Answer:
130 cm
Explanation:
After each bounce, the mechanical energy decreases by 18%, which means the maximum height decreases by 18%. Modeling this as exponential decay:
h = 290 (1 − 0.18)ⁿ
h = 290 (0.82)ⁿ
h = 290 (0.82)⁴
h = 130
The ball reaches a height of 130 cm.
Answer:
130 cm
Explanation:
Gradpoint
2020 NV Cargo’s electronically controlled Multi-Control Valve on the V8 engine helps enhance ________.
Answer:
Power when towing
Explanation:
The V8 engine has Direct Injection Gas (DIG) technology, which provides better wide-open throttle performance and improved fuel consumption and emissions performance (compared to a non-direct-injection system) by reducing engine knock, improving combustion stability and offering precise injection control.
The multi-control valve on the V8 engine helps to enhance power when towing by reducing the amount of torque the engine must expend to move the vehicle, allowing it to commit more to moving the load.
What is the advantage of D-step tuning on 2020 Pathfinder’s Xtronic CVT at cruising speed?
Explanation:
The transmission stimulates shifts at higher rotation per minutes and providing stepped acceleration at with linear acceleration feel.
D-Step Logic Control is found in other Nissan CVT equipped models such as 2020 Altima, 2020 Pathfinder, 2020 Murano and the sporty 2020 Maxima.
A child does 5.0 J of work on a spring while loading a ball into a spring-loaded toy gun. If mechanical energy is conserved, what will be the kinetic energy of the ball when it leaves the gun?
A 0 J
B 3.7 J
C 2.5 J
D 5.0 J
Explanation:
Here mechanical energy is conserved.
Kinetic energy + Potential energy = Constant.
First the child does 5.0 J of work on a spring while loading a ball into a spring-loaded toy gun.
That is potential energy = 5 J
Kinetic energy = 0 J
Kinetic energy + Potential energy = 0 + 5 = 5 J
Secondly the spring is released.
That is potential energy = 0 J
Kinetic energy = ?
Kinetic energy + Potential energy = Constant = 5 J
Kinetic energy + 0 = 5 J
Kinetic energy is 5 J
Option D is the correct answer.
The kinetic energy of the ball when it leaves the spring-loaded toy gun is 5.0 J. This is because the work done on the spring is entirely converted into the kinetic energy of the ball, according to the law of conservation of energy.
Explanation:The subject of this question is based on the conservation of mechanical energy, which is a principle of physics. The principle states that the total mechanical energy in a closed system—meaning one that does not have any external forces, like air resistance, acting on it—remains constant. In this case, the child does 5.0 J of work on the toy gun's spring. This work is converted into potential energy that is stored in the compressed spring.
When the spring launches the ball, the potential energy of the spring is then converted into the kinetic energy of the ball, as there's no friction or air resistance to cause energy loss. So, according to the law of conservation of energy, all of the initial energy (5.0 J) used to compress the spring will be transferred to the ball as kinetic energy. Therefore, the kinetic energy of the ball as it leaves the gun is 5.0 J (Option D).
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The __________ behind a vehicle is one of the most common causes of collisions while ____________.
The main cause of accidents related to vehicles is rash driving, inexperienced drivers, and bad driving manners. Lack of awareness regarding the driving methods.
Most of the commonly made mistakes are due to drinking and driving. Most people feel drossy at night and some even don't horn when appropriate. Hence the blind spot after the vehicles is the most common cause of collisionsLearn more about the vehicle is one of the most common causes of collisions.
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The blind spot behind a vehicle is a common cause of collisions while driving. Safety measures like properly adjusted mirrors and checking over the shoulder before changing lanes can help. Cars with lighter plastic components crumple upon collision, increasing collision time and reducing the force exerted on occupants for increased safety.
Explanation:The blind spot behind a vehicle is one of the most common causes of collisions while driving. This pertains to the area of the road that cannot be directly seen by the driver while looking forward or through either the rear-view or side mirrors. The risk of such collisions can be minimized by proper adjustment of mirrors, use of blind spot mirrors, and always checking over one's shoulder before making a lane change.
Upon collision, cars with lighter weight are able to offer better protection to their occupants due to longer collision time, because of their plastic components. The crumpling of the car in an event of a collision or the deployment of dashboard padding and airbags increases the collision time and hence, the force exerted on the occupants to bring them to a stop is significantly less. Modern automobiles use this physics principle to enhance safety during collisions.
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A block of copper was heated to 55oC and dropped into a beaker of 55 mL of water at 22oC. After the water reached thermal equilibrium, the temperature was 28oC. What was the mass of the copper block? Assume no heat is lost by the beaker.Cs, Cu= 0.385 J/gKCs, H2O= 4.18 J/gK
Answer:
132.70kg
Explanation:
Given:
Temperature of copper block = 55°C
Temperature of water = 22°C
Mass of copper block, m₁ = ?
Mass of water, m₂ = 55 mL = 5.5 × 10⁻⁵m³
Density of water [tex]= \frac{mass}{volume}[/tex]
m₂ = Density of water × volume
m₂ = 1000kg/m³ × (5.5 × 10⁻⁵m³)
m₂ = 0.055 kg
m₂ = 55g
Quantity of heat lost by the copper block = m₁cΔT
= m₁ × 0.385 × (55 - 28)
= m₁ × 0.385 × 27
= 10.395 × m₁ J
Quantity of heat gained by the water = m₂cΔT
= 55 × 4.18 × (28-22)
= 55 × 4.18 × 6
= 1379.4 J
Heat lost by copper block = Heat gained by water
10.395m₁ = 1379.4
[tex]m_{1} =\frac{1379.4}{10.395}[/tex]
m₁ = 132.6984kg
m₁ = 132.70kg
The mass of the copper block is 132.70kg
A particle on a string is whirled in a circle at a constant speed, in the absence of a gravitational field. a top view of the circular motion at one instant is
Answer:
This is an incomplete question. The diagram and a part of the question is missing.
Explanation:
In the context, it is given that the particle tight to a string is whirled in a circular direction in a constant speed. And there is no gravitational field.
Now since the particle's speed is constant, hence the tangential acceleration is zero. The particle exhibits radial acceleration only which will act along the radius towards the center of the circle (towards the left).
Therefore the correct representation of the component of the acceleration is given below --
A particle being whirled in a circle at a constant speed demonstrates uniform circular motion. The changing direction of velocity results in a centripetal acceleration, determined by an external centripetal force. Similar motion is observed in centrifuges and orbiting satellites.
Explanation:A top view of a particle on a string whirled in a circle at a constant speed would show uniform circular motion. In this simplest form of curved motion, the particle moves along a fixed radius at a constant speed. Although the magnitude of its velocity doesn't change, the direction of the velocity is constantly changing, leading to what's referred to as centripetal acceleration. This is caused by a net external force - known as the centripetal force.
This type of motion is similar to other examples of circular motion, like a satellite orbiting Earth, a race car moving around a racetrack, or a ball being swung in a circle. Whenever there's no centripetal force to cause circular motion, inertia carries the object along a line tangent to the circle observed as outward motion in a centrifugal frame of reference. This inertial effect is seen in various physical phenomena.
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What did antoine lavoisier contribute to the atomic theory
Explanation:
Antoine lavoisier is most famous for his role in discovering of oxygen. He recognized and name two important element oxygen(1778) and hydrogen(1779).
In a chemical reaction, Lavoisier observed the mass is retained. A chemical reaction's total mass of the products will always be the same as the total mass of the reactant materials used in the reaction. His results led to one of the basic laws of chemical behavior: the law of material preservation, which states that matter is preserved in a chemical reaction.
Final answer:
Antoine Lavoisier's major contributions to atomic theory include the discovery of the law of conservation of mass and transforming chemistry into a quantitative science by disproving the phlogiston theory and identifying the role of oxygen in combustion. These discoveries paved the way for the future development of the atomic theory.
Explanation:
Contributions of Antoine Lavoisier to Atomic Theory
Antoine Lavoisier, often regarded as the 'father of modern chemistry', made several groundbreaking contributions to atomic theory. He is particularly famous for discovering the law of conservation of mass. This principle, established through careful experimentation, states that mass in an isolated system is conserved over time, regardless of the type of chemical reactions happening within. This fundamental law formed a cornerstone for John Dalton to later develop the modern atomic theory.
Additionally, Lavoisier conducted experiments that disproved the phlogiston theory and instead suggested that oxygen was a key element in combustion. His innovative approach to chemical reactions included the use of precise weighing measures and conducting reactions in sealed environments to accurately track the mass of gases involved. Lavoisier's meticulous quantitative methods transformed chemistry from a qualitative to a quantitative science.
Through these contributions, Lavoisier laid down the basis for atomic theory as well as the concept of chemical elements, thereby fundamentally changing our understanding of chemical processes. He also impacted other areas such as explaining the role of oxygen in respiration and the composition of air.
When does the most significant drop in physical activity typically occur in people's lives?
Answer:
Later high school years and freshman year of college
Explanation:
The transition from high school to college is an important developmental milestone that holds the potential for personal growth and behavioral change. A cohort of 2,025 students was recruited during the summer before they matriculated into college and completed Internet-based surveys about their participation in a variety of behavioral risks during the last three months of high school and throughout the first year of college. Alcohol use, marijuana use, and sex with multiple partners increased during the transition from high school to college, whereas driving after drinking, aggression, and property crimes decreased. Those from rural high schools and those who elected to live in private dormitories in college were at highest risk for heavy drinking and driving after drinking.
Marcel is helping his two children, Jacques and Gilles, to balance on a seesaw so that they will be able to make it tilt back and forth without the heavier child, Jacques, simply sinking to the ground. Given that Jacques, whose weight is W, is sitting at distance L to the left of the pivot, at what distance L₁ should Marcel place Gilles, whose weight is w, to the right of the pivot to balance the seesaw?
Express your answer in terms of L, W and ω.
Answer:
Explanation:
Given
Jacques weight is W and is at distance of L to the left
Gilles weight is [tex]\omega [/tex] and should be Placed at right at a distance of [tex]L_1[/tex] from pivot
Distance should be such that the torque of Jacques and Gilles is same in magnitude but opposite in direction.
[tex]W\times L-\omega \times L_1=0[/tex]
such that net torque is zero.
[tex]L_1=\frac{W}{\omega }\times L[/tex]
To balance the seesaw, the product of the weight of Jacques and the distance he is sitting from the pivot must be equal to the product of the weight of Gilles and the distance he should sit from the pivot.
Explanation:To balance the seesaw, the product of the weight of Jacques and the distance he is sitting from the pivot must be equal to the product of the weight of Gilles and the distance he should sit from the pivot.
So, we can write the equation as:
W * L = w * L₁
To find L₁, we can rearrange the equation:
L₁ = (W * L) / w
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A 35-kg girl is standing near and to the left of a 43-kg boy on the frictionless surface of a frozen pond. The boy throws a 0.75-kg ice ball to the girl with a horizontal speed of 6.2 m/s. What are the velocities of the boy and the girl immediately after the girl catches the ice ball?
Answer:
The velocity of the boy is 0.11 m/s to the right.
The velocity of the girl is 0.13 m/s to the left.
Explanation:
Hi there!
The momentum of the system is conserved. That means that the initial momentum is equal to the final momentum (after throwing the ice ball for the boy and after catching the ball for the girl).
Let´s calculate the momentum of the system boy-ball:
The equation of the momentum is the following:
p = m · v
Where:
p = momentum.
m = mass of the object.
v = velocity.
Initially, the ball and the boy are at rest, so that the momentum of the system boy-ball is zero:
initial momentum = mib · vib + mb · vb
Where:
mib = mass of the ice ball.
vib = velocity of the ice ball.
mb =mass of the boy.
vb = velocity of the boy.
The initial momentum is zero because both velocities are zero.
After throwing the ball, the momentum of the system will be:
final momentum = mib · vib + mb · vb
final momentum = 0.75 kg · (- 6.2 m/s) + 43 kg · vb (Let´s consider the left as negative).
Since final momentum = initial momentum
0 kg · m/s =- 4.65 kg · m/s + 43 kg · vb
Solving for vb:
4.65 kg · m/s/43 kg = vb
vb = 0.11 m/s
The velocity of the boy after releasing the ball is 0.11 m/s. Since there is no friction, this velocity is constant. When the girl catches the ball, the velocity of the boy will be 0.11 m/s (to the right).
Now let´s do the same for the system girl-ball.
initial momentum = mg · vg + mib · vib
initial momentum = 35 kg · 0 m/s + 0.75 kg · (-6.2 m/s)
initial momentum = -4.65 kg · m/s
The final momentum is the momentum of the girl plus the ball:
final momentum = (mg + mb) · vgb
final momentum = (35 kg + 0.75 kg) · vgb
Since initial momentum = final momentum
-4.65 kg · m/s = (35 kg + 0.75 kg) · vgb
-4.65 kg · m/s / (35 kg + 0.75 kg) = vgb
vgb = -0.13 m/s
The velocity of the girl after catching the ball is -0.13 m/s (0.13 m/s to the left).
The velocity of the boy after catching the ice is 0.108m/s right and the velocity of the girl after catching the ice is 0.132m/s left.
Data;
mass of girl = 35kgmass of the boy = 43kgmass of the ice ball - 0.75kgspeed of the ball = 6.2m/sConservation of linear momentumThe conservation of linear momentum expects that the momentum of the boy or girl must be equal to the momentum of the ball.
for the boy
[tex]m_1v_1 = m_2v_2\\43*v = 0.75*6.2\\v = 0.108m/s[/tex]
The velocity of the boy after catching the ice is 0.108m/s right
for the girl
[tex]m_1v_1 = m_2 v_2\\0.75*6.2 = 35 * v\\v = 0.132 m/s[/tex]
The velocity of the girl after catching the ice is 0.132m/s left.
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The carbon isotope 14C is used for carbon dating of archeological artifacts. 14C(mass 2.34×10−26kg) decays by the process known as beta decay in which the nucleus emits an electron (the beta particle) and a subatomic particle called a neutrino. In one such decay, the electron and the neutrino are emitted at right angles to each other. The electron (mass 9.11×10−31kg) has a speed of 3.40×107 m/s and the neutrino has a momentum of 6.70×10−24 kg⋅m/s .
What is the recoil speed of the nucleus?
The answer is not 1900 or 1600 m/s...
The recoil speed of the nucleus in the beta decay process is gotten as; 1354.27 m/s
What is the recoil speed?From principle of conservation of momentum, we will have;
Recoil momentum of nucleus = Recoil momentum of emitted particle
We are given;
Mass of electron; m_e = 9.11 × 10⁻³¹ kg
speed of electron; v_e = 3.4 × 10⁷ m/s
Momentum of electron; P = 6.7 × 10⁻²⁴ kg.m/s
Thus;
Momentum of electron ignoring relativistic effect is;
P_f = m_e * v_e
P_f = 9.11 × 10⁻³¹ × 3.4 × 10⁷
P_f = 3.0974 × 10⁻²³ kg.m/s
Resultant momentum is gotten from;
R = √[(3.0974 × 10⁻²³)² + (6.7 × 10⁻²⁴)²]
R = 3.169 × 10⁻²³ kg.m/s
The formula for the recoil speed of the nucleus is;
v = R/m_n
where m_n is mass of neutrino = 2.34 × 10⁻²⁶ kg
v = (3.169 × 10⁻²³)/(2.34 × 10⁻²⁶)
v = 1354.27 m/s
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Final answer:
The recoil speed of the carbon nucleus after beta decay can be determined using the conservation of momentum and is found to be approximately 1381 m/s.
Explanation:
The recoil speed of the nucleus can be calculated using the principle of conservation of momentum, which states that the total momentum of a closed system is constant if no external forces are acting on it. In this case of beta decay, the initial momentum of the stationary carbon nucleus is zero. After decay, the sum of momenta of the electron, neutrino, and recoiling nucleus must also be zero, as momentum is conserved.
The momentum of the electron is given by its mass times its velocity (pe = me x ve), and the momentum of the neutrino is given (pν = 6.70 x 10-24 kg·m/s). The nucleus will recoil with momentum equal in magnitude but opposite in direction to the vector sum of the electron and neutrino momenta. Given that the electron and neutrino are emitted at right angles, we can use the Pythagorean theorem to find the magnitude of the resultant momentum that the nucleus must have:
Calculate the momentum of the electron: pe = me x veUse the Pythagorean theorem to calculate the magnitude of the vector sum of the electron and neutrino momenta: ptotal = √(pe2 + pν2)Since the nucleus must recoil with this magnitude of momentum to conserve momentum, we can find its speed using the recoil momentum and the mass of the carbon nucleus: vnucleus = ptotal / mnucleusFollowing through the calculations:
pe = (9.11 x 10-31 kg) x (3.40 x 107 m/s) = 3.0974 x 10-23 kg·m/sptotal = √((3.0974 x 10-23 kg·m/s)2 + (6.70 x 10-24 kg·m/s)2)ptotal = √(9.59577 x 10-46 + 4.489 x 10-47) kg·m/sptotal = √(1.044577 x 10-45) kg·m/sptotal = 3.23082 x 10-23 kg·m/svnucleus = (3.23082 x 10-23 kg·m/s) / (2.34 x 10-26 kg) = 1.38112 x 103 m/sTherefore, the recoil speed of the nucleus is approximately 1381 m/s.
Summers in Phoenix Arizona are hot (125 F is not uncommon), and dry. If you hop into an outdoor swimming pool on a summer day in Phoenix, you will find that the water is too warm to be very refreshing. However, when you get out of the pool and let the sun dry you off, you find that you are quite cold for a few minutes.
Answer:
Explanation:
when we get out of the water we feel quite cold due to the latent heat of evaporation of water.
Water at our body gets converted into gas and leaves behind the cooling effect which makes us feel cold.
While when we are inside the pool we are in constant touch of water, therefore, we get the warmth of the water and it becomes difficult to bear it.
Water has a high heat capacity. What does this term mean? a) Water is relatively resistant to an increase in temperature. b) Water heats up or cools down readily c) Water provides a useful source of stored kilocalories. d) Water provides excellent insulation for the body.
Answer:a) Water is relatively resistant to an increase in temperature
Explanation:
Water has relatively high heat capacity i.e. it requires high amount of heat to raise a little increase in temperature.
Heat capacity is defined as ability of molecule to absorb heat . Mathematically heat capacity is defined as
[tex]C=\frac{Q}{\Delta T}[/tex]
where [tex]C=heat\ capacity[/tex]
[tex]Q=heat\ interaction[/tex]
[tex]\Delta T=change\ in\ Temperature[/tex]
A particle with a positive charge q is moving in the positive x direction with velocity of magnitude v0. If there were an electric field in the positive y direction with magnitude E0, and the velocity of the particle is unchanged, find the magnitude and direction of magnetic field.
The magnitude of the magnetic field in the given scenario is zero.
Explanation:The magnitude and direction of the magnetic field can be determined by analyzing the force experienced by the positively charged particle q as it moves in the positive x direction and encounters an electric field in the positive y direction. The force experienced by the particle, due to the Lorentz force law, is given by:
F = qvB sin
Where F is the force, q is the charge, v is the velocity, B is the magnetic field, and θ is the angle between the velocity and the magnetic field. Since the velocity of the particle remains unchanged, the force experienced by the particle in the y direction must be zero. This means that the angle θ between the velocity and the magnetic field must be 90 degrees. Therefore, sin θ = 1. Substituting these values into the equation, we get
0 = qv0
Solving for B, we find that
B = 0
Therefore, the magnitude of the magnetic field in this scenario is zero.
If another driver does not follow the right-of-way rules at a YIELD sign, what should you do?
Answer:Stop
Explanation:
To avoid accident even thought you in the right
Suppose you want to heat a 600 mL cup of water in the microwave from 20° to 100°C. Water has a specific heat capacity of 4.184 J/g°C and a density of 1.00 g/mL in this temperature range. How much energy is required to heat the cup of water?
Answer:
The quantity of heat required to to heat the cup of water through a temperature change of 80°C = 200.83 kJ
Explanation:
Density = mass/Volume.
∴ mass = Density × volume
Where Density of water = 1.00 g/mL, volume of water = 600 mL
Mass = 1 × 600 = 600 g.
(Q) = cm(ΔT)...................... equation 1
Where Q = quantity of heat, c = specific heat capacity of water, m = mass of water, ΔT = T₁-T₂ = change in temperature.
Where c = 4.184 J/g°C, m = 600 g, ΔT = T₁-T₂ = 100 - 20 = 80°C
Substituting these values into equation 1,
Q = 4.184 × 600 × 80
Q = 200832 J = 200.83 kJ
Therefore the quantity of heat required to to heat the cup of water through a temperature change of 80°C = 200.83 kJ
Laser light of wavelength lambda passes through a thin slit of width a and produces its first dark fringes at angles of +/- 30 degree with the original direction of the beam. The slit is then reduced in size to a circle of diameter a. When the same laser light is passed through the circle, the first dark fringe occurs at:________
A) +/- 66.9 degree.
B) +/- 45.0 degree.
C) +/- 37.6 degree.
D) +/- 36.6 degree.
E) +/- 15.0 degree.
Answer:
D) θ₂= 36. 6º
Explanation:
In this diffraction experiment it is described by the equation
sin θ = m λ
The first dark strip occurs for m = 1 and since the angle is generally small we can approximate sine to the value of the angle
θ₁ = λ/ a
This equation is valid for linear slits, in the case of a circular slit the problem must be solved in polar coordinates, so the equation changes slightly
θ₂ = 1.22 λ / a
In the proposed exercise we start with a linear slit of width a, where tes1 = 30º and end with a circular slit of the same diameter
θ₂ = 1.22 λ / a
Let's clear (Lam/a) of equalizing the two equations
θ₁ = θ₂/ 1.22
θ₂ = 1.22 θ₁
θ₂ = 1.22 30
θ₂= 36. 6º
When reviewing the correct results is D
A positive charge is placed at rest at the center of a region of space in which there is a uniform electric field. (A uniform field is one whose strength and direction are the same at all points within the region.) What happens to the electric potential energy of the positive charge, after the charge is released from rest in the uniform electric field?A. It will remain constant because the electric field is uniform.B.It will decrease because the charge will move in the opposite direction of the electric field.C.It will remain constant because the charge remains at rest.D.It will decrease because the charge will move in the direction of the electric field.E.It will increase because the charge will move in the direction of the electric field.
Answer:
.D.It will decrease because the charge will move in the direction of the electric field
Explanation:
which there is a uniform electric field. (A uniform field is one whose strength and direction are the same at all points within the region.) What happens to the electric potential energy of the positive charge, after the charge is released from rest in the uniform electric field?A. It will remain constant because the electric field is uniform.B.It will decrease because the charge will move in the opposite direction of the electric field.C.It will remain constant because the charge remains at rest.D.It will decrease because the charge will move in the direction of the electric field.E.It will increase because the charge will move in the direction of the electric field.
solution
The potential energy decreases, converted to kinetic energy
The charge will feel a force in the direction of the electric field (F=Eq) and thus it will accelerate with
a constant acceleration. (Just like releasing an object above the earth's surface - constant acceleration,
at least until it hits something.)
tus te answer will be
.D.It will decrease because the charge will move in the direction of the electric field
Would the frequency of the angular simple harmonic motion (SHM) of the balance wheel increase or decrease if the dimensions of the balance wheel were changed as described?
Answer:
Yes the frequency of the angular simple harmonic motion (SHM) of the balance wheel increases three times if the dimensions of the balance wheel reduced to one-third of original dimensions.
Explanation:
Considering the complete question attached in figure below.
Time period for balance wheel is:
[tex]T=2\pi\sqrt{\frac{I}{K}}[/tex]
[tex]I=mR^{2}[/tex]
m = mass of balance wheel
R = radius of balance wheel.
Angular frequency is related to Time period as:
[tex]\omega=\frac{2\pi}{T}\\\omega=\sqrt{\frac{K}{I}} \\\omega=\sqrt{\frac{K}{mR^{2}}[/tex]
As dimensions of new balance wheel are one-third of their original values
[tex]R_{new}=\frac{R}{3}[/tex]
[tex]\omega_{new}=\sqrt{\frac{K}{mR_{new}^{2}}}\\\\\omega_{new}=\sqrt{\frac{K}{m(\frac{R}{3})^{2}}}\\\\\omega_{new}={3}\sqrt{\frac{K}{mR^{2}}}\\\\\omega_{new}={3}\omega[/tex]
A tuning fork with a frequency of 512 Hz is used to tune a violin. When played together, beats are heard with a frequency of 4 Hz. The string on the violin is tightened and when played again, the beats have a frequency of 2 Hz. The original frequency of the violin was ______.
The original frequency of the violin was 508 Hz. This is based on the principle of beats, where the beat frequency is the absolute difference in frequency between the two sources - in this case, the tuning fork and the violin string.
Explanation:The original frequency of the violin string can be found using the principle of beats. The frequency of the beats is equal to the absolute difference in frequency between the two sources - in this case, the tuning fork and the violin string.
Initially, the beat frequency was heard as 4 Hz. This indicates that the original frequency of the violin was either 512 Hz + 4 Hz = 516 Hz, or 512 Hz - 4 Hz = 508 Hz. However, when the violin string was tightened, the beat frequency decreased to 2 Hz, which means the frequency of the note it was producing increased.
Therefore, the violin must have initially been producing a note with lower frequency (508 Hz), and even after tightening the string, the note it now produces (510 Hz) remains lower than that of the tuning fork.
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If you push against a wall, the wall pushes back against you with ____ force.
1. equal
2. less
3. more
4. no
Answer:
1. Equal.
Explanation:
Newton's third law of motion;
According to this law every action have its reaction with same magnitude but in the opposite direction.
If we push a wall with some amount of force then wall pushes back with same magnitude but in the opposite direction.This law tell us about action and reaction forces which are in same magnitude but in the opposite direction.
Therefore the answer will be 1.
1. Equal.
When pushing a wall, the wall pushes back with equal force as stated by Newton's Third Law of Motion. This law means forces have equal magnitude, but opposite direction.
Explanation:
When you push against a wall, the wall pushes back against you with equal force. This is demonstrated by Newton's Third Law of Motion, which states that 'for every action, there is an equal and opposite reaction'. The force you exert on the wall and the force the wall exerts on you are action-reaction force pairs, meaning the force exerted on the wall is the same magnitude, but in the opposite direction to the force the wall exerts on you.
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A player hits a ball with a bat. The action force is the impact of the bat against the ball. The reaction to this force is the
Answer:
Force of the ball against the bat
Explanation:
Newton's third law of motion states that for every action, there is an equal and opposite reaction. When a player hits a ball with a bat, the force the player exerted on the ball through the bat gave the ball a push force in the forward direction. This is an action force. Now that an action has been initiated, there must be a reaction according to Newton's third law of motion. The magnitude of the force on the ball equals the magnitude of the force on the bat. The direction of the force on the ball is opposite to the direction of the force on the ball. The ball will give the bat an equal and opposite force trying to push the bat backward by resisting the impact of the bat. This is the reaction. The ball will only move if the applied force is able to overcome the resisting force by the bat.
[tex]F_{A} = - F_{B}[/tex]
Where;
[tex]F_{A}[/tex] is the action force of the bat against the ball.
[tex]F_{B}[/tex] is the equal and opposite reaction force of the ball towards the ball.
If a player hit a ball with a bat the ore that which the ball is coming towards the player and the force with which the player is moving the bat will impact the ball which will have an equal and opposite reaction.
Thus the reaction of the force will be the force of the ball against the bat.Hence the newtons law of motion will be applied.
Learn more about the player hits a ball with a bat.
brainly.com/question/20074931.
A golfer starts with the club over her head and swings it to reach maximum speed as it contacts the ball. Halfway through her swing, when the golf club is parallel to the ground, does the acceleration vector of the club head point straight down, parallel to the ground, approximately toward the golfer's shoulders, approximately toward the golfer's feet, or toward a point above the golfer's head? Explain.
Answer:
approximately toward the golfer's feet
Explanation:
The golf club experiences two accelerations. when the club is horizontal, centripetal acceleration acts on it toward the center parallel to the ground. The tangential acceleration acts towards the ground in downward direction. So when the golf club is horizontal, the acceleration vector is given by the combination of tangential and centripetal acceleration. the acceleration vector thus points in between horizontal and vertical direction . hence towards the golfer's feet.
Answer:
approximately toward the golfer's feet
Explanation:
The club head undergoes circular motion so it has a centripetal acceleration. As the speed of the club head is increasing, it also has an acceleration component pointed vertically down. Thus, the acceleration vector is pointed as described in (c)
An object is lifted from the surface of aspherical planet to an altitude equal to the radius of the planet.As a result, what happens to the mass and wieght of the object?a) massincreases; weight decreasesb) massdecreases; weight decreasesc) massincreases; weight increasesd) massincreases; weight remains the samee) mass remainsthe same; weight decreasesf) mass remainsthe same; weight increasesg) mass remainsthe same; weight remains the same
Answer: Mass remains the same and weight decrease
Explanation: mass is always constant but weight varies. Weight is affected by height. The higher you go the lesser your weight because you are moving away from gravity
When a person strikes and lights a match, potential energy in the match is transformed into which types of energy?
a. electrical and thermal
b. thermal and radiant
c. radiant and nuclear
d. nuclear and kinetic
A fire hose is turned on the door of a burning building in order to knock the door down. This requires a force of 1000 N. If the hose delivers 40 kg per second, what is the minimum velocity of the stream needed, assuming the water doesn't bounce back?
Answer:
Minimum velocity is 25m/s
Explanation:
Given force F =1000N
Mass flow rate m/t= 40kg/s
Velocity=v
Recall Newton second law of motion F =MV/t
1000=40v
V=1000/40
25m/s
A radio receiver has an effective resistance of 300 Ω to the input signal on the antenna downlead. The signal voltage is 700 µV. What is the signal current flow in the antenna downlead?
Answer:
I = 2.33 µA
Explanation:
given,
Effective resistance (R)= 300 Ω
Voltage of signal (V)= 700 µV
current flow in the antenna = ?
Using ohm's law
V = I R
where I is the current flow
[tex]I = \dfrac{V}{R}[/tex]
[tex]I = \dfrac{700\times 10^{-6}}{300}[/tex]
I = 2.33 x 10⁻⁶ A
I = 2.33 µA
Hence, the current flow in the antenna downloaded is equal to I = 2.33 µA
Answer:I = 2.33 µA
Explanation:
In a ballistics test, a 28-g bullet pierces a sand bag that is thick. If the initial bullet velocity was and it emerged from the sandbag moving at what was the magnitude of the friction force (assuming it to be constant) that the bullet experienced while it traveled through the bag?
A. 130 N
B. 1.3 N
C. 1.4 N
D. 38 N
E. 13 N
Answer:
A) 130N
Explanation:
We know that:
[tex]E_i -E_f = W_f[/tex]
where [tex]E_i[/tex] is the initial energy, [tex]E_f[/tex] is the final energy and [tex]W_f[/tex] is the work of the friction force.
so:
[tex]\frac{1}{2}MV_i^2 -\frac{1}{2}MV_f^2 = Fd[/tex]
where M is the mass, [tex]V_i[/tex] is the initial velocity, [tex]V_f[/tex] is the final velocity, F the force and d the distance.
Replacing values, we get:
[tex]\frac{1}{2}(0.028)(55m/s)^2 -\frac{1}{2}(0.028)(18m/s)^2 = F(0.3m)[/tex]
solving for F:
F= 126N
the closest answer is A. 130 N
A man plans to make a rectangular garden with one side adjoining a neighbor’s yard. The garden is to be 675 ft2. If the neighbor agrees to pay half of the dividing fence, what should the dimensions of the garden be to ensure a minimum cost for the man?
Answer:
L = W = 26 ft.
Explanation:
Let the length of the garden is L and the width is W.
area of garden , A = L x W
675 = L x W ... (1)
Costing is minimum when the perimeter is minimum.
Perimeter, P = 2 ( L + W)
[tex]P=2\left ( L+\frac{675}{L} \right )[/tex]
For maxima and minima, differentiate perimeter with respect to L.
[tex]\frac{dP}{dL}=2\left ( 1-\frac{675}{L^{2}} \right )[/tex]
It should be zero for maxima and minima
L² = 675
L = 26 ft
W = 675/26 = 26 ft
Now, [tex]\frac{d^{2}P}{dL^{2}}=4\frac{675}{L^{3}}[/tex]
It is positive, so the costing is minimum.
So, length and width of the garden is 26 ft.
The eel has a certain amount of rotational kinetic energy when spinning at 14 spins per second. If it swam in a straight line instead, about how fast would the eel have to swim to have the same amount of kinetic energy as when it is spinning
Answer:
[tex]v=\frac{28\pi R}{\sqrt{2} }[/tex] m/sec
Explanation:
According to the question
[tex]\frac{1}{2}I\omega^2=\frac{1}{2} mv^2[/tex]
\omega= angular velocity = 14 spins per sec
I= MOI of the spinning eel= 0.5mR^2
m= mass of eel
v= linear velocity of eel.
[tex]\frac{1}{2}0.5mR^2\omega^2=\frac{1}{2} mv^2[/tex]
solving for v in the above equation we get
[tex]v=\sqrt{\frac{R^2\omega^2}{2} }[/tex]
now \omega in radians = 14 rev/sec×2π radian/rev= 28π radian/sec
value of radius is not provided in the question
therefore we get
[tex]v=\frac{28\pi R}{\sqrt{2} }[/tex]