Final answer:
To find the magnitude and direction of the fourth displacement, we can use vector components. We need to add up the north and east components of the three given displacements, and then find the fourth displacement that brings the sum back to the starting point.
Explanation:
To find the magnitude and direction of the fourth displacement, we can use vector components. We need to add up the north and east components of the three given displacements, and then find the fourth displacement that brings the sum back to the starting point. Let's break down the given displacements:
West, 190m45.0° east of south, 210m30.0° east of north, 270mFirst, let's convert the given angles to north and east components:
West, 190m --- North: 0m, East: -190m45.0° east of south, 210m --- North: -210sin(45°), East: -210cos(45°)30.0° east of north, 270m --- North: 270sin(30°), East: -270cos(30°)Now we can add up the north and east components:
North component: 0 + (-210sin(45°)) + 270sin(30°)
East component: -190 + (-210cos(45°)) + (-270cos(30°))
Finally, we can use these components to find the magnitude and direction of the fourth displacement using the Pythagorean theorem and trigonometry.
Final answer:
The magnitude and direction of the fourth displacement, use vector components to represent each displacement as a vector and add them together. Then subtract the vector sum from the starting point to find the magnitude and direction of the fourth displacement.
Explanation:
To find the magnitude and direction of the fourth displacement in the given scenario, we can use vector components. We start by representing each displacement as a vector with its magnitude and direction. The first displacement is 190 m straight west, which can be represented as (-190, 0) in vector form. The second displacement is 210 m in a direction 45.0° east of south, which can be represented as (210*cos(45°), -210*sin(45°)). The third displacement is 270 m at 30.0° east of north, which can be represented as (270*cos(30°), 270*sin(30°)). Adding these vectors together will give us the vector sum of the first three displacements. To find the fourth displacement, we need to subtract this vector sum from the starting point, which will give us the magnitude and direction of the fourth displacement.
Because cosmologists can't go out into space and test all of their theories, they must depend on the cosmological principle. This principle assumes that _____.
the universe stays at a steady state
any physical laws are the same for the entire universe
the universe is going to eventually collapse
the universe is cooling down
B.) Any physical laws are the same for the entire universe.
Let v(t)=t^2−3t be the velocity, in feet per second, of an object at time t, in seconds.
a) What is the initial velocity? ___ ft/sec
b) When does the object have a velocity of zero? If there is more than time, list all answers in a comma separated list. ___ seconds
The initial velocity of the object is 0 ft/sec. The points in time when the object has a velocity of zero are at t=0 and t=3 seconds.
Explanation:To answer these questions, it's important to understand what the variables represent in this equation. The object's velocity is given by v(t)=t^2−3t where v is the velocity in feet per second and t is the time in seconds.
a) The initial velocity is the velocity of the object at the start, which means at time t=0. By substituting t=0 in the equation, we obtain v(0)=(0)^2 - 3(0) = 0 feet/sec.
b) The object has a velocity of zero when v(t) = 0. In other words, we need to solve the equation t^2−3t = 0 for t. Factoring, we get t(t - 3) = 0, thus t = 0, 3 seconds are the moments at which the object's velocity is zero.
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Elements used to make semiconductors for computers include germanium and
A speeding car collides with a wall (attached to Earth). Consider the car-Earth system to be isolated. A loud sound is produced in the collision, and the car is deformed. What can you say about the momentum of the car-Earth system in this case? ...?
Answer:
A. The total momentum of the system is conserved.
according to newton's first law of motion what is required to make an object slow down
According to Newton's first law of motion, an object at rest will remain at rest and an object in motion will continue moving at a constant velocity unless acted upon by an external force. To make an object slow down, an external force in the opposite direction of its motion, such as friction, is required.
Explanation:According to Newton's first law of motion, an object will continue moving at a constant velocity unless acted upon by an external force. To make an object slow down, an external force in the opposite direction of its motion is required. This force is called friction. Friction can be caused by various factors, such as air resistance or contact with a surface.
Learn more about Newton's first law of motionAn airplane heads northeast at an airspeed of 700 km/hr, but there is a wind blowing from the west at 60 km/hr. In what direction does the plane end up flying? What is its speed relative to the ground?
Final answer:
The plane ends up flying northeast. To find its speed relative to the ground, use vector addition to calculate the resultant velocity as 694 km/hr.
Explanation:
Direction: The plane ends up flying northeast.
Speed Relative to the Ground: To find the speed relative to the ground, we need to calculate the resultant velocity. The plane's velocity relative to the air is northeast at an angle, while the wind blows from the west. Using vector addition, we determine the speed relative to the ground to be 694 km/hr.
Vector Addition: Vector addition is essential to determine the resultant velocity of the plane with respect to the ground, taking into account both the airspeed and the wind speed.
What two organelles should be labeled that WOULD NOT be found in an animal cell?
how does the volume occupied by a cubic centimeter compare with the volume occupied by a millimeter
Which of the following best defines mass?
A. The amount of matter in a substance.
B. The amount of water that a substance displaces.
C. The way a sample of matter fills a container.
D. How much space a sample of matter takes up.
Which of the following best defines mass?
A. The amount of matter in a substance.
B. The amount of water that a substance displaces.
C. The way a sample of matter fills a container.
D. How much space a sample of matter takes up.
Answer:
option (A)
Explanation:
The amount of matter contained in the matter is called its mass.
Mass is a scalar quantity and it always remains constant.
The SI unit of mass is kg.
Which of the following best illustrates the role that gravity played in the formation of our solar system?
A. Gravity allowed the nebula to expand and move outward.
B. Gravity caused the nebula to cool enough for planets to form.
C. Gravity removed excess gas and dust from the cores of the planets.
D. Gravity pulled particles of dust and gas together to form planets.
Answer:
Option D
Explanation:
Gravity is a force of attraction by virtue of mass of a body. It is an attractive force. It is due to gravity that the planets and hence, the solar system was formed. Starting from the nebula, the gravity caused the nebula to contract and form start. From rest of the material, the dust and gas were pulled in together due to gravity to form planet. The gravity of the Sun holds the planets in their respective orbits.
Thus, option D is correct.
Weatherstripping prevents heat loss by
a. lessening evaporation.
b. reducing convection and conduction.
c. preventing condensation.
d. increasing radiation. ...?
Answer: Weatherstripping can refer to either the process or the agent that is used to seal small openings around windows, doors, trunk lids and other areas where a tight seal is desired. Essentially weatherstripping is designed to eliminate a flow or draft from an interior space to an exterior space. Because of this property, weatherstripping is often added to window sashes and doors in order to allow for more efficient heating and cooling of the interior space.
So “B” Is the answer of your question.
Explanation:Weatherstripping can take on several different forms. When it comes to dealing with drafts originating from a small open space between the bottom of a door and the floor, the addition of a small rubber strip along the threshold will often be sufficient to seal the area. The weather stripping will effectively block the airflow between inside and outside, while still allowing the door to be opened and closed with ease. Weatherstripping doors may be accomplished when the door is hung, or added at a later time as the house settles.
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a particle moves along a straight line OX. at a time t(in seconds) the distance X(in metres) from the particle O is given by x=40+12t-t3. how long would the particle travel before coming to rest ...?
Answer:
16m
Explanation:
Which of the following is distance divided by the change in time?
displacement
acceleration
speed
velocity
Answer:
the correct answer is speed, velocity scored incorrectly on my quiz
Explanation:
Brittany is changing the tire of her car on a steep hill 22.4 m high. She stumbles and drops the 10.5-kg spare tire, which rolls down the hill, starting with an initial speed of 2.10 m/s.
What is the speed of the tire at the top of the next hill, which is 8.59 m high?
The speed of the tire at the top of the next hill, which is 8.59 m high, is approximately 15.12 m/s.
a) Variables:
- [tex]\( h_1 \)[/tex] = Initial height of the hill (22.4 m)
- [tex]\( h_2 \)[/tex] = Height of the next hill (8.59 m)
- [tex]\( v_{i1} \)[/tex] = Initial speed of the tire (2.10 m/s)
-[tex]\( v_{f1} \)[/tex] = Final speed at the top of the first hill
- [tex]\( v_{f2} \)[/tex] = Final speed at the top of the next hill
- g = Acceleration due to gravity (-9.8 m/s²)
b) Equation for the first hill:
[tex]\[ v_{f1}^2 = v_{i1}^2 + 2gh_1 \][/tex]
c) Calculate [tex]\( v_{f1} \)[/tex]:
[tex]\[ v_{f1}^2 = (2.10 \, \text{m/s})^2 + 2(-9.8 \, \text{m/s}^2)(22.4 \, \text{m}) \][/tex]
[tex]\[ v_{f1} \approx 16.83 \, \text{m/s} \][/tex]
d) Equation for the next hill:
[tex]\[ v_{f2}^2 = v_{f1}^2 + 2gh_2 \][/tex]
e) Solve for [tex]\( v_{f2} \)[/tex]:
[tex]\[ v_{f2}^2 = (16.83 \, \text{m/s})^2 + 2(-9.8 \, \text{m/s}^2)(8.59 \, \text{m}) \][/tex]
[tex]\[ v_{f2} \approx 15.12 \, \text{m/s} \][/tex]
The speed of the tire at the top of the next hill, which is 8.59 m high, is approximately 15.12 m/s.
Final answer:
The speed of the tire at the top of the next hill is 21.2 m/s.
Explanation:
To find the speed of the tire at the top of the next hill, we can use the principle of conservation of energy.
According to the principle of conservation of energy, the initial potential energy of the tire at the top of the first hill is equal to the final potential energy of the tire at the top of the next hill.
Therefore, we have:
mgh = 1/2 × mv²
Where m is the mass of the tire, g is the acceleration due to gravity, h is the height difference between the two hills, and v is the final velocity of the tire at the top of the next hill.
Plugging in the values, we get:
10.5 × 9.8 × 22.4 = 1/2 × 10.5 × v²
Solving for v, we find:
v = sqrt((2 × 10.5 × 9.8 × 22.4) / 10.5)
v = 21.2 m/s
A 3858 N piano is to be pushed up a(n) 3.49 m frictionless plank that makes an angle of 31.6 ◦ with the horizontal. Calculate the work done in sliding the piano up the plank at a slow constant rate. Answer in units of J.
Answer:
7055.13 J
Explanation:
Step 1: identify the given parameters
Applied force on the piano = 3858NLength of plank = 3.49mangle between the plank and horizontal surface = 31.6⁰Note: frictional force between the piano and horizontal surface is zero since the plank is frictionless.
Step 2: work done in sliding the piano up the plank = applied force X distance moved by the piano.
The distance moved by the piano is equal to the height above ground when the piano reach top of the plank.
make a sketch of right angle trianglelength of the plank is the hypotenuse sideangle between the hypotenuse and the horizontal is 31.6⁰height of the triangle is the height above ground , let it be the unknownHeight of the triangle = 3.49m X sine31.6⁰
Height of the triangle = 1.8287m
Recall, height of the triangle is the height above ground which is equal to the distance moved by the piano
work done in sliding the piano up the plank = applied force X distance moved by the piano.
work done in sliding the piano up the plank = 3858N X 1.8287M
= 7055.13 J
The velocity v of the flow of blood at a distance "r" from the central axis of an artery of radius "R" is: v = k(R^2^ - r^2^) where k is the constant of proportionality. Find the average rate of flow of blood along a radius of the artery. (use 0 and R as the limits of integration) ...?
Final answer:
The average rate of flow of blood along the radius of an artery is found by integrating the velocity equation v = k(R² - r²) from 0 to R, which results in an average velocity formula of (2/3)kR after integration and simplification.
Explanation:
The question asks to find the average rate of flow of blood along a radius of the artery using the given velocity equation v = k(R² - r²) and integrating between the limits 0 and R. To find the average velocity, we integrate the given equation across the artery's radius and then divide by the radius R to calculate the average.
The integration process involves calculating the integral of k(R² - r²) with respect to r, over the interval from 0 to R, which gives us kR²r - (kr³)/3 evaluated between 0 and R. Substituting the limits and simplifying, the result is (2/3)kR². To find the average velocity, we divide this by R, resulting in an average velocity of (2/3)kR.
What is the speed of a wave with a wavelength of 3 m and a frequency of .1Hz?
The correct answer to the question is 0.3 m/s i.e the speed of the wave is 0.3 m/s.
CALCULATION:
As per the question, the wavelength of the wave is given as [tex]\lambda=\ 3\ m.[/tex]
The frequency of the wave f = 0.1 Hz.
We are asked to calculate the speed [ V ] of the wave .
The relation among speed, frequency and wavelength of a wave is given as -
speed = frequency × wavelength
⇒ V = f × [tex]\lambda[/tex]
= 3m × 0.1 Hz
= 0.3 m/s. [ans]
Hence, the speed of the wave will be 0.3 m/s.
A 60.0- kg dancer leaps 0.32 m high. With what momentum does he reach the ground
The momentum of the dancer is equal to 151 Kg.m/s.
What is momentum?The momentum of a body can be defined as the function of the mass of the body and its velocity. Momentum (p) can be determined as the kinetic energy of the body and is the multiplication of velocity (v) and mass (m).
The mathematical equation to calculate the momentum of the body is equal to:
p = m×v
The momentum can be described as the conserved quantity and will be zero if the velocity of an object is equal to zero.
Given, the mass of the dancer, m = 60 Kg
The height from the ground, h = 0.32 m
The initial velocity of the dancer, u = 0
v² - u² = 2gh
v² - 0 = 2 × 9.8 ×0.32
v² = 6.272
v = 2.53 m/s
The momentum of the dancer does he reach the ground:
p = 60 × 2.53
p = 151 Kg.m/s
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What is the value of the normal force if the coefficient of kinetic friction is 0.22 and the kinetic frictional force is 40 newtons?
The value of the normal force if the coefficient of kinetic friction is 0.22 and the kinetic frictional force is 40 Newtons would be 181.81 Newtons.
What is friction?The friction force prevents any two surfaces of objects from easily sliding over each other or slipping across one another. It depends upon the force applied to the object.
As given in the problem we have to find the value of the normal force if the coefficient of kinetic friction is 0.22 and the kinetic frictional force is 40 newtons,
Friction force =(coefficient of friction)*Normal force
40 = 0.22* Normal force
Normal Force = 40/0.22
=181.81 Newtons
Thus, the normal force comes out to be 181.81 Newtons.
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Suppose all of the apples have a mass of 0.10 kg and one of the apples in the bowl (C) is 1.0 meter off the ground. If the apple (C) falls from the table, what is the maximum kinetic energy it can gain?
Find a vector w with the same direction of u but twice as long as v. u = {0 4 2} v = {2 1 0}.
To find a vector w with the same direction of u but twice as long as v, we can use unit vectors. The magnitude of u is √20 and the magnitude of v is √5. The unit vector parallel to u is (0, 2/√5, 1/√5) and the unit vector parallel to v is (2/√5, 1/√5, 0). Multiplying the unit vector parallel to u by 2 times the magnitude of v gives us the vector w = (4/√5, 2/√5, 0).
Explanation:To find a vector w with the same direction as u but twice as long as v (u = {0 4 2} v = {2 1 0}), we can use the concept of unit vectors. First, let's calculate the magnitudes of vectors u and v. The magnitude of u is √(0^2 + 4^2 + 2^2) = √20. The magnitude of v is √(2^2 + 1^2 + 0^2) = √5.
To find a unit vector parallel to u and v, we divide each vector by its magnitude. The unit vector parallel to u is (0/√20, 4/√20, 2/√20) = (0, 2/√5, 1/√5). The unit vector parallel to v is (2/√5, 1/√5, 0).
To find a vector w with the same direction as u but twice as long as v, we can multiply the unit vector parallel to u by 2 times the magnitude of v. w = 2(2/√5, 1/√5, 0) = (4/√5, 2/√5, 0).
A push or pull that gives energy to an ob-
ject, causing that object to start moving, stop
moving, or change its motion is
1. friction.
2. pressure.
3. inertia.
4. a force. ...?
Static, sliding and rolling are types of friction true or false
A cyclist maintains a constant velocity of
4 m/s headed away from point A. At some
initial time, the cyclist is 253m from point A.
What will be his displacement from his
starting position after 64 s?
Answer in units of m
What will be his position from point A after
that time?
Answer in units of m
The cyclist's displacement from the starting position after 64 seconds is 256 meters. Their position from point A after that time is 509 meters.
Explanation:If a cyclist maintains a constant velocity of 4 m/s headed away from point A, their displacement after any given time can be calculated using the formula Δx = vt, where Δx is the displacement, v is the velocity, and t is the time. For a time of 64 seconds, the displacement would be Δx = (4 m/s) × (64 s) = 256 meters.
Since the cyclist starts 253 meters away from point A, the new position (total distance from point A) after 64 seconds can be found by adding the initial distance to the displacement. This gives us a total distance = 253 m + 256 m = 509 meters from point A.
what is Initial temperature and final temperature equations??
...?
Audio frequency range of a human ear is 20Hz - 20000 Hz. Express the range in terms of time period ? Answer needed urgently. Pl. help. Thanks ! S.Ramya ...?
The radius of a cylinder is 5" and the lateral area is 70 PI sq. in. Find the length of the altitude.
? inches ...?
The stress force that causes a mass of rock to pull or twist in opposite directions in called ______.
Shearing
The stress force that causes a mass of rock to pull or twist in opposite directions is called shearing.
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A car has a mass of 1,200 kg. What is its acceleration when the engine exerts a force of 600 N? (Formula: F=ma) 0.5 m/s2 2 m/s2 600 m/s2 1,800 m/s2
As per the question the car has a mass of 12,00 kg.
The engine exerts a force of 600 N. [ here newton i.e N is the unit of force]
We are asked to calculate the acceleration of the particle .
From Newton's second law of motion we know that force acting on a particle is mass times the acceleration of the particle . Mathematically it can be written as-
F = ma [Here F is the applied force,m is the mass which is constant here and ' a' is the acceleration]
Here m =1200 kg
F = 600 N
Hence the acceleration produced due to the force exerted by the engine on car is-
[tex]a =\frac{F}{m}[/tex]
[tex]=\frac{600 N}{1200 kg}[/tex]
[tex]=0.5 m/s^2[/tex] [ans]
Julie drives 100 mi to Grandmother's house. On the way to Grandmother's, Julie drives half the distance at 33.0 and half the distance at 80.0 . On her return trip, she drives half the time at 33.0 and half the time at 80.0 . What is Julie's average speed on the way to Grandmother's house? What is her average speed on the return trip? ...?