34.) If a quadrilateral is a parallelogram and the diagonals are perpendicular, then it must be a rectangle.

A. True
B. False

Answers

Answer 1
Answer: False

The diagonals are perpendicular, so the figure is a rhombus. The rhombus is only a rectangle if it is a square as well. If the rhombus is not a square, then it cannot be a rectangle.
Answer 2

Answer:

The correct answer is: False


Related Questions

What does it mean if two angles are congruent?

Answers

If two angles are congruent, then they are at the same degree. For example, if one angle is 20 degrees, and another is 20 degrees, then they are congruent. Hope this helps!

Does a regular hexagon have 2 parallel sides

Answers

No because they are all connected making them intersect each other 
No because the hexagon all side are connect to each other . Parallel are separated with two different lines. Hope if it help.

The sum of the two numbers is 50 and their difference is 4 what are the two numbers

Answers

27 and 23

x+y=50
x-y=4

If you substitute them:
27+23=50
50=50

27-23=4
4=4

Find the least common multiple of 3,4,5,6,10,15

Answers

The least common multiple for 3, 4, 5, 6, 10, and 15 is 60. 
the least common mulitiple is 5

Point G is between points F and H. FH = 102, FG = 5x + 9, and HG = 9x − 5. Show your work.
A.) What is the value of x ?
B.) What is the length of ̅̅̅̅FG?
C.) What is HG?

Answers

Refer to the diagram shown below.

FH = FG + GH, therefore
(5x + 9) + (9x - 5) = 102
5x + 9 + 9x - 5 = 102
14x + 4 = 102
Subtract 4 from each side.
14x = 98
Divide each side by 14.
x = 7

FG = 5x + 9 = 5*7 + 9 = 35 + 9 = 44
HG = 9x - 5 = 9*7 - 5 = 63 - 5 = 58

Answers:
Part A)  x = 7
Part B) FG = 44
Part C) HG = 58

How many lines of symmetry does a regular polygon with 12 sides have?

Answers

6, because a 12 sided shape can have six lines drawn down it from the vertex points.

The measures of the 3 sides of a triangle can be represented by algebraic expressions x, 3x-1, and 4x+2.the perimeter of the triangle is 81inches. What are the lengths of the sides of the triangle?

Answers

x + 3x - 1 + 4x + 2 = 81
(add all the like terms)
8x + 1 = 81
8x = 81 - 1
8x = 80
x = 80/8
x = 10

The length of a rectangular garden is 3yd more than twice it’s width. The perimeter of the garden is 36yd. What are the width and length of the garden?

Answers

2L + 2W = 36
2(3+2W) + 2W = 36
6 + 4W + 2W = 36
6W + 6 = 36
        -6  = -6
6W=30
W= 30/6 = 5     L= 3 + 2W = 3 +2 (5) = 3 +10= 13

Width is 5
Length is 13


1/4=1/4h + 4
I understand how to do the 2-step equations, but not the ones with 2 fractions.

Answers

1/4 = 1/4h+4

Mulitpily by 4 on both sides.

1= h+16

subtract 16 on both sides.

-15=h

Answer: h= -15

Why do two negative numbers multiplied equal a positive?

Answers

Write these steps down

Positive times positive=positive
Negative times positive=negative
negative times negative= positive

when any two numbers that are negative it will always equal a positive.
Its a rule for math.

12. A race car is running practice laps in preparation for an upcoming race. To judge how

the car is performing, the crew takes measurements of the car’s speed S(t) (in miles per

hour, or mph) every minute. The measurements are given in the table below.


t (minutes) S(t) (mph)

0 201

1 205

2 208

3 214

4 218

5 212

6 219

7 223

8 220

9 221

10 217

11 218


A. Use the trapezoid rule with 4 equal subdivisions to approximate the total distance the car

traveled (in miles) over the first 12 minutes.


B.Find one approximation for Sv(6), including the units. Explain what this quantity means in

the context of the problem.


C. What was the car’s average speed in mph over the first 12 minutes? If the car needs to

have an average speed of 210 mph to qualify for the race, is it currently running fast enough

to qualify?

Answers

My response is very long so I will comment it below.
Final answer:

The student's problem involves the use of the trapezoid rule to approximate total distance traveled by a race car, finding the speed at a particular time point (Sv(6)), and calculating the car's average speed to see if it meets the qualifying speed.

Explanation:

To solve this problem, we need to conduct several mathematical operations. Firstly, let's use the trapezoid rule to approximate the total distance the car traveled in 12 minutes. Then we'll find an approximation for Sv(6) and explain its meaning. Finally, we'll calculate the car's average speed and determine if it's fast enough to qualify for the race.

For the trapezoid rule, remember that it's structured as (b-a)/2n [f(x0) + 2f(x1) + 2f(x2) + ... + 2f(xn) + f(xn+1)]. We'll create 4 equal subdivisions over the first 12 minutes. Due to the lack of full data set, let's suppose the missing speeds are similar to the closely related ones provided.Sv(6) stands for the velocity, or speed, at the 6th minute, which is 219 mph. This represents how fast the car was going at that specific moment.To get the average speed, add up all the speeds given and divide by the number of measurements. If the resultant speed is at least 210 mph, then the car is fast enough to qualify for the race.

Learn more about Trapezoid Rule & Average Speed here:

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Two slices of Dans Famous pizza have 230 calories how many calories would you expect to be in 5 slices of the same pizza

Answers

575= Calories

2p=230
divide 2
p=115

Each slice of pizza is 115 calories.

5p=c
5(115)=c
575= Calories
There are 1,150 calories in 5 slices of pizzas.

The length of a rectangle is four more than five times its width. its perimeter is 4444 inches. find its dimensions​ (length and​ width).

Answers

L=5W+4
L+L+W+W=4444
Replace L with 5W+4: 5W+4+5W+4+W+W=4444
12W+8=4444
12W=4436
W=369 and 2/3
L=1852 and 1/3

Alvin's age is three times elga's age. the sum of their ages is 32 . what is elga's age

Answers

Final answer:

Elga's age is determined by setting up an equation E + 3E = 32 and solving for E. After simplifying, we find that Elga is 8 years old.

Explanation:

To solve this problem, we can use algebra to set up two equations based on the information given that Alvin's age is three times Elga's age and the sum of their ages is 32.

Let's let E represent Elga's age. According to the problem, Alvin's age will be 3E because it is three times Elga's age. We can write the following equation to represent the sum of their ages:

E + 3E = 32

Combining like terms, we have:

4E = 32

Dividing both sides by 4 to solve for E, we get:

E = 32 / 4

Therefore, Elga's age is:

E = 8

Elga is 8 years old.

The rate of change is constant in each table. Find the rate of change. Explain what the rate of change means for the situation. time (hours) 4, 6, 8, 10 distance (miles) 212, 318, 424, 530

Answers

[tex]\bf \begin{array}{ccll} \stackrel{\stackrel{x}{hours}}{time}&\stackrel{\stackrel{y}{miles}}{distance}\\ \text{\textemdash\textemdash\textemdash}&\text{\textemdash\textemdash\textemdash}\\ 4&212\\ \boxed{6}&\boxed{318}\\ 8&424\\ \boxed{10}&\boxed{530} \end{array}\\\\ -------------------------------[/tex]

[tex]\bf \begin{array}{lllll} &x_1&y_1&x_2&y_2\\ % (a,b) &({{ 6}}\quad ,&{{ 318}})\quad % (c,d) &({{ 10}}\quad ,&{{ 530}}) \end{array} \\\\\\ % slope = m slope = {{ m}}= \cfrac{rise}{run} \implies \cfrac{{{ y_2}}-{{ y_1}}}{{{ x_2}}-{{ x_1}}}\implies \cfrac{530-318}{10-6}\implies \cfrac{212}{4} \\\\\\ \stackrel{\textit{average rate of change}}{\cfrac{53}{1}}[/tex]

recall the top is distance, and the bottom is hours, so 53 miles for every 1 hour.  So the object or vehicle is moving at 53 mph on average.

Answer:

The car travels 53 miles per hour.

Step-by-step explanation:

time (hours)           4       6      8       10

distance (miles)   212   318   424   530

The rate of change can be given as:

[tex]\frac{318-212}{6-4}[/tex] = [tex]\frac{106}{2}[/tex] = 53 mph

[tex]\frac{424-318}{8-6}[/tex] = [tex]\frac{106}{2}[/tex] = 53 mph

Hence, the rate of change is 53 mph or we can say the car travels 53 miles per hour.

Please someone help

Answers

25° because both sides have the same length
The answer is C because, since angle J is equal to angle L and angle J is 25 degrees, L should be 26 degrees too.

A package is in the shape of a triangular prism. The bases are right triangles with perpendicular legs measuring 9 centimeters and 12 centimeters. The distance between the bases is 10 centimeters. What is the surface area of the triangular prism? square centimeters


Answers

The surface area of the triangular prism is 468 (square cm).

The surface area A of a triangular prism is given by the formula:

[tex]\[ A = 2A_{\text{base}} + P_{\text{base}} \times h \][/tex]

where:

- [tex]\( A_{\text{base}} \)[/tex] is the area of one of the triangular bases,

- [tex]\( P_{\text{base}} \)[/tex] is the perimeter of one of the triangular bases,

- h is the distance between the bases.

The area of a right triangle is given by:

[tex]\[ A_{\text{base}} = \frac{1}{2} \times \text{base} \times \text{height} \][/tex]

And the perimeter of a right triangle is the sum of the lengths of its three sides.

Given that the legs of the right triangles forming the bases are 9 cm and 12 cm, and the distance between the bases is 10 cm, we can calculate the surface area.

1. Area of the triangular base [tex](\(A_{\text{base}})\)[/tex]:

[tex]\[ A_{\text{base}} = \frac{1}{2} \times 9 \times 12 \][/tex]

2. Perimeter of the triangular base [tex](\(P_{\text{base}})\)[/tex]:

[tex]\[ P_{\text{base}} = 9 + 12 + \sqrt{9^2 + 12^2} \][/tex]

3. Surface area of the triangular prism A:

[tex]\[ A = 2 \times A_{\text{base}} + P_{\text{base}} \times 10 \][/tex]

Calculate each part and find the total surface area.

[tex]\[ A_{\text{base}} = \frac{1}{2} \times 9 \times 12 = 54 \, \text{cm}^2 \][/tex]

[tex]\[ P_{\text{base}} = 9 + 12 + \sqrt{9^2 + 12^2} = 9 + 12 + 15 = 36 \, \text{cm} \][/tex]

[tex]\[ A = 2 \times 54 + 36 \times 10 = 108 + 360 = 468 \, \text{cm}^2 \][/tex]

So, the surface area of the triangular prism is [tex]\(468 \, \text{cm}^2\)[/tex].

14. For the equation 5x + 36 = x, which value could be a solution? A)–9 B) 5 C)9 D)–5

Answers

5x + 36 = x

5x (-5x) + 36 = x (-5x)

36/-4 = -4x/-4

x = -9

A) -9

hope this helps

Combine like terms.


9 + 3x – 9x + 16

A.19x

B.3x + 16

C.25 – 6x

D.18x + 3x + 16

Answers

you subtract 3x-9x=-6x
then you add 9+16=25
last you put the two together to get 25-6x so the answer is C

Find the coordinates of the midpoint of the segment whose endpoints are given . e(4,-4) , f (1,7)

Answers

Let g(x,y) be the midpoint of the segment ef;
So, x = (4+1)/2; then x = 5/2;
y = (-4+7)/2; then y = 3/2;
Finally, g(5/2,3/2).

A local charity sponsors a 5K race to raise money. It receives $25 per race entry and $5,000 in donations, but it must spend $5 per race entry to cover the cost of the race. Write and solve an inequality to determine the number of race entries the charity needs to raise more than $25,000. Show your work!

Question 1 options:

Spell check

Answers

they receive 25 per entry but 5 goes towards the cost of the race

 so 25-5 = 20 per entry is for the charity

 so 20x + 5000 = 25000

subtract 5000 from each side

20x= 20000

 divide both sides by 20

 x = 20000/ 20  

x = 1000

 they need at least 1000 entries to make 25000

 so to make more than 25000, they need 1001 entries

measures of an angle and five times it’s complement is 298 what is the measure of the angle

Answers

complementary angles add up to 90°, therefore, let's say the angles are "a" and "b".

so the sum of "a" plus " 5 times its complement", that is 5 times "b" is 298, so a + 5b = 298.

now, if a + b = 90, that means b = 90 - a.

therefore

[tex]\bf a+5b=298\implies a+5(90-a)=298\implies a+450-5a=298 \\\\\\ -4a=-152\implies a=\cfrac{-152}{-4}\implies a=38[/tex]

Write the ratio using fraction notation and reduce.
20 minutes to 1 hour

(a) 20
(b )1/3
(c) 1/20
(d) 3

Answers

Since there are 60 minutes in an hour, we can write 20 minutes/1 hour as 20 minutes/60 minutes. As 20*3=60, 20/60=1/3

HELPS PLS ryad borrowed $1450 and made 18 payment of $95.25 how much did he pay in interest?

Answers

First calculate total payments
18×95.25=1,714.5

After that to find the interest you just subtract the amount borrowed from the total payments
Interest=1,714.5−1,450=264.5

Hope it helps!

which of the following equations represents a proportional relationship? Choose all that apply.
A. x=2y
B.a = 1/3b
C.4x=y-2
D.7/3x=n
E.1/2=1/4

Answers

The options A, B, and D have a proportional relationship.

What is a proportional relationship?

It is the relationship between two variables where their ratios are equivalent.

Consider the first equation, x = 2y.

It can be written like the ratio of x and y.

i.e              [tex]\frac{x}{y} -\frac{2}{1}[/tex]

So, option A is proportional at x = 2 and y = 1.

For option B, It can rewrite as

[tex]\frac{a}{b} =\frac{1}{3}[/tex]

So, option B is proportional when a = 1 and b = 3.

Option C is not proportional since it can't be written as a ratio.

Option D can be written as

[tex]\frac{7}{3} =\frac{n}{x}[/tex]

It is proportional when n = 7 and x = 3.

Option E is not proportional since it is not equal.

Therefore the proportional options are A,B, and D.

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What is the value of x? (7x-8) (6x+11)

Answers

the answer is
x=19  
 
7x-8=6x+11
   +8     +8
 
7x=6x+19
-6x -6x

x=19




we know that

Vertical angles are a pair of opposite and congruent angles formed by intersecting lines

In this problem

[tex](7x-8)=(6x+11)[/tex] --------> by vertical angles

Solve for x

Combine like terms

[tex](7x-6x)=(11+8)[/tex]

[tex]x=19\ degrees[/tex]

therefore

the answer is

the value of x is [tex]19\ degrees[/tex]

What would be an appropriate measure to describe the depth of a lake?



miles

cubic centimeters

milliliters

feet

Answers

Feet

cm^3 is volume... miles is too big... mm is to small

Answer:

Feet is the appropriate unit.

Step-by-step explanation:

Feet will be an appropriate measure to describe the depth of a lake.

Miles is a very large unit usually used to describe distance between two places.

Cubic centimeters is a unit of volume.

Millimeters is a very small unit used to describe small objects like the diameter of a penny etc.

Therefore, feet is the most appropriate unit to measure the depth of the lake.

what is the measure on angle A?
- 110
-70
250
55

Answers

The answer would be 70 however it would be negative sry this isnt very helpful

Calculus: Help ASAP
Evaluate exactly the value of the integral from negative 1 to 0 of the product of the cube of the quantity 4 times x to the 6th power plus 2 times x and 12 times x to the 5th power plus 1, dx. Your work must include the use of substitution and the antiderivative.

Answers

[tex]\bf \displaystyle \int\limits_{-1}^{0}~(4x^6+2x)^3(12x^5+1)\cdot dx\\\\ -------------------------------\\\\ u=4x^6+2x\implies \cfrac{du}{dx}=24x^5+2\implies \cfrac{du}{2(12x^5+1)}=dx\\\\ -------------------------------\\\\ \displaystyle \int\limits_{-1}^{0}~u^3\underline{(12x^5+1)}\cdot\cfrac{du}{2\underline{(12x^5+1)}}\implies \cfrac{1}{2}\int\limits_{-1}^{0}~u^3\cdot du\\\\ -------------------------------\\\\[/tex]

[tex]\bf \textit{now, we'll change the bounds, using u(x)} \\\\\\ u(-1)=4(-1)^6+2(-1)\implies u(-1)=2 \\\\\\ u(0)=4(0)^6+2()\implies u(0)=0\\\\ -------------------------------\\\\ \displaystyle \cfrac{1}{2}\int\limits_{2}^{0}~u^3\cdot du\implies \left. \cfrac{1}{2}\cdot \cfrac{u^4}{4} \right]_{2}^{0}\implies \left. \cfrac{u^4}{8} \right]_{2}^{0}\implies [0]-[2]\implies -2[/tex]

Answer:

2.264 (3 d.p.)

Step-by-step explanation:

Given integral:

[tex]\displaystyle \int^0_{-1} \left(4x^6+2x\right)^3\left(12x^5+1\right)\;\text{d}x[/tex]

First, evaluate the indefinite integral using the method of substitution.

[tex]\textsf{Let} \;\;u = 4x^6+2x[/tex]

Find du/dx and rewrite it so that dx is on its own:

[tex]\dfrac{\text{d}u}{\text{d}x}=24x^5+2 \implies \text{d}x=\dfrac{1}{24x^5+2}\; \text{d}u[/tex]

Rewrite the original integral in terms of u and du, and evaluate:

[tex]\begin{aligned}\displaystyle \int\left(4x^6+2x\right)^3\left(12x^5+1\right)\;\text{d}x&=\int \left(u\right)^3\left(12x^5+1\right)\cdot \dfrac{1}{24x^5+2}\; \text{d}u\\\\&=\int \left(u\right)^3\left(12x^5+1\right)\cdot \dfrac{1}{2(12x^5+1)}\; \text{d}u\\\\&=\int \dfrac{u^3\left(12x^5+1\right)}{2(12x^5+1)}\; \text{d}u\\\\&=\displaystyle \int \dfrac{u^3}{2}\; \text{d}u\\\\&=\dfrac{u^{3+1}}{2(3+1)}+C\\\\&=\dfrac{u^4}{8}+C\end{aligned}[/tex]

Substitute back u = 4x⁶ + 2x:

                                              [tex]=\dfrac{(4x^6+2x)^4}{8}+C[/tex]

Therefore:

[tex]\displaystyle \int \left(4x^6+2x\right)^3\left(12x^5+1\right)\;\text{d}x=\dfrac{(4x^6+2x)^4}{8}+C[/tex]

To evaluate the definite integral, we must first determine any intervals within the given interval -1 ≤ x ≤ 0 where the curve lies below the x-axis. This is because when we integrate a function that lies below the x-axis, it will give a negative area value.

Find the x-intercepts by setting the function to zero and solving for x.

[tex]\left(4x^6+2x\right)^3\left(12x^5+1\right)=0[/tex]

Therefore:

[tex]\begin{aligned}\left(4x^6+2x\right)^3&=0\\4x^6+2x&=0\\x(4x^5+2)&=0\end{aligned}[/tex]

[tex]x=0[/tex]

[tex]\begin{aligned}4x^5+2&=0\\4x^5&=-2\\x^5&=-\frac{1}{2}\\x&=\sqrt[5]{-\dfrac{1}{2}}\end{aligned}[/tex]

[tex]\begin{aligned}12x^5+1&=0\\12x^5&=-1\\x^5&=-\dfrac{1}{12}\\x&=\sqrt[5]{-\dfrac{1}{12}}\end{aligned}[/tex]

Therefore, the curve of the function is:

Below the x-axis between -1 and ⁵√(-1/2).Above the x-axis between ⁵√(-1/2) and ⁵√(-1/12).Below the x-axis between ⁵√(-1/12) and 0.

So to calculate the total area, we need to calculate the positive and negative areas separately and then add them together, remembering that if you integrate a function to find an area that lies below the x-axis, it will give a negative value.

Integrate the function between -1 and ⁵√(-1/2).

As the area is below the x-axis, we need to negate the integral so that the resulting area is positive:

[tex]\begin{aligned}A_1&=-\displaystyle \int_{-1}^{\sqrt[5]{-\frac{1}{2}}} \left(4x^6+2x\right)^3\left(12x^5+1\right)\;\text{d}x\\\\&=-\left[\dfrac{(4x^6+2x)^4}{8}\right]_{-1}^{\sqrt[5]{-\frac{1}{2}}}\\\\&=-\left[\left(\dfrac{\left(4\left(\sqrt[5]{-\frac{1}{2}}\right)^6+2\left(\sqrt[5]{-\frac{1}{2}}\right)\right)^4}{8}\right)-\left(\dfrac{(4(-1)^6+2(-1))^4}{8}\right)\right]\\\\&=-[0-2]\\\\&=2\end{aligned}[/tex]

Integrate the function between ⁵√(-1/2) and ⁵√(-1/12).

[tex]\begin{aligned}A_2&=\displaystyle \int_{\sqrt[5]{-\frac{1}{2}}} ^{\sqrt[5]{-\frac{1}{12}}} \left(4x^6+2x\right)^3\left(12x^5+1\right)\;\text{d}x\\\\&=\left[\dfrac{(4x^6+2x)^4}{8}\right]_{\sqrt[5]{-\frac{1}{2}}}^{\sqrt[5]{-\frac{1}{12}}}\\\\&=\left(\dfrac{\left(4\left(\sqrt[5]{-\frac{1}{12}}\right)^6+2\left(\sqrt[5]{-\frac{1}{12}}\right)\right)^4}{8}\right)-\left(\dfrac{\left(4\left(\sqrt[5]{-\frac{1}{2}}\right)^6+2\left(\sqrt[5]{-\frac{1}{2}}\right)\right)^4}{8}\right)\\\\\end{aligned}[/tex]

     [tex]\begin{aligned}&=\dfrac{625}{648\sqrt[5]{12^4}}-0\\\\&=0.132117398...\end{aligned}[/tex]

Integrate the function between ⁵√(-1/12) and 0.

As the area is below the x-axis, we need to negate the integral so that the resulting area is positive:

[tex]\begin{aligned}A_3&=-\displaystyle \int_{\sqrt[5]{-\frac{1}{12}}}^0 \left(4x^6+2x\right)^3\left(12x^5+1\right)\;\text{d}x\\\\&=-\left[\dfrac{(4x^6+2x)^4}{8}\right]_{\sqrt[5]{-\frac{1}{12}}}^0\\\\&=-\left[\left(\dfrac{(4(0)^6+2(0))^4}{8}\right)-\left(\dfrac{\left(4\left(\sqrt[5]{-\frac{1}{12}}\right)^6+2\left(\sqrt[5]{-\frac{1}{12}}\right)\right)^4}{8}\right)\right]\\\\&=-\left[0-\dfrac{625}{648\sqrt[5]{12^4}}\right]\\\\&=\dfrac{625}{648\sqrt[5]{12^4}}\\\\&=0.132117398...\\\\\end{aligned}[/tex]

To evaluate the definite integral, sum A₁, A₂ and A₃:

[tex]\begin{aligned}\displaystyle \int^0_{-1} \left(4x^6+2x\right)^3\left(12x^5+1\right)\;\text{d}x&=2+2\left( \dfrac{625}{648\sqrt[5]{12^4}}\right)\\\\&=2+ \dfrac{625}{324\sqrt[5]{12^4}}\right}\\\\&=2.264\; \sf (3\;d.p.)\end{aligned}[/tex]

Why cant you take the inverse of a matrix with det = 0?

Answers

Because taking the inverse of a matrix A involves multiplying a matrix by the scalar value 1/det(A), and that value is undefined when det(A)=0

A matrix with a determinant of zero is called a singular matrix and doesn't have an inverse because it indicates the system of equations it represents doesn't have a unique solution, and the transformation it performs is not reversible.

When a matrix has a determinant of zero (det A = 0), it is classified as a singular matrix and is not invertible. This characteristic implies that the matrix cannot be used to find unique solutions for a set of linear equations because such a matrix corresponds to a system of equations that has either no solution or an infinite number of solutions.

The ability to have an inverse matrix is crucial as it allows us to solve matrix equations and essentially 'undo' the transformations applied by the original matrix.

The reason why a zero determinant indicates the absence of an inverse lies in the mathematics of linear transformations.

A determinant of zero suggests that the transformation associated with the matrix collapses the dimensionality of the space, which means some information about the original vectors is lost, and hence, an inverse operation to recover the original vectors cannot exist.

To further illustrate this, consider the matrix equation AB = I, where A is our original matrix and B is its supposed inverse yielding the identity matrix I. It follows from the properties of determinants that det(AB) = det(A) x det(B).

If det(A) is zero, then the product det(A) x det(B) will also be zero, not equal to 1, which is the determinant of the identity matrix. Therefore, B cannot serve as the inverse of A.

In other words, having a non-zero determinant is a prerequisite for a matrix to have an inverse, as it ensures that the system of equations it represents is solvable and that the matrix transformation is reversible.

Other Questions
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