intersects with every other street, resulting in 15 intersections. Therefore, 15 traffic lights are needed for the 6 streets.