Which transformations can be used to map a triangle with vertices A(2, 2), B(4, 1), C(4, 5) to A’(–2, –2), B’(–1, –4), C’(–5, –4)? a 180 rotation about the origin a 90 counterclockwise rotation about the origin and a translation down 4 units a 90 clockwise rotation about the origin and a reflection over the y-axis a reflection over the y-axis and then a 90 clockwise rotation about the origin

Answer:

A. 726,485,760

Step-by-step explanation:

A mathematics journal has accepted 14 articles for publication.

However, due to budgetary restraints only 9 articles can be published this month.

As the journals are published one by one (arranged combination), so the order matters in this case.

So permutation should be used in this case, rather than combination.

Hence, the number of ways the journal editor can assemble 9 of the 14 articles for publication is,

[tex]=\ ^{14}\text{P}_9=\dfrac{14!}{(14-9)!}=\dfrac{14!}{6!}=726,485,760[/tex]

the circle is divided into 8 sections

5 are shaded

so 5/8 are shaded

5 divided by 8 = 0.625

0.625 = 62.5%

 Round to 63% if you need to.

I think that it is c - P[-3/4, - 1/8]

BMK

The maximum area that can be enclosed is 22500 feet²

A rectangle is a quadrilateral in which opposite sides are equal and parallel to each other.

Let x represent the length and y represent the width. Hence:

perimeter = 2(length + width)

600 = 2(x + y)

300 = x + y

y = 300 - x

The area of a rectangle (A) = length * width

A = x * (300 - x)

A = 300x - x²

The maximum area is at dA/dx = 0, hence:

dA/dx = 300 - 2x

300 - 2x = 0

2x = 300

x = 150 feet

y = 300 - x = 300 - 150 = 150 feet

The maximum area = x * y = 150 * 150 = 22500 feet²

The maximum area that can be enclosed is 22500 feet²

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Answer:

The graph of y = f(x) will shift down 9 units.

Step-by-step explanation:

With the graph of y = f(x)-9  the graph of y=f(x) will shift down 9 units. For example:

if f(0) = 0, then y = f(0) -9 = -9.

if f(1) = 9, then y= f(1) - 9 = 9-9 = 0.

The same proccess with all x in the domain of f(x).

In a circle, corresponding arc measures are equal to the angle at the center, while any chord, secant, or tangent length can be determined with a known radius. Furthermore, other angles and arcs can be obtained via properties of circles such as vertical angles, linear pairs, or the properties of quadrilaterals inscribed in circles.

You've asked about the properties of angles, lines, and arc measures within a circle. For the first part, if angle SUT is 39 degrees, then since angle TUV is a vertical angle to it, angle TUV is also 39 degrees because vertical angles are equal. For the arc measure of VTS, since we know the measure of angle SUT, arc VTS will be 2 times that, or 78 degrees, due to the concept of inscribed angles.

Next, the lengths of any chord, secant, or tangent line segments can be calculated knowing the radius length, as they all relate back to the radius in some way. This knowledge comes from our study of circles.

For the third part, if angle MOP is 49 degrees, we can find other angle and arc measures because of the properties of circles. Other angle measures can be found using concepts like vertical angles, linear pairs, or the properties of quadrilaterals inscribed in circles, while arc lengths can be determined by the concept of inscribed angles or central angles. Understanding these concepts allows us to make calculated assertions on angles and arcs within circles.

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Answer:

40

Step-by-step explanation:

The answer is 23.6 if I pretty sure

correct answer 60th costumer

Answer:

c

Step-by-step explanation:

e2020

Drop a perpendicular from an obtuse vertex.

That makes a 30 - 60º right triangle, with

hypotenuse 6 and short leg 3. So the long leg,

which is the height of the rhombus, is 3√3 .

Since a rhombus is a parallelogram, its area

is base x height = 6 x 3√3 = 18√3 .

Drop a perpendicular from an obtuse vertex.

That makes a 30 - 60º right triangle, with hypotenuse 6 and short leg 3. So the long leg, which is the height of the rhombus, is 3√3 .

Since a rhombus is a parallelogram, its area is base x height = 6 x 3√3 = 18√3

the equation has infinite solutions

Answer:

infinity solutions

Step-by-step explanation:

The area under the standard normal curve to the left of z = −2.8 and to the right of z = 2.06 is 0.9776.

Given that, z₁ = -2.8 and z₂ = 2.06.

It is also called the Gaussian Distribution. It is the most important continuous probability distribution. The curve looks like a bell, so it is also called a bell curve.

The z-score is a numerical measurement used in statistics of the value's relationship to the mean of a group of values, measured in terms of standards from the mean.

The area under the standard normal curve to the left of z = −2.8 and to the right of z = 2.06 will be calculated as follows:

The standard normal table represents the area under the curve.

P(z<-2.8) ∩ P(z>2.06)=P(z<-2.8) + P(z>2.06)------(1)

According to the standard normal table, we have

z = -2.8 correspond to an area of = 0.0026

z = 2.06 correspond to an area of = 0.9750

Substitute these values in equation 1, we have

P(z<-2.8) + P(z>2.06) = 0.9750 + 0.0026 = 0.9776

Therefore, the area under the standard normal curve to the left of z = −2.8 and to the right of z = 2.06 is 0.9776.

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Final answer:

The equation of the line for Part A is y = (4/3)x + 11/3, since it is parallel to the given line with a slope of 4/3. The equation for the line in Part B is y = (-3/4)x - 1/2, as it is perpendicular to the given line and the slope is the negative reciprocal of 4/3.

Explanation:

Writing Equations of Lines

To find the equation of a line in the form y = mx + b, we first need to determine the slope (m) and the y-intercept (b). For Part A, since the line needs to be parallel to 4x - 3y - 7 = 0, the slope of our line must be the same as the slope of this given line. To find the slope of the given line, we can rewrite it in slope-intercept form:

4x - 3y = 7
-3y = -4x + 7
y = (4/3)x - 7/3

The slope is 4/3. Since parallel lines have the same slope, our line's slope is also 4/3. Using the point (-2, 1) it passes through, we can substitute into the equation y = mx + b to find b:

1 = (4/3)(-2) + b
1 = -8/3 + b
b = 1 + 8/3
b = 11/3

Thus, the equation of the line for Part A is y = (4/3)x + 11/3.

For Part B, to find a line perpendicular to the given line, we need the negative reciprocal of its slope. The negative reciprocal of 4/3 is -3/4. We then use the given point (-2, 1) to find the y-intercept:

1 = (-3/4)(-2) + b
1 = 3/2 + b
b = 1 - 3/2
b = -1/2

So, the equation for the line in Part B is y = (-3/4)x - 1/2.

Answer:y=csc(x) -1

Step-by-step explanation:

The correct answer is option D. y = csc(x)+1

To determine which function has the range (-infinity, 0) U (2, infinity), we need to analyze each option:

Therefore, the function is y = csc(x) + 1.