Answer: The proof is done below.
Step-by-step explanation: We are given to prove that the following statement is true :
"For every natural number n, [tex]n^5+4n[/tex] is a multiple of 5."
We will prove the above statement by MATHEMATICAL INDUCTION.
Let n = 1. Then, we get
[tex]n^5+4n=1^5+4\times5=5,[/tex] a multiple of 5.
Let n = 2. Then, we get
[tex]n^5+4n=2^5+4\times2=40,[/tex] a multiple of 5.
Let the statement be true for n = m, where m is a natural number.
So,
[tex]m^5+4m=5k,[/tex] for any natural number k.
Then,
[tex](m+1)^5+4(m+1)\\\\=m^5+5m^4+10m^3+10m^2+5m+1+4m+4\\\\=(m^5+4m)+5m^4+10m^3+10m^2+5m+5\\\\=5k+5(m^4+2m^3+2m^2+m+1)\\\\=5(k+m^4+2m^3+2m^2+m+1),[/tex] which is a multiple of 5.
Therefore, if the statement is true for n = m, then it is true for n = m+1.
That is, the statement is true for all natural numbers n.
Hence proved.
Susan buys the item listed below at a grocery store. 2 packages of chicken priced at $12.36 per package. 1/2 pound of broccoli priced at $1.98 per pound. 1gallon of milk priced at $3.49 per gallon. There is no sales tax on the food she buys. Susan pays for the items and recevies $0.80 in change. What amount of money does Susan use to pay for the items?
Answer:
Susan payed $30 for her purchase
Step-by-step explanation:
Chicken: $12.36 per package (x2) = $24.72
Broccoli: $1.98 per pound (x1/2) = $0.99 +
Milk: $3.49 per gallon (x1) = $3.49
-and no added sales tax ____________
$29.20
If Susan got $0.80 in return, then she must have payed $30 to begin with.
Answer:
The amount of money that Susan use to pay for the items = $30
Step-by-step explanation:
2×(12.36)+0.5×(1.98)+(3.49)+(0.8) = 30.
:)
Graph the inverse of the function.
Answer:
The graph of the inverse function is the same that the graph of the original function
Step-by-step explanation:
step 1
Find the equation of the function in the graph
Let
f(x) ---> the function in the graph
we know that
Is a linear function
take the points (0,6) and (6,0)
Find the slope of the linear function
[tex]m=(0-6)/(6-0)\\m=-1[/tex]
Find the the equation of the linear function in slope intercept form
[tex]f(x)=mx+b[/tex]
we have
[tex]m=-1[/tex]
[tex]b=6[/tex] ---> the y-intercept is given
substitute
[tex]f(x)=-x+6[/tex]
step 2
Find the inverse of the function f(x)
Let
y=f(x)
[tex]y=-x+6[/tex]
Exchange the variables (x for y and y for x)
[tex]x=-y+6[/tex]
Isolate the variable y
[tex]y=-x+6[/tex]
Let
[tex]f^{-1}(x)=y[/tex]
[tex]f^{-1}(x)=-x+6[/tex]
[tex]f^{-1}(x)=f(x)[/tex]
In this problem the graph of the inverse function is the same that the graph of the original function
Graphing the inverse of a function is achieved by flipping the graph over the line y = x. In science, graphs of inversely proportional variables like P and V form a hyperbola, but these can be 'linearized' for clarity and accuracy. Often, a regression analysis is utilized to find the best fitting line within a set of data plots.
Explanation:To graph the inverse of a function, you observe the function as a set of points in a 2D space (on a graph) and flip each point over the line y = x. This results in a new function, which is the inverse. When it comes to more specific functions like pressure and volume relationships, this is shown when plotting the inverse of the pressure (P^-1) versus the volume (V), or the inverse of volume (V^-1) versus the pressure (P).
Scientists often linearize data when graphs have curved lines because they're difficult to read accurately at low or high values. If you plot P (pressure) versus V (volume), you will get a hyperbola. This kind of function can be 'linearized' to make it easier to understand and interpret.
Finally, in many cases, such as plotting data points of inflation rate versus unemployment rate, the resulting graph can be analysed using a statistical process called regression. This helps to find the best fitting line for the set of data plots, which can often not perfectly fit the line.
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In a random sample of 400 items where 84 were found to be defective, the null hypothesis that 20% of the items in the population are defective produced Upper Z Subscript STATequalsplus 0.50. Suppose someone is testing the null hypothesis Upper H 0: piequals0.20 against the two-tail alternative hypothesis Upper H 1: pinot equals0.20 and they choose the level of significance alphaequals0.10. What is their statistical decision?
Answer:
[tex]z=\frac{0.21 -0.2}{\sqrt{\frac{0.2(1-0.2)}{400}}}=0.5[/tex]
[tex]p_v =2*P(Z>0.5)=0.617[/tex]
So the p value obtained was a very high value and using the significance level given [tex]\alpha=0.1[/tex] we have [tex]p_v>\alpha[/tex] so we can conclude that we have enough evidence to FAIL to reject the null hypothesis, and we can said that at 10% of significance the true proportion of defectives it's not significant different from 0.2.
Step-by-step explanation:
1) Data given and notation
n=400 represent the random sample taken
X=84 represent the number of items defective
[tex]\hat p=\frac{84}{400}=0.21[/tex] estimated proportion of defectives
[tex]p_o=0.2[/tex] is the value that we want to test
[tex]\alpha=0.1[/tex] represent the significance level
Confidence=90% or 0.90
z would represent the statistic (variable of interest)
[tex]p_v[/tex] represent the p value (variable of interest)
2) Concepts and formulas to use
We need to conduct a hypothesis in order to test the claim that the true proportion is 0.2 or 20%:
Null hypothesis:[tex]p=0.2[/tex]
Alternative hypothesis:[tex]p \neq 0.2[/tex]
When we conduct a proportion test we need to use the z statisitc, and the is given by:
[tex]z=\frac{\hat p -p_o}{\sqrt{\frac{p_o (1-p_o)}{n}}}[/tex] (1)
The One-Sample Proportion Test is used to assess whether a population proportion [tex]\hat p[/tex] is significantly different from a hypothesized value [tex]p_o[/tex].
3) Calculate the statistic
Since we have all the info requires we can replace in formula (1) like this:
[tex]z=\frac{0.21 -0.2}{\sqrt{\frac{0.2(1-0.2)}{400}}}=0.5[/tex]
4) Statistical decision
It's important to refresh the p value method or p value approach . "This method is about determining "likely" or "unlikely" by determining the probability assuming the null hypothesis were true of observing a more extreme test statistic in the direction of the alternative hypothesis than the one observed". Or in other words is just a method to have an statistical decision to fail to reject or reject the null hypothesis.
The significance level provided [tex]\alpha=0.1[/tex]. The next step would be calculate the p value for this test.
Since is a bilateral test the p value would be:
[tex]p_v =2*P(Z>0.5)=0.617[/tex]
So the p value obtained was a very high value and using the significance level given [tex]\alpha=0.1[/tex] we have [tex]p_v>\alpha[/tex] so we can conclude that we have enough evidence to FAIL to reject the null hypothesis, and we can said that at 10% of significance the true proportion of defectives it's not significant different from 0.2.
Select all the correct systems of equations.
Which systems of equations have infinite solutions?
Answer: Comment: From the explanations below,
2x + y = 10
-6x = 3y + 7 had an infinite solution, while y = 14 -2x
6x + 3y = 42 has a fictitious solution, so also equation
2x + y = 17
-6x = 3y - 51.
Step-by-step explanation:
Answer:
(C) y = 14 - 2x
6x + 3y+ 42
(F) 2x + y = 17
-6x = 3y - 51
Step-by-step explanation:
Plato Correct answer. Got them right. Select the two boxes that have the equation written above.
Leiff goes online to buy a new video game. He finds a site that currently has a promotion of 15% off on all orders over $50. Leiff decides to buy his video game, with a price tag of $128, at this site because he knows that he will get the 15% discount when he checks out. Leiff pays 5.3% sales tax on the discounted price and pays a shipping fee of $4.75. What is the total of Leiff’s online purchase?
Answer:
$119.32
Step-by-step explanation:
Leiff decides to buy his video game, with a price tag of $128, at this site
he will get the 15% discount when he checks out.
100-15= 85%
Discounted price=85% of 128 is [tex]0.85 \cdot 128=108.8[/tex]
Leiff pays 5.3% sales tax on the discounted price
5.3% is 0.053
sales tax amount=0.053 times 108.8=5.7664
So we add the sales tax amount and shipping fee
[tex]108.8+5.7664+4.75=119.32[/tex]
So $119.32 is the total amount
The total of Leiff’s online purchase is $119.31.
To calculate the total of Leiff's online purchase, we need to first calculate the discount on the video game.
The discount is calculated by multiplying the original price of the video game by the discount rate.
Discount = $128 * 15%
= $19.20
The discounted price of the video game is the original price minus the discount.
Discounted price = $128 - $19.20
= $108.80
The sales tax is calculated by multiplying the discounted price of the video game by the sales tax rate.
Sales tax = $108.80 * 5.3%
= $5.76
The total cost of the video game, including the discount and sales tax, is:
Total cost = $108.80 + $5.76
= $114.56
The total cost of Leiff's online purchase is the cost of the video game plus the shipping fee.
Total cost = $114.56 + $4.75
= $119.31
Therefore, the answer is $119.31.
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Sally is interested in taking a job in a city which she's not familier with the cost of living. She is especially concerned about the cost of housing and is interested in the average cost of a three bedroom home. Which of the following averages will be most influenced by three bedroom homes owned by millionaires?
a.mode
b.median
c.mean
d.none of the above
Answer:
c.Mean
Step-by-step explanation:
We have been given that the Sally is interested in taking a job in a city in which she's not familiar with the cost of living. She is especially concerned about the cost of housing and is interested in the average cost of a three bedroom home.
We know that in a normal distribution all central tendencies (mean, mode, median) are equal.
When a very large or very small valued data point is added to data set, mean is mostly affected by that outlier.
We know that mode of a data set is the point that appears at-most in the data set, so outliers doesn't affect mode.
Median of a data set is less affected by outliers.
The price of the three bedroom homes owned by millionaires will be greater than prices of houses owned by people in the neighborhood.
Therefore, mean will be most influenced by three bedroom homes owned by millionaires.
involving a carnival fishpond. Assume that the pond contains 100 fish: 78 purple, 21 blue, and 1 silver. A contestant pays $0.65 to randomly catch one fish and receives $0.40 if the fish is purple, $0.80 if the fish is blue, and $13.00 if the fish is silver. How much (on average) does the carnival gain on each play?
Answer:
On average the carnival gain on each play
= 0.04 dollars
Step-by-step explanation:
Given that a pond contains 100 fish: 78 purple, 21 blue, and 1 silver.
Fish Purple Blue Silver total
Frequency 78 21 1 100
Prob 0.78 0.21 0.01 1
Revenue 0.4 0.8 13
game fee 0.65 0.65 0.65
Net revenue -0.25 0.15 12.35
Net Rev*Prob -0.195 0.0315 0.1235 -0.04
Thus we get per player expected net revenue is -0.04
This would be gain for Carnival
Hence On average the carnival gain on each play
= 0.04 dollars
Final answer:
To calculate the carnival's average gain per play, determine the expected payoff for each fish type, subtract the cost to play, and sum these amounts. The carnival gains an average of $0.61 per play.
Explanation:
The student's question involves calculating the average gain for a carnival on each play of a carnival fishpond game. To find this, we need to determine what the carnival earns on average based on the probabilities of catching each type of fish (purple, blue, or silver) and the payoff for each.
Let's calculate the expected profit (gain) per play for the carnival. The probability and payoff for each type of fish are:
Purple fish: Probability = 78/100, Payoff = $0.40
Blue fish: Probability = 21/100, Payoff = $0.80
Silver fish: Probability = 1/100, Payoff = $13.00
The expected payoffs for the carnival from catching each type of fish are:
Purple: 78/100 * $0.40
Blue: 21/100 * $0.80
Silver: 1/100 * $13.00
Subtract the contestant's cost ($0.65) from each expected payoff to find the expected gain. Then, sum these expected gains to find the overall average gain for the carnival.
The carnival's expected gain is:
Expected Gain per Play = (78/100 * $0.40) + (21/100 * $0.80) + (1/100 * $13.00) - $0.65
Calculating:
Expected Gain per Play = ($0.3120) + ($0.1680) + ($0.1300) - $0.65
Expected Gain per Play = $0.61
This calculation shows that on average, the carnival gains $0.61 for each play of the fishpond game.
Jakes truck can tow a max weight of 5,000 pounds. What is the max number of horses he can take in his trailer at one time without going over the max weight his truck can tow
Answer:
He can take 5 Horses at max in his trailer at one time without going over the max weight his truck can tow. (Assuming the average weight of one horse to be equal to 1000 pounds)
Step-by-step explanation:
The no. of horses that can be carried by the truck can be found by simply dividing the maximum weight, that the truck can tow by the weight of a horse.
Max. No of Horses = (Max weight truck can tow)/(Average weight of one horse)
The weight of a horse is not given in the question .Thus, we assume the average weight of one horse, to be equal to 1000 pounds, we get:
Max. No of Horses = 5000 pounds/ 1000 pounds
Max. No of Horses = 5
Thomas Malthus, a political economist, showed that the human population would outstrip available resources unless kept in check by other factors such as famine, war, and disease. How did Charles Darwin apply this principle to his theory of evolution by natural selection?A. Darwin used this as a contrast to plant and animal populations, which live in balance with their available resources.B. Darwin used this to illustrate that because food supply remains relatively the same, plant and animal populations show little variation in size.C. Darwin realized this also applied to plant and animal populations, and this struggle for existence resulted in an opportunity for natural selection to act on differences within populations.D. Darwin used this to illustrate that as food supplies increase, populations increase.
Answer:
C. Darwin realized this also applied to plant and animal populations, and this struggle for existence resulted in an opportunity for natural selection to act on differences within populations.
Step-by-step explanation:
Thomas Malthus in his Malthusian theory of population concluded that since population increases geometrically and resources only increase arithmetically, there will reach a point in time when the resources will be not be able to sufficiently cater for the population.
The Charles Darwin theory of Evolution is based on five key observations and conclusions drawn from them. These observations and inferences are summarized as:
Species are more fertile. They birth more offspring than can grow to adulthood. Populations remain fairly stable with miniscule fluctuations. Food resources are limited, but are relatively constant most of the time.Based off these observations, it is seen that there will be a struggle amongst the members of the specie for the limited resources.
In sexually reproducing species, generally no two individuals are identical. Variation is rampant.Much of this variation is heritable.From the last two observations, the species that survive then pass on their traits to their offspring and the cycle repeats itself with each subsequent generation being better evolved than the previous ones.
Thus, Darwin discovered that the Malthusian theory of population also applies to plant and animal populations where scarcity of resources gives room for natural selection to take place due to the variation within populations.
Really need help with this.
Answer:
B = 47°
Step-by-step explanation:
THe theorem to solve this is very simple. The angle created Angle B intercepts to arcs, one major, another minor.
The major arc is DE, 142 degrees.
The minor arc is AC, 48 degrees.
The two secants intersect outside the circle and creates a vertex angle, Angle B. The theorem tells us that the measure of that vertex angle would be ONE HALF of the difference of the two intercepted arcs. So, we have:
[tex]B=\frac{1}{2}(142-48)=47[/tex]
So, B = 47°
PLEASE HELP ASAP THANK UU
[I'm still thinking sorry]
I'm assuming 2x-12 is the angle measure of DAC in degrees.
Let p=AB=AD, q=AC
By the Law of Cosines,
22² = p² + q² - 2pq cos 48°
q² - 2pq cos 48° + p² - 22² = 0
We also require by the triangle inequality
CD+AD < AC
16 + p < q
Let's set them equal and see where we are.
q=p+16
(p+16)² - 2p(p+16) cos 48° + p² - 22² = 0
p≈12.2125,
q≈28.2125
16² = p² + q² - 2 pq cos DAC
16² = 12.2125² + 28.2125² - 2 (12.2125)(28.2125) cos DAC
cos DAC = (12.2125² + 28.2125² - 16²)/(2 (12.2125)(28.2125) ) = 1
That's a surprise, DAC maxes out at a right angle
90 = 2x - 12
102 = 2x
x = 51
Answer: 6 < x < 51
Jade took a math test with 20 questions is worth an equal number of points. The test is worth 100 points in total. Write an equation that can be used to calculate jade's score based on the number of questions she got right on the test.
Answer:
[tex]Jade's\,score=5*right\,answers[/tex]
Step-by-step explanation:
Because all the questions have the same point, we can find the weight (value) of each question dividing the total points by the total number of answers questions:
[tex]\frac{100}{20}= 5[/tex]
Now with the weight of each question the only thing we should to do is to multiply it by the number of the questions she got right:
[tex]Jade's\,score=5*right\,answers[/tex]
Let check if our equation works, if Jade got all the answers right, we expect she got a 100 score. Let verify on the equation
[tex]Jade's\,score=5*(20)=100[/tex], that's what we expected
If she got 10 right answers, we expect 50 score and if she got 0 right answers, we expect 0 score, let check again:
[tex]Jade's\,score=5*(10)=50[/tex]
[tex]Jade's\,score=5*(0)=0[/tex]
Again, we obtain the expected scores, so we can conclude our equation works.
To find Jade's score on the math test, calculate the points per question by dividing the total points (100) by the number of questions (20). Each question is worth 5 points. Jade's score is the number of questions she got right multiplied by 5 points.
Explanation:To calculate Jade's score on a math test with 20 questions that is worth a total of 100 points, we can start by finding out how many points each correct answer is worth. Since the total points are evenly distributed among the questions, we divide the total points by the number of questions.
Each question is worth 5 points (100 points total ÷ 20 questions).
Let x represent the number of questions Jade got right. The equation to calculate Jade's score is then:
Score = 5 × x
To find Jade's score, we simply multiply the number of questions she got right by 5. For example, if Jade answered 16 questions correctly, her score would be 80 points (5 points/question × 16 questions).
Help please!! Stuck on this question!! ∠ABC is adjacent to ∠CBD. If the m∠ABC=4x+23, m∠CBD=6x+7, and m∠ABD=130°, what is the measure of angle ABC?
Answer:
63 degrees
Step-by-step explanation:
add 4x + 23 and 6x + 7, then equal that to 130. When you find x, plug it into 4x+23 and get 63.
Graph the linear equation.
x = - 9
WILL GIVE BRAINLIEST
Mia has 50 feet of fencing to make a rectangular kennel for her dog. She decides to use a part of her house as one side of the kennel. She needs a minimum enclosed area of 300 square feet. Of the inequalities listed, which forms of the inequality represent this situation?
-2l2 + 50l − 300 ≥ 0
(l − 15)(l − 10) ≥ 0
l(50 − 2l) ≥ 300
(l − 15)(l − 10) ≤ 0
l(2l − 50) ≥ 300
-2l2 + 50l − 300 ≤ 0
Answer:
-2L² + 50L − 300 ≥ 0
Step-by-step explanation:
View Image
Perimeter is the sum of all the sides. She got 50 feet of fence work with. So our equation right now is:
y + y + x + x = 50
However, she used her house for one of the side, so we can remove one of the side. Our new equation is now:
y + y + x = 50
Solve for one of the side. I solved for x because it's easier to work with and substitute later. I got x = 50 - 2y.
Now I solve for area. Area of a rectangle is Length * Width.
A = LW
I used x and y for my sides so my area is this instead:
A = yx
Substitute in x.
A = y(50 - 2y)
A = 50y - 2y²
Area must be a minimum of 300ft², so
50y - 2y² ≥ 300
50y - 2y² - 300 ≥ 0
replace y with L because that's what they used in the answer choice
-2L² + 50L − 300 ≥ 0
Answer:
-2l^2+50l-300 ≥ 0
l(50 − 2l) ≥ 300
(l − 15)(l − 10) ≤ 0
Step-by-step explanation:
What is the proper time sequence of the following three political movements/parties, from earliest to latest?
Answer:
The proper time sequence of the three political parties/movements, from earliest to latest is as follow:
Greenback party, Populist Party, Progressive movement.Step-by-step explanation:
Greenback party is such an American political party with the ideology of against the monopoly. It was founded in 1874 and dissolved in 1889. They worked for the rights of the farmers and workers of industries. They ran three candidates for the presidential elections in their era of political life. Populist Party is such an American party that is also known as People's Party which was founded in 1892 and dissolved in 1908. They fought for anti-corruption and were supporter of state control of railways. The women played a very active role in this party.Progressive Moment is also known as Progressive Era that was ended in 1920. This era demanded the reforms in the political system and gave rise to the social activism. The issues like corruption, industrialization and many such issues came in limelight.Find the area of the largest isosceles triangle that can be inscribed in a circle of radius r
Answer:
(3/4)(√3)r²
Step-by-step explanation:
The largest such triangle is an equilateral triangle. It will have a side length of r√3. The area can be found a number of ways, one of which is to use the formula for the area of an equilateral triangle of side length s:
A = s²·(√3)/4
Using s=r√3, we get ...
A = (3/4)(√3)r²
There are 70 students in a school band. 40%are sixth graders,20% are seventh graders and the rest are eighth graders.How many sixth graders are there.
Answer:the number of sixth graders is 28
Step-by-step explanation:
Total number of students in the school band is 70. 40% are sixth graders. 20% are seventh graders and the rest are eighth graders. This means that the percentage of eighth graders is 100 - (40+20) = 100 - 60 = 40%
This means that the number of sixth graders would be 40% of the total number of students in the school band. It becomes
40/100 × 70 = 0.4×70 = 28
Amc "for each $x$" in [0,1], define f(x) = 2x for how many values of x in [0,1] if f 2005 (x) = 1/2?
Answer:
[tex]2^{2005}[/tex]
Step-by-step explanation:
We are given [tex]f^{[2005]}(x) = \frac {1}{2}[/tex].
Hence, [tex]f(f^{[2004]}(x))=\frac{1}{2}[/tex].
Assume [tex]y=f^{[2004]}(x)[/tex].
Hence, [tex]f(y)=\frac{1}{2}[/tex] or [tex]y=\frac{1}{4}[/tex] or [tex]y=\frac{3}{4}[/tex].
So we can conclude that [tex]f^{[2004]}(x)=\frac{1}{4}[/tex] or [tex]f^{[2004]}(x)=\frac{3}{4}[/tex].
So we can find [tex]f(f^{[2003]}(x))=\frac{1}{4}[/tex] orf(f^{[2003]}(x))=\frac{3}{4}.
Assume [tex]z=f^{[2003]}(x)[/tex].
Hence, [tex]f(z)=\frac{1}{8}[/tex] or f(z)=\frac{7}{8} or f(z)=\frac{5}{8} or f(z)=\frac{3}{8}.
Therefore, we double the number of possible solutions for each iteration.
Thus, the number of solutions is [tex]2^{2005}[/tex].
Virenas Scout troop is trying to raise at least $650 this spring. How many boxes of cookies must they sell at $4.50 per box in order to reach their goal?
Answer:
145
Step-by-step explanation:
To find the number of boxes to reach the goal, divide the goal amount by the box amount:
[tex]650 \div 4.50 \approx144.444444[/tex]
Since you can't sell .444444 of a box, you must sell 145 boxes.
Carly's family is moving out ,so she needs to pack the dishes .Dishes brake easily so she must wrap them up. She cuts a sheet of bubble wrap into two pieces .What is the fraction ?
1/2, or one half. since she cuts it into 2.
HELP!!!!
What’s the length of a segment that begins at the point (4,7) and ends at the point (13,19)?
A. 24
B. 15
C. 20
D. 18
Answer:
Step-by-step explanation:
You just need the distance formula here. It's very simple to follow:
[tex]d=\sqrt{(x_{2}-x_{1})^2+(y_{2}-y_{1})^2 }[/tex]
which, for us, looks like this:
[tex]d=\sqrt{(13-4)^2+(19-7)^2}[/tex] and
[tex]d=\sqrt{9^2+12^2}[/tex] and
[tex]d=\sqrt{81+144}[/tex] and
[tex]d=\sqrt{225}[/tex] so
d = 15
Rowan has $50 in a savings jar and is putting in $5 every week. Jonah has $10 in his own jar and is putting in $15 every week. Each of them plots his progress on a graph with time on the horizontal axis and amount in the jar on the vertical axis. Which statement about their graphs is true?
(1) Rowan's graph has a steeper slope than Jonah's.(2) Rowan's graph always lies above Jonah's.(3) Jonah's graph has a steeper slope than Rowan's.(4) Jonah's graph always lies above Rowan's.
Answer:
(3) Jonah's graph has a steeper slope than Rowan's
Step-by-step explanation:
First we are going to write the equations for the amount of money that each one save
y = a+bx
Where y: Amount of money in the jar
a: Initial saving
b: Money saved every week ( graph's slope )
x: Number of week
Then, for Rowan
y = 50 + 5x
and for Jonah
y = 10 + 15x
Initially Rowan's graph lies above Jonah's graph but this situation change with time.
It is always true that Jonah's graph has a steeper slope than Rowan's, because for Rowan's graph the slope is 5 and for Jonah's graph the slope is 15
Then the answer is:
(3) Jonah's graph has a steeper slope than Rowan's
3) Jonah's curve has a steeper slope than Rowan's is True, All others are false
Rowan savings already (Intercept of Curve) = $ 50 ; Rowan Additional savings per week Slope with time) = $ 5Rowan Savings Equation = 50 + 5t , where t is weekly time
Jonah savings already (Intercept of Curve) = $ 10 ; Jonah Additional savings per week (Slope with time) = $ 15Rowan Savings = 10 + 15t , where t is weekly time
Jonah's curve has higher (steeper) slope, denoting more change in dependent variable 'savings' with change in independent variable weekly time. t weeks Rowan savings Jonah savings1 50 + 5 (1) = 55 10 + 15 (1) = 25
2 50 + 5 (2) = 60 10 + 15 (2) = 40
3 50 + 5 (3) = 65 10 + 15 (3) = 55
4 50 + 5 (4) = 70 10 + 15 (4) = 70
5 50 + 5 (5) = 75 10 + 15 (5) = 85
At t weeks < 3 , Rowan savings > Jonah savings. At t weeks > 4, Jonah savings > Rowan savings. At t = 4 units, their savings are equal. So, none savings curve is above the other 'always'.
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A trough is 8 feet long and has perpendicular cross section in the shape of an isosceles triangle (point down) with base 1 foot and height 2 feet. The trough is being filled with water at a rate of 1 cubic foot every 5 minutes. How fast is the water level rising whenthe water is 1/2 foot deep?
Answer:
Dh/dt = 0.082 ft/min
Step-by-step explanation:
As a perpendicular cross section of the trough is in the shape of an isosceles triangle the trough has a circular cone shape wit base of 1 feet and height h = 2 feet.
The volume of a circular cone is:
V(c) = 1/3 * π*r²*h
Then differentiating on both sides of the equation we get:
DV(c)/dt = 1/3* π*r² * Dh/dt (1)
We know that DV(c) / dt is 1 ft³ / 5 min or 1/5 ft³/min
and we are were asked how fast is the water rising when the water is 1/2 foot deep. We need to know what is the value of r at that moment
By proportion we know
r/h ( at the top of the cone 0,5/ 2) is equal to r/0.5 when water is 1/2 foot deep
Then r/h = 0,5/2 = r/0.5
r = (0,5)*( 0.5) / 2 ⇒ r = 0,125 ft
Then in equation (1) we got
(1/5) / 1/3* π*r² = Dh/dt
Dh/dt = 1/ 5*0.01635
Dh/dt = 0.082 ft/min
If stewart and patrick can finish a science project together in 20 minutes, and Patrick works four times as quickly as Stewart, how long would it take Patrick to complete the project alone?
Answer:
It would take 25 minutes for Patrick to complete the project alone.
Step-by-step explanation:
They did the project in 20 minutes, that is, 100% of the project, so:
[tex]x + y = 1[/tex]
In which x is the percentage that Patrick worked and y is the percentage that Stewart worked.
Patrick works four times as quickly as Stewart, so x = 4y.
So
[tex]x + y = 1[/tex]
[tex]4y + y = 1[/tex]
[tex]5y = 1[/tex]
[tex]y = 0.2[/tex]
-----------
[tex]x = 4y = 4*0.2 = 0.8[/tex]
Patrick did 80% of the project in 20 minutes. We can solve this problem by a simple rule of three, in which the time it would take for him to complete the project alone is 100%. So
20 minutes - 0.8
x minutes - 1
[tex]0.8x = 20[/tex]
[tex]x = 25[/tex]
It would take 25 minutes for Patrick to complete the project alone.
Patrick, who works four times as quickly as Stewart, would take 25 minutes to complete the project alone.
Explanation:This question is about rates and can be solved using algebra. Let's denote the rate at which Stewart can do the work as S and the rate at which Patrick does the work as P. Since Patrick works four times as quickly as Stewart, P=4S. The rate at which they work together is S+P. According to the question, together they can complete the job in 20 minutes, so their combined rate is 1 job per 20 minutes or 1/20. Therefore, S + P = 1/20.
Substitute P=4S into the equation, we get S + 4S = 1/20, which simplifies to 5S = 1/20. Solve this equation, we find that S = 1/100. So Stewart alone would finish the job in 100 minutes. Since Patrick is four times faster, Patrick alone would complete it in 100/4 = 25 minutes.
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In the xy-coordinate plane, line l is perpendicular to the y-axis and passes through the point (5, -3).Which of the following is an equation of line l?A. x = 0B. x = 5C. y = −3D. y + 3 = x + 5E. y − 3 = x + 5
Answer:
C. y = -3
Step-by-step explanation:
Line L is perpendicular to the y-axis, so line L is just a straight horizontally line going from left to right.
This mean that the x-coordinate they gave us is irrelevant since our flat line is going to pass through all possible x-values. The only thing we need to focus on the the y-value.
So we know that the line passes through (__, -3)
the equation y = -3 gives us a horizontal line that passes through (__, -3).
Therefore answer is C.
Answer A and B are wrong because they gave us vertical lines, we want horizontal lines. D and E are wrong because those are diagonal lines, we want flat horizontal lines.
Which system of equations is represented by the matrix below?
Answer:
C
Step-by-step explanation:
The elements of the matrix need to match the coefficients in the equations.
Answer:
c.
Step-by-step explanation:
h
Find the probability of rolling a sum less than 6 or a sum greater than 8 when a pair of dice is rolled?
Answer:
[tex]\frac{5}{9}\approx0.556[/tex]
Step-by-step explanation:
A pair of dice is rolled so the outcome space will be.
[tex]S= \{(1,1),(1,2),(1,3),(1,4),(1,5),(1,6)\\(2,1),(2,2),(2,3),(2,4),(2,5),(2,6)\\(3,1),(3,2),(3,3),(3,4),(3,5),(3,6)\\(4,1),(4,2),(4,3),(4,4),(4,5),(4,6)\\(5,1),(5,2),(5,3),(5,4),(5,5),(5,6)\\(6,1),(6,2),(6,3),(6,4),(6,5),(6,6)\}[/tex]
Total number of elements [tex]=36[/tex]
Possible outcomes in which sum is less than [tex]6[/tex] or greater than [tex]8[/tex]
[tex]S_{1} = \{(1,1),(1,2),(1,3),(1,4),(2,1),(2,2),(2,3),(3,1),(3,2),(3,6),\\(4,1),(4,5),(4,6),(5,4),(5,5),(5,6),(6,3),(6,4),(6,5),(6,6)\}[/tex]
Number of element in this space [tex]=20[/tex]
P(sum is less than [tex]6[/tex] or greater than [tex]8[/tex])
[tex]=\frac{Favourable\ outcomes}{total\ outcomes} \\=\frac{20}{36}\\ =\frac{5}{9}[/tex]
What is the unit rate for each size to the nearest cent? If the cost is less than a dollar, put a zero to the left of the decimal point.
Answer:
Size C can is the best buy.
Step-by-step explanation:
The given question is incomplete; here is the complete question.
One brand of canned salmon is sold in four different sizes.
Size A The 7 1/5 -ounce can costs $3.49.
Size B The 16 1/2 -ounce can costs $6.49.
Size C The 24 3/4 -ounce can costs $8.49.
Size D The 30 2/3 -ounce can costs $10.99. What is the unit rate for each size to the nearest cent? If the cost is less than a dollar, put a zero to the left of the decimal point.
Size Unit rate
A (Blank)
B (Blank)
C (Blank)
D (Blank)
What size is best to buy? explain how you know.
For Size A - [tex]7\frac{1}{5}[/tex] ounce or [tex]\frac{36}{5}[/tex] ounce can costs $3.49
Therefore, per ounce cost = [tex]\frac{\text{Total cost}}{\text{Size of can}}[/tex]
= [tex]\frac{3.49}{\frac{36}{5}}[/tex]
= [tex]\frac{3.49\times 5}{36}[/tex]
= $0.48
For Size B - [tex]16\frac{1}{2}[/tex] or [tex]\frac{33}{2}[/tex] ounce can costs $6.49
Per ounce cost = [tex]\frac{6.49}{\frac{33}{2}}[/tex]
= [tex]\frac{6.49\times 2}{33}[/tex]
= 0.39
For size C - [tex]24\frac{3}{4}[/tex] ounce or [tex]\frac{99}{4}[/tex] ounce can costs $8.49
Per ounce cost = [tex]\frac{8.49}{\frac{99}{4}}[/tex]
= [tex]\frac{8.49\times 4}{99}[/tex]
= $0.34
For size D - [tex]30\frac{2}{3}[/tex] or [tex]\frac{92}{3}[/tex] ounce can for $10.99
Per ounce cost = [tex]\frac{10.99}{\frac{92}{3} }[/tex]
= [tex]\frac{10.99\times 3}{92}[/tex]
= $0.36
For size C, per ounce cost of the can is the least. Therefore, size C can is the best buy.
For a certain experiment, the available experimental units are eight rats, of which four are female (F1, F2, F3, F4) and four are male (M1, M2, M3, M4). There are to be four treatment groups, A, B, C, and D. If a randomized block design is used, with the experimental units blocked by gender, which of the following assignments of treatments is impossible?
a. A (F1, M1), B (F2, M2), C (F3, M3), D (F4, M4)
b. A (F1, M2), B (F2, M3), C (F3, M4), D (F4, M1)
c. A (F1, M1), B (F3, F2), C (F4, M1), D (M3, M4)
d. A (F4, M1), B (F2, M3), C (F3, M2), D (F1, M4)
e. A (F4, M1), B (F1, M4), C (F3, M2), D (F2, M3)
Answer:
c
Step-by-step explanation:
In the experimental design we are choosing a random rats from both sets either male and female.
each set contains 2 elements (A,B), where A is a Female i.e F1, F2,F3,F4
and B is a male i.e M1,M2,M3,M4.
none of the sets can have 2 male or 2 female.
Only option 'C' has sets which contains B (F3, F2) and D (M3, M4) which is impossible.
Hence c is the answer.
The assignment of treatments that is impossible is given as
c.) A (F1, M1), B (F3, F2), C (F4, M1), D (M3, M4)
Which of the following assignments of treatments is impossible?Treatment, the way by which someone acts towards someone else.
Generally, from the parameters, we see that
A is a Female i.e F1, F2,F3,F4
B is a male i.e M1,M2,M3,M4.
In conclusion, the sets can't have 2 male or 2 female.
Therefore, we have
c.) A (F1, M1), B (F3, F2), C (F4, M1), D (M3, M4)
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