a circle with radius 10 in has radii drawn to the endpoints of a 6 in chord.What is the measure of the central angle,to the nearest degree?What is the area of the triangle formed,to the nearest tenth.
Please show work

It might have come from

9/n  =  10/m

Answer: Hi, in the equation 9*m = 10*n the proportion is 9 to 10, which means that 9 times the number m is equal to 10 times the number n.

So n is proportional to m in the way that n= (9/10)*m

and m is proportional to n in the way that m= (10/9)*n

This means that the proportion can be written as 9 to 10, or 9:10.

Answer: circumference: 22π  area: 121π

Step-by-step explanation:

area of a circle is [tex]\pi r^2[/tex]

circumference is [tex]2\pi r[/tex]

Check the picture below.

Answer:

1/4

Step-by-step explanation:

Step 1: Find the GCF. List out the factors of the numerator and the denominator. 1, 3, 9 are the factors of 9, while 1, 2, 3, 4, 6, 9, 12, 18, and 36 are the factors of 36. 9 is a common factor of both of them, so the GCF is 9.

Step 2: Divide the numerator and denominator by 9 (the GCF). 9/9 is 1. 36/9 is 4. This means that our fraction is 1/4. The fraction is in simplest form.

Answer:

40cm

Step-by-step explanation:

1. 10000cm^3/25cm= 400cm^2

2. 400cm^2/10 cm= 40cm

Final answer:

To find the height of the box, divide the volume of the box by the area of the base. In this case, the height is 40 cm.

Explanation:

To find the height of the box, we need to divide the volume of the box by the area of the base. The volume is given as 10000 cm³ and the base has dimensions 25 cm by 10 cm. So, the area of the base is 25 cm * 10 cm = 250 cm². Now, we can find the height by dividing the volume by the area: Height = Volume / Area = 10000 cm³ / 250 cm² = 40 cm.

It would be 49,009 because LA of a cone is height (50) times the radius (120) and that equals about 49,009.

Answer:

48984 m^2

Step-by-step explanation:

The height(h) of cone is given by: 50 m.

Diameter of cone is: 240 m.

Also radius(r) of cone is:240/2=120 m.

[tex]\bf \begin{array}{|cc|ll} \cline{1-2} x&y\\ \cline{1-2} {-2}~~\ast&{4}~~\ast\\ 0&2\\ 1&1\\ {3}~~\ast&{-1}~~\ast\\ \cline{1-2} \end{array}~\hspace{10em} (\stackrel{x_1}{-2}~,~\stackrel{y_1}{4})\qquad (\stackrel{x_2}{3}~,~\stackrel{y_2}{-1}) \\\\\\ slope = m\implies \cfrac{\stackrel{rise}{ y_2- y_1}}{\stackrel{run}{ x_2- x_1}}\implies \cfrac{-1-4}{3-(-2)}\implies \cfrac{-5}{3+2}\implies \cfrac{-5}{5}\implies -1[/tex]

The slope of this line is -1.

The slope formula is useful:

m = (y2 -y1)/(x2 -x1)

where:

m is the slope of the line

y1 and y2 are the y-coordinates of two points on the line

x1 and x2 are the x-coordinates of the two points on the line

 m = (2 -4)/(0 -(-2)) = -2/2 = -1

The slope of this line is -1.

The points on the line drop 1 unit for each 1 unit to the right.

 m = rise/run = -1/1 = -1

Answer:

The correct answer is option A.  5 units

Step-by-step explanation:

Points to remember

Distance formula

Length of a line segment with end points (x1, y1) and (x2, y2) is given by,

Distance = √[(x2 - x1)² + (y2 - y1)²]

It is given that, two points are

(5, –2) and (5, 3)

To find the distance

(x1, y1) = (5, -2)  and (x2, y2) = (5, 3)

Distance = √[(x2 - x1)² + (y2 - y1)²]

 = √[(5 - 5)² + (3 - -2)²]

 = √[(5)²  = 5

Therefore the correct option is Option A  5 units

Answer:

a

Step-by-step explanation:

Answer:

Option (A) and (D) are not trigonometric identities.

Step-by-step explanation:

Option (A )  tan²x + sec²x = 1

Since [tex]tanx =\frac{sinx}{cosx}[/tex] and [tex]secx =\frac{1}{cosx}[/tex]

put these in left hand side of tan²x + sec²x = 1

[tex](\frac{sinx}{cosx})^{2}[/tex] + [tex](\frac{1}{cosx})^{2}[/tex]

[tex](\frac{sin^{2}x}{cos^{2}x})[/tex] + [tex](\frac{1}{cos^{2}x})[/tex]

Take L.C.M of above expression,

[tex](\frac{sin^{2}x + 1}{cos^{2}x})[/tex]

since, sin²x  = 1 - cos²x

[tex](\frac{1-cos^{2}x+1}{cos^{2}x})[/tex]

[tex](\frac{2-cos^{2}x}{cos^{2}x})[/tex]

we are not getting 1

so, this is not a trigonometric identity.

Option (A) is correct option

Option (B)  sin²x + cos²x = 1

This is an trigonometric identity

Option (C)  sec²x - tan²x = 1

Divide the trigonometric identity sin²x + cos²x = 1 both the sides by cos²x so, we get

[tex]\frac{sin^{2}x}{cos^{2}x}+\frac{cos^{2}x}{cos^{2}x}\,=\,\frac{1}{cos^{2}x}[/tex]

[tex]tan^{2}x}+1\,=\,sec^{2}x}[/tex]

subtract both the sides by tan²x in above expression

[tex]tan^{2}x}+1\,-tan^{2}x=\,sec^{2}x-tan^{2}x[/tex]

[tex]1=\,sec^{2}x}-tan^{2}x[/tex]

Hence, this is the trigonometric identity.

Option (D)  sec²x + cosec²x = 1

Since [tex]secx =\frac{1}{cosx}[/tex] and [tex]cosecx =\frac{1}{sinx}[/tex]

put these in left hand side of sec²x + cosec²x = 1

[tex](\frac{1}{cosx})^{2}+(\frac{1}{sinx})^{2}[/tex]

[tex]\frac{1}{cos^{2}x}+\frac{1}{sin^{2}x}[/tex]

we are not getting 1

so, this is not a trigonometric identity.

Option (D) is correct option.

Hence, Option (A) and (D) are not trigonometric identities.

Answer:

(b, c)

Step-by-step explanation:

The mid-point of two vertices or point is calculated by adding the respective coordinates of those points and then dividing by two. The x-coordinates will be added and then divided by 2 and then y-coordinates will be added and divided by 2.

So for the given question,

P(0,0)

Q(2a,0)

And

R(2b, 2c)

Mid-point of PR =( (0+2b)/2, (0+2c)/2)

=(2b/2, 2c/2)

=(b,c)

So the mid-point of PR is (b, c)

Last option is the correct answer..

[tex]\boxed{c^2+d^2+2cd}[/tex]

Hope this helps.

r3t40

The volume is 12 770.05 cubic centimeters (cm3)

12 770.50 cubic centimeters

Check the picture below.

so then, the perimeter of that hexagon will  just be the sum of all its 6 sides, or namely 3⅖ + 3⅖ + 3⅖ + 3⅖ + 3⅖ + 3⅖, or just 6( 3⅖ ).

[tex]\bf \textit{area of a regular polygon}\\\\ A=\cfrac{1}{2}ap~~ \begin{cases} a=apothem\\ p=perimeter\\[-0.5em] \hrulefill\\ a=3\\ p=6\left(3\frac{2}{5} \right) \end{cases}\implies A=\cfrac{1}{2}(3)\left[ 6\left(3\frac{2}{5} \right) \right]\implies A=\cfrac{1}{2}(3)\left[ 6\left(\cfrac{17}{5} \right) \right] \\\\\\ A=\cfrac{1}{2}(3)\left(\cfrac{102}{5} \right)\implies A=\cfrac{1}{2}\left( \cfrac{306}{5} \right)\implies A=\cfrac{153}{5}\implies A=30\frac{3}{5}[/tex]

see if u understand, note that the degree is 90

The height of the kite is 9 feet.

Trigonometric ratio is used to show the relationship between the sides of a triangle and its angles.

Let h represent the height of the kite. Hence, using trigonometric ratios:

sin(30) = h / 18

h = 9 feet

Therefore the height of the kite is 9 feet.

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Answer:

A. [tex]h=\dfrac{2A}{b}[/tex]

Step-by-step explanation:

You are given formula

[tex]A=\dfrac{1}{2}bh[/tex]

Multiply this equation by 2 to get rid of fraction:

[tex]2A=bh[/tex]

Divide this equation by b to find h in terms of A and b:

[tex]h=\dfrac{2A}{b}[/tex]

Answer:

[tex]175\ in^{2}[/tex]

Step-by-step explanation:

step 1

Find the scale factor

we know that

If two figures are similar, then the ratio of its volumes is equal to the scale factor elevated to the cube

Let

z----> the scale factor

x----> volume of the larger solid

y----> volume of the smaller solid

[tex]z^{3}=\frac{x}{y}[/tex]

we have

[tex]x=125\ in^{3}[/tex]

[tex]y=27\ in^{3}[/tex]

substitute

[tex]z^{3}=\frac{125}{27}[/tex]

[tex]z=\frac{5}{3}[/tex]

step 2

Find the surface area of the larger solid

we know that

If two figures are similar, then the ratio of its surface areas is equal to the scale factor squared

Let

z----> the scale factor

x----> surface area of the larger solid

y----> surface area of the smaller solid

[tex]z^{2}=\frac{x}{y}[/tex]

we have

[tex]z=\frac{5}{3}[/tex]

[tex]y=63\ in^{2}[/tex]

substitute

[tex](\frac{5}{3})^{2}=\frac{x}{63}[/tex]

[tex]x=\frac{25}{9}*63=175\ in^{2}[/tex]

To solve the equation[tex]\(x^2 = 50\),[/tex] we'll take the square root of both sides. However, when we do this, we need to consider both the positive and negative square roots:

[tex]\[ x = \pm \sqrt{50} \]\[ x = \pm \sqrt{25 \cdot 2} \]\[ x = \pm 5\sqrt{2} \]So, the solutions to the equation \(x^2 = 50\) are \(x = 5\sqrt{2}\) and \(x = -5\sqrt{2}\).[/tex]

To solve the equation [tex]\(x^2 = 50\),[/tex]we'll take the square root of both sides. Remembering that the square root of a number has both positive and negative solutions, we have:

[tex]\[ x = \pm \sqrt{50} \]\[ x = \pm \sqrt{25 \cdot 2} \]\[ x = \pm 5\sqrt{2} \][/tex]

Therefore, the solutions to the equation[tex]\(x^2 = 50\) are \(x = 5\sqrt{2}\) and \(x = -5\sqrt{2}\). This means that when \(x\) is equal to either \(5\sqrt{2}\) or \(-5\sqrt{2}\), \(x^2\) will be equal to 50. These solutions represent the values of \(x\)[/tex]that satisfy the original equation and make it true.

Answer: 9

Step-by-step explanation: 4.5=.5xZ. 4.5/.5=9=z

Answer: 4

Step-by-step explanation:

The degree is the highest exponent , in which in this problem it is 4. The 3x counts as an exponent of 1 because the variable x is 1, and the 2 counts as an exponent of zero. Which means the degree is 4.

The area of the rectangle is decreased by 75%, when the dimensions of a rectangle are decreased by 50%.

The area of the rectangle is the multiplication of length and width.

Area = l × b

It is given that:  length and breadth is by 50%

New Length = l × (1-50/100)

                   = l × (1-1/2)

                  = l/2

New Width = b × (1-50/100)

                  = b × (1-1/2)

                 = b/2

New area = new length × new width

               = (l/2) x (b/2)

              = lb/4

Change percent =[tex]\frac{Final Area\;-\; Initial Area}{Initial Area} * 100[/tex]

                        = [tex]\frac{(lb/4)\;-\; lb}{lb} * 100[/tex]

                        = (- 3lb)/4× 100

                        = (-3)/4 × 100

                        =  -75%

Hence, the area decreased by 75 %.

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Final answer:

Decreasing the dimensions of a rectangle by 50% results in a new area that is 25% of the original, equating to a decrease of 75% in the area.

Explanation:

When the dimensions of a rectangle are decreased by 50%, each dimension (length and width) becomes 50% of the original. To determine the effect on the area, you can use the formula for the area of a rectangle, which is Area = length tmes width.

Let's consider the original length to be L and the original width to be W. The original area is L times W. When both dimensions are decreased by 50%, the new length is 0.5L and the new width is 0.5W. Therefore, the new area is (0.5L) times (0.5W), which is 0.25 times (L times W). This means the new area is 25% of the original area, representing a 75% decrease.

Answer:

3 left

Step-by-step explanation:

If she starts out with 73 and drops 5 she is left with 68, an you cannot evenly divide 68 and 13 so you divide it as much as you can evenly which is five containers leaving 3 extra cupcakes.

For this case we have that initially there are 73 cupcakes, if Leda dropped 5 then we are left with:

[tex]73-5 = 68[/tex]

Now, you must equally divide the 68 cupcakes into 13 containers:

putting 5 cupcakes in each of the 13 containers we have;

[tex]13 * 5 = 65[/tex]

[tex]68-65=3[/tex]

So, we have 3 cupcakes left.

Answer:

3 cupcakes

Answer:

8

Step-by-step explanation:

The number is a, another number is b.

a = b + 18 So, b=a - 18

(a+b) + ab

= a + a - 18 + a (a - 18)

= 2a - 18 + a^2 - 18a

{ ax^2 + bx + c }

= a^2 -1 6a - 18 {a = 1b = -16 }

When a = b/-2a = -16/-2*1 = 8

the a^2 - 1ba - 18 is minimum,

So the number is 8

Answer:

300π ft^3

Step-by-step explanation:

let's use the volume of a cylinder formula:

π*r^2*h

π=3.14

r=5

h=12

since we need to solve in terms of pi, do not plug the value of pi into the formula

π*5^2*12= 300π

300π

if the diameter is 6 units, then the radius is half that, or 3.

[tex]\bf \textit{area of a circle}\\\\ A=\pi r^2~~ \begin{cases} r=radius\\ \cline{1-1} r=3 \end{cases}\implies A=\pi 3^2\implies A=9\pi \implies A\approx 28.27[/tex]

Final answer:

To calculate the area of a circle with a 6-inch diameter, use the radius (3 inches) in the area formula πr² to get an approximate area of 28.274 square inches.

Explanation:

To find the area of a circle with a diameter of 6 inches, we use the formula for the area of a circle, which is πr², where r is the radius of the circle. Since the diameter is 6 inches, we divide by two to find the radius (r = diameter / 2 = 6 / 2 = 3 inches).

Substituting the radius into the formula gives us π(3²) = π(9), and using the approximation π ≈ 3.14159, we find the area to be approximately 28.274 square inches.

Answer:

D

Step-by-step explanation:

If y = log x is the basic function, let's see the transformation rule(s):

Then,

1. y = log (x-a) is the original shifted a units to the right.

2. y = log x + b is the original shifted b units up

Hence, from the equation, we can say that this graph is:

** 2 units shifted right (with respect to original), and

** 10 units shifted up (with respect to original)

only, left or right shift affects vertical asymptotes.

Since, the graph of y = log x has x = 0 as the vertical asymptote and the transformed graph is shifted 2 units right (to x = 2), x = 2 is the new vertical asymptote.

Answer choice D is right.

Answer:

y = - 7

Step-by-step explanation:

The y- intercept is the point on the y- axis that the line passes through.

The line passes through the y- axis at (0, - 7), hence

the y- intercept is - 7

Slope-intercept form: y = mx + b   [m is the slope, b is the y-intercept or the y value when x = 0 ---> (0 , y)]

Since you know m = -3, you can plug that into the equation

y = mx + b

y = -3x + b       To find b, plug in the point they gave you into x and y, but since x = 0, your y-intercept is -7

Answer:

The correct answer option is 0.2.

Step-by-step explanation:

We are given that there are 3 red marbles and 3 green marbles in an opaque bag.

If two marbles are chosen one after one without replacement, we are to find the probability of getting both green marbles.

P (1st green marble) = [tex] \frac { 3 } { 6 } [/tex]

P (2nd green marble) = [tex] \frac { 2 } { 5 } [/tex]

P (both green marbles) = [tex] \frac { 3 } { 6 } \times \frac { 2 } { 5 } [/tex] = 0.2

Answer:

i think its forty

Step-by-step explanation:

im sorry if its wrong

Answer:

This answer would be 2,463.01 "D"

Step-by-step explanation:

The approximate size of the cover will be 2463.01 square feet

'A cylinder is a three-dimensional solid that holds two parallel bases joined by a curved surface, at a fixed distance.'

According to the given problem,

The size of the cover of the tank = area of  the circle of the tank                                (approximately)

r = 28 feet

Area of the circle = [tex]\pi r^{2}[/tex]

                             = [tex]\pi *28^{2}[/tex]

                             = [tex]2463.01[/tex]

Hence, we have concluded that in order to cover the tank, which is a circular area, the area of the cover has to be approximately 2463.01 square feet.

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Answer:

∴The distance CA =  = 2√2

Step-by-step explanation:

Find the distance CA:

The distance between two points (x₁,y₁),(x₂,y₂) = d

The coordinates of point C = (-2,2)

The coordinates of point A = (0,0)

The distance CA distance between C and A

∴The distance CA =  = 2√2

The distance[tex]\( C'B' \) is \( \sqrt{10} \)[/tex] units.

after applying the transformation[tex]\( T: (x, y) \rightarrow (x + 2, y + 1) \)[/tex], the distance between points [tex]\( C' \)[/tex] and [tex]\( B' \)[/tex] is [tex]\( \sqrt{10} \)[/tex] units.

The distance [tex]\( C'B' \)[/tex] is [tex]\( \sqrt{10} \)[/tex] units.

To find the distance [tex]\( C'B' \)[/tex], we first need to find the coordinates of points [tex]\( C' \)[/tex] and [tex]\( B' \)[/tex] after applying the transformation [tex]\( T: (x, y) \rightarrow (x + 2, y + 1) \) to points \( C \)[/tex] and [tex]\( B \).[/tex]

Given the coordinates of [tex]\( C \)[/tex] and [tex]\( B \)[/tex] as[tex]\( C(1, 2) \)[/tex] and [tex]\( B(4, 3) \)[/tex] respectively, we apply the transformation to each point:

For point [tex]\( C \):[/tex]

[tex]\[ C'(x', y') = (x + 2, y + 1) = (1 + 2, 2 + 1) = (3, 3) \][/tex]

For point [tex]\( B \):[/tex]

[tex]\[ B'(x', y') = (x + 2, y + 1) = (4 + 2, 3 + 1) = (6, 4) \][/tex]

Now, we use the distance formula to find the distance between [tex]\( C' \)[/tex]and [tex]\( B' \):[/tex]

[tex]\[ C'B' = \sqrt{(x'_2 - x'_1)^2 + (y'_2 - y'_1)^2} \][/tex]

[tex]\[ C'B' = \sqrt{(6 - 3)^2 + (4 - 3)^2} \][/tex]

[tex]\[ C'B' = \sqrt{(3)^2 + (1)^2} \][/tex]

[tex]\[ C'B' = \sqrt{9 + 1} \][/tex]

[tex]\[ C'B' = \sqrt{10} \][/tex]

Thus, the distance [tex]\( C'B' \)[/tex] is[tex]\( \sqrt{10} \)[/tex] units.

In conclusion, after applying the transformation [tex]\( T: (x, y) \rightarrow (x + 2, y + 1) \)[/tex], the distance between points [tex]\( C' \)[/tex] and [tex]\( B' \)[/tex] is [tex]\( \sqrt{10} \)[/tex] units.

Complete question

Using the transformation T: (x, y) (x + 2, y + 1), find the distance named. Find the distance C'B’