Answer:
Step-by-step explanation:
Binomial distribution is to be used here due to following reasons.
(a)
Probability of sending a box to an experienced inspector
= Probability of getting non-zero unacceptable cans
= 1 - Probability of getting zero unacceptable cans
=1- P(X = 0) = 1 - 10.08^0 *(1 – 0.08)^(4-0) = 0.283607
(b)
Expected cost per inspector in an hour in case of 8% unacceptable cans
= {(1-0.283607)*16+0.283607*22} = $ 17.70164
If groceries reduce their unacceptable rate to 4% then X - Bin(4, 0.04) .
In this scenario,
Probability of sending a box to an experienced inspector
= Probability of getting non-zero unacceptable cans
= 1 - Probability of getting zero unacceptable cans
=1- P(X = 0) = 1 - 0.04^0 * (1 – 0.04)*(4-0) = 0.150653
Expected cost per inspector in an hour in case of 4% unacceptable cans
= {(1-0.150653)*16+0.150653*22} = $ 16.90392
Percentage of savings realized = (17.70164-16.90392)/17.70164*100% = 4.506475%
indicate if the following systems are lineare or non linjear systems d^2x/dt+5dx/dt+10x = 0
Answer: You have only provided one Differential Equation (DE), it looks like you intended listing more.
The equation you wrote contains an incorrect d²x/dt, it is likely to be d²x/dt² + 5dx/dt + 10x = 0, which is linear. Unless it is (dx/dt)² + 5dx/dt + 10x = 0, then it is nonlinear.
Not to worry though, I will explain what linear and nonlinear DE's are.
Step-by-step explanation:
LINEAR DE: This is the kind of DE in which the functions of the dependent variable are linear. There are no powers of the dependent variable and/or its derivatives, there are no products of the dependent variable and its derivative, there are no functions of the dependent variable like cos, sin, exp, etc.
Example:
* 5d²x/dt² + dx/dt - x = 2t
This is linear, as it satisfies all the conditions.
NONLINEAR DE: If any condition explained for linear DE is not satisfied, then it is called nonlinear.
Example:
* d²x/dt² - sinx = 0
This is nonlinear because of the presence of sinx.
* d²x/dt² + xdx/dt = 0
This is nonlinear because of the product of the dependent variable, x, and its derivative, dx/dt.
* d²x/dt² + x² = 0
This is nonlinear because a function of the dependent variable is not linear. You shouldn't have x².
* (dx/dt)³ + 3dx/dt = 0 is equally nonlinear. You can't have nonlinear functions of the dependent variable or its derivatives.
I hope this helps answer the remaining parts of your question.
Philip ran out of time while taking a multiple-choice test and plans to guess on the last 444 questions. Each question has 555 possible choices, one of which is correct. Let X=X=X, equals the number of answers Philip correctly guesses in the last 444 questions. Assume that the results of his guesses are independent.
What is the probability that he answers exactly 1 question correctly in the last 4 questions?
Answer:
There is a 40.96% probability that he answers exactly 1 question correctly in the last 4 questions.
Step-by-step explanation:
For each question, there are only two possible outcomes. Either it is correct, or it is not. This means that we use the binomial probability distribution to solve this problem.
Binomial probability distribution
The binomial probability is the probability of exactly x successes on n repeated trials, and X can only have two outcomes.
[tex]P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}[/tex]
In which [tex]C_{n,x}[/tex] is the number of different combinatios of x objects from a set of n elements, given by the following formula.
[tex]C_{n,x} = \frac{n!}{x!(n-x)!}[/tex]
And p is the probability of X happening.
In this problem we have that:
There are four questions, so n = 4.
Each question has 5 options, one of which is correct. So [tex]p = \frac{1}{5} = 0.2[/tex]
What is the probability that he answers exactly 1 question correctly in the last 4 questions?
This is [tex]P(X = 1)[/tex]
[tex]P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}[/tex]
[tex]P(X = 1) = C_{4,1}*(0.2)^{1}*(0.8)^{3} = 0.4096[/tex]
There is a 40.96% probability that he answers exactly 1 question correctly in the last 4 questions.
Answer:
0.41
Step-by-step explanation:
kahn
For each part, give a relation that satisfies the condition. a. Reflexive and symmetric but not transitive b. Reflexive and transitive but not symmetric c. Symmetric and transitive but not reflexive
Answer:
For the set X = {a, b, c}, the following three relations satisfy the required conditions in (a), (b) and (c) respectively.
(a) R = {(a,a), (b,b), (c, c), (a, b), (b, a), (b, c), (c, b)} is reflexive and symmetric but not transitive .
(b) R = {(a, a), (b, b), (c, c), (a, b)} is reflexive and transitive but not symmetric .
(c) R = {(a,a), (a, b), (b, a)} is symmetric and transitive but not reflexive .
Step-by-step explanation:
Before, we go on to check these relations for the desired properties, let us define what it means for a relation to be reflexive, symmetric or transitive.
Given a relation R on a set X,
R is said to be reflexive if for every [tex]a \in X, (a,a) \in R[/tex].
R is said to be symmetric if for every [tex](a, b) \in R, (b, a) \in R[/tex].
R is said to be transitive if [tex](a, b) \in R[/tex] and [tex](b, c) \in R[/tex], then [tex](a, c) \in R[/tex].
(a) Let R = {(a,a), (b,b), (c, c), (a, b), (b, a), (b, c), (c, b)}.
Reflexive: [tex](a, a), (b, b), (c, c) \in R[/tex]
Therefore, R is reflexive.
Symmetric: [tex](a, b) \in R \implies (b, a) \in R[/tex]
Therefore R is symmetric.
Transitive: [tex](a, b) \in R \ and \ (b, c) \in R[/tex] but but (a,c) is not in R.
Therefore, R is not transitive.
Therefore, R is reflexive and symmetric but not transitive .
(b) R = {(a, a), (b, b), (c, c), (a, b)}
Reflexive: [tex](a, a), (b, b) \ and \ (c, c) \in R[/tex]
Therefore, R is reflexive.
Symmetric: [tex](a, b) \in R \ but \ (b, a) \not \in R[/tex]
Therefore R is not symmetric.
Transitive: [tex](a, a), (a, b) \in R[/tex] and [tex](a, b) \in R[/tex].
Therefore, R is transitive.
Therefore, R is reflexive and transitive but not symmetric .
(c) R = {(a,a), (a, b), (b, a)}
Reflexive: [tex](a, a) \in R[/tex] but (b, b) and (c, c) are not in R
R must contain all ordered pairs of the form (x, x) for all x in R to be considered reflexive.
Therefore, R is not reflexive.
Symmetric: [tex](a, b) \in R[/tex] and [tex](b, a) \in R[/tex]
Therefore R is symmetric.
Transitive: [tex](a, a), (a, b) \in R[/tex] and [tex](a, b) \in R[/tex].
Therefore, R is transitive.
Therefore, R is symmetric and transitive but not reflexive .
Relation from the set of two variables is subset of certain product. The relation for the condition are,
[tex]R_1\;\;\;\;\ (1,1), (1,2),,(2,1), (2,2),(2,3)((3,2),3,3)[/tex]
[tex]R_2\;\;\;\;\ (1,1), (2,2),,(3,3)(1,3)3,1)[/tex]
[tex]R_3\;\;\;\;\ (1,2),,(2,1), ,(2,3)((3,2)[/tex]
Relation-Relation from the set of two variables is subset of certain product. Relation are of three types-
ReflexiveSymmetricTransitive1) Reflexive and symmetric but not transitive -
Let a data set as,
[tex]X=1,2,3[/tex]
For the data set the relation can be given as,
[tex]R_1\;\;\;\;\ (1,1), (1,2),,(2,1), (2,2),(2,3)((3,2),3,3)[/tex]
[tex]R_1[/tex] is reflexive as it can be represent as [tex]R_1(a,a)[/tex] for,
[tex]a=1,2,3, \;\;\;\;\; [/tex]
[tex]a[/tex] ∈ [tex]X[/tex]
[tex]R_1[/tex] is symmetric as it can be represent as [tex]R_1(a,b)[/tex] for,
[tex]a,b \;\;\;\;(1,2) (2,1)[/tex]
[tex]a,b[/tex] ∈ [tex]X[/tex]
[tex]R_1[/tex] is not transitive as it can be represent as [tex]R_1\neq (a,c)[/tex] .
[tex]a,c\neq \;\;\;\;(1,3) (3,1)[/tex]
2) Reflexive and transitive but not symmetric
Let a data set as,
[tex]X=1,2,3[/tex]
For the data set the relation can be given as,
[tex]R_2\;\;\;\;\ (1,1), (2,2),,(3,3)(1,3)3,1)[/tex]
[tex]R_2[/tex] is reflexive as it can be represent as [tex]R_2(a,a)[/tex] for,
[tex]a=1,2,3, \;\;\;\;\; [/tex]
[tex]a[/tex] ∈ [tex]X[/tex]
[tex]R_1[/tex] is transitive as it can be represent as [tex]R_1(a,c)[/tex] for,
[tex]a,c \;\;\;\;(1,3) (3,1)[/tex]
[tex]a,c[/tex] ∈ [tex]X[/tex]
[tex]R_1[/tex] is not symmetric as it can be represent as [tex]R_1\neq (a,b)[/tex] .
[tex]a,b\neq \;\;\;\;(1,2) (2,1)[/tex]
3) Symmetric and transitive but not reflexive
Let a data set as,
[tex]X=1,2,3[/tex]
For the data set the relation can be given as,
[tex]R_3\;\;\;\;\ (1,2),,(2,1), ,(2,3)((3,2)[/tex]
[tex]R_1[/tex] is symmetric as it can be represent as [tex]R_3(a,b)[/tex] for,
[tex]a,b=(1,2),(2,1) \;\;\;\;\; [/tex]
[tex]a,b[/tex] ∈ [tex]X[/tex]
[tex]R_3[/tex] is transitive as it can be represent as [tex]R_3(a,c)[/tex] for,
[tex]a,c \;\;\;\;(1,3) (3,1)[/tex]
[tex]a,c[/tex] ∈ [tex]X[/tex]
[tex]R_1[/tex] is not reflexive as it can be represent as [tex]R_3\neq (a,a)[/tex] .
[tex]a,a\neq \;\;\;\;(1,1) [/tex]
Thus the relation for the condition are,
[tex]R_1\;\;\;\;\ (1,1), (1,2),,(2,1), (2,2),(2,3)((3,2),3,3)[/tex]
[tex]R_2\;\;\;\;\ (1,1), (2,2),,(3,3)(1,3)3,1)[/tex]
[tex]R_3\;\;\;\;\ (1,2),,(2,1), ,(2,3)((3,2)[/tex]
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Find the equation of the plane that is parallel to the vectors left angle 3 comma 0 comma 3 right angle and left angle 0 comma 1 comma 3 right angle, passing through the point (2 comma 0 comma negative 1 ).
Answer:
[tex]x + 3y -z - 3 = 0[/tex]
Step-by-step explanation:
We have to find the equation of plane that is parallel to the vectors
[tex]\langle 3,0,3\rangle, \langle0,1,3\rangle[/tex]
The plane also passes through the point (2,0,-1).
Hence, the equation of plane s given by:
[tex]\displaystyle\left[\begin{array}{ccc}x-2&y-0&z+1\\3&0&3\\0&1&3\end{array}\right]\\\\=(x-2)(0-3) - (y-0)(9-0) + (z+1)(3-0)\\=-3(x-2)-9y+3(z+1)\\\Rightarrow -3x + 6 - 9y + 3z + 3 = 0\\\Rightarrow 3x + 9y -3z -9 = 0\\\Rightarrow x + 3y -z - 3 = 0[/tex]
It is the required equation of plane.
An SRS of 350 350 high school seniors gained an average of ¯ x = 22.61 x¯=22.61 points in their second attempt at the SAT Mathematics exam. Assume that the change in score has a Normal distribution with standard deviation σ = 53.63 . σ=53.63. We want to estimate the mean change in score μ μ in the population of all high school seniors. (a) Using the 68 68 – 95 95 – 99.7 99.7 Rule or the z - z- table (Table A), give a 95 % 95% confidence interval ( a , b ) (a,b) for μ μ based on this sample.
Answer: (16.9914, 28.2286).
Step-by-step explanation:
The formula to find the confidence interval for population mean is given by :-
[tex]\overline{x}\pm z^*\dfrac{\sigma}{\sqrt{n}}[/tex]
, where [tex]\overline{x}[/tex] = Sample mean
[tex]\sigma[/tex]= Population standard deviation
n= Sample size.
z* = Critical value.
Let μ be the mean change in score in the population of all high school seniors.
As per given , we have
n= 350
[tex]\overline{x}=22.61[/tex]
[tex]\sigma=53.63[/tex]
The critical z-value for 95% confidence interval is z*= 1.96 [From z-table]
Substitute all the value in formula , we get
[tex]22.61\pm (1.96)\dfrac{53.63}{\sqrt{350}}[/tex]
[tex]=22.61\pm (1.96)\dfrac{53.63}{18.708287}[/tex]
[tex]=22.61\pm (1.96)(2.8666)[/tex]
[tex]=22.61\pm (5.6186)[/tex]
[tex]=(22.61-5.6186,\ 22.61+5.6186) =(16.9914,\ 28.2286)[/tex]
Hence, the 95% confidence interval for [tex]\mu[/tex] is (16.9914, 28.2286).
Based on a poll, a newspaper reported that between 52% and 68% of voters would be likely to vote for a schoolbond issue. What is the margin of error of the poll?
Answer:
The margin of error of the poll is 8%.
Step-by-step explanation:
This is a confidence interval. A confidence interval has both a lower end and an upper end.
The true proportion is the midpoint between the two ends.
The margin of error is the absolute difference between the proportion and the ends(which is the same, upper end - proportion = proportion - lower end),
In this problem, we have that:
The lower end is 52%.
The upper end is 68%.
The proportion is (52 + 68)/2 = 60%.
The margin of error is 60 - 52 = 68 - 60 = 8%.
Assume that about 30% of all U.S. adults try to pad their insurance claims. Suppose that you are the director of an insurance adjustment office. Your office has just received 140 insurance claims to be processed in the next few days. What is the probability that from 45 to 47 of the claims have been padded?
a. 0.222
b. 0.167
c. 0.119
d. 0.104
e. 0.056
Answer:
For x=45
sample proportion=45/140=0.321
z=(0.321-0.30)/sqrt(0.3*(1-0.3)/140)
z=0.54
For x=47
sample proportion=47/140=0.336
z=(0.336-0.30)/sqrt(0.3*(1-0.3)/140)
z=0.93
Now,
P(0.54<z<0.93)=P(z<0.93)-P(z<0.54)
=0.8238-0.7054
=0.118
So,correct option is 0.119
Suppose the coefficient matrix of a linear system of four equations in four variables has a pivot in each column. Explain why the system has a unique solution. What must be true of a linear system for it to have a unique solution? Select all that apply.
If the coefficient matrix has a pivot in each column, it means that it is shaped like this:
[tex]A=\left[\begin{array}{cccc}a_{1,1}&a_{1,2}&a_{1,3}&a_{1,4}\\0&a_{2,2}&a_{2,3}&a_{2,4}\\0&0&a_{3,3}&a_{3,4}\\0&0&0&a_{4,4}\end{array}\right][/tex]
So, the correspondant system
[tex]Ax = b[/tex]
will look like this:
[tex]\left[\begin{array}{cccc}a_{1,1}&a_{1,2}&a_{1,3}&a_{1,4}\\0&a_{2,2}&a_{2,3}&a_{2,4}\\0&0&a_{3,3}&a_{3,4}\\0&0&0&a_{4,4}\end{array}\right]\cdot \left[\begin{array}{c}x_1\\x_2\\x_3\\x_4\end{array}\right] = \left[\begin{array}{c}b_1\\b_2\\b_3\\b_4\end{array}\right][/tex]
This turn into the following system of equations:
[tex]\begin{cases}a_{1,1}x_1+a_{1,2}x_2+a_{1,3}x_3+a_{1,4}x_4=b_1\\a_{2,2}x_2+a_{2,3}x_3+a_{2,4}x_4=b_2\\a_{3,3}x_3+a_{3,4}x_4=b_3\\a_{4,4}x_4=b_4\end{cases}[/tex]
The last equation is solvable for [tex]x_4[/tex]: we easily have
[tex]x_4=\dfrac{b_4}{a_{4,4}}[/tex]
Once the value for [tex]x_4[/tex] is known, we can solve the third equation for [tex]x_3[/tex]:
[tex]x_3 = \dfrac{b_3-a_{3,4}x_4}{a_{3,3}}[/tex]
(recall that [tex]x_4[/tex] is now known)
The pattern should be clear: you can use the last equation to solve for [tex]x_4[/tex]. Once it is known, the third equation involves the only variable [tex]x_3[/tex]. Once
Which relationship is a direct variation?
Answer:
A relationship is said to have direct variation when one variable changes and the second variable changes proportionally; the ratio of the second variable to the first variable remains constant. For example, when y varies directly as x, there is a constant, k, that is the ratio of y:x.
Factor the GCF out of the trinomial on the left side of the equation. (2 points: 1 for the GCF, 1 for the trinomial)2x^2 + 6x - 362(x^2 + 3x - 18)
Answer:
2(x+6)(x-3)
Step-by-step explanation:
Factor the GCF out of the trinomial on the left side of the equation.
[tex]2x^2 + 6x - 36 =2(x^2 + 3x - 18)[/tex]
Greatest common factor of 2, 6, 18 is 2
so GCF is 2
divide each term when we take out GCF 2
so [tex]2(x^2 + 3x - 18)[/tex]
now factor the trinomial
product is -18 and sum is +3
6 times -3 is -18 and 6-3=3
[tex]2(x^2+3x-18)\\2(x+6)(x-3)[/tex]
Evaluate the limit using the appropriate Limit Law(s). (If an answer does not exist, enter DNE.) lim x→8 1 + 3 x 5 − 6x2 + x3
Answer:
[tex] [tex] lim_{x \to 8} (1+3\sqrt{x})(1-6x^2 +x^3)[/tex]=[tex]1-384 +512+3\sqrt{8} -18(8)^{5/2} +3 (8)^{7/2} =1223.601[/tex]
And the limit on this case exists.
Step-by-step explanation:
We want to find the following limit:
[tex] lim_{x \to 8} (1+3\sqrt{x})(1-6x^2 +x^3)[/tex]
First we can distribute the polynomials like this:
[tex] lim_{x \to 8} (1-6x^2 +x^3+3\sqrt{x} -18 x^{5/2} +3x^{7/2})[/tex]
And Now we can use the distributive property for the limit and we got:
[tex] lim_{x \to 8} 1 - 6 lim_{x \to 8} x^2 + lim_{x \to 8} x^3 +3 lim_{x \to 8} \sqrt{x} -18 lim_{x \to 8} x^{5/2} + 3 lim_{x \to 8} x^{7/2}[/tex]
And now we can evaluate the limit and we got:
[tex] [tex] lim_{x \to 8} (1+3\sqrt{x})(1-6x^2 +x^3)[/tex]=[tex]1-384 +512+3\sqrt{8} -18(8)^{5/2} +3 (8)^{7/2} =1223.601[/tex]
And the limit on this case exists.
To solve limit problems in mathematics, limit laws are often very useful. In this specific case, as the function is a polynomial and defined for all real number values, a direct substitution of x=8 into the function is sufficient. Therefore, the limit as x approaches 8 for function 1 + 3x5 - 6x2 + x3 is calculable.
Explanation:In the field of mathematics, limit laws are used quite frequently for evaluating limits. In this case, we want to calculate the limit as x approaches 8 for the function 1 + 3x5 - 6x2 + x3.
For a given polynomial function like this one, an easy and very straightforward approach is to substitute the value x is approaching (in this scenario, x = 8) directly into the polynomial function.
So, after substitution, our function becomes: 1 + 3*(8)^5 - 6*(8)^2 + (8)^3. Simplifying it further, the limit as x approaches 8 of this function gives us a definite numeric value.
Always remember while applying limit laws, you might at times need the limit laws to evaluate complex limit problems but in this given scenario, direct substitution works perfectly fine because this polynomial function is defined for all real number values of X.
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Suppose 60% of homes in Miami have a swimming pool and 30% have both a swimming pool and a Jacuzzi. What is the probability that a randomly selected home will have a Jacuzzi given that it has a swimming pool?
Answer:
0.5 is the probability that a randomly selected home will have a Jacuzzi given that it has a swimming pool.
Step-by-step explanation:
We are given the following in the question:
S: Homes in Miami have a swimming pool
J: Homes in Miami have a jacuzzi
[tex]P(S) = 60\% = 0.6\\P(S\cap J) = 30\% = 0.3[/tex]
We have to find the probability that a randomly selected home will have a Jacuzzi given that it has a swimming pool.
Thus, we have to calculation the conditional probability of having a jacuzzi given the house has a swimming pool.
[tex]P(J|S) = \dfrac{P(J\cap S)}{P(S)}\\\\P(J|S) = \displaystyle\frac{0.3}{0.6} = 0.5[/tex]
0.5 is the probability that a randomly selected home will have a Jacuzzi given that it has a swimming pool.
You and your friend play a game. You answer 80% of the questions correctly and your friend answers 0.60 of the questions correctly. What is the minimum number of questions in the game?
Answer:
5
Step-by-step explanation:
Assuming both players can answer the same question, the minimum number of questions is the smallest number that when multiplied by either 0.60 or 0.80 yields a whole number.
Let x be the number of questions, solving by trial and error:
[tex]if\ x=2\\x*0.8=1.6\\x*0.6=1.2\\\\if\ x=3\\x*0.8=2.4\\x*0.6=1.8\\\\if\ x=4\\x*0.8=3.2\\x*0.6=2.4\\\\if\ x=5\\x*0.8=4\\x*0.6=3\\\\[/tex]
Therefore, the minimum number of questions in the game is 5.
To find the minimum number of questions in a game where one person answers 80% correctly and another answers 60% correctly, calculate the LCM of the fractions' denominators. The result is 5 questions.
You and your friend have different accuracy rates when answering questions in a game. You answer 80% of the questions correctly, while your friend answers 60% of the questions correctly. To find the minimum number of questions in the game, we need to ensure that both percentages can correspond to whole numbers of questions.
Convert the percentages to fractions: You: [tex]\( \frac{80}{100} = \frac{4}{5} \)[/tex] and your friend: [tex]\( \frac{60}{100} = \frac{3}{5} \)[/tex]To find the smallest number of questions (N) that allows both fractions to be whole numbers, find the Least Common Multiple (LCM) of the denominators (5 in both cases).The LCM of 5 is 5 since it’s the same for both.Thus, the minimum number of questions in the game is 5.In a game with 5 questions:
You would answer 4 out of 5 questions correctly (80%).Your friend would answer 3 out of 5 questions correctly (60%).Therefore, the minimum number of questions in this game is 5.
The stop-board of a shot-put circle is a circular arc 1.22 m in length. The radius of the circle is 1.06 m. What is the central angle?
Answer:
Central angle= 1.15 radians
Step-by-step explanation:
[tex]Arc\,\,length=s= 1.22\,m\\Radius=r=1.06\,m\\\\Central\,\, angle=\theta=?\\\\Using\\\\ s=r\theta\\\\\theta=\frac{s}{r}\\\\\theta= \frac{1.22}{1.06}\\\\\theta=1.15 \,rad[/tex]
Question 5 (Fill-In-The-Blank Worth 1 points)
(05.05 MC)
A system of equations is shown below:
6x - 5y = 5 ,
3x + 5y = 4
The x-coordinate of the solution to this system of equations is
Numerical Answers Expected!
Answer:
The x-coordinate of the solution to this system of equations is 1.
Step-by-step explanation:
Given,
[tex]6x - 5y = 5\\\\3x + 5y = 4[/tex]
We have to find out the x-coordinate of the equation.
Solution,
Let [tex]6x-5y=5\ \ \ \ equation\ 1[/tex]
Again let [tex]3x+5y=4\ \ \ \ \ equation \ 2[/tex]
Now using elimination method we will solve the equations.
For this we will add equation 1 and equation 2 and get;
[tex](6x-5y)+(3x+5y)=5+4\\\\6x-5y+3x+5y=9\\\\9x=9[/tex]
Now on dividing both side by '9' we get;
[tex]\frac{9x}{9}=\frac{9}{9}\\\\x=1[/tex]
Hence The x-coordinate of the solution to this system of equations is 1.
1
ur welcome homie
poggers
The Honolulu advertiser stated that in Honolulu there was an average of 661 burglaries per 400,000 households in a given year. In the Kohola drive neighborhood there are 317 homes. Let r be the number of homes that will be burglarized in a year. Compute the probability for r > or equal to 2 round your answer to the nearest ten thousandth.
A)0.3010
B) 0.1013
C) 0.0144
D) 0.0902
E) 0.0369
Answer:
D) 0.0902
Step-by-step explanation:
Data provided in the question:
Probability of burglary, p = [tex]\frac{661}{400,000}[/tex]
= 0.00165
q = 1 - p
or
q = 1 - 0.00165
or
q = 0.99835
Now,
P(r ≥ 2) = 1 - P(r < 2)
= 1 - [ P(0) + P(1) ]
= 1 - [ [tex]^{317}C_0(0.00165)^0(0.99835)^{317-0}+^{317}C_1(0.00165)^1(0.99835)^{317-1}[/tex] ]
[ as P(x) = [tex]^nC_rp^rq^{n-r}[/tex]]
= 1 - [ 0.593 + 0.3168]
= 1 - 0.9098
= 0.0902
Hence,
Option (D) 0.0902
Let V be the vector space of all 2 X 2 matrices over the field F. Prove that V has dimension 4 by exhibiting a basis for V which has four elements.
Answer:
See the proof below.
Step-by-step explanation:
We can define a basis of V with the following elements:
[tex]X_1=\begin{matrix}1 & 0 \\0 & 0 \end{matrix} [/tex]
[tex]X_2=\begin{matrix}0 & 1 \\0 & 0 \end{matrix} [/tex]
[tex]X_3=\begin{matrix}0 & 0 \\1 & 0 \end{matrix} [/tex]
[tex]X_4=\begin{matrix}0 & 0 \\0 & 1 \end{matrix} [/tex]
So then if we define the basis X as following:
[tex] X = [X_1, X_2, X_3, X_4][/tex]
[tex]X =[\begin{pmatrix}1 & 0\\0 & 0\end{pmatrix},\begin{pmatrix}0 & 1\\0 & 0 \end{pmatrix},\begin{pmatrix}0 & 0\\1 & 0\end{pmatrix},\begin{pmatrix}0 & 0\\0 & 1 \end{pmatrix}[/tex]
We see the the dimension for X is 4 [tex] dim (V) = 4[/tex] since the basis have a dimension of 4 [tex] dim (X) =4[/tex]
Final answer:
The vector space V of all 2 x 2 matrices over a field F has a basis consisting of four matrices which are linearly independent and span V. This basis demonstrates that V has a dimension of 4.
Explanation:
In order to prove that the vector space V of all 2 x 2 matrices over a field F has dimension 4, we need to exhibit a basis for V that consists of four linearly independent elements, which also span V. Consider the following 2 x 2 matrices as the candidate basis elements:
⬑ 1 0 ⬑These matrices are linearly independent and span the vector space of all 2 x 2 matrices. To show linear independence, assume that a linear combination of these matrices equals the zero matrix:
a ⬑ 1 0 ⬑ + b ⬑ 0 1 ⬑ + c ⬑ 0 0 ⬑ + d ⬑ 0 0 ⬑
⬑ 0 0 ⬑ ⬑ 0 0 ⬑ ⬑ 1 0 ⬑ ⬑ 0 1 ⬑
= ⬑ 0 0 ⬑
⬑ 0 0 ⬑
This equation leads to a = b = c = d = 0, which verifies the linear independence. Since we can represent any 2 x 2 matrix as a linear combination of these four basis matrices, they also span V, fulfilling both criteria for a basis. Hence, there are four basis elements, and therefore, the dimension of V is 4.
Which table represents the graph of a logarithmic function with both an x-and y-intercept?
Answer:
The answer is B
Step-by-step explanation:
Answer:
B. The second graph
Step-by-step explanation:
edge 2021 math assignment
Find the vector representing the area of the triangle ABC where A=(4,5,6), B=(6,4,5) and C=(5,4,6) oriented so that it faces upward.
Answer: Area of triangle is √3 / 2
Step-by-step explanation:
The explanation can be found in the attached in picture
Find the sales tax and total cost of a Sony Playstation that costs $172.99. The tax rate is
4%. Round your answer to the nearest cent.
Answer:
all work is shown and pictured
Answer:The total cost of the Sony Playstation is $179.9096
Step-by-step explanation:
The initial or regular cost of the Sony Playstation is $172.99.
The tax rate is 4%. Therefore, the value of the sales tax would be
4/100 × 172.99 = 0.04 × 172.99 = $6.9196
The total cost of the Sony Playstation would be the sum of the regular price and the sales tax. It becomes
172.99 + 6.9196 = $179.9096
1. Suppose the coefficient matrix of a linear system of four equations in four variables has a pivot in each column. Explain why the system has a unique solution.
2. What must be true of a linear system for it to have a unique solution?
Select all that apply.
A. The system has no free variables.
B. The system has one more equation than free variable.
C. The system is inconsistent.
D. The system is consistent. Your answer is correct.
E. The system has at least one free variable.
F. The system has exactly one free variable.
Answer:its A
Step-by-step explanation:it was
In a sample of 11 men, the mean height was 178 cm. In a sample of 30 women, the mean height was 167 cm. What was the mean height for both groups put together?
Answer:
I'm pretty sure it would be 345, just add the two 178 and 167
An airplane has a front nad a rear door that are bother openedto allow passengers to exit when the plane lands. the planehas 100 passengers seated. the number of passengers exitingthrought the front door shougl have
a) a binomial distribution with mean 50
b) a binomial distribution with 100 trials but successprobability not equal to .5
c)a normal didtribution with a standard deviation of5
d) none of the above
Answer:
a) a binomial distribution with mean 50
Step-by-step explanation:
Given that an airplane has a front nad a rear door that are bother opened to allow passengers to exit when the plane lands. the plane has 100 passengers.
These 100 passengers can select either back door or front door with equal probability (assuming)
so probability for selecting front door = 0.5
No of passengers =100
Each passenger is independent of the other
Hence X no of passengers exiting through the front door is binomial with
p =0.5 and n =100
Mean of the variable X = np = 100(0.5) = 50
Variance of X = 100(0.5)(0.5)
Hence std dev = 10(0.5) = 5
So correct answers are
a) a binomial distribution with mean 50
Find the mean amount hospitals had to pay in wrong-site lawsuits. Round your answer to the nearest whole dollar.
Answer:
dont see much information here but as far as lawsuits go id aim for the highest answer
Step-by-step explanation:
_____________________________________
PLEASE HELP!!!
Carol paid $0.78 per liter for gas while driving across Canada. Find the cost per gallon to the nearest cent.
Please give a step by step
Answer:
2.95 cent
Step-by-step explanation:
1 gallon = 231 cubic inches
1 litre = 1000ml = 61.0237 cubic inches
1 galloon = 231 / 61.0237 = 3.7854118 liters
if Carol paid $0.78 per litre
1 galloon = 0.78 x 3.7854118 = 2.952621204 ≅ 2.95 cent
Samples of skin experiencing desquamation are analyzed for both moisture and melanin content. The results from 100 skin samples are as follows: melanin content high low moisture high 13 10 content low 47 30 Let A denote the event that a sample has low melanin content, and let B denote the event that a sample has high moisture content. Determine the following probabilities. Round your answers to three decimal places (e.g. 98.765).
a) P(A)
b) P(B)
c) P (A|B)
d) P (BA)
Answer: a. 0.40 b. 0.23 c . 0.435 d . 0.25
Step-by-step explanation:
melanin content Total
high low
moisture high 13 10 23
content low 47 30 77
Total 60 40 100
Let A denote the event that a sample has low melanin content, and let B denote the event that a sample has high moisture content.
a) Total skin samples has low melanin content = 10+30=40
P(A)=[tex]\dfrac{40}{100}=0.40[/tex]
b) Total skin samples has high moisture content = 13+10=23
P(B) =[tex]\dfrac{23}{100}=0.23[/tex]
c) A ∩ B = Total skin samples has both low melanin content and high moisture content =10
P(A ∩ B) =[tex]\dfrac{10}{100}=0.10[/tex]
Using conditional probability formula , [tex]P (A|B)=\dfrac{P(A\cap B)}{P(B)}[/tex]
[tex]P (A|B)=\dfrac{0.10}{0.23}=0.434782608696\approx0.435[/tex]
d) [tex]P (B|A)=\dfrac{P(A\cap B)}{P(A)}[/tex]
[tex]P (B|A)=\dfrac{0.10}{0.40}=0.25[/tex]
How many 7/8 cup servings are in 1/2 of a cup of juice? (in simplest fraction form)
The result is [tex]\frac{4}{7}[/tex]
Step-by-step explanation:
In this problem, we are asked to find how many 7/8 cup servings are in 1/2 of a cup of juice.
Mathematically, this is equivalent to divide 1/2 by 7/8. So we can write:
[tex]\frac{1/2}{7/8}[/tex]
This can be rewritten as a multiplication by reversing the denominator:
[tex]\frac{1}{2}\cdot \frac{8}{7}[/tex]
Now we can perform the multiplication of both the numerator and the denominator:
[tex]\frac{1\cdot 8}{2\cdot 7}=\frac{8}{14}[/tex]
And simplifying (dividing by 2),
[tex]\frac{8}{14}=\frac{4}{7}[/tex]
Learn more about fractions:
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There are 4/7 servings of 7/8 cup in 1/2 cup of juice.
To determine the number of 7/8 cup servings in 1/2 of a cup of juice, divide the 1/2 cup of juice by 7/8 cup.
Now, the reciprocal of 7/8 and multiplying it by 1/2.
Reciprocal of 7/8 = 8/7
Now, perform the multiplication:
= (1/2 cup) * (8/7)
= (1 * 8) / (2 * 7)
= 8/14
= 4/7
Therefore,4/7 servings of 7/8 cup in 1/2 cup of juice.
Learn more about Unitary Method here:
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Determine which matrices are in reduced echelon form and which others are only in echelon form. a. [Start 3 By 4 Matrix 1st Row 1st Column 1 2nd Column 0 3rd Column 0 4st Column 0 2nd Row 1st Column 0 2nd Column 2 3rd Column 0 4st Column 0 3rd Row 1st Column 0 2nd Column 0 3rd Column 1 4st Column 1 EndMatrix ]1 0 0 0 0 2 0 0 0 0 1 1 b. [Start 3 By 4 Matrix 1st Row 1st Column 1 2nd Column 0 3rd Column 1 4st Column 1 2nd Row 1st Column 0 2nd Column 1 3rd Column 1 4st Column 1 3rd Row 1st Column 0 2nd Column 0 3rd Column 0 4st Column 0 EndMatrix ]1 0 1 1 0 1 1 1 0 0 0 0 c. [Start 4 By 4 Matrix 1st Row 1st Column 0 2nd Column 0 3rd Column 0 4st Column 0 2nd Row 1st Column 1 2nd Column 3 3rd Column 0 4st Column 0 3rd Row 1st Column 0 2nd Column 0 3rd Column 1 4st Column 0 4st Row 1st Column 0 2nd Column 0 3rd Column 0 4st Column 1 EndMatrix ]
Answer:
Step-by-step explanation:
Check the attachment for the solution
Answer:
Echelon form.Reduced Echelon form.Neither.Step-by-step explanation:
The objective is to determine which of the following matrices are in reduced echelon form and which others are only in echelon form. The given matrices are
[tex]\begin{bmatrix} 1 & 0 & 0 & 0 \\ 0& 2 & 0 & 0 \\ 0& 0 & 1 & 1 \end{bmatrix}[/tex], [tex]\begin{bmatrix} 1 & 0 & 1 & 1 \\ 0& 1& 1 & 1 \\ 0& 0 & 0 & 0 \end{bmatrix}[/tex] and [tex]\begin{bmatrix} 0& 0 & 0 & 0 \\ 1& 3 & 0 & 0 \\ 0& 0 & 1 & 0 \\ 0& 0 & 0 & 1 \end{bmatrix}[/tex].
First, recall what is an echelon and reduced echelon form of a matrix.
A matrix is said to be in a Echelon form if
If there is any zero rows, all nonzero rows are placed above them;Each first non-zero entry in a row, which is the leading entry, is placed to the right of the leading entry of the row above it;All elements below the leading entry must be equal to zero in each column.A matrix is said to be in a Reduced Echelon form if
In each non-zero row, the leading entry is 1.In its column, each leading 1 is actually the only non-zero element.A column that contains a leading 1 which is the only non-zero element is called a pivot column.
Now, let's have a look at the first matrix
[tex]\begin{bmatrix} 1 & 0 & 0 & 0 \\ 0& 2 & 0 & 0 \\ 0& 0 & 1 & 1 \end{bmatrix}[/tex]
As we can see, it doesn't have any zero rows. Each leading entry in a row is placed to the right of the leading entry from the row above and all elements below the leading entries in all columns are equal to zero. Therefore, this matrix is in an Echelon form.
In the second row, the leading entry is 2, not 1, so because of the first property of the Reduced Echelon form, it is not in a Reduced Echelon form.
Notice that it can be transformed to the Reduced Echelon form by multiplying the second row by [tex]\frac{1}{2}.[/tex]
The second matrix is
[tex]\begin{bmatrix} 1 & 0 & 1 & 1 \\ 0& 1& 1 & 1 \\ 0& 0 & 0 & 0 \end{bmatrix}[/tex]
There is a zero row, and all non-zero rows are placed above it. Each leading entry in a row, which is the first non-zero entry, is placed to the right of the entry of the row above it and all elements below the leading entry are equal to zero in each column, so it is in the Echelon form.
It is also in the Reduced Echelon form, since all non-zero rows the leading entry is 1 and it is the only non zero element in each column.
The least given matrix is
[tex]\begin{bmatrix} 0& 0 & 0 & 0 \\ 1& 3 & 0 & 0 \\ 0& 0 & 1 & 0 \\ 0& 0 & 0 & 1 \end{bmatrix}[/tex]
This matrix doesn't satisfy the condition that if there is any zero-row, it must be below all other non-zero rows, so it is not in Echelon form.
A matrix that is not in an Echelon form, it is not in an Reduced Echelon form either.
Therefore, this matrix is not in an Reduced Echelon form.
A student earned grades of Upper AA, Upper DD, Upper AA, Upper CC, and Upper BB. Those courses had the corresponding numbers of credit hours 44, 22, 22, 33, and 11. The grading system assigns quality points to letter grades as follows: Aequals=4; Bequals=3; Cequals=2; Dequals=1; Fequals=0. Compute the grade point average (GPA) as a weighted mean and round the result with two decimal places. If the Dean's list requires a GPA of 3.00 or greater, did this student make the Dean's list? The grade point average is nothing. (Round to two decimal places as needed.) Did this student make the Dean's list? A. Yes because at least two of the student grades are B or above B. No because the students GPA is not 4.0 C. NoNo because the student has at least one grade lessless than 3 D. NoNo because the student's GPA is lessless than 3.0
Answer:
The grade point average is 2.92The student didn't make the Dean's list because the student's GPA is less than 3.0Step-by-step explanation:
I take the grades as A,D,A,C,B not AA,DD,AA,CC,BB.I take numbers of credit hours as 4,2,2,3,1 not as 44, 22, 22, 33, and 11.Since quality points to letter grades are A=4; B=3; C=2; D=1; F=0, weighted mean is the sum of the qulity points times corresponding credit hours divided by the total credit hours:
[tex]\frac{(4*4) + (1*2) + (4*2) + (2*3) + (3*1)}{12}[/tex] ≈ 2.92
Since 2.92<3.0, the student is not in Dean's list.
A student who has created a linear model is disappointed to find that herR2 value is a very low 13%. a) Does this mean that a linear model is not appropriate? Explain. b) Does this model allow the student to make accurate predictions? Explain.
Answer:
a) No it doesn't mean that linear model is inappropriate
b) No. The prediction using this model will not be accurate.
Step-by-step explanation:
a)
For answering this part, firstly consider the concept of [tex]R^{2}[/tex]
The [tex]R^{2}[/tex] also known as coefficient of determination is used to determine the amount of variability in dependent variable is explained by the linear model. Lower [tex]R^{2}[/tex] depicts that less variation of dependent is explained by the independent variable using the linear model. The linearity of model is determined by scatter plot. Thus, if the [tex]R^{2}[/tex] is lower, it doesn't mean that linear model is inappropriate.
b)
The predictions made by the model having lower [tex]R^{2}[/tex] value are erroneous. The model is used for prediction if the linear model explains the larger portion of variability in dependent variation. If the predictions made from the model that have lower [tex]R^{2}[/tex] value then the predicted values will not be close to the actual value and thus residuals will not be minimum as residuals are the difference of actual and predicted values.