Why did the scientist make an exact duplicate of himself

Answers

Answer 1

This is a math riddle in which you can only discover the answer by cracking the given equations and each answer has the corresponding letters. Nonetheless, the solution to this is the scientist created an exact duplicate of himself because HE WAS JUST CLONING AROUND

Answer 2

Answer:

he was just cloning around!

Step-by-step explanation:

it's a riddle :)

Related Questions

pls I help I need answers and work shown

Answers

0.30 as a fraction is 30/100 = 3/10

0.30 as a percent = 0.30 * 100 = 30%

answer is D. 3/10 and 30%

.30 is .3

do .30 divided by 1 and you get 3/10

Percentage= move the decimal 2 places to the right and you get 30%

So your answer is D.

Between two tenths of a mile will the second relay exchange occur? Explain.

Answers

yes it will occur because two tenths of a mile the second relay will exchange

2/10

There is one tenth in a mile. I have the same question. But I am just guessing.

There are six different sixth roots of 64. That is, there are six complex numbers that solve x^6=64

Please help

Answers

There are two possible solutions:

1)
When we know that:

[tex]\sqrt[n]{z}=\sqrt[n]{|z|}\Big(\cos\frac{\phi+2k\pi}{n}+i\sin\frac{\phi+2k\pi}{n}\Big)\qquad\text{for}\quad k=0,1,\ldots,n-1[/tex]

when [tex]z=|z|(\cos\phi+i\sin\phi)[/tex]

then:

[tex]x^6=64\quad|\sqrt[6]{(\ldots)}\\\\x=\sqrt[6]{64}[/tex]

For [tex]x=64[/tex] we have:

[tex]64=|64|(\cos0+i\sin0)\quad\Rightarrow\quad \phi=0[/tex]

and:

[tex]\sqrt[6]{64}=\sqrt[6]{64}\Big(\cos\frac{0+2k\pi}{6}+i\sin\frac{0+2k\pi}{6}\Big)\qquad\text{for}\quad k=0,1,\ldots,5\\\\\\ \sqrt[6]{64}=2\Big(\cos\frac{k\pi}{3}+i\sin\frac{k\pi}{3}\Big)\qquad\text{for}\quad k=0,1,\ldots,5 [/tex]

k = 0

[tex]2\Big(\cos\frac{0}{3}+i\sin\frac{0}{3}\Big)=2(1+0i)=2\cdot1=\boxed{2}[/tex]

k = 1

[tex]2\Big(\cos\frac{\pi}{3}+i\sin\frac{\pi}{3}\Big)=2\Big(\frac{1}{2}+i\frac{\sqrt{3}}{2}\Big)=\boxed{1+i\sqrt{3}}[/tex]

k = 2

[tex]2\Big(\cos\frac{2\pi}{3}+i\sin\frac{2\pi}{3}\Big)=2\Big(-\frac{1}{2}+i\frac{\sqrt{3}}{2}\Big)=\boxed{-1+i\sqrt{3}}[/tex]

k = 3

[tex]2\Big(\cos\frac{3\pi}{3}+i\sin\frac{3\pi}{3}\Big)=2\Big(\cos\pi+i\sin\pi\Big)=2(-1+0i)=\boxed{-2}[/tex]

k = 4

[tex]2\Big(\cos\frac{4\pi}{3}+i\sin\frac{4\pi}{3}\Big)=2\Big(-\frac{1}{2}-i\frac{\sqrt{3}}{2}\Big)=\boxed{-1-i\sqrt{3}}[/tex]

k = 5

[tex]2\Big(\cos\frac{5\pi}{3}+i\sin\frac{5\pi}{3}\Big)=2\Big(\frac{1}{2}-i\frac{\sqrt{3}}{2}\Big)=\boxed{1-i\sqrt{3}}[/tex]

So the answer is:

[tex]x=\{2,\,1+i\sqrt{3},\,-1+i\sqrt{3},\,-2,\,-1-i\sqrt{3},\,1-i\sqrt{3}\}[/tex]

2)
We don't know method (1). If so, we could use following identities:

[tex](1)\quad a^2-b^2=(a+b)(a-b)\\\\(2)\quad a^3-b^3=(a-b)(a^2+ab+b^2)\\\\(3)\quad a^3+b^3=(a+b)(a^2-ab+b^2)[/tex]

There will be:

[tex]x^6=64\\\\x^6-64=0\\\\(x^3)^2-8^2=0 \qquad\text{from (1)}\\\\(x^3+8)(x^3-8)=0\\\\(x^3+2^3)(x^3-2^3)=0\qquad\text{from (2) and (3)}\\\\ (x+2)(x^2-2x+4)(x-2)(x^2+2x+4)=0\qquad(\star)[/tex]

Now, we complete the square for:

[tex]x^2-2x+4=x^2-2x+1+3=(x^2-2x+1)+3=(x-1)^2+3=\\\\=(x-1)^2+(\sqrt{3})^2=(x-1)^2-(-1)(\sqrt{3})^2=(x-1)^2-i^2(\sqrt{3})^2=\\\\=(x-1)^2-(i\sqrt{3})^2=\text{from (1)}=\boxed{(x-1-i\sqrt{3})(x-1+i\sqrt{3})}[/tex]

and for:

[tex]x^2+2x+4=x^2-2x+1+3=(x^2+2x+1)+3=(x+1)^2+3=\\\\=(x+1)^2+(\sqrt{3})^2=(x+1)^2-(-1)(\sqrt{3})^2=(x+1)^2-i^2(\sqrt{3})^2=\\\\=(x+1)^2-(i\sqrt{3})^2=\text{from (1)}=\boxed{(x+1-i\sqrt{3})(x+1+i\sqrt{3})}[/tex]

When we return to [tex](\star)[/tex]:

[tex](x+2)(x^2-2x+4)(x-2)(x^2+2x+4)=0\\\\(x+2)(x-1-i\sqrt{3})(x-1+i\sqrt{3})(x-2)(x+1-i\sqrt{3})(x+1+i\sqrt{3})=\\=0[/tex]

And we have answer:

[tex]x=\{-2,\,1+i\sqrt{3},\,1-i\sqrt{3},\,2,\,-1+i\sqrt{3},\,-1-i\sqrt{3}\} [/tex]

To find the six sixth roots of 64, you can use polar form and De Moivre's Theorem to calculate the complex numbers. The roots are 2, 1+i√3, -1+i√3, -2, -1-i√3, and 1-i√3.

[tex]X^6 = 64[/tex]

The sixth roots of 64 are complex numbers and can be found by writing 64 in polar form and applying De Moivre's Theorem. Let's find the six roots:

First root: 2(cos(0) + i sin(0)) = 2

Second root: 2(cos(π/3) + i sin(π/3)) = 2(1/2 + i√3/2) = 1 + i√3

Third root: 2(cos(2π/3) + i sin(2π/3)) = 2(-1/2 + i√3/2) = -1 + i√3

Fourth root: -2

Fifth root: -2(cos(-π/3) + i sin(-π/3)) = -2(1/2 - i√3/2) = -1 - i√3

Sixth root: -2(cos(-2π/3) + i sin(-2π/3)) = -2(-1/2 - i√3/2) = 1 - i√3

Find the point p where the line x = 1 + t, y = 2t, z = -3t intersects the plane x + y - z = -4.

Answers

[tex]\begin{cases}x=1+t\\y=2t\\z=-3t\end{cases}\implies x+y-z=(1+t)+2t-(-3t)=-4[/tex]
[tex]\implies6t+1=-4\implies t=\dfrac12[/tex]

[tex]\implies p=(x,y,z)=(1+t,2t,-3t)\implies p=\left(\dfrac32,1,-\dfrac32\right)[/tex]

Final answer:

The point of intersection between the given line and plane is (1/6, -5/3, 5/2). This is determined by substituting the parametric line equations into the plane equation, simplifying to find the value of the parameter t, and substituting that value back into the line equations.

Explanation:

The given line and plane equations are, x = 1 + t, y = 2t, z = -3t and x + y - z = -4 respectively. To find where the line intersects the plane, we need to substitute the parametric line equations into the plane equation.

Step by Step Solution

Step 1: Substitute x, y, and z from the line equation into the plane equation, giving you (1+t) + 2t - (-3t) = -4.
Step 2: Simplify the equation to find the value of t. You get 6t + 1 = -4, so t = -5/6.
Step 3: Substitute t = -5/6 into the line equations to find x = 1/6, y = -5/3, and z = 5/2.

So, the point P where the line intersects the plane is (1/6, -5/3, 5/2).

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Simplify the expression 3 1/3/3 1/3. Explain how the expression and its simplified form show that the set of irrational numbers is not closed under division

Answers

The expression given is ambiguous according to the standard rules of math (PEMDAS) due to the lack of appropriate parentheses and probably the exponentiation symbol ^.

From the context, I assume it to mean
(3^(1/3)) / (3^(1/3)) = 1

Since 3^(1/3) is the cube-root of 3, and is thus irrational.
However, the quotient is exactly 1, which is a rational number.

The example is therefore a counter-example for the statement that "set of irrational numbers is closed under division", or stated differently,
"the set of irrational numbers is not closed under division"

What is the value of x?

6 + 8x
-------------- = 5x
2

A) -2
B) -1
C) 1/3
D) 3

Answers

The ans is choice D. since there nothing under 5x, imagine there is a 1 under. After that, you can simply cross multiply, so it would be 1(6+8x)= 2(5x). 6+8x= 10x now combine like terms so subtract 8x from both sides and divide 6 by 2 and you will get 3

I just took the test the answer is D.3

one positive integer is 5 less than another. the product of the two integers is 36. what are the integers?

Answers

let the numbers be x and (x-5)

x(x-5)=36

x^2-5x-36=0

solving the equation we get

x=9 and x= -4

now find out the integers

1st number = x

2nd number = x-5

x*(x-5) = 36

x^2-5x =36

x^2 -5x-36 = 0

factor the polynomial:

(x-9) (x+4)

9-9 = 0, -4 +4 = 0

so x = 9 or -4

the question states a positive number

so x = 9

the 2 numbers are 9 and 4

Which of the following equations is of a parabola with a vertex at (0, 3)?

y = (x - 3) 2
y = (x + 3) 2
y = x 2 - 3
y = x 2 + 3

Answers

The formula for a parabola is (y-k)=(x-h)^2, or y = (x-h)^2 + k, where (h,k) is the vertex. If h=0 and k=3, then the parabola would be y = x^2 + 3

Answer:

Option D.

Step-by-step explanation:

We have to find the equation of the parabola which has vertex at ( 0,3 )

If we write the equation of a parabola in the vertex from then we will write

y = ( x - h )² + (k)²

In this equation ( h, k) will be the vertex.

(a) y = (x-3)² + 0

so ( 3,0) will be the vertex

(b) y = ( x+3)² + 0

or y = [x - (-3)]² + 0

then ( -3,0) will be the vertex

y = ( x-0 )² + (-3)

then ( 0, -3) is the vertex.

(d) y = x² + 3

y = ( x-0 )² + 3

Then ( 0, 3 ) will be the vertex of this parabola.

Option D. is the answer.

Use the function below to find f(4).

Answers

f(x) = 1/3 * 4^x.......f(4)....so we sub in 4 for x
f(4) = 1/3 * 4^4
f(4) = 1/3 * 256
f(4) = 256/3 <===

Answer: The correct option is (C) [tex]\dfrac{256}{3}.[/tex]

Step-by-step explanation: The given function is

[tex]f(x)=\dfrac{1}{3}\times 4^x.[/tex]

We are to find the value of f(4).

To find the value of f(4), we need to substitute the value of x as 4 in the given definition of function f(x).

Substituting x = 4 in f(x), we have

[tex]f(4)=\dfrac{1}{3}\times 4^4=\dfrac{1}{3}\times 256=\dfrac{256}{3}.[/tex]

Therefore, the value of f(4) is [tex]\dfrac{256}{3}.[/tex]

Option (C) is correct.

I have 5 digits. My 4s are worth 4 [10,000s] and 4 * 10. One of my 3s is worth 3,000. The other is worth 1/10 as much. My other digit is a 2. What number am I?

Answers

The given information are actually the digits and their place values in multiples of 10. To know the identity of the number, simply multiply the digit with its place value. The solution is as follows:

4(10,000) + 4(10) + 3,000 + 3,000(1/10) + 2 = 43,342

Thus, the 5-digit number is 43,342.

There are 60 minutes in 1 hour. What fraction of an hour is 4 minutes? Write your answer in lowest terms.

Answers

4 minutes/60 minutes

Divide the numerator and denominator by 4
1/15

Final answer: 1/15

The fraction of an hour is 4 minutes in lowest terms is 1/15.

What fraction of an hour is 4 minutes in lowest terms?

To find the fraction of an hour that 4 minutes represents, we need to compare the number of minutes to the total number of minutes in an hour, which is 60.

We can set up a fraction where the numerator represents the number of minutes we want to find the fraction for (4 minutes) and the denominator represents the total number of minutes in an hour (60 minutes).

So, the fraction can be written as 4/60.

To simplify the fraction to its lowest terms, we can divide both the numerator and the denominator by their greatest common divisor (GCD). In this case, the GCD of 4 and 60 is 4.

Dividing both the numerator and denominator by 4, we get:

4/60 = (4 ÷ 4) / (60 ÷ 4) = 1/15.

Therefore, 4 minutes in lowest terms is equal to 1/15th of an hour.

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Express each repeating decimal as a fraction.

1.
1.8[4]

2.
2.1[26]

Answers

Hello,

1.8444444....=1.8+1/10*0.44444....
=1.8+1/10*4/9
=1.8+4/90
=162/90+4/90
=166/90
=83/45

2.126262626...=2.1+1/10*0.262626...
=2.1+1/10*26/99
=2.1+26/990
=2079/990+26/990
=2105/990
=421/198

Answer:

1.8444444....=1.8+1/10*0.44444....

=1.8+1/10*4/9

=1.8+4/90

=162/90+4/90

=166/90

=83/45

2.126262626...=2.1+1/10*0.262626...

=2.1+1/10*26/99

=2.1+26/990

=2079/990+26/990

=2105/990

=421/198

The following formula relates three quantities force mass and acccelerations
F=ma

Answers

True. Dissect "F=ma" and you'll get "Force," "mass" and "acceleration."

How many pairs of whole numbers have a sum of 99

Answers

does anyone know lol

44 pairs. I believe that's the right answer.

complete the steps to solve the inequality 0.2 (x+20)-3>-7-6.2x

Answers

The answer should be 0.2x+4>1.2x

0.2x+4-3>-7-6.2x

0.2x+1>-7-6.2x

0.2x+0.6x>-8

0.8x>-8

the correct answer is: x>-1.25

Marcus walked 5 km due east and then he turned around and walk 5 km to West how many kilometers is Marcus now from his starting point

Answers

N
I
I
W------------------E
I
I
S o km

which
of the following is the least?
A.0.105
B.0.501
c.o.015
D.0.15

Answers

Is C 0.015? If so, then C, because if you imagine all of the numbers to the right as whole numbers, you get, in order from least to greatest, c, a, d, b. C is the answer.

You want to replace the countertops in a kitchen. One counter measures 24 inches by 6 feet. The other is 30 inches by 4 feet. If the new countertop costs $42.00 per square foot, what will be the cost of the new top?

Answers

First, multiply to find the total square footage of the counter.

2 ft x 6 ft=12 square feet
2.5 ft x 4 ft=10 square feet
Total square feet of the counter is 22 square feet.

To find the total cost, just multiply the area by the cost per square foot.
$42 x 22=$924

Answer:

The cost of the new top $924.

Step-by-step explanation:

You want to replace the counter-tops in a kitchen.

The dimensions of the first counter is 24 inches by 6 feet.

i.e [tex]24 \text{ inch} \times 6 \text{ feet}[/tex]

or [tex]2\text{ feet} \times 6 \text{ feet}[/tex]

As 1 feet =12 inches

Hence the area of the counter is [tex]2\times 6=12\text{ feet}^2[/tex]

The dimensions of the second counter is 30 inches by 4 feet.

i.e [tex]30 \text{ inch} \times 4 \text{ feet}[/tex]

or [tex]2.5\text{ feet} \times 4 \text{ feet}[/tex]

Hence the area of the counter is [tex]2.5\times 4=10\text{ feet}^2[/tex]

Hence, the total area will be [tex]12+10=22 \text{ feet}^2[/tex]

The unit cost of the counter-top is [tex]\$42.00\text{ feet}^2[/tex]

So the net cost will be,

[tex]=42\times 22=\$924[/tex]

Rational numbers are _____ natural numbers.

always
sometimes
never

Answers

Rational numbers are sometimes natural numbers.

Sometimes is the answer meh dude

A picture frame has a total perimeter P of 5 meters. The height of the frame is
2/3 times its width.

Answers

2/3x+x=2.5
H should equal 1 and the width is 1.5

The height of the frame is 1.5 meters.

The Width of the frame is 1 meter.

What is the perimeter of the rectangle?

The perimeter of a rectangle is defined as the addition of the lengths of the rectangle's four sides.

The perimeter of a rectangle = 2(L+W)

Where W is the width of the rectangle and L is the length of the rectangle

Given that,

P = 5 meters

w = 2/3h = 0.67h

We have to determine the height of the frame.

The perimeter of the frame = 2h + 2W

We know all the other values So we can plug in values to solve for h:

5 = 2h + 2(.67h)

5 = 2h+ 1.33h

5 = 3.33h

5/3.33 = h

h = 1.5

So the height of the frame is 1.5 meters

We need to find the width and we know that W = 0.67h

W = 0.67(1.5)

W = 1

So the Width of the frame is 1 meter.

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write 4 hundred-thousand, 13 thousand, 11 hundreds, 4 ones in standard form

Answers

The correct answer would be 400,000+13,000+1,100+4=414,104.

The standard form of the expression 4 hundred-thousand, 13 thousand, 11 hundreds, 4 ones is [tex]4.14104 \times10^5[/tex]

In order to write 4 hundred-thousand, 13 thousand, 11 hundreds, 4 ones in standard form, let us write each of the expressions in figures

4 hundred-thousand = 400,000

13 thousand = 13,000

11 hundreds = 11 x 100

11 hundreds = 1100

4 ones = 4 x 1

4 ones = 4

The next step is to sum up all the figures together

400000 + 13000 + 1100 + 4 = 414,104

Convert 414104 to standard form

[tex]414104 = 4.14104 \times10^5[/tex]

Therefore, the standard form of the expression 4 hundred-thousand, 13 thousand, 11 hundreds, 4 ones is [tex]4.14104 \times10^5[/tex]

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Express the area of each square below as a monomial
14g5h9

Answers

Assuming the side of the square is 14 g^5 h^9, its area as [14 g^5 h^9] ^2.

So, the resulting expression is found using the properties of the power.

=> (14)^2 (g^5)^2 (h^9)^2 = 196 g^10 h^18.

Answer: 196 g^10 h^18

Find the range of the graphed function?

Answers

for finding range pay attention to y axis max of function is 5 and its min is -9
B is true

B is the correct answer

if f(x)=x/2-2 and g(x)=2x^2+x-3, find (f+g)(x)

Answers

hello :
If f(x)=x/2-2 and g(x)=2x^2+x-3, find (f+g)(x)
(f+g)(x)= f(x) +g(x) = x/2-2 +2x²+x-3 = x/2 +2x²+x-5
(f+g)(x)= (x+4x²-2x-10) /2
(f+g)(x)= (4x²+3x-10)/2 = 2x²+3/2 x -5

Answer:

B. [tex]2x^2+\frac{3x}{2}-5[/tex]

Step-by-step explanation:

Given functions,

[tex]f(x)=\frac{x}{2}-2[/tex]

[tex]g(x)=2x^2+x-3[/tex]

Since, (f+g)(x) = f(x) + g(x)

[tex]=\frac{x}{2}-2+2x^2+x-3[/tex]

[tex]=2x^2+\frac{x+2x}{2}-5[/tex] ( combine like terms )

[tex]=2x^2+\frac{3x}{2}-5[/tex]

Option 'B' is correct.

Kate have 110 bows. 10 bows fit in a bag. how many bags can she fill

Answers

Final answer:

By dividing the total number of bows (110) by the number of bows that fit in one bag (10), we find that Kate can fill 11 bags with her bows.

Explanation:

To find out how many bags Kate can fill with her bows, we need to divide the total number of bows by the number of bows that fit in one bag. In this case, Kate has 110 bows and 10 bows fit in one bag.

So, we divide 110 by 10: 110 / 10 = 11

Therefore, Kate can fill 11 bags with her 110 bows.

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Kate can fill 11 bags with her 110 bows.

Given:

Kate has 110 bows

No. of bows fit in the bag = 10

No. of bags she can fill:

110 bows ÷ 10 bows per bag

= [tex]\frac{110}{10}[/tex]

= 11 bags.

So, Kate can fill 11 bags with her 110 bows.

Find the equation in standard form of the line with slope
[tex] \frac{7}{2} [/tex] that passes through the point (5,7)
Please explain as well

Answers

[tex]\bf \begin{array}{lllll} &x_1&y_1\\ % (a,b) &({{ 5}}\quad ,&{{ 7}}) \end{array} \\\\\\ % slope = m slope = {{ m}}= \cfrac{rise}{run} \implies \cfrac{7}{2} \\\\\\ % point-slope intercept \stackrel{\textit{point-slope form}}{y-{{ y_1}}={{ m}}(x-{{ x_1}})}\implies y-7=\cfrac{7}{2}(x-5)\implies y-7=\cfrac{7}{2}x-\cfrac{35}{2} \\\\\\ y=\cfrac{7}{2}x-\cfrac{35}{2}+7\implies \stackrel{standard~form}{-\cfrac{7}{2}x+y=-\cfrac{21}{2}}[/tex]

Distributive property of 68/4

Answers

Start with 68/4. Rewrite 68 as (4)(17)/4. Cancel the 4s. Result: 17.

The trick here is to rewrite 68 as 4(17).

solve 5.3×0.5 and show work

Answers

5.3 * 0.5 = 2.65
5.3/2=2.65

Here is the five-number summary for a group of 100 runners in a 5-kilometer race. the variable is the time to complete the race. five-number summary: minimum: 15 minutes q1: 27 minutes median: 31 minutes q3: 32 minutes maximum: 50 minutes are there any outliers in the runners’ finish times by the 1.5 * iqr definition?

Answers

Final answer:

The interquartile range (IQR) is 5 minutes. Any values below 19.5 minutes or above 39.5 minutes would be considered outliers. In this data set, both the minimum time of 15 minutes and the maximum time of 50 minutes are outliers.

Explanation:

The question is whether there are any outliers in the finish times of a group of runners based on the IQR definition. To determine this, we first calculate the interquartile range (IQR), which is the range of the middle 50 percent of the data. Q1 = 32 min - 2 For this data set, we calculate the IQR by subtracting the first quartile (Q1) from the third quartile (Q3). Here, IQR = Q3 - 7 min = 5 min.

Next, we multiply the IQR by 1.5, which is our test for outliers. This gives 1.5 * IQR = 1.5 * 5 min = 7.5 min.

An outlier is defined as a data point that is below Q1 - 1.5 * IQR or above Q3 + 1.5 * IQR. So, any time less than 27 min - 7.5 min = 19.5 min or greater than 32 min + 7.5 min = 39.5 min would be considered an outlier.

Given the five-number summary: min=15 min, Q1=27 min, median=31 min, Q3=32 min, max=50 min, we can clearly see that the minimum time of 15 min is an outlier because it's less than 19.5 min. Also, the maximum time of 50 min is an outlier because it's greater than 39.5 min.

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The minimum time is 15 minutes and below the lower bound of 19.5 minutes, there is at least one outlier in the given data set.

To determine if there are any outliers using the 1.5 * IQR (interquartile range) definition, we need to calculate the IQR first. The IQR is the difference between the third quartile (Q3) and the first quartile (Q1).

Given:

- Q1 = 27 minutes

- Q3 = 32 minutes

We can calculate the IQR as follows:

[tex]\[ IQR = Q3 - Q1 = 32 - 27 = 5 \text{ minutes} \][/tex]

Now, we can use the 1.5 * IQR rule to find the lower and upper bounds for potential outliers:

Lower Bound: Q1 - 1.5 * IQR

Upper Bound: Q3 + 1.5 * IQR

[tex]\[ \text{Lower Bound} = 27 - 1.5 \times 5 = 27 - 7.5 = 19.5 \text{ minutes} \]\[ \text{Upper Bound} = 32 + 1.5 \times 5 = 32 + 7.5 = 39.5 \text{ minutes} \][/tex]

Any finish times below 19.5 minutes or above 39.5 minutes would be considered potential outliers according to the 1.5 * IQR rule.

Since the minimum time is 15 minutes and below the lower bound of 19.5 minutes, there is at least one outlier in the data set.

domain of the function

Answers

hello :
y exist : x+6 ≥ 0
x ≥ -6

Other Questions

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