In a community fitness group, 40% of members run for exercise and 36% of members run and play a sport. What percentage of members who run for exercise also play a sport?

Answers

Answer 1

Imagine you have 100 people, this means 40 of them run for exercise. We also know 36 people run for exercise AND play a sport. So 36 of the 40 runners are the percentage we are looking for, this would be 36/40=0.9 or 90%

Answer 2

By dividing the percentage of community fitness group members who run and play a sport (36%) by those who run for exercise (40%), we find that 90% of the members who run for exercise also play a sport.

To determine the percentage of community fitness group members who run for exercise and also play a sport, we can use the information provided. The question states that 40% of members run for exercise and 36% of members run and play a sport. To find what percentage of members who run also play a sport, we need to find the proportion of runners who are also sport players.

To do this, we divide the percentage of members who run and play a sport by the percentage who only run:

Percentage of runners who also play a sport = (Percentage of members who run and play a sport) / (Percentage of members who run for exercise)

So,

Percentage of runners who also play a sport = 36% / 40% = 0.9

We then multiply by 100 to convert this to a percentage:

0.9 × 100 = 90%.

Therefore, 90% of the members who run for exercise also play a sport.

Related Questions

I need to know the solution

Answers

For the first one, you have to get x by itself and make it positive. So divide both sides by -11. Then, you get x=-7. The answer is x=-7.

For the second one, get x by itself as a whole number. Multiply each side by 8. You get x=16. The answer is x=16. Hope this helps! ;)

a. x=7
and
c. x=16
you can also get an app that is called script calculator that helps with that

When 332 college students are randomly selected and surveyed, it is found that 113 own a car. find a 99% confidence interval for the true proportion of all college students who own a car?

Answers

Given:
n = 332, sample size
p = 113/332 = 0.3404, sample proportion
99% confidence interval

The confidence interval for the population is calculated from
[tex]p \pm z^{*} \sqrt{ \frac{p(1-p)}{n} } [/tex]
where z* = 2.58 for the 99% confidence level (from tables)..

[tex]2.58 \sqrt{ \frac{0.3404(1-0.3404)}{332} } =0.0671[/tex]
Therefore the 99% confidence interval is
(0.3404 - 0.0671, 0.3404 + 0.0671) = (0.2733, 0.4075)

Answer:
The 99% confidence interval is (0.273, 0.408) or (27%, 41%).
That is, between 27% and 41% of the students own cars.

A volcano fills the volume between the graphs z=0 and z=1/(x^2+y^2)^10 and outside the cylinder x+y=1. find the volume.

Answers

For this case, we use the cylindrical coordinates:
x² + y² = r²
dV = r dz dr dθ

The limits are:
z = 0 to z = 1/(r²)^10 = 1/r^20
r = 1 to ∞
θ = 0 to 2π

Integrating over the limits:
V = ∫ [0 to 2π] ∫ [1 to ∞] ∫ [0 to 1/r^20] r dz dr dθ
V = ∫ [0 to 2π] ∫ [1 to ∞] rz | [z = 0 to 1/r^20] dr dθ
V = ∫ [0 to 2π] ∫ [1 to ∞] 1/r^19 dr dθ
V = ∫ [0 to 2π] −1/(18r^18) |[1 to ∞] dθ
V = ∫ [0 to 2π] 1/18 dθ
V = θ/18 |[0 to 2π]
V = π/9

The volume of the volcano is an illustration of definite integral

The volume of the volcano is: [tex]\mathbf{\frac{1}{9}\pi}[/tex]

The graphs are given as:

[tex]\mathbf{z = 0}[/tex] and [tex]\mathbf{z = \frac{1}{(x^2 + y^2)^{10}}}[/tex]

The cylinder is:

[tex]\mathbf{x + y =1}[/tex]

For cylindrical coordinates, we have:

[tex]\mathbf{r^2 =x^2 + y^2}[/tex]

So, we have:

[tex]\mathbf{z = \frac{1}{(r^2)^{10}}}[/tex]

[tex]\mathbf{z = \frac{1}{r^{20}}}[/tex]

Where:

[tex]\mathbf{r = 1 \to \infty}[/tex]

[tex]\mathbf{\theta = 0 \to 2\pi}[/tex]

So, the integral is:

[tex]\mathbf{V = \int\limits^{2\pi}_0 {\int\limits^{\infty}_1 {\frac{1}{r^{20}}} \, r\ dr } \, d\theta }[/tex]

Cancel out r

[tex]\mathbf{V = \int\limits^{2\pi}_0 {\int\limits^{\infty}_1 {\frac{1}{r^{19}}} \, dr } \, d\theta }[/tex]

Rewrite as:

[tex]\mathbf{V = \int\limits^{2\pi}_0 {\int\limits^{\infty}_1 {r^{-19}} \, dr } \, d\theta }[/tex]

Integrate

[tex]\mathbf{V = \int\limits^{2\pi}_0 {{-\frac{1}{18}r^{-18}}} |\limits^{\infty}_1 \, d\theta }[/tex]

Expand

[tex]\mathbf{V = \int\limits^{2\pi}_0 {{-\frac{1}{18}(\infty^{-18} -1^{-18}) }} , d\theta }[/tex]

[tex]\mathbf{V = \int\limits^{2\pi}_0 {{-\frac{1}{18}(0 -1) }} , d\theta }[/tex]

[tex]\mathbf{V = \int\limits^{2\pi}_0 {{-\frac{1}{18}( -1) }} , d\theta }[/tex]

[tex]\mathbf{V = \int\limits^{2\pi}_0 {{\frac{1}{18} }} , d\theta }[/tex]

Integrate

[tex]\mathbf{V = \frac{1}{18}(\theta)|\limits^{2\pi}_0}[/tex]

Expand

[tex]\mathbf{V = \frac{1}{18}(2\pi - 0)}[/tex]

[tex]\mathbf{V = \frac{1}{18}(2\pi )}[/tex]

Cancel out 2

[tex]\mathbf{V = \frac{1}{9}\pi}[/tex]

Hence, the volume is: [tex]\mathbf{\frac{1}{9}\pi}[/tex]

Answers

alrighty

remember
[tex](ab)^c=(a^c)(b^c)[/tex]
and
[tex]x^\frac{m}{n}=\sqrt[n]{x^m}[/tex]
and
[tex](x^m)^n=x^{mn}
and
[tex]x^0=1[/tex] for all real numbers x
and
[tex]x^{-m}=\frac{1}{x^m}[/tex]

b.
[tex](x^5y^4)^\frac{1}{2}=((x^5)^\frac{1}{2})((y^4)^\frac{1}{2})[/tex]=
[tex](x^\frac{5}{2})(y^\frac{4}{2})=(\sqrt{x^5})(\sqrt{y^4})=x^2y^2\sqrt{x}[/tex]

c.
x^0=1
so
that (x^-3y)^0=1
because exponents first in pemdas
so we are left with
x^2y^-1
[tex]x^2y^{-1}=(x^2)(y^{-1})=(x^2)(\frac{1}{y^1})=\frac{x^2}{y}[/tex]

[tex](x^5y^4)^{ \frac{1}{2} }= \sqrt{x^5y^4} =x^2y^2 \sqrt{x} \\ \\ \\ (x^2y^{-1})(x^{-3}y)^0= (x^2y^{-1})*1= \frac{x^2}{y} [/tex]

enter an equation in slope-intercept form that describes a line that contains the points (4,1) and (4,2)

Answers

[tex]\bf \begin{array}{lllll} &x_1&y_1&x_2&y_2\\ % (a,b) &({{ 4}}\quad ,&{{ 1}})\quad % (c,d) &({{ 4}}\quad ,&{{ 2}}) \end{array} \\\\\\ % slope = m slope = {{ m}}= \cfrac{rise}{run} \implies \cfrac{{{ y_2}}-{{ y_1}}}{{{ x_2}}-{{ x_1}}}\implies \cfrac{2-1}{4-4}\implies \cfrac{1}{0}\leftarrow unde fined[/tex]

so... the slope is undefined, the graph of it is just a vertical line, check the picture below, and that's the equation.

now... you can't quite put it in y = mx + b, or slope-intercept form, since it has no defined slope and it doesn't have an y-intercept either.

Determine the number of possible triangles, abc, that can be formed given c = 85°, a = 10, and c = 13. 0 1 2

Answers

Given:
m∠C = 85°, a= 10, c = 13

From the Law of Sines,
sin(A)/a = sin(C)/c
sin(A) = (a/c)*sin(C)
= (10/13)*sin(85°)
= 0.7663
m∠A = sin⁻¹ 0.7663 = 50°, or 130°

When m∠A = 50°, obtain
m∠B = 180° - (m∠A + m∠C) = 180 - (50+85) = 45°
Again from the Law of Sines, obtain
b = (sinB/sinC)*c = 9.2

When m∠A = 130°, obtain
m∠B = 180° - (130 + 85) = -35° (not possible)
Therefore this triangle does not exist.

Answer:
There is only one possible triangle, with
A=50°, B=45°, C=85°, a=10, b=9.2, c=13.

Final answer:

Correcting for the apparent typo in the question, assuming 'c' refers to an angle and a side length respectively, there can only be one possible triangle formed given the angle and two sides. This is based on geometric principles where a unique triangle can be determined from an angle opposite and its respective side length.

Explanation:

The question presents a probable typo since it mentions two different values for 'c'. Assuming 'c = 85°' refers to an angle, and 'c = 13' refers to the length of a side opposite this angle, the proper interpretation involves finding possible triangles given an angle and two sides. However, the principles of geometry dictate that with one angle and two sides specified, especially in this non-ambiguous manner where one side length and the angle opposite are known, one can determine a unique triangle, assuming the given information leads to a viable geometric figure.

By using the Law of Sines, one might attempt to find the other angles or sides, but since we only have one angle and one side length, we directly know there's no ambiguity - geometrically speaking, there's only one way to construct such a triangle, thus, only one possible triangle can be formed given the corrected assumptions.

In two or more complete sentences, compare the number of x-intercepts in the graph of f(x) = x2 to the number of x-intercepts in the graph of g(x) = -(x-4)2. Be sure to include the transformations that occurred between the parent function f(x) and its image g(x).

Answers

There is only one x-intercept for f(x) and g(x), f(x) having a minimum value of zero and g(x) having a maximum value of zero. f(x)=0 when x=0, g(x)=0 when x=4.

g(x) is f(x) reflected about the about the x-axis and shifted to the right by 4 units.

Since x^2 = 0 implies x = 0 with multiplicity 2, there is one x-intercept
Since -x^2-5 = 0 implies x = +-sqrt(5)i, there are no x-intercepts
Transformations:
Reflect f(x) in the x-axis,
then vertically shift the result down by 5 units,
to get g(x).

The circle given by x^2+y^2-4x-10=0 can be written in standard form like this: (x-h)^2+y^2=14. What is the value of h in this equation??

Answers

Answer: H=2

Step-by-step explanation:

we just need to complete the square for the x terms

gropu x terms

x^2-4x

take 1/2 of linear coefient and square it

-4/2=-2, (-2)^2=4

x^2-4x+4

factor

(x-2)^2

h=2

The value of h is 2.

Completing the square for the x terms by grouping x terms

x^2-4x

Taking 1/2 of linear coefficient and squaring it.

-4/2=-2, (-2)^2=4

x^2-4x+4

Factorizing the equation.

(x-2)^2

h=2.

What is an equation?

An equation is a mathematical statement this is made of two expressions related with the aid of an identical sign. As instance, 3x – 5 = 16 is an equation. To fix this equation, we get the value of the variable x as x = 7.

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The perimeter of a square is 96 inches. if the side length is 2x + 4, what is the value of x and the length of each side?

Answers

subtract 4 from 96 and divide by 2

The area of one circle is 4 times as large as a smaller circle with a radius of 3 inches. the radius of the larger circle is

Answers

The area of small circle= π(3^2)=9π
As the area of other circle is four times greater than small one
So the area of larger circle will be= 4(9π)=36π
So the radius will be
area=π r^2
36π=π(r^2)
r^2=36
√r^2=√36
r=6 inchs
ANSWER IS THAT THE RADIUSOF LARGER CIRCLE WILL BE
6 INCHES

HOW DO YOU MOVE A VARIABLE FROM ONE SIDE OF AN EQUATION TO ANOTHER? I need to know as I'm reviewing module 7 algebra and i want to know please

Answers

The easiest way to do this is to add or subtract the value of the variable.
For example in the equation 5+a=7, subtract a from both sides to get 5=7-a.
If the initial equation was 5-a=7, add from both sides (5=a+7).
Basically, if the initial value is negative, add its value to cancel to zero.
Do the opposite if the initial value is positive.

A square garden plot has an area of 75 ft^2. Find the length of each side in simplest radical form. Calculate the length of each side to the nearest tenth of a foot..

Answers

Hello.

The area of a square is calculated by the formula:

A = l²

As A = 75 ft², we have:

75 = l²

l = √75

Now, note that: 75 = 3 . 25 = 3 . 5²

So:

l = √(3 . 5²) = √3 . √(5²)

l = 5√3 ft

Now, we can assume √3 = 1.73

l ≈ 5 * 1.732

l ≈ 8,7 ft (Note that I have already put it in the nearest tenth)

OK :)

What is the circumference of this circle, in millimeters? use 22/7 for pi

r = 49

Answers

Circumference=[tex]2\pi r=2\times \dfrac{22}{7} \times 49 = \boxed{308 \text{ mm}}[/tex]

Answer: circumference = 308mm

Step-by-step explanation: the formula for the circumference of a circle is given by

C=2πr

Given that r=49mm

Pi=22/4

C=2*22/7*49

C=44*7=308mm

In geometry, the circumference of a circle is the distance around it. That is, the circumference would be the length of the circle if it were opened up and straightened out to a line segment. Since a circle is the edge of a disk, circumference is a special case of perimeter.

A given line has the equation 10x + 2y = −2.

What is the equation, in slope-intercept form, of the line that is parallel to the given line and passes through the point (0, 12)?

Answers

y = -5x + 12 since the slope of that line is -5x and in order to pass through that point the y intercept must be 12

Step 1

Find the slope of the given line

we have

[tex]10x+2y=-2[/tex]

Isolate the variable y

Subtract [tex]10x[/tex] both sides

[tex]2y=-10x-2[/tex]

Divide by [tex]2[/tex] both sides

[tex]y=-5x-1[/tex]

The slope of the given line is

[tex]m=-5[/tex]

Step 2

Find the equation of the line that is parallel to the given line and passes through the point [tex](0, 12)[/tex]

we know that

If two lines are parallel. then their slope are equal

In this problem we have

[tex]m=-5[/tex]

[tex](0, 12)[/tex]

The equation of the line into slope-intercept form is equal to

[tex]y=mx+b[/tex]

substitute the values

[tex]12=-5*0+b[/tex]

[tex]b=12[/tex]

the equation of the line is

[tex]y=-5x+12[/tex]

therefore

the answer is

[tex]y=-5x+12[/tex]

Simplify 5 − (−1).

a. 6
b. −6
c. 4
d. −4

Answers

Hi!

Subtracting a negative number is the same as adding a positive.

So instead of

5 - (-1)

We could write

5 + 1

5 + 1 = 6

The answer is 6.

Hope this helps! :)

Answer: it is a

Step-by-step explanation: :) :v :B

Constantine picks two letters at random from the word constantinople with replacement. what is the probability that both letters picked are consonants?

Answers

Constantinople has a total of 14 letters of which 9 are consonants

P(picking a consonant) = 9/14

P(2 letters are consonants with replacement) = 9/14 * 9/14 = 81/196

Calculate the upper and lower limit for a 95% confidence interval about this mean. a family needs a new car, but isn't sure they can fit the payment into their budget. a sample of 36 months of grocery bills yields a mean of $94 with a standard deviation of $10. if the upper limit of a 95% confidence level is below $100, the family can afford to buy the car. standard error = (standard deviation)/(square root of sample size) upper limit (dollars and cents) lower limit (dollars and cents)

Answers

To find the upper and lower limits of a 95% confidence interval for the given data, calculate the standard error, use the multiplier of 2, and apply the formula Sample mean ± Multiplier * Standard error.

To calculate the upper and lower limit for a 95% confidence interval, we use the formula: Confidence interval = Sample mean ± Multiplier * Standard error. For this case, the sample mean is $94 and the standard deviation is $10. The standard error is calculated as $10 / √36 = $10 / 6 ≈ $1.67.

With a 95% confidence level, the multiplier is approximately 2. Therefore, the upper limit would be $94 + 2($1.67) = $94 + $3.34 ≈ $97.34, and the lower limit would be $94 - $3.34≈ $90.66.

Which value is in the domain of f(x)?
A.) –7
B.) –6
C.) 4
D.) 5

Answers

C.) 4 is in the domain of f(x)

f(x) = -2x + 3 0<x <= 4

hope that helps

Answer:

C) 4

Step-by-step explanation:

The given function is

[tex]f(x)=\left \{ {{2x+5,\:-6\:<\:x\le0} \atop {-2x+3,\:0\:<x\le4}} \right.[/tex]

The function is defined on two intervals.

The first interval is

[tex]-6\:<\:x\le0[/tex] and the second interval is [tex]\:0\:<x\le4[/tex].

[tex]-7[/tex] does not belong to any of these intervals.

[tex]-6[/tex] does not also belong to any of these intervals.

[tex]4[/tex] belongs to the interval [tex]\:0\:<x\le4[/tex].

Hence 4 is in the domain of f(x).

[tex]5[/tex] does not also belong to any of the intervals.

Therefore the correct answer is C.

HELP if f(x)=-14x-2, then f^-1(x)=?

Answers

Replace f(x) with y. Then swap x and y. Once the swap has been done, solve for y to get the inverse.

[tex]f(x) = -14x - 2 [/tex]

[tex]y = -14x - 2 [/tex]

[tex]x = -14y - 2 [/tex]

[tex]x+2 = -14y [/tex]

[tex]-14y = x+2 [/tex]

[tex]y = -\frac{x+2}{14} [/tex]

[tex]f^{-1}(x) = -\frac{x+2}{14} [/tex]

A ball is thrown from a height of 70 feet with an initial downward velocity of 4/fts. The ball's height h (in feet) after t seconds is given by the following.

h=70-4t-16t^2

How long after the ball is thrown does it hit the ground?

Round your answer(s) to the nearest hundredth.
(If there is more than one answer, use the "or" button.)

Answers

In this one, you must make h = 0.

You get : [tex]-16t^2-4t+70[/tex] which can be further simplified to [tex]8t^2+2t-35[/tex] if you divide all of the numbers by -2.

Here you can use the quadratic formula again!
You get the numbers to be : 1.97 and -2.22

I had made a mistake to think that negative numbers can be included but in these questions, you can't have negative numbers as your answer. So the correct answer is 1.97!

Distance is a scalar quantity that refers to "how much ground an object has covered" during its motion. 1.97 is the time taken by the ball to hit the ground.

What is Distance?

Distance is a scalar quantity that refers to "how much ground an object has covered" during its motion.

Given that a ball is thrown from a height of 70 feet with an initial downward velocity of 4/fts. The ball's height h (in feet) after t seconds is given by the following.

h=70-4t-16t²

Now we can take h=0

h=-16t²+70-4t

-16t²+70-4t

Divide by 2

-8t²-2t+35

Now apply quadratic formula

a=-8, b=-2, c=35

t=-b±√b²-4ac/2a

t=2±√-2²-4(-8)(35)/2(-8)

t=2±√4+1120/-16

we get t= 1.97 and t= -2.22

You get the numbers to be : 1.97 and -2.22

We do not consider negative values. So the correct answer is 1.97

Hence 1.97 is the time taken by the ball to hit the ground.

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Find the missing length.

Answers

Find this using the pythagoream theorem for right triangles.

a^2+b^2=c^2
12^2+9^2=c^2

144+81= c^2
225=c^2
15=c

Final answer: c=15

What percent of 210 is 70?

Answers

if we take 210 to be the 100%, what is 70 off of it in percentage then?

[tex]\bf \begin{array}{ccllll} amount&\%\\ \text{\textemdash\textemdash\textemdash}&\text{\textemdash\textemdash\textemdash}\\ 210&100\\ 70&x \end{array}\implies \cfrac{210}{70}=\cfrac{100}{x}\implies x=\cfrac{70\cdot 100}{210}[/tex]

percent means parts out of 100
so x%=x/100

'of' means multiply

so

what percent of 210 is 70 translates to
x/100 times 210=70
210x/100=70
21x/10=70
times 10 both sides
21x=700
divide both sides by 21
x=33.333333

33.33333333% of 210 is 70

Redo, Answers please?

Answers

11) ?=12
10) ?=13
14) ?=13

11)

11+15+13 = 39

39 - 27 = 12

so

answer
? = 12

10)

18 - 11 + 13 = 20

33 - 20 = 13

so

answer

? = 13

14)

16+17+12=45

45 - 27 = 18

answer

? = 18

A can factory requires 2 sheets of metal to make 36 cans and 10 sheets of metal to make 180 cans. The proportionality constant between the number of cans made and the number of sheets of metal used is

a-36
b-18
c-288
d-5

Answers

B. 18 because you divide the total number of cans by the number of sheets used to make them. 36/2 = 18, 180/10 = 18

Consider the leading term of the polynomial function. What is the end behavior of the graph? Describe the end behavior and provide the leading term.
-3x^5 + 9x^4 + 5x^3 + 3

Answers

The leading term is -3x^5. The end behavior of any function is the behavior that the highest powered term has as x approaches ±oo.

In this case because the highest order term is -3x^5, as x approaches -oo, y approaches +oo. And as x approaches +oo, y approaches -oo.

Smallville’s town council has records of the town’s budget over a 10-year period. Create a best fit and model for the data. What does the model predict the town’s budget will be in the year 2011?

Answers

I found the missing image and choices.
If these were the missing choices:

A)$391,000

B)$417,000

C)$404,000

D)$411,000

My answer is D) $411,000 in 2011.

There is an average increase of 4% from the previous budget to arrive at the amount of the current year.

2009 budget $381,700

381,700 * (1.04)² = 381,700 * 1.0816 = 412,846.72 only Choice D. is nearest to the amount

2000 budget $265,100

265,100 * (1.04)¹¹ = 265,100 * 1.540 = 408,254 only Choice D. is nearest to the amount.

Two less than twice a number is the same as four times the number

Answers

x is the number
-2+2x=4x
minus 2x both sides
-2=2x
divide by 2
-1=x
the number is -1

Final answer:

The algebraic expression representing 'two less than twice a number is the same as four times the number' is solved, resulting in the number being -1.

Explanation:

The student's question involves solving a simple algebraic equation. We are given that two less than twice a number is the same as four times the number. To represent this algebraically, let's let the unknown number be n. The phrase 'twice a number' can be written as 2n. 'Two less than' this expression would be 2n - 2. The statement implies this is equal to four times the number, which is 4n. Therefore, the equation we need to solve is 2n - 2 = 4n. To solve this equation, we need to isolate the variable n on one side of the equals sign.

Subtract 2n from both sides: -2 = 2n.

Divide both sides by 2 to find the value of n: n = -1.

In conclusion, the number that satisfies the condition given is -1.

One student can paint a wall in 10 minutes. another student can paint the same wall in 15 minutes. working together, how long will it take for them to paint the wall?

Answers

the answer:
One student can paint a wall in 10 minutes
another student can paint the same wall in 15 minutes.
If they paint together the wall, the result time will be

15mn - 10mn = 5 mn

proof:
let / = minute

student 1:    / /     /     /    /    /    /    /    /    /

student2:     / /     /     /    /    /    /    /    /    /    /    /    /    /    /
                   x----------------------------------------x
                                already done
the remain time is / / / / / =   five minutes

Answer:

6 days

Step-by-step explanation:

Given that one student can paint a wall in 10 minute and another student in 15 minutes.

Since if number of persons increase, painting time decreases, this is a question of inverse proportion

Hence if they work together they can paint in one day

[tex]\frac{1}{10} +\frac{1}{15}[/tex] part of the work

i.e. work completed in 1 day when they work together

=[tex]\frac{1}{10} +\frac{1}{15} \\=\frac{9+6}{90} \\=\frac{1}{6}[/tex]

Hence in 6 days they can together complete the full work

A club decides to sell T-Shirts for 15$ as a fund-raiser. It cost $20 plus $9 per T-Shirt to make them. How many T-Shirts need to be made to make a profit of at least $150?

Answers

The expression for T-shirt production is 20+9T
The expression for total price of selling the T-shirts is 15T

Profit = Total cost of selling - Total cost of buying
Profit = 15T - (20+9T)
Profit = 15T - 20 - 9T
Profit = 6T - 20

To make profit ≥150

6T - 20 ≥ 150
6T ≥ 170
T ≥ 170/6
T ≥ 28.3

The minimum number of T-shirts needed is 29 T-shirts

Find the area of the circle with the given radius or diameter. Use = 3.14.

r = 6

A =

37.68 sq. units
113.04 sq. units
226.08 sq. units

Answers

Radius [ r ] = 6 units

Area of a circle = [tex] \pi r^{2} [/tex] = [tex]3.14 * 6 * 6 = 3.14 * 36 = 113.04 [/tex] sq. units.

Hence, the answer is B.

Answer: 113.04 sq. units

Other Questions

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