You look at the clock and it is exactly 2pm. you set an alarm to go off in 51 hours. at what time does the alarm go off? (hint: you could count on your fingers, but this is not what we’re after. if you are tempted to count on your fingers, change the 51 to 5100.)

Answers

Answer 1
2 p.m. to 2 p.m. = 24 hrs
2 p.m to 2 p.m = 24 hrs
2 p.m. to 5 p.m. = 3 hrs

the alarm goes off at 5 p.m.
Answer 2

If you look at the clock and it is exactly 2pm. you set an alarm to go off in 51 hours then 5PM is the time when alarm go off.

What is Time?

Time can be defined as an ongoing and continuous sequence of events that occur in succession, from past through the present, and to the future.

Given that You look at the clock and it is exactly 2pm and set an alarm to go off in 51 hours.

We need to find at which time the alarm go off.

We know that in a clock we will have 12 hours.

For every 12 hours the PM changes to PM.

2PM-2PM=24 hours

2PM-2PM=24 hours

When we add the hours we get 48 hours still we needed three more hours to turn off the alarm

2PM-5PM=3 hours.

at 5PM it becomes 51 hours.

Hence, if you look at the clock and it is exactly 2pm. you set an alarm to go off in 51 hours then 5PM is the time when alarm go off.

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Related Questions

The population of a species of rabbit triples every year. This can be modeled by f(x) = 4(3)x and f(5) = 972. What does the 4 represent? (1 point) The starting population of the rabbits The population of the rabbits after five years The rate the population increases The number of years that have passed

Answers

Exponential functions are of the form:

y=ab^x, y=final amount, a=initial amount, b=rate, t=time

So the value a, 4 in this case, is the starting population of the rabbits.

Answer: The starting population of the rabbits

Step-by-step explanation:

Given: The population of a species of rabbit triples every year. This can be modeled by f(x) = 4(3)x and f(5) = 972.

We know that the exponential growth function is given by :-

[tex]f(x)=Ab^x[/tex], where A is the initial amount and b is the multiplicative rate of change in time x.

As compared to the given exponential function, we have

A=4

Therefore, 4 represents the starting population of the rabbits

If F(theta)=tan theta=3, find F(theta+pi)

Answers

Given:
f(θ) = tan(θ) = 3

Note that
[tex]tan(x+y) = \frac{tanx + tany}{1-tanx \, tany} [/tex]

Note that tan(π) = 0.
Therefore
f(θ + π) = tan(θ+π)
            = (tanθ + tan π)/(1 -tanθ tan π)
            = 3/1 = 3

Answer: 3
As given 
[tex]f(\theta) = tan( \theta) = 3[/tex]

So [tex]f(\theta + \pi) = tan (\theta + \pi)[/tex]

And we know [tex]tan(\theta + \pi) = -tan(\theta)[/tex] because it is in second quadrant and tan is negative in second quadrant.

So [tex]f(\theta + \pi) = -tan(\theta) = -3[/tex]

So answer is -3.

Solve the equation by completing the square. Round to the nearest hundredth if necessary. x^2-3x-3=0

Answers

x^2 - 3x = 3
(x - 1.5)^2 - 2.25 = 3
(x - 1.5) = +/- sqrt 5.25

x = 1.5 +/- sqrt5.25

x  = -0.79, 3.79  to nearest hundredth
This is the answer I wrote it all out

A ball is thrown from an initial height of 1 meter with an initial upward velocity of 13 m/s. The ball's height h (in meters) after t seconds is given by the following.

h=1+13t-5t^2

Find all values of t for which the ball's height is 8 meters.

Round your answer(s) to the nearest hundredth.
(If there is more than one answer, use the "or" button.)

Answers

Here the answer is: 0.76 and 1.84

I hope I don't have to explain it again.






For t=1.84 and t=0.76 the ball's height is 8 meters in equation h=1+13t-[tex]5t^{2}[/tex].

What is equation?

An equation is a relationship between two or more variables expressed in equal to form. Equation of two variables look like ax+ by=c. It is solved in order to find the values of variables.

How to solve equation?

We have been given an equation h=1+13t-[tex]5t^{2}[/tex] and we have to find the values of t for which h=8.

So,

1+13t-[tex]5t^{2}[/tex]=8

[tex]-5t^{2}[/tex]+13t+1-8=0

[tex]-5t^{2}[/tex]+13t-7=0

Removing negative signs.

[tex]5t^{2}[/tex]-13t+7=0

We cannot solve through factorization so e use the following formula:

x=-b+-[tex]\sqrt{b^{2} -4ac}/2a[/tex]

t=(13+-[tex]\sqrt{-13^{2} -4*5*7}[/tex])/2*5

t=(13+-[tex]\sqrt{169-140}[/tex])/10

t=(13+5.38)/10, (13-5.38)/10

t=1.838, 0.762

By rounding off to nearest hundred t=1.84, 0.76.

Hence value of t for which h=8 meters are 1.84 and 0.76.

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Bradley is returning home from a place that is 2 kilometers away. The function y = 2,000 − 90x represents Bradley's distance from home in meters, y, in relation to the number of minutes he walks, x. Which statements about this function are true?

Answers

Final answer:

The function y = 2,000 - 90x shows Bradley's distance from home decreases by 90 meters for every minute walked, starting from 2,000 meters away. The graph of this equation is a straight line with a negative slope, indicating constant speed.

Explanation:

The equation y = 2,000 - 90x represents Bradley's distance from home in meters, y, as a function of the time x in minutes that he walks. This equation is a linear function where the initial value 2,000 meters represents the distance from home at the start, and -90 meters/minute is the rate at which this distance decreases as Bradley walks home. As time increases by 1 minute, the distance from home decreases by 90 meters. This relationship shows that Bradley travels at a constant speed since the slope of the line representing the equation (which is the rate of change of distance with respect to time) is constant.

If we graph this function, we would get a straight line that starts at 2,000 meters on the y-axis when t=0 and has a negative slope of 90. Therefore, the graph shows that as time passes, Bradley gets closer to home at a steady pace. This also reflects that the total distance Bradley would walk is 2,000 meters, and the time it would take for him to return home can be found by setting the function equal to zero and solving for x.

PLEASE HELP ME!!!!

Part A: Amir rented a scooter at $43 for 3 hours. If he rents the same scooter for 8 hours, he has to pay a total rent of $113.

Write an equation in the standard form to represent the total rent (y) that Amir has to pay for renting the scooter for x hours.

Part B: Write the equation obtained in Part A using function notation.

Part C: Describe the steps to graph the equation obtained above on the coordinate axes. Mention the labels on the axes and the intervals.

Answers

Part A:

The equation in standard form is given Ax+By+C = 0
where x is the gradient of a straight line (or the rate of change)

The rate of change = (113-43) / (8-3) = 70/5 = 14
This value means there's an increase of $14 for every hour rented.

We also need to work out the value of C, which is the fixed value (happen at x=0)

We know that Amir paid $43 for 3 hours. 
Amir would have paid $29 for 2 hours
Amir would have paid $15 for 1 hour
Since the hourly rate is $14, the fixed fee is 15 - 14 = $1

The equation that represents the total cost of renting a scooter is

y = 14x + 1

Rearranging this equation to get the standard form
14x - y + 1 = 0

Part B:

Writing the equation as function ⇒ f(x) = 14x + 1

Part C:

To graph the equation, we can start by choosing the x-intervals, say we have the value of x between 0 and 10

x   0   1     2    3    4    5    6     7    8     9     10
y   1   15  29  43  57  71   85   99  113  127  141

Each pair of x-value and y-value is then plotted on a graph then each plot is joined to draw a straight line.


Answer:

Step-by-step explanation:

Part A: The two points that represent this situation are (3,43) and (8,113). To put this in standard form, I will first find the slope-intercept form. I did this in the image below.

Now, to find the standard form I will rearrange, 14x -y +1 = 0.

Part B: To put this in function notation I simply take my slope-intercept equation of y=14x+1, and replace y with f(x) so,   f(x)=14x+1

Part C: To graph this, put the y, intercept at 1, and give the line a slope of 14/1. Label the x-axis with hours, from 0 -  8, and the y-axis with dollars, from 0-150.

Find the missing factor n(n-3)+2(n-3)=() (n-3)

Answers

Greetings!

Solve for the missing factor: [tex](x)[/tex]
[tex]n(n-3)+2(n-3)=x(n-3)[/tex]

Divide both sides by [tex](n-3)[/tex]:
[tex] \frac{n(n-3)}{(n-3)} + \frac{2(n-3)}{(n-3)}= \frac{x(n-3)}{(n-3)} [/tex]

Cancel Common Factors:
[tex]n+2=x[/tex]

The Missing Factor is:
[tex]\boxed{n+2}[/tex]

I hope this helped!
-Benjamin

decimal fundamentals
add 729.3 + 3.4006

Answers

732.7006 is the answer to this question

A computer simulation tossed a 10-faced die 5 times. How many possible outcomes exist? 9,765,625 100,000 252 100

Answers

10 * 10 * 10 * 10 * 10 = 100,000

Answer:

Possible outcomes in tossing a 10-faced die 5 times is:

100,000

Step-by-step explanation:

A computer simulation tossed a 10-faced die 5 times.

Number of outcomes in each throw=10

Number of outcomes in 2 throws

=Number of outcomes in first throw×number of outcomes in second throw

=10×10

= 100

Hence, Number of outcomes in 5 throws

=10×10×10×10×10

=100,000

Possible outcomes in tossing a 10-faced die 5 times is:

100,000

Help please..........,.,,,

Answers

A, the cost of 6 show tickets is $30, the blue dot is where 30 and 6 intersect. Hope this helps.
A is your answer its  30 dollars for 6 tickets 


Prove that if m, d, and k are integers and d > 0, then (m + dk) mod d = m mod
d.

Answers

from the rules of modular arithmetic, (A+B)mod C= (A)modC +(B)modC

So,  (m + dk) mod d =  (m) mod d+ (dk) mod d

clearly (dk) mod d = 0, as one of the things (dk) mod d represents, is the remainder of dk, when divided by d, which is clearly 0.


Thus

(m + dk) mod d =  (m) mod d+ (dk) mod d= (m) mod d+ 0=(m) mod d


(m + dk) mod d =(m) mod d
Final answer:

To prove that (m + dk) mod d = m mod d, we can use the definition of the modulo operation and properties of integers.

Explanation:

To prove that (m + dk) mod d = m mod d, we can use the definition of the modulo operation and properties of integers. Let's assume that m and d are integers, d > 0, and k is an integer.

Start with the left-hand side: (m + dk) mod d.Using the distributive property, we can rewrite (m + dk) as m mod d + (dk mod d).Since any number mod d is less than d, (dk mod d) is equivalent to 0.Therefore, (m + dk) mod d simplifies to m mod d + 0, which is equal to m mod d.Since the left-hand side is equal to the right-hand side, we have proved that (m + dk) mod d = m mod d.

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Graph y=-1/2x^2-1. Identify the vertex of the graph. tell whether it is a minimum or maximum. (To clarify, 1/2 is a fraction *x^2)

1. (-1,0);minimum
2.(-1,0);maximum
3.(0,1);maximum
4.(0,-1);minimum

Answers

[tex]y= -\frac{1}{2} x^{2}-1[/tex] is a quadratic function, so its graph is a parabola.

Notice that the coefficient of x is 0, this always means that the axis of symmetry is the y-axis.

That is, the vertex of the parabola is in the y-axis, so the x-coordinate of the vertex is 0.

for x=0, y=-1. So the vertex is (0, -1)

The coefficient of [tex] x^{2} [/tex] is negative. This means that the parabola opens downwards, so the vertex is a maximum.


Answer: (0, -1) , maximum (none of the choices)

The equation y = -1/2x^2 - 1 represents a downward opening parabola with the vertex at (0, -1), making it a maximum point.

Graph: The given equation is y = -1/2x^2 - 1. This represents a downward opening parabola.

Vertex: The vertex of the parabola is at (0, -1), making it a maximum point.

Conclusion: The correct answer is option 4: (0, -1); minimum.

Please check my work!

Answers

That is correct! The graph shows that the students their are 40 students that have both a part-time job and a cell phone. B) Is correct.

Two cars leave the same location at the same time but one car is heading north and the other is heading south. After 3 hours, the cars are 360 miles apart. If the car heading north is traveling 10 miles per hour slower than the car heading south, what are the two speeds of the cars?

SHOW THE EQUATION

Answers

3x +3(x-10) = 360

3x +3x-30 =360

6x-30 =360

6x=390

X = 390/6 = 65

65-10 =55

 One car was driving 65 mph

 The other was 55 mph


[tex]d=vt[/tex]
[tex]360=(v_{s})(3)+(v_{n})(3)[/tex]
[tex]360=(v_{s})(3)+((v_{s}-10)(3)[/tex]
[tex]360=3v_{s}+3v_{s}-30[/tex]
[tex]390=6v_{s}[/tex]
[tex]v_{s}=\frac{390}{6}=65[/tex]
[tex]v_{n}=v_{s}-10=65-10=55[/tex]

The south car is traveling at 65mph. The north car is traveling at 55mph. 

On a number line, the directed line segment from Q to S has endpoints Q at –14 and S at 2. Point R partitions the directed line segment from Q to S in a 3:5 ratio. Which expression correctly uses the formula to find the location of point R?

Answers

Final answer:

To find the location of point R on the number line, you can use the formula for finding a point on a line segment given the endpoints and the ratio. In this case, the ratio is 3:5 and the endpoints are -14 and 2.

Explanation:

To find the location of point R, you can use the formula for finding a point on a line segment given the endpoints and the ratio. In this case, the formula is:

R = Q + r(QS)

where Q is the starting point, S is the ending point, r is the ratio between Q and S, and QS is the displacement vector from Q to S. In this problem, Q is -14, S is 2, and the ratio is 3:5. So we can substitute these values into the formula and solve:

R = -14 + (3/8)(2 - (-14)) = -14 + (3/8)(16) = -14 + 6 = -8

Therefore, the location of point R is -8 on the number line.

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The location of point R is -8. The correct answer is option a. [tex]\frac{3}{3+5}(2-(-14))+(-14)[/tex]

To find the location of point R which partitions the directed line segment from Q to S in a 3:5 ratio, we use the section formula. The formula is:

[tex]R =\frac{m}{m+n}(x_2-x_1)+x_1[/tex]

Here, m = 3 and n = 5, while Q is at [tex]x_1 =[/tex] -14 and S is at [tex]x_2 =[/tex] 2.

Plugging in the values, we have:

[tex]R =\frac{3}{3+5}(2-(-14))+(-14)[/tex][tex]R = \frac{3}{8}(2+14)-14[/tex][tex]R = \frac{3}{8} (16)-14[/tex][tex]R = \frac{48}{8}-14[/tex][tex]R = 6-14[/tex]R = -8

Therefore, the location of point R is at -8 on the number line and it is calculated by the expression [tex]R =\frac{3}{3+5}(2-(-14))+(-14)[/tex].

The complete question is:
On a number line, the directed line segment from Q to S has endpoints Q at –14 and S at 2. Point R partitions the directed line segment from Q to S in a 3:5 ratio. Which expression correctly uses the formula [tex]R =\frac{m}{m+n}(x_2-x_1)+x_1[/tex] to find the location of point R?

a. [tex](\frac{3}{3+5})(2-(-14))+(-14)[/tex]

b. [tex](\frac{3}{3+5})(-14-2)+2[/tex]

c. [tex](\frac{3}{3+5})(2-14)+14[/tex]

d. [tex](\frac{3}{3+5})(-14-2)-2[/tex]

WILL GIVE A BRAINLIEST IF THE ANSWER IS CORRECT!!! PLEASE HELP ASAP!!

Find the value of x in the expression (2a^4b^2)^x=4a^8b^4.

A.
x = 2
B.
x = 3
C.
x = 4
D.
x = 5

Answers

remember
[tex](ab)^c=(a^c)(b^c)[/tex]
and
[tex](a^b)^c=a^{bc}[/tex]
so

[tex](2a^4b^2)^x=(2^x)(a^{4x})(b^{2x})[/tex]

so
[tex](2^x)(a^{4x})(b^{2x})=4a^8b^4[/tex]
we can see from the 2^x=4 that x=2
and 4 times 2=8
and 2 times 2=4

x=2
answer is A

The graph shows f(x) = 1/2 and its translation, g(x).


Which describes the translation of f(x) to g(x)?

Answers

As you can see, each point on f(x) is moved up 4 units to get to g(x), so the function is g(x) = f(x) + 4.  The f(x) function cannot possibly be f(x)=1/2, though, because that would be a horizontal line through y = 1/2 and that function is clearly not a horizontal line.  So whatever f(x) is REALLY, add 4 to the tail end of it to show its translation.

Answer:

The translation function g(x) is given as:

[tex]g(x)=\dfrac{1}{2^x}+4[/tex]

step-by-step explanation:

The parent function is f(x) and its representation is given as:

[tex]f(x)=\dfrac{1}{2^x}[/tex]

Now the graph g*x) is obtained by translation of the graph f(x) by some units.

Now as the graph of g(x) is a shift of the graph f(x) or the graph g(x) is translated by 4 units upwards.

hence the function g(x) is represented by:

g(x)=f(x)+4.

Hence the translation function g(x) is given as:

[tex]g(x)=\dfrac{1}{2^x}+4[/tex]

10 POINTS!!! TO ANSWER CORRECTLY AND BRAINLIEST!!!!

Convert these unlike fractions to equivalent like fractions and add them. You must use the LCD to get the answer correct. If possible, reduce the final sum.

Answers

1/5 = 3/15
2/3 = 10/15
3/15 + 10/15 = 13/15

The LCD is 15, so multiply the numerator and denominator of 1/5 by 3, this leaves us with 3/15. Now, multiply the numerator and denominator of 2/3 by 5,
this leaves us with 10/15. Now, if we add 3/15 and 10/15, we get 13/15. This cannot be simplified because 13 is a prime number, thus it is only divisible by itself and 1.

F a company provides 1 1/4 vacation days to its employees every month, how many vacation days does an employee get every year?

Answers

1 1/4 per month

12 months per year

1 1/4 * 12 =

5/4 * 12/1 = 60/4 = 15

 they get 15 days per year

Which of the following rational functions is graphed below?

Answers

I can't see all the answers. Could u take a better pic so I could help because I'd love to!

The solution is, Option A. is correct.

F(x) = 1/ (x-1)(x+4)

What is rational fraction?

A rational fraction is an algebraic fraction such that both the numerator and denominator are polynomials.

Here, we have,

a graph is given .

We need to find which of the given rational functions is graphed in image.

On x-axis, 1 unit = 2 units

Clearly, we can see the graph is not defined at point x = - 4 and at x = 1.

Corresponding to x = - 4, factor is (x+4) .

Corresponding to x = 1, factor is (x-1) .

So, this graph is of the rational fraction

F(x) = 1/ (x-1)(x+4)

Hence, Option A. is correct.

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Convert 48°36'12" to the nearest thousandth of a degree

Answers

48 degrees remains

divide minutes by 60

36/60 = 0.6

then divide seconds by 3600

12/3600=0.003 ( to nearest thousandth)

now add them all up

48 +0.6 + 0.003 = 48.603 degrees

10 employees in an office were absent. Of these absentees constitutes 25% of the employees, what is the total number of employees?

Answers

25% is 1/4, it looks like 10*4 = 40 is the total number, right?

Find the probability of a couple having a baby girlgirl when their fourthfourth child is​ born, given that the first threethree children were all girlsall girls. assume boys and girls are equally likely. is the result the same as the probability of getting all girlsall girls among fourfour ​children?

Answers

Every single time a person has a baby, it has a 50% chance of being a boy or a girl. Having 3 girls previously will not change anything. These events are independent. So the probability of having a baby girl given that the first 3 were girls is 50% or 1/2 or 0.5.

However, prior to having any kids, the probability of having all girls among 4 children is : 1.2 * 1/2 * 1/2 * 1/2 = 1/16...so the result are different.

need help solving for the midpoint between point a and point b

Answers

A is located at (-3,-5) B is located at (1,-9)

-3 + 1 = -2/2 =-1

-5 + -9 = -14/2 = -7

 midpoint is (-1,-7)

The graph below represents which system of inequalities? graph of two infinite lines that intersect at a point. One line is solid and goes through the points 0, 2, negative 2, 0 and is shaded in below the line. The other line is dashed, and goes through the points 0, 6, 3, 0 and is shaded in below the line. y < −2x + 6 y ≤ x + 2 y ≤ −2x + 6 y < x + 2 y < 2 over 3x − 2 y ≥ 2x + 2 None of the above

Answers

(0,2)(-2,0)
slope = (0 - 2) / -2 - 0) = -2/-2 = 1
(0,2)...x = 0 and y = 2
sub and find b, the y int
2 = 1(0) + b
2 = b
equation is : y = x + 2......solid line, means there is an equal sign....shaded below the line means less then....
ur inequality for this line is : y < = x + 2

(0,6)(3,0)
slope = (0 - 6) / (3 - 0) = -6/3 = -2

y = mx + b
slope(m) = -2
(0,6)...x = 0 and y = 6
sub and find b, the y int
6 = -2(0) + b
6 = b

ur equation is : y = -2x + 6....dashed line means there is no equal sign...and shading below the line means less then...
so ur inequality of this line is : y < -2x + 6

In summary, ur 2 inequalities are : y < = x + 2 and y < -2x + 6

To solve the problem we should know about the Equation of a line and slope of a line.

The equations are (y≤ x+2) and (y< -2x+6).

Given to us

One line is solid and goes through the points (0, 2), and (-2, 0) and is shaded below the line.The other line is dashed, goes through the points (0, 6) and (3, 0), and is shaded below the line.

For the first line,

Given the points (0, 2), and (-2, 0), therefore,

[tex]x_2=0\\y_2=2\\x_1=-2\\y_2=0[/tex]

Substituting the values in the formula of the slope,

[tex]m=\dfrac{(y_2-y_1)}{(x_2-x_1)}[/tex]

[tex]m=\dfrac{2-0}{0-(-2)} = \dfrac{2}{2} = 1[/tex]

Substitute the value of slope and a point in the formula of line,

[tex]y = mx+c\\y_2 = mx_2+c\\2 = (1)0 +c\\c = 2[/tex]

Thus, the equation of the line is y=x+2, but as given the line is solid and is shaded below the line. therefore,

y≤ x+2

For the Second line,

Given the points (0, 6) and (3, 0), therefore,

[tex]x_2=0\\y_2=6\\x_1=3\\y_2=0[/tex]

Substituting the values in the formula of the slope,

[tex]m=\dfrac{(y_2-y_1)}{(x_2-x_1)}[/tex]

[tex]m=\dfrac{6-0}{0-3} = \dfrac{6}{-3} = -2[/tex]

Substitute the value of slope and a point in the formula of line,

[tex]y = mx+c\\y_2 = mx_2+c\\6 = (-2)0 +c\\c = 6[/tex]

Thus, the equation of the line is y=-2x+6, but as given the line is shaded below the line. therefore,

y< -2x+6

Hence, the equations are (y≤ x+2) and (y< -2x+6).

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What is the length of the hypotenuse of the triangle?

Answers

15^2 + 8^2 = 225 + 64 = 289

square root 289 = 17

answer

length of the hypotenuse of the triangle = 17 cm (3rd choice)

Answer:

length of the hypotenuse = 17 cm

Step-by-step explanation:

To find the length of the hypotenuse of any triangle we use pythagorean theorem

[tex]c^2 = a^2 + b^2[/tex]

Where c is the hypotenuse

a  and b are the legs of the triangle

Given : a= 8 cm, and b= 15 cm

We find hypotenuse C

[tex]c^2 = 15^2 + 8^2[/tex]

[tex]c^2 = 225 + 64[/tex]

[tex]c^2 = 289[/tex]

Take square root on both sides

c= 17

So length of the hypotenuse = 17 cm

D: y> -1/3 x+1 helpppp

Answers

The answer is A. It is less than or equal to because the line is solid instead of dashed. It is less than because the shaded portion is below the line.

Find the value of the variable and DF if D is between C and F if CD 4y -9, DF 2y-7, and CF 14.

Answers

CF = CD + DF (since D is simply a point on the line, and C to that point added onto F to that point is CF), so 4y-9+2y-7=14. Adding it up, we get 6y-16=14 and adding by 16 we get 30=6y. Dividing both sides by 6, we get y=5. Plugging that into DF, we get 10-7=DF=3

From a deck of 52 cards, one card is drawn at random. Match the following subsets with their correct probabilities.
1. P(face card)
2. P(seven of hearts)
3. P(no black)
4. P(king)
5. P(diamond)

Answers

1.3/13(if you mean jacks queens and kings)
2.1/52
3.1/2
4.1/13
5.1/4

Answer:

P(face card)=3/13 P(seven of hearts)=1/52P(no black)=1/2P(king)=1/13P(diamond)=1/4

Step-by-step explanation:

We know that there are a total 52 cards out of which:

There are 12 face cards ( 4 kings,4 queen and 4 jack)

There are 4 pack:

13- spades     13- club     13-heart     13-diamond.

Out of which there are 26 black cards( 13 spade and 13 club)

There are 26 red cards( 13 heart and 13 diamond)

Now , we are asked to find the probability of each of the following,

1)

P(face card)

Since there are total 12 face cards out of 52 playing cards.

Hence,

P(face card)=12/52=3/13

2)

P( seven of hearts)

As there is just 1 seven of heart out pf 52 cards.

Hence,  P(seven of hearts)=1/52

3)

P(no black)

This means we are asked to find the probability of red card.

As there are 26 red card.

Hence P(no black)=26/52=1/2

4)

P(king)

As there are 4 kings out of 52 cards.

Hence, P(king)=4/52=1/13

5)

P(diamond)

As there are total 13 cards of diamond.

Hence,

P(diamond)=13/52=1/4

If a line contains the point (0, -1) and has a slope of 2, then which of the following points also lies on the line?

A. (2, 1)
B. (1, 1)
C. (0, 1)

Answers

The answer is B because y=2x-1
Answer:

                The point that lie on the line is:

                        B.  (1,1)

Step-by-step explanation:

We are given that a line passes through the point (0,-1) and has a slope of 2.

We know that the equation of a line passing through (a,b) and having slope m is given by:

           [tex]y-b=m(x-a)[/tex]

Here we have:  (a,b)=(0,-1) and m=2

This means that the equation of line is:

[tex]y-(-1)=2(x-0)\\\\y+1=2x\\\\y=2x-1[/tex]

Now we will check which option is true.

A)

                (2,1)

when x=2

we have:

[tex]y=2\times 2-1\\\\\\y=4-1\\\\\\y=3\neq 1[/tex]

Hence, option: A is incorrect.

B)

                     (1,1)

when x=1

we have:

[tex]y=2\times 1-1\\\\\\y=2-1\\\\\\y=1[/tex]

                Hence, option: B is correct.

C)

                      (0,1)

when x=0

we have:

[tex]y=2\times 0-1\\\\\\y=0-1\\\\\\y=-1\neq 1[/tex]

Hence, option: C is incorrect.

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