Why does increasing the pressure of a gas usually increase reaction rate

Answers

Answer 1
ANSWER: Well increasing the pressure of a reacting gas increases the number of reactant particles that are in the same volume, Therefore there will be a greater chance of particles colliding and increases in the frequency of collisions and so that increases the rate of reaction.

EXPLANATION: More pressure means more gas; more gas means more particles react.
Answer 2

Answer:

It increases the number of collision


Related Questions

What is the potential difference vab between points a and b when the switch s is open?

Answers

Final answer:

The potential difference vab between points a and b when the switch s is open can be calculated using the formula VAB = Ed where E is the electric field intensity and d is the distance between the points.

Explanation:

The potential difference vab between points a and b when the switch s is open can be calculated using the formula VAB = Ed, where E is the electric field intensity and d is the distance between the points. The potential difference is measured in volts (V).

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By what amount does the sound intensity decrease when the distance to the source doubles?

Answers

The relationship of the two is that, the sound intensity is inversely proportional to the square of the distance of the source.

I α 1 / r^2

Where I = intensity and r = distance from source

From this, we can equate two conditions 1 and 2:

I1 / I2 = r2^2 / r1^2

So when r2 = 2 r1, the intensity becomes:

I1 / I2 = (2r1 / r1)^2

I1 / I2 = 4

I2 = I1 / 4

So when we double the distance of the source, the intensity of the sound reduces by a factor of 4 (divided by 4).

A balloon is released from a tall building. the total mass of the balloon including the enclosed gas is 2.0 kg. its volume is 5.0 m3. the density of air is 1.3 kg/m3. will the balloon rise, fall, or remain stationary; and why?

Answers

Given:
m = 2.0 kg, mass of the balloon and enclosed gas
V = 5.0 m³, volume of balloon.

Calculate the effective density of the balloon.
ρ = m/V
   = 2/5 
   = 0.4 kg/m³

The density of air is 1.3 kg/m³, which is denser than the balloon. Therefore the balloon will rise.

Answer: The balloon will rise because its density is less than that of air.

In order to induce electrical energy into a conductor or generator, what three factors must be present?

Answers

The electricity produced by a generator works through the concepts of the following three factors; magnetic field, voltage and current. When a conductor with current flowing in it is placed in a magnetic field, it will cause the electrons to move in a direction perpendicular to the magnetic field. When working with generators, the guide for this direction is Fleming's Right Hand Rule. Since the electron move in perpendicular motion with magnetic field all the time, it would cause it to spin in a helical direction. These turns would then induce voltage and create electricity.

An athlete does one push-up. In the process, she moves half of her body weight, 250 newtons, a distance of 20 centimeters. This distance is the distance her gravity moves when she fully extends her arms. How much work did she do after one push-up?

Answers

We know that an athlete moves half of her body weight 250 N a distance of 20 cm.
So:  F = 250 N,  d = 20 cm = 0.2 m
The work formula:
W = F * d
W = 250 N * 0.2 m
W = 50 J
Answer: Her work after one push-up is 50 J.

What are the components of earths life support system

Answers

The four major components of the earth's life-support system are the atmosphere (air), the hydrosphere (water), the geosphere (rock, soil, and sediment), and the biosphere (living things).

The components of Earth's life support system are air, water, soil, and living organisms.  

What is a Life support system?

The life support system is necessary for living organisms. It elements are necessary to promote living organisms and give sustainable life to living organisms.

It is a system that provides all the substances which is essential for the living. It is the combination of equipment that allows the survival in environment.

Life support systems offer food, oxygen, water, and the disposition of carbon and wastes. It includes the atmosphere(air), hydrosphere (water), biosphere (living organisms), and geosphere (soil).

The atmosphere offers air (oxygen) for living organisms to breathe. Hydrosphere offers water for living organisms and the geosphere offers shelter for living organisms.

Hence the components of Earth's life support system are air, water, soil, and oxygen.

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A car braked with a constant deceleration of 8 ft/s2, producing skid marks measuring 100 ft before coming to a stop. how fast was the car traveling when the brakes were first applied?

Answers

In physics, it is convenient that there are already derived formulas for rectilinear motion at constant acceleration from Newton's Law of motion. One of these equations useful for this problem is:

2ax = vf2 - v02, where a is the acceleration, x is the distance, vf is the final velocity and v0 is the initial velocity.

Now, a=-8 ft/s2. It is negative because the car is decelerating. The distance x is 100 ft, the vf is equal to 0m/s because the car comes to a stop. The only unknown would be v0.

2(-8 ft/s2)(100 ft) = (0m/s)^2 - v0^2
v0 = 40 m/s
Final answer:

To find the initial speed of the car when the brakes were first applied, you can use the formula: v^2 = u^2 + 2as. Plugging in the given values, we find that the car was traveling at approximately 28.3 ft/s (or 19.3 mph) when the brakes were first applied.

Explanation:

To find the initial speed of the car when the brakes were first applied, you can use the formula:

v^2 = u^2 + 2as

v is the final velocity, which is 0 ft/s since the car comes to a stopu is the initial velocity, which we need to finda is the deceleration, which is given as 8 ft/s^2s is the distance, which is given as 100 ft

Plugging in the values into the formula, we get:

0 = u^2 + 2(8)(100)

Solving for u, we find that the car was traveling at approximately 28.3 ft/s (or 19.3 mph) when the brakes were first applied.

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A speedboat moving at 31.0 m/s approaches a no-wake buoy marker 100 m ahead. the pilot slows the boat with a constant acceleration of −4.00 m/s2 by reducing the throttle. (a) how long does it take the boat to reach the buoy? s (b) what is the velocity of the boat when it reaches the buoy? m/s

Answers

u = 31 m/s, the initial speed of the boat
s = 100 m, distance to the buoy
a = -4 m/s², the acceleratin (actually deceleration)

Part (a)
Let t = time required to reach the buoy.
Use the formula ut + (1/2)at² = s.
(31 m/s)*(t s) - (1/2)*(4 m/s²)*(t s)² = (100 m)
2t² - 31t + 100 = 0

Solve with the quadratic formula.
t = (1/4) [31 +/- √(31² - 800)]
  = 10.92 s or 4.58 s
Before selecting the answer, we should determine the velocity at the buoy.

Part (b)
When t = 10.92 s, the velocity at the buoy is
v = (31 m/s) - (4 m/s²)*(10.92 s) = -12.68 m/s
Because of the negative value, this value of t should be rejected.

When t = 4.58 s, the velocity at the buoy is
v = (31 m/s) - (4 m/s²)*(4.58 s) = 12.68 m/s
This value of t is acceptable.

Answer (to nearest tenth): 
(a) The time is 4.6 s 
(b) The velocity is 12.7 m/s
Final answer:

The boat takes 7.75 seconds to reach the buoy and its velocity when it reaches the buoy is 0 m/s.

Explanation:

To solve this problem, we can use the equations of motion under constant acceleration. Let's start with part (a).

Given:

Initial velocity, v0 = 31.0 m/s

Final velocity, v = 0 m/s (since the boat reaches the buoy and stops)

Acceleration, a = -4.00 m/s2

We can use the equation:

v = v0 + at

Substituting the given values, we have:

0 = 31.0 - 4.00t

4.00t = 31.0

t = 7.75 s

Therefore, it takes the boat 7.75 seconds to reach the buoy.

Now, let's move on to part (b).

To find the final velocity, we can use the same equation:

v = v0 + at

Substituting the known values:

v = 31.0 - 4.00(7.75)

v = 31.0 - 31.0

v = 0 m/s

Therefore, the velocity of the boat when it reaches the buoy is 0 m/s.

A person riding north on a bike speeds up from 0m/s to 9m/s in 3 seconds. What is the acceleration of the bike

Answers

A=(V-V0)/T
V=9m/s
V0=0m/s
T=3sec

So a=9/3=3m/s^2

The acceleration of the bike that speeds up from 0m/s to 9m/s in 3 seconds is 3m/s². Details about acceleration can be found below.

How to calculate acceleration?

The acceleration of a moving body can be calculated by dividing the change in velocity of the body by the time taken.

According to this question, a bike speeds up from 0m/s to 9m/s in 3 seconds. The acceleration can be calculated as follows:

a = (9m/s - 0m/s)/3 seconds

a = 9m/s ÷ 3s

a = 3m/s²

Therefore, the acceleration of the bike that speeds up from 0m/s to 9m/s in 3 seconds is 3m/s².

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The time a basketball player spends in the air when shooting a basket is called the​ "hang time." the vertical leap l measured in feet is related to the hang time t measured in seconds by the equation lequals=4t2. suppose that a basketball player has a vertical leap of 4 feet 4 inches. find the hang time for this leap.

Answers

I believe that L is in feet while t is in seconds. To find for the hang time, all we have to do is to plug in the value of L in feet in the equation.

4 inches is equivalent to 4/12 feet or 0.33 feet, therefore the total L is:

L = 4.33 ft

Using the equation to find for t:

L = 4 t^2

4.33 = 4 t^2

t = 1.04 s

To calculate the hang time for a basketball player with a vertical leap of 4 feet 4 inches, solve the equation l = 4[tex]t^2[/tex] to find that the hang time is approximately 1.041 seconds.

The vertical leap l is related to the hang time t by the equation l = 4[tex]t^2[/tex]. To find the hang time for a basketball player with a vertical leap of 4 feet 4 inches (which is 4.333 feet), we plug this value into the equation and solve for t:

4.333 = 4[tex]t^2[/tex]

[tex]t^2[/tex] = 4.333 / 4

[tex]t^2[/tex] = 1.08325

t = [tex]\sqrt{(1.08325)[/tex]

t ≈ 1.041

Hence, the hang time for this leap is approximately 1.041 seconds.

A thin film of polystyrene is used as an antireflective coating for fabulite (known as the substrate). the index of refraction of the polystyrene is 1.49, and the index of refraction of the fabulite is 2.409. what is the minimum thickness of film required? assume that the wavelength of the light in air is 500 nanometers.

Answers

To solve this problem, we assume that the wavelength of the light in air is 500 nanometers.

For this case we only need the refractive index of the polystyrene. For an antireflective coating, we need a quarter of wave thickness at the wavelength in the air. Which means that the antireflective coating needs to be as thick as 1/4 of the wavelength, divided by the coating’s refractive index. This is expressed mathematically in the form:

x = λ / (4 * n)

where,

x = thickness

λ = wavelength of light

n = index of refraction of polystyrene

Substituting:

x = 500 nm / (4 * 1.49)
x = 500 nm / 5.96
x = 83.90 nm

The minimum thickness of the film required assuming that the wavelength of the light in air is 500 nanometers is; 83.9 nm

Calculations about Destructive Interference

We are given;

Index of refraction of polystyrene; η_p = 1.49

Index of refraction of Fabulite; η_f = 2.409

Wavelength of the light in air; λ = 500 nm

In this question, it will be discovered that light will first of all be reflected two times, first from the upper layer of coating and then from the interface between the coating and the polystyrene material.

The additional path travelled by the light in coating is 2t while the path difference is 2tη_p.

Thus, minimum thickness of film required will be gotten from the formula used in destructive interference which is;

2tη_p = λ/2

t = λ/2 * 1/2η_p

t = λ/(4η_p)

t = 500/(4 * 1.49)

t = 83.9 nm

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A circuit contains a 6.0-v battery, a 4.0-w resistor, a 0.60-µf capacitor, an ammeter, and a switch all in series. what will be the current reading immediately after the switch is closed?

Answers

You are given a circuit that contains a 6.0-v battery, a 4.0 ohm resistor, a 0.60 micro farad capacitor, an ammeter, and a switch all in series. You are asked to find the current reading after the switch is closed. Apply ohms law where V = IR where V is the voltage, I is the current and R is the resistor.

V = IR
I = V/R
I = 6 volts / 4 ohms
I = 1.5A

When the switch is closed, the cathode side plate begins to fill up with electrons when it was originally empty before the switch was closed. When it fills up the cathode side of the circuit, the current decreases. And when the capacitor cannot hold more electrons, the current will stop. The higher the capacitance, the higher is the capacity to store electrons.

Answer:

I = 0.667 A

Explanation:

A capacitor behaves like a short circuit at t = 0 immediately after the switch is closed, therefore we can discard it from the equation, the resistance is given in watts or power units equivalent to current by voltage and the ammeter behave like a short circuit by nature.

Considering all of the above, the circuit looks like a battery in series with a resistor, therefore, we can use the power equation to solve the problem as follow:

P = I*V

4W = I*6V

I = 0.667 A  

Jessica stretches her arms out 0.6 m from the center of her body while holding a 2 kg mass in each hand. she then spins around on an ice rink at 1.1 m/s.
a. what is the combined angular momentum of the masses?

Answers

Angular momentum is the measure of the amount of rotation of the body. It is the product of the moment of inertia and the angular velocity. The moment of inertia has the equation I=mr^2, where m is the mass and r is the radius of the circle. In this case, the radius is 0.6 m. Then, I = 2kg * (0.6)^2 = 0.72 kg-m2/s2.

The angular velocity on the other hand is the product of linear velocity and the radius. The equation is ω = rv, where v is the linear velocity. Therefore, ω = 0.6*1.1 = 0.66 rad/s

Therefore, the angular momentum is 

= 0.72 kg-m2/s2*0.66 rad/s
= 0.48 kg-m^2/s

What is the maximum capacity of an analog circuit with a bandwidth of 4000 hz using qam?

Answers

The answer is 16,000 bps

How are chemical reactions classified?

Answers

Types of Chemical Reactions. Combination or Synthesis Reactions Two or more reactants unite to form a single product. Substitution or Single Replacement Reactions A single free element replaces or is substituted for one of the elements in a compound. The free element is more reactive than the one its replaces.

The types of chemical reactions are

a) Combination reaction.

b) Decomposition reaction.

c) Displacement reaction.

d) Double Displacement reaction.

e) Precipitation Reaction.

What are chemical reactions?

In a chemical reaction, one or more chemicals , also known as reactants are changed into one or more other substances, known as products. In a chemical reaction, the atoms that make up the reactants are rearranged to produce various products.

Chemical equations, which depict the reactants and products of the reaction using chemical symbols and chemical formulae, can be used to represent chemical reactions. The relative numbers of atoms or molecules participating in the reaction are indicated by the coefficients placed in front of the chemical formulae.

Given data ,

The types of chemical reactions are given as

Combination reaction, Decomposition reaction , Displacement reaction , Double Displacement reaction , Precipitation Reaction

And , the characteristics of a chemical reaction are evolution of gas , formation of a precipitate , change in color or temperature and state , formation of new substances

Thermodynamic and kinetic characteristics govern the many types of chemical processes, and they may be modeled by a number of factors including energy, entropy, and Gibbs free energy change.

Hence , the types of chemical reactions are solved

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An ideal solenoid having a coil density of 5000 turns per meter is 10 cm long and carries a current of 4.0
a. what is the strength of the magnetic field at its center?

Answers

The rule that is used to get the strength of magnetic field at the center of solenoid (B) is:
B = µ x n x I where:
µ is the permeability of the medium where the solenoid is based. In this problem, the medium is air which means that µ = µ o = 4 pi x 10^-7 Tm/A
I is the current passing (I = 4 amperes)
n is the number of turns per unit length (5000 turns)

Substituting in the mentioned equation, we find that:
B = 4 x 3.14 x 10^-7 x 5000 x 4 = 25.132 mT

a body of mass 1 kg is placed at a distance of 2 m from another body of mass 10 kg. At what distance from the body of mass 1 kg, another body must be placed so that the net gravitational force acting on the body of mass 1 kg is zero

Answers

To answer this problem, we will use the formula for gravitational force:

F = G m1 m2 / r^2

Where,

G = gravitational constant (6.67 * 10^-11)

m = mass of a body

r = distance between two bodies

To have a net gravitational force equal to zero acting on body of mass 1 kg, then the forces of 1 kg and 10 kg bodies and 1 kg and 5 kg bodies should be equal.

F1 (1 kg and 10 kg) = F2 (1 kg and 5 kg)

Therefore,

(1 kg) (10 kg) / (2 m)^2 = (1 kg) (5 kg) / r2^2

Calculating for r2 (distance of another body 5 kg from body of mass 1 kg):

r2^2 = 2

r2 = 1.41 m       (ANSWER)

Therefore another body of mass 5 kg should be placed 1.41 m from body of mass 1 kg to have a net gravitational force equal to zero.

Which describes how to generate a real image of an object using a concave mirror?

Answers

A concave mirror is curved inward in the middle, more like a cave. Because the mirror is curved inward, the angle of the light surface can be focused similar to that of the camera. They can form real images that are projected out in front of the mirror at the place where light focuses. When the object is located at the center of the curvature the image formed will also be at the curvature. The image will be inverted and the magnification value is equal to 1 which will become a real image because the ray of light converges at the location of the formed image.

Answer:

The object must be farther from the mirror than the focal point

Explanation:

gradpoint lesson

A standing wave is set up in a 200-cm string fixed at both ends. the string vibrates in 5 distinct segments when driven by a 120-hz source. what is the wavelength?

Answers

The wavelength of a standing wave is equivalent to:

wavelength = 2 l / n

Where l is the length of the string and n is the number of segments.

so, wavelength = 2 (0.2 m) / 5 
wavelength = 0.08m      (ANSWER)

Answer:

[tex]\lambda=80\ cm[/tex]

Explanation:

It is given that,

Length of the string, L = 200 cm = 2 m

Frequency, f = 120 Hz

It vibrates in 5 distinct segments such that there is fifth harmonics. For a string fixed at both ends, the wavelength is given by :

[tex]\lambda=\dfrac{2}{5}L[/tex]

[tex]\lambda=\dfrac{2}{5}\times 2[/tex]

[tex]\lambda=0.8\ m[/tex]

[tex]\lambda=80\ cm[/tex]

So, the wavelength of the string fixed at both ends is 80 cm. Hence, this is the required solution.

A recent experiment reports that increased lighting during the winter months results in lower depression scores. for this study, what is the dependent variable?

Answers

the weather is the dependent variable

Give three examples from your life of magnetic force.

Answers

headphones, refrigerator magnets, and compasses

Hope that was helpful.
Magnets,popsocket, and a car

When studying whiplash resulting from rear end collisions, the rotation of the head is of primary interest. an impact test was performed, and it was found that the angular acceleration of the head is defined by the relation α = 700cosθ + 70sinθ, where α is expressed in rad/s2 and θ in radians. knowing that the head is initially at rest, determine the angular velocity of the head when θ = 30°?

Answers

The correct answer is[tex]\(\boxed{\omega \approx 479.0 \text{ rad/s}}\)[/tex].

To determine the angular velocity of the head when[tex]\(\theta = 30^\circ\),[/tex] we need to integrate the angular acceleration with respect to time. However, since angular acceleration is given as a function of [tex]\(\theta\)[/tex], we will use the relationship between angular acceleration [tex](\(\alpha\))[/tex], angular velocity[tex](\(\omega\))[/tex], and angle [tex](\(\theta\))[/tex] to find the angular velocity as a function of [tex]\(\theta\).[/tex]

The relationship between angular acceleration, angular velocity, and angle is given by:

[tex]\[\alpha = \frac{d\omega}{dt} = \frac{d\omega}{d\theta} \cdot \frac{d\theta}{dt} = \omega \frac{d\omega}{d\theta}\][/tex]

Since[tex]\(\alpha\)[/tex]is a function of [tex]\(\theta\)[/tex], we can write:

[tex]\[\omega \frac{d\omega}{d\theta} = 700\cos\theta + 70\sin\theta\][/tex]

To find [tex]\(\omega\),[/tex] we separate variables and integrate:

[tex]\[\int \omega \, d\omega = \int (700\cos\theta + 70\sin\theta) \, d\theta\][/tex]

Integrating both sides, we get:

[tex]\[\frac{\omega^2}{2} = 700\sin\theta - 70\cos\theta + C\][/tex]

where [tex]\(C\)[/tex] is the constant of integration. To find [tex]\(C\)[/tex], we use the initial condition that the head is initially at rest, which means[tex]\(\omega = 0\)[/tex] when [tex]\(\theta = 0\)[/tex]. Plugging these values into the equation, we find:[tex]\[0 = 700\sin(0) - 70\cos(0) + C\]\[C = 70\][/tex]

Now we have the constant[tex]\(C\)[/tex], and we can find the angular velocity when [tex]\(\theta = \frac{\pi}{6}\) radians (or \(30^\circ\)):[/tex][tex]\[\frac{\omega^2}{2} = 700\sin\left(\frac{\pi}{6}\right) - 70\cos\left(\frac{\pi}{6}\right) + 70\] \[\frac{\omega^2}{2} = 700\left(\frac{1}{2}\right) - 70\left(\frac{\sqrt{3}}{2}\right) + 70\] \[\frac{\omega^2}{2} = 350 - 35\sqrt{3} + 70\] \[\frac{\omega^2}{2} = 420 - 35\sqrt{3}\][/tex]

Multiplying both sides by 2 to solve for[tex]\(\omega^2\)[/tex]:

[tex]\[\omega^2 = 2(420 - 35\sqrt{3})\]\[\omega^2 = 840 - 70\sqrt{3}\][/tex]

Taking the square root of both sides to find [tex]\(\omega\)[/tex]:

[tex]\[\omega = \sqrt{840 - 70\sqrt{3}}\][/tex]

Now we can calculate the numerical value:

[tex]\[\omega \approx \sqrt{840 - 70 \times 1.732}\] \[\omega \approx \sqrt{840 - 121.24}\] \[\omega \approx \sqrt{718.76}\] \[\omega \approx 479.0 \text{ rad/s}\][/tex]

Therefore, the angular velocity of the head[tex]when \(\theta = 30^\circ\) is approximately \(\boxed{479.0 \text{ rad/s}}\)[/tex]

How strong is the electric field between the plates of a 0.86 µf air-gap capacitor if they are 2.0 mm apart and each has a charge of 64 µc?

Answers

The electric field between the plates is equal to the potential difference across the plates divided by the separation of the plates.
The potential difference across the plates is equal to the charge stored divided by the capacitance.

The surface or material that underlies a two-dimensional work of art is called the ____.

Answers

The surface or material that underlies a two-dimensional work of art is called the support.
Final answer:

The term for the surface or material that underlies a two-dimensional work of art is 'substrate'. It plays a critical role in the final appearance of the artwork, and its understanding is key to appreciating a given piece of art.

Explanation:

The surface or material that underlies a two-dimensional work of art is called the substrate. This term refers to the material on which the artwork is created. For example, in a painting, the substrate could be the canvas. Similarly, for a drawing, the substrate might be a piece of paper. The substrate plays a vital role in the final appearance of the artwork.

One can relate the concept of substrate in art to Aristotle's explanation of substance as a composite of matter and form. In his perspective, the form is the unchanging purpose or idea informing each particular instance, while the substrate (in his terminology, matter or material cause) contributes to the physical properties of the artwork. Therefore, understanding the substrate is an essential aspect of appreciating a given piece of art.

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A man whose weight is 650 N is standing on the ground. The force the ground exerts on him is _____.

Answers

The force the ground exerts on him is 650 N.

What is force?

The push or pull on an object with mass that causes it to change its velocity.

According to law of newton

"Every action has an equal and opposite reaction."

This means that the ground is exerting the same amount of force as the man, 650 N.

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When you eat a candy bar and then decide to go for a walk, energy transformations take place. beginning with the food energy in the candy bar, describe the forms of energy used and the changes in energy that occur as you decide to walk and as you do the walking?

Answers

When we eat a candy bar and then decide to go for a walk, we get instant energy in the body due to the food energy in the candy and that is called carbohydrates. The carbohydrates in the candy give our body some instant energy due to which we feel more energetic and do the walk or another physical thing with a boost.  
Our potential energy somewhat increases after eating the candy and when we walk, it gets transformed into kinetic energy

When a sound wave moves through a medium such as air, the motion of the molecules of the medium is in what direction (with respect to the motion of the sound wave?

Answers

A sound wave is a pressure wave that results from the vibration of the particles o the medium from the source. The motion of the particles in the medium is parallel to the direction of the energy transport. The type of wave formed by a sound wave is the longitudinal wave. A longitudinal wave is characterized by rarefactions. A longitudinal wave is a wave motion wherein the particles in the wave medium are displaced parallel to transport. When motion is detected from the source, the particle next to it vibrates from its rest position and a progressive change in phase vibration is observed at each particle within that wave. The result is that the energy is transported from one region to the other. These combined motions result in the movement of alternating regions of rarefaction in the direction of propagation.      

A(n) _________ is responsible for collecting light rays previously focused on the specimen.

Answers

objective lens are responsible

Answer:

Objectives lens are responsible

Which of newton's laws could we have used to predict that the forces in parts b and e are equal and opposite?

Answers

That's the The third Newton's Law.

1. A 0.828-nm photon collides with a stationary electron. After the collision, the electron moves forward and the photon recoils backwards.
a) Find the momentum of the electron.

b) Find the kinetic energy of the electron.

Answers

a) Find the momentum of the electron.

The momentum would be as follows:
p = E / c 
p= (h(c) / (wavelength)) / c 
p = h / wavelength
p = 6.626x10^-34 J s / 0.828x10^-9 m 
p = 8.00 x 10^-25 kg m/s 

b) Find the kinetic energy of the electron.

Assuming this is a head-on collision, then cosine of the angle would be -1. 
wavelength (after) - wavelength (before) = 2(h / m(e) c) 
wavelength (after) = 2(h/m(e) c) + wavelength (before) 
wavelength (after) = 0.00485 nm + 0.828 nm 
wavelength (after) = 0.83385 nm 

E = h(c)/wavelength 
E(before) = h c / 0.828x10^-9 = 2.4x10^-16 J
E(after) = h c / 0.83385 x10^-9 = 2.38 x10^-16 J 
Total change in E = 2.4x10^-16 J - 2.38 x10^-16 J 
Total change in E = 3.16x10^-17 J
Final answer:

To find the momentum of the electron after collision with a photon, the momentum of the photon must be calculated first using Planck's constant and the wavelength of the photon. The kinetic energy of the electron depends on the specific details of the conservation of energy and momentum in the collision, which are not provided.

Explanation:

The question involves calculating the momentum of the electron and the kinetic energy of the electron after it collides with a photon. This scenario is explored in the context of compton scattering, which is a common topic in high school and college physics classes.

To find the momentum of the electron, we use the relationship for the momentum (p) of a photon, which is given by p = h/λ, where h is Planck's constant (6.63 × 10-34 m² kg/s) and λ is the wavelength of the photon. For an 0.828-nm photon, this yields a momentum that the electron will take after the collision.

However, without additional information on the scattering angle or final energy/wavelength of the photon, we cannot accurately determine the momentum or the kinetic energy of the electron, as these values depend on the specifics of the conservation of energy and momentum in the collision process.

Learn more about Compton scattering here:

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