Find the equation of a line parallel to y - 5x = 10 that passes through the point (3, 10). (answer in slope-intercept form)

Answer:  The required probability of getting two green marbles is 49.45%.

Step-by-step explanation:  Given that a bag contains 10 green marbles and 4 yellow marbles. Two marbles are chosen at random, one at a time and without replacement.

We are to find the probability of getting two green marbles.

Let S denote the sample space for the experiment of choosing a marble from the bag and A denote the event of getting a green marble.

The, n(S) = 10 + 4 = 14   and   n(A) = 10.

So, the probability of event A will be

[tex]P(A)=\dfrac{n(A)}{n(S)}=\dfrac{10}{14}=\dfrac{5}{7}.[/tex]

After getting one green marble and not replacing, let S' denote the sample space for the experiment of choosing a marble from the bag

and

let B denote the event of getting another green marble.

Then, n(S') = 14 - 1 = 13    and    n(B) = 10 - 1 = 9.

Then, the probability of getting two green marbles is given by

[tex]P\\\\=P(A)\times P(B)\\\\=\dfrac{5}{7}\times\dfrac{n(B)}{n(S')}\\\\\\=\dfrac{5}{7}\times\dfrac{9}{13}\\\\\\=\dfrac{45}{91}\times100\%\\\\=49.45\%.[/tex]

Thus, the required probability of getting two marbles is 49.45%.

The area of the triangle is 6 square units.

To find the area of a triangle with vertices at (-2, 1), (2, 1), and (3, 4), we can use the formula for the area of a triangle: Area = 1/2 × base × height.

First, we need to find the base and height of the triangle. The base is the distance between the points (-2, 1) and (2, 1), which is 4 units. The height is the distance between the point (3, 4) and the line formed by the base, which is the vertical distance from (3, 4) to the line y=1, which is 3 units.

Plugging these values into the formula, we get Area = 1/2 × 4 ×3 = 6 square units.

Answer:

I hope this helps

Step-by-step explanation:

from x15 to x 25 is 4 - -16 = -20 degree change

25 -15 = 10000 feet

-20/10 = -2 degrees every 1000 feet

To solve for "p" in the equation "t = d + pm," isolate "p" by subtracting "d" from both sides: "t - d = pm." Then, divide both sides by "m" to find "p": "p = (t - d) / m." This formula allows you to calculate "p" based on given values of "t," "d," and "m."

To solve for "p" in the equation "t = d + pm," you need to isolate "p" on one side of the equation. Here's how you do it step by step:

Start with the Equation:

The equation is t = d + pm, where "t" represents a value, "d" represents another value, "p" is the variable we want to solve for, and "m" is yet another value.

Isolate the "pm" Term:

To get "pm" by itself, we need to eliminate the "d" term on the right side. We can do this by subtracting "d" from both sides of the equation:

t - d = pm

Solve for "p":

Now that "pm" is isolated on the right side, we can solve for "p" by dividing both sides by "m":

p = (t - d) / m

So, the solution for "p" in terms of "t," "d," and "m" is given by the formula p = (t - d) / m. This formula tells you how to calculate the value of "p" based on the values of "t," "d," and "m."

In practical terms, this equation might be used in various scenarios. For example, if "t" represents total distance, "d" represents a fixed distance, and "m" represents a constant speed, then "p" would represent the time it takes to cover the remaining distance to reach "t." This formula can be quite useful in solving real-world problems involving time, distance, and speed.

For more such question on equation

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The probability of heads on the fifth trial is still 0.5, just like any other coin flip.

The probability of heads on the fifth trial is still 0.5, just like any other coin flip. The outcome of each coin flip is independent of the previous flips, so each trial has the same probability of resulting in heads or tails.

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Let's suppose the breadth of the rectangle be x cm 

The length of the rectangle = x + 3 cm

It is assumed that the length and breadth of the rectangle is amplified by 2.

Now, the breadth of the rectangle = x + 2

The length of the rectangle = x + 3 + 2 = x + 5

It is also assumed that the area of the rectangle is 70 sq. cm

Hence, the area of the rectangle = length x breadth = (x + 2)(x + 5) = 70

= x2 + 5x + 2x + 10 = 70

= x2 + 7x = 70 - 10

=  x2 + 7x = 60

= x2 + 7x - 60 = 0

= x2 + 12x - 5x - 60 = 0

=  x( x + 12) -5(x + 12) = 0

= ( x + 12) (x - 5) = 0

=x + 12 = 10               or              =x - 5 = 0

= x = 10 - 12 = -2               = x = 5

The breadth of a rectangle is never negative, so the value of x is 5 cm

Therefore, the breadth of the rectangle = 5 cm

The length of the rectangle = 5 + 3 = 8 cm

Answer:

- m∠ABC = m∠ACB = 25° (as triangle ABC is isosceles).

- m∠BAC = 130°.

- m∠BDC = m∠DCB = 30° (as triangle DBC is isosceles).

Explanation:

We can solve this problem by using the properties of isosceles triangles and the fact that the sum of angles in a triangle is 180 degrees.

1. Since triangle DBC is isosceles, m∠DBC = m∠DCB.

Therefore, m∠DCB = 30°.

2. In triangle ABC, since it's isosceles, m∠ABC = m∠ACB.

3. We know that m∠ABD = 155°. Since triangle ABD is a triangle, the sum of its angles is 180 degrees. So, m∠ABD + m∠BAD + m∠ADB = 180°. Therefore, m∠BAD + m∠ADB = 180° - 155° = 25°.

4. Since triangle ABC is isosceles, m∠ABC = m∠ACB = 25°.

5. In triangle ABC, the sum of its angles is 180 degrees. So, m∠ABC + m∠BAC + m∠ACB = 180°. Substituting the known values, we get 25° + m∠BAC + 25° = 180°. Solving for m∠BAC,

we find m∠BAC = 180° - 25° - 25° = 130°.

Answer:

slope = -3

Step-by-step explanation:

To find the slope of the graphed line, we can use the slope formula:

[tex]\boxed{\begin{array}{l}\underline{\textsf{Slope formula}}\\\\m=\dfrac{y_2-y_1}{x_2-x_1}\\\\\textsf{where:}\\\phantom{w}\bullet\;\;m\; \textsf{is the slope.}\\\phantom{w}\bullet\;\;(x_1,y_1)\;\textsf{and}\;(x_2,y_2)\;\textsf{are two points on the line.}\end{array}}[/tex]

First, identify two points on the line:

Substitute the coordinates into the slope formula:

[tex]m=\dfrac{0-3}{1-0}=\dfrac{-3}{1}=-3[/tex]

Therefore, the slope of the graphed line is:

[tex]\Large\boxed{\boxed{\textsf{slope}=-3}}[/tex]