Change fraction to decimal: 4/7 and round to the nearest thousandth?

Answers

Answer 1

To solve this problem, all we have to remember is that fractions also mean division. Therefore this means that:

4 / 7 = 4 divided by 7

We can use either a calculator to solve for this or do the long division method of division (your choice). Now to solve this simply, I used the calculator and got the answer:

4 / 7 = 0.571428571

However, the problem asked us to round this to the nearest thousandth. We know that the decimal places are:

0.(tenths)(hundredths)(thousandths)

So we are to round this into 3 decimal numbers which gives us:

4 / 7 = 0.571

Related Questions

Jean has 5 different colors of markers: red, blue, green, orange, and purple. Two colors are used to make a sign. How many different combinations are possible? List them.

Answers

We need to find the number of possible combinations of r objects from a set of n objects.
Jean has 5 different colors which means that n=5 and 2 colors are used to make a sign, which means r=2.
The number of combinations can be calculated with the formula:
C=n!/((n-r)!r!)
C=5!/(5-2)!*2!
C=5*4*3!/3!*2*1
C=20/2=10
The possible combinations are:
1.red blue
2.red green
3.red orange
4.red purple
5. blue green
6. blue orange
7. blue purple
8. green orange
9. green purple
10. orange purple

Solve the system of equations: 2x + 9y = 0 and 3x + 5y = 17.

Answers

2x + 9y = 0 (1st)
3x + 5y = 17 (2nd)

multiply (st) by 3 and (2nd) by 2

6x + 27y = 0 (1st)
6x + 10y = 34 (2nd)
----------------------------subtract
17y = -34
y = -2

2x + 9y = 0
2x +9(-2) = 0
2x = 18
x = 9

answer
(9, -2)

Use complete sentences to describe the range of the sine function.

Answers

The Range of a function is the set of all values that that function can take.

Given the sine function f(x)=sinx,

This function is the function which calculates the sine of the values of x.

According to the definition of the sine of an angle x in the unit circle,

[tex]-1 \leq sinx \leq 1[/tex],

so the sine of an angle is always larger or equal to -1, and smaller or equal to 1.

This means that the values that the sine function takes are any values between -1 and 1, inclusive.

This determines the Range of the sine function.

So the Range of the sine function is [-1, 1]

Two 6-sided dice are rolled. what is the probability the sum of the two numbers on the die will be 4?

Answers

1+3=4. 2+2=4. 3+1=4.
3/6 or 1/2 if only addition
5-1=4. 6-2=4.
2/6 or 1/3 if only subtraction
if both 5/6

Answer:

[tex]\frac{1}{12}[/tex].

Step-by-step explanation:

Given : Two 6-sided dice are rolled.

To find : what is the probability the sum of the two numbers on the die will be 4.

Solution : We have given

Two 6-sided dice are rolled.

Dice have number { 1,2,3,4,5,6} { 1,2,3,4,5,6} .

[tex]Probability =\frac{outcome\ happn}{total\ outcome}[/tex].

sum of the two numbers on the die will be 4.

Case (1) : first dice rolled 3 and second dice rolled 1.

{3,1}

3 +1 = 4 .

Case (2) : first dice rolled 1 and second dice rolled 3 .

{1,3}

1 + 3 = 4 .

Case (3) : first dice rolled 2 and second dice rolled 2.

{2,2}

2 + 2 = 4.

Then there are 3 possible outcomes where the sum of the two dice is equal to 4.

The number of total possible outcomes = 36.

[tex]Probability =\frac{3}{36}[/tex].

[tex]Probability =\frac{1}{12}[/tex].

Probability of getting sum of two dice is [tex]\frac{1}{12}[/tex].

Therefore, [tex]\frac{1}{12}[/tex].

I need all the answers for question 2 and please explain each step to get the answer, thanks

Answers

a) check the picture below

b)

hmm where is that point A anyway? sounds like it's asking the same thing as in part a)

c)

well, where's M, the midpoint of BC, let's check.

[tex]\bf \textit{middle point of 2 points }\\ \quad \\ \begin{array}{lllll} &x_1&y_1&x_2&y_2\\ % (a,b) B&({{ 1}}\quad ,&{{ 4}})\quad % (c,d) C&({{ 9}}\quad ,&{{ 10}}) \end{array}\qquad % coordinates of midpoint \left(\cfrac{{{ x_2}} + {{ x_1}}}{2}\quad ,\quad \cfrac{{{ y_2}} + {{ y_1}}}{2} \right) \\\\\\ M=\left( \cfrac{9+1}{2}~,~\cfrac{10+4}{2} \right)\implies M=(5,7)[/tex]

now, the coordinator says that the midpoint of MC is at 6,8, let's check.

[tex]\bf \textit{middle point of 2 points }\\ \quad \\ \begin{array}{lllll} &x_1&y_1&x_2&y_2\\ % (a,b) M&({{ 5}}\quad ,&{{ 7}})\quad % (c,d) C&({{ 9}}\quad ,&{{ 10}}) \end{array}\qquad % coordinates of midpoint \left(\cfrac{{{ x_2}} + {{ x_1}}}{2}\quad ,\quad \cfrac{{{ y_2}} + {{ y_1}}}{2} \right) \\\\\\ N=\left( \cfrac{9+5}{2}~,~\cfrac{10+7}{2} \right)\implies N=\left(7~,~\frac{17}{2} \right)\implies N=\left(7~,~8\frac{1}{2} \right)[/tex]

how to write 314,207 in word form

Answers

three hundred fourteen thousand two hundred seven

Answer: three hundred fourteen thousand, two hundred seven

explanation for the comma after thousand: I’m used to putting one there because it says 314, not just 314 so I added one. Hope I helped !

A parallelogram has vertices E(−4, 6), F(1, 3), G(3, −4), and H(−2, −1). What are the coordinates of the midpoint of each diagonal?

(−3.5, 2.5)
(−0.5, −1)
(−0.5, 1)
(0.5, −1)

Answers

I would say that the answer is (-0.5,1).
Hope this helped!

A giraffe can run 40 meters per second what is its speed in miles per hour

Answers

bearing in mind that, there are

60 seconds in 1 minute,
60 minutes in 1 hr,
1000 meters in 1 km,
and 1.609 km in 1 mile

[tex]\bf \cfrac{40\underline{m}}{\underline{s}}\cdot \cfrac{60\underline{s}}{\underline{min}}\cdot \cfrac{60\underline{min}}{hr}\cdot \cfrac{\underline{km}}{1000\underline{m}}\cdot \cfrac{mi}{1.609\underline{km}}\implies \cfrac{40\cdot 60\cdot 60\cdot mi}{hr\cdot 1000\cdot 1.609} \\\\\\ \cfrac{144000mi}{1609hr}\approx 89.496581\frac{mi}{hr}[/tex]

what is the period of the sinusoid given by y=-4sin( [tex] \frac{2π}{3} [/tex] x) ?

Answers

[tex]\bf \qquad \qquad \qquad \qquad \textit{function transformations} \\ \quad \\ % function transformations for trigonometric functions \begin{array}{rllll} % left side templates f(x)=&{{ A}}sin({{ B}}x+{{ C}})+{{ D}} \\\\ f(x)=&{{ A}}cos({{ B}}x+{{ C}})+{{ D}}\\\\ f(x)=&{{ A}}tan({{ B}}x+{{ C}})+{{ D}} \end{array} \\\\ -------------------\\\\[/tex]

[tex]\bf \bullet \textit{ stretches or shrinks}\\ \left. \qquad \right. \textit{horizontally by amplitude } |{{ A}}|\\\\ \bullet \textit{ flips it upside-down if }{{ A}}\textit{ is negative}\\ \left. \qquad \right. \textit{reflection over the x-axis} \\\\ \bullet \textit{ flips it sideways if }{{ B}}\textit{ is negative}\\ \left. \qquad \right. \textit{reflection over the y-axis}[/tex]

[tex]\bf \bullet \textit{ horizontal shift by }\frac{{{ C}}}{{{ B}}}\\ \left. \qquad \right. if\ \frac{{{ C}}}{{{ B}}}\textit{ is negative, to the right}\\\\ \left. \qquad \right. if\ \frac{{{ C}}}{{{ B}}}\textit{ is positive, to the left}\\\\ [/tex]

[tex]\bf \bullet \textit{vertical shift by }{{ D}}\\ \left. \qquad \right. if\ {{ D}}\textit{ is negative, downwards}\\\\ \left. \qquad \right. if\ {{ D}}\textit{ is positive, upwards}\\\\ \bullet \textit{function period or frequency}\\ \left. \qquad \right. \frac{2\pi }{{{ B}}}\ for\ cos(\theta),\ sin(\theta),\ sec(\theta),\ csc(\theta)\\\\ \left. \qquad \right. \frac{\pi }{{{ B}}}\ for\ tan(\theta),\ cot(\theta)[/tex]

with that template in mind, let's see

[tex]\bf \begin{array}{llll} y=&-4sin(&\frac{2\pi }{3}x)\\ &A&B \end{array}\qquad period\implies \cfrac{2\pi }{B}\implies \cfrac{2\pi }{\frac{2\pi }{3}}\implies \cfrac{\frac{2\pi }{1}}{\frac{2\pi }{3}} \\\\\\ \cfrac{2\pi }{1}\cdot \cfrac{3}{2\pi }\implies 3[/tex]

Answer:

The answer is 3 for A P E X

Step-by-step explanation:

The sum of two rational numbers will always be

Answers

that would always be rational

this the picture for my question

Answers

3 is (x-3)(x-9) as when you use FOIL, you get -12x when adding -3x and -9x and also 27 when you multiply -3 times -9.

So, we know that the quadratic formula is x=-b+- the square root of b^2-4ac and all of this divided by 2a. You might be like "wow, where did all of these come from?" It is actually really easy. So, let's take your first equation: 2x^2-19x+24=0. So, let us look at the standard form for a quadratic formula: a^2+b+c=0. Now, If you look at the normal equation and the standard form for a quadratic, you will see that they are alike. Now, just match the letter with the number: a=2, b=-19, and c=24. Now that you know what each letter represents, you can plug everything into the equation x=-b+- the square root of b^2-4ac and all of this divided by 2a.

How could the relationship of the data be classified?

scatter plot with points loosely scattered going down to the right

A positive correlation
A causation
A negative correlation
No correlation

Answers

It would be C. A negative correlation. Think of it as a line. If a line goes to the right and is dipped downward just a little bit, it would have a negative slope.

Answer: A negative correlation

Step-by-step explanation:

If the points in the scatter plot scattered going down to the right, it shows that there are inverse relationship between the quantities.

With the increase of one quantity or variable there is decrease in the other quantity or variable.

Therefore, if in the scatter plot with points loosely scattered going down to the right , then the relationship of the data be classified as a negative correlation.

Josh has 40 minutes to complete a government exam. There are 15 multiple-choice questions worth 3 points each. There are also 5 short-answer questions worth 11 points each. It takes about 2 minutes for Josh to answer the multiple-choice questions m and about 8 minutes to complete the short-answer questions s. The system of inequalities that represents this problem is graphed below. Which ordered pair is not a vertex of the feasible region?

Answers

The feasible vertices of the system representing Josh's exam are (0,0), (12,5), and (15,1.25). The non-feasible vertices are (15,0), (0,5), and (20,0). Therefore, the ordered pair (15,0) is not a vertex of the feasible region.

1. System of Inequalities:

- Time constraint: [tex]$2m + 8s \leq 40$[/tex]

- Number of multiple-choice questions: [tex]$m \leq 15$[/tex]

- Number of short-answer questions: [tex]$s \leq 5$[/tex]

2. Feasible Vertices:

- (0,0), (12,5), (15,1.25)

3. Non-feasible Vertices:

- (15,0), (0,5), (20,0)

So, the ordered pair (15,0) is not a vertex of the feasible region.

85 is 20% of what number? Enter your answer in the box.

Answers

20% = 20/100 = 0.2

85/0.2 = 425 ← answer

What is the equation of the line that passes through the point of intersection of the lines y = 2x − 5 and y = −x + 1, and is also parallel to the line y=1/2x+4?

Answers

find inersection first

both equal y so
2x-5=-x+1
3x-5=1
3x=6
x=2
sub back

y=2x-5
y=2(2)-5
y=4-5
y=-1
intersection is (2,-1)

paralell to a line is having same slope
y=mx+b, m is slope
given
y=1/2x+4
slope is 1/2
so
y=1/2x+b
find b
given the point (2,-1) that it must pass through
(x,y) so x=2 and y=-1
-1=1/2(2)+b
-1=1+b
-2=b

the equation is y=1/2x-2

y = 2x - 5
y = -x + 1

2x - 5 = -x + 1
2x + x = 1 + 5
3x = 6
x = 6/3
x = 2

y = -x + 1
y = -2 + 1
y = -1

solution is (2,-1)...point of intersection between the 2 lines given.

y = 1/2x + 4....slope here is 1/2. A parallel line will have the same slope.

y = mx + b
slope(m) = 1/2
(2,-1)...x = 2 and y = -1
sub and find b
-1 = 1/2(2) + b
-1 = 1 + b
-1 -1 = b
-2 = b

so ur parallel equation is : y = 1/2x - 2 <==

Are rational numbers always, sometimes or never natural numbers?

Answers

Rational numbers are sometimes natural numbers. For example, the number 1 is both a rational and natural number. Remember that natural numbers are 1, 2, 3, 4.. etc. Rational numbers are any number that can be expressed as a ratio of 2 integers. 1/1 is rational.

Most rational numbers, however, are not natural. For example, 3/4, 89/88, and so on.

Answer:

SOMETIMES

Step-by-step explanation:

A video game club charges a fixed annual membership fee of $18 and $3 per video game rented. Let f(n) represent the total annual cost of renting n video games. Which of the following functions best represents the relationship between f(n) and n if the membership was increased by $20 the next year?

Answers

Since there is a flat membership fee of $18, the y intercept is 18. And since there is a $3 fee per number of video games rented, n, the slope or rate of change of the linear equation is 3. The slope-intercept form of a line is:

f(x)=mx+b, where m=slope and b=y-intercept so in terms of n, games rented, the cost, f(n) is:

f(n)=3n+18

Answer:

The correct answer is f(n)=3n+38

Step-by-step explanation:

Put in y=mx+b form, so y= f(n), $3 is fee per video game rented and n is the number of video games rented, b is ($18 fixed fee for this year +$20 fee for next year). So, f(n)=3n+38.

What is the factorization of the polynomial below?

x²+12x+27

A. (x+3)(x+9)
B. (x+9)(2x+9)
C. (12x+1)(x+2)
D. (3x+3)(x+9)

Answers

The answer is A.

(x + 3)(x + 9) = x^2 + 3x + 9x + 27, which simplifies to x^2 + 12x + 27

Which linear inequality is represented by the graph? y ≥ 1/3x – 4 y ≤ 1/3x – 4 y ≤ 1/3x + 4 y ≥ 1/3x + 4

Answers

solid line...means equal sign is present.....shading below the line means less then....u have a y int at (0,-4)...u have a positive slope of 1/3

thats gonna be 2nd answer choice

Answer:

[tex]y\leq \frac{1}{3}x-4[/tex]

Step-by-step explanation:

we know that

The solution of the inequality is the shaded area below the solid line

The slope of the line is positive

The y-intercept of the solid line is equal to [tex]-4[/tex]

therefore

The inequality must be

[tex]y\leq \frac{1}{3}x-4[/tex]

Determine whether the sequence is arithmetic or geometric. Sequence 1: –10, 20, – 40, 80, ... Sequence 2: 15, – 5, – 25, – 45, ... Which of the following statements are true regarding Sequence 1 and Sequence 2.

Answers

Sequence one is geometric since you are multiplying each number by a certain value (-2). Sequaence 2 is arithmetic since you are ADDING each number by -20

Answer:

Sequence 1 is arithmetic and Sequence 2 is geometric.

(4.05 LC)

The graph shows y as a function of x:

Graph of x against y shows 4 segments. Segment A is a horizontal line parallel to the x-axis. Segment B is a slanting straight line going up. Segment C is a horizontal line parallel to the x-axis. Segment D is a slanting straight line going down that touches the x-axis.

In which segment is the function increasing?
A
B
C
D

Answers

I think the answer will be B

Answer: I think the answer is A.

Step-by-step explanation:

I think this because its the only time that It could stay the same.

Use the given graph to determine the limit, if it exists. A

Find limit as x approaches three from the left of f of x..

Answers

check the picture below.

A line passes through (2, –1) and (8, 4).Write an equation for the line in point-slope form.
Rewrite the equation in standard form using integers.

Answers

Hello : let A(2,-1) B(8,4)
the slope is : (YB - YA)/(XB -XA)
(4+1)/(8-2) = 5/6

an equation for the line in point-slope form is : y-(-1) =( 5/6)(x-2)
y+1 = (5/6)x -5/3
6y+6 = 5x -10
the equation in standard form is : 5x-6y = 16

Answer: Equation of line in point slope form,

[tex]y + 1 = 5 ( x - 2 )[/tex]

And, Equation of line in standard form,

[tex]5 x - 6 y = 16[/tex]

Step-by-step explanation:

Since, If a line passes through two points [tex](x_1,y_1)[/tex] and [tex](x_2,y_2)[/tex] ,

Then the equation of line,

[tex]y-y_1=\frac{y_2-y_1}{x_2-x_1} (x-x_1)[/tex]

Here [tex]x_1 = 2[/tex], [tex]y_1=-1[/tex], [tex]x_2=8[/tex] and [tex]y_2=4[/tex]

Thus, the equation of the given line,

[tex]y-(-1)=\frac{4-(-1)}{8-2} (x-2)[/tex]

⇒ [tex]y+1=\frac{4+1}{8-2} (x-2)[/tex]

⇒ [tex]y+1=\frac{5}{6} (x-2)[/tex] -----(1)

⇒ [tex]6(y+1)= 5(x-2)[/tex]

⇒ 6 y + 6 = 5 x - 10

⇒ 6 = 5x - 6y - 10 ( By subtracting by on both sides )

⇒ 6 + 10 = 5x - 6y ( By adding 10 on both sides )

⇒ 16 = 5x - 6y

⇒ 5 x - 6 y = 16 ------(2)

Since, in slope for of a line is, [tex]y-y_1= m (x-x_1)[/tex]

Thus, equation (1) shows the in slope form of the line.

And, standard form of the line is ax + by = c where a, b and c are the integers.

Thus, equation (2) shows the standard form of the given line.

Assume that the flask shown in the diagram can be modeled as a combination of a sphere and a cylinder. Based on this assumption, the volume of the flask is ____ cubic inches. If both the sphere and the cylinder are dilated by a scale factor of 2, the resulting volume would be _____ times the original volume.

options for the first blank are: 20.22, 35.08, 50.07, or 100.11

options for the second blank are: 2, 4, 6 or 8

Answers

The total volume of the flask will be 50.06 [tex]\rm inches ^3[/tex] and if both the sphere and the cylinder are dilated by a scale factor of 2, the resulting volume would be '8' times the original volume.

Given :

Flask can be modeled as a combination of a sphere and a cylinder.

The volume of Sphere is given by the:

[tex]V_s = \dfrac{4}{3}\pi r^3[/tex]

Given - diameter of sphere = 4.5 inches. Therefore, radius is 2.25 inches.

Now, the volume of sphere of radius 2.25 inches will be:

[tex]V_s = \dfrac{4}{3}\times \pi\times (2.25)^3[/tex]

[tex]\rm V_s = 47.71\; inches^3[/tex]

The volume of Cylinder is given by the:

[tex]V_c = \pi r^2h[/tex]

Given - diameter of cylinder = 1 inches then radius is 0.5 inches and height is 3 inches.

Now, the volume of cylinder of radius 0.5 inches and height 3 inches will be:

[tex]V_c = \pi\times (0.5)^2 \times 3[/tex]

[tex]\rm V_c = 2.35\; inches^3[/tex]

Therefore the total volume of the flask will be = 47.71 + 2.35 = 50.06 [tex]\rm inches ^3[/tex].

Now, if both the sphere and the cylinder are dilated by a scale factor of 2 than:

Radius of sphere = [tex]2.25\times 2[/tex] = 4.5 inches

Radius of cylinder = [tex]0.5\times 2[/tex] = 1 inch

Height of cylinder = [tex]3\times 2[/tex] = 6 inches

Now, the volume of sphere when radius is 4.5 inches will be:

[tex]V_s' = \dfrac{4}{3}\times \pi \times (4.5)^3[/tex]

[tex]\rm V_s' = 381.70\; inches ^3[/tex]

And the volume of cylinder when radius is 1 inch and height is 6 inches will be:

[tex]V_c' = \pi \times (1)^2\times 6[/tex]

[tex]\rm V_c'=18.85\;inches^3[/tex]

Therefore the total volume of the flask after dilation by a scale factor of 2 will be = 381.70 + 18.85 = 400.55 [tex]\rm inches ^3[/tex].

Now, divide volume with dilation by theorginal volume of the flask.

[tex]\dfrac{400.55}{50.06}=8[/tex]

Therefore, if both the sphere and the cylinder are dilated by a scale factor of 2, the resulting volume would be '8' times the original volume.

For more information, refer the link given below:

https://brainly.com/question/15861918

Graph the functions and approximate an x-value in which the quadratic function exceeds the exponential function. y = 4x y = 7x2 + 4x - 2
x = -0.5
x = 0
x = 0.5
x = 2

Answers

I believe that it is 0.5

Answer:

Option 3th is correct

x = 0.5

Step-by-step explanation:

The given functions are:

Function 1: [tex]y = 4^x[/tex]

Function 2: [tex]y=7x^2+4x-2[/tex]

The values of function at x = -0.5, 0, 0.5 and 2 are as follow:

x values Function 1 Function 2

-0.53 0.5 -2.25

0 1 -2

0.53 2.086 2.0863

2 16 34

From the above table. It is clear that the quadratic function [tex]y=7x^2+4x-2[/tex] exceeds the exponential function [tex]y = 4^x[/tex] at x = 0.53

Therefore, the approximate x-value in which the quadratic function exceeds the exponential function at x = 0.5

What percentage is the fraction 2/4 equal to?

Answers

Is it equal to 50% because 2/4 is .5 and to make a fraction you move the decimal over two places to the right

It is equal to 50%.
When 2/4 is simplified, it becomes 1/2, which is equal to 0.5.

Can you square both sides of an inequality

Answers

Technically you can, if both sides of the inequality have no negative integers.

Squaring both sides of an inequality can be valid if you know both sides are non-negative, but it can introduce extraneous solutions. Therefore, it's important to check any solutions against the original inequality to ensure their validity, especially in cases involving negative numbers or functions with restricted domains.

When you're working with inequalities, you have to be careful when performing operations like squaring both sides. Unlike equalities, where multiplication or division by the same number on both sides does not change equality, with inequalities, the effect can be more complex due to the direction of the inequality sign and the possibility of dealing with negative numbers.

For instance, squaring both sides of an inequality is not always a valid operation because if one or both sides of the inequality are negative, squaring could lead to incorrect results. When you square a negative number, it becomes positive, which could potentially reverse the inequality's direction. However, if you know that both sides of the inequality are non-negative, then squaring both sides is permissible. This concept is similar to solving quadratic constraints without introducing square roots, using identities like |(1 + ix)²|² = ([1 + ix|²)².

To avoid introducing solutions that were not there originally (extraneous solutions), it is important to check the solutions obtained after squaring against the original inequality. An example where squaring both sides might be questioned is when solving trigonometric inequalities, where a common mistake is to square both sides without considering the domain of the original function.

system of equations with different slopes and different y-intercepts have one solution.

A. Always
B. Sometimes
C. Never
I think it is A but I am not sure and it is impossible for system of equations with different slopes and different y-intercepts to be parallel or infinite.

Answers

The answer is :
A. Always

Also
If two equations have different slopes but equivalent y-intercepts, they will have one solution and that will be the point where the y-intercept is. If two equations have different slopes and different y-intercepts, then there will be one solution where those two lines meet. If two equations have the same slope but different y-intercepts, the lines will be parallel, and there is no possible intersection point. And if two equations have equal slopes and equal y-intercepts, these lines will have an infinite amount of solutions, because if the equations are one the same line, every single point on that line is a solution to the system.

Always. The only time you have 0 solutions is when you have two parallel lines, meaning same slope. The only time you have more than 1 is when you have the SAME line, because every point is a answer. Therefore, when you have two completely different lines, then they MUST only have 1 solution always.

If this helped please rate, thank, and give brailnliets!

The lifetimes of lightbulbs of a particular type are normally distributed with a mean of 392 hours and a standard deviation of 9 hours. find the first quartile, q1.

Answers

The 1st quartile q1 is also called the 25th percentile (the bottom 25% of a data set). In this case, if we choose 100 light bulbs, then the 1st quartile will be the 25 bulbs with shortest useful life.

To solve this problem, we would have to use the z statistic. Using the standard distribution tables for z, we locate for the value of z at P = 0.25:

z = - 0.674

Then to calculate for the 1st quartile, we use the formula:

Q1 = x + z * s

where x is the mean, and s is the standard deviation, therefore:

Q1 = 392 + (- 0.674) (9)

Q1 = 385.934

Final answer:

To find the first quartile of a normal distribution, use the z-score corresponding to an area of 25%. For these lightbulbs with a mean of 392 hours and standard deviation of 9 hours, the first quartile is approximately 386 hours.

Explanation:

In statistics, the quartiles of a dataset divide the data into four equal parts. The first quartile, Q1, is the value below which 25% of the data fall. To determine Q1 for the lifetime of a certain type of lightbulb, we use the properties of the normal distribution.

First, realize that 25% of data falls below Q1, and hence using the z-table, we find that z=-0.675 corresponds to an area of 0.25. We then use the formula for a z-score in a normal distribution, z = (X - μ)/σ. Solving for X we find X = z*σ + μ.

Plugging in the known values we get Q1 = -0.675*9 + 392 = 386.025 hours. So, for these lightbulbs, 25% will have failed by around 386 hours.

Learn more about First Quartile here:

https://brainly.com/question/24329548

#SPJ11

Given the following triangle side lengths, identify the triangle as acute, right or obtuse. Show your work.
a. 3in, 4in, 5 in

b. 5in, 6in, 7in

c. 8in, 9in, 12in

Answers

Let "a", "b" and "с" be sides of the triangle ("с" is the longest side).
The triangle will be:

right if a² + b² = c²
аcute if    a² + b² > c²
obtuse if   a² + b² < c²

a.
a=3, b=4 and c=5

a² + b² = 3² + 4² = 9 + 16 = 25 and c² = 5² = 25

25 = 25 ⇒ right triangle.

b.
a=5, b=6 and c=7

a² + b² = 5² + 6² = 25 + 36 = 61   and c² = 7² = 49

61 > 49 ⇒ аcute triangle.

c.
a=8, b=9 and c=12

a² + b² = 8² + 9² = 64 + 81 = 145   and c² = 12² = 144

145 > 144 ⇒ аcute triangle.

From the information, A is a right angle, B is an acute triangle and C is an acute angle.

How to solve the triangle

It will be a right triangle if a² + b² = c². It will be аcute if a² + b² > c² and it'll be obtuse if a² + b² < c².

For the first one,

a² + b² = 3² + 4² = 9 + 16 = 25 and c² = 5² = 25

25 = 25

This is a right triangle.

For the second one,

a² + b² = 5² + 6²

= 25 + 36 = 61

c² = 7² = 49

61 > 49 = аcute triangle.

For the third one,

a² + b² = 8² + 9²

= 64 + 81 = 145

c² = 12² = 144

145 > 144 = аcute triangle.

Learn more about triangles on:

https://brainly.com/question/4521351

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