Which of the following tasks should be performed before measuring the mass of any object on a triple-beam balance? A. Make sure that all the counterweights are set to zero. B. Make sure that the balance is on a level surface. C. Make sure that the balance pan is clean and free of debris. D. all of these
its all of these trust me
In process in which An animal's cells use oxygen and digested food molecules to release the energy in food is called
How does most of the water in the water cycle move from lakes and rivers directly back into the atmosphere?
there are 28L of soup in a pot. Marshall serves 400mL in each bowl. If he fills 16 bowls how much soup is left in the pot? in liters
The mineral halite has __________ bonds which form a cubic crystal lattice
The name of the compound whose formula is aucl3 is
Manganese(iv) oxide reacts with aluminum to form elemental manganese and aluminum oxide: 3mno2+4al→3mn+2al2o3part awhat mass of al is required to completely react with 30.0 g mno2?
To completely react with 30.0 g of MnO2, 107.92 g of aluminum is required.
Explanation:To determine the mass of aluminum required to completely react with 30.0 g of MnO2, we need to use the balanced chemical equation and the molar mass of MnO2. In the balanced equation, the coefficient of MnO2 is 3, which means that 3 moles of MnO2 react with 4 moles of Al.
First, calculate the molar mass of MnO2:
Molar mass of Mn = 54.94 g/molMolar mass of O = 16.00 g/molMolar mass of MnO2 = (54.94 g/mol) + 2(16.00 g/mol) = 86.94 g/molNext, convert 30.0 g of MnO2 to moles:
Moles of MnO2 = Mass of MnO2 / Molar mass of MnO2 = 30.0 g / 86.94 g/mol = 0.344 molesUsing the mole ratio from the balanced equation, we can calculate the moles of Al required:
Moles of Al = (3/3) x 4 moles of Al = 4 moles of AlFinally, convert moles of Al to mass:
Mass of Al = Moles of Al x Molar mass of Al = 4 moles x 26.98 g/mol = 107.92 gThe mass of aluminum required to completely react with 30.0 g of MnO2 is 107.92 g.
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To completely react with 30.0 g of MnO2, 12.4 g of Al is required.
Explanation:To determine the mass of aluminum required to completely react with 30.0 g of MnO2, we need to use the balanced equation for the reaction:
3MnO2 + 4Al -> 3Mn + 2Al2O3
From the equation, we can see that the mole ratio of MnO2 to Al is 3:4. We can use this ratio to calculate the mass of Al.
First, convert the mass of MnO2 to moles using its molar mass. Then, use the mole ratio to find the moles of Al. Finally, convert the moles of Al back to mass using its molar mass.
Let's calculate:
Convert the mass of MnO2 to moles: (30.0 g MnO2) / (86.94 g/mol MnO2) = 0.345 mol MnO2Using the mole ratio, calculate the moles of Al: 0.345 mol MnO2 * (4 mol Al / 3 mol MnO2) = 0.460 mol AlConvert the moles of Al to mass: 0.460 mol Al * (26.98 g/mol Al) = 12.4 g AlTherefore, 12.4 grams of Al are required to completely react with 30.0 grams of MnO2.
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2.5 million atoms of a particular element have a mass of 8.33 x 10-16 grams. what is this element
To determine the element, the mass in grams is converted to atomic mass units using the known mass of an atomic mass unit. The calculated atomic mass matches the approximate atomic masses of elements like Neon or Calcium. However, a precise identification may require isotopic composition.
The student is asking about the identity of an element based on a given mass and number of atoms. To find the answer, we use the concept of atomic mass units (u) and Avogadro's number. The mass of a single atomic mass unit is 1.661 × 10-24 grams. With 2.5 million atoms having a mass of 8.33 × 10-16 grams, we can calculate the average atomic mass of an individual atom.
First, we divide the total mass by the number of atoms:
8.33 × 10-16 g / 2.5 million atoms = 3.332 × 10-22 g/atom.
Next, we convert this mass into atomic mass units by dividing by the mass of one atomic mass unit:
3.332 × 10-22 g/atom / 1.661 × 10-24 g/u = 20.04 u/atom.
This calculated value can be compared to the atomic mass or atomic weight of elements listed in the periodic table to identify the element. The mass is approximately 20 u, which suggests the element could be Neon (Ne) with an atomic mass of approximately 20.18 u or Calcium (Ca) with an atomic mass of 40.08 u considering the natural abundance of isotopes. For a more precise identification, additional information such as isotopic composition would be needed.
Part b an element belongs to group 9. what common name might be used to describe the group to which this element belongs?
Group 9 of the Periodic Table does not have a widely recognized common name but is part of the broader category known as transition elements or transition metals.
An element that belongs to Group 9 is part of the transition metals on the Periodic Table. Unfortunately, there isn't a widely used common name for Group 9 specifically, unlike other groups with well-known common names such as the alkali metals for Group 1 or the halogens for Group 17. However, elements in Group 9 are part of the larger family known as the transition elements, which share similar properties such as conducting electricity and heat, possessing a high density, and having a high melting and boiling points.
Calculate and compare the [h+] and ph for a 0.100 m solution of hclo4 and a 0.100 m solution of hclo (ka = 2.9 × 10–8).
HClO₄ has a higher [H⁺] than HClO (0.100 M vs. 5.4 × 10⁻⁵ M).
HClO₄ has a lower pH than HClO (1.00 vs. 4.3).
Classification of acids according to their strengthWeak acids: dissociate partially in water.Strong acids: dissociate completely in water.HClO₄ is a strong acid. Thus, of HClO₄ is 0.100 M, H⁺ will be 0.100 M as well. We can use this value to calculate the pH for this acid.
pH = -log [H⁺] = -log 0.100 = 1.00
HClO is a weak acid. Thus, [H⁺] ≠ [HClO]. Given the acid dissociation constant (Ka) and the concentration of the acid (Ca), we can calculate [H⁺] and pH using the following expressions.
[tex][H^{+} ] = \sqrt{Ca \times Ka } = \sqrt{0.100 \times (2.9 \times 10^{-8} ) } = 5.4 \times 10^{-5} \\\\pH = -log 5.4 \times 10^{-5} = 4.3[/tex]
HClO₄ has a higher [H⁺] than HClO (0.100 M vs. 5.4 × 10⁻⁵ M).
HClO₄ has a lower pH than HClO (1.00 vs. 4.3).
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Calculate the ph for a 0.3 m solution of (a) sodium leucinate
draw a transition state for the reaction between ethyl iodide and sodium acetate
The reaction between ethyl iodide and sodium acetate is a substitution reaction, likely involving an SN2 (nucleophilic substitution bimolecular) mechanism.
In the transition state for an SN2 reaction, the nucleophile (acetate ion) is attacking the substrate (ethyl iodide) from the backside, leading to inversion of configuration. The reaction between ethyl iodide and sodium acetate is a substitution reaction, with an SN2 (nucleophilic substitution bimolecular) mechanism most likely at work.
In the transition state:
The leaving group (iodide in this case) is partially leaving.
The nucleophile (acetate ion) is partially bonded to the carbon, approaching from the backside.
The carbon undergoing substitution is in a tetrahedral arrangement with the nucleophile, the leaving group, and two other substituents.
When a hammer strikes a compound formed by covalent bonds, what will most likely happen to the compound?
It will break into many pieces
It will reform into a new shape
It will spread out and then return to it's original shape
It will stay solid and resist the force of the hammer
Answer: Option (a) is the correct answer.
Explanation:
A compound formed by sharing of electrons is known as a covalent compound.
A covalent compound has weak intermolecular forces due to which it is brittle in nature. Hence, when we hit hammer on a covalent compound then it breaks easily.
Thus, we can conclude that when a hammer strikes a compound formed by covalent bonds, then most likely it will break into many pieces.
Answer:
option A.
Explanation:
have a good day.
:)
Will bromine react with sodium? Explain your answer.
Dinosaur fossils are often dated by using an element other than carbon, like potassium-40, that has a longer half life (in this case, approximately 1.25 billion years). suppose the minimum detectable amount is 0.1% and a dinosaur is dated with 40k to be 67 million years old. is this possible?
How many grams of caf2 would be needed to produce 1.29 moles of f2?
Answer is: 100.72 grams of calcium fluoride.
Balanced chemical reactions:
1) CaF₂ + H₂SO₄ → 2HF + CaSO₄.
2) 2HF → F₂ + H₂.
1) From chemical reaction 2: n(F₂) : n(HF) = 1 : 2.
n(HF) = 2 · 1.29 mol.
n(HF) = 2.58 mol.
2) From chemical reaction 1: n(HF) : n(CaF₂) = 2 : 1.
n(CaF₂) = 2.58 mol ÷ 2.
n(CaF₂) = 1.29 mol; amount of substance.
m(CaF₂) = n(CaF₂) · M(CaF₂).
m(CaF₂) = 1.29 mol · 78.08 g/mol.
m(CaF₂) = 100.72 g.
Using enthalpies of formation, calculate the quantity of heat produced when 14.0 g of propane is completely combusted in air under standard conditions. Assume that liquid water is forming
The balanced chemical reaction here is:
C3H8(g) + 5O2(g) --> 3CO2(g) + 4H2O(l)
Calculating for the molar change in enthalpy:
Enthalpy change = 3(-393.5) + 4(-285.83) - (-103.85) = -2220.0 kJ/mole
Now, propane has a molar mass of 44g/mol. So, for
us to calculate the heat released by burning 14 grams of propane, we have:
-2220 kJ/mole * ( 14g / 44g/mol) = -706.36 kJ
Answer:
-706.36 kJ
(negative means heat is released)
A student determines the acetic acid concentration of a sample of distilled vinegar by titration of 25.00 ml of the vinegar with standardized sodium hydroxide solution using phenolphthalein as an indicator. which error will give an acetic acid content for the vinegar that is too low
Adding a too small volume of sodium hydroxide solution during titration will give an acetic acid content for the vinegar that is too low.
Explanation:The error that will give an acetic acid content for the vinegar that is too low is adding a too small volume of sodium hydroxide solution during titration. In this case, the student titrated 25.00 ml of the vinegar, and if the volume of sodium hydroxide solution added is insufficient, it will not neutralize all the acetic acid present in the vinegar. This will result in a lower calculated concentration of acetic acid in the vinegar.
Draw the lewis dot structure for se2−. to change the symbol of an atom, double-click on the atom and enter the letter of the new atom. show the formal charge of the atom
To begin with the Lewis dot structure,
Se possesses six valence electrons, resulting in a Lewis structure with six dots.Now, Se 2- denotes that the Se atom has two additional electrons, completing the octet rule (eight electrons in the outer shell).Make a huge square bracket around that structure and write 2- as a superscript in the upper right corner.[tex]**\\ **Se^{2-} **\\ **[/tex]
Thus, the structure has 8 electrons represented by *.
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Name two elements in which the last electrons to be added are placed into s subshells
The statement "matter can be neither created nor destroyed by chemical means, but it can be changed from one form to another" is the chemical law of
It the chemical law of conservation of matter
Calculate the frequency of the n = 6 line in the Lyman series of hydrogen.
The frequency of the n = 6 line in the Lyman series of hydrogen is [tex]\boxed{{\mathbf{3}}{\mathbf{.196 \times 10 }}{{\mathbf{s}}^{{\mathbf{ - 1}}}}}[/tex].
Further Explanation:
The given problem is based on the concept of the emission spectrum of a hydrogen atom.
Lyman series:
When an electron undergoes transition from any higher energy orbit [tex]\left({{{\text{n}}_{\text{f}}}=2,{\text{ }}3,{\text{ }}4,...}\right)[/tex] to first energy orbit [tex]\left({{{\text{n}}_{\text{i}}} = 1}\right)[/tex] then it emits the energy to complete the process. This spectral lines formed due to this emission is known as the Lyman series of hydrogen atom.
The formula to calculate the energy of transition in the hydrogen atom is,
[tex]\Delta E={R_{\text{H}}}\left({\frac{1}{{{{\left({{{\text{n}}_{\text{i}}}}\right)}^2}}}-\frac{1}{{{{\left({{{\text{n}}_{\text{f}}}}\right)}^2}}}}\right)[/tex]
Where,
[tex]\Delta E[/tex] is the energy difference between two energy levels.
[tex]{R_{\text{H}}}[/tex] is a Rydberg constant and its value is [tex]2.179 \times {10^{ - 18}}{\text{ J}}[/tex].
[tex]{{\text{n}}_{\text{i}}}[/tex] is the initial energy level of transition.
[tex]{{\text{n}}_{\text{f}}}[/tex] is the final energy level of transition.
Substitute the 1 for [tex]{{\text{n}}_{\text{i}}}[/tex] , 6 for [tex]{{\text{n}}_{\text{f}}}[/tex] and [tex]2.179\times {10^{ - 18}}{\text{ J}}[/tex] for [tex]{{\text{R}}_{\text{H}}}[/tex] in the above formula to calculate the value of energy of the given transition.
[tex]\begin{aligned}\Delta E &={R_{\text{H}}}\left({\frac{1}{{{{\left( {{{\text{n}}_{\text{i}}}}\right)}^2}}} \frac{1}{{{{\left({{{\text{n}}_{\text{f}}}}\right)}^2}}}}\right)\\&=\left({2.179 \times {{10}^{ - 18}}{\text{ J}}} \right)\left({\frac{1}{{{{\left( {\text{1}}\right)}^2}}}-\frac{1}{{{{\left({\text{6}} \right)}^2}}}}\right)\\&={\mathbf{2}}{\mathbf{.118 \times 1}}{{\mathbf{0}}^{{\mathbf{ - 18}}}}{\mathbf{ J}}\\\end{aligned}[/tex]
Now we can calculate the frequency of the given transition by using the following formula.
[tex]\Delta E = hv[/tex]
Where,
[tex]\Delta E[/tex] is the energy difference between two energy levels.
[tex]h[/tex] is a Plank’s constant and its value is [tex]6.626\times {10^{ - 34}}{\text{ Js}}[/tex].
v is a frequency of the transition.
Rearrange the above formula to calculate the frequency of the given transition and substitute the value of [tex]\Delta E[/tex].
[tex]\begin{aligned}\Delta E&=hv\hfill\\v&=\frac{{\Delta E}}{h}\hfill\\&=\frac{{{\text{2}}{\text{.118}} \times {\text{1}}{{\text{0}}^{ - {\text{18}}}}{\text{ J}}}}{{6.626 \times {{10}^{ - 34}}{\text{ Js}}}} \hfill\\&={\mathbf{3}}{\mathbf{.196 \times 10 }}{{\mathbf{s}}^{{\mathbf{ - 1}}}} \hfill \\\end{aligned}[/tex]
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Answer details:
Grade: Senior School
Subject: Chemistry
Chapter: Structure of atom
Keywords: Lyman series of hydrogen, hydrogen, n=6 transition, emission spectra, Plank’s constant, transition, energy orbits.
PLEASE HELP, 30 POINTS!
Suppose 1 kg each of water (4.19 J/g⋅∘C), brick (0.90 J/g⋅∘C), iron (0.46 J/g⋅∘C), and plastic (1.01 J/g⋅∘C) were held at the same initial temperature and heated for an equivalent amount of time. Indicate the relative final temperatures by ordering from lowest to highest resulting temperature (if using the Intro tab of the PhET to help visualize the temperature changes, assume the water iron, and plastic are 1 kg in mass, and the brick has a mass of 0.5 kg). Assume no heat is lost to the surroundings.
Rank from lowest resulting temperature to highest resulting temperature. To rank items as equivalent, ove
Scenario 1:
Mass of each of water, brick, iron, and plastic = 1 kg = 1000 g
Specific heat of water = 4.19 J/g⋅∘C
To raise the temperature of 1 g of water by 1∘C the heat required is 4.19 J
Therefore, to raise the temperature of 1000 g of water by 1∘C the heat required is 4.19 x 1000 = 4190 J
Specific heat of brick = 0.90 J/g⋅∘C
To raise the temperature of 1 g of brick by 1∘C the heat required is 0.9J
Therefore, to raise the temperature of 1000 g of brick by 1∘C the heat required is 0.90 x 1000 = 900 J
Specific heat of iron = 0.46 J/g⋅∘C
To raise the temperature of 1 g of iron by 1∘C the heat required is 0.46 J
Therefore, to raise the temperature of 1000 g of iron by 1∘C the heat required is 0.46 x 1000 = 460 J
Specific heat of plastic = 1.01 J/g⋅∘C
To raise the temperature of 1 g of plastic by 1∘C the heat required is 1.01 J
Therefore, to raise the temperature of 1000 g of plastic by 1∘C the heat required is 1.01 x 1000 = 1010 J
So it takes the greatest amount of heat in Joules to raise the temperature of water, followed by plastic, followed by brick and iron.
Now all of them are heated for an equivalent amount of time as a result water will have the lowest resulting or final temperature. The resulting or final temperature of plastic will be greater than water. The resulting or final temperature of brick will be greater than plastic. . The resulting or final temperature of iron will be greater than brick.
Water plastic brick iron
(lowest resulting temperature) --> (highest resulting temperature)
What maximum amount of ammonia in kilograms can be synthesized from 5.22 kg of h2 and 31.5 kg of n2? express your answer in kilograms to one decimal place?
Which unit abbreviation is a measurement of force?
m/s
m/s2
N
N/s
Answer:
Newton is the unit of force, abbreviated as "N"
Explanation:
Let us understand the given units:
a) m/s: it is meter per second. It is SI unit of speed or velocity.
b) m/s: it is meter per second square. It is SI unit of acceleration (velocity per second).
c) N : it is unit of force. It stands for Newton.It is equal to 1 kilogram meter per second squared.
d) N/s: it is newton per second. It is unit of momentum.
How many moles of oxygen are required to produce 37.15 g CO2?
How many liters of water are required to dissolve 1.00 g of barium chromate? express your answer in liters to three significant figures?
The solubility Barium chromate in grams per liter = 2.78 . 10⁻³ grams/L
359 liters of water are required to dissolve 1.00 g of Barium chromate
Further explanationSolubility is the maximum amount of a substance that can dissolve in some solvents. Factors that affect solubility
1. Temperature: 2. Surface area: 3. Solvent type: 4. Stirring process:Ksp is an ion product in equilibrium
Solubility relationships and solubility constants (Ksp) of the AxBa solution can be stated as follows.
AₓBₐ (s) ← ⎯⎯⎯⎯ → x Aᵃ⁺ (aq) + a Bˣ⁻ (aq)
s xs as
Ksp = [Aᵃ⁺] ˣ [Bˣ⁻] ᵃ
Ksp = (xs) ˣ (as) ᵃ
Solubility units in the form of mol / liter or gram / liter
At 25.°C, the molar solubility of Barium chromate BaCrO₄ in water is 1.10. 10⁻⁵M.
to change units to grams / liter, we multiply by molar mass:
M BaCrO₄ = Ba + Cr + 4. Ar O
M BaCrO₄ = 137 + 52 + 4.16
M BaCrO₄ = 253
So the solubility is in grams / liter
= 1.10 . 10⁻⁵ mol / liter x 253 grams / mol
= 278.3 .10⁻⁵ = 2.78 . 10⁻³ grams/L
(3 significant numbers, 2.7 and 8)
If we dissolve 1 gram of Barium chromate into the solution, we need water :
= 1 grams / 2.78 . 10⁻³ grams / liter
= 359 liters
(3 significant numbers, 3.5 and 9)
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In comparison to molecules that interact by London dispersion forces only, the melting point of similar-sized molecules forming hydrogen bonds would most likely be
about the same.
unpredictable.
lower.
higher.
A 108 49in source emits a 633-kev gamma photon and a 606-kev internal-conversion electron from the k shell. what is the binding energy of the electron in the k shell?
Heating oxygen difluoride gas yields oxygen gas and fluorine gas? Whats the balance chemical equation for this?
Heating oxygen difluoride gas yields oxygen gas and fluorine gas
2OF2(g) —> O2(g) + 2F2(g)
what are the properties of oxygen ?Oxygen atom belongs to group of chalcogen represented in the periodic table which is one of the abundant and essential element and participate in combustion reaction abundantly found in the Earth’s crust.
oxygen is colorless, odorless whereas liquid oxygen is paramagnetic, forms oxides with element except helium, neon, krypton, and argon.
Dioxygen form of oxygen is allotropic where as Trioxygen is the most reactive allotrope of oxygen which can damage to lung tissue and it is called as ozone.
These oxygen are used in the production and manufacturing of glass and stone products, it also be used in the process of melting, refining, and manufacturing of steel along with other metals.
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