An airplane flies with a constant speed of 840 km/hr. How far will go in 270 min

Answers

Answer 1
It would be 3780 km... hope this helps and have a great day<3 !!!!

Related Questions

Which is a major area of study in psychology?mentalism totalculturalism behaviorism actionism

Answers

Before the first behaviorist (Watson), Psychology was a part of philosophy.

Answer: behaviorism

Explanation:

The psychology can be define as the scientific study of the function of the mind and the behavior associated with it. The wide discipline of psychology deals with the study of the human development, health, sports, clinical , cognitive and social behavior.

The major area of study in psychology is the behaviorism. It is a systematic approach which is used to understand the behavior of the human beings. The behavior is the response to various stimuli of the environment. The behavior is associated with the reinforcement and punishment.

Top-down processing is often used when one encounters an unfamiliar stimulus. Please select the best answer from the choices provided T F

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The answer for this question would be B) False or the second option because top-down processing is NOT often used when one encounters an unfamiliar stimulus.

Answer: The given statement is False.

Top down processing is based on the information that is already present in the mind. It occurs when an individual works from general concepts ( that are imprinted in the brain) to specific.

This means that impressions that are already present in the brain influences the information that is gathered with the help of five senses. Thus, top down processing is not used when an individual encounters an unfamiliar stimulus.

A train is slowing down with an average acceleration of −5.0 m/s2 (negative sign shows deceleration). If its initial velocity is 50. m/s, how far does it travel in 6.0 seconds?

Answers

This problem requires 2 kinematics equations. What you first must do is find the Final Velocity with the given values... Vf = Vi + at ... which is Vf = 50 + (-5)(6) which would simplify to Vf = 30. Then you can plug this value along with the given values into the kinematics equation Vf^2=Vi^2 + 2ax. Plugged in this would be 30^2=50^2 + 2 (-5)x. This can then be simplified to find x (distance). Which would be x=160. This means that the train traveled 160m.

Answer:

the train travels 210 m

Explanation:

Kinematics equations of motion

[tex]vf=vi+a*t[/tex],   equation(1)

[tex]vf^{2} =vi^{2} +2*a*d[/tex] equation(2)

Vi= initial velocity (m/s)

Vf= final velocity (m/s)

a = acceleration [tex]m/s^{2}[/tex]

d= traveling distance (m)

known information:

vi=50m/s

a=-5[tex]m/s^{2}[/tex]

t=6 s

Calculation of the final speed replacing the information known in the equation 1

[tex]vf=50-5*6[/tex]

[tex]vf=50-30=20m/s[/tex]

Calculation of the distance replacing the information known  and the final velocity in the equation 2

[tex]20^{2} =50^{2} -2*5*d\\400= 2500-10d\\10d=2500-400\\d=2100/d\\d=210m[/tex]

25 points!
A boy with a mass 50 kg walks up the stairs from the ground to the top of a spiral water slide in 1 minute. The height of the slide is 11.5 m above the ground. As the boy slides down the slide and reaches the bottom, his speed is 12 m/s and the distance traveled along the slide is 108 m.

Find the mechanical energy lost by the boy in sliding down the slide.
What is the average frictional force acting on the boy?

Answers

Refer to the diagram shown below.

At A, the boy begins walking up the stairs.

At B, the boy is at the top of the slide. He has acquired PE (potential energy).
The value of the PE is
(50 kg)*(9.8 m/s²)*(11.5 m) = 5635 J

At C, the boy has KE (kinetic energy).
The value of the KE is
(1/2)*(50 kg)*(12 m/s)² = 3600 J

Energy is lost between B and C due to friction.
The lost energy is
5635 - 3600 = 2035 J

The distance traveled along the slide is 108 m.
If F =  the average frictional force, then
(F N)*(108 m) = 2035 J
F = 18.84 N

Answers:
(a) The mechanical energy lost by sliding is 2035 J.
(b) The average frictional force is 18.84 N

The sun lives in which component of the milky way?

Answers

The sun lives in which component of the milky way? the answer is the disk 

i hope this helps 


Compare and contrast rutherford's "planetary model" of the atom with our current understanding of an atom's internal structure.

Answers

Rutherford felt that the atom had an internal structure much like our solar system, with a nucleus surrounded by orbiting electrons. Today, we know that the electrons inhabit specific shells and sub-shells, and there is an order to which these electrons are located.

Rutherford's model revolutionized atomic theory by proposing a nucleated structure. Our current understanding, based on quantum mechanics, offers a more accurate and probabilistic description of the atom's internal structure.

Rutherford's model, proposed in 1911, was a significant departure from the earlier plum pudding model. It postulated a positively charged nucleus at the center of the atom, with negatively charged electrons orbiting around it in a manner similar to planets orbiting the sun.

However, our current understanding of the atom, based on quantum mechanics, is much more complex:

1. Electron Orbitals: Instead of well-defined orbits, electrons are found within orbitals, which are regions of space around the nucleus where the probability of finding an electron is high. These orbitals are defined by quantum numbers and have various shapes (s, p, d, f, etc.).

2. Quantization: Electrons can only occupy certain energy levels, and the energy of an electron in an atom is quantized. This is in contrast to the planetary model, where electrons could theoretically occupy any orbit at any distance from the nucleus.

3. Nuclear Structure: The nucleus itself is composed of protons and neutrons, which are further made up of quarks. Rutherford's model did not delve into the substructure of the nucleus.

4. Electron Spin and the Pauli Exclusion Principle: Electrons have an intrinsic property called spin, and the Pauli Exclusion Principle states that no two electrons in an atom can have the same set of quantum numbers.

A 0.50 kilogram frog is at rest on the bank surrounding a pond of water. As the frog leaps from the bank, the magnitude of the acceleration of the frog is 3.0 meters per second^2. Calculate The magnitude of the net force exerted on the frog as it leaps.

Answers

F = ma
F = (0.5 kg)(3 m/s^2)
F = 1.5 N

The magnitude of net force exerted on the frog is of 1.5 N.

Given data:

The mass of frog is, m = 0.50 kg.

The magnitude of acceleration of frog is, [tex]a = 3.0 \;\rm m/s^{2}[/tex].

As per the concept of Newton's Second law, the force applied on any object is equal to the product of mass and acceleration of an object. Then the expression is given as,

[tex]F=m \times a[/tex]

Solving as,

[tex]F = 0.50 \times 3.0\\\\F=1.5 \;\rm N[/tex]

Thus, we can conclude that the magnitude of net force exerted on the frog is of 1.5 N.

Learn more about the Newton's second law here:

https://brainly.com/question/19860811

Wo particles are separated by a certain distance. the force of gravitational interaction between them is f0. now the separation between the particles is tripled. find the new force of gravitational interaction f1.

Answers

The gravitational force is inversely proportional to the square of the separation distance.

f1. =. 1/9 of f0.

When did galileo discover projectile motion?

Answers

Between 1589-1592 when he discovered projecctile motion

A rocket initially at rest on the ground lifts off vertically with a constant acceleration of 2.0 Ã 101 meters per second2 . how long will it take the rocket to reach an altitude of 9.0 Ã 103 meters?

Answers

Answer:

Time taken, t = 30 seconds

Explanation:

It is given that,

Initial speed of the rocket, u = 0

It is lifted with a constant acceleration of, [tex]a=2\times 10^1\ m/s^2=20\ m/s^2[/tex]

Height to be attained, [tex]d=9\times 10^3\ m[/tex]

Let t is the time taken by the rocket to reach an altitude of [tex]9\times 10^3\ m[/tex]. Using the second equation of kinematics to find it as :

[tex]d=ut+\dfrac{1}{2}at^2[/tex]

[tex]d=\dfrac{1}{2}at^2[/tex]

[tex]t=\sqrt{\dfrac{2d}{a}}[/tex]

[tex]t=\sqrt{\dfrac{2\times 9\times 10^3}{20}}[/tex]

t = 30 seconds

So, the time taken by the rocket to reach given height is 30 seconds. Hence, this is the required solution.

The train speeds passed Holly at 70 km/h north ward. This spider crawls past lukes foot in the same direction at 30 m/h. What is the velocity of the spider relative to Holly?

Answers

It has 178200000 ms^-1 and the train has 25200000ms^-1.

In the pulley system shown below, a 360 N weight is slowly lifted. Assuming the system is 100% efficient and each pulley is weightless, what is the minimum input force needed to lift the weight? Rope Pile L= 16.74m

A. 61 N
B. 121 N
C. 181 N
D. 361 N

Answers

your answer is D. 361 N

Answer:

A. 61 N

Explanation:

In this system, there are three moveable pulleys. In this case, the rope will have to move six times as far as the weight will rise. In other words, the input distance is 6 times the output distance  ( d in =6⋅ d out ) . Because the efficiency is 100%, the work input is equal to the work output, so we have:

work input  = work output

f( in)  ⋅  d( in) =   f( out)  ⋅  d( out)

 f( in)  ⋅ (6 ⋅  d( out))  =  f( out)  ⋅  d( out)

 f( in)  ⋅ 6 =  f( out)

  f( in)  ⋅ 6 = 360 N

  f( in)  = 60 N  

Another way to think of this is that since the rope has to move 6 times as far as the height of the weight, the mechanical advantage will be 6. Therefore, the input force needed is  360 ÷ 6 = 60 N . Of course, 60 N will balance the object, so a force slightly greater than 60 N (like 61 N) will be required to lift it.

In an old-fashioned amusement park ride, passengers stand inside a 3.0-m-tall, 5.0-m-diameter hollow steel cylinder with their backs against the wall. the cylinder begins to rotate about a vertical axis. then the floor on which the passengers are standing suddenly drops away! if all goes well, the passengers will "stick" to the wall and not slide. clothing has a static coefficient of friction against steel in the range 0.60 to 1.0 and a kinetic coefficient in the range 0.40 to 0.70. what is the minimum rotational frequency, in rpm, for which the ride is safe?

Answers

Final answer:

The minimum rotational frequency needed for the amusement park ride to be safe is between 0.165 and 0.215 revolutions per minute. This is calculated based on the coefficient of static friction between the riders' clothing and the wall, and the radius of the cylinder.

Explanation:

In order for the riders to not slide down the wall of the amusement park ride, the centripetal force must be greater than or equal to the force of static friction between the riders' clothing and the wall. The centripetal force is given by the formula:

Fc = (mv^2) / r

where m is the mass of the rider, v is the linear speed, and r is the radius of the cylinder. The force of static friction is given by:

fs = μsN

where μs is the coefficient of static friction and N is the normal force.

At the minimum rotational frequency, the riders will experience the maximum static friction force:

fs(max) = μsN

Substituting the values and equations, we get:

(mv^2) / r = μsN

Since the normal force N is equal to the weight of the riders, we have:

(mv^2) / r = μs(mg)

Canceling out the mass on both sides and solving for v, we get:

v = √(μsgr)

The minimum rotational frequency is the linear speed v divided by the circumference of the cylinder:

f(min) = v / (2πr)

Substituting the value of v, we have:

f(min) = √(μsg / (2π))

Using the given range for the coefficient of static friction, the minimum rotational frequency is between 0.165 and 0.215 revolutions per minute.

A copper ball and an aluminum ball of mass 150 g each are heated to 100°C and then cooled to a temperature of 20°C. The heat lost by the copper ball is 4.6 kJ. The heat lost by the aluminum ball is 10.8 kJ. What is the specific heat of copper, if the specific heat of aluminum is 0.90 J/g°C?

Answers

The specific heat of aluminum is actually simply a diversion. Because we can directly compute for the specific heat of copper using the formula:

ΔH = m C ΔT

where ΔH is change in enthalpy or heat lost, m is mass, C is specific heat and ΔT is change in temp

 

4,600 J = 150 g * C * (100 °C - 20°C)

C = 0.38 J/g°C

Answer:

0.383 J/g°C

Explanation:

The heat emitted by the copper ball while cooling down is given by:

[tex]Q=m C_s \Delta T[/tex]

where:

m = 150 g is the mass of the ball

Cs = ? is the specific heat of copper

[tex]\Delta T=100^{\circ}C-20^{\circ}C=80^{\circ}C[/tex] is the change in temperature

We know that the heat lost by the copper ball is

[tex]Q=4.6 kJ=4600 J[/tex]

So we can re-arrange the formula to find the specific heat capacity:

[tex]C_s = \frac{Q}{m \Delta T}=\frac{4600 J}{(150 g)(80^{\circ} C)}=0.383 J/g^{\circ}C[/tex]

What kinds of images are made by painting or drawing on top of the surface of a rock?

Answers

pictographs would be ur answer

Which of the following is not an example of an abiotic factor? a. plants b. air c. temperature d. soil Please select the best answer from the choices provided A B C D

Answers

Correct answer choice is:A. Plants.Explanation:

The living beings in an ecosystem are named biotic factors. Living beings involve plants, creatures, bacteria, parasites and many more. The non-living components of an ecosystem are named abiotic factors. In an ecosystem, few abiotic factors are sunshine, temperature, climatic gases, water, and clay.

Plants are not an example of an abiotic factor.

Further Explanation:

Many factors affect the environment such as some factors determines how much the tree can grow, why birds are migrating one place to another, and where the plants and animals are found. There are mainly two types of factors that influence the environment are

Biotic Abiotic

Abiotic factors are referred as a non-living part of an environment that can easily influence living organisms. These factors are very crucial for living organisms. Every plant and animal requires these factors to live. Without these factors organism can become dehydrated, and week. Examples of Abiotic factors are:

Water Sunlight Temperature Oxygen Soil

Biotic factors are referred to as all the living parts of an ecosystem. For example, animals and plants are biotic factors. These living things of the ecosystem interact with each other in different ways. Thus, plants are part of biotic factors and not part of abiotic factor.

Learn more:

Learn more about abiotic factor https://brainly.com/question/1561256 Learn more about cellular respiration https://brainly.com/question/8900186 Learn more about primary and secondary succession https://brainly.com/question/4723069

Answer Details:

Grade: High School  

Subject: Biology

Chapter: Ecology

Keywords:

Biotic, abiotic, sun, light, water, oxygen, plant, animal, non-living, living, ecosystem, organism, tree, grow, bird, migration.

Velocity question...is it A B Cor D
If a motorcycle starts from rest and maintains a constant acceleration of 3 m/s^2, what will its velocity be after 10 s?
A. 10 m/s
B. 30 m/s
C. 90 m/s
D. 100 m/s

Answers

In a constant acceleration of 3m per second, after 10 seconds,

3 x 10 = 30

B. 30m/s is your answer

hope this helps :D
B is the answer
Hope it helped!

The radius of a potassium atom is 0.227 nanometer (nm). what is this radius in centimeters (cm)?

a. 2.27 Ã 10â8 cm

b. 2.27 Ã 106 cm

c. 2.27 Ã 10â10 cm

d. 2.27 Ã 10â11 cm check answer

Answers

A nanometer is equivalent to 10^-9 meter. While a centimetre is equivalent to 10^-2 meter. Therefore the conversion factors are:

1 nanometer = 10^-9 meter

1 centimeter = 10^-2 meter

 

So,

0.227 nanometer * (10^-9 meter / 1 nanometer) * (1 centimeter / 10^-2 meter) = 2.27 x 10^-8 centimeter

 

Answer:

a

As Lucy pushes a box across the floor, she exerts a force on the box in the forward direction. What is the equal and opposite force in this interaction, according to Newton\'s third law?

Answers

Final answer:

Newton's third law dictates that as Lucy pushes a box forward, the box pushes back with an equal and opposite force.

Explanation:

According to Newton's third law, whenever Lucy pushes the box across the floor exerting a force on it, the box exerts an equal and opposite force back onto Lucy. This law states that forces occur in equal but-opposite-to pairs -- meaning, if object A exerts a force on object B, object B exerts a force of equal magnitude but in the opposite direction on object A. In Lucy's case, as she pushes the box forward, the box pushes back on her with the same amount of force.

Are the items in the list renewable or nonrenewable resources?

Choose N for nonrenewable resources.
Choose R for renewable resources.

coal

silver

soil

water

diamonds

Answers

Nonrenewable- Coal, Silver, soil and diamonds  Renewable- Water 


Answer:

Nonrenewable:Coal, Silver, soil and diamonds  

Renewable- Water  

Explanation:

i hope this helps you to answer your question

According to the periodic table, the average atomic mass of helium is

Answers

Helium has an atomic mass of 4.00 atomic mass units.

A flatbed truck is carrying a 20.0 kg crate along a level road. the coefficient of static friction between the crate and the bed is 0.400, and the coefficient of kinetic friction is 0.300. what is the maximum acceleration that the truck can have if the crate is to stay in place relative to the truck?

Answers

3.92 m/s^2 Assuming that the local gravitational acceleration is 9.8 m/s^2, then the maximum acceleration that the truck can have is the coefficient of static friction multiplied by the local gravitational acceleration, so 0.4 * 9.8 m/s^2 = 3.92 m/s^2 If you want the more complicated answer, the normal force that the crate exerts is it's mass times the local gravitational acceleration, so 20.0 kg * 9.8 m/s^2 = 196 kg*m/s^2 = 196 N Multiply by the coefficient of static friction, giving 196 N * 0.4 = 78.4 N So we need to apply 78.4 N of force to start the crate moving. Let's divide by the crate's mass 78.4 N / 20.0 kg = 78.4 kg*m/s^2 / 20.0 kg = 3.92 m/s^2 And you get the same result.

A car accelerates from rest to a velocity of 5 meters/second in 4 seconds. What is its average acceleration over this period of time?

A: its acceleration is 1.25 meters/second.
B: its acceleration is 5 meters/second.
C: its acceleration is 0.8 meters/second.
D: its acceleration is 1.25 meters/second^2.
E: its acceleration is 20 meters.

Answers

the answer is D: its acceleration is 1.25 meters/second^2.

What is the average acceleration of the particle between 0 seconds and 4 seconds?

Answers

2 as it is the middle of both the numbers

The average acceleration of the particle between 0 seconds and 2 seconds is 4 m/s², and it is constant. From 2 seconds to 4 seconds, the particle experiences no acceleration as it moves at a constant velocity.

The question asks about the average acceleration of a particle between 0 seconds and 4 seconds. Since the acceleration is constant and equal to 4 m/s² along the x-direction, this value itself represents the average acceleration over the given time interval. There's no need to perform any additional calculations if the acceleration doesn't change with time, as is the case here.

However, it's important to note that the value of the constant acceleration (4 m/s²) applies only between 0 seconds and 2 seconds, after which the particle travels at constant velocity and the acceleration is zero.

The wavelength of a wave is the wavelength of a wave is how strong the wave is. equal to the speed of the wave times the wave's frequency. the distance between where the wave is emitted and where it is absorbed. the distance between two adjacent peaks of the wave. the distance between a peak of the wave and the next trough.

Answers

The wavelength of a wave is 

A) how strong the wave is.

B) the distance between a peak of the wave and the next trough.

C) the distance between two adjacent peaks of the wave.

D) the distance between where the wave is emitted and where it is absorbed. 

E) equal to the speed of the wave times the wave's frequency.

the  right answer is C 
C) the distance between two adjacent peaks of the wave.

The wavelength is the distance between two adjacent peaks of the wave.

Hence, option C is correct.

What is Wavelength?

The distance between two identical locations (adjacent crests) in successive cycles is known as the wavelength, and it is used to describe waveform signals that are transmitted over wires or into space. Typically, in wireless systems, this length is specified in meters (m), centimeters (cm), or millimeters (mm). The wavelength is more frequently described in nanometers (nm), which are units of 10-9 m, or angstroms, which are units of 10-10 m, for infrared (IR), visible light (UV), and gamma radiation.

Frequency, which is defined as the number of wave cycles per second, and wavelength have an inverse relationship. The wavelength of a signal decreases with increasing frequency, or we can say that wavelength and refractive index are inversely proportional to each other.

To get more information about Wavelength :

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A camel has a hump to store water so it can survive in its desert environment. Which kind of adaptation is this?

Answers

This kind of adaptation is called STRUCTURAL ADAPTATION.
There are three types of adaptation, which are: behavioral adaptation, physiological adaptation and structural adaptation. A living organism is said to possess a structural adaptation if it has an organ in its body which helps it to survive harsh conditions. The hump on the camel's back is an example of structural adaptation which helps it to survive in the desert.

If I drop a watermelon from the top of one of the tower dorms at CSU, and it takes 3.34 seconds to hit the ground, calculate how tall the building is in meters

Answers

T= 3.34

Vi= 0

A= 9.81

D= ?

d=Vit+1/2at^2

d= 1/2(9.81)(3.34)2

d= 54.7 or 55 meters tall

which of the materials would be able to scratch Quartz

Answers

anything harder than mohs scale 7 so eg Topaz, Corundum and diamond representing mohs scale 8 9 and 10 respectively.

What influences the strength of an electric field?

Answers

The source/size of the charge.

The distance from the source of charge

The speed of a 4.0 n hockey puck, sliding across a level ice surface, decreases at the rate of 0.61 m/s2 . the coefficient of kinetic friction between the puck and ice is: hint: find the puck's mass first.

Answers

The coefficient of the kinetic friction is u = 0.0622. You obtain a part of the frictional force from gravity, 9.81 m/s^2, and the remainder from the mass of the hockey puck. The deceleration is do from the sheer force on the ice to the hockey puck combined with the downward gravitational force
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