Answer:
Fast heating up causes the water to spit out (decrepitation)
Explanation:
Hello,
Fast heating up causes the water to spit out (decrepitation), this implies that the drops containing portions of the salt could get lost and subsequently the yield is dwindled. So a graduated heating up must be ejected.
Best regards.
The hydrate compound should be heated slowly to facilitate the controlled release of water and prevent spattering and the formation of steam pockets, ensuring safety and accurate measurements. This is particularly important in exothermic processes, such as those involving sodium acetate in heat packs or the dissolution of sodium hydroxide.
Explanation:The process of slowly heating hydrate compounds is necessary to prevent rapid water loss, which can cause the compound to spatter and possibly result in an inaccurate measurement of the remaining anhydrous salt. This heating process, when done slowly, ensures a controlled release of water, and prevents the formation of steam pockets that might otherwise disrupt the sample and pose a safety risk.
In the context of a substance like sodium acetate (NaC2H3O2), this substance can release heat in an exothermic process, such as when it transitions from aqueous to solid form, which is utilized in heat pack applications where the solid dissolves upon reheating, allowing for reuse.
In exothermic dissolution experiences like with sodium hydroxide, the heat generated during the dissolution process must be managed carefully to avoid unsafe temperature elevations, indicating why a gradual approach to heating is critical for safety and accuracy in handling hydrates.
is table salt and chalk a homogeneous or heterogeneous mixture?
what is a compound in chemistry
a compound is a elements that are bonded together chemically
What is the concentration of a solution made by diluting 65 ml of 6.0 m hcl to a final volume of 750 ml?
Answer:
Concentration: 0,52
Explanation:
Remember that the concentration of a solution, is the calculus of dividing the amount of solute, could be in grams, mililiters, moles, by the amount of solvent in which the solute is going to be dissolved, in this case we will use the data provided to solve with the next formula:
[tex]C1V1=C2V2\\C2=\frac{C1*V1}{V2}\\ C2=\frac{65*6}{750}\\ C2=0,52[/tex]
So the concetration will be 0,52 m
The concentration of the diluted solution is 0.52 M
Dilution is simply reducing the concentration of a solution by the application of water.
The concentration of a diluted solution can be obtained by using the following formula:
C₁V₁ = C₂V₂Where:
C₁ => is the concentration of the stock solution
V₁ => is the volume of the stock solution
C₂ => is the concentration of the diluted solution
V₂ => is the volume of the diluted solution.
With the above formula, we can obtain the concentration of the diluted solution as follow:
Volume of stock solution (V₁) = 65 mL
Concentration of stock (C₁ ) = 6 M
Volume of diluted solution (V₂) = 750 mL
Concentration of diluted solution (C₂) =?C₁V₁ = C₂V₂
6 × 65 = C₂ × 750
390 = C₂ × 750
Divide both side by 750
C₂ = 390 / 750
C₂ = 0.52 MTherefore, the concentration of the diluted solution is 0.52 M
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Giving out 20 points please answer!!!!!
Marcia is given an incomplete chemical equation that includes the number of nitrogen atoms present in the products of the reaction. How can she conclude that the reaction started with three nitrogen atoms?
Answer:
here u go all the anser to the qustion
Marcia is given an incomplete chemical equation that includes the number of nitrogen atoms present in the products of the reaction. How can she conclude that the reaction started with three nitrogen atoms?
There would have to be three nitrogen atoms in the products. The law of conservation of matter states that the amount of substance before a reaction occurs should be the same as the amount of substance after the reaction.
Sample Response: There would have to be three nitrogen atoms in the products. The law of conservation of matter states that the amount of substance before a reaction occurs should be the same as the amount of substance after the reaction.
Which facts did you include in your response? Check all that apply.
There are three nitrogen atoms in the products.
The law of conservation of mass states that the amount of substance should be the same before and after a reaction.
Explanation:
Which of the statements are evidence that gases do not always behave ideally? it is impossible to compress a gas enough so that it takes up no volume. when two gases are mixed, they follow dalton's law of partial pressures. co2 gas becomes dry ice (solid co2) at 1 atm and –78.5∘c. at 4 k and 1 atm, helium is a liquid?
Answer:
Explanation:
"It is impossible to compress a gas enough so that it takes up no volume"
Reason: Real gases posses intermolecular forces, which allows them to deviate from showing properties of ideal gases, real gases have volumes of their own, but the molecules of ideal gases are assumed to have no volume.
Dalton's law of partial pressure is only applicable to ideal gases and not real gases.
The most stable conformation of trans-1-tert-butyl-2-methylcyclohexane is the one in which:
Final answer:
The most stable conformation of trans-1-tert-butyl-2-methylcyclohexane is one where both the tert-butyl and methyl groups are in equatorial positions to minimize steric repulsion, thus stabilizing the molecule.
Explanation:
The most stable conformation of trans-1-tert-butyl-2-methylcyclohexane is the one in which the bulky substituents, tert-butyl and methyl groups, are in the more spacious equatorial positions. This conformation reduces steric interactions, particularly the 1,3-diaxial interactions that would otherwise occur if the bulky groups were in the axial positions. Since the molecule is trans, the substituents are on opposite sides of the cyclohexane ring, therefore, the most stable conformation would have the tert-butyl group equatorial on one face of the ring and the methyl group equatorial on the opposite face.
These orientations minimize steric repulsion between the bulky groups and the hydrogens on the cyclohexane ring, thus following similar principles to those observed in conformations of butane and monosubstituted cyclohexanes. Cyclohexane chair conformations, as well as cis-trans isomerism in cycloalkanes, influences the stability of the molecule depending on the spatial arrangement of the substituents.
The correct answer is: b. both groups are equatorial. The most stable conformation of trans-1-tert-butyl-2-methylcyclohexane is the one in which both groups are equatorial.
The most stable conformation of cis-1-tert-butyl-2-methylcyclohexane is determined by the preference for bulky substituents (tert-butyl and methyl groups) to occupy the less sterically hindered positions, which are typically the equatorial positions in cyclohexane rings.
In cyclohexane, substituents prefer to be in the equatorial positions to minimize steric hindrance. Therefore, the most stable conformation of cis-1-tert-butyl-2-methylcyclohexane is when both the tert-butyl group and the methyl group are in equatorial positions. This minimizes steric interactions and maximizes stability compared to having one or both groups in axial positions.
The complete question is- The most stable conformation of cis-1-tert-butyl-2-methylcyclohexane is the one in which
a. the molecule is in the half chair conformation
b. both groups are equatorial
c. both groups are axial.
d. the methyl group is axial and the tert-butyl group is equatorial
e. the tert-butyl group is axial and the methyl group is equatorial.
A mass of 0.630 g of nacl is dissolved in 525 g of water. part a calculate the molality of the salt solution.
Molality is simply defined as the number of moles of solute over the mass of the solvent.
In this case the solute is NaCl and the solvent is water, therefore:
moles solute = 0.630g/ 58.44 g/mol = 0.0108 mol
So the molality is:
m = 0.0108 mol / (0.525 kg)
m = 0.0205 molal
Final answer:
To calculate the molality of the salt solution, divide the number of moles of NaCl by the mass of water in kilograms. In this case, the molality is 0.0206 mol/kg.
Explanation:
Molality is defined as the number of moles of solute per kilogram of solvent. To calculate the molality of the salt solution, we need to convert the mass of NaCl and water to moles and kilograms, respectively.
First, let's calculate the number of moles of NaCl:
moles of NaCl = mass of NaCl / molar mass of NaCl
moles of NaCl = 0.630 g / 58.44 g/mol = 0.0108 mol
Next, let's calculate the mass of water in kilograms:
mass of water = 525 g / 1000 = 0.525 kg
Finally, the molality of the salt solution is:
molality = moles of NaCl / mass of water
molality = 0.0108 mol / 0.525 kg = 0.0206 mol/kg
Give the name and formula of the compound formed from each pair of elements: (a) 37q and 35r (b) 8q and 13r (c) 20q and 53r
Answer:
(a) [tex]RbBr[/tex] - rubidium bromide.
(b) [tex]Al_2O_3[/tex] - aluminium oxide.
(c) [tex]CaI_2[/tex] - calcium iodide.
Explanation:
Hello,
(a) In this case, the elements having 37 and 35 as the oxidation states are rubidium and bromine respectively, in such a way the formed compound, due their gatherable oxidation states (+1 and -1 respectively) is the following binary salt:
[tex]RbBr[/tex] - rubidium bromide.
(b) In this case, the elements having 8 and 13 as the oxidation states are aluminium and oxygen respectively, in such a way the formed compound, due their gatherable oxidation states (+3 and -2 respectively) is the following basic oxide:
[tex]Al_2O_3[/tex] - aluminium oxide.
(c) In this case, the elements having 20 and 53 as the oxidation states are calcium and iodine respectively, in such a way the formed compound, due their gatherable oxidation states (+2 and -1 respectively) is the following binary salt:
[tex]CaI_2[/tex] - Calcium iodide.
Best regards.
Methyl orange (hmo) is an acid-base indicator. its two forms in solution are hmo (red) and mo- (yellow). when hmo is added to distilled water, the solution is yellow. how would you turn the solution red?
If the methyl orange solution is yellow in color in basic solution, it can be turned to red by adding an acid to it.
Given that the methyl orange solution is an indicator, it can have different colors in acidic, basic and neutral media.
An indicator is an organic dye that has a different color in acidic, basic and neutral media. The color of methyl orange in a basic medium is yellow while the color of methyl orange in an acid medium is red.
If the methyl orange is represented by HMO, an equilibrium is set up thus;
HM ⇄ MO^- + H^+
Red yellow
Addition of an acid ( H^+) shifts the equilibrium position to the left yielding the red color.
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Be sure to answer all parts. thallium(i) is oxidized by cerium(iv) as follows: tl+(aq) + 2ce4+(aq) → tl3+(aq) + 2ce3+(aq) the elementary steps, in the presence of aqueous mn(ii), are as follows: step 1: ce4+ + mn2+ → ce3+ + mn3+ step 2: ce4+ + mn3+ → ce3+ + mn4+ step 3: tl+ + mn4+ → tl3+ + mn2+ the rate law is given by the equation: rate = k[ce4+][mn2+] identify the catalyst: tl+ tl3+ ce3+ ce4+ mn2+ mn3+ mn4+ identify the intermediates: tl+ tl3+ ce3+ ce4+ mn2+ mn3+ mn4+ identify the rate-determining step
How many electrons in an atom could have n = 2, l = 1, ml = 0?
Sulfur dioxide gas reacts with oxygen gas to form sulfur trioxide gas. express your answer as a chemical equation. identify all of the phases in your answer.
Answer:
2SO2(g)+O2(g)→2SO3(g)
Explanation:
Two moles of sulfur dioxide needs to react with 1 mole of oxygen to form 2 moles of sulfur trioxide.
The chemical equation for the reaction between sulfur dioxide gas and oxygen gas to form sulfur trioxide gas is 2 SO₂(g) + O₂(g) → 2 SO₃(g), with all substances in the gaseous state.
Explanation:The reaction between sulfur dioxide gas and oxygen gas to form sulfur trioxide gas can be expressed as the following balanced chemical equation:
2 SO₂(g) + O₂(g) → 2 SO₃(g)
In this equation, (g) indicates that sulfur dioxide (SO₂), oxygen (O₂), and sulfur trioxide (SO₃) are all in the gaseous phase. This reaction is a fundamental step in the industrial synthesis of sulfuric acid and is exothermic, releasing energy in the form of heat.
Which type of rock can melt to become magma?
Answer:
It's all three.
Explanation:
In part a, we saw that the theoretical yield of aluminum oxide is 1.40 mol . calculate the percent yield if the actual yield of aluminum oxide is 0.938 mol .
The percent yield of a reaction is calculated by dividing the actual yield by the theoretical yield and then multiplying by 100. In this case, you would divide 0.938 mol (the actual yield) by 1.40 mol (the theoretical yield) and then multiply by 100 to find the percent yield.
Explanation:The percent yield of a reaction is calculated by comparing the actual yield (the amount obtained in a chemical reaction) with the theoretical yield (the maximum amount that could be produced). In this case, your theoretical yield of aluminum oxide is 1.40 mol while your actual yield is 0.938 mol. So, to calculate your percent yield, you can the formula:
Percent Yield = (Actual Yield / Theoretical Yield) x 100%
This means you would substitute your values to look like this:
Percent Yield = (0.938 mol / 1.40 mol) x 100%
After running these numbers through a calculator, you should be able to find the specific percent yield associated with this particular reaction.
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An element belongs to group 9. what common name might be used to describe the group to which this element belongs?
Explanation:
According to the periodic table chart, elements present in groups 3 to 12 are placed at the center.
These elements are known as d-block elements and all these elements are metals. General electronic configuration of d-block elements is [tex](n-1)d^{1-10} ns^{1-2}[/tex].
These d-block elements are also known as transition elements. For example, elements of group 9 are Co, Rh, Ir etc.
Therefore, we can conclude that common name which might be used to describe the group to which this given element belongs is transition metals.
A specific steroid has λmax = 2.70 × 102 nm and molar absorptivity ε = 11,500 l mol–1 cm–1. what is the concentration of the compound in a solution whose absorbance at 2.70 × 102 nm is a = 0.095 with a sample pathlength of 1.00 cm?
When 3-bromo-2,4-dimethylpentane is treated with sodium hydroxide, only one alkene is formed?
When sodium hydroxide (NaOH) is used to treat 3-bromo-2,4-dimethylpentane, an elimination reaction occurs that produces an alkene. In this instance, a dihydrohalogenation reaction specifically occurs.
In this process, both a bromine atom (Br) from the 3-position and a hydrogen atom (H) from the -carbon (the carbon next to the bromine atom) are removed. As a result, the -carbon and the carbon previously bonded to the bromine form a double bond (alkene).
2,4-dimethylpent-2-ene is the alkene that is produced when 3-bromo-2,4-dimethylpentane is reacted with sodium hydroxide. Depending on the reaction conditions, solvent and other variables, this reaction can also occur via E1 or E2 mechanism. The unique conditions of the reaction can have an effect on the selectivity of the reaction.
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Final answer:
3-Bromo-2,4-dimethylpentane will form only one alkene product upon treatment with sodium hydroxide due to the presence of only one β-hydrogen in the correct position for an E2 elimination reaction.
Explanation:
When 3-bromo-2,4-dimethylpentane is treated with sodium hydroxide, the reaction is an elimination reaction, specifically an E2 mechanism. In an E2 mechanism, the base removes a hydrogen atom that is anti to the leaving group, in this case bromide, resulting in the formation of a double bond and thus creating an alkene. For 3-bromo-2,4-dimethylpentane, there is only one β-hydrogen available that is anti to the leaving group, which is on the third carbon. This means that only one alkene can form, as there are no other β-hydrogens that can be removed to form a different alkene.
which context clue best helps you figure out the meaning of the word threshold?
A compound of metallic and nonmetallic elements for which the interatomic bonding range from 100% covalent to 100% ionic is
a............................
A compound has the empirical formula ch and a formula mass of 52.10 amu. part a what is the molecular formula of the compound?
Answer: The 3rd option (CH4) on edg
Explanation:
When 2.50 g of copper reacts with oxygen the copper oxide product has a mass of 2.81 g. what is the simplest formula of the copper oxide?
By using proportional rule, the simplest formula can be calculated as [tex]\rm \bold { Cu_2O}[/tex]
Molar mass of Copper is 63.54 g
Molar mass of Oxygen is 16
Here,
The mole of copper is 0.0393
The moles of oxygen is 0.0194
Hence, by using proportional rule, the simplest formula can be calculated as [tex]\rm \bold { Cu_2O}[/tex].
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Why is the solubility of a neutral organic compound unaltered by exposure to aqueous acid or base?
Why does sand conduct heat better than water? The molecules in water are closer together than the molecules in sand. The molecules in sand are closer together than the molecules in water. The molecules in sand are larger than the molecules in water. The molecules in water are more dense than the molecules in sand.
Does a precipitate form when a solution of sodium acetate and a solution of calcium chloride and a solution of mercury(i) nitrate are mixed together?
Final answer:
When a solution of sodium acetate is mixed with solutions of calcium chloride and mercury(I) nitrate, a precipitate of mercury(I) chloride will form, as it is insoluble in water according to solubility rules.
Explanation:
To determine if a precipitate forms when a solution of sodium acetate is mixed with a solution of calcium chloride and mercury(I) nitrate, we must first consider the ions present and their potential reactions based on solubility rules. Sodium acetate dissociates into Na+ and CH3COO- ions. Calcium chloride breaks down into Ca2+ and Cl- ions, while mercury(I) nitrate yields Hg2^2+ and NO3- ions in solution.
Following the solubility rules and considering possible cation/anion pairings, one possible reaction is between calcium (Ca2+) and acetate (CH3COO-) ions to form calcium acetate. However, all acetates are soluble in water, so no precipitate would form from this pairing. Another possibility is the reaction between the mercury(I) (Hg2^2+) cation and the chloride (Cl-) anion, which could produce mercury(I) chloride. However, mercury(I) chloride (Hg2Cl2) is insoluble and will form a precipitate. Therefore, when these solutions are mixed, mercury(I) chloride precipitate will indeed form.
A solution was prepared by dissolving 31.0 g of kcl in 225 g of water. part a calculate the mass percent of kcl in the solution.
Final answer:
To find the mass percent of KCl in the solution, add the mass of KCl to the mass of water to get the total mass of the solution, then divide the mass of KCl by this total mass and multiply by 100% to get a mass percent of 12.11%.
Explanation:
To calculate the mass percent of KCl in a solution where 31.0 g of KCl is dissolved in 225 g of water, you should first determine the total mass of the solution. This is done by adding the mass of the solute (KCl) to the mass of the solvent (water). Therefore, the mass of the solution is:
mass of solution = mass of solute + mass solvent
mass of solution = 31.0 g KCl + 225 g water = 256.0 g
Next, to find the mass percent of KCl, divide the mass of KCl by the total mass of the solution and then multiply by 100%:
Percent by mass = (mass of solute / mass of solution) x 100%
Percent by mass = (31.0 g / 256.0 g) x 100% = 12.11%
Therefore, the mass/mass percent concentration of KCl in the solution is 12.11%.
4NH3 (g)+502(g)->6H20g)+4NOg) What is the enthalpy change for this reaction?
Final answer:
The exact enthalpy change (ΔH) for the given chemical reaction cannot be determined without the standard enthalpies of formation or a series of reactions leading to the overall reaction.
Explanation:
The enthalpy change for the reaction 4NH3 (g) + 5O2 (g) → 4NO (g) + 6H2O (g) can be determined by summing the enthalpy changes of intermediate steps that sum up to give the overall reaction.
The provided information suggests the need to combine different reactions and their respective enthalpy changes to find the total ΔH for the reaction of interest.
However, the details offered are not clear enough to calculate a precise value directly. To calculate the exact enthalpy change, you would need to know the standard enthalpies of formation for each reactant and product, or you would sum the enthalpy changes of a series of reactions that produce the same final products from the same initial reactants.
If we consider similar reactions and principles provided in the reference information, it can be noted that multiplying or dividing an equation and its enthalpy change by a number gives an adjusted enthalpy change for the new stoichiometric coefficients.
Also, from a given reaction such as N2(g) + O2(g) → 2NO(g) having an enthalpy change of 181 kJ, one can infer similar adjustments. Nevertheless, without precise data for the given reaction, an accurate value for the ΔH cannot be provided here.
the enthalpy change for the reaction is -1169.2 kJ. The negative sign indicates that the reaction is exothermic, releasing heat to the surroundings.
To determine the enthalpy change for the given reaction, you can use the enthalpy values of the individual compounds involved in the reaction. Enthalpy change is usually represented by the symbol ΔH. In this case, you need to calculate the overall change in enthalpy for the reaction:
1. Identify the enthalpy values for the reactants and products in the reaction. For example:
- Enthalpy of formation of NH3 = -46.1 kJ/mol
- Enthalpy of formation of O2 = 0 kJ/mol
- Enthalpy of formation of H2O = -285.8 kJ/mol
- Enthalpy of formation of NO = 90.3 kJ/mol
2. Calculate the enthalpy change for the reaction using the given enthalpy values:
ΔH = ΣΔH(products) - ΣΔH(reactants)
ΔH = [6(-285.8 kJ/mol) + 4(90.3 kJ/mol)] - [4(-46.1 kJ/mol) + 5(0 kJ/mol)]
3. Substitute the values into the equation and solve for ΔH:
ΔH = [-1714.8 kJ + 361.2 kJ] - [-184.4 kJ]
ΔH = -1353.6 kJ + 184.4 kJ
ΔH = -1169.2 kJ
Therefore, the enthalpy change for the reaction is -1169.2 kJ. The negative sign indicates that the reaction is exothermic, releasing heat to the surroundings.
Complete the sentences to explain why the lattice energy of potassium bromide is more exothermic than the lattice energy of rubidium iodide?
Due to strong forces of attraction in potassium bromide, the lattice energy of potassium bromide is more exothermic than rubidium iodide.
Further Explanation:
Lattice energy:
It is the amount of energy released when ions are combined to form an ionic compound or the energy required to break the ionic compound into its constituent gaseous ions. It cannot be measured directly and is denoted by [tex]{\mathbf{\Delta}}{{\mathbf{H}}_{{\mathbf{lattice}}}}[/tex] . It can have positive as well as negative values.
Case I: Positive lattice energy
The value of lattice energy [tex]$$({\text{\Delta }}{{\text{H}}_{{\text{lattice}}}})$$[/tex] comes out to be positive if the energy supplied to the system is more than that released during the reaction. In other words, [tex]{\mathbf{\Delta}}{{\mathbf{H}}_{{\mathbf{lattice}}}}[/tex] is positive in case of endothermic reactions.
Case II: Negative lattice energy
The value of lattice energy [tex]$$({\text{\Delta }}{{\text{H}}_{{\text{lattice}}}})$$[/tex] comes out to be negative if the energy released by the system is more than the energy supplied during the reaction. In other words, [tex]{\mathbf{\Delta}}{{\mathbf{H}}_{{\mathbf{lattice}}}}[/tex] is negative in case of exothermic reactions.
Lattice energy is used to determine the stability of ionic compounds.
The lattice energy of an ionic solid depends upon the following factors:
(1) The charge on the ions.
(2) The size or the radius of the ions.
The charge on the ions is directly related to the lattice energy, and therefore the lattice energy increases with increases in the charge on the ion. The size of an ion is inversely proportional to the lattice energy. Therefore, when the size of an ion increases, the lattice energy decreases.
As we move down the group in the periodic table, the size of an atom increases and therefore the lattice energy decreases.
The charge on the potassium ion and rubidium ion are +1, and the charge on the bromide ion and iodide ion are -1. Therefore the charge present on the ions in potassium bromide and rubidium iodide is same.
Potassium has smaller size as compared to rubidium ion, and bromide ion has smaller size as compared to iodide ion. The size of an ion is inversely proportional to the lattice energy and therefore potassium bromide has higher lattice energy as compared to rubidium iodide.
Potassium bromide is more effectively packed and has strong force of attraction as compared to rubidium iodide. This is the reason that more energy is released in the case of potassium bromide as compared to rubidium iodide.
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Answer details:
Grade: Senior School
Subject: Chemistry
Chapter: S-block elements.
Keywords: Lattice energy, potassium bromide, rubidium iodide, crystal lattice, exothermic, endothermic, elements, s-block, periodic table and ionic size.
which is acceptable when using powered tools?
Using powered tools requires adherence to safety protocols such as wearing protective equipment, inspecting the tool, using it as per the manual, and maintaining a firm grip and balance. Electric tools should never be used in damp conditions and should be unplugged when not in use or during maintenance.
Explanation:When using powered tools, it is crucial to follow safety measures to prevent accidents or injuries. One of the key aspects is to always wear appropriate personal protective equipment, such as gloves, protective glasses, and sturdy shoes. It is also acceptable and necessary to inspect the tool before use to ensure it is in good working condition. Always use the tools as instructed by their manual, never applying force or using them in a way they were not designed for.
Electric power tools should always be unplugged when not in use or during maintenance or cleaning and should never be used in wet or damp conditions as water can cause an electric shock. Furthermore, you should always maintain a firm grip and balanced posture when using powered tools to prevent undesired movement that may lead to accidents.
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Phosphorous pentchloride (pcl5 ) is used as a chlorinating reagent in chlorination of organic compounds. what type of bonding occurs between the atoms of a pcl5 molecule?
The type of bond that a Phosphorous pentachloride have is an Ionic Bonding. It is a form of chemical bond that encompasses the electrostatic attraction between oppositely charged ions which serves as the primary interaction happening in ionic compound. Phosphorus has 5 valence electrons and Chlorine has 7 valence electrons. Phosphorus contributes 1 electron to each chlorine and all the 6 achieve 8 electrons in the outer shell thus creating an ionic bond.
Answer:
PCl5 is a covalent bond
Explanation:
Ionic bonds are bonds between a metal and a non-metal.
Covalent bonds are bonds between 2 or more non-metals.
Neither P or Cl are metals, therefore PCl5 has a covalent bond.
Calculate empirical formula 24.5 g nitrogen 70 g oxygen