You are dealt one card from a standard 52-card deck find the probability of being dealt an ace or an 8

Answers

Answer 1

there are 4 Aces and 4 8's for a total of 8 cards

52 cards in a deck

 so probability of picking an Ace or 8 = 8/52

Answer 2

Final answer:

The probability of being dealt an ace or an 8 from a standard 52-card deck is 2/13, which is approximately 15.38%.

Explanation:

The question asks for the probability of being dealt an ace or an 8 from a standard 52-card deck. There are 4 aces and 4 eights in a 52-card deck. To calculate the probability of getting either an ace or an 8, we add the probability of getting an ace to the probability of getting an 8. The probability of drawing an ace (P(Ace)) is 4/52 and the probability of drawing an 8 (P(8)) is also 4/52. Since these are mutually exclusive events (you cannot draw an ace and an 8 simultaneously with one card), we can simply add these probabilities together:

P(Ace or 8) = P(Ace) + P(8)
= (4/52) + (4/52)
= 8/52
= 2/13

Therefore, the probability of being dealt an ace or an 8 is 2/13, which is approximately 0.1538 or 15.38%.


Related Questions

2s + 5 greater than or equal to 49

Answers

s is greater than or equal to 22

The value of s is greater or equal to 22.

What is inequality?

It shows a relationship between two numbers or two expressions.

There are commonly used four inequalities:

Less than = <

Greater than = >

Less than and equal = ≤

Greater than and equal = ≥

We have,

2s + 5 greater than or equal to 49.

This can be written as,

(2s + 5) ≥ 49

Solve for s.

2s + 5 ≥ 49

2s ≥ 49 - 5

2s ≥ 44

s ≥ 22

Thus,

s is greater than or equal to 22.

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Suppose S and T are mutually exclusive events. Find P(S or T) if P(S) = 65% and P(T) = 7%.

a. 4.55%
b. 72%
c. 58%
d. 455%

Answers

When you have two mutually exclusive events, to find the probability of one or another, you add the probabilities.
65+7=72
Final answer: B

Answer: P(S\cup T)=72%

Step-by-step explanation:

We are given that S and T are mutually exclusive events.

Therefore, the intersection of both the events must be 0.

i.e. [tex]p(S\cap T)=0[/tex]

P (S) = 65% and P(T) = 7%

We know that P(S or T)=[tex]P(S\cup T)=P(S)+P(T)-P(S\cap T)[/tex]

[tex]\Rightarrow P(S\cup T)=65\%+7\%=72\%[/tex]

Hence, P(S\cup T)=72%

please help me right now will give brainliest and offering 50 points





Above are two different models of the same hexagon. If the side length of the model on the left is in, what is the corresponding side length of the model on the right?

A. 10 1/4 in


B. 4 in


C. 5 in


D. 3 3/4 in


Answers

You didn't finish your question what exactly are you asking? What side? "If the side length of the model on the left is in" in what?

Answer:

The answer is 5 in.

Step-by-step explanation:

Since the scale for the model on the left is 1 in = 12 ft, and the scale for the model on the right is 1 in = 3 ft, the model on the right is 4 times larger than the model on the left.

Multiply the side length of the model on the left by 4 to find the side length of the model on the right.

John’s gross pay for the week is $500. He pays 1.45 percent in Medicare tax, 6.2 percent in Social Security tax, 2 percent in state tax, 20 percent in federal income tax, and $20 as an insurance deduction. He does not have any voluntary deductions. What is John’s net pay for the week?

Answers

gross pay = 500

deductions :
medicare tax : 0.0145(500) = 7.25
S.S tax : 0.062(500) = 31.00
sales tax : 0.02(500) = 10.00
income tax : 0.2(500) = 100
insurance = 20
total deductions : 7.25 + 31 + 10 + 100 + 20 = 168.25

gross pay - deductions = net pay
500 - 168.25 = net pay
331.75 = net pay <===
Final answer:

John's net pay is calculated by subtracting deductions for Medicare, Social Security, state and federal taxes, and insurance from his gross pay of $500. The total deductions amount to $168.25, resulting in a net pay of $331.75.

Explanation:

Calculation of John's Net Pay

To calculate John's net pay, we need to subtract all the deductions from his gross pay. Since his gross pay is $500, we will apply the following deductions:

Medicare tax: 1.45% of $500 = $7.25

Social Security tax: 6.2% of $500 = $31.00

State tax: 2% of $500 = $10.00

Federal income tax: 20% of $500 = $100.00

Insurance deduction: $20.00

Add up all deductions: $7.25 (Medicare) + $31.00 (Social Security) + $10.00 (State Tax) + $100.00 (Federal Tax) + $20.00 (Insurance) = $168.25

John's net pay is therefore calculated by subtracting the total deductions from his gross pay: $500.00 - $168.25 = $331.75.

A supply company manufactures copy machines. The unit cost C (the cost in dollars to make each copy machine) depends on the number of machines made. If x machines are made, then the unit cost is given by the function
C (x) = 0.8x ^ 2 - 256x +25,939 . How many machines must be made to minimize the unit cost? Do not round your answer.
Number of copy machines:

Answers

To minimize unit cost, 160 machines must be made.

Step-by-step explanation:

Find the first derivative of the cost function:  C'(x) = 1.6x - 256.

Set the derivative equal to 0 and solve for x to find the critical point: 1.6x - 256 = 0. x = 160.

Check the nature of the critical point using the second derivative test to confirm that x = 160 gives the minimum cost.

Therefore, the number of machines that must be made to minimize the unit cost is 160 machines.

The number of machines that must be made to minimize the unit cost is 160.

To find the number of machines that must be made to minimize the unit cost, we need to find the minimum point of the function [tex]\(C(x) = 0.8x^2 - 256x + 25,939\).[/tex]

The function \(C(x)\) represents a quadratic equation, and the vertex of a quadratic equation represents its minimum or maximum point. The x-coordinate of the vertex of a quadratic function in the form [tex]\(ax^2 + bx + c\) is given by \(-\frac{b}{2a}\).[/tex]

[tex]For the function \(C(x) = 0.8x^2 - 256x + 25,939\), we have \(a = 0.8\) and \(b = -256\).Now, let's calculate the x-coordinate of the vertex:\[ x_{\text{vertex}} = -\frac{b}{2a} = -\frac{-256}{2 \times 0.8} = -\frac{-256}{1.6} = 160 \][/tex]

So, the number of machines that must be made to minimize the unit cost is 160.

How many 2n-digit positive integers can be formed if the digits in odd positions (counting the rightmost digit at position 1) must be odd and the digits in even positions must be even and positive?

Answers

Final answer:

To find the number of 2n-digit integers where odd position digits are odd, and even position digits are even and positive, we calculate based on the choices for each position, giving us a result of (5^n) * (4^n).

Explanation:

We encounter a combinatory problem in working out how many 2n-digit positive integers can be formed if the digits in odd positions must be odd and the digits in even positions must be even. Before proceeding, it's important to grasp the concept of positional numbering, where the rightmost digit is considered at position 1, and the counting proceeds from right to left.

For a 2n-digit positive integer, i.e., an integer with an even number of digits, there will be n digits at odd positions and n digits at even positions. For the odd positions, the digits can be any one of the five odd integers (1, 3, 5, 7, 9) and for the even positions, the digits can be any one of the four even positive integers (2, 4, 6, 8) because 0 is excluded as the question mentions they should be positive.

Therefore, for each position, we have a choice of five odd integers or four even integers. Since there are n odd positions and n even positions, we end up with (5^n) * (4^n) total possibilities or combinations.

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The total number of valid 2n-digit positive integers, where digits in odd positions must be odd and digits in even positions must be even, is calculated using the formula 5ⁿ * 4ⁿ.

To solve this problem, we need to consider the constraints given: digits in odd positions must be odd and digits in even positions must be even. Let's break down the problem step-by-step:

We have 2n-digit numbers. Therefore, there are n odd positions and n even positions.For the odd positions (1st, 3rd, 5th, ....., 2n-1), each digit can be 1, 3, 5, 7, or 9. So, there are 5 choices for each position.For the even positions (2nd, 4th, 6th, ....., 2n), each digit can be 2, 4, 6, or 8. There are 4 choices for each position.To find the total number of such 2n-digit positive integers, multiply the number of choices for all positions:

Total combinations = (Number of choices for odd positions) n * (Number of choices for even positions) n = 5ⁿ * 4ⁿ

This is the formula to calculate the number of valid 2n-digit integers under the given constraints.

If a boatman rows his boat 35km up stream and 55km downstream in 12 hours and he can row 30km upstream and 44 km downstream in 10hr , then the speed of the stream and that of the boat in still water

Answers

To answer this item, we let x be the speed of the boat in still water. The speed of the current, we represent as y.

When the boat travels upstream or against the current, the speed is equal to x – y and x + y if it travels downstream or along with the current.

The time it takes for the an object to travel a certain distance is calculated by dividing the distance by the speed.

First Travel:    35 / (x – y)   + 55 / (x + y) = 12

Second travel: 30 / (x – y)   + 44 / (x + y) = 10

Let us multiply the two equations with the (x-y)(x+y)

This will give us,

              35(x + y) + 55(x – y) = 12(x-y)(x+y)

              30(x + y) + 44(x – y) = 10(x-y)(x+y)

Using dummy variables:

Let a = x + y and b be x – y

                35a + 55b = 12ab

                30a + 44b = 10ab

From the first equation,

                     b = 35a/(12a – 55)

Substituting to the second equation,

                30a + 44(35a/(12a – 55)) = 10a(35a/(12a-55))

The value of a is 11.

              b = 35(11)/(12(11) – 55))

              b = 5

Putting back the equations,

        x + y = 11

       x – y = 5

Adding up the equations give us,

  2x = 16

    x = 8 km/hr

The value of x, the speed of the boat in still water, is 8 km/hr. 

Answer:

speed of the stream = 3 km/hr

and speed of boat in still water= 8 km/hr

Step-by-step explanation:

Let s be the speed of the boat upstream

and s' be the speed of the boat downstream.

We know that:

[tex]Time=\dfrac{distance}{speed}[/tex]

Hence, we get:

  [tex]\dfrac{35}{s}+\dfrac{55}{s'}=12[/tex]

and

[tex]\dfrac{30}{s}+\dfrac{44}{s'}=10[/tex]

Now, let

[tex]\dfrac{1}{s}=a\ and\ \dfrac{1}{s'}=b[/tex]

Hence, we have:

[tex]35a+55b=12--------------(1)\\\\\\and\\\\\\30a+44b=10--------------(2)[/tex]

on multiplying equation (1) by 4 and equation (2) by 5 and subtract equation (1) from (2) we get:

[tex]a=\dfrac{1}{5}[/tex]

and by putting value of a in (2) we get:

[tex]b=\dfrac{1}{11}[/tex]

Hence, speed of boat in upstream= 5 km/hr

and speed of boat in downstream= 11 km/hr

and we know that:

speed of boat in upstream=speed of boat in still water(x)-speed of stream(y)

and speed of boat in downstream=speed of boat in still water(x)+speed of stream(y)

Hence, we get:

[tex]x-y=5\\\\\\and\\\\\\x+y=11[/tex]

Hence, on solving the equation we get:

[tex]x=8[/tex]

and y=3

Hence, we get:

speed of the stream = 3 km/hr

and speed of boat in still water= 8 km/hr

if the divisor is 40 what is the least 3 digit number dividend that would give a remainder of 4

Answers

The answer to this question is:

If the divisor is 40 what is the least 3 digit number dividend that would give a remainder of 4"124/40"

Hope this help, Lukifer677
Your Welcome :)
where the divisor is 40 ... 40 x 3 = 120, this is a 3 digit number and the least 3 digit number

What the answer to this question?

Answers

volume = (1/3)*PI*(r1^2+r1*r2+r2^2)*h

 h=10

r1=5

r2=2

= 408.41 cubic inches

 round off answer as needed.

A new bank account is opened on week 1 with a $200 deposit. After that first week, weekly deposits of $55 are made in the account. If y represents the total deposited into the account and x represents the number of weeks, which function rule describes this situation?

Answers

On week 1, we started with a deposit of $200. Every week from that point on, we place a deposit of $55.

We know y is total amount of money (deposits) in the bank account.
We also know x represents the number of weeks.

On week 1, we would have $200 in the back account.
On week 2, we would have $200 + $55 or $255 in the bank account.

So, we could build an expression of 55(x - 1) + 200 which is equal to y.

So, y = 55(x - 1) + 200 is the answer.

What is the value of 3×5+6×2+1

Answers

Just do [tex]PEMDAS[/tex] 

[tex]Parentheses \\ Equations \\ Multiplication \\ Addition \\ Subtraction[/tex]

Looks like we're doing: [tex]multiplication [/tex] and [tex]addition [/tex]

[tex]3(5) + 6(2) + 1 \\ 3(5)= 15 \\ 15 + 6(2) = \\ 6(2) =12 \\ 15 + 12 = 27 \\ 27 + 1 = 28 \\ Answer: 28 [/tex]

~ [tex]MeIsKaitlyn :) [/tex]

                                 Good luck on your assignment and enjoy your day! 

1 1 2 4 3 9 4 what is the next number

Answers

The answer is 16. 1^2 is 1, 2^2 is 4, 3^2 is 9, and 4^2 would be 16. 

Mrs. Jackson has $7,000 to invest. If she invests part at 6% simple annual interest and part at 8% simple annual interest, she will get an annual return of $520. How much should she invest at 8%?

Answers

let's say she invest the amounts of "a" at 6% and "b" at 8%.

well, she has to invest on both amounts, 7000 total, thus a + b = 7000

how much is 6% of a? well, (6/100) * a, or 0.06a.
how much is 8% of b? well, (8/100) * b, or 0.08b.

now, we know the annual return in interest from those two amounts is 520.
thus 0.06a + 0.08b = 520

[tex]\bf \begin{cases} a + b = 7000\implies \boxed{a} = 7000-b\\ 0.06a + 0.08b = 520\\ --------------\\ 0.06\left( \boxed{7000 - b} \right)+0.08b = 520 \end{cases}[/tex]

solve for "b".

what is the gcf of 120 and 72

Answers

Hello there!

The GCF acronym between two or more numbers means the "greatest common factor."
The greatest common factor means the highest factor two numbers have in common.
Let's factor out our numbers.

120;
1 x 120
2 x 60
3 x 40
5 x 24
6 x 20
8 x 15
10 x 12

72;
1 x 72
2 x 36
3 x 24
4 x 18
6 x 12
8 x 9

Now, let's look at the highest factors that are in common between these two numbers.

The highest factor is 12, which is your GCF.

I hope this helps!

A stocker put 57 boxes of detergent on the shelves in 2 minutes. After 5 minutes, he had put 117 boxes on the shelves. How many boxes were on the shelves when he started?

Answers

57 boxes of detergent on the shelves in 2 minutes
After 5 minutes, he had put 117 boxes on the shelves

117 - 57 = 60 (60 boxes of detergent for 3 minutes)
60/3 = 20 (20 boxes of detergent per minute)
so

20 x 5 = 100 boxes of detergent 

117 - 100 = 17 boxes

answer
17 boxes of detergent were on the shelves when he started
(2,57)(5,117)
slope = (117 - 57) / (5 - 2) = 60/3 = 20

y = mx + b
slope(m) = 20
(2,57)...x = 2 and y = 57
sub and find b, the y int
57 = 20(2) + b
57 = 40 + b
57 - 40 = b
17 = b

equation is : y = 20x + 17....with x being the number of minutes, and 17 being the number of boxes on the shelf when he started

what is 1/3m-1-1/2n when m=21 and n=12

Answers

((1/3)(21)-1-(1/2)(12))=0

Answer:

Value of the expression is 0

Step-by-step explanation:

[tex]\frac{1}{3} m -1-\frac{1}{2} n[/tex]

Given the value of m and n

m= 21  and n= 12

We plug in the value of m  and n in the given expression

[tex]\frac{1}{3} m -1-\frac{1}{2} n[/tex]

[tex]\frac{1}{3}(21) -1-\frac{1}{2}(12)[/tex]

[tex]\frac{21}{3} -1-\frac{12}{2}[/tex]

[tex]7-1-6= 0[/tex]

So the value of given expression is 0 when we plug in the values of m  and n

jim is running on a trail that is 5/4 of a mile long. so far he has run 2/3 of the trail. how many miles has he run so far

Answers

(5/4) / (2/3)
= 5/6

therefore: he has run 5/6 miles so far

Rationalize the denominator of square root of negative 16 over open parentheses 1 plus i close parentheses plus open parentheses 6 plus 3 i.

Answers

[tex]\bf \cfrac{\sqrt{-16}}{(1+i)+(6+3i)}\implies \cfrac{\sqrt{-1\cdot 16}}{1+i+6+3i}\implies \cfrac{\sqrt{-1}\cdot \sqrt{16}}{7+4i} \\\\\\ \cfrac{i\cdot \sqrt{4^2}}{7+4i}\implies \cfrac{4i}{7+4i}\impliedby \begin{array}{llll} \textit{now, we'll multiply by the}\\ \textit{conjugate of the denominator} \end{array}\\\\ -------------------------------\\\\[/tex]

[tex]\bf \textit{and recall }\textit{difference of squares} \\ \quad \\ (a-b)(a+b) = a^2-b^2\qquad \qquad a^2-b^2 = (a-b)(a+b)\\\\ \textit{also recall that }i^2=-1 \\\\ -------------------------------\\\\[/tex]

[tex]\bf \cfrac{4i}{7+4i}\cdot \cfrac{7-4i}{7-4i}\implies \cfrac{4i(7-4i)}{(7+4i)(7-4i)}\implies \cfrac{28i-16i^2}{7^2-(4i)^2} \\\\\\ \cfrac{28i-16(-1)}{49-(4^2i^2)}\implies \cfrac{28i+16}{49-[16(-1)]}\implies \cfrac{16+28i}{49+16}\implies \cfrac{16+28i}{65} \\\\\\ \cfrac{16}{65}+\cfrac{28i}{65}[/tex]

What is the next value.
4 D 7 G 10 J 13

Answers

Numbers means the number of letter in the alphabet. D is the fourth letter, G is the seventh letter, J is the 10-th letter.
The next value ​​in the row is M (thirteenth letter).

The next value in the sequence is 16, following an increment of 3 in each step.

The next value in the sequence is 16.

The sequence increments by 3 starting from 4 (4, 7, 10, 13, ...)

Therefore, the next value after 13 would be 13 + 3 = 16.

If log65 = 1.812, what is the value of log 1000 65? a. 0.1812 b. 0.00182 c. 0.604 d. 0.0604

Answers

We know that : log 65 = 1.812 or: log (10) 65 = 1.812 ( logarithm with the base of 10 )
log (1000) 65 = log ( 10^3 ) 65 = 1/3 * log (10) 65 =  
/ this is because the logarithmic rule is:  log(a^b) x = 1/b * log (a) x /
= 1/3 * 1.812 = 0.604
Answer: c. 0.604

Answer:

0.604 on a p e x

What is the product of 119 thousandths times 10?
a. 119 hundreths
b. 119 thousands
c. 119 tenths

Answers

the answer is A becaues 119 thousand times 10 equals 1190000
then you divide it by 100 to get A.119 hunderths

Answer:

119 hundreths

Step-by-step explanation:

To Find: What is the product of 119 thousandths times 10?

Solution:

Thousandths can be represented in the fraction form as[tex]\frac{1}{1000}[/tex]

So, 119 thousandths = [tex]\frac{119}{1000}[/tex]

Now to find the product of 119 thousandths times 10

[tex]\Rightarrow \frac{119}{1000} \times 10[/tex]

[tex]\Rightarrow \frac{119}{100} [/tex]

Now hundreths  can be represented in the fraction form as[tex]\frac{1}{100}[/tex]

So, [tex]\Rightarrow \frac{119}{100} [/tex]  = 119 hundreths.

Hence the product of 119 thousandths times 10 is 119 hundreths.

Thus Option A is True.

Adam can spend a maximum of $252 on office supplies. Each ream of paper costs $6. Each ink cartridge costs $18. Which of the following graphs represents the possible combinations of paper and ink cartridges that he may buy? *Graph pictures below*

Answers

Your answer is A.
If she just bought ink cartridges she could buy 14.
252 / 18 = 14
If she just bought paper she could buy 42 reams.
252 / 6 = 42

Answer:

Option A The graph in the attached figure

Step-by-step explanation:

Let

x-----> the number of ream of paper

y-----> the number of ink cartridge

we know that    

[tex]6x+18y\leq 252[/tex] ----> inequality that represent the possible combinations of paper and ink cartridges that Adam may buy

using a graphing tool

the solution is the triangular shaded area

see the attached figure

A salesperson sold a total of $6,400.00.If her rate of commission is 6%, what is her commission?

Answers

multiply 6400 x 6%

6% = 0.06

6400 x 0.06 = 384

 her commission was $384

Answer:

The commission amount of the salesperson is $384.

Step-by-step explanation:

A salesperson sold a total of $6,400.00.

The rate of commission is 6% or 0.06. Commissions are based on sales. These are some percentage of the sales amount.

So, here the amount will be = [tex]0.06\times6400=384[/tex] dollars

So, the commission amount of the salesperson is $384.

If thewronskian w of f and g is 3e4t,and if f(t) = e2t,find g(t).

Answers

[tex]W(f(x),g(x))=\begin{vmatrix}f(x)&g(x)\\f'(x)&g'(x)\end{vmatrix}=f(x)g'(x)-g(x)f'(x)[/tex]

We have [tex]f(t)=e^{2t}\implies f'(t)=2e^{2t}[/tex], so

[tex]W(f(t),g(t))=e^{2t}g'(t)-2e^{2t}g(t)=3e^{4t}[/tex]
[tex]\implies e^{-2t}g'(t)-2e^{-2t}g(t)=3[/tex]
[tex]\implies\dfrac{\mathrm d}{\mathrm dt}[e^{-2t}g(t)]=3[/tex]
[tex]\implies e^{-2t}g(t)=\displaystyle\int3\,\mathrm dt[/tex]
[tex]\implies e^{-2t}g(t)=3t+C[/tex]
[tex]\implies g(t)=3te^{2t}+Ce^{2t}[/tex]

where [tex]C[/tex] is any arbitrary constant.

A spring is oscillating so that its length is a sinusoidal function of time. Its length varies from a minimum of 10 cm to a maximum of 14 cm. At t=0 seconds, the length of the spring was 12 cm, and it was decreasing in length. It then reached a minimum length at time t= 1.2 seconds. Between time t=0 and t=8 seconds, how much of the time was the spring longer than 13.5 cm?

Answers

Let the x(t) represent the motion of the spring as a function of time, t.

The length of the oscillating spring varies from a minimum of 10 cm to a maximum of 14 cm.
Therefore its amplitude is A = (14 - 10)/2 = 2.

When t = 0 s, x = 12 cm.
Therefore the function is of the form
x(t) = 2 sin(bt) + 12

At t=0, x(t) is decreasing, and it reaches its minimum value when t = 1.2 s.
Therefore, a quarter of the period is 1.2 s.
The period is given by
T/4 = 1.2
T = 4.8 s

That is,
b = (2π)/T = (2π)/4.8 = π/2.4 = 1.309

The function is
x(t) = 2 sin(1.309t) + 12
A plot of x(t) is shown below.

When x(t) = 13.5, obtain
2 sin(1.309t) + 12 = 13.5
sin(1.309t) = (13.5 - 12)/2 = 0.75
1.309t = sin⁻¹ 0.75 = 0.8481 or π - 0.8481
t = 0.8481/1.309 or t = (π - 0.8481)/1.309
  = 0.649 or 1.751
The difference in t is 1.751 - 0.649 = 1.1026.

This difference occurs twice between t=0 and t=8 s.
Therefore the spring length is greater than 13.5 cm for 2*1.1026 = 2.205 s.

Answer:
Between t=0 and t=8, the spring is longer than 13.5 cm for 2.205 s.

How much interest is gained if $250 is deposited in your bank account at the end of the year for each of the next 7 years? savings account pays 8% compounded annually?

Answers

Compounded Interest after 7 years will be $744.50

The Sugar Sweet Company is going to transport its sugar to market. It will cost $5250 to rent trucks, and it will cost an additional $175 for each ton of sugar transported. Let C represent the total cost (in dollars), and let S represent the amount of sugar (in tons) transported. Write an equation relating C to S, and then graph your equation using the axes below.

Answers

c(s)=175s+5250

So to graph this you only need two points because it is a linear function and the velocity is constant.

When s=0, c=5250, so you have the point (0, 5250).  The you can just use the next point, (1, 5425).  Now you can connect the two dots and extend as far upward and to the right as necessary.  Do not go to the left and down as negative s values have no meaning to this real world problem as sugar cannot be negatively shipped :P
Final answer:

The linear equation formed is C = 5250 + 175S, where C is the total cost and S is the amount of sugar in tons. This expresses the cost for Sugar Sweet Company to transport its sugar to the market, beginning from a fixed cost of $5250 with an additional $175 charged per ton of sugar transported.

Explanation:

The question involves the creation of a linear equation that represents the total cost, C, of transporting sugar. We are told the initial cost of renting trucks is $5250 and there's an additional cost of $175 for each ton of sugar, S.

Therefore, we can write the equation as: C = 5250 + 175S.

To graph this equation, start at the point (0, 5250) on the y-axis which represents the initial cost. The slope of the line is 175, which means for each ton of sugar transported, the cost increases by $175. From the starting point, you can plot other points moving up vertically 175 units for each unit moved to the right horizontally.

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Write an algebraic expression which represents the volume of a box whose width is 4y, height is 6y and length is 3y + 1.

Answers

The correct expression is: 72y^3

State whether each situation involves a combination or a permutation.

4 of the 20 radio contest winners selected to try for the grand prize

5 friends waiting in line at the movies

6 students selected at random to attend a presentation

a) permutation, combination, permutation
b) combination, permutation, permutation
c) combination, permutation, combination
d) permutation, combination, combination

Answers

Answer:

4 of the 20 radio contest winners selected to try for the grand prize : C

5 friends waiting in line at the movies: C

6 students selected at random to attend a presentation: P

Final answer:

The scenarios illustrate combination when order does not matter (selecting contest winners and student attendees) and permutation when order matters (friends in line). The correct sequence is combination, permutation, combination.

Explanation:

In the context of the scenarios provided, we need to differentiate whether the situations are examples of combinations or permutations. A permutation is an arrangement of objects where order matters, while a combination is a selection of objects where order does not matter.

4 of the 20 radio contest winners selected to try for the grand prize - This is a combination, as the order in which the winners are selected is not relevant.5 friends waiting in line at the movies - This is a permutation, as the order in which the friends are lined up matters.6 students selected at random to attend a presentation - This is a combination, as the order of selection does not impact which students attend.

Thus, the correct answer to the sequence of scenarios is: combination, permutation, combination, which correlates with option c.

Which algebraic expression shows the average melting points of helium, hydrogen, and neon if h represents the melting point of helium, j represents the melting point of hydrogen, and k represents the melting point of neon?

Answers

Given:
h = melting point of helium
j =  melting point of hydrogen
k = melting point of neon

Number of values = 3
Therefore, the average is
(Sum of values)/(Number of values) = (h+j+k)/3

Answer:
The average melting point of helium, hydrogen, and neon is
(h+j+k)/3

Final answer:

The algebraic expression for finding the average melting points of helium, hydrogen, and neon, using variables h, j, and k as their respective melting points, is (h + j + k) / 3.

Explanation:

The question asks for the algebraic expression that represents the average melting points of helium, hydrogen, and neon. The variables h, j, and k denote the individual melting points of these elements, respectively. To calculate the average melting point, you would add the melting points of each element and divide by the number of elements.

The algebraic expression for the average melting point is:

(h + j + k) / 3

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