A falling stone is at a certain instant 90 feet above the ground. two seconds later it is only 10 feet above the ground. if it was thrown down with an initial speed of 4 feet per second, from what height was it thrown?

Answers

Answer 1
Final answer:

The stone was originally thrown from a height of 234 feet. This solution was obtained using the physics kinematic equation for vertical motion.

Explanation:

This problem can be solved using the kinematic equation:

Δy = V₀t + 1/2gt²

, where:

Δy is the displacement (final position - initial position)V₀ is the initial velocityt is the timeg is the acceleration due to gravity, which is -32 ft/s² (negative because it's acting downwards)

From the statement we know: Δy = 10 ft - 90 ft = -80 ft after 2 seconds. We substitute these values and solve for the initial position, y₀. The equation becomes:

-80 = 4*2 + 1/2*(-32)*2²

. Solving gives us -80 = 8 - 64, so

y₀ = 80 + 64 + 90 = 234 ft

. Therefore, the stone was thrown from a height of 234 feet.

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Answer 2
Final answer:

Using the equations of motion under gravity, it's determined that the stone was thrown from a height of 162 feet considering it was thrown down with an initial velocity and passed specific heights in its journey.

Explanation:

The question involves finding the original height from which a stone was thrown, given that it was thrown down with an initial speed and passes specific points in its descent. To solve this problem, we can use the equations of motion under the influence of gravity. The formula that relates the initial velocity (u), the acceleration due to gravity (g = 32 feet/second2 downward), the time taken (t), and the displacement (s) is s = ut + (1/2)gt2.

In this instance, the stone is observed to move from 90 feet above the ground to 10 feet above the ground in 2 seconds, with an initial downward speed of 4 feet/second. The drop in height (displacement) is 80 feet (90 - 10). We can insert these values into the formula to find the initial height: Let H be the initial height, the equation becomes H - 90 = 4(2) + (1/2)(32)(22). Simplifying, we find that H - 90 = 8 + 64, which resolves to H = 162 feet.

Hence, the stone was thrown from a height of 162 feet.


Related Questions

A brick is released with no initial speed from the roof of a building and strikes the ground in 1.80 s , encountering no appreciable air drag. how tall, in meters, is the building?

Answers

Kinematics is used in this problem. The mass does not matter here because the question is mass independent. vi = 0 vf = x d = ? d = vi + 1/2 a t^2 d = 0 + 1/2 (9.8) (1.8)^2 d = 15.9 m (counting sig figs)

Which of these statements are true about scientific theories and laws?
Theories are untested.
Laws are untested.
Laws are often expressed as math formulas.
A law is the same as a theory.
Theories are not opinions.

Answers

Answer:

Theories are not opinions.

Explanation:

Theories are all of them tested, with the scientific method in order to be accepted or refuted, then Laws are tested and are observable by any means all around the globe, the only option that is actually correct would be that Theories are not opinions because they are scientific statements that can be tested.

Answer:

theories are not opinions

Explanation:

What is the chemical formula for mercury(I) nitrate? Hgmc021-1.jpg(NOmc021-2.jpg) Hg(NOmc021-3.jpg)mc021-4.jpg Hgmc021-5.jpg(NOmc021-6.jpg)mc021-7.jpg Hgmc021-8.jpg(NOmc021-9.jpg)mc021-10.jpg

Answers

Final answer:

The chemical formula for mercury(I) nitrate is Hg2(NO3)2, featuring a Hg₂²+ dimeric cation.

Explanation:

The chemical formula for mercury(I) nitrate is Hg2(NO3)2. This compound is created when a large excess of mercury reacts with dilute nitric acid. Mercury(I) compounds are unique because they contain a Hg₂²+ ion, which is a dimeric cation where two mercury atoms are bonded together, each with a +1 oxidation state, giving the overall molecule a +2 charge. It's important to note that the compound must be handled with care due to the toxicity of mercury compounds.

Two cars start from rest at a red stop light. When the light turns green, both cars accelerate forward. The blue car accelerates uniformly at a rate of 3.8 m/s2 for 4.6 seconds. It then continues at a constant speed for 9.2 seconds, before applying the brakes such that the car’s speed decreases uniformly coming to rest 257.71 meters from where it started. The yellow car accelerates uniformly for the entire distance, finally catching the blue car just as the blue car comes to a stop.
How far does the blue car travel before its breaks are applied to  slow down?

Answers

First, create an illustration of the motion of the two cars as shown in the attached picture. The essential equations used are:

For constant acceleration:
a = v,final - v,initial /t
d = v,initial*t + 1/2*at²

For constant velocity:
d = constant velocity*time

The solutions is as follows:

   a = v,final - v,initial /t
  3.8 = (v₁ - 0)/4.6 s
  v₁ = 17.48 m/s

    Total distance = d1 + d2 + d3
    d1 = d = v,initial*t + 1/2*at²
    d2 = constant velocity*time
    
   Total distance =  0*(4.6) + 1/2*(3.8)(4.6)² + (17.48)(9.2) + d3= 257.71
   d3 = 56.69 m

How long will it take light at 300000 km/s to reach us from the sun? The sun is 15000000 km from earth

Answers

That would take 0.02 seconds :).

Light takes approximately 8 minutes and 20 seconds to travel from the Sun to Earth.

Light travels from the Sun to the Earth at approximately 300,000 kilometers per second. The average distance from the Sun to Earth is about 150 million kilometers. To calculate the time it takes for light to travel this distance, we can use the formula:

Time (seconds) = Distance (kilometers) / Speed of light (kilometers/second)

We divide 150,000,000 kilometers by 300,000 kilometers/second to find the time it takes light to travel from the Sun to Earth:

Time = 150,000,000 km / 300,000 km/s = 500 seconds

Now, we convert seconds into minutes:

Time = 500 seconds / 60 seconds/minute = 8 minutes and 20 seconds

Thereby, it takes light approximately 8 minutes and 20 seconds to travel from the Sun to Earth, a fact that gives us a practical understanding of the vastness of space within our solar system.

Jermaine runs exactly 2 laps arounda 400 meter track. What is his distance traveled?

Answers

He would’ve ran 800 meters. 400 meters per lap times 2 laps equals 800 meters
The answer would be 800 m. This is simple multiplication. If two laps were run on a 400 meter track, we would take those two numbers and multiply. This is because, to put it simply, there are two 400's. So, your answer would be 400 plus 400, or 400 times 2. If you take the zero's off of the 400's, you would get 4 plus 4, or 4 times 4. Since 4 times 4 is 8, 400 times 400 would be 800. Since we have a unit involved, your answer is not 800, it is 800 m. So, your final answer is 800 m. 

why doesn't a ball roll on forever after being kicked at a soccer game?

Answers

Because of gravity and friction. 
friction of the grass and gravity holding it down

The shadow cast by a simple stick or obelisk allowed ancient people to

Answers

The answer to this question is tell the time of day
The shadow cast that used by ancient people will be really dependant on the positioning of the sun that creates a different type of shadows.
This serves a very similar purpose with modern-time clock because the people could predict the time of the day by simply seeing the type of the shadows

The shadow cast by a simple stick or obelisk allowed ancient people to keep track of time, establish different moments during the day, and with a little more precision, establish hours.

Further explanation

Time is a property of life that always goes on, it never stops. Since the beginning of time, humans have wanted to measure time and keep track of it. This idea was possible since we live in a periodic world, because we have a new day every 24 hours, and a ney year every 365 consecutive days.

In ancient times, we didn't have clocks that could tell us the time, so humans used the tools that they had at hand to do this. The most widespread tool that all could afford to use was the Sun, and they used it because the Sun rises everyday from the East and rests everyday at the west, more or less at the same time (at least in the Ecuador).

Therefor due to this periodic motion, ancient civilizations could keep track of at least some moments of the day, like when the Sun is at its highest point, or when the shadow done by an object is equal to the object's length. This was a rough but powerful idea, and then with the invention of other more precise tools (like sand clocks), they could keep track of specific lengths of time. Joining both principles together, the Sun clock was born.

In today's time, some of those Sun clocks are still seen (mostly as a way of decoration on parks), however they are a reminder of how things were done in the old days.

Learn moreMovement of the Sun: https://brainly.com/question/9352910How time can be used for other porpuses: https://brainly.com/question/3154844Keywords

Time, Sun, solar clock, sand clock

A dynamite blast at a quarry launches a rock straight upward, and 2.4 s later it is rising at a rate of 10 m/s. assuming air resistance has no effect on the rock, calculate its speed (a) at launch and (b) 5.1 s after launch.

Answers

Answer:

(a) 33.52 m/s

(b) 16.46 m/s downward

Explanation:

Part (a)

To find the initial speed of the rocket, we can use the kinematic equation:

[tex]v = u + at[/tex]

where:

u is the initial velocity of the object. v is the final velocity of the object.a is the constant acceleration of the object. t is the time elapsed during the acceleration.

In this case:

v = 10 m/sa = -9.8 m/s²t = 2.4 s

Therefore:

[tex]10 = u + (-9.8)(2.4)[/tex]

[tex]10 = u - 23.52[/tex]

[tex]u = 10 + 23.52[/tex]

[tex]u = 33.52 \textsf{ m/s}[/tex]

So, the speed of the rock at launch is 33.52 m/s.

Part (b)

We can use the same kinematic equation to find the speed at t = 5.1 s:

[tex]v = u + at[/tex]

[tex]v = 33.52 + (-9.8)(5.1)[/tex]

[tex]v = 33.52 - 49.98[/tex]

[tex]v = -16.46 \textsf{ m/s}[/tex]

The negative sign indicates that the rock is moving downward at this time.

So, 5.1 seconds after launch, the speed of the rock is 16.46 m/s downward.

A group of students is investigating whether copper is a better thermal conductor than steel. The students take a copper wire and a steel wire of the same length and diameter. They put equal lengths of wax on one end of each wire and dip the other end into a beaker of hot water. The length of wax left on the wires after 10 minutes is shown.
Experimental Observations:
- Original length of wax
- Copper: 3 cm
- Steel: 3 cm
- Length of wax after 10 minutes
- Copper: 0.7 cm
- Steel: 1.8 cm
What was the dependent variable in this experiment?
a. Type of wire used
b. Original length of wire
c. Original length of wax
d. Thermal conductivity of wire

Answers

Answer: Option c: original length of wax.

In an experiment, there are three types of variables: independent, dependent, controlled or constant.

Independent variables are the ones which do not change but can be changed by the scientist. dependent variables are the ones which change when the independent variables change. This is what a scientist observes. Constant variables are the conditions which are kept the same through out the experiment.

In the given experiment, the type of wire used, the length of the wire, thermal conductivity of the wire are independent variables. The time for which the wire is dipped in the hot water, the temperature of the water are controlled variables.

The original length of the wax is a dependent variable. This is because, as the wire is changed, depending upon the thermal conductivity of the wire, the original length of the wax changes.

Actually, here’s more explaining for this question. In the given experiment, the students are investigating whether copper is a better thermal conductor than steel. To do this, they take a copper wire and a steel wire of the same length and diameter. They put equal lengths of wax on one end of each wire and dip the other end into a beaker of hot water. They then observe the length of wax left on the wires after 10 minutes.In this experiment, the dependent variable is the original length of wax. The reason for this is that the length of wax left on the wires after 10 minutes will vary depending on the thermal conductivity of the wire. The independent variables in this experiment are the type of wire used (copper or steel) and the original length of the wire. The students have control over these variables and can choose to use either copper or steel wire of the same length and diameter.The controlled variables in this experiment are the time for which the wire is dipped in the hot water and the temperature of the water. These variables are kept constant throughout the experiment to ensure that any changes in the length of wax can be attributed to the thermal conductivity of the wire and not to other factors. So, to summarize, the dependent variable in this experiment is the original length of wax, while the independent variables are the type of wire used and the original length of the wire. The controlled variables are the time for which the wire is dipped in the hot water and the temperature of the water. Therefore, option C is your answer.

Hope this helps!

-encey6915

Suppose the shipping company were packing balls with a diameter of 2 inches instead of Cubes. Would the large box hold more balls or fewer balls than boxes? Explain your answer.

Answers

To determine if the larger box will hold more cubes or spheres, one should determine or calculate for the volumes of the figures and whichever gives the smaller value will have to be the answer. 

     Volume of cube = (edge)³ = (2 in)³ = 8 in³

     Volume of sphere = (4πr³)/3
      where r is the radius and is equal to half of the length of the sides. Substituting,
             Volume of sphere = (4π)(1 in)³ / 3 = 4.19 in³

Since spheres give the smaller value for volume, the answer to this item would have to be SPHERE. 

The position of a rabbit along a straight tunnel as a function of time is plotted. what is its instantaneous velocity

Answers

Since the plot is not given, I;m not sure I can give the exact answer since there are two possible cases. If the plot is linear, then the instantaneous velocity is the same for each point in the plot. This is equal to the slope of the line. However, if the plot is a curve, you have to be specific at what time you would like to determine the instantaneous velocity. The slope at that point would be the instantaneous velocity of the motion. For example, the equation of the curve is:

x = t² + 5t + 3
If you want to find the inst. velocity at t = 2s, differentiate the equation and replace t with 2:
dx/dt = 2t + 5 = 2(2) + 5 = 9 m/s 

Consider a box sitting in the back of a pickup. The pickup accelerates to the right, and because the bed of the pickup is sticky, the box does not slide around the truck when this happens.What direction is the force acting on the box due to the truck?

Answers

The force would be coming from the right causing the box the lean/ slide to left, if it wasnt sticky.

Considering a box sitting in the back of a pickup. The pickup accelerates to the right, and because the bed of the pickup is sticky, the box does not slide around the truck when this happens. But the force acting on the box is left.

What is Force ?

Force is responsible for the motion of an object. it produces acceleration in the body. According to newton's second law force is mass times acceleration i.e. F =ma. Its SI unit is N which is equivalent to kg.m/s².

There are two types of forces, balanced force and unbalanced force.

When Net force acting on a body is zero then we call it as balanced force. .

Unbalanced forces are those when resultant of all the forces is not equal to zero is called as unbalanced force. unbalanced force is responsible for the motion of the body.

Whatever we are talking about force in this problem is called as pseudo force, it same as we feel in the bus when we are standing in the bus suddenly driver brakes we go ahead in the bus or we feel forward force.

Pseudo force is not actual force but it can felt, centrifugal force is a type of pseudo force.

In this problem, as pickup accelerates, according to newtons first law box in the pickup tend to have its original velocity(0 if pickup is at rest or v when it is in motion). because of this when pickup accelerates right, box feel pseudo force in the opposite direction(Left).

Hence left is correct.

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Explain what the star looks like to Jane
Explain what the star looks like to John
Explain why the stars look different between Jane and john

Answers

This is what I wrote for my project on this exact question! Hope this helps!

Now, Jane and John are in a different situation, observing stars through a telescope. The Doppler effect is also true for light emitted by stars, but instead of hearing the difference, you see the difference in their color. You know if a star is coming or going from the color it emits. Based on how close and in what direction the star is moving, the star can look very different. One person could be looking at a star and see a red color light being emmited from the star. This basically means the star is traveling in the direction of the person viewing it. This person could also see another star and see a blue color light being emmited from the star. This simply means the star in traveling away from the person viewing it.

    Also, of course the size could be different based on how close the star is. We know all stars are extremely far away from earth but you can tell if a star is closer to earth than another star based on if it is relatively larger than than other star and if it is brighter. To John, the star he sees has a blue light so his star is traveling away from him. However, to Jane her star has a red light which means that star is traveling towards the earth. To summarize, Jane's star has a red light and is traveling towards the earth while John's star star has a blue light and is traveling away from the earth. This is also a prime example of the Doppler Effect in motion. The stars look different because they are traveling in different directions.

How might a theory relate to a model

Answers

a theory can be represented as a model

A cylindrical tube 14.0 cm high and 2.5 cm in diameter is used to collect blood samples. how many cubic decimeters (dm3) of blood can it hold (v of a cylinder = r2h)?

Answers

A decimeter is one tenth of meter.

The formula to measure the volume of cylinder is V = h(r^2), where v = volume, r = radius, and h = height.

First, we plug those numbers into the formula. Remember that radius is one half of the diameter.

V = 14(2.5/2)^2

Simplify the problem.
V = 21.875

Now, let's convert this answer from centimeters to decimeters.
Since a decimeter is one tenth of a meter, we can divide the answer by ten.
= 21.875/10

Therefore, your answer is 2.1875dm3

A clothes dryer uses about 30 amps of current from a 240 volt line. How much power does it use?

Answers

not sure if this answer is write or wrong but i think its 4500 watts

Answer:

7,200 watts

Explanation:

% = Wo/Wi x 100 Solve for Wo
% = Wo/Wi x 100 Solve for Wi

Answers

1) % = (Wo /Wi) * 100

Solve for Wo => Wo = (% / 100) * Wi

For example, % =30% and Wi = 250 => Wo = (30 /100) * 250 = 0.30 * 250 = 75

Wo = 75

2) % = (Wo / Wi) * 100

Solve for Wi

=> Wi = Wo * (%/100)

For example, Wo = 125 and % = 40%

=> Wi = 125 * (40 / 100) = 125 * 0.40 = 50

Wi = 50

a person trying to throw a ball as far as possible will run forward during the throw. explain why this increases the distance of the throw

Answers

It increases the throw because you are putting more force and speed into the throw

The time of flight of an object is only limited by its vertical velocity, since gravity only works to pull an object down towards the earth.

What is velocity?

The terms speed and velocity  give us an idea of ​​how fast or slow an object is moving. We often come across situations where we need to identify which of  two or more objects is moving faster. The faster of them can be easily distinguished if they move in the same direction on the same road. However, if their direction of movement is opposite, it is difficult to determine the fastest. In such cases, the concept of speed is useful.

The horizontal velocity remains unchanged. So by running prior to throwing the ball, the person can impart and even faster initial horizontal velocity to the ball. So, although the ball still travels for the same amount of time through the air, it travels at a faster horizontal velocity and, therefore, travels a farther horizontal distance.

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Objects A and B are brought close to each other. Object A will soon become positively charged. Identify the charge that must transfer for this situation to occur.

Answers

The following situation occurs:

The two objects are brought close to each other (but they do not touch). Object B must be negatively charged: in this case, for induction, the positive charges on object A migrate towards the side of the object closer to object B, while the negative charges migrate to the other side. Then, object A must be connected to the ground, so that the negative charges migrate to the ground: therefore, an excess of positive charges remain on object A, which is now positively charged.

Answer:

a positive charge will transfer from object b

Explanation:

a positive charge will transfer from object b to object a making a positively charged

Have a good day = )

Fiora starts riding her bike at 20 mi/h. after a while, she slows down to 12 mi/h, and maintains that speed for the rest of the trip. the whole trip of 70 mi takes her 4.5 h. for what distance did she travel at 20 mi/h?

Answers

d = r*t

t = hours at 20 mi/hr


20t + 12*(4.5 - t) = 70
8t = 16
t = 2 hours

d at 20 mi/hr = 20*2 = 40 miles

40/20 + 30/12 = 4.5 hours

Fiora travels a total distance of 4.5 hours

Answer : Distance, d = 40 mi.

Explanation :

It is given that,

Fiora starts riding her bike at 20 mi/h. after a while, she slows down to 12 mi/h and maintains that speed for the rest of the trip. the whole trip of 70 mi takes her 4.5 h.

Let for t hours she traveled at 20 mi/h. So, for ( 4.5 - t) h she has traveled with a speed of 12 mi/h.

We know that,

distance covered = speed × time

20 mi/h × t +12 mi/h (4.5 h - t) = 70 mi

t = 2 h

So, the distance covered in 2 h is, d = 20 mi/h × 2 h = 40 mi.

Hence, this is the required solution.

A football player runs from his own goal line to the opposing team's goal line returning to the fifty yard line all i 18.0s calculate average speed and average velocity

Answers

assuming the pitch is 100yards long, the player runs 100yards to the other goal then a further 50 yards back to the 50-yard line. So he/she runs 150yards in 18s
150/18 = 8.33yards per second average speed.
Initial velocity = 0, average velocity =8.33
Vav = (Vinitial+Vfinal)/2
Vav = 4.16m/s

Answers:

Average speed = 8.33 yard/s

Average velocity = 2.78 yard/s

Explanation:

1) Definitions and equations:

i) Average speed = distance run / time elapsed

ii) Average velocity = displacement / time elapsed

iii) displacement = [final position - initial position]

2) Distance run:

i) Take a total length of 100 yards from goal to goal lines

ii) distance run = distance from goal to goal lines + back to yard 50 = 100 yards + 50 yards = 150 yards

3) Average speed = distance run / total time = 150 yards / 18.0s = 8.33 yard/s

4) Displacement:

final position - initial position = 50 yard - 0 yard = 50 yards

5) Average velocity = 50 yards / 18.0 s = 2.78 yards/s

For the circuit shown in the figure above, the correct procedure for measuring the resistance value of R1 is to

A. connect the multimeter between points D and A and measure the resistance with switch S1 open.
B. connect the multimeter between points C and D and measure the resistance with switch S1 open.
C. connect the multimeter between points C and D and measure the resistance with switch S1 closed.
D. connect the multimeter between points D and A and measure the resistance with switch S1 closed.

Answers

Choices A and D are the same procedure. It's not correct in either place. Choice-B is the correct one.

Answer:

B. connect the multimeter between points C and D and measure the resistance with switch S1 open.

Explanation:

multimeter is a device which is used to measure the resistance of wire across which it is connected.

Here we need to connect the two ends of the multimeter across the two ends of resistance and then it's reading is to be measured.

Here we need to take care that while measuring the resistance the circuit resistance current must not flow through it.

So here we need to make sure that switch S1 must be open while measuring the resistance

so correct answer will be

B. connect the multimeter between points C and D and measure the resistance with switch S1 open.

Of the four states of matter, which has particles that are the most tightly packed together?

Answers

Particles of solid are tightly packed, vibrating about a fixed position. Solids have definite shape and volume. Hope i helped.

Answer:

solid

Explanation:

common sense tehehe :)

Density is ____ per unit volume. length area space mass

Answers

Density is mass per unit volume.
The answer is mass! 

Hope I helped,
Ms.Weasley

High levels of cockpit noise in an aircraft can damage the hearing of pilots who are exposed to this hazard for many hours. cockpit noise in a jet aircraft is mostly due to airflow at hundreds of miles per hour. this 3 × 3 contingency table shows 61 observations of data collected by an airline pilot using a handheld sound meter in a certain aircraft cockpit. noise level is defined as “low” (under 88 decibels), “medium” (88 to 91 decibels), or “high” (92 decibels or more). there are three flight phases (climb, cruise, descent).

Answers

Final answer:

The question addresses the impact of intense cockpit noise on pilots and the importance of hearing protection, touching on noise levels during different flight phases and potential active noise reduction solutions.

Explanation:

The question provided by the student relates to the subject of Physics, specifically concerning the topic of sound intensity levels and the effects of noise exposure on human hearing. High levels of cockpit noise can have detrimental effects on pilots, as they are exposed to these intense noise levels for prolonged periods. It is mentioned that jet aircraft noise during climb, cruise, and descent can vary, with levels sometimes reaching well above the recommended guidelines for noise exposure. The importance of ear protection is highlighted, as prolonged exposure even at 85 decibels (dB) without hearing protection can lead to hearing damage. For instance, exposure to 100 dB noise, such as the take-off of a jet plane, can lead to noise-induced hearing loss. Active noise reduction techniques, including headphones that use destructive interference, can significantly lower noise levels by as much as 30 dB, providing a potential solution to protecting pilots' hearing.

A proton and an electron are separated by 6.5 Ã 10â10 m. (a) calculate the magnitude of the electric force that the proton exerts on the electron

Answers

Couloumb's law : (1/(4*pi*epsilon_nought))*((q_1*q_2)/r^2)

8.99*10^9* ((charge of a proton*charge of an electron)/(6.5*10^10m)^2)

8.99*10^9* ((1.602*10^-19)(|-1.602*10^-19|)/((6.5*10^10)^2)

=5.4608*10^-50

We have that the magnitude of the electric force that the proton exerts on the electron

[tex]F=5.45*10^{-10}N[/tex]

From the question we are told that

proton and an electron are separated by 6.5 Ã 10â10 m

Generally the equation for the Force  is mathematically given as

[tex]F=\frac{kq_1q_2}{r^2}\\\\F=\frac{9*10^{9}*(1.6*10^{-19})^2}{(6.5*10^{-10})^2}[/tex]

[tex]F=5.45*10^{-10}N[/tex]

Therefore

the magnitude of the electric force that the proton exerts on the electron

[tex]F=5.45*10^{-10}N[/tex]

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A stone is thrown upward from ground level. The initial speed is 128 feet per second. How high will it go?

Answers

Final answer:

The stone, thrown upward with an initial speed of 128 feet per second, will reach a maximum height of 256 feet before gravity causes it to fall back to the ground.

Explanation:

In the given problem, the stone is thrown upward from the ground with an initial speed of 128 feet per second. We can use the equations of motion to determine how high the stone will go. The height, h, reached by the stone can be calculated using the formula h = (v^2) / (2g), where v is the initial velocity and g is the acceleration due to gravity which is approximately 32.2 feet per second per second in standard units. Subbing in the values, h = (128^2) / (2*32.2) = 256 feet.

Therefore, the stone will reach a maximum height of 256 feet. This is the maximum height the stone reaches before it starts falling back to the ground due to gravity.

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The stone will reach a maximum height of 256 feet.

A stone is thrown upward from ground level with an initial speed of 128 feet per second. To determine how high it will go, we can use the kinematic equation:

v² = u² + 2as

where:

v is the final velocity (0 ft/s at the highest point)

u is the initial velocity (128 ft/s)

a is the acceleration (-32 ft/s² due to gravity)

s is the displacement (height)

Rearranging the equation to solve for s:

0 = (128)² + 2(-32)s

0 = 16384 - 64s

64s = 16384

s = 256 feet

Therefore, the stone will reach a maximum height of 256 feet.

How many kilograms are there in a 2.00 L bottle of drinking water?

Answers

there are 2 kilograms of water in 2 liters of water. if you convert the amount of water to kilograms it equals 2

you did not write your question right... wdym??

John and mary are skating at an ice rink. john skates at a constant speed of 6.7 m/s, with respect to the ice surface, directly south. mary skates at a constant speed of 10.9 m/s in a direction of 28° west of south, with respect to the ice. what are the magnitude and direction of mary's velocity with respect to john? give the direction as measured relative to due south.

Answers

John and mary are skating at an ice rink. john skates at a constant speed of 6.7 m/s, with respect to the ice surface, directly south, Mary's velocity with respect to John is approximately 10.06 m/s at an angle of 102.04° south of due south.

We may use vector addition to determine the size and direction of Mary's velocity relative to John.

While John's velocity is solely in the south, Mary's velocity can be depicted as a vector moving in the south-west.

Let's break down Mary's velocity into its south and west components:

- Mary's southward velocity component [tex](\(v_{\text{south}}\)) = \(10.9 \, \text{m/s} \cdot \sin(28^\circ)\)[/tex]

- Mary's westward velocity component [tex](\(v_{\text{west}}\)) = \(10.9 \, \text{m/s} \cdot \cos(28^\circ)\)[/tex]

Now, to find Mary's velocity with respect to John, we subtract the components of John's velocity:

- Mary's velocity with respect to John [tex](\(v_{\text{MJ}}\)) = \((v_{\text{south}} - v_{\text{J}}) \hat{i} + v_{\text{west}} \hat{j}\)[/tex],

where [tex]\(v_{\text{J}} = 6.7 \, \text{m/s}\)[/tex] is John's velocity.

Calculate the components and magnitude of Mary's velocity with respect to John:

[tex]\(v_{\text{MJ}} = (10.9 \, \text{m/s} \cdot \sin(28^\circ) - 6.7 \, \text{m/s}) \hat{i} + 10.9 \, \text{m/s} \cdot \cos(28^\circ) \hat{j}\)[/tex]

[tex]\(v_{\text{MJ}} \approx -2.18 \, \text{m/s} \hat{i} + 9.76 \, \text{m/s} \hat{j}\)[/tex]

Magnitude of [tex]\(v_{\text{MJ}}\) = \(\sqrt{(-2.18 \, \text{m/s})^2 + (9.76 \, \text{m/s})^2}\)[/tex]

Magnitude of [tex]\(v_{\text{MJ}} \approx 10.06 \, \text{m/s}\)[/tex].

Now, to find the direction of Mary's velocity with respect to John [tex](\(\theta\)):[/tex]

[tex]\(\theta = \arctan\left(\frac{v_{\text{MJ,y}}}{v_{\text{MJ,x}}}\right)\),[/tex]

Calculate the direction angle:

[tex]\(\theta \approx \arctan\left(\dfrac{9.76 \, \text{m/s}}{-2.18 \, \text{m/s}}\right)\)[/tex]

[tex]\(\theta \approx -77.96^\circ\).[/tex]

Thus, since the direction is measured relative to due south, the direction of Mary's velocity with respect to John is approximately [tex]\(180^\circ - 77.96^\circ = 102.04^\circ\)[/tex] south of due south.

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Final answer:

Mary's velocity with respect to John is 5.56 m/s at 33° west of south.

Explanation:

To find Mary's velocity with respect to John, we need to find the vector difference between Mary's velocity and John's velocity. We can break Mary's velocity into its north and east components, where the north component is 10.9cos(28°) and the east component is 10.9sin(28°). John's velocity is directly south, so his velocity has no east component and his south component is 6.7 m/s.

The north component of Mary's velocity relative to John is 10.9cos(28°) - 6.7 = 4.81 m/s, and the south component is 10.9sin(28°) so the magnitude of her velocity with respect to John is √((4.81)² + (10.9sin(28°))²) ≈ 11.60 m/s.

The angle can be found using tan⁻¹((10.9sin(28°))/(4.81)) ≈ 32.75°. So, the direction of Mary's velocity with respect to John is 180° - 32.75° ≈ 147.25° west of south, which can be rounded to 33° west of south.

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