A motorcycle with an initial value of $14,000 is decreasing in value at a rate of 3% each year. At this rate, approximately what will the value of the motorcycle be in 9 years?

A) 14,000
B) 10,000
C) 9,800
D) 550

Answers

Answer 1
Final answer:

The value of the motorcycle after 9 years, with a depreciation rate of 3% per year, will be approximately $9,800. This answer has been calculated using the formula for percent decrease applied to the initial value of the motorcycle.

Explanation:

This question revolves around the concept of percent decrease, a fundamental topic in mathematics. To estimate the value of the motorcycle after nine years, we need to apply the percent decrease continuously for these years.

The formula is: Final Value = Initial Value * (1 - rate of decrease)number of years

So in this case, the final value will be: $14,000 * (1 - 0.03)^9.

Calculating that gives us approximately $9,855, so the closest answer would be option C, $9,800.

Therefore after 9 years, the motorcycle will have depreciated to around $9,800 in value given a yearly depreciation rate of 3%.

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Related Questions

Solve for x and y: 28x-49y=35 and 4x-7y=5

Answers

The answer to your problem is (x,-5/7+4/7x) or 0=0. Infinite Solution

Grace is standing 14 feet from a lighthouse and Kelly is standing 12 feet from Grace. The angle that Grace looks up to see the top of the lighthouse is 45°. The angle that Kelly looks up to see the top of the lighthouse is y°. Find the height, h, of the lighthouse. Find the angle, rounded to the nearest tenth of a degree, in which Kelly looks up to the top of the lighthouse. To the nearest tenth of a degree, find the value of x° . In two or more sentences, explain your calculations

Answers

Grace has a 45 degree upwards angle, then the height of the lighthouse is 14'.

Case A. Kelly is 26 feet from the lighthouse.
The arcTangent of 14/26 is a 28.3 degree angle.

Case B. But if Kelly stood closer to the lighthouse, i.e. 2 feet away, then her angle is arcTangent of 14/2 = 81.9 degrees

What is the area of a rectangle with a length of 15 feet and a width of 9 feet?

Answers

Final answer:

The area of a rectangle with a length of 15 feet and a width of 9 feet is 135 square feet.

Explanation:

The area of a rectangle can be found by multiplying its length and width.

In this case, the length is 15 feet and the width is 9 feet.

To find the area, multiply 15 feet by 9 feet:

Area = 15 feet x 9 feet = 135 square feet

Therefore, the area of the rectangle is 135 square feet.

please help , show your steps , thanks

Answers

5 + 2*SQRT(x) = 15

 subtract 5 from each side

2*SQRT(x) = 10

(2*SQRT(x))^2 =10^2

2^2 *x = 100

4x=100

x=400/4

x = 25

If the lengths of two of the possible sides of a right triangle measure 4 root 15 and 7 root 6 what is the smallest possible length of the third side

Answers

Given that the sides of a right angle measures 4sqrt15 and 7sqrt6, thus the possible size of the third side will be:
using Pythagorean theorem:
c^2=a^2+b^2
c^2=(4sqrt15)^2+(7sqrt16)^2
c^2=4^2*15+7^2*16
c^2=240+784
c^2=1024
hence;
c=sqrt1024
c=32
Th possible third side is 32

The state of wyoming has roughly the shape of a rectangle that is 3.6 x 102 miles long and 2.8 x 102 miles high. what is the approximate area of wyoming? hint: the area of a rectangle is product of its length and width.

Answers

Assuming a regularly shaped rectangle, the formula for the area is given as:

A = L * W

where L and W are the length and width respectively

A = 3.6 x 10^2 miles * 2.8 x 10^2 miles

A = 100,800 square miles

or

A = 10.08 x 10^2 miles

Answer: The area of wyoming is [tex]A=1.008\times 10^{5}\, miles^{2}[/tex]

Step-by-step explanation:

The shape of wyoming is rectangular with length , [tex]L=3.6\times 10^{2}\, miles[/tex]

and height , [tex]H=2.8\times 10^{2}\, miles[/tex]

Area of rectangle , [tex]A=L\times W[/tex]

=> [tex]A=(3.6\times 10^{2})\times (2.8\times 10^{2})\, miles^{2}[/tex]

=>[tex]A=1.008\times 10^{5}\, miles^{2}[/tex]

Thus the area of wyoming is [tex]A=1.008\times 10^{5}\, miles^{2}[/tex]

QUESTION 18 I want to build a right triangular garden on the side of my house. Find the sides of the triangle if the hypotenuse is 6 feet and the two sides are equal in length.

Answers

The diagram of the right-angled triangle is shown below

Using the Pythagoras theorem
6² = a²+a²
36 = 2a²
18 = a²
a = √18 = 3√2

Solve the inequality -2x is less than or equal to 3x + 1 is less than or equal to 10

Answers

-2x < = 3x + 1 < = 10

split them
-2x < = 3x + 1         3x + 1 < = 10
-2x - 3x < = 1          3x < = 10 - 1
-5x < = 1                 3x < = 9
x > = -1/5                 x < = 3

solution is : -1/5 < = x < = 3 <==

A ramp 28 ft long rises to a platform. the bottom of the platform is 15 ft from the foot of the ramp. find x , the angle of elevation of the ramp

Answers

I'm not way too sure, but the angle of elevation is perhaps 32.39

Let $AB = 6$, $BC = 8$, and $AC = 10$. What is the area of the circumcircle of $\triangle ABC$ minus the area of the incircle of $\triangle ABC$?

Answers

The problem is illustrated by the figure shown below.

It is clear that ΔABC is a right triangle because
(a) it is inscribed in a circle,
(b) Its sides satisfy the Pythagorean theorem because
      6² + 8² = 36 + 64 = 100, and 10² = 100.

Therefore, AC is the diameter of the circumscribing circle, and the radius is
 r = 5.

The area of the circumscribing circle is 
A₁ = π(5²) = 25π

The area of the triangle is
A₂ = (1/2) 8*6 = 24

The required area, of the circumcircle minus that of the triangle (shaded area) is
A₁ - A₂ = 25π - 24 = 54.54 square units.

Answer:
54.54 square units.

You will be charged 12.5% interest on a loan of $678. how much interest will you pay on the loan?

Answers

12.5% of 678 = 
0.125(678) = 84.75 <==

It is given in the question that

You will be charged 12.5% interest on a loan of $678.

So to find the interest, we have to find 12.5% of 678. And 12.5% = 0.125

So we have to find the value of 0.125 of 678.

[tex]0.125*678 = 84.75[/tex]

Therefore the interest that you will have to pay on loan is $84.75 .

Find the possible value or values of n in the quadratic equation 2n2 – 7n + 6 = 0

Answers

2n^2-7n+6=0

2n^2-4n-3n+6=0

2n(n-2)-3(n-2)=0

(2n-3)(n-2)=0

n=3/2, n=2

Answer:

[tex]n=\frac{3}{2},\,\,n=2[/tex].

Step-by-step explanation:

The equation you have is a quadratic equation because the polynomial [tex]2n^{2}-7n+6[/tex] has degree 2. One of the methods available to solve kind of equations is  to factorize the polynomial  on the left hand side. To factorize you can do the following:

(1) [tex]2n^2-7n+6[/tex]. The given polinomial

(2) [tex]\frac{2\times(2n^2-7n+6)}{2}=\frac{(2n)^{2}-7(2n)+12}{2}[/tex].  Multiply and divide by 2, because it is the coeficient of [tex]n^{2}[/tex]

(3)  [tex]\frac{(2n)^{2}-7(2n)+12}{2}=\frac{(2n-\_\_)(2n-\_\_)}{2}[/tex]. Separate the polynomial in two factors, each one with [tex]2n[/tex] as a first term. The sign in the first factor is equal to the sign in the second term of the polynomial, that is to say, [tex]-7n[/tex]. The sign in the second factor is the sign of the second term multiplied by the sign of the third term, that is to say [tex](-)\times(+)=(-)[/tex] . In the blanks you should select two numbers whose sum is 7 and whose product is 12. Those numbers must be 3 and 4.

(4)The polynomial factorized is [tex]\frac{(2n-4)(2n-3)}{2}[/tex]

(5)Use the common factor in the numerator to cancel the number 2 in the denominator to obtain [tex](n-2)(2n-3)[/tex]

Then the given equation can be written as:

[tex]{(2n-3)(n-2)=0[/tex]

The product of two expression equals zero if and only if one of the expression is zero. From here we have that

[tex]2n-3=0[/tex] or [tex]n-2=0[/tex]

From the first equality we obtain that [tex]n=\frac{3}{2}[/tex]. From the second equality we obtain that [tex]n=2[/tex].

Find S8 for the geometric series 3 + -6 + 12 + -24 +…

Answers

I guess you are asking to find the sum of the first 8 terms. If so, then:
Sum = a₁(1-rⁿ)/(1-r), where a₁ is the 1st term,  r=common ratio and n=number of terms:
the 1st term a₁ =3
common ratio r = - 2 (since -6/3 = - 2, and 12/-6 = - 2, etc.)

Sum = 3[(1- (-2)⁸]/(1-2) = 3(1- 256)/(1/2)
Sum = -1530

the sum of the first 8 terms of the series is [tex]\( -255 \)[/tex].

To find the sum [tex]\( S_8 \)[/tex] of the geometric series [tex]\( 3 - 6 + 12 - 24 + \ldots \)[/tex], we need to determine the common ratio [tex](\( r \))[/tex] and the first term [tex](\( a \)).[/tex]

The general form of a geometric series is [tex]\( a + ar + ar^2 + \ldots + ar^{n-1} \)[/tex], where:

- [tex]\( a \)[/tex] is the first term,

- [tex]\( r \)[/tex] is the common ratio,

- [tex]\( n \)[/tex] is the number of terms.

In our series:

- [tex]\( a = 3 \)[/tex] (the first term),

- To find the common ratio [tex](\( r \))[/tex], we can divide any term by its preceding term:

 - [tex]\( \frac{-6}{3} = -2 \)[/tex]

 - [tex]\( \frac{12}{-6} = -2 \)[/tex]

 - [tex]\( \frac{-24}{12} = -2 \)[/tex]

So, [tex]\( r = -2 \)[/tex].

Now, [tex]\( S_n \)[/tex], the sum of the first [tex]\( n \)[/tex] terms of a geometric series, is given by the formula:

[tex]\[ S_n = \frac{a(1 - r^n)}{1 - r} \][/tex]

Substituting the values of [tex]\( a \), \( r \)[/tex], and [tex]\( n = 8 \)[/tex], we get:

[tex]\[ S_8 = \frac{3(1 - (-2)^8)}{1 - (-2)} \][/tex]

[tex]\[ S_8 = \frac{3(1 - 256)}{1 + 2} \][/tex]

[tex]\[ S_8 = \frac{3(-255)}{3} \][/tex]

[tex]\[ S_8 = -255 \][/tex]

So, the sum of the first 8 terms of the series is [tex]\( -255 \)[/tex].

Mr. Rr the Rreliable Rrobot has been programmed to whistle every $18$ seconds and do a jumping jack every $42$ seconds, starting from the moment he is turned on. (For example, he does his first jumping jack $42$ seconds after he is turned on.)

How many times during the first $15$ minutes after activation will Mr. Rr whistle and do a jumping jack at the same instant?

Answers

Answer:

7 times during the first 15 minutes

Step-by-step explanation:

Remember that

[tex]1\ min=60\ sec[/tex]

so

[tex]15\ min=15(60)=900\ sec[/tex]

Decompose the numbers 18 and 42 in prime factors

we know that

[tex]18=(2)(3^2)[/tex]

[tex]42=(2)(3)(7)[/tex]

Find the least common multiple (LCM)

The LCM is

[tex](2)(3^2)(7)=126\ sec[/tex]

we need to find all multiples of 126 that are less than or equal 900.

[tex]126*1=126\ sec\\126*2=252\ sec\\126*3=378\ sec\\126*4=504\ sec\\126*5=630\ sec\\126*6=756\ sec\\126*7=882\ sec[/tex]

therefore

7 times during the first 15 minutes

Which of the following is the sum of the polynomials 5x2 - 4x + 1 and -3x2 + x - 3 ?

2x2 + 3x + 2
8x2 - 5x - 2
2x2 - 3x - 2
-8x2 - 3x - 2

Answers

The answer is 2x^2-3x-2.
Just align the polynomials and combine like terms.

in the diagram which pair of angles are corresponding angles

Answers

The answer  to that is <3 and <7

C

Answer:

Option C is correct .i.e., ∠3 and ∠7

Step-by-step explanation:

Corresponding angles are the angles that are at the same corner at each Point of Intersection.i.e., if first angle is at the top left corner of one intersection then the angle at the other intersection is also at the top left.

From Given Figure,

Following are pairs of corresponding angles,

∠1 and ∠5

∠2 and ∠6

∠4 and ∠8

∠3 and ∠7

Therefore, Option C is correct .i.e., ∠3 and ∠7

A Web music store offers two versions of a popular song. The size of the standard version is 2.8 megabytes (MB). The size of the high-quality version is 4.9 MB. Yesterday, there were 1070 downloads of the song, for a total download size of 3521 MB. How many downloads of the high-quality version were there?

Answers

x=  standard

y = high quality

x +y = 1070

y=1070-x

2.8x + 4.9y =3521

2.8x +4.9(1070-x) = 3521

2.8x+5243-4.9x =3521

-2.1x=-1722

x=-1722/-2.1 = 820

820*2.8 =2296

1070-820 =250

250*4.9 = 1225

1225+2296 = 3521


there were 250 high quality downloads



What is the graph of the function f(x) = the quantity of 3 x squared plus 2 x plus 10, all over x plus 3

A) a graph is shown with a vertical asymptote at x = -3 increasing from negative infinity to just under -35 and then decreasing back to negative infinity as well as decreasing to just under five and increasing to infinity
B) graph with vertical asymptote of x equals 3, and oblique asymptote of y equals x minus 1
C) graph with vertical asymptote of x equals 3, and oblique asymptote of y equals negative x minus 1
D) graph with vertical asymptote of x equals negative 3, and oblique asymptote of y equals negative x minus 1

Answers

I think the correct answer would be the first option. The graph of the function  f(x) = the quantity of 3 x squared plus 2 x plus 10, all over x plus 3 would be a graph that is showing  a vertical asymptote at x = -3 increasing from negative infinity to just under -35 and then decreasing back to negative infinity as well as decreasing to just under five and increasing to infinity. The graph intersects the y-axis at one point which is at y = 3.33333. It would be best if you graph the function by using a software as you will see the real structure of the plot.

Max is in a control tower at a small airport. He is located 50 feet above the ground when he spots a small plane on the runway at an angle of depression of 27. What is the distance of the plane from the base of the tower? Round to the nearest foot. A. 25 feet B. 110 feet C. 56 feet D. 98 feet

Answers

tanα=y/x

x=y/tanα, we are told the height is 50 ft and the angle is 27°

x=50/tan27° ft

x≈98 ft (to nearest whole foot)
Answer:

The distance of the plane from the base of the tower is:

                    Option: D

                    D.  98 feet  

Step-by-step explanation:

Let x denotes the distance of the plane from the base of the tower.

Now, in the right angled triangle we will need to use trignometric identity corresponding to 63°.

Based on the figure we have:

[tex]\tan 63=\dfrac{x}{50}\\\\\\x=50\times \tan 63[/tex]

[tex]x=50\times 1.9626\\\\\\x=98.13\ feet[/tex]

which to the nearest feet is:

                        98  feet

Find all solutions in the interval [0, 2π). 7 tan3x - 21 tan x = 0

Answers

To solve the trigonometric expression we proceed as follows;
7(tan x)^3-21tanx=0
this can be written as:
7(tan x)^3=21tanx
dividing through by 7 we get:
(tan x)^3=tan x
dividing through by tan x we get:
(tanx)^1=1
hence;
tan x=+\-1
when tan x=1
x=45
when tan x=-1
x=-45
Given that our answer should be at the interval [0,2π] the answer:
45=45/180=1/4π

PLEASE HELP ME ON THESE PROBLEMS, ITS URGENT! (Help for any of these would be greatly appreciated!)

1. A grocer mixes two grades of coffee which sell for 70 cents and 80 cents per pound, respectively. How much of each must he take to make a mixture of 80 pounds which he can sell for 76 cents per pound?

2. How many quarts of pure alcohol must be added to 40 quarts of a mixture that is 35% alcohol to make a mixture that will be 48% alcohol?

3. If a container contains a mixture of 5 gallons of white paint and 11 gallons of brown paint, how much white paint must be added to the container so that the new mixture will be two-thirds white paint?

4. Can the sum of three consecutive odd integers be (a) 25? (b) 45?

5. A tank can be filled in 9 hours by one pipe alone, in 12 hours by a second pipe alone, and can be drained when full, by a third pipe, in 15 hours. How long would it take to fill the tank if it is empty, and if all pipes are in operations?

Answers

1.) We can solve the problem by developing a linear model.
Let x represent the quantity to be used of the grade of coffee that sells for $70 per pound, and y represent the quantity to be used of the grade of coffee that sells for $80 per pound, then
[tex] \left\begin{array}{c}x+y=80 . . . (1)\\70x+80y=76(80) . . . (2)\end{array}\right \\ \\ \Rightarrow \left\begin{array}{c}80x+80y=6400 . . . (3)\\70x+80y=6080 . . . (4)\end{array}\right \\ \\ \Rightarrow10x=320 \\ \\ \Rightarrow x=32 \\ \\ \Rightarrow y=80-32=48[/tex]
Therefore, 32 pounds of the grade of coffee that sells for $70 per pound, and 48 pounds of the grade of coffee that sells for $80 per pound should be used.


2.) Volume of alcohol in the original mixture
[tex] \frac{35}{100} \times 40=14 [/tex] quarts

Let x be the number of quarts of alcohol to be added, then
Volume of alcohol in the new mixture
[tex]\frac{48}{100} \times (40+x)=14+x \\ \\ \Rightarrow19.2+0.48x=14+x \\ \\ \Rightarrow0.52x=5.2 \\ \\ \Rightarrow x=10[/tex]

Therefore, 10 quarts of pure alcohol should be added


3.) Original proportion of white paint in the mixture
[tex]=\frac{5}{5+11}=\frac{5}{16}[/tex]

Let x be the number of gallons of white paint to be added, then
[tex]\frac{5+x}{16+x}=\frac{2}{3} \\ \\ \Rightarrow3(5+x)=2(16+x) \\ \\ \Rightarrow15+3x=32+2x \\ \\ \Rightarrow x=32-15=17[/tex]
Therefore, 17 gallons of white paint should be added.


4a.) Let the three consecutive odd integers be x - 2, x and x + 2, then
[tex]x - 2 + x + x + 2 = 25 \\ \\ \Rightarrow3x=25\Rightarrow x=8.33[/tex]
which is not an integer.
Hence, the sum of three consecutive odd integers cannot be 25.

4b.) Let the three consecutive odd integers be x - 2, x and x + 2, then
[tex]x - 2 + x + x + 2 = 45 \\ \\ \Rightarrow3x=45\Rightarrow x=15[/tex]
Thus, the three consecutive odd intergers whose sum is 45 are 13, 15 and 17.


5.) If all pipes are open and the tank was initially empty, let t be the time it will take to fill the tank, then
[tex] \frac{1}{t} = \frac{1}{9} + \frac{1}{12} - \frac{1}{15} = \frac{20+15-12}{180} = \frac{23}{180} \\ \\ \Rightarrow t= \frac{180}{23} =7.83 [/tex]
Therefore, it will take 7.83 hours to get the tank filled up.

What is the equation of the following line? Be sure to scroll down first to see all answer options.

Answers

the answer is C y = 1/3x

Answer:

Option C. is the correct option.

Step-by-step explanation:

Equation of line is represented as y = mx + c

where m = slope of the line

c = y - intercept

Since line is passing through origin (0, 0) and a point (6, 2)

Therefore y intercept of the line will be 0.

c = 0

Slope of the line [tex]m=\frac{y-y'}{x-x'}[/tex]

[tex]m=\frac{2-0}{6-0}[/tex]

[tex]m=\frac{2}{3}[/tex]

So the equation will be

[tex]y=\frac{1}{3}x[/tex]

Therefore, option C. is the answer.

Find the length of arc VZX in circle C

Answers

|VZX|= 2.π.8.[tex] \frac{(360-160)}{360} [/tex]


= [tex]\frac{400 \pi }{45}[/tex]



=  [tex]\frac{80 \pi }{9}[/tex]

Good Luck!

Length of arc VZX is 27.92 units.

What is arc?

The arc is a portion of the circumference of a circle.

Given,

Radius of circle = 8 units

∠VCX = 160°

Let length of arc VZX = x

x = area of circle×(360°- ∠VCX)/360°

x = 2π×8×(360-160)/360

x = 2π×8×(200)/360

x = 400π/45

x = 80π/9

x = 27.92 units

Hence, length of arc VZX is 27.92 units.

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Arrange the functions in ascending order, starting with the function that eventually has the lowest value and ending with the function that eventually has the greatest value.
2x+5
2^x+3
2^x+10
2x
x²+2

PLEASE HELP 20 POINTS PROVIDED

Answers

2^x+10,2^x+3,x²+2,x²,2x+5,2x
2^x is higher than x²+2 because in small numbers for x ,x^2 is bigger but after x=6 the difference between them increases and 2^x becomes more

What is 78% written as a decimal

Answers

Hello there!

78% as a decimal is 0.78
All you have to do is move the decimal place two times to the left.
78%
7.8
0.78 <---- this is your answer, and how to get to it.

I hope this helps!

Drag the tiles to the correct boxes to complete the pairs. Match the numerical expressions to their simplified forms.


Drag the tiles to the correct boxes to complete the pairs. Match the numerical expressions to their simplified forms


Tiles:

A).
(P^5) ^1/4
---------------
(P^-3 Q^-4)

B).
(P^2Q^7) ^1/2
----------
(Q^4)

C).
(P^6Q^3/2)^1/3

D).
(PQ^3)^1/2
--------------
(PQ)^-1/2


Pairs:

1.)
P^2Q^1/2

2.)
PQ^2

3.)
P^2Q

4.)
PQ^3/2

Answers

A ) ( P^5 * P^3 * Q^4 )^(1/4) = ( P^8 * Q^4 )^(1/4) = P^2 Q   Answer: 3 )
B ) ( P^2 * Q^7 / Q^4 )^(1/2)= ( P^2 * Q^3 )^(1/2) = P Q^(3/2)
Answer: 4 )
C ) ( P^6 * Q^(3/2) )^(1/3) = P^2 Q^(1/2)  Answer:  1 )
D ) ( P * Q^3 ) ^(1/2) * ( P * Q )^(1/2) = ( P^2 * Q^4 )^(1/2) =
= P Q^2    Answer:  2 )

find the magnitude of 6+2i

Answers

Final answer:

The magnitude of 6 + 2i is 2√10.

Explanation:

To find the magnitude of the complex number 6 + 2i, we can use the Pythagorean theorem. The magnitude, or absolute value, of a complex number is found by taking the square root of the sum of the squares of its real and imaginary parts. In this case, the real part is 6 and the imaginary part is 2. So the magnitude is:

|6 + 2i| = √(6^2 + 2^2) = √(36 + 4) = √40 = 2√10

Therefore, the magnitude of 6 + 2i is 2√10.

Help which is the correct function

Answers

It is decreasing in the positive x axis  so the exponent will be negative so its either B or D.
when x = 5,  y is about 3 . something:-

check for d:-  4*e^(0.05*5) = 3.11

so its D.

What is the probability of drawing two yellow marbles if the first one is NOT placed back into the bag before the second draw? Their is 10 marbles total, 2 yellow, 3 pink, and 5 blue

Answers

Final answer:

The probability of drawing two yellow marbles in succession without replacement from a bag of 10 marbles, where 2 are yellow, is 1/45.

Explanation:

The student is asking about the probability of drawing two yellow marbles successively without replacement from a bag containing a total of 10 marbles with different colors. To solve this problem, we use conditional probability. The probability of drawing the first yellow marble is 2 out of 10 since there are 2 yellow marbles among 10 total marbles. This can be written as P(Y1) = 2/10 or 1/5. After the first yellow marble is drawn, there is only 1 yellow left among 9 total marbles, so the probability of drawing a second yellow marble is P(Y2|Y1) = 1/9.

The two events are dependent since the outcome of the first draw affects the second draw. Therefore, to find the overall probability of both events happening, we multiply their probabilities: P(Y1 and Y2) = P(Y1) × P(Y2|Y1) = (1/5) × (1/9) = 1/45. So, the probability of drawing two yellow marbles successively without replacement is 1/45.

Help please:((((((((((((((((

Answers

Answer:

  B.  The amount spent on grapes compared with the weight of the purchase.

Step-by-step explanation:

Grapes are usually sold at some dollar amount per pound. That dollar amount is the "rate of change," and it is generally constant.

___

In the case of pizza delivery or bus ridership, it is hard to imagine what the "rate of change" might be, as the relationship is probably not a function.

Other Questions
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