Answer:
Speed with which it strike the water = 36.66 m/s
Explanation:
Horizontal component of velocity = 18 m/s
We need to find vertical component of velocity.
Considering vertical motion of stone
Initial velocity, u = 0 m/s
Acceleration , a = 9.81 m/s²
Displacement, s = 52 m
We have equation of motion v² = u² + 2as
Substituting
v² = u² + 2as
v² = 0² + 2 x 9.81 x 52
v = 31.94 m/s
Vertical component of velocity = 31.94 m/s
[tex]\texttt{Total velocity = }\\\\\sqrt{\texttt{Horizontal component of velocity}^2+\texttt{Vertical component of velocity}^2}\\\\\texttt{Total velocity = }\sqrt{18^2+31.94^2}=36.66m/s[/tex]
Speed with which it strike the water = 36.66 m/s
If a person standing at the edge of a seaside cliff kicks a stone over the edge, the speed with which the stone strike the water is 36.65 m/s.
Given the following data:
Initial horizontal velocity = 18 m/s (since the stone was kicked over the edge).Vertical displacement = 52 metersInitial vertical velocity = 0 m/sWe know that acceleration due to gravity (a) is equal to 9.8 meter per seconds square.
First of all, we would determine the vertical component of the velocity by using the third equation of motion;
[tex]V^2 = U^2 + 2aS[/tex]
Where:
V is the final speed. U is the initial speed. a is the acceleration. S is the displacement.Substituting the given parameters into the formula, we have;
[tex]V^2 = 0^2 + 2(9.8)(52)\\\\V^2 = 0 + 1038.2\\\\V = \sqrt{1019.2}[/tex]
Vertical component of velocity = 31.92 m/s
To find the speed with which the stone strike the water, we would calculate the resultant speed by doing a vector addition of the horizontal component of the velocity and the vertical component of the velocity;
[tex]Speed = \sqrt{H^2 + V^2} \\\\Speed = \sqrt{18^2 + 31.92^2}\\\\Speed = \sqrt{324 + 1019.2}\\\\Speed = \sqrt{1343.2}[/tex]
Speed = 36.65 m/s
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Most subduction-derived magma never reaches the surface. however, what is formed if this type of magma reaches the surface of a continent?
A young boy was riding his bicycle down the street when he hit a parked car. what was the second collision?
The second collision in this scenario is likely to be when the boy's body hits some interior part of the car after he initially impacts with the car. This is because of the conservation of momentum which needs to go somewhere after the initial collision, often resulting in a further collision.
Explanation:In the scenario you explained, a young boy was riding his bicycle and hit a parked car. This is referred to as the first collision. The second collision in this context would be the boy's body hitting some interior part of the car (like the car door or windshield) after the initial impact with the car.
This is an application of the physics principle of conservation of momentum. Initially, the bike and the boy have some momentum, and after hitting the parked car, that momentum needs to go somewhere - which often results in a second collision. However, the exact nature of the second collision could depend on a few factors such as the speed of the bicycle and the angle at which the bicycle hit the car.
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What evidence suggests that Earth attracts or pulls on objects?
Traffic officials indicate, it takes longer to ______ when you drive fast.
Answer:
Stop
Explanation:
when we drive fast it will be take longer time to stop.
As car is moving fast the acceleration will be to decelerate we have to apply brake.
By applying brake the car decelerates very fast as deceleration is the change in velocity per unit time. change in velocity is very high so deceleration will be high.
when the brake is applied the distance travel by the high speed vehicle will be more than the vehicle moving at slow speed.
When you set something down on the ground what kind of work is your arm doing
When set something is set down on the ground, negative work is said to be done by the body.
What is Negative work?This is the type of work which is characterized by the force and displacement being in opposite direction.
This type of work occurs when the arm set down something on the ground which makes it the most appropriate choice.
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Determine the rate of a reaction that follows the rate law:rate = k[A]m[B]n, where:k = 1 × 10-2[A] = 2 M[B] = 3 Mm = 2n = 1
Final answer:
The rate of the reaction is calculated by substituting the given values into the rate law, resulting in a rate of 0.12 M/s, with the rate constant k having units of mol² L²/s for this reaction.
Explanation:
To calculate the rate of a reaction with the given rate law, we insert the provided values into the rate equation: rate = k[A]m[B]n. With the values k = 1 × 10-2, [A] = 2 M, [B] = 3 M, m = 2, and n = 1, the rate is calculated as follows:
rate = (1 × 10-2 M-1s-1)(2 M)2(3 M)1
rate = 1 × 10-2 M-1s-1 × 4 M2 × 3 M
rate = 0.12 M/s
The rate constant k has the units necessary to provide the rate in terms of mol/L/s, which for this second-order reaction in [A] and first-order in [B] (total order: 3), is mol-2 L2/s.
A glass is half-full of water, with a layer of vegetable oil (n 5 1.47) fl oating on top. a ray of light traveling downward through the oil is incident on the water at an angle of 71.48. determine the critical angle for the oil–water interface and decide whether the ray will penetrate into the water.
A steel cylinder with a moveable piston on top is filled with helium (He) gas. The force that the piston exerts on the gas is constant, but the volume inside the cylinder doubles, pushing the piston up.
Which of the following answers correctly states the cause for the change described in the scenario?
The temperature increased.
The density of the helium atoms decreased.
The pressure decreased.
The helium atoms increased in size.
A basketball player jumps straight upward. After 0.625 s, she is 0.411 m above the ground. What was her initial velocity? PLEASE HELP
use the formula
trianglex = vi * t+ 1/2g * t^2
Answer:
3.72!!!
Explanation:
For maximum visibility, backing a vehicle requires a driver to:
When backing a vehicle for maximum visibility, a driver should check all mirrors, look over their shoulder, and utilize a rear-view camera if available to maintain full awareness of their surroundings.
Explanation:For maximum visibility when backing a vehicle, a driver is required to regularly check all mirrors, turn their head to look over their shoulder, and use the vehicle's rear-view camera if one is available. Maintaining a full awareness of their surroundings is essential. For example, looking over the right shoulder will help spot any pedestrians, obstacles, or approaching vehicles from that direction. Similarly, the mirrors and rear-view camera enable a driver to monitor the areas behind and to the sides of the vehicle, ensuring a safe and smooth backing maneuver.
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For maximum visibility while backing a vehicle, the driver should use all mirrors, check blind spots, ensure rear visibility is unobstructed, and back slowly. It is also crucial that the vehicle is well-maintained with functioning lights and signals.
For maximum visibility when backing a vehicle, a driver needs to be highly alert and use all available visual aids. This includes checking all mirrors, turning to look over each shoulder for blind spots, and using the rear-view camera if the vehicle is equipped with one. It's important to have a clear view of the path behind the vehicle, which means ensuring that the rear windshield is free of obstructions like stickers, dirt, and snow. Furthermore, it's essential for the driver to move slowly and smoothly, allowing more time to react if an obstacle appears. A step-by-step approach includes:
Adjusting all mirrors for the widest field of vision.Checking for obstacles around the vehicle before getting in.Ensuring the rear windshield is clear.Turning to physically check blind spots.Backing slowly to maintain control and react to changes.It's also crucial that the vehicle is in good condition, as noted in 'KNOW YOUR HIGHWAYS and BE SURE TO HAVE YOUR CAR IN GOOD CONDITION', including functioning lights and reverse signals to alert nearby pedestrians and motorists. Being aware of the surrounding environment, such as obeying unknown speed limits as inferred from the scenario with the test car, increases safety while maneuvering.
What do astronomers mean by light pollution?
Final answer:
Light pollution is the excessive or misdirected artificial light that brightens the night sky, making it difficult to see celestial objects. It is a concern for astronomers, environmentalists, and those worried about global warming.
Explanation:
Light pollution refers to the excessive or misdirected artificial light that brightens the night sky, making it difficult to see celestial objects such as planets and stars. This phenomenon is of concern not just to astronomers, but also to environmentalists and those who are worried about global warming. It can disrupt the natural life cycle of animals and lead to unnecessary expenses and energy consumption. Light pollution can be measured and compared using citizen science projects like Globe at Night, and organizations like the International Dark-Sky Association work to address this issue.
What characteristics of the sun would make it a difficult place to explore or visit?
Telephone companies are replacing older, analog lines with digital lines because
A. wireless transmissions can be used only for short distances. B. computers can now be equipped with modems to translate transmissions. C. digital lines are less expensive. D. data is transmitted more quickly over digital lines.
A car slow down at -5.00 m/s2 until it comes to a stop after traveling 15.0 m. What was the initial speed of the car? (Unit=m/s)
Answer:
12.25 m/s
Explanation:
If a car slows down at -5 m/s2 and it comes to a stop after traveling 15 m we just have to use the next formula:
[tex]Vf^{2} =Vo^{2} +2ad[/tex]
Now we know that the final velocity is 0, so by inserting our data into the formula it would look like this:
[tex]Vf^{2} =Vo^{2} +2ad[/tex]
[tex]0 =Vo^{2} +2(-5m/s^{2})(15m)[/tex]
[tex]-Vo^{2}= -150m^{2}/s^{2}[/tex]
[tex]Vo^{2}= 150m^{2}/s^{2}[/tex]
[tex]Vo= \sqrt{150m^{2}/s^{2}}[/tex]
[tex]Vo= 12.25m/s[/tex]
The second shell in the ground state of atomic argon contains ________ electrons.
The second shell in the ground state of atomic argon contains 8 electrons.
Argon is represented with the symbol Ar and is the 18th element on the periodic table.It is an inert/noble gas.its electronic configuration is written as { Ne] 3s23p6According to the 2,8,8 rule, The first shell can have only two electrons, the second shell can hold up to eight and the third shell can hold up to 18 etc.Therefore, we can say that the atomic argon has 8 electrons in the second shell.
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What is the range of wavelengths for fm radio (88 mhz to 108 mhz)?
The range of wavelengths for FM radio waves is approximately 2.78 meters to 3.41 meters.
What is wavelength?Wavelength is a physical property of a wave that refers to the distance between two consecutive points on a wave that are in phase, i.e., they have the same position in their cycle of motion. It is the distance over which the wave's shape repeats itself.
In other words, the wavelength is the distance between two successive peaks or troughs of a wave. It is usually denoted by the Greek letter lambda (λ) and is measured in units of length, such as meters or nanometers.
The wavelength of a wave is determined by its frequency and the speed at which it travels through a medium. In general, waves with higher frequencies have shorter wavelengths, while waves with lower frequencies have longer wavelengths.
Wavelength is an important property of many types of waves, including light waves, sound waves, and radio waves. Understanding the properties of wavelength is crucial in fields such as physics, engineering, and telecommunications, as it affects how waves interact with materials, how they can be detected and measured, and how they can be transmitted over long distances.
Here in the Question,
The ranges of wavelengths for FM (frequency modulation) radio waves can be calculated using the formula:
wavelength (in meters) = speed of light (in meters per second) / frequency (in hertz)
The frequency range for FM radio is 88 MHz to 108 MHz. To calculate the corresponding wavelength range, we can use the speed of light, which is approximately 299,792,458 meters per second:
For the lower end of the FM radio frequency range (88 MHz), the wavelength is:
wavelength = 299,792,458 m/s / 88,000,000 Hz ≈ 3.41 meters
For the upper end of the FM radio frequency range (108 MHz), the wavelength is:
wavelength = 299,792,458 m/s / 108,000,000 Hz ≈ 2.78 meters
Therefore, the range of wavelengths for FM radio waves is approximately 2.78 meters to 3.41 meters.
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A football kicked off at an angle 20° from the ground reaches a maximum height of 4.7 m. What is the initial velocity of the kick?
A bird experiences an acceleration of -1.80 m/s^2 for 3.81 s, and ends up 26.5 m to the left of its starting point. What is its final velocity?
To solve this problem, we can assume that the motion is linear so that we can use the equations:
Xf = Xi + v0 t + 0.5 a t^2 ---> 1
vf = v0 + a t ---> 2
where Xi = initial distance = 0, v0 = initial velocity, Xf = final distance = 26.5 m, a = acceleration = - 1.80 m/s^2, t = time = 3.81 s, vf = final velocity
Substituting the given values into equation 1 to find for v0:
26.5 = v0 (3.81) + 0.5 (-1.80 m/s^2) (3.81)^2
3.81 v0 = 39.56449
v0 = 10.38 m/s
Using equation 2 to find for vf:
vf = 10.38 + (-1.80) (3.81)
vf = 3.53 m/s
An object has a mass of 15 kg. on planet x, the object weighs 126 n. the force of gravity on planet x is _____. 0.12 m/s2 8.4 m/s2 1875 m/s2
The force of gravity on planet x is equal to 8.4 m/s². Therefore, option (B) is correct.
What is the weight of the object?The weight of a body can be defined as the force acting on the body due to the gravity of the earth or any planet. Weight can be described as a vector parameter if the gravitational force is exerted on the object.
The measurement unit for weight is similar to that of force, which (SI) is the newton (N). A body with a mass of 1 Kg has a weight of 9.8 N on Earth's surface, and about 1/6th as much on the Moon.
The mathematical expression to determine the weight of an object is written as follows:
W = mg
Given the mass of the given object, m = 15 Kg
The weight of the object, W = 126N
The force of gravity on planet x will be equal to:
126 N = 15 Kg × g
g = 126/15
g = 8.4 m/s²
Therefore, the force of gravity on planet x is equal to 8.4 m/s².
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After using a thermometer where should it be placed
If white light illuminates a diffraction grating having 790 lines/mm , over what range of angles does the visible m = 1 spectrum extend?
Final answer:
The range of angles over which the visible m = 1 spectrum extends can be calculated using the equation θ = sin^(-1)(mλ/d), where θ is the angle, m is the order of the spectrum, λ is the wavelength of light, and d is the grating spacing. For a diffraction grating with 790 lines/mm spacing, the range of angles for the visible m = 1 spectrum is approximately 18.42° to 33.57°.
Explanation:
We are given the property of the illuminating light:
790 lines/mm
Which is also equivalent to:
790,000 lines/m
Taking the reciprocal of this value will give us the distance per line:
d = 1 m / 790,000 lines
d = 1.2658 * 10^-6 m
Now we can solve for the range of angles using the formula
λ = d * sin θ
sin θ = λ / d
where λ is the wavelength of light and θ is the angle
Now we know that visible light ranges from 400 to 700 nm, therefore we use these values to find the range.
when λ = 400 nm = 400 * 10^-9 m
sin θ = 400 * 10^-9 m / 1.2658 * 10^-6 m
θ = 18.42°
when λ = 700 nm = 700 * 10^-9 m
sin θ = 700 * 10^-9 m / 1.2658 * 10^-6 m
θ = 33.57°
Therefore the range of angles is 18.42° to 33.57°.
If the building absorbed so much heat that it turned into a liquid, then it would have undergone a phase change known as _____.
If the building absorbed so much heat that it turned into a liquid, then it would have undergone a phase change known as Melting.
under what conditions would a scale record a weight for an object which is equal to the magnitude of the gravitational force on the object?
answer:if there are no external forces acting on the object
Explanation:
under what conditions would a scale record a weight for an object which is equal to the magnitude of the gravitational force on the object?
If gravity and the normal reaction force are the only forces acting on the body, and the body is at rest or moving at constant velocity, the normal force and the weight are equal and opposite. Also if there are no influence of external forces
and air resistance is negligible.
from newtons law of motion which states that the rate of change in momentum is directly proportional to the force applied
f=km(v-u)/t
f=kma
where k is the constant and equal to 1
f=ma
When a bus moves forward after stopping to pick up passengers, why do the passengers feel as though they are being pushed back against their seats?
A. The passengers' bodies tend to remain still relative to the ground while the bus is moving.
B. The forward force caused by the inertia of the bus pushes back on the passengers' bodies.
C. The force of gravity tries to hold the bodies of the passengers in place.
D. The body of the bus moves faster than the seats on the bus due to inertial forces.
What object or class of objects makes up most of the solar systemâs mass?
When a magnet is moved into a wire coil, voltage is induced. if the coil had twice as many loops, the voltage induced would be?
Stars originate as large bodies of slowly rotating gas. because of gravity, these clumps of gas slowly decrease in size. the angular velocity of a star increases as it shrinks because of
Determine the displacement of a plane that is uniformly accelerated from 66 m/s to 88 m/s in 12 sec
The displacement of a plane that is uniformly accelerated is equal to 925.7 m.
What is the equation of motion?The equations of motion can be described as the relationship of the motion of any physical system as the function of time and set up the relationship between the acceleration, velocity, time, and displacement of a moving system.
Given, the initial velocity of the plane, u = 66 m/s
The final velocity of the plane, v = 88 m/s
The time taken by the plane, t = 12 sec
From the first equation of motion we can calculate the acceleration:
v = u + at
88 = 66 + a(12)
a = 1.83 m/s²
From the second equation of motion we can calculate the displacement of the plane:
S = ut + (1/2)gt²
S = 66 × 12 + (1/2)× 9.8× (12)²
S = 925.7 m
Therefore, the displacement of the plane is 925.7 m.
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The work done in pushing a tv set a distance of 2 m with an average force of 20 n is
creativity helps a scientist to
A) propose non testable theories about solar system
B)post valid scientific questions about solar systems
C) give unacceptable explanations about the solar system
D) use biased methods to answer questions about the solar system
Answer:
B.
Explanation:
I don't believe scientists would use a biased source to obtain credible and accurate evidence for their research, and we all should know that C. is wrong. With A. being wrong, the best choice to me would be none other than B.