Yesterday, Chau had m baseball cards. Today, he gave 5 away. Using m , write an expression for the number of cards Chau has left.

Answers

Answer 1

If m = baseball cards he had yesterday, and today he got rid of 5, the expression is equal to

m - 5 = x.

As an example of what the answer is, replace m with 10.

If he had 10 baseball cards and gave away 5 today, x = 5.

The answer is m - 5 = x.

Related Questions

43 ones x 3 tens= Tens

Answers

43 ones x 3tens would give you 129 tens. 43x30=1290 so you then divide 1290 by 10 which gives you 129 tens

Place value is the value of each digit in a number.

The value of 43 ones x 3 tens is 129 tens

43 ones x 3 tens = 129 tens.

What is a place value?

Place value is the value of each digit in a number.

Example: 2345.67

2 – thousands place value

3 – hundreds place value

4 – tens place value

5 – ones place value

6 – tenths place value

7 – hundredths place value

We have,

43 ones x 3 tens

43 ones can be written as 43

3 tens can be written as 30

So,

43 ones x 3 tens = 43 x 30

43 x 30 = 1290

This means,

1290 = 129 tens

43 ones x 3 tens = 129 tens

Thus,

The value of 43 ones x 3 tens is 129 tens

Learn more about place value here:

https://brainly.com/question/27734142

#SPJ2

Danny “Dimes” Donahue is a neighborhood’s 9-year old entrepreneur. His most recent venture is selling homemade brownies that he bakes himself. At a price of $1.75 each, he sells 100. At a price of $1.25 each, he sells 300.

Answers

a. The elasticity of demand is 0.0225.

b. Demand is inelastic over this price range.

c. Total revenue would increase due to the more elastic demand resulting in a greater quantity demanded with a price decrease.

Let's first calculate the price elasticity of demand using the midpoint method:

a. Price elasticity of demand formula:

[tex]\[ E_d = \frac{\text{Percentage change in quantity demanded}}{\text{Percentage change in price}} \times \frac{\text{Average price}}{\text{Average quantity}} \][/tex]

Percentage change in quantity demanded:

[tex]\[ \text{Percentage change in quantity demanded} = \frac{300 - 100}{\frac{300 + 100}{2}} \times 100\% = \frac{200}{200} \times 100\% = 100\% \][/tex]

Percentage change in price:

[tex]\[ \text{Percentage change in price} = \frac{1.25 - 1.75}{\frac{1.25 + 1.75}{2}} \times 100\% = \frac{-0.5}{1.5} \times 100\% = -33.33\% \][/tex]

Average price and average quantity:

[tex]\[ \text{Average price} = \frac{1.25 + 1.75}{2} = \frac{3}{2} = 1.50 \]\[ \text{Average quantity} = \frac{300 + 100}{2} = \frac{400}{2} = 200 \][/tex]

Now, we can plug these values into the elasticity formula:

[tex]\[ E_d = \frac{100\%}{-33.33\%} \times \frac{1.50}{200} \]\[ E_d = -3 \times 0.0075 \]\[ E_d = -0.0225 \][/tex]

a. The elasticity of demand is 0.0225.

b. Since the elasticity of demand is less than 1, demand is inelastic over this price range.

c. If demand had the same elasticity for a price decline from $1.25 to $0.75 as it does for the decline from $1.75 to $1.25, cutting the price from $1.25 to $0.75 would increase Danny's total revenue because the demand would be more elastic, resulting in a greater increase in quantity demanded compared to the decrease in price.

Complete Question:

Instructions: Use the midpoint method and round your answer to 2 decimal places. Do not include a minus sign.

a. What is the elasticity of demand?

b. Is demand elastic or inelastic over this price range?

c. If demand had the same elasticity for a price decline from $ 1.25 to $ 0.75 as it does for the decline from $ 1.75 to $ 1.25, would cutting the price from $ 1.25 to $ 0.75 increase or decrease Danny's total revenue?

How many choices if 2 of the friends will only attend together?

Answers

Is there more information for this question? It seems like you forgot something.

I Need to identify the property that justifies each step to simplify the expression

Answers

What is the expression ? And there are four properties
1) equality of addition , subtraction , multiplication, and division

Dennis wrote down a three digit number, The digit in the tens place is 2 more than the digit in the hundreds place. The digit in the ones place is 6less than the digit in the tens place. The digit in the hundreds place is odd number. What is the three digit number?

Answers

793 . 9-7= 2. 9-6 =3 and 7 is an odd number

round 7300 correct to one significant figure.

Answers

the answer is 7000.

Any zero that isnt trapped between two non-zero numbers (on the left side of the decimal) is insignificant, therefore the 3 rounds down. hope this helped!

Hello There!

Significant figure means you should have x amounts of numbers that aren't zero.
In this case you are required to have one number that isn't a zero.
Therefore you round down to give you 7000 as your final answer.

To get a better idea follow through the rest:
E.g Round 64, 492 to two significant figures.
This means you'd have two numbers that aren't a zero.
So you're final answer would have been 64000.

Hope This Helps You!
Good Luck :)

- Hannah ❤

A total of 14000 votes were cast to two opposing candidates. Adam and Karl.Adam won by ratio of 4:3 how many votes were cast to karl?

Answers

8000 because add the ratio and divide to get 2000 now multiply by 4 to get 8000

ANSWER

The number of votes cast to Karl is
[tex]6000[/tex]

EXPLANATION

The total votes cast is

[tex]14000[/tex]

We were given that Adam and Karl won by ratio of
[tex]4:3[/tex]
This means the number of votes cast to Adam corresponds to 4, while that of Karl corresponds to 3.

The total ratio is

[tex] = 4 + 3 = 7[/tex]

Number of votes cast to Karl is

[tex] = \frac{Karl's\:ratio}{Total\:ratio} \times Total\:votes \:cast[/tex]

[tex] = \frac{3}{7} \times 14000[/tex]

This simplifies to,

[tex] = 3 \times 2000[/tex]

[tex] = 6000[/tex]

Therefore 6000 votes were cast in favour of Karl.

Find the linear equation of the plane through the point (2,4,9) and parallel to the plane x+4 y+5 z+4 =0.

Answers

y = x + 5A linear equation (in slope-intercept form) for a line perpendicular to y = -x + 12 with a y-intercept of 5.y = 1/2x - 5Convert the equation 4x - 8y = 40 into slope-intercept form.y = -1/2x + 5A linear equation (in slope-intercept form) which is parallel to x + 2y = 12 and has a y-intercept of 5.3x - y = -5A linear equation (in standard form) which is parallel to the line containing (3, 5) and (7, 17) and has a y-intercept of 5.y = -3x + 1A linear equation (in slope-intercept form) which contains the points (10, 29) and (-2, -7).y = -5A linear equation which goes through (6, -5) and (-12, -5).x = -5A linear equation which is perpendicular to y = 12 and goes through (-5, 5).y = 5A linear equation which is parallel to y = 12 and goes through (-5, 5).y = -x + 5A linear equation (in slope-intercept form) which is perpendicular to y = x and goes through (3, 2).y = -5xA linear equation (in slope-intercept form) which goes through the origin and (1, -5).x = 2A linear equation which has undefined slope and goes through (2, 3).y = 3A linear equation which has a slope of 0 and goes through (2, 3).2x + y = -9A linear equation (in standard form) for a line with slope of -2 and goes through point (-1, -7).3x +2y = 1A linear equation (in standard form) for a line which is parallel to 3x + 2y = 10 and goes through (3, -4).y + 4 = 3/2 (x - 3)A linear equation (in point-slope form) for a line which is perpendicular to y = -2/3 x + 9 and goes through (3, -4).y - 8 = -0.2(x + 10)The table represents a linear equation.
Which equation shows how (-10, 8) can be used to write the equation of this line in point-slope form?

What is 2/3 times 3/4

Answers

2/3(3/4) = 6/12, which simplifies to 1/2

1/2 is your answer

hope this helps

Since you are multiplying, not dividing, the fractions wouldn't need a common denominator... They would stay the same.
[tex] \frac{2}{3} [/tex] × [tex] \frac{3}{4} [/tex]

First, you would cross simplify the equation... But, you don't have to do it now, you can do it at the end (I think this was is easiest).
[tex] \frac{1}{1} [/tex] × [tex] \frac{1}{2} [/tex]

Finally, you would answer the equation.
[tex] \frac{1}{1} [/tex] × [tex] \frac{1}{2} [/tex] = [tex] \frac{1}{2} [/tex]

Your answer would be [tex] \frac{1}{2} [/tex].

I hope this helps!

What age was the mean of all the guesses (rounded to the nearest whole number)? 57 59 63 68 74?

Answers

The answer is 64, rounded from 64.2.

To get this, you just have to add all the numbers up, and then divide your answer by the amount of numbers you added (just for future reference in problems like these!). To round to the nearest whole number, you look at the decimal: .2. It's closer to 0 than it is to 10, so the 64.2 would round down to 64.

I hope this helps!

What is the value of k? 0.5k+6=4k-8

Answers

6+8=4k-.5k
14=3.5k
So K=4

this is the answer check it out

To paint a sunset, you make a shade of orange paint using 55 drops of red paint for every 88 drops of yellow paint. If you use 1515 drops of red paint, how many drops of yellow paint would you need?]

Answers

divide 1515 by 55 then multiply by 88 and you get 2424

Where are the negative rational numbers placed on a vertical number line

Answers

to the left of the zero. hey to the left to the left to the left lol

Two pools are being filled with water. To start, the first pool contains 890 liters of water and the second pool is empty. Water is being added to the first pool at a rate of 20.5 liters per minute. Water is being added to the second pool at a rate of 42.75 liters per minute.

Answers

Let x=amount of time it takes both pipes draining together to empty the pool
First pipe empties at the rate of 540,000/150=3600 liters/min
Second pipe empties at the rate of 540,000/225=2400 liters/min
Together, both pipes empties at the rate of 3600+2400=6000 liters/min, so our equation to solve is:
6000*x=540000

is 30 x 10 to the 3rd power equal 30000

Answers

yes, it is. hope i was helpful!

Yes,[tex]$30 \times 10^3$[/tex] is equal to 30,000.

When we have a number written in scientific notation, such as [tex]$10^3$,[/tex] it means we are multiplying the base (which is 10 in this case) by itself a certain number of times, indicated by the exponent (which is 3 in this case).

So, [tex]$10^3$[/tex] means [tex]$10 \times 10 \times 10$[/tex], which equals 1,000.

Therefore, when we multiply 30 by [tex]$10^3$[/tex], it's equivalent to multiplying 30 by 1,000, which results in 30,000.

solve the equationX=15/x+1/4

Answers

Answer:

x = -3.75 or 4

Step-by-step explanation:

Multiply by 4x and solve the resulting quadratic in any of the usual ways.

... 4x² = 60 +x

... 4x² -x -60 = 0 . . . . . . . . . . . subtract 60+x

... (x -4)(4x +15) = 0 . . . . . . . . .factor the equation

... x = 4 . . . or . . . -15/4 . . . . . . the values that make the factors zero

_____

Comment on the graph

It is convenient to use a graphing calculator to find the zeros of a function, so it works well to rewrite the equation to be something that is equal to zero. Here, we've subtracted the right side, so we have ...

... f(x) = x - (15/x +1/4) = 0

Divide.
-5 1/3 ÷ 2 3/4
A. -12 5/6
B. -7 5/12
C. -1 31/33
D. -1 11/12

Please answer fast!!!!!!

Answers

I believe the answer is c

80 miles per hour is how many feet per minute?

Answers

keeping in mind that, there are 5280 feet in 1 mile and 60 minutes in 1 hour.

[tex]\bf \cfrac{80~\underline{mile}}{\underline{hr}}\cdot \cfrac{5280~feet}{\underline{mile}}\cdot \cfrac{\underline{hr}}{60~min}\implies \cfrac{80\cdot 5280~feet}{60~min}\implies \cfrac{422400~feet}{60~min} \\\\\\ 7040\frac{feet}{min}[/tex]

What is the greatest perfect square that is a factor of 396? Explain

Answers

To find the greatest perfect square that is a factor of 396, first we check what are the factors of 396
Factors of 396 are: 1,2,3,4,6,9,11,12,18,22,33,36,44,66,99,132,198,396
Now we check which is the greatest perfect square in these.
396, 198, 132, 99, 66,44 are not perfect square,
so 36 is the largest perfect square from the factors of 396, 6 x 6 = 6² = 36

What are the coordinates of the vertices of the triangle under the translation (x, y) mc011-2.jpg (x + 1, y - 4)?

(0, -3), (0, 0), (3, -3)

(-3, 0), (3, -3), (0, -3)

(0, -3), (-3, -3), (-3, 0)

(-3, 0), (0, 0), (-3, -3)

Answers

Original
(-1,1) (-4,1) (-4, 4)

translation (x, y) to (x + 1, y - 4)
(0,-3) (-3,-3) (-3, 0)

answer
(0, -3), (-3, -3), (-3, 0)

it is c :

(0,-3), (-3,-3), (-3,0)

just take the X and Y of the coordinates of the original triangle and substitute it in the given equation (x + 1, y - 4)

try it out yourself it works :)

When twotwo basketball players are about to have a free-throw competition, they often draw names out of a hat to randomly select the order in which they shoot. what is the probability that they shoot free throws in alphabetical order? assume each player has a different name?

Answers

There are 2! = 2 ways to arrange the names of two basketball players in a hat.

Since, the are going to throw alphabetically, there is 1 way for the names to be arranged alphabetically.

Therefore, the probability that they shoot free throws in alphabetical order is [tex] \frac{1}{2} = 0.5[/tex]

Final answer:

The probability of shooting free throws in alphabetical order is 0.5.

Explanation:

Probability of shooting free throws in alphabetical order:

Determine the total number of ways the players can shoot. There are 2 players, so 2! (2 factorial) = 2 ways.

Calculate the number of ways they can shoot in alphabetical order. As they have different names, only 1 way exists.

Probability = (Number of ways shooting in alphabetical order) / (Total number of ways to shoot) = 1/2 = 0.5.

kim and brittany are selling chocolate chip cookies and red velvet cupcakes. kim made $81 selling 18 chocolate chip cookies and 12 red velvet cupcakes .brittany made $77 by selling 2 chocolate chip cupcakes and 24 red velvet cupcakes . what was the price of each type of cupcake ?

Answers

I use a website called papa math the chocolate chip cookies are $2.50 while the cupcakes are $3.00 what i did was this 81=18c+12r; 77=2c+24r hope it will help you the long way when you use the papa math calculator

Y=(2x-3)^5(2-x^4)^3 differentiate the function please

Answers

[tex]\bf y=(2x-3)^5(2-x^4)^3\\\\ -------------------------------\\\\ \cfrac{dy}{dx}=\stackrel{\textit{product rule}}{[5(2x-3)^4\cdot 2(2-x^4)3]~~+~~[(2x-3)^5[3(2-x^4)^2(-4x^3)]]} \\\\\\ \cfrac{dy}{dx}=10(2x-3)^4(2-x^4)^3~~-~~12x^3(2x-3)^5(2-x^4)^2 \\\\\\ \cfrac{dy}{dx}=\stackrel{\textit{common factor}}{2(2x-3)^4(2-x^4)^2}~[5(2-x^4)-6x^3(2x-3)] \\\\\\ \cfrac{dy}{dx}=2(2x-3)^4(2-x^4)^2~[10-5x^4-12x^4+18x^3] \\\\\\ \cfrac{dy}{dx}=2(2x-3)^4(2-x^4)^2(10-17x^4+18x^3)[/tex]

The problem is

2n>14
n=?

Answers

If 2n>14, then
n>14/2
n>7

2n >14
=n>7

so, n can be any number which is greater than 7.

A train moving at a constant speed of 70.0 km/h moves east for 45.0 min, then in a direction 55.0° east of due north for 25.0 min, and then west for 55.0 min. what is the average velocity of the train during this run? (let the +x-axis point towards the east and the +y-axis point towards the north.)

Answers

We know the starting point and the ending point. Find the vector that connects the starting point to the ending point, and then divide this by the total time elapsed (45.0 + 25.0 + 55) min.

The result will be your average velocity (a vector quantity).

Must a function that is decreasing over a given interval always be negative over that same interval ? Explain

Answers

check the picture below.

Answer:

For a function to be decreasing over an interval, the outputs on the function are getting smaller as the inputs of the function are getting larger, but the outputs could be positive or negative. For a function to be negative over an interval, the outputs must be negative, while the inputs could be positive or negative.

Walter takes 7/10 of an hour to mow 2/5 of an acre of lawn. At this rate, how many acres will he mow in an hour?

Answers

[tex]\bf \begin{array}{ccll} hours&\stackrel{lawn}{acre}\\ \text{\textemdash\textemdash\textemdash}&\text{\textemdash\textemdash\textemdash}\\ \frac{7}{10}&\frac{2}{5}\\\\ 1&a \end{array}\implies \cfrac{\frac{7}{10}}{1}=\cfrac{\frac{2}{5}}{a}\implies \cfrac{\frac{7}{10}}{\frac{1}{1}}=\cfrac{\frac{2}{5}}{\frac{a}{1}}\implies \cfrac{7}{10}\cdot \cfrac{1}{1}=\cfrac{2}{5}\cdot \cfrac{1}{a} \\\\\\ \cfrac{7}{10}=\cfrac{2}{5a}\implies 35a=20\implies a=\cfrac{20}{35}\implies a=\cfrac{4}{7}[/tex]

Answer:

4/7 acres per hour

Step-by-step explanation:

Where are the asymptotes of f(x) = tan(4x − π) from x = 0 to x = pi over 2 ?

Answers

[tex]tan(4x- \pi )= \frac{sin(4x- \pi )}{cos(4x- \pi )} [/tex]

The asymptotes are where the graph is undefined. Since: tan(x) =sin(x)/cos(x)
It is where cos(4x-π) = 0

cos(4x-π) = 0 when the inside is -π/2 , π/2 , 3π/2

4x - π = π/2
4x = π/2 + π
4x = 3π/2
x = 3π/8

4x - π = 3π/2
4x = 3π/2 + π
4x = 5π/2
x = 5π/8
This ones outside the interval (5π/8 > π/2) , try -π/2

4x - π = -π/2
4x = -π/2 + π
4x = π/2
x = π/8

Asymptotes are π/8 and 3π/8

Answer:

D 3pi/8 , 5pi/8

Step-by-step explanation:

a 3 pound pork loin can be cut into 10 pork chops of equal weight. how many ounces are in each pork chop? please show your work

Answers

Attached a solution and showed work.

Pounds to Ounce- 1 Pound -->16 ounces
3 Pound Pork Loin-48 Ounces
48÷10=4.8
Answer= Each Pork chop weighs 4.8 ounces

Number 49....I need help

Answers

now, keep in mind that, we'll be using 25mile intervals, notice, that at a cost of 200 bucks, it went for 50 miles, now the charges are just for every 25miles only, so, if you drive 30 miles, you pay for 25miles and if you drive for 49 miles, you still only pay for 25 miles, but because 50/25 is 2 intervals, then if you drive for 50 miles, you're paying for 2 intervals of 25miles, not just one.

now, also let's keep in mind that, when the car was driven for 200 miles, that's 200/25 or 8 25mile intervals, so the 25mile charge kicked in 8 times.

[tex]\bf \stackrel{cost}{y}=\stackrel{fixed~charge}{F}+\stackrel{25mile~intervals}{m}\quad \stackrel{25mile~charge}{x}\implies y=F+mx\\\\ -------------------------------\\\\ \begin{cases} 200=F+2x\implies 200-2x=\boxed{F}\\ 245=F+8x\\ ----------\\ 245=\boxed{200-2x}+8x \end{cases} \\\\\\ 45=6x\implies \cfrac{45}{6}=x\implies \cfrac{15}{2}=x\impliedby \begin{array}{llll} \textit{so the 25mile charge is}\\ \textit{7 bucks and 50cents} \end{array} \\\\\\ [/tex]

[tex]\bf 200=F+2\left( \frac{15}{2} \right)\implies 200=F+15\implies 185=F \\\\\\ \textit{and the \underline{fixed charge} is 185 bucks then, let's check for 450} \\\\\\ \boxed{y=185+\frac{15}{2}x}\qquad \begin{cases} 450~miles\\\\ \cfrac{450}{25}\implies 18~\textit{\underline{25mile intervals}}\\\\ x=18 \end{cases} \\\\\\ y=185+\cfrac{15}{2}\cdot 18\implies y=185+135\implies y=320[/tex]

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