How do you rewrite y+4=-2(x-1) in slope-intercept form

Answer:

he's wrong it's actually 80mph

Step-by-step explanation:

dfor every 20 houses 13 have computers

 divide 60 by 20

60/20 = 3

 multiply 3 by 13

3*13 = 39

 39 houses have computers

To find the probability of getting a blue jelly bean, we use the equation P = B / Total. Substituting the given values, we find that the probability of getting a blue jelly bean is approximately 0.1733 or 17.33%.

To solve the given problem, we can use the equation provided in the example: P = B / 26. Since we know that there are 26 blue jelly beans out of 150 total jelly beans, we can substitute these values into the equation to find the probability: P(B) = 26 / 150. Simplifying this fraction, we get P(B) = 13 / 75.

Therefore, the probability of getting a blue jelly bean is 13/75, or approximately 0.1733, which can be expressed as a percentage as 17.33%.

"3 miles; it represents the original distance of the bird from its nest."

x = 71 degrees. Yes, the ladder meets safety standards.

A hypotenuse is defined as the longest side of a right triangle, the side opposite the right angle where the length of the hypotenuse can be found using the Pythagorean theorem, which states that the square of the length of the hypotenuse equals the sum of is the square of the lengths of the other two sides.

The equation is expressed as:

[tex]a^2 + b^2 = c^2[/tex]

a = side of right triangle

b = side of right triangle

c = hypotenuse

For above given information, the problem describes a right triangle with hypotenuse 12, the side against the ground is 4, and the angle between those two sides is "x".  

For this triangle,

cosx = (side adjacent to angle) / hypotenuse

   =  4 /12= 1/3

x  is approximately 70.52° which is 71° rounded to the nearest degree.

Thus, x = 71 degrees. Yes, the ladder meets safety standards.

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Answer:  The required sum is [tex]6x^4-x^3-5x^2+10x+5.[/tex]

Step-by-step explanation:  We are given to find the following sum:

[tex]S=(2x^4+x^3-4x^2+3)+(4x^4-2x^3-x^2+10x+2).[/tex]

To find the sum, we need to add the coefficients of the same exponents of the unknown variable x.

The summation is as follows:

[tex]S\\\\=(2x^4+x^3-4x^2+3)+(4x^4-2x^3-x^2+10x+2)\\\\=(2+4)x^4+(1-2)x^3+(-4-1)x^2+10x+(3+2)\\\\=6x^4+(-1)x^3+(-5)x^2+10x+5\\\\=6x^4-x^3-5x^2+10x+5.[/tex]

Thus, the required sum is [tex]6x^4-x^3-5x^2+10x+5.[/tex]

Answer:2,800.00

Step-by-step explanation:

[tex]\bf u\implies \begin{cases} (14,-6)\\ (-4,7) \end{cases}\implies (-4-14)~,~(7-(-6)) \\\\\\ (-18) ~,~(7+6)\implies \stackrel{\textit{component form}}{\ \textless \ -18~,~13\ \textgreater \ } \\\\[-0.35em] \rule{34em}{0.25pt}\\\\ ||u||=\sqrt{a^2+b^2}\implies ||u||=\sqrt{(-18)^2+13^2}\implies ||u||=\sqrt{493}[/tex]

The component form of vector u is (-18, 13) and its magnitude is approximately 22.2.

The subject of this question is vector algebra, specifically finding the component form and magnitude of a vector. The component form of a vector is found by subtracting the coordinates of the initial point from the terminal point. Thus, the component form of vector u with initial point at (14, -6) and terminal point at (-4, 7) is (-4-14 , 7-(-6)) = (-18, 13).

To find the magnitude of a vector, you use the formula which is the square root of the sum of the squares of the components. So for vector u, the magnitude is found by calculating √((-18)² + 13²) = √ (324 + 169) = √493, which is approximately 22.2.

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The value of j is -3.

An expression is a way of writing a statement with more than two variables or numbers with operations such as addition, subtraction, multiplication, and division.

Example: 2 + 3x + 4y = 7 is an expression.

We have,

j = (2j + 3)

Solve for j.

j = 2j + 3

Keep like terms on one side.

2j - j = -3

j = -3

Thus,

The value of j is -3.

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Answer:

probably  3:6 and 2:6

Step-by-step explanation:

An outlier is a data point that is significantly different from the other data points in a set. It may or may not affect measures of central tendency. Outliers are not always the highest or lowest values in a data set.

An outlier is a data point that is significantly different from the other data points in a set. It can be either higher or lower than the other values.

Outliers may be errors or abnormal data, or they may provide valuable insights into the population under study.

An outlier does not necessarily mean that it is a false data point. It needs to be examined closely to determine if it should be included in the analysis or not.

An outlier may or may not affect measures of central tendency, such as the mean, median, and mode.

It depends on the specific data set and the impact of the outlier on these measures. It is not always the highest or lowest value in a data set, as it can be any data point that deviates significantly from the rest.

Answer:

Mr. haigwood is not right.

Step-by-step explanation:

The veggie burgers comes in packages of 15 and buns come in packages of 6.

Mr. haigwood wants to serve veggie burgers on buns and wants to have no items left over.

Now, to find the least number of burgers and buns needed so nothing is left over, we will find the LCM of 15 and 6.

15 = 3 x 5

6 = 2 x 3

LCM = 2 x 3 x 5 = 30

As given, Mr. haighwood says that he will have to buy at least 90 of each item 6 x 15 =90.

This is not right. He needs to buy at least 30 of each item so that nothing is left over.

The two consecutive even integers whose sum is 126 are 62 and 64.

Let's represent the first even integer as x. Since the next consecutive even integer would be the next even number, we can represent it as x + 2.

The problem states that the sum of these two consecutive even integers is 126. We can set up the equation:

x + (x + 2) = 126

Now, let's solve for x by simplifying and combining like terms:

2x + 2 = 126

Subtract 2 from both sides of the equation:

2x + 2 - 2 = 126 - 2

2x = 124

Divide both sides of the equation by 2 to isolate x:

(2x) / 2 = 124 / 2

x = 62

Now that we have found the value of x, we can find the second consecutive even integer:

x + 2 = 62 + 2 = 64

Therefore, the two consecutive even integers whose sum is 126 are 62 and 64.

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