how was dance used in primitive cultures
A daredevil decides to jump a canyon of width 8.88 m. to do so, he drives a motorcycle up an incline sloped at an angle of 22.5 ◦ . the acceleration of gravity is 9.8 m/s 2 . what minimum speed must he have in order to clear the canyon? answer in units of m/s.
Final Answer:
The daredevil must have a minimum speed of approximately 14.7 m/s to clear the canyon.
Explanation:
To clear the canyon, the daredevil's vertical displacement at the edge of the canyon must be equal to the width of the canyon. Using the kinematic equation for vertical motion [tex]\( y = v_0t + \frac{1}{2}gt^2 \)[/tex], where y is the vertical displacement, [tex]\( v_0 \)[/tex] is the initial vertical velocity, g is the acceleration due to gravity, and t is the time of flight, and solving for [tex]\( v_0 \)[/tex], we get [tex]\( v_0 = \sqrt{2gy} \)[/tex]. Substituting the given values [tex]\( g = 9.8 \, \text{m/s}^2 \) and \( y = 8.88 \, \text{m} \)[/tex], we find [tex]\( v_0 \approx 14.7 \, \text{m/s} \)[/tex], which is the minimum speed required to clear the canyon.
Which of the following statements proves that scientific knowledge changed due to the discovery of the fossil of a hadrosaur in North Dakota?
Hadrosaurs were better runners than earlier thought.
Hadrosaurs had no pattern on their skin, which was not expected.
The length of the hadrosaur was shorter than previously thought.
The muscular structure of the hadrosaur was less developed than expected.
Sadi Carnot came up with a hypothetical heat engine that had the maximum possible efficiency. What discovery did Carnot make that helped him recognize how to create this "perfect" heat engine?
Answer:
The difference in the temperatures between the hot and cold reservoirs determined how well a heat engine would work
Explanation:
I got a 100% on my test
A can of sardines is made to move along an x axis from x = 0.47 m to x = 1.20 m by a force with a magnitude given by F = exp(–8x), with x in meters and F in newtons. (Here exp is the exponential function.) How much work is done on the can by the force?
Consider a father pushing a child on a playground merry-go-round. the system has a moment of inertia of 84.4 kg · m2. the father exerts a force on the merry-go-round perpendicular to its radius to achieve an angular acceleration of 4.44 rad/s2. (a) how long (in s) does it take the father to give the merry-go-round an angular velocity of 1.43 rad/s? (assume the merry-go-round is initially at rest.)
It takes 0.322 s to give the merry-go-round an angular velocity of 1.43 rad/s
[tex]\texttt{ }[/tex]
Further explanationCentripetal Acceleration can be formulated as follows:
[tex]\large {\boxed {a = \frac{ v^2 } { R } }[/tex]
a = Centripetal Acceleration ( m/s² )
v = Tangential Speed of Particle ( m/s )
R = Radius of Circular Motion ( m )
[tex]\texttt{ }[/tex]
Centripetal Force can be formulated as follows:
[tex]\large {\boxed {F = m \frac{ v^2 } { R } }[/tex]
F = Centripetal Force ( m/s² )
m = mass of Particle ( kg )
v = Tangential Speed of Particle ( m/s )
R = Radius of Circular Motion ( m )
Let us now tackle the problem !
[tex]\texttt{ }[/tex]
Given:
moment of inertia = I = 84.4 kg.m²
initial angular velocity = ωo = 0 rad/s
angular acceleration = α = 4.44 rad/s²
final angular velocity = ω = 1.43 rad/s
Asked:
time taken = t = ?
Solution:
[tex]\omega = \omega_o + \alpha t[/tex]
[tex]1.43 = 0 + 4.44t[/tex]
[tex]1.43 = 4.44t[/tex]
[tex]t = 1.43 \div 4.44[/tex]
[tex]t = 0.322 \texttt{ s}[/tex]
[tex]\texttt{ }[/tex]
Learn moreImpacts of Gravity : https://brainly.com/question/5330244Effect of Earth’s Gravity on Objects : https://brainly.com/question/8844454The Acceleration Due To Gravity : https://brainly.com/question/4189441[tex]\texttt{ }[/tex]
Answer detailsGrade: High School
Subject: Physics
Chapter: Circular Motion
[tex]\texttt{ }[/tex]
Keywords: Gravity , Unit , Magnitude , Attraction , Distance , Mass , Newton , Law , Gravitational , Constant
If 31.25
10
18
electrons are removed from a
neutral dielectric, how much charge is stored in
coulombs?
Answer:
it will become charged by Q = 5C
Explanation:
When electron is removed from matter then the system will get positively charged
So we will have
[tex]Q = Ne[/tex]
here N = number of electrons that is removed
[tex]N = 31.25 \times 10^{18}[/tex]
also we know that charge on one electron is given as
[tex]e = 1.6 \times 10^{-19}[/tex]
here we have
[tex]Q = Ne[/tex]
[tex]Q = (31.25 \times 10^{18})(1.6 \times 10^{-19})[/tex]
[tex]Q = 5 C[/tex]
so it will become charged by Q = 5C
which is NOT a "big idea" involving force and motion?
a) a force acting on an object in motion causes it to stop moving
b) a force acting on an object in motion causes it to change its motion
c) a force action on an object at rest causes it to move
Answer:a) a force acting on an object in motion causes it to stop moving
Explanation: gradpoint
Now assume that the stream flows east at 4.0 m/s. draw the vectors v⃗ w, representing the velocity of the stream, and v⃗ tot, representing the velocity of your rowboat relative to the stream bank. be sure to draw both vectors. draw v⃗ tot and v⃗ w starting at the tail and tip of v⃗ still respectively. the location, orientation and length of the vectors will be graded. each vector's length is displayed in meters per second.
Remember that the total velocity of the motion is the vector sum of the velocity you would have in still water and the stream. Always place the vectors carefully to be able to come up with an accurate sum vector.
what velocity does a 2kg mass have when its kinetic energy is 16 J
The velocity of a 2kg mass with a kinetic energy of 16 J is 4 m/s. This result is obtained by rearranging and plugging the given values into the kinetic energy formula.
Explanation:To find the velocity of a 2kg mass when its kinetic energy (KE) is 16 J, we can use the kinetic energy formula:
KE = (1/2)mv²
where:
m is the mass of the objectv is the velocity of the objectBy rearranging the formula to solve for v, we get:
v = √(2KE/m)
Substituting the given values:
v = √(2 × 16 J / 2 kg)
v = √(16 J / kg) = 4 m/s
So, the velocity of the 2kg mass when its kinetic energy is 16 J is 4 m/s.
The velocity of a 2 kg mass with 16 J of kinetic energy is 4 m/s, calculated using the kinetic energy formula KE = 0.5 * m * v² and solving for v.
Explanation:To find the velocity of a 2 kg mass when its kinetic energy is 16 J, we can use the kinetic energy formula:
KE = ½mv²
where:
KE is the kinetic energy,
m is the mass,
v is the velocity.
First, we can solve for v:
v = √(2KE/m)
Substitute the given values (KE = 16 J and m = 2 kg) into the formula:
v = √(2*16 J / 2 kg)
v = √(16 J/kg)
v = 4 m/s
Therefore, the velocity of the 2 kg mass is 4 m/s.
Find an expression for the acceleration a of the red block after it is released. use mr for the mass of the red block, mg for the mass of the gray block, and μk for the coefficient of kinetic friction between the table and the red block. express your answer in terms of mr, mg, μk, and g.
Assuming pulley is frictionless. Let the tension be ‘T’. See equation below.
The expression for the acceleration of the red block after it is released from the rest is
[tex]\fbox{\begin{minispace}\\{a = \dfrac{{\left( {{m_g} - \mu {m_r}} \right)g}}{\left( {{m_g} + {m_r}} \right)}}\end{minispace}}[/tex]
Further Explanation:
The friction force acting on the red block placed on the table is acting opposite to the direction of motion of block. The motion of the system, of red block and grey block, is vertically downward direction. It implies that the tension on the string is less than the weight on the grey block.
Given:
The mass of the red block is [tex]{m_r}[/tex].
The mass of the grey block is [tex]{m_g}[/tex].
The coefficient of friction between red block and table is [tex]\mu[/tex].
Concept:
The net force on the red block is acting along the direction of motion of the system and is equal to the difference between the tension in the string and friction force.
The net force on the red block is:
[tex]{m_r}a = T - f[/tex]
Rearrange the above expression.
[tex]T = {m_r}a + f[/tex]
Substitute [tex]\mu {m_r}g[/tex] for [tex]f[/tex] in above equation.
[tex]\fbox{\begin\\T = {m_r}a + \mu {m_r}g\end{minispace}}[/tex] …… (1)
Here, [tex]T[/tex] is the tension on the string, [tex]{m_r}[/tex] is the mass of the red block, [tex]a[/tex] is the acceleration of the system and [tex]g[/tex] is the acceleration due to gravity.
The net force on the grey block is along the direction of motion of the system and it is equal to the difference between the weight on grey block and tension on the string.
The net force on the grey block is:
[tex]{m_g}a = {m_g}g - T[/tex] …… (2)
Here, [tex]{m_g}[/tex] is the mass of the grey block.
Substitute [tex]{m_r}a + \mu {m_r}g[/tex] for [tex]T[/tex] in equation (2).
[tex]{m_g}a = {m_g}g - \left( {{m_r}a + \mu {m_r}g} \right)[/tex]
Rearrange the above expression.
[tex]{m_g}a + {m_r}a = {m_g}g - \mu {m_r}g[/tex]
Simplify the above expression.
[tex]\fbox{\begin{minispace}\\{a = \dfrac{{\left( {{m_g} - \mu {m_r}} \right)g}}{\left( {{m_g} + {m_r}} \right)}}\end{minispace}}[/tex]
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Answer Details:
Grade: College
Subject: Physics
Chapter: Kinematics
Keywords:
Acceleration, friction, tension, system of two blocks, pulley mass system, motion, net force, string, block placed on the table, block hanging through a pulley, block is released from rest.
all but which of the following might cause a tsunami? a. volcanic eruption b. flooding c. landslide d. earthquake
A 0.0075 kg bullet is traveling at a speed of 365 m/s. My coffee cup, when full, has a total mass of about 1.25 kg. How fast must I throw my full coffee cup in order to have the same momentum as the bullet?
Answer:
2.19 m/s
Explanation:
The momentum (p) is the product of the mass (m) and velocity (v) of an object.
p = m × v
The momentum of a 0.0075 kg bullet traveling at a speed of 365 m/s is:
p(bullet) = 0.0075 kg × 365 m/s = 2.74 kg.m/s
We want the 1.25 kg-coffee cup to have the same momentum than the bullet.
p(cup) = p(bullet) = 2.74 kg.m/s
p (cup) = m(cup) × v(cup)
2.74 kg.m/s = 1.25 kg × v(cup)
v(cup) = 2.19 m/s
i need a answer quick pleasee!!!!
Which of the following are correct statements about electrons
A. the valence shell is the furthest shell from the nucleus
B. there are four electrons in every electron shell
C. Electrons are in the nucleus of an atom
D. Electrons are located in layers around the nucleus
what do you think will happen to dirt and rocks on the Mountainside when the ice melts
Final answer:
When the ice on a mountainside melts, dirt and rocks that were held in place by the ice become unstable and may move downhill, altering the landscape. Saturated soil can cause mud flows and contribute to erosion. Glaciers also play a significant role in sculpting landscapes by carrying rock and sediment as they move.
Explanation:
When ice on a mountainside melts, the dirt and rocks that were previously held in place by the ice may become less stable. Erosion processes, such as water runoff and gravity, can lead to increased movement of these materials. As the water from the melting ice saturates the mountain's soil and rock, it can trigger debris flows or mud flows. These events have the potential to transport large amounts of material downslope, often resulting in significant changes to the landscape. The movement of this material can lead to the formation of new features, such as valleys or depressions, and can also contribute to the reshaping or smoothing of existing mountainous terrain.
It's also worth noting that glaciers, which are large bodies of ice that move slowly over land, have historically been powerful agents of erosion. As they advance and retreat, glaciers grind down rocks and carry sediment far from its origin, which is evidence of their strong impact on shaping the landscapes.
A force of 25 N acts on an object at an angle of 30 degrees above the horizontal. How much work does the force do if the object slides 3 m?
The force does 195 Joules of work on the object.
Explanation:To calculate the work done by a force, we use the formula:
Work = Force x Distance x cos(theta)
Given that the force is 25 N, the angle is 30 degrees, and the distance is 3 m, we can substitute these values into the formula to calculate the work:
Work = 25 N x 3 m x cos(30 degrees) = 195 J
Therefore, the force does 195 Joules of work on the object.
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A girl delivering newspapers travels one block west then three blocks north then five blocks east. what is her resultant displacement?
A satellite, moving in an elliptical orbit, is 360 km above earth's surface at its farthest point and 180 km above at its closest point. calculate (a) the semimajor axis and (b) the eccentricity of the orbit.
The semimajor axis is equal to 270 Km. The eccentricity of the orbit is 0.33 Km.
What is an elliptical orbit?An elliptic orbit or elliptical orbit can be described as a Kepler orbit with an eccentricity of less than 1. It is a circular orbit with an eccentricity equal to 0. It is a Kepler orbit with an eccentricity greater than 0 and less than 1 and a Kepler's orbit with negative energy. The radial elliptic orbit has an eccentricity equal to 1.
Given the satellite, moving in an elliptical orbit has the farthest point from the above earth's surface, [tex]R_a[/tex] = 360 Km
The closest point from the above earth's surface, [tex]R_p[/tex] = 180 Km
Semi-major axis can be calculated as , [tex]{\displaystyle a = \frac{R_a+R_p}{2}[/tex]
[tex]{\displaystyle a = \frac{360 + 180}{2}[/tex]
a = 270 km
The eccentricity of the elliptical orbit, we can calculate as shown below:
[tex]{\displaystyle e = \frac{a- R_p}{a}[/tex]
e = (270 - 180)/270
e = 1/3
e = 0.33 km
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While driving your car on a level road at 60.0 mph, the traffic ahead of you comes to a sudden stop. you apply your brakes in a panic, causing them to lock. your car skids for 57.0 m before hitting the car in front of you. if µk = 0.550 for your tires on the road, find the speed of your car as it collides with the other car?
First let us calculate the acceleration of the car.
The net force is equivalent to the frictional force:
m a = µk m g
a = µk g
a = 0.550 * 9.8 m/s^2
a = 5.39 m/s^2 (negative direction) = -5.39 m/s^2
Then we use the equation:
v^2 = vi^2 + 2 a d
where v is final speed or velocity, vi is initial speed = 60 mph = 26.8224 m/s, d is distance
v^2 = (26.8224 m/s)^2 + 2 (-5.39 m/s^2) * 57 m
v^2 = 104.98 m^2/s^2
v = 10.25 m/s (ANSWER)
Which positive result could develop if carbon dioxide increases in the atmosphere? A. People breathe carbon dioxide, so Earth could support more human life. B. Plants give off carbon dioxide, so an increase in plant life could decrease world hunger. C. Carbon dioxide will protect people from the sun's radiation. D. Carbon dioxide will create more sunny weather, which is good for plant growth.
A girl stands on a sofa. identify the number of the action/reaction pairs of forces between the girl and the sofa.
Final answer:
There are at least two fundamental action-reaction pairs of forces when a girl stands on a sofa, including the force of gravity and the normal force, as well as any frictional forces if there is lateral movement.
Explanation:
Action-Reaction Pairs
In the scenario where a girl stands on a sofa, there are several action-reaction pairs of forces at play. According to Newton's third law, every action has an equal and opposite reaction. When the girl exerts a force on the sofa (due to her weight), the sofa exerts an equal and opposite force back onto the girl. This is one pair. Additionally, if the girl were to push on the sofa to stand up or adjust her position, the sofa would push back with an equal force in the opposite direction, forming another action-reaction pair.
The number of action-reaction pairs can vary based on what specific interactions are being considered. Generally, in this scenario, we consider at least two fundamental pairs: the force of gravity on the girl (action) and the normal force from the sofa on the girl (reaction), and if there's any lateral movement while standing, there would be a frictional force between the sofa and the girl's feet (action), and an equal and opposite frictional force from the girl's feet on the sofa (reaction).
PLZZZZ I NEED HELP ASAP!!!!
Would Wegener have been more or less successful in convincing scientists today than he was when he proposed his ideas? Why or why not?
Which of the following would most likely result in a flash flood?
An ice storm
Melting snow on a plain
Excess precipitation in one location
A tornado with speeds of 110 km/h
A force of 660 n stretches a certain spring a distance of 0.300 m. what is the potential energy of the spring when a 70.0 kg mass hangs vertically from it?
Calculate the inductance of a coil that induces 120v when the current through it changes at a rate of 5a/s. calculate the inductance of a coil that in
A sphere mass m1 and a block of mass m2 are connected by a light cord that passes over a pulley. The radius of the pulley is R, and the mass of the thin rim is M.. The block slides on a frictionless, horizontal surface.
Derive an expression for the linear acceleration of the two objects
The expression for the linear expression of the two objects will be
[tex]a=\dfrac{m_1g}{m_2+m_1-M}[/tex]
What is acceleration?Acceleration is defined as the change of the velocity with the time. Acceleration is a vector quantity and is defined by both the magnitude and the direction.
The mass of sphere is m1 radius is R and mass m2 is connected by light chord.
Now by using free body diagram
The tension in the chord will be
[tex]m_1g-T_1=m_1a[/tex]
[tex]T_1=m_1(g-a)[/tex]
For tension T2 we will have
[tex]T_2=m_2a[/tex]
Now the torque will be
[tex]T_{net}=I\alpha[/tex]
[tex]T_2R-T_1R=I(\dfrac{a}{R})[/tex]
[tex]T_2R-T_1R=MR^2(\dfrac{a}{R})[/tex]
[tex]T_2-T_1=Ma[/tex]
[tex]m_2a-m_1(g-a)=Ma[/tex]
[tex]m_2a-m_1g+m_1a=Ma[/tex]
[tex]a(m_2+m_1-M)=m_1g[/tex]
[tex]a=\dfrac{m_1g}{m_2+m_1-M}[/tex]
Thus the expression for the linear expression of the two objects will be
[tex]a=\dfrac{m_1g}{m_2+m_1-M}[/tex]
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Two objects are moving at equal speed along a level, frictionless surface. the second object has twice the mass of the first object. they both slide up the same frictionless inclined plane. which object rises to a greater height?
Final answer:
Despite their different masses, two objects with equal speeds moving on a frictionless incline reach the same height because mechanical energy is conserved and potential energy at a given height is not dependent on mass.
Explanation:
In a scenario where two objects with different masses but equal speeds slide up a frictionless incline, the laws of physics tell us that both objects should reach an equivalent height. This is because the mechanical energy (kinetic plus potential energy) in a closed system without any external forces (like friction) is conserved. Since both objects start with the same kinetic energy (due to equal speeds) and potential energy is directly related to height (not mass), they should convert their kinetic energy into the same amount of potential energy, meaning they should rise to the same height before coming to a stop and sliding back down.
It's important to note that if there were friction or some other external force acting on the objects, the outcomes could be different as the mechanical energy would no longer be conserved in the same way, but in a frictionless situation, mass does not affect the height an object reaches if it starts with the same kinetic energy.
Manny walked a total of 3 miles. The reference point used to calculate the total distance that he walked was the same as the ending point. Which describes where Manny most likely walked? from the bottom of a hill to the top on a circular nature trail on a sidewalk from his house to the mall from the beginning of a straight track to the end
As per the statement, Manny walks about 3 miles and the reference point for calculating the distance is the same as the starting point.
Thus manny walked on a circular nature trail. As the starting point is equal to the ending point and the bottom of the hill is a reference point and the top. So manny is in a circular pathway.Hence the option B is correct.
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What is the minimum work needed to push a 950-kg car 710 m up along a 9.0° incline? ignore friction?
Answer:
Work done, [tex]W=1.03\times 10^6\ J[/tex]
Explanation:
It is given that,
Mass of the car, m = 950 kg
Distance up to the incline, d = 710 m
Angle of inclination of the car is 9 degrees.
When the car is push in the inclined path, the vertical component of the force will act on it such that the work done is given by :
[tex]W=mg\ sin\theta\times d[/tex]
[tex]W=950\times 9.8\times \ sin(9) \times 710[/tex]
[tex]W=1.03\times 10^6\ J[/tex]
So, the minimum work needed to push a car is [tex]1.03\times 10^6\ J[/tex]. Hence, this is the required solution.
The minimum work needed to push a car up an incline can be found by calculating the work done against gravity. This is done by multiplying the mass of the car by the gravitational acceleration and the height, which can be deduced from the sin of the incline angle and the distance.
Explanation:The question is asking for the minimum work done to push a car up an inclined plane. To solve this, you use the concept of work done against gravity. The formula for work done against gravity is Work = m * g * h, where m is the mass, g is the gravitational acceleration and h is the height. Since the distance and incline angle are provided, we can calculate the height with the trigonometric function sine, h = sin(angle) * distance. Substituting these values, we get Work = 950kg * 9.81m/s² * sin(9.0°) * 710m. The required calculation will then provide the answer to the work done in pushing the car up the incline.
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WHO EVER THAT CAN ANSWER THIS GETS 17 POINTS
1. Research how cars or planes have been designed to have less mass.
2. How is the balance between
strength and mass resolved when
designing cars or planes?
To make cars and airplanes lighter, engineers use materials with high strength-to-weight ratios and apply aerodynamic principles to reduce drag. The balance of strength versus mass is resolved through materials selection and careful design optimization, including computer simulations and wind tunnel tests to create vehicles that are strong, lightweight, and efficient.
When designing cars or airplanes, the challenge is to reduce the mass of the vehicle while maintaining structural integrity. One way to achieve a lighter car is to incorporate plastics instead of metal in parts of its construction. For airplanes, advanced composite materials such as carbon fiber are often used because of their strength-to-weight ratios. Aerodynamics play a critical role in this process, as reducing drag through aerodynamic shaping can not only decrease fuel consumption but also reduce the required structural mass.
The balance between strength and mass is resolved through the use of advanced materials and design strategies. Modern design approaches involve analyzing aerodynamic forces and optimizing the shape and structures to endure these forces. With the help of computer simulations and wind tunnel testing, engineers can fine-tune designs to achieve the desired balance. The selection of materials follows a criterion that ensures they are lightweight yet able to withstand the high stresses experienced during operation. Often, the design includes failsafes that account for the worst expected loads.
Ultimately, the goal is to meet specific design objectives that include performance metrics like range, payload capacity, and fuel efficiency. Designers look at comparator aircraft or vehicles and use their data as references for optimizing wing loading, thrust-to-weight ratio, and other design parameters. Thus, the optimal design is often a trade-off between various competing factors including mass, strength, and aerodynamic efficiency.