∠1 is decomposed into two nonoverlapping angles, ∠2 and ∠3. let m∠1 = 130° and m∠3 = 75°. what type of angle is ∠2?
a. acute
b. obtuse
c. right
d. straight
A cable installer charges $30.00 per hour plus a $50.00 service charge. Your father's firm hires him to hook up his company's Internet service.
Find the total charges if it takes the cable installer 8.5 hours to complete the task. ...?
Final answer:
To calculate the total charges for the cable installation, multiply the hourly rate of $30.00 by the 8.5 hours spent ($255.00) and add the $50.00 service charge, resulting in total charges of $305.00.
Explanation:
The task requires us to calculate the total charges based on the cable installer's hourly rate and a service charge. The installer charges $30.00 per hour and there's an additional $50.00 service charge. To find the total cost for 8.5 hours of work, we multiply the hourly rate by the number of hours and then add the service charge.
Calculation: Total charges = (Hourly rate × Number of hours) + Service charge = ($30.00 × 8.5 hours) + $50.00
Step 1: Calculate the hourly charge
Hourly charge = $30.00 × 8.5 = $255.00
Step 2: Add the service charge
Total charges = $255.00 + $50.00 = $305.00
The total charges for the cable installation service will be $305.00.
What is the surface area of a sphere with a radius of 11 units? Leave it in pi
Answer:
[tex]\text{Area of sphere is }484\pi units^2[/tex]
Step-by-step explanation:
Given the radius of sphere 11 units
we have to find the surface area of sphere
Radius=11 units
As area of sphere can be calculated as
[tex]\text{Area}=4\pi r^2[/tex]
[tex]=4\pi (11)^2=484\pi units^2[/tex]
[tex]\text{Area of sphere is }484\pi units^2[/tex]
Calculate the slope of the line given the points (2, 1) and (1, -4).
A. 1/5
B. 5
C.-3
D. none of the above
The cost, c(x), for a taxi ride is given by c(x) = 2x + 4.00, where x is the number of minutes. What does the slope mean for this situation?
A. The taxi ride costs a total of $4.00.
B. The taxi ride costs $2.00 per trip.
C. The rate of change of the cost of the taxi ride is $2.00 per minute.
D. The rate of change of the cost of the taxi ride is $4.00 per minute.
Answer:
Answer is option c
Step-by-step explanation:
Given that the cost, c(x), for a taxi ride is given by c(x) = 2x + 4.00, where x is the number of minutes.
We find that whenever 1 minute increases cost increases by 2 dollars.
Hence rate of change of cost with respect to minute of taxi ride = 2 dollas
i.e. this is of the form y=mx+b where
m =2 is the slope or rate of change and
b = 4 is the fixed charge even for 0 minute.
Thus option C is right
13x - 7 = 136
11
15
8
9
6) If sec theta+tan theta = P. PT sin theta=P^2-1/P^2+1 ...?
A $15,000, 6 percent , 50-day note ,dated November 8, is discounted at 5 percent on November 28, the proceeds of the note would be?
A. $14,936,46
b. $ 15,610,64
c. $63,54
d. $15,061,98
Answer:
D. $15061.98
Step-by-step explanation:
In order to calculate the proceeds we will using the following computation:
Principal + {Principal * Discounted rate * Frequency of a year on Maturity Date}
15,000 + {15,000 * 5% * (30/365)}
Hence, the proceeds of note would be $15,061.98
Solve the system of equations.
x + 3y = −1
2x + 2y = 6 (1 point)
(−4, 1)
(2, −1)
(4, −1)
(5, −2)
the solution to the system of equation is (5, -T
System of equationx + 3y = −1 2x + 2y = 6From equation 1;
x = -1 - 3y
Substitute x = -1-3y into equation 2
x + y = 3
-1-3y + y = 3
-1 -2y = 3
-2y = 4
y = -2
Since x + y = 3
x = 3 + 2
x = 5
Hence the solution to the system of equation is (5, -2)
S = p/(q + p(1 − q)) solve for q
The line y = –2x – 8 is graphed. Which ordered pairs are solutions to the equation? Check all that apply.
A) (–8, 8)
B) (–6, 2)
C) (–2, 4)
D) (0, –4)
E) (2, –12)
The students at Monroe Junior High sponsored a canned food drive. The seventh-grade class collected 129% of its canned food drive goal.
a. ABOUT how many canned foods did the seventh-graders collect if their goal was 200 cans? _____________________
b. ABOUT how many canned foods did the seventh-graders collect if their goal was 595 cans? _________________________
which phrase best defines a rhombus? a.a parallelogram with four congruent anglesb.a parallelogram with four congruent sidesc.a quadrilateral with exactly one pair of parallel sides d.a quadrilateral with no congruent sides
What is the simplified form of each expression?
A. 729x33
B. 3x33
C. 729x29
D. 3x29
The simplified form of each expression is as follows:
[tex]A. \( 729 \times 33 \) simplifies to \( 3^6 \times 33 \) B. \( 3 \times 33 \) simplifies to \( 3 \times 3 \times 11 \) or \( 3^2 \times 11 \). C. \( 729 \times 29 \) simplifies to \( 3^6 \times 29 \). D. \( 3 \times 29 \) simplifies to \( 3 \times 29 \).[/tex]
To simplify these expressions, we recognize that 729 is a power of 3, specifically [tex]\( 3^6 \)[/tex], and that 33 and 29 are prime numbers. Therefore, we can express each product in terms of its prime factors.
A. For the expression [tex]\( 729 \times 33 \)[/tex] , we know that 729 is [tex]\( 3^6 \)[/tex] and 33 is a prime number. Thus, the simplified form is [tex]\( 3^6 \times 33 \)[/tex].
[tex]B. For the expression \( 3 \times 33 \), we can further break down 33 into \( 3 \times 11 \), since 33 is the product of these two prime numbers. Therefore, the simplified form is \( 3^2 \times 11 \) or \( 3 \times 3 \times 11 \).[/tex]
[tex]C. For the expression \( 729 \times 29 \), similar to expression A, 729 is \( 3^6 \) and 29 is a prime number. Hence, the simplified form is \( 3^6 \times 29 \).[/tex]
[tex]D. For the expression \( 3 \times 29 \), both 3 and 29 are prime numbers, so the expression is already in its simplest form and cannot be simplified further. Thus, the simplified form remains \( 3 \times 29 \).[/tex]In summary, the simplified forms are:
[tex]A. \( 3^6 \times 33 \) B. \( 3^2 \times 11 \) or \( 3 \times 3 \times 11 \) C. \( 3^6 \times 29 \) D. \( 3 \times 29 \)[/tex]
Determine algebraically all points where the graphs of xy=10 and y=x+3 intersect
How many solutions are there to this equation?
5(x + 10)- 25= 5x + 25
a. 1
b. 0
c. infinitely many
consider the function f(x) = {(sinx)/x, x cannot equal 0
{k, , x = 0
In order for f(x) to be continuous at x - 0, the value of k must be..
Final answer:
For the function f(x) = (sinx)/x to be continuous at x = 0, the value of k must be 1, which is the limit of the function as x approaches 0.
Explanation:
The student is asking about the continuity of a given function at x = 0. To determine what the value of k must be for the function f(x) = (sinx)/x when x is approaching 0, we need to look at the limit of the function as x approaches 0.
Although the function is not defined at x = 0 due to division by zero, we know that the limit of (sin x)/x as x approaches 0 is 1. This can be proven using L'Hospital's rule or the squeezing theorem. Hence, for the function to be continuous at x = 0, the value of k must also be 1.
Which of the following describes the non-rigid transformation in the function shown below?
y-1=-(3x+1)^2
A. The graph is shifted 3 units down.
B. The graph is stretched vertically by a factor of 3.
C. The graph is reflected across the x-axis.
D. The graph is stretched horizontally to 1/3 the original width.
Answer:
the graph is stretched horizontally to 1/3 the original width
Step-by-step explanation:
the graph is also reflected and translated but those are rigid transformations and this is asking about the non rig transformations
what is an asymptote? ...?
Which terms could have a greatest common factor of 5m2n2? Check all that apply.
m5n5
5m4n3
10m4n
15m2n2
24m3n4
Answer : [tex] 5m^4n^3[/tex] and [tex] 15m^2n^2[/tex]
Greatest common factor of [tex] 5m^2n^2 [/tex]
If we are able to factor out [tex] 5m^2n^2 [/tex] from each option then that would be our answer.
Lets check with each options
(a)[tex] m^5n^5 [/tex], we cannot take out 5.
(b)[tex] 5m^4n^3 [/tex], We can take out common factor and it can be written as [tex] 5m^4n^3=5m^2n^2(m^2n) [/tex]
(c) [tex] 10m^4n [/tex], we cannot take out n^2 because we have only 'n'
(d) [tex] 15m^2n^2[/tex], We can take out common factor and it can be written as [tex] 15m^2n^2=5m^2n^2(3) [/tex]
(e) [tex] 24m^3n^4 [/tex], we cannot take out 5 because we have 24
So answer is (b) and (d)
Area of a kite
Solve for d2: A=1/2d1d2
Answer:
The value of the equation for [tex]d_2[/tex] is [tex]d_2=\frac{2A}{d_1}[/tex].
Step-by-step explanation:
Consider the provided equation.
[tex]A=\frac{1}{2}d_1d_2[/tex]
We need to solve the equation for [tex]d_2[/tex].
Multiply both the sides by 2.
[tex]2A=2\times \frac{1}{2}d_1d_2[/tex]
[tex]2A=d_1d_2[/tex]
Divide both sides by [tex]d_1[/tex].
[tex]\frac{2A}{d_1}=\frac{d_1d_2}{d_1}[/tex]
[tex]d_2=\frac{2A}{d_1}[/tex]
Hence, the value of the equation for [tex]d_2[/tex]is [tex]d_2=\frac{2A}{d_1}[/tex].
What are the variable terms in the expression?
6x^2 + 3xy + 4z
Answer:
[tex]6x^2,3xy,4z[/tex]
Step-by-step explanation:
We are given that an expression
[tex]6x^2+3xy+4z[/tex]
We have to find the variable terms in the given expression.
Variable term: The term which contains variable is called variable term.
Constant term:The term which does not contain variable is called constant term.
To find the variable terms we will find the terms which contains variable.
We can see that in the given expression
There are three terms which contain variables.
Hence, the variable terms are
[tex]6x^2,3xy,4z[/tex]
What is 7 40/81 rounded to the nearest whole number
Answer:
9
Step-by-step explanation:
Marietta is selling cheeses for the holiday fund raiser. Monday she sole 7/9 of the boxes of cheeses. Tuesday she restocked her supply and sold 0.85 of the boxes of cheeses. Which day did she sell more boxes? Explain and show.
A baseball team plays in a stadium that holds 51,000 spectators. With ticket prices at $10, the average attendance had been 38,000. When ticket prices were lowered to $8, the average attendance rose to 42,000. Find the demand function (price p as a function of attendance x), assuming it to be linear?? ...?
Answer:
[tex]p(x)=-0.0005x+29[/tex]
Step-by-step explanation:
It is given that a baseball team plays in a stadium that holds 51,000 spectators.
Let x be the attendance and p be the price.
With ticket prices at $10, the average attendance had been 38,000. When ticket prices were lowered to $8, the average attendance rose to 42,000.
Assuming that the demand function is linear. It means, the demand line passes through the points (38000,10) and (42000,8).
The equation of line is
[tex]y-y_1=\dfrac{y_2-y_1}{x_2-x_1}(x-x_1)[/tex]
[tex]y-10=\dfrac{8-10}{42000-38000}(x-38000)[/tex]
[tex]y-10=\dfrac{-2}{4000}(x-38000)[/tex]
[tex]y-10=-0.0005(x-38000)[/tex]
[tex]y-10=-0.0005x-0.0005(-38000)[/tex]
[tex]y-10=-0.0005x+19[/tex]
[tex]y=-0.0005x+19+10[/tex]
[tex]y=-0.0005x+29[/tex]
Substitute y=p(x).
[tex]p(x)=-0.0005x+29[/tex]
Therefore, the demand function is [tex]p(x)=-0.0005x+29[/tex].
How many solutions to this equation?
145 = 10x - 8x
A. 2
B. 1
C. infinitely many
in 2000 the average cost for a gallon of gasoline was 1.40 in 2007 the average cost for a gallon of gasoline is 2.60 what is the percent of increase rounded to the nearest whole number
So basically the answer would be 86%
The soccer team voted on what they wanted to eat. There are 20 members on the team. Six members voted for pizza, 10 voted for chicken, and the rest voted for hot dogs.
Which ratio represents the number of votes for hot dogs to chicken?
(1.) decide if function f is invertible.
a) f(n) is the number of students in your calculus class whose birthday is on the nth day of the year.
b) f(x) is the volume in litters of x kilograms of water at 4 degrees celsius. ...?
A commuter must pass through five traffic lights on her way to work, and will have to stop at each one that is red. She estimates the probability model for the number of red lights she hits, as shown below.
X= # of red P(x)
0 0.05
1 0.25
2 0.35
3 0.15
4 0.15
5 0.05
a. How many red lights should she expect to hit each day?
b. What's the standard deviation?
c. Find the mean and standard deviation of the number of red lights the commuter should expect to hit on her way during a 5 day work week.
Answer:
a) 2 red lights
b) SD = 1.26
c) mean = 10, SD = 1.26
Step-by-step explanation:
a) The number of red lights she expects to hit by day can be gotten by calculating the mean of the distribution.
[tex]E(X) = \sum xP(x)[/tex]
[tex]E(X) = (0*0.05) + (1*0.25) + (2*0.35) + (3*0.15) + (4*0.15) + (5*0.15)\\E(X) = 2.25[/tex]
Since the number of lights cannot be a decimal, she expects to hit 2 lights each day
b)
Variance, [tex]V(X) = \sum(x- \mu)^{2} P(x)[/tex]
[tex]V(X) = [(0-2.25)^{2}*0.05] + [(1-2.25)^{2}*0.25] + [(2-2.25)^{2}*0.35] + [(3-2.25)^{2}*0.15] + [(4-2.25)^{2}*0.15] + [(5-2.25)^{2}*0.05][/tex]
V(X) = 0.253 + 0.391 + 0.022 + 0.084 + 0.459 + 0.378
V(X) = 1.587
Standard Deviation, [tex]SD = \sqrt{V(X)}[/tex]
[tex]SD = \sqrt{1.587}[/tex]
SD = 1.26
c) In a 5 day work week, the commuter is expected to hit an average of 5* 2 red lights, i.e. mean = number of red lights hit per day * number of days
mean = 2 * 5
mean = 10
The standard deviation will not change, SD = 1.26