Answer:
Option C - Simplify the right side using the "difference of two logs is the log of the quotient" property.
Step-by-step explanation:
Given : Expression [tex]\ln (x-1)=\ln 6-\ln x[/tex]
To find : What is the first step in solving the expression ?
Solution :
Expression [tex]\ln (x-1)=\ln 6-\ln x[/tex]
Step 1 - Simplify the right side using the "difference of two logs is the log of the quotient" property.
i.e. [tex]\ln a-\ln b=\ln(\frac{a}{b})[/tex]
Apply the first step we get,
[tex]\ln (x-1)=\ln(\frac{6}{x})[/tex]
Therefore, Option C is correct.
A conference room is in the shape of a rectangle. Its floor has a length of (x − 4) meters and a width of (3x − 1) meters. The expression below represents the area of the floor of the room in square meters:
(x − 4)(3x − 1)
Which of the following simplified expressions represents the area of the floor of the conference room in square meters?
x2 − 13x + 4
3x2 − 13x + 4
3x2 − 11x + 4
x2 − 12x + 4
Answer:
3x^2−13x+4
Step-by-step explanation:
(x−4)(3x−1)
=(x+−4)(3x+−1)
=(x)(3x)+(x)(−1)+(−4)(3x)+(−4)(−1)
=3x^2−x−12x+4
=3x^2−13x+4
Answer:
Option A. 3x² - 13x + 4 is the answer.
Step-by-step explanation:
A conference room is in the shape of a rectangle. Its floor has a length of (x - 4) and width of (3x - 1) meters.
The expression that represents the area of the room is (x - 4)(3x -1) meter²
We further simplify this expression representing the area of the conference room.
(x - 4)(3x -1) = x(3x -1) - 4(3x -1) [Distributive law]
= 3x² - x - 12x + 4
= 3x² - 13x + 4
Option A. 3x² - 13x + 4 is the simplified form of the given expression.
if f(x)=2x-6 and g(x)=x^3 what is (g f)(0)
ANSWER
[tex](g \circ \: f)(0) = - 216[/tex]
EXPLANATION
The functions are:
[tex]f(x) = 2x - 6[/tex]
[tex]g(x) = {x}^{3} [/tex]
[tex](g \circ \: f)(x) =g(f(x))[/tex]
[tex](g \circ \: f)(x) =g(2x - 6)[/tex]
We substitute f(x) into g(x) to obtain:
[tex](g \circ \: f)(x) =(2x - 6)^{3} [/tex]
We now substitute x=0 to obtain;
[tex](g \circ \: f)(0) =(2(0) - 6)^{3} [/tex]
[tex](g \circ \: f)(0) =(- 6)^{3} [/tex]
This simplifies to:
[tex](g \circ \: f)(0) = - 216[/tex]
I’m not sure how to solve this. Please show how you solve this problem, thank you.
Answer:
Pretend that H is the midpoint of AB, connect O and H
=> OH is the median of ΔOAB
Since we know that OA = OB => ΔOAB is an isosceles triangle
=> OH is also the height of ΔOAB
=> ∠OBA = ∠OAB = (180° - ∠AOB)/2 = (180° - 120°)/2 = 60°/2 = 30°
Now look at ΔOHB (that you create by connecting O and H)
We have:
cos30° = BH/OB
=> BH = cos30° · OB = √3/2 · x = (√3 x)/2
Because we have H as the midpoint of AB, we know that:
AB = 2 · BH = 2 · (√3 x)/2 = √3 x
So the answer is B
img1
Equation: w = 112 + 8t
Which input results in an output of 176?
What is the output in the ordered pair (4, 144)?
The equation
[tex]w=112+8t[/tex]
means that you choose a value for the input variable t, and you compute the correspondent value for the output variable w.
So, if the input is t = 176, the output will be
[tex]w=112+8\cdot 176 = 112+1408 = 1520[/tex]
Similarly, the ordered pair (4, 144) means that if you choose 4 as input, you get 144 as output, in fact you have
[tex]w=112+8\cdot 4= 112+32= 144[/tex]
Answer:
The first one is 8
The second one is 144
Step-by-step explanation:
I just did it on brainly
Angelica swims 14 3/7 hours per month. If she swims the same amount every month, how many hours does she swim in 6 months?
85 4/7 hours
86 1/7 hours
86 4/7 hours
86 1/7 hours
Answer:
86 4/7, C.
Step-by-step explanation:
14x6= 84
+
6 x 3/7 = 2 4/7
86 4/7
Answer:
multiply 14 over 7 to get the number as one fraction. after adding three to that product, you get 101/7. Multiply that by 6/1 to get 606/7, then divide 606 by 7 to get 86 4/7 hours every 6 months.
Step-by-step explanation:
What is the correct answer for this equation? 6 ÷ 2(1+2) =
Answer:
9
Step-by-step explanation:
6 ÷ 2(1+2)
= 6 ÷ 2 x 3
= 3 x 3
= 9
The correct answer is 9
First you have to divide 6/2 is 3
Then you distribute 3 into the parentheses
3(1+2) = (3*1)+(3*2)
Then you solve
(3*1)=3
(3*2)=6
So,
6+3=9
A dolphin jumps from the water at a initial velocity of 16 feet per second the equation h=-8t^2 + 16t models the dolphins height at any given time t what is the maxim height the dolphin jumps
The maximum height that the dolphin jumps is 8 ft.
What is a parabola?A parabola is a planar curve which symmetrical across its vertex.
What is the standard equation of a parabola?The standard equation of a parabola is given by:
y = (x-h)² + k
Where (h, k) is the vertex of the parabola.
The maximum height that the dolphin reaches is the y-coordinate of the vertex of the parabola. We can change the given quadratic equation to standard form as follows:
h = -8t² + 16t
Subtract and add 8:
h = -8t² + 16t - 8 + 8
h = -8 (t² - 2t + 1) + 8
h = -8 (t - 1)² + 8
The negative coefficient outside the square term means that the parabola opens downward. From this standard form, we can see that the vertex of the parabola is (1, 8). This means that the maximum height that the dolphin can reach is 8 ft.
Therefore, we have found that the maximum height the dolphin jumps is 8 ft.
Learn more about parabolas here-https://brainly.com/question/25651698
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Final answer:
The dolphin reaches its maximum height after 2 seconds and jumps 32 feet.
Explanation:
To find the maximum height the dolphin jumps, we need to determine the time it takes for the dolphin to reach its highest point. The equation given is h = -8t^2 + 16t, where h represents the dolphin's height at any given time t. Since the dolphin jumps straight up, its final velocity at the highest point is 0. Setting h = 0 and solving the resulting quadratic equation, we can find the time it takes for the dolphin to reach its maximum height.
Using the equation -8t^2 + 16t = 0, we can factor out -8t to get t(-8t + 16) = 0. This yields two solutions: t = 0 and t = 2. As time cannot be negative, we discard t = 0. Therefore, the dolphin reaches its maximum height after 2 seconds.
To find the maximum height, we substitute t = 2 in the equation h = -8t^2 + 16t. Plugging in the value, we get h = -8(2)^2 + 16(2) = -8(4) + 32 = 0 + 32 = 32 feet. Thus, the maximum height the dolphin jumps is 32 feet.
8. The amount f (t)of a certain medicine, in milligrams, in a patient's
bloodstream t minutes after being taken is given by f(t) =
Find the amount of medicine in the blood after 20 minutes.
Answer:
The amount of medicine in the patient's blood after 20 minutes is 2.6906 milligrams
Step-by-step explanation:
The amount of medicine in the patient's blood after 20 minutes will given by;
f(20)
since we are informed that the amount f(t) of a certain medicine in a patient's bloodstream t minutes after being taken is given by f(t);
We simply substitute t = 20 in the function f(t);
[tex]f(20)=\frac{60(20)}{20^{2}+46 }=2.6906[/tex]
Answer:
Step-by-step explanation:
Since the formula is given, we only need to substitute 20 for t to find the answer.
60t/t sq. + 46 we substitute 20 for x:
60(20)/ 20x20 +46
1200/446 which equals
2.6905 milligrams
When simplified and written in standard form, which quadratic function is equivalent to the polynomial shown?
2 + 7c – 4c2 – 3c + 4
Final answer:
The quadratic function equivalent to the polynomial 2 + 7c – 4c2 – 3c + 4 when simplified and written in standard form is – 4c2 + 4c + 6.
Explanation:
When you simplify and write the polynomial 2 + 7c – 4c2 – 3c + 4 in standard form, the quadratic function equivalent is – 4c2 + 4c + 6. First, combine like terms by adding the constants and the terms with c. This gives you – 4c2 + (7c – 3c) + (2 + 4), which simplifies to – 4c2 + 4c + 6.
The standard form of a quadratic equation is ax2 + bx + c = 0. In the case of the simplified polynomial, a = -4, b = 4, and c = 6. If needed, you can use the quadratic formula to find the roots of this quadratic equation by substituting these values into the formula.
HELP FIND AREA AND PERIMETER VERY ARGENT PLEASE HELP
Answer:
Area = 575m² Perimeter = 94
Step-by-step explanation:
Trust me I'm right
Answer:
Area of the Figure: 575 m
Perimeter of the Figure: 94 m
Step-by-step explanation:
That shape can easily be divided into a right triangle and a rectangle.
•••To solve the area for the rectangle:
base x height
17 * 25 = 425 m
•••To solve the area for the right triangle:
1/2 x base x height
1/2 x 15 x 20 = 150 m
•••Perimeter of the figure:
Add all the sides.
17 + 17 + 25 + 15 + 20 = 94 m
Can someone help me with this? sin150° =
Answer:
sin(150°) = 1/2
Step-by-step explanation:
* Lets study how we can solve this problem
- At first the measure of the angle is 150°
- Ask your self in which quadrant can you find this measure
* To know the answer lets revise the four quadrants
# First quadrant the measure of all angles is between 0° and 90°
the measure of any angle is α
∴ All the angles are acute
∴ All the trigonometry functions of α are positive
# Second quadrant the measure of all angles is between 90° and 180°
the measure of any angle is 180° - α
∴ All the angles are obtuse
∴ The value of sin(180° - α) only is positive ⇒ sin(180° - α) = sinα
# Third quadrant the measure of all angles is between 180° and 270°
the measure of any angle is 180° + α
∴ All the angles are reflex
∴ The value of tan(180° + α) only is positive ⇒ tan(180° + α) = tanα
# Fourth quadrant the measure of all angles is between 270° and 360°
the measure of any angle is 360° - α
∴ All the angles are reflex
∴ The value of cos(360° - α) only is positive ⇒ cos(360° - α) = cosα
* Now lets check the angle of measure 150
- It is an obtuse angle
∴ It is in the second quadrant
∴ the value of sin(150) is positive
∴ sin(150°) = sinα
∵ 180 - α = 150 ⇒ isolate α
∵ α = 180° - 150° = 30°
∴ sin(150°) = sin(30°)
∵ sin(30°) = 1/2
∴ sin(150°) = 1/2
ANSWER
[tex]\sin(150 \degree) = \frac{1}{2} [/tex]
EXPLANATION
The principal angle for 150° is 30°.
The terminal side of 150° is in the second quadrant.
In this quadrant the sine ratio is positive.
This implies that;
[tex] \sin(150 \degree)= \sin(30 \degree) [/tex]
On the unit circle,
[tex] \sin(30 \degree) = \frac{ 1 }{2} [/tex]
Therefore
[tex]\sin(150 \degree)= \sin(30 \degree) = \frac{1 }{2} [/tex]
25 POINTS WILL MARK RIGHT ANSWER AS BRAINLIEST! What is the value of x to the nearest tenth?
Answer:
The value of x is 2.5 to the nearest tenth
Step-by-step explanation:
* Lets revise the trigonometry functions
- In any right angle triangle:
# The side opposite to the right angle is called the hypotenuse
# The other two sides are called the legs of the right angle
* If the name of the triangle is ABC, where B is the right angle
∴ The hypotenuse is AC
∴ AB and BC are the legs of the right angle
- ∠A and ∠C are two acute angles
- For angle A
# sin(A) = opposite/hypotenuse
∵ The opposite to ∠A is BC
∵ The hypotenuse is AC
∴ sin(A) = BC/AC
# cos(A) = adjacent/hypotenuse
∵ The adjacent to ∠A is AB
∵ The hypotenuse is AC
∴ cos(A) = AB/AC
# tan(A) = opposite/adjacent
∵ The opposite to ∠A is BC
∵ The adjacent to ∠A is AB
∴ tan(A) = BC/AB
* Now lets solve the problem
∵ x is opposite to the angle of measure 23°
∵ 6 is adjacent to the angle of measure 23°
∴ tan(23°) = x/6 ⇒ × 6 to both sides
∴ x = 6 × tan(23°) = 2.5
* The value of x is 2.5 to the nearest tenth
Answer: [tex]x=2.5[/tex]
Step-by-step explanation:
You need to remember the identity:
[tex]tan\alpha=\frac{opposite}{adjacent}[/tex]
You can identify in the figure that for the angle 67°:
[tex]\alpha=67\°\\opposite=6\\adjacent=x[/tex]
Then you need to substitute these values into [tex]tan\alpha=\frac{opposite}{adjacent}[/tex] and solve for "x":
[tex]tan(67\°)=\frac{6}{x}\\\\xtan(67\°)=6\\\\x=\frac{6}{tan(67\°)}\\\\x=2.5[/tex]
The population of ls Vegas Nevada has been increasing at an annual rate of 7.0%. If the population of Las Vegas was 478,434 in 1999, predict its population in 2015
The answer is:
The population in 2015 will be 1,412,415.
Why?Since from the statement we know that the population is increasing, we know that we are working with an exponential growth problem.
We can calculate the exponential growth using the following equation:
[tex]Population(t)=StartPopulation(1+growthpercent)^{t}[/tex]
Where,
P, is the population after t (years, months, days or hours)
Start Population, is the starting population.
Growth percent, is the percent of growth
t, is the time elapsed (years, months, days or hours)
So, we are given the following information:
[tex]StartPopulation=478434\\\\GrowthPercent=7(percent)=\frac{7(percent)}{100}=0.07\\\\TimeElapsed=2015-1999=16years[/tex]
Now, substituting and calculating, we have:
[tex]Population(t)=StartPopulation(1+growthpercent)^{t}[/tex]
[tex]Population(t)=478434(1+0.07)^{16}=141241.5=1412415[/tex]
Hence, the population in 2015 will be 1,412,415.
Have a nice day!
Answer please show steps please
Answer:
25 girls
Step-by-step explanation:
Let
x denote number of boys
and
y denote number of girls
According to the statement that total 45 people came,
x+y = 45 => Eqn 1
And total paid amount was 175
So,
5x + 3y = 175 => Eqn 2
For solving, We will use the substitution method
So, from eqn 1
x = 45-y
Putting value of x in eqn 2
5(45-y) +3y = 175
225 - 5y + 3y = 175
-2y+225 = 175
-2y = 175-225
-2y = -50
2y = 50
y = 25
Putting y =25 in eqn 1
x+25 = 45
x = 45 - 25
x = 20
As y= 25
So, 25 girls came to the dance ..
Anna has to straighten her arm from 90° to 118°. She can straighten it
by about 12° every 3 days. How many days will it take to get to 118°?
Answer:
it would take her 7 days
Step-by-step explanation:
Answer:
7 days
Step-by-step explanation:
90-118=(-28)
28° to go.
12°/3 days = 4° per day
28/4=7. 7 days
Help me please? This problem is really not that easy?
Answer:
1. x = 49.10 - 5 divided by 2.10
2. 21 miles
Answer:
X=49.10
21 miles
Step-by-step explanation:
First, you need to divide 2.10 and the $5 . which will give you 4.2.
this has nothing to do with the problem lol.
I would keep on mulitiplying if i were you.
And, once you hit 21 miles, you will get $44.10 and the $5 which will equal 49.10 :).
Solve the Equation
5x+15y=10
5x-10y=-40
Answer:
Step-by-step explanation:
-5x + 10 = 15y
(-5(x-2))/15
(-x+2)/3 = y
5x - 10((-x+2)/3)
5x - ((-10x + 20)/3)=-40
5x + (10x-20)/3
15x + 10x - 20 = -120
25x = -100
x = -4
5x + 15y = 10
-20 + 15y = 10
30 = 15y
y = 2
Answer:
x = -4, y = 2Step-by-step explanation:
[tex]\left\{\begin{array}{ccc}5x+15y=10\\5x-10y=-40&\text{change the signs}\end{array}\right\\\underline{+\left\{\begin{array}{ccc}5x+15y=10\\-5x+10y=40\end{array}\right}\qquad\text{add both sides of the equations}\\.\qquad\qquad25y=50\qquad\text{divide both sides by 25}\\.\qquad\qquad\boxed{y=2}\\\\\text{Put the value of y to the first equation:}\\\\5x+15(2)=10\\5x+30=10\qquad\text{subtract 30 from both sides}\\5x=-20\qquad\text{divide both sides by 5}\\\boxed{x=-4}[/tex]
The width, w, of a rectangular swimming pool 9r + 1. The area A of the pool is 90r^6+28r^5+2r^(4 )+ 45r^3+5r^2. What is an expression for the length of the pool?
Answer:
10r⁵ + 2r⁴ + 5r²
Step-by-step explanation:
A = 90r⁶ + 28r⁵ + 2r⁴ + 45r³ + 5r²
Factor our r²:
A = r² (90r⁴ + 28r³ + 2r² + 45r + 5)
Factor 2r² from the first three terms and 5 from the last two:
A = r² (2r² (45r² + 14r + 1) + 5 (9r + 1))
Factor the trinomial:
A = r² (2r² (5r + 1)(9r + 1) + 5 (9r + 1))
Factor out 9r+1:
A = r² (2r² (5r + 1) + 5) (9r + 1)
Distribute the 2r²:
A = r² (10r³ + 2r² + 5) (9r + 1)
Distribute the r²:
A = (10r⁵ + 2r⁴ + 5r²) (9r + 1)
The area is width times length, and the width is 9r + 1.
WL = (10r⁵ + 2r⁴ + 5r²) (9r + 1)
(9r + 1) L = (10r⁵ + 2r⁴ + 5r²) (9r + 1)
L = 10r⁵ + 2r⁴ + 5r²
The length of the pool is 10r⁵ + 2r⁴ + 5r².
A certain element has a half-life of 69 years. An experiment starts with 1,500 grams of the element. The amount of the element remaining x years after the experiment began can be modeled with the function f(x) = 1,500(2)–x/69. The mathematical domain of the function is all real numbers.
Which statement describes how the reasonable domain compares to the mathematical domain?
1The reasonable domain is restricted to integers.
2The reasonable domain is restricted to positive real numbers.
3The reasonable domain has a minimum value of 1,500.
4The reasonable domain has a maximum value of 1,500.
Answer:
2. The reasonable domain is restricted to positive real numbers.
Step-by-step explanation:
The variable "x" is time in years from when the experiment began. It makes no sense to have negative values of x, as the experiment had not yet begun in negative time.
___
I would include x=0 in the domain, too, though you already know the amount of remaining element at x=0 and don't have to use the function to calculate it.
__
x might be restricted to integers if you're only measuring the remaining amount once a year.
The maximum value of 1500 applies to the *range* of the function, not its domain.
The minimum value of 1500 has nothing to do with anything.
Answer:
B) the reasonable domain is restricted to positive real numbers
Step-by-step explanation:
the function g is defined by g(x)=3k-5x, where k is a constant. find k, if the graph of g passes through the point (3,11).
Answer:
[tex]k=26/3[/tex]
Step-by-step explanation:
we have
[tex]g(x)=3k-5x[/tex]
we know that
If the graph of g(x) passes through the point (3,11)
then
the ordered pair (3,11) must satisfy the equation g(x)
Substitute
[tex]x=3,g(3)=11[/tex]
[tex]11=3k-5(3)[/tex]
[tex]11=3k-15[/tex]
[tex]3k=11+15[/tex]
[tex]3k=26[/tex]
[tex]3k=26[/tex]
[tex]k=26/3[/tex]
Find two consecutive odd numbers such that the sum of the first number and one-third of the second number is equal to fifty.
Answer:
37, 39
Step-by-step explanation:
n + 1/3 (n + 2) = 50
Multiply both sides by 3 to cancel out the 1/3:
3n + (n + 2) = 150
Simplify:
4n + 2 = 150
4n = 148
n = 37
n + 2 = 39
Answer:
37 and 39.
Step-by-step explanation:
Let the two odd numbers are x and ( x + 2 ) Then by statement " Sum of the first number and one third of second number is equal to 50."
So equation will be
x + [tex]\frac{1}{3}[/tex] (x+2) = 50
We multiply the equation by 3
3x + ( x+2 ) = 150
3x + x + 2 = 150
4x + 2 = 150
4x = 150 - 2 = 148
x = 37
So numbers are 37 and 39.
find the solution of 4x^2-4x-1=0
[tex]4x^{2} -4x - 1 = 0[/tex]
To solve for the zeros you can use the quadratic formula:
[tex]\frac{-b plus/minus\sqrt{b^{2}-4ac } }{2a}[/tex]
a = 4
b = -4
c = -1
[tex]\frac{-(-4) plus/minus\sqrt{(-4)^{2}-4(4)(-1) } }{2(4)}[/tex]
[tex]\frac{4 plus/minus\sqrt{16+16 } }{8}[/tex]
[tex]\frac{4plus/minus\sqrt{32} }{8}[/tex]
[tex]\frac{4plus/minus4\sqrt{2 } }{8}[/tex]
[tex]\frac{1 plus/minus\sqrt{2} }{2}[/tex]
Hope this helped!
~Just a girl in love with Shawn Mendes
The quadratic equation 4x^2 - 4x - 1 = 0 can be solved by using the quadratic formula -b ± √b² - 4ac / 2a. After substituting the coefficients into the formula, we get 4 ± √((-4)^2 - 4 * 4 * -1) / 2 * 4. These roots are the solution to the equation.
Explanation:The subject of the question is the solution of a quadratic equation which can be found using the quadratic formula. For the given equation 4x^2 - 4x - 1 = 0, the values of a, b, and c as per the general quadratic equation (ax^2 + bx + c = 0) are a = 4, b = -4 and c = -1. The quadratic formula to solve for x is -b ± √b² - 4ac / 2a.
Substituting the given values in to the formula we get the solution for x: 4 ± √((-4)^2 - 4 * 4 * -1) / 2 * 4, which can further be solved to get the two roots of the quadratic equation.
Learn more about Solving quadratic equations here:https://brainly.com/question/30398551
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which graph represents y=square root of x
Answer: b on edge 2020
Step-by-step explanation:
Select the two values of x that are roots of this equation.
x^2+1=5x
*APEX
Answer:
[tex]\large\boxed{B.\ x=\dfrac{5+\sqrt{21}}{2},\ C.\ x=\dfrac{5-\sqrt{21}}{2}}[/tex]
Step-by-step explanation:
[tex]\text{Use the quadratic formula:}\\\\ax^2+bx+c=0\\\\x=\dfrac{-b\pm\sqrt{b^2-4ac}}{2a}\\\\================================\\\\\text{We have}:\\\\x^2+1=5x\qquad\text{subtract}\ 5x\ \text{from both sides}\\\\x^2-5x+1=0\\\\a=1,\ b=-5,\ c=1\\\\b^2-4ac=(-5)^2-4(1)(1)=25-4=21\\\\x=\dfrac{-(-5)\pm\sqrt{21}}{2(1)}=\dfrac{5\pm\sqrt{21}}{2}[/tex]
Answer:
b and c Apex answers
A classroom globe has a diameter of 18 inches. Which of the following is the approximate surface area, in square inches, of the globe? (Surface Area = 4r2)
Answer:
1017.36 square inches
Step-by-step explanation:
The globe is in the shape of a sphere. As we given the diameter of the globe
d = 18 inches
We have to find the radius of globe first
[tex]Radius=r=\frac{d}{2}\\r=\frac{18}{2}\\r=9\ inches[/tex]
The formula for finding the surface area is:
[tex]Surface\ Area=4\pi r^{2}\\Putting\ the\ values\ of \pi \ and\ r\\Area=4*3.14*(9)^{2} \\=4*3.14*81\\=1017.36\ square\ inches[/tex]
Hence, the surface area is 1017.36 square inches ..
Find the slope and Y-intercept
[tex]\bf y=\stackrel{\stackrel{m}{\downarrow }}{\cfrac{7}{5}}x\stackrel{\stackrel{b}{\downarrow }}{-3}\impliedby \begin{array}{|c|ll} \cline{1-1} slope-intercept~form\\ \cline{1-1} \\ y=\underset{y-intercept}{\stackrel{slope\qquad }{\stackrel{\downarrow }{m}x+\underset{\uparrow }{b}}} \\\\ \cline{1-1} \end{array}\qquad \qquad \cfrac{7}{5};-3[/tex]
The formula y=mx+b which this equation is in shows the slope as m and y-intercept as b. In this situation where m is the fraction 7 over 5 and b is -3. So the slope is 7/5 and the y-intercept is -3
What is the solution set of the following equation? 4/5 x2 = 2x - 4/5
Answer:
[tex]x=\frac{1}{2}[/tex] or [tex]x=2[/tex]
Step-by-step explanation:
The given quadratic equation is:
[tex]\frac{4}{5}x^2=2x-\frac{4}{5}[/tex]
We multiply through by 5 to get:
[tex]4x^2=10x-4[/tex]
Rewrite in standard quadratic form;
[tex]4x^2-10x+4=0[/tex]
Or
[tex]2x^2-5x+2=0[/tex]
Split the middle term to get:
[tex]2x^2-4x-x+2=0[/tex]
Factor to get:
[tex]2x(x-2)-1(x-2)=0[/tex]
Factor further to get:
[tex](2x-1)(x-2)=0[/tex]
Either [tex](2x-1)=0[/tex] or [tex](x-2)=0[/tex]
Either [tex]x=\frac{1}{2}[/tex] or [tex]x=2[/tex]
Jamal simplified the expression √75x^5y^8 where x≥ 0 and y≥0. √75x^5y^8 = √25 times 3 times x^4 times x times y^8 = 5x^2y^2 √3x Which describes the error Jamal made? He should have written the square root of in the answer as , not . He should have written the square root of in the answer as , not . He should have written the 5 inside of the radical in the answer. He should have written the 3 outside of the radical in the answer. Mark this and return
Answer:
He should have written the square root of [tex]y^8[/tex] in the answer as [tex]y^4[/tex], not [tex]y^2[/tex]
Step-by-step explanation:
We need to remember that:
[tex]\sqrt[n]{x^n}=x[/tex]
The Product of powers property states that:
[tex](a^m)(a^n)=a^{(m+n)}[/tex]
The Power of a power a property states that:
[tex](a^m)^n=a^{(mn)}[/tex]
Let's check the procedure made by Jamal to simplify the expression [tex]\sqrt{75x^5y^8 }[/tex] where [tex]x\geq0[/tex] and [tex]y\geq0[/tex]:
[tex]=\sqrt{25*3*x^4*x*y^8}[/tex] (This is correct)
[tex]5x^2y^2\sqrt{3x}[/tex] (Jamal made a mistake)
The correct procedure is:
[tex]=\sqrt{25*3*x^4*x*y^8}[/tex]
[tex]=5x^2y^4\sqrt{3x}[/tex]
Because:
[tex]\sqrt{y^8}=\sqrt{(y^4)^2}=y^4[/tex]
Therefore: He should have written the square root of [tex]y^8[/tex] in the answer as [tex]y^4[/tex], not [tex]y^2[/tex],
Answer:
He should have written the square root of y Superscript 8 in the answer as y Superscript 4, not y squared.
Step-by-step explanation:
its A on Ed
Which points are reflections of each other across both the y-axis
Answer:
Reflect over the y-axis
Step-by-step explanation:
When you reflect a point across the y-axis, the y-coordinate remains the same, but the x-coordinate is transformed into its opposite (its sign is changed).
Notice that B is 5 horizontal units to the right of the y-axis, and B' is 5 horizontal units to the left of the y-axis.
The reflection of the point (x,y) across
the y-axis is the point (-x,y).
How do I plot a decimal on a coordinate plane?
Answer:
To plot a decimal on a coordinate plane you plot it between the two whole numbers its close to.
Step-by-step explanation: