Answer:
y = 1/4x-1
Step-by-step explanation:
The slope intercept form of a line is
y = mx+b
m is the slope and b is the y intercept
but we do not know the slope y know the x intercept
(4,0 )
and the y intercept
( 0,-1)
We can calculate the slope using these points
m = (y2-y1)/ (x2-x1)
= (-1-0)/(0-4)
= -1/-4
= 1/4
Now we can put the slope = 1/4 and the y intercept =-1 into the formula
y = 1/4x-1
y=1/4x-1 I think is the answer to that question
j^2 over 2j times 2j over 3g
Answer:
D
Step-by-step explanation:
given [tex]\frac{j^2}{2j}[/tex] × [tex]\frac{2j}{3g}[/tex]
the 2j on the denominator of the first fraction cancels with the 2j on the numerator of the second fraction, leaving the expression in simplified form as
= [tex]\frac{j^2}{3g}[/tex] → D
what is 25.9 billion times 20 and then divided by 100? will mark brainliest.
Answer:
five hundred seventeen billion nine hundred ninety-nine million nine hundred ninety-nine thousand nine hundred
Step-by-step explanation:
25.9 billion times 20=five hundred eighteen billion
then subtract one hundred from that to get the answer
Answer:
Step-by-step explanation:
5180000000
Use the formula F = 9/5c + 32 to convert -3 degrees Celsius to degrees Fahrenheit
[tex]\text{Put c = -3 to the equation}\ F=\dfrac{9}{5}c+32.\\\\F=\dfrac{9}{5}(-3)+32=-\dfrac{27}{5}+32=-5.4+32=26.6\\\\Answer:\ \boxed{-3^oC=26.6^oF}[/tex]
what is the estimate of 8.36
Answer:
You can estimate to the nearest 10th.
Example:8.4
Step-by-step explanation:
Teresa bought a 50 pound bag of flour for her bakery. She used 13.65 pounds of flour.
How many pounds of flour are left in the bag?
The speed of an Arabian horse is "4x + 2" miles per hour slower than a thoroughbred horse with a speed of "25x − 5" miles per hour. Find a single expression that represents the speed of an Arabian horse. A) 21x − 3 B) 21x − 7 C) 29x − 3 D) 29x − 7
PLS AWNSER THIS WERE GOING TO LEEVE AT 855
Answer:
B) 21x-7
Step-by-step explanation:
Let A = speed of Arabian horse and T = speed of thoroughbred.
Then
A = T – (4x + 2)
A = T – 4x - 2 Remove parentheses
A = 25x - 5 - 4x – 2 Combine like terms
A = 21x - 7
if a line includes the points (8,0) and (20,12). What is its equation in slope-intercept form?
The slope-intercept form:
[tex]y=mx+b[/tex]
m - slope
b - y-intercept
The formula of a slope:
[tex]m=\dfrac{y_2-y_1}{x_2-x_1}[/tex]
substitute the coordinates of the points (8, 0) and (20, 12) to the formula:
[tex]m=\dfrac{12-0}{20-8}=\dfrac{12}{12}=1[/tex]
y = 1x + b = x + b
Put the coordinates of the point (8, 0) to the equation of a line:
0 = 8 + b subtract 8 from both sides
-8 = b
Answer: y = x - 8Ryan has 4 cups of grape juice and Kelsey has 7 cups of lemonade they want to combine what they have to make punch how many 1/2 cup servings of punch can they make
Answer:
5.5 servings
Step-by-step explanation:
4+7=11
11/2=5.5 sevings
At 10:00 AM, Gavin rented a mountain bike. He returned the bike at 3:00 PM, having gone 30 miles. He paid $33 for the rental. Find the rental rate, in dollars per mile.
$6.60/mile
$1.10/mile
$6.00/mile
$0.92/mile
Answer:
$1.10 per mile PLEASE GIVE BRAINLIEST
Step-by-step explanation:
30 miles ÷ $33 = $1.10 per mile
Rewrite the set E by listing its elements. Make sure to use the appropriate set notation. E= { x | x is an interger and -5 ≤ x < -2
Answer:
E = {-5, -4, -3}
How many variable terms are in the expression 3x^3y+5x^2-4y+z+9
Answer:
5
Step-by-step explanation:
x + y + x + y + z = 5
Marjorie baked 100 cupcakes for a bake sale. She sold each cupcake for $0.50. The function P(c) = 0.50c represents the amount, in dollars, that she earned from the bake sale by selling c cupcakes. What domain and range are reasonable for the function?
Answer:
The answer in the procedure
Step-by-step explanation:
we have
P(c)=0.50c
where
P(c) ---> is the amount in dollars that Marjorie earned from the bake sale
c ----> is the number of cupcakes
The domain of the function are the number of cupcakes sold
so
The domain is the interval -----> [0,100]
All positive integers greater than or equal to 0 and less than or equal to 100
Find the range
For c=0
P(0)=0.50(0)=$0
For c=100
P(0)=0.50(100)=$50
The range is the interval -----> [0,50]
All real numbers multiples of 0.50 greater than or equal to 0 and less than or equal to 50
The domain for the function is c ≥ 0, and the range is P(c) ≥ 0.
Domain: The domain for the function P(c) = 0.50c, where c represents the number of cupcakes sold, would be all non-negative integers since Marjorie cannot sell a negative number of cupcakes. So, the domain is c ≥ 0.
Range: The range for the function would be all the possible earnings that Marjorie can make from selling cupcakes. Since each cupcake is sold for $0.50, the earnings can be any non-negative real number. Therefore, the range is P(c) ≥ 0.
Solve the following subtraction problems. Remember to borrow as necessary.
a. 5 lb. – 2lb. 5 oz.
b. 17 T. 13 lb. 3 oz. – 9 T. 20 lb. 9 oz.
c. 68 lb. 13 oz. – 30 lb. 15 oz.
Answer:
a. 2 lb 11 oz, b. 7 T 1,992 lb 12 oz , c. 38 lb 14 oz
Step-by-step explanation:
The first thing we need to understand is the conversions.
1 T = 2,000 lb
1 lb = 16 oz
Knowing this, there are many ways to find out the answer, please see below the one I used; I converted all measure units to oz, subtracted the amounts, and finally converted the units back to their original ones.
a. 5 lb or (16 oz*5) - (2 lb or (16 oz*2) + 5 oz) = 80 oz - 37 oz = 43 oz = 2 lb 11 oz
b. (17 T or (2,000 lb*17) + 13 lb + 3 oz) - (9 T or (2,000 lb*9) + 20 lb + 9 oz) = (34,013 lb or (16 oz *34,013) + 3 oz) - (18,020 lb or (16 oz *18,020) + 9 oz) = 544,213 oz - 288,329 oz = 255,884 oz = 7 T 1992 lb 12 oz
c. (68 lb or (16 oz*68) + 13 oz) - (30 lb or (16 oz*30)+15) = 1,117 oz - 495 oz = 622 oz = 38 lb 14 oz
Answer:
A. 2 pounds 11 ounces
B. 7T 1,992 pounds 12 ounces
C. 38 pounds and 14 ounces
find o(30) where o(n) =2n-1
Answer:
o(30) = 59
Step-by-step explanation:
o(30) means we want to let n = 30 in our function
o(n) =2n-1
o(30) = 2*30 -1
o(30) = 60 -1
o(30) = 59
7.3 back side help me
Answer:
11. x=4.5
12. x=16
13. x=15
14. x=15
15. x=10
EH=9
16. Corry is 6 feet tall.
17. The Ferris Wheel is 15 m tall.
18. The mural is 150 inches long.
19. A 15 foot ladder would touch the building at a height of 10 feet.
Step-by-step explanation:
11. x/7.5=6/10
Simplifying the fraction on the right side of the equation:
x/7.5=3/5
Solving for x: Multiplying both sides of the equation by 7.5:
7.5(x/7.5)=7.5(3/5)
x=1.5(3)
x=4.5
12. x/20=(27-15)/15
x/20=12/15
Simplifying the fraction on the right side of the equation:
x/20=4/5
Solving for x: Multiplying both sides of the equation by 20:
20(x/20)=20(4/5)
x=4(4)
x=16
13. x/6=(14-4)/4
x/6=10/4
Simplifying the fraction on the right side of the equation:
x/6=5/2
Solving for x: Multiplying both sides of the equation by 6:
6(x/6)=6(5/2)
x=3(5)
x=15
14. x/20=12/(12+4)
x/20=12/16
Simplifying the fraction on the right side of the equation:
x/20=3/4
Solving for x: Multiplying both sides of the equation by 20:
20(x/20)=20(3/4)
x=5(3)
x=15
15. [(x+5)+9]/(x+5)=12/6
(x+5+9)/(x+5)=2
(x+14)/(x+5)=2
Solving for x: Multiplying both sides of the equation by (x+5):
(x+5)(x+14)/(x+5)=(x+5)2
x+14=2(x+5)
Eliminating the parentheses applying the distributive property:
x+14=2(x)+2(5)
Multiplying:
x+14=2x+10
Grouping the x's on the right side of the equation: Subtracting x both sides of the equation:
x+14-x=2x+10-x
Subtracting:
14=x+10
Solving for x: Subtracting 10 both sides of the equation:
14-10=x+10-10
4=x
x=4
EG=x+5→EG=4+5→EG=9
EH/HF=EG/GD
Replacing the known values:
EH/9=9/9
EH/9=1
Solving for EH: Multiplying both sides of the equation by 9:
9(EH/9)=9(1)
EH=9
16. Corry's height / Corry's shadow = Giraffe's height / Giraffe's shadow
Replacing the given values:
Corry's height / 4 feet = 18 feet / 12 feet
Simplifying the fraction on the right side of the equation:
Corry's height / 4 feet = 3/2
Solving for Corry's height: Multiplying both sides of the equation by 4 feet:
4 feet (Corry's height / 4 feet) =4 feet (3/2)
Corry's height = 2 feet (3)
Corry's height = 6 feet
17. Ferris Wheel's height / Ferris Wheel's shadow =
Man's height / Man's shadow
Replacing the given values:
Ferris Wheel's height / 20 m = 1.8 m / 2.4 m = 18/24
Simplifying the fraction on the right side of the equation:
Ferris Wheel's height / 20 m = 3/4
Solving for Ferris Wheel's height: Multiplying both sides of the equation by 20 m:
20 m (Ferris Wheel's height / 20 m) =20 m (3/4)
Ferris Wheel's height = 5 m (3)
Ferris Wheel's height = 15 m
18. Mural's length / Mural's width =
Photographer's length / Photographer's width
Replacing the given values:
Photographer's length / 120 inches = 5 inches / 4 inches = 5/4
Solving for Photographer's length: Multiplying both sides of the equation by 120 inches:
120 inches (Photographer's length / 120 inches) = 120 inches (5/4)
Photographer's length = 30 inches (5)
Photographer's length = 150 inches
19. Height 15-foot ladder touch the building / 15 feet =
Height 9-foot ladder touch the building / 9 feet
Height 15-foot ladder touch the building / 15 feet = 6 feet / 9 feet = 6/9
Simplifying the fraction on the right side of the equation:
Height 15-foot ladder touch the building / 15 feet = 2/3
Solving for Height 15-foot ladder touch the building: Multiplying both sides of the equation by 15 feet:
15 feet (Height 15-foot ladder touch the building / 15 feet) = 5 feet (2/3)
Height 15-foot ladder touch the building = 5 feet (2)
Height 15-foot ladder touch the building = 10 feet
You work at a fruit market. Bananas cost 50¢ a pound. A customer hands you a bunch of bananas that weighs 3 pounds. How much should you charge for the bunch of bananas?
Answer: I should charge 150¢ for the bunch of bananas.
Step-by-step explanation: Given that I work at a fruit market and bananas cost 50¢ a pound.
A customer hands me a bunch of bananas that weighs 3 pounds.
We are to find the price that I should charge for the bunch of bananas.
We will be using the UNITARY method to solve the given problem.
Also, we know that
100 ¢ = $1.
Cost of 1 pound of bananas = 50¢
Therefore, the cost of 3 pounds of bananas is given by
p = (50 × 3)¢ = 150¢ = $1.50.
Thus, I should charge 150¢ for the bunch of bananas.
Amara needs 4545 kilograms of meat to feed her 22 pet dragons each day. Each pet dragon eats the same amount of meat.
How many kilograms of meat does Amara need to feed 44 pet dragons each day?
Answer:9090
it is simple you just need to multiply by 2
Answer:
9090
Step-by-step explanation:
meat to feed 22 pet dragons per day=4545
meet to feed 44 pet dragons per day=?
as number of pet dragons have doubled
so amount of feed will also be doubled
hence
meet to feed 44 pet dragons per day=4545*2=9090
pls someone should kindly help me with this
Answer: a = 1, a = [tex]{\bold{-\dfrac{119}{125}}[/tex]
Step-by-step explanation:
In order to have the same root, the discriminant cannot be irrational.
Case 1: Discriminant = zeroCase 2: Discriminant = perfect square(a + 3)x² - (11a + 1)x + a = 2(a - 5)
(a + 3)x² - (11a + 1)x + a = 2a - 10
(a + 3)x² - (11a + 1)x + a - 2a + 10 = 0
(a + 3)x² - (11a + 1)x - (a - 10) = 0
a = a+3 b = -(11a+1) c = -(a - 10)
Case 1:
b² - 4ac = 0
[-(11a + 1)]² - 4(a + 3)[-(a - 10)] = 0
121a² + 22a + 1 + 4a² - 28a - 120 = 0
125a² - 6a - 119 = 0
Use any method to solve the quadratic equation. I chose to use the factoring method.
125a² - 6a - 119 = 0
125a² - 125a + 119a - 119 = 0
125a(a - 1) + 119(a - 1) = 0
(125a + 119)(a - 1) = 0
125a + 119 = 0 and a - 1 = 0
a = [tex]-\dfrac{119}{125}[/tex] and a = 1
Check:
(a + 3)x² - (11a + 1)x + a = 2(a - 5)
((1) + 3)x² - (11(1) + 1)x + (1) = 2((1) - 5)
4x² - 12x + 1 = -8
4x² - 12x + 9 = 0
(2x + 3)² = 0
x = [tex]-\dfrac{3}{2}[/tex]
Case 2: I am not sure how to do this one
[tex]ax^2+bx+c=0\\\\if\ \Delta=b^2-4ac>0\ then\ two\ solutions\qquad x_1=\dfrac{-b-\sqrt\Delta}{2a}\ and\ x_2=\dfrac{-b+\sqrt\Delta}{2a}\\if\ \Delta=b^2-4ac=0\ then\ one\ solution\\if\ \Delta=b^2-4ac<0\ then\ no\ real\ solution[/tex]
--------------------------------------------
[tex](a+3)x^2-(11a+1)x+a=2(a-5)\qquad\text{use distributive property}\\\\(a+3)x^2-(11a+1)x+a=2a-10\qquad\text{subtract 2 from both sides and add 10 to both sides}\\\\(a+3)x^2-(11a+1)x-a+10=0\\\\\Delta=[-(11a+1)]^2-4(a+3)(-a+10)\qquad\text{use}\ (a+b)^2=a^2+2ab+b^2\\\\\Delta=(11a)^2+2(11a)(1)+1^2+(-4a-12)(-a+10)\\\\\Delta=121a^2+22a+1+4a^2-40a+12a-120\\\\\Delta=125a^2-6a-119[/tex]
[tex]\text{One solution if}\ \Delta=0.\\\\\Delta=0\iff125a^2-6a-119=0\\\\\Delta_a=(-6)^2-4(125)(-119)=36+59,500=59,536\\\\\sqrt{\Delta_a}=\sqrt{59,536}=244\\\\a_1=\dfrac{-(-6)-244}{2(125)}=\dfrac{-238}{250}=\dfrac{-238:2}{250:2}=-\dfrac{119}{125}\\\\a_2=\dfrac{-(-6)+244}{2(125)}=\dfrac{250}{250}=1\\\\Answer:\ \boxed{a=-\dfrac{119}{125}\ or\ a=1}[/tex]
what is the equation of a line that passes through the point (6,1) and perpendicular to the line whose equation is 2x+y= - 6 ?
Answer:
y = [tex]\frac{1}{2}[/tex] x - 2
Step-by-step explanation:
the equation of a line in slope- intercept form is
y = mx + c ( m is the slope and c the y-intercept )
rearrange 2x + y = - 6 into this form
subtract 2x from both sides
y = - 2x - 6 ← in slope-intercept form
with slope m = - 2
given a line with slope m then the slope of a line perpendicular to it is
[tex]m_{perpendicular}[/tex] = - [tex]\frac{1}{m}[/tex] = - [tex]\frac{1}{-2}[/tex] = [tex]\frac{1}{2}[/tex]
y = [tex]\frac{1}{2}[/tex] x + c ← is the partial equation
to find c substitute (6, 1) into the partial equation
1 = 3 + c ⇒ c = 1 - 3 = - 2
y = [tex]\frac{1}{2}[/tex] x - 2 ← equation of perpendicular line
Write a polynomial function with zeros -7, -1, 4
Answer:
(x+7)(x+1)(x-4)
Step-by-step explanation:
A zero is is the x-intercept of the function. It is also known as the root. From the equation, the zero or root comes from the factors. When the factors are set equal to 0, we solve for x and the zero is the result. We will reverse this by taking the opposite value of the zero and placing into a factor expression. Remember the factor has the form x+a.
-7: x+7
-1: x+1
4: x-4
We write them together. (x+7)(x+1)(x-4). With more information we could find the leading coefficient and so forth.
The stem and leaf plot below displays a set of data recorded in the North Pole.
Stem:
-3, -2, -1, 0, 1, 2, 3
Leaf:
5,2,2,1,0,7,7,7,5,3,2,0,-9,-6,-4,-1,-1,0,3,6,1,2,5
Which box plot closely resembling the data set within the stem and leaf plot, represents a data set with outliers?
Answer:
plot B
Step-by-step explanation:
-3
-2 goes with 5,2,2,1,0
-1 goes with 7,7,7,5,3,2,0
0 goes with -9,-6,-4,-1,-1,0,3,6
1 goes with 1,2
2 goes with 6
3
This means there should be no data in our box and whisker plot until a whisker starts at -25. This eliminates plot A
We will also stop our last whisker at 26 . This eliminates plot C
We have 23 data points. So the median point is 12
The 12th point is -10
The middle of our box should be at -10 This eliminates plot D
Our answer is plot B
state of each triangle is acute, obtuse, or right
Answer:
5 is right 6 is right 7 is right ....
Step-by-step explanation:
actually they are all right triangles
Each of the triangle should be classified as follows;
5. Acute triangle.
6. Right triangle.
7. Obtuse triangle.
8. Obtuse triangle.
9. Obtuse triangle.
10. Acute triangle.
11. Right triangle.
12. Right triangle.
How to determine and classify each of the triangles?A triangle is classified as an acute triangle if the square of its longest side (c) is less than the sum of the squares of the two smaller sides (a + b).
Also, a triangle is classified as an obtuse triangle if the square of its longest side (c) is greater than the sum of the squares of the two smaller sides (a + b).
A triangle is classified as a right triangle if the square of its longest side (c) is equal to than the sum of the squares of the two smaller sides (a + b).
Part 5.
c² > a² + b²
15² > 11² + 12²
225 > 265 (False, it's an acute triangle).
Part 6.
c² > a² + b²
13² > 5² + 12²
169 > 169 (False, it's a right triangle).
Part 7.
c² > a² + b²
10² > 3² + 8²
100 > 73 (True, it's an obtuse triangle).
Part 8.
c² > a² + b²
20² > 9² + 12²
400 > 225 (True, it's an obtuse triangle).
Part 9.
c² > a² + b²
15² > 7² + 12²
225 > 193 (True, it's an obtuse triangle).
Part 10.
c² > a² + b²
10² > 8² + 7²
100 > 113 (False, it's an acute triangle).
Part 11.
c² > a² + b²
15² > 9² + 12²
225 > 225 (False, it's a right triangle).
Part 12.
c² > a² + b²
13² > 5² + 12²
169 > 169 (False, it's a right triangle).
Read more on triangles here: https://brainly.com/question/31186179
#SPJ6
What value correctly fills in the blank in the equation 16 + 12 = 4 ´ ( __ + 3) to show the sum of the two areas of flowers?
Answer:
4
Step-by-step explanation:
What is the greatest common factor for both terms: 24x + 8
[tex]24x=\boxed{2}\cdot\boxed{2}\cdot\boxed{2}\cdot3\cdot x\\\\8=\boxed{2}\cdot\boxed{2}\cdot\boxed{2}\\\\GCF(24x,\ 8)=\boxed{2}\cdot\boxed{2}\cdot\boxed{2}=8\\\\24x+8=8(3x+1)[/tex]
1/2x + 1/3y = 0
1/4x -1/2 y = 8
What is the solution of the system shown?
(-8, 12)
(8, -12)
(8, 12)
Answer:
[tex](8,-12)[/tex]
Step-by-step explanation:
The two equations are:
[tex]\frac{1}{2}x+\frac{1}{3}y=0\\\frac{1}{4}x-\frac{1}{2}y=8[/tex]
We can solve the first equation for [tex]x[/tex] and then substitute into second equation to find the value of [tex]y[/tex].
[tex]\frac{1}{2}x+\frac{1}{3}y=0\\\frac{1}{2}x=-\frac{1}{3}y\\x=\frac{-\frac{1}{3}y}{\frac{1}{2}}\\x=-\frac{2}{3}y[/tex]
Now,
[tex]\frac{1}{4}x-\frac{1}{2}y=8\\\frac{1}{4}(-\frac{2}{3}y)-\frac{1}{2}y=8\\-\frac{2}{12}y-\frac{1}{2}y=8\\-\frac{2}{3}y=8\\y=\frac{8}{-\frac{2}{3}}\\y=-12[/tex]
Substituting [tex]y=-12[/tex] into the "solved for [tex]x[/tex]" version of first equation, we get the value of [tex]x[/tex]. So,
[tex]x=-\frac{2}{3}y\\x=-\frac{2}{3}(-12)\\x=8[/tex]
Hence the ordered pair is [tex](8,-12)[/tex] and this is the solution to the system of equations shown.
Answer:
(8,-12) the second option :)
Step-by-step explanation:
Find the surface area of the figure below.
We have two equilateral triangles and three rectangles.
The formula of an area of an equilateral triangle:
[tex]A_{\triangle}=\dfrac{a^2\sqrt3}{4}[/tex]
a - length of side
We have a = 14 ft. Substitute:
[tex]A_{\triangle}=\dfrac{14^2\sqrt3}{4}=\dfrac{196\sqrt3}{4}=49\sqrt3\ in^2[/tex]
The formula of an area of a rectangle:
[tex]A_{\boxed{\ }}=lw[/tex]
l - length
w - width
We have l = 10ft and w = 14 ft. Substitute:
[tex]A_{\boxed{\ }}=(10)(14)=140\ ft^2[/tex]
The Surface Area of the figure:
[tex]S.A.=3A_{\boxed{\ }}+2A_{\triangle}\\\\S.A.=3\cdot140+2\cdot49\sqrt3=(420+98\sqrt3)\ ft^2[/tex]
Given that line segments are taken to line segments of the same length during rigid transformations, which transformation maps the line segment AB onto itself?
The line is -2,1 and 4,3
A) rotation counterclockwise of 90° → x-axis reflection → rotation counterclockwise of 270° → x-axis reflection
B) rotation counterclockwise of 90° → y-axis reflection → rotation counterclockwise of 270° → y-axis reflection
C) rotation counterclockwise of 90° → x-axis reflection → rotation counterclockwise of 270° → y-axis reflection
D) rotation counterclockwise of 180° → x-axis reflection → rotation counterclockwise of 270° → y-axis reflection
Answer:
Correct choice is C
Step-by-step explanation:
Consider segment AB with endpoints A(-2,1) and B(4,3).
1. Rotation counterclockwise of 90° has a rule
(x,y)→(-y,x),
then
A(-2,1)→C(-1,-2);B(4,3)→D(-3,4).2. x-axis reflection has a rule
(x,y)→(x,-y),
then
C(-1,-2)→E(-1,2);D(-3,4)→F(-3,-4).3. Rotation counterclockwise of 270° has a rule
(x,y)→(y,-x),
then
E(-1,2)→G(2,1);F(-3,-4)→H(-4,3).4. y-axis reflection has a rule
(x,y)→(-x,y),
then
G(2,1)→A(-2,1);H(-4,3)→B(4,3).Answer:
C) Rotation counter-clockwise of 90 degree → x-axis reflection → rotation counter-clockwise of 270 degree → y-axis reflection
Step-by-step explanation:
We are given the line segment AB with end points (-2,1) and (4,3).
It is provided that after applying rigid transformations the line segment AB maps onto itself.
So, according to the options,
1. Rotation counter-clockwise by 90 degree changes (x, y) into (-y, x)
i.e. (-2,1) → (-1,-2) and (4,3) → (-3,4)
2. X-axis reflection changes (x, y) into (x, -y)
i.e. (-1,-2) → (-1,2) and (-3,4) → (-3,-4)
3. Rotation counter-clockwise by 270 degree changes (x,y) into (y, -x)
i.e. (-1,2) → (2,1) and (-3,-4) → (-4,3)
4. Y-axis reflection changes (x,y) into (-x,y)
i.e. (2,1) → (-2,1) and (-4,3) → (4,3)
Hence, we see that after applying transformations to AB we are again obtaining the line AB as seen below in the figure.
So, option C is correct.
So I copied this off from my teacher she was showing this on the board but I need help showing my work on this so that she doesn’t know I copied it which I think she wouldn’t but you never know
Answer:
x < 3 or x > 9
Step-by-step explanation:
given 6| x - 6 | + 7 > 25 ( subtract 7 from both sides )
6| x - 6 | > 18 ( divide both sides by 6 )
| x - 6 | > 3
Inequalities of the form | x | > a always have solutions of the form
x < - a OR x > a, hence
x - 6 < - 3 or x - 6 > 3 ( add 6 to both sides in both inequalities )
x < 3 or x > 9
Answer: x > 9 or x < 3
Step-by-step explanation:
Step 1: Isolate the absolute value expression.
6 | x - 6 | + 7 > 25
6 | x - 6 | > 18 subtracted 7 from both sides
| x - 6 | > 3 divided both sides by 3
Step 2: Solve for x.
Note: the absolute value symbol makes the value positive, so the value inside could be positive or negative. We need to find both solutions.
If inside is negative
-(x - 6) > 3
x - 6 < -3 divided both sides by -1 which flipped the inequality
x < 3 added 6 to both sides
If inside is positive
+(x - 6) > 3
x - 6 > 3 distributed +1, which didn't change the inequality
x > 9 added 6 to both sides
Step 3: Graph the solution
←-------------o -3 9 o--------------→
The quotient of 12 times an unknown number and 13 is 6 what is the unknown number?
Answer:
unknown number is 13/2
Step-by-step explanation:
Let unknown number be 'x'
given that quotient of 12 times x and 13 is 6
i.e. 12 x/13 =6
multiply 13 both sides
12x = 6 * 13
divide 12 on both sides
x= (6*13)/12
x=13/2
Identify the slope of the line shown in the graph below: slope = -1
Slope = 0
Slope = undefined
Slope = 1
Answer:
slope is undefined
Step-by-step explanation:
Answer:
Undefined
Step-by-step explanation:
The line is going straight down which means it cannot be negative or positive.
If you try to make the equation(y=mx + b), when you try to find the slope, you can't because (rise/run), there is no run. It is just a rise.
This means you cannot define the slope of the line.