Your school is sponsoring a pancake dinner to raise money for a field trip. You estimate that 200 adults and 250 children will attend. Let x represent the cost of an adult ticket and y represent the cost of a child ticket.
Write an equation that can be used to find what ticket prices to set in order to raise $3800
Show your work

Answer: 1/16,384 microbes

Step-by-step explanation:

Since the microbes divides every 30minutes, if the microbes divides by half every 30minutes, then after an hour it will divides by another half that is (1/2)of 1/2 to give 1/4.

Subsequently after another hour, the microbes will reduces to 1/4 of its remains (i.e 1/4) to give 1/16.

Since the denominator is increasing geometrically each hour.

Looking at the trend;

After 1hr = 1/4 of the original microbe = 1/4

After 2 hrs = 1/4 of the remaining microbe = 1/4 of 1/4 = 1/16

Generalizing, we will let the number of hours be n

According to the progression, 1, 1/4,1/16,...n

Since its a Geometric Progression, nth term = ar^n-1

Where a is the first term = 1

r is the common ratio = 1/4

n is the number of hours of decay

After 8hours, the microbes will have been divided by

(1)(1/4)^8-1

= (1/4)^7

= 1/16,384 microbes

Answer:

1/2^16 or 0.0000152588 microbes

Step-by-step explanation:

Assuming you start with just one microbe that divides every 30 minutes.

This means that the half life of the microbe is 30 minutes or 0.5hours

The interpretation of this half life is that after every half-life, which in this case is 30 minutes, half of the microbe will be gone, and half will remain.

It follows that after another half hour the amount remaining will be

1/2 of 1/2= 1/4 microbes

Thus after 8 hours, there would have been (8/0.5)=16 half lives.

Therefore the amount of microbes remaining will be 1/2^16 of 1 = 0.0625

Alternatively, we could solve the differential equation

dM/dt=kM, where dM/dt is the rate of decay, and M is the amount at any time t, k is the decay constant

Solution of this first order differential equation by separating the variables and integrating yields {dM/M={kt+c, lnM=kt+c, and ......

M=Moexp(-kt)

The initial value Mo=1, when t=0, and given value M=0.5, t=0.5h yields the value of k as follows

0.5=exp(-k*0.5)

ln(0.5)=-k*0.5

k=1.386

After any time time, thus the given expression holds

M=exp(-1.386t)

Thus after 8 hours, the microbes remaining will be

M=exp(-1.386t)=exp(-1.386*8)=0.000152588 microbes.

Answer:

The opportunity cost will be 3 cars

So option (d) will be correct answer

Step-by-step explanation:

The opportunity is cost is best characterized as the following best action done without, it is something we give up to gain another.

For instance the opportunity cost of going to class can be the pleasure from watching movie, or spending time with companions or something different. The opportunity  cost can be determined by isolating what you forgone by what you gain.

So opportunity cost [tex]=\frac{12}{4}=3cars[/tex]

So option (d) will be the correct answer

Final answer:

Pete's opportunity cost of producing one truck is 3 cars, which is found by dividing Pete's car production rate by his truck production rate (12 cars per hour / 4 trucks per hour).

Explanation:

Pete's opportunity cost of producing one truck can be determined by looking at the alternative production of cars he could have achieved in the same amount of time. Since Pete can produce 12 cars per hour or 4 trucks per hour, we can set up a ratio of cars to trucks based on his production abilities. To find the opportunity cost of one truck, we divide the number of cars Pete can make by the number of trucks, which is 12/4, giving us 3. Hence, Pete's opportunity cost of one truck is 3 cars. This calculation is similar to how opportunity cost is determined in examples such as the production possibility frontier, where the slope shows the trade-off between two different products.

Answer

Domain=[80, 100] ie. both of them inclusive.

Step-by-step explanation:

Albert has total $105.

Let the cost of a product be c.

Therefore, the total cost of a product after the delivery and all is represented by a function f(c)

f(c)=c+[tex]\frac{c}{20}[/tex]

f(c)=[tex]\frac{21c}{20}[/tex]

The domain, of the function is the no. of possible values of c that can satisfy the equation.

Now, lets check the maximum price of the product that Albert can buy.

f(c)=105

[tex]\frac{21c}{20}[/tex]=105

c=$100

As, the minimum price of a product of is $80 , the domain needs to start from here. And it will go on till $100.

Domain=[80, 100]

Answer: the maximum number of visits would be 38

Step-by-step explanation:

A person can pay $7 for a membership to the history museum and then go to the museum for just $1 per visit.

Let x represent the number of visits that the person makes to the museum after paying for the membership. This means that if the person makes x visits to the history museum, the total cost would be

7 + x

If a member of the history museum pays a total of $45. It means that the number of visits that he can make to the history museum would be

7 + x = 45

x = 45 - 7 = 38

Answer:

[tex]y+6=(x+1)^{2}[/tex]

Step-by-step explanation:

we have

[tex]y=x^{2}+2x-5[/tex]

This is the equation of a vertical parabola open upward (because the leading coefficient is positive)

The vertex is a minimum

The equation of a vertical parabola into vertex form is

[tex]y-k=a(x-h)^2[/tex]

where

(h,k) is the vertex of the parabola

Convert the equation into vertex form

Move the constant term to the left side

[tex]y+5=x^{2}+2x[/tex]

Complete the square

[tex]y+5+1=x^{2}+2x+1[/tex]

[tex]y+6=x^{2}+2x+1[/tex]

Rewrite as perfect squares

[tex]y+6=(x+1)^{2}[/tex]

therefore

[tex]a=1\\h=-1\\k=-6[/tex]

The vertex is the point (-1,-6)

Answer:

2% area reduction

Step-by-step explanation:

The original area is 18.2*28.5=518.7 sq km

1.2% reduction of 18.2 km is 17.9816 km (18.2-18.2*1.2/100)

0.8% reduction of 28.5 km is 28.272 km (28.5-28.5*0.8/100)

The new are is 17.9816*28.272=508.3757 sq km (98 % of the original area)

Another way is (100-1.2)*(100-0.8) LW/(100*100)=0.98LW (98 % of the original area)

Answer:

Here's the answer ;)

Answer:The number of minutes that Alexandra talked on her cell phone is 120

Step-by-step explanation:

A cell phone company charges a flat rate of 4.75 per month with an additional charge 0.19 per minute. Assuming the total number of minutes of call made for the month is represented by x and the total cost of x minutes of call is y, then

y = 0.19x + 4.75

To determine how many minutes that Alexandra talked on her cell phone if his monthly bill was 27.55, we would substitute y = 27.55 into the equation. It becomes

27.55 = 0.19x + 4.75

0.19x = 27.55 - 4.75 = 22.8

x = 22.8/0.19 = 120 minutes.

Answer:

0.03

Step-by-step explanation:

Anthony can expect to pull out a blue candy 30 times in 150 draws, as each draw has a 1/5 probability of being blue, and the total number of draws is 150.

The question can be answered by calculating the expected frequency of pulling a blue candy based on the probability of drawing a blue candy from the bag. Anthony has 4 blue candies, 6 green candies, and 10 yellow candies, making a total of 20 candies in the bag. Since each draw is independent and the candies are replaced each time, the probability of drawing a blue candy is 4/20 or 1/5.

To find the expected number of times Anthony could pull out a blue candy in 150 tries, we multiply the probability by the number of trials:

Expected blue candies = (Probability of blue candy) x (Number of trials)

Expected blue candies = (1/5) x 150

Expected blue candies = 30

Therefore, Anthony can expect to pull out a blue candy 30 times in 150 draws.

Answer:

[tex]\frac{2\sqrt3}{3}[/tex] [tex]cm^2[/tex]

Step-by-step explanation:

Since [tex]\triangle ABC[/tex] is equilateral triangle, then [tex]\angle A = \pi /3[/tex]

So,

[tex]S_{\triangle ABC} = \frac{2 * 2 * sin(\pi /3)}{2} = \frac{2 * 2 * \sqrt{3}/2}{2} = \sqrt{3}[/tex] [tex]cm^2[/tex]

Then we need to find [tex]S_{\triangle AEF}[/tex] which can be computed by finding length_AF.

Let's call x = length_AF.

By Menelao's Theorem,

[tex]\frac{BE*x*CD}{AE*(2-x)*BD} = \frac{1*x*2}{1*(2-x)*4}  = 1[/tex]

⇒ x = 4/3 cm

Thus,

[tex]S_{\triangle AEF} = \frac{1 * x * sin(\pi /3)}{2} = \frac{1 * 4/3 * \sqrt{3}/2}{2} = 1/\sqrt{3}[/tex] [tex]cm^2[/tex]

To find the area of quadrilateral [tex]BEFC[/tex], we have to subtract [tex]S_{\triangle AEF}[/tex] from [tex]S_{\triangle ABC}[/tex]

Hence,

[tex]S_{BEFC} = S_{\triangle ABC} - S_{\triangle AEF} = \sqrt3 -1/\sqrt3 = \frac{2\sqrt3}{3}[/tex] [tex]cm^2[/tex]

Answer:

It is an obtuse angle.

Step-by-step explanation:

It is not a 180° angle. Because 180° angle forms a straight line.

The given angle is an obtuse angle which means it is greater than 90° and less than 180°

Note that 90° angle is perpendicular angle(interior angles of a rectangle)

That angle can be measured using a protractor.

Final answer:

The student asked for the completion of a Java function to compute the nth Fibonacci number using recursion. The base case for the function is missing, which should return the index when it is either 0 or 1. Two alternatives to improve runtime are memoization and dynamic programming, with an example provided for the latter technique.

Explanation:

The student is asking for the missing code in a recursive Java function to compute the nth Fibonacci number. To complete the base case of the provided function, we should return the index itself because the 0th and 1st Fibonacci numbers are defined as 0 and 1, respectively.

The function should look as follows:

public static int fib(int index) {
   if (index == 0) return 0; // Base case for 0
   if (index == 1) return 1; // Base case for 1
   else // Reduction and recursive calls
       return fib(index - 1) + fib(index - 2);
}

Using this recursive algorithm is inefficient due to its exponential time complexity, represented by O(2^n). To illustrate the concept of reducing computation time, two alternative approaches can be used: memoization and dynamic programming. Memoization stores the results of expensive function calls and reuses them when the same inputs occur again, thus avoiding the need to recompute them. Dynamic programming approaches the problem from a bottom-up perspective, computing and storing the result of smaller subproblems first, which then are used to compute larger ones.

An example of a dynamic programming approach is to use a loop to calculate the sequence iteratively:

public static int fib_loop(int index) {
   if (index == 0) return 0;
   if (index == 1) return 1;
   int a = 0, b = 1, sum;
   for (int i = 2; i <= index; i++) {
       sum = a + b;
       a = b;
       b = sum;
   }
   return b;
}

The time complexity for the iterative solution is O(n), which is significantly faster than the recursive approach. Therefore, fib_loop() can compute Fibonacci numbers much quicker than the recursive fib(). For example, calculating fib(40) using the recursive method can take a significant amount of time, while fib_loop(40) will complete in a fraction of the time due to its linear time complexity.

Answer:

She would have to work 11 hours to get enough money to buy the sneakers

But if you want the hours included for the time she needs to work to pay off the loan she would have to work 8 hours, so all together 19 hours.

Answer:

It would be x ≥ 18

Step-by-step explanation:

Answer: 50%

Step-by-step explanation:

It is estimated that almost 50% of collisions involving a vehicle and a train were at crossings where warning devices such as lights, gates and bells were in working order. This high percentage may be as a result of malfunction of warning devices, because when warning devices malfunction they give wrong signals that could lead to accidents. It could also be as a result of violation or ignorance of traffic rules and warning signals which can also lead to collision.

The question discusses the number of accidents happening at railway crossings despite working warning systems, akin to a problematic intersection at Clay Street and Eagle Avenue that saw many accidents despite traffic rules. While specific statistics aren't given, such cases highlight the importance of adhering to traffic signals and safety measures for both drivers and pedestrians.

The question seems to be related to railroad crossing safety, specifically the effectiveness of warning devices like bells, lights, and gates. While the exact percentage is not provided, studies show that a significant proportion of vehicle-train collisions occur at crossings where these warning systems are fully functional. Like the traffic signal installed at the intersection of Clay Street and Eagle Avenue to prevent the high number of accidents, these warning devices aim to control vehicular and pedestrian traffic. Unfortunately, they may not always be heeded, and thus accidents occur.

Similar to the situation in the Clay Street and Eagle Avenue intersection, safety measures only work if they're respected. A traffic signal might reduce accidents, but only if drivers and pedestrians heed it. Unfortunately, despite railroad crossing warnings, accidents still occur, often due to negligence, recklessness, or distraction.

It emphasizes the importance of traffic rules and safety measures in our day to day life. Be it the students crossing the road or vehicles moving in traffic, the role of traffic signals and warning signs is critical. We must remember these are not there to restrict us, but to ensure everyone's safety.

https://brainly.com/question/33417376

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Answer:

For the given circle, the center is at (-7,4)  and radius is 7

Step-by-step explanation:

Given equation of the circle is [tex](x+7)^2+(y-4)^2=49\hfill (1)[/tex]

To find the center and radius of given circle with the help of its equation:

Equation of the circle is of the form

(x-h)^2+(y-k)^2=r^2\hfill (2)[/tex] with center at (h,k) and radius is r.

Given [tex](x+7)^2+(y-4)^2=49[/tex]

The above equation can be written as,

[tex](x-(-7))^2+(y-4)^2=7^2\hfill (3)[/tex]

Now comparing the equations (2) and (3) we get

h=-7, k=4 and r=7

Therefore center at (h,k) is (-7,4) and radius is 7

For the given circle, the center is at (-7,4)  and radius is 7

Answer:

The price of each hamburger is $3

The price of each hot dogs is $2  .

Step-by-step explanation:

Given as :

The total price of 3 hamburger and 2 hot dogs = $13

The total price of 2 hamburger and 5 hot dogs = $16

Let The price of each hamburger = $x

Let The price of each hot dogs = $y

Now, According to question

3 x + 2 y = 13              .........A

2 x + 5 y = 16              .......B

Now, Solving to eq A and B

3 × (2 x + 5 y ) - 2 × (3 x + 2 y ) = 3 × 16 - 2 × 13

Or, (6 x + 15 y) - (6 x + 4 y) = 48 - 26

Or, (6 x - 6 x) + (15 y - 4 y) = 22

Or, 0 + 11 y = 22

∴  y = [tex]\dfrac{22}{11}[/tex]

i.e y = $2

so, The price of each hot dogs = y = $2

Now, Put the value of y into eq B

i.e 2 x + 5 y = 16

or, 2 x + 5 × 2 = 16

or, 2 x = 16 - 10

or, 2 x = 6

∴  x = [tex]\dfrac{6}{2}[/tex]

i.e x = $3

So, The price of each hamburger = x = $3

Hence, The price of each hamburger is $3 and  The price of each hot dogs is $2  . Answer

Answer:

Y = 66x - 1200 will be the equation.

Step-by-step explanation:

This question is incomplete; Here is the complete question.

A charity organization had a fundraiser where they sold each ticket for a fixed price. After selling 200 tickets, they had a net profit of $12,000. They had to sell a few tickets just to cover necessary production costs of $1200.

       Let Y represent the net profit (in dollars) when they have sold c tickets. Complete the equation for the relationship between the net profit and the number of tickets sold.

If the selling price of one ticket is $x, then selling price of 200 tickets

= $200x

Since production cost of the tickets = $1200 and profit earned is $12000

Therefore, Profit = Selling price of x tickets - production cost

12000 = 200x - 1200

200x = 13200

x = $66

Now we can rewrite the equation for c tickets sold and profit earned $Y

Y = 66c - 1200

Answer:

160 basket of each fruit baskets we can make using all fruit.

Step-by-step explanation:

Given:

Oranges comes in bags = 16

Apples comes in bags = 20

bananas come in bags = 32

We need to find the greatest number of fruit baskets that you can make using all fruit.

Also Given:

You have one bag of each fruit basket must be identical.

So we will first find the least common multiple of all the numbers we get;

20 = 20,40,60,80,100,120,140,160

16 = 16,32,48,64,80,96,112,128,144,160

32 = 32,64,96,128,160

The least common multiple is 160.

Hence we can say that, 160 basket of each fruit baskets we can make using all fruit.

Answer:

  [tex]h_1(t)=-16t^2+154[/tex]

Step-by-step explanation:

Put the initial height of ball 1 into the given formula:

  [tex]h_1(t)=-16t^2+154[/tex]

Answer:

a. A minimum of 300

Step-by-step explanation:

If her bill  is $142 then it is a sum of the flat rate plus the money she pays for all the smses she sent. As an equation, it can be expressed this way

106 + 0.12x = 142  where x  is the number of smses

0.12x = 36

x = 300 smses

So if we were told that she pays $142 per month, we'd know that she sends 300 smses. But we are told she pays AT LEAST $142 so there is a possibility that she sends even more than 300 smses

Answer:

[tex] 2b+f = 8[/tex]   (1)

[tex]3b+f=11[/tex]   (2)

[tex] b = 11-8=3[/tex]

[tex]f= 8-2(3) = 8-6 =2[/tex]

Step-by-step explanation:

For this case we can put some notation

Let b= dozen bagels and f=  delivery fee

And for this case we know that "On Monday, they delivered two dozen bagels, b, to an office at a total cost of $8", so then the total taling in count the delivery fee we have this:

[tex] 2b+f = 8[/tex]

And for the other part "On Tuesday, three dozen bagels were delivered at a total cost of $11", we can write the expression like this:

[tex]3b+f=11[/tex]

And our system of equations would be:

[tex] 2b+f = 8[/tex]   (1)

[tex]3b+f=11[/tex]   (2)

If we solve for f from equation (1) we got:

[tex]f= 8-2b[/tex]

And if w replace this into equation (2) we got:

[tex]3b+8-2b=11[/tex]  

[tex] b = 11-8=3[/tex]

And solving for f we got:

[tex]f= 8-2(3) = 8-6 =2[/tex]

Answer:

The dimensions of the drawing are 10 units by 8 units

Step-by-step explanation:                        

we know that

The scale drawing is [tex]\frac{1}{15}\ \frac{unit}{feet}[/tex]

That means ---> 1 unit in the drawing represent 15 feet in the actual

To find out the dimensions of the drawing, multiply the actual dimensions by the scale drawing

so

[tex]150\ ft=150(\frac{1}{15})=10\ units[/tex]

[tex]120\ ft=120(\frac{1}{15})=8\ units[/tex]

therefore

The dimensions of the drawing are 10 units by 8 units

The equation of the least squares regression line (LSRL) predicting sodium level from the number of calories in beef hot dogs is Sodium Level (mg) = 37.77 mg + 4.077 mg/calories × Calories.

The equation of the least squares regression line (LSRL) predicting sodium level from the number of calories in beef hot dogs can be determined using the given statistics and the formula for the slope (b) of the LSRL:

b = r (sy/sx)

Where r is the correlation coefficient, sy is the standard deviation of the y-values (sodium levels), and sx is the standard deviation of the x-values (calories).

Given that r = 0.887, sy = 102.43 mg, and sx = 22.64 calories, we can calculate the slope (b):

b = 0.887 (102.43 mg / 22.64 calories) = 4.077 mg/calories

Then, we can use the y-intercept (a) in the equation y = a + bx, where a = y-bar - b*x-bar.

Given that the average sodium level y-bar = 401.15 mg and the average number of calories x-bar = 156.85 calories, the y-intercept (a) will be:

a = 401.15 mg - (4.077 mg/calories * 156.85 calories) = 37.77 mg

Therefore, the equation of the LSRL is:

Sodium Level (mg) = 37.77 mg + 4.077 mg/calories × Calories

Answer: UTS is similar to UQR, second choice

The other choices refer to the same triangle but we have to have corresponding vertices in the same order.  U corresponds to itself, so has to be listed first in the similar triangle.   T corresponds to Q and S to R, so UQR is our answer.

Answer:

whole numbers can be written in fraction form. But fraction can or cannot be whole number.

Answer is fraction.

Step-by-step explanation:

As, the fraction number is in the form of [tex]\frac{p}{q}[/tex] and the first number is whole number [tex](a)[/tex].

when fraction multiply by whole number,

[tex]\frac{p}{q} \times a=\frac{a \times p}{q}[/tex] is fraction.

For example, [tex]p=2,q=3 \ and \ a=4[/tex]

[tex]\frac{p}{q} \times a=\frac{4 \times 2}{3}[/tex]

[tex]\frac{p}{q} \times a=\frac{8}{3} \Rightarrow \ fraction[/tex]

For example, [tex]p=3,q=5 \ and \ a=5[/tex]

[tex]\frac{p}{q} \times a=\frac{5 \times 3}{5}[/tex]

[tex]\frac{p}{q} \times a=\frac{3}{1} \Rightarrow \ whole \ number[/tex]

Answer:

At the end of 6 years, he would have paid $13985.6

Step-by-step explanation:

Initial amount taken as load is $10,000 This means that the principal

P = 10000

It was compounded annually. This means that it was cam pounded once in a year. So

n = 1

The rate at which the principal was compounded is 5.75%. So

r = 5.75/100 = 0.0575

it takes you six years to pay off the loan. So

t = 6

The formula for compound interest is

A = P(1+r/n)^nt

A = total amount of money that you would have paid back by the end of the six years. Therefore

A = 10000 (1+0.0575/1)^1×6

A = 10000(1.0575)^6 = $13985.6

Answer:

Part A) [tex]sin(\alpha)=\frac{4}{7},\ cos(\beta)=\frac{4}{7}[/tex]

Part B) [tex]tan(\alpha)=\frac{4}{\sqrt{33}},\ tan(\beta)=\frac{4}{\sqrt{33}}[/tex]

Part C) [tex]sec(\alpha)=\frac{7}{\sqrt{33}},\ csc(\beta)=\frac{7}{\sqrt{33}}[/tex]

Step-by-step explanation:

Part A) Find [tex]sin(\alpha)\ and\ cos(\beta)[/tex]

we know that

If two angles are complementary, then the value of sine of one angle is equal to the cosine of the other angle

In this problem

[tex]\alpha+\beta=90^o[/tex] ---> by complementary angles

so

[tex]sin(\alpha)=cos(\beta)[/tex]

Find the value of [tex]sin(\alpha)[/tex] in the right triangle of the figure

[tex]sin(\alpha)=\frac{8}{14}[/tex] ---> opposite side divided by the hypotenuse

simplify

[tex]sin(\alpha)=\frac{4}{7}[/tex]

therefore

[tex]sin(\alpha)=\frac{4}{7}[/tex]

[tex]cos(\beta)=\frac{4}{7}[/tex]

Part B) Find [tex]tan(\alpha)\ and\ cot(\beta)[/tex]

we know that

If two angles are complementary, then the value of tangent of one angle is equal to the cotangent of the other angle

In this problem

[tex]\alpha+\beta=90^o[/tex] ---> by complementary angles

so

[tex]tan(\alpha)=cot(\beta)[/tex]

Find the value of the length side adjacent to the angle alpha

Applying the Pythagorean Theorem

Let

x ----> length side adjacent to angle alpha

[tex]14^2=x^2+8^2\\x^2=14^2-8^2\\x^2=132[/tex]

[tex]x=\sqrt{132}\ units[/tex]

simplify

[tex]x=2\sqrt{33}\ units[/tex]

Find the value of [tex]tan(\alpha)[/tex] in the right triangle of the figure

[tex]tan(\alpha)=\frac{8}{2\sqrt{33}}[/tex] ---> opposite side divided by the adjacent side angle alpha

simplify

[tex]tan(\alpha)=\frac{4}{\sqrt{33}}[/tex]

therefore

[tex]tan(\alpha)=\frac{4}{\sqrt{33}}[/tex]

[tex]tan(\beta)=\frac{4}{\sqrt{33}}[/tex]

Part C) Find [tex]sec(\alpha)\ and\ csc(\beta)[/tex]

we know that

If two angles are complementary, then the value of secant of one angle is equal to the cosecant of the other angle

In this problem

[tex]\alpha+\beta=90^o[/tex] ---> by complementary angles

so

[tex]sec(\alpha)=csc(\beta)[/tex]

Find the value of [tex]sec(\alpha)[/tex] in the right triangle of the figure

[tex]sec(\alpha)=\frac{1}{cos(\alpha)}[/tex]

Find the value of [tex]cos(\alpha)[/tex]

[tex]cos(\alpha)=\frac{2\sqrt{33}}{14}[/tex] ---> adjacent side divided by the hypotenuse

simplify

[tex]cos(\alpha)=\frac{\sqrt{33}}{7}[/tex]

therefore

[tex]sec(\alpha)=\frac{7}{\sqrt{33}}[/tex]

[tex]csc(\beta)=\frac{7}{\sqrt{33}}[/tex]

To find the values of sin(a)&cos(B), tan(a)&cot(B), and sec(a)&csc(B), use trigonometric identities and the reciprocal identities of trigonometric functions.

The question is asking to find the values of sin(a)&cos(B), tan(a)&cot(B), and sec(a)&csc(B). To solve these trigonometric expressions, you need to recall the definitions and relationships between trigonometric functions. Here are the step-by-step calculations:

Answer:

Members of Singing group will buy minimum 135 number of balcony tickets.

Step-by-step explanation:

Given:

Minimum of tickets will be bought =250

Let number of lawn tickets be 'l'.

Also Let number of balcony tickets be 'b'

Now given

The group buys 20 fewer lawn tickets than balcony tickets.

Framing in equation form we get;

[tex]l=b-20[/tex]

Now The Sum of Number of balcony tickets and Number of lawn tickets should be greater than or equal to Minimum of tickets will be bought by the group.

Framing in equation form we get;

[tex]l+b\geq 250[/tex]

Now substituting the value of 'l' in above equation we get;

[tex](b-20)+b\geq 250\\\\b-20+b\geq 250\\\\2b-20\geq 250\\\\2b\geq 250+20\\\\2b\geq 270\\\\b\geq \frac{270}{2}\\\\b\geq 135[/tex]

Now we know the value of b which is 135 we will substitute in equation [tex]l=b-20[/tex] to find the value of l we get;

[tex]l=135-20 = 115[/tex]

Hence Members of singing group will buy minimum 135 number of balcony tickets.

Answer:

Step-by-step explanation:

From the table, the number of copies can be plotted on the y axis and against the number of minutes on x axis. The slope of the straight line graph that would be formed would represent the become n, the number of copies the machine can print in one minute.

n = (y2-y1)/(x2-x1)

Picking points from the table,

y2 = 650

y1 = 325

x2 = 10

x1 = 5

Slope, n = (650 - 325)/(10 - 5)

n = 325/5 = 65 copies per minute

Working at the same rate, the time that it will take the machine to print 5,200 copies would be

65 copies = 1 minute

5200 copies would take

5200/65 = 80 minutes

Answer: False.

Step-by-step explanation:

For any random variable x,

Formula to calculate the z-score : [tex]z=\dfrac{x-\mu}{\sigma}[/tex]

, where [tex]\mu[/tex] = Mean

[tex]\sigma[/tex] = Standard deviation

Let x be the data point has a corresponding z-score of -1.5.

Then , we have

[tex]-1.5=\dfrac{x-\mu}{\sigma}[/tex]

[tex]-1.5\sigma=x-\mu[/tex]

[tex]\mu-1.5\sigma=x[/tex]

i.e. x is one and a half standard deviations below the mean value.

( one and a half =[tex]1+\dfrac{1}{2}=1.5[/tex] )

Therefore , the given statement is false.

18 kg of 15% copper and 72 kg of 60% copper should be combined by the metalworker to create 90 kg of 51% copper alloy.

Step-by-step explanation:

Let x = kg of 15% copper alloy

Let y = kg of 60% copper alloy

Since we need to create 90 kg of alloy we know:

x + y = 90

51% of 90 kg = 45.9 kg of copper

So we're interested in creating 45.9 kg of copper

We need some amount of 15% copper and some amount of 60% copper to create 45.9 kg of copper:

0.15x + 0.60y = 45.9

but

x + y = 90

x= 90 - y

substituting that value in for x

0.15(90 - y) + 0.60y = 45.9

13.5 - 0.15y + 0.60y = 45.9

0.45y = 32.4

y = 72

Substituting this y value to solve for x gives:

x + y = 90

x= 90-72

x=18

Therefore, in order to create 90kg of 51% alloy, we'd need 18 kg of 15% copper and 72 kg of 60% copper.