Which solution is a buffer? • 0.100 m hno2 and 0.100 m hcl • 0.100 m hno3 and 0.100 m nano3 • 0.100 m hno2 and 0.100 m nacl • 0.100 m hno2 and 0.100 m nano2?

Answer:

1.0 x 10⁻⁹ M OH⁻.

Explanation:

∵ [H₃O⁺][OH⁻] = 10⁻¹⁴.

[H₃O⁺] = 1.0 x 10⁻⁵ M.

∴ [OH⁻] = 10⁻¹⁴/[H₃O⁺] = 10⁻¹⁴/(1.0 x 10⁻⁵ M) = 1.0 x 10⁻⁹ M.

So, the right choice is: 1.0 x 10⁻⁹ M OH⁻.

Answer:

1.0 x 10-9M OH-

Explanation:

I just took the test and this was correct

Answer:4)Wind energy can harm migrating birds.

Explanation:

"The correct option is 4) Wind energy can harm migrating birds.

Wind energy is considered controversial for several reasons, one of which is its potential impact on wildlife, particularly migrating birds. Large wind turbines can pose a threat to birds when they collide with the spinning blades, leading to fatalities. This is especially true for bird species that migrate through areas where wind farms are located. The issue has garnered attention from environmentalists and the public, prompting discussions on how to balance the benefits of renewable energy with the protection of wildlife.

Let's consider the other options to understand why they are not the correct answers:

1) Wind energy is nonrenewable: This statement is incorrect because wind energy is indeed a renewable source of energy. It is generated from the kinetic energy of wind, which is abundant and inexhaustible.

 2) Wind energy needs fossil fuels: While the manufacturing and maintenance of wind turbines may indirectly involve fossil fuels, wind energy itself is produced without the use of fossil fuels. Therefore, this statement is misleading. Wind energy is valued precisely because it can reduce dependence on fossil fuels and lower greenhouse gas emissions.

 3) Wind energy is expensive: The cost of wind energy has decreased significantly over the years, making it one of the most cost-effective sources of renewable energy. Although the initial investment in wind farms can be high, the operational costs are relatively low, and the technology continues to improve, further reducing costs. Thus, this statement does not accurately reflect the current status of wind energy economics.

 In conclusion, the most accurate answer to why wind energy is controversial is due to its potential negative impact on migrating birds, which aligns with option 4.

Answer: Option (d) is the correct answer.

Explanation:

The given compound is [tex]N_{2}O_{3}[/tex]. It contains two nitrogen atoms and three oxygen atoms.

Therefore, according to naming nomenclature "di" will be added before the name of nitrogen. Whereas a prefix "tri" will be added before the name of oxygen atom.

Hence, name of the compound [tex]N_{2}O_{3}[/tex] is dinitrogen trioxide.

The correct name for N2O3  is dinitrogen trioxide. This is demonstrated by the di- prefix in dinitrogen indicating two nitrogen atoms, and the tri- prefix in trioxide indicating three oxygen atoms. The correct name for N2O3 is dinitrogen trioxide. Nitric oxide (NO) and nitrous oxide (N2O) are different compounds.

The correct name for the chemical compound with the formula N2O3 is dinitrogen trioxide.

this can be broken down as follows: the prefix 'di-' in dinitrogen indicates that there are two nitrogen atoms, and the prefix 'tri-' in trioxide indicates there are three oxygen atoms. Therefore, the formula correctly matches the name since there are two Nitrogen atoms and three Oxygen atoms.

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Answer:

3.92 x 10⁻⁵.

Explanation:

∵ [H⁺] = √(Ka.c)

∴ Ka = [H⁺]²/c = (2.8 x 10⁻³)²/(0.20) = 3.92 x 10⁻⁵.

Answer:

         1.64 × 10 ⁻³⁸ J

Explanation:

1) Data:

a) KE =?

b) v =  6.00 × 10⁻⁶ m/s.

c) m = 9.11 × 10⁻²⁸ g.

2) Formula:

3) Solution:

Answer: The kinetic energy of the electron is [tex]1.64\times 10^{-17}J[/tex]

Explanation:

To calculate the kinetic energy of the electron, we use the equation:

[tex]E=\frac{1}{2}mv^2[/tex]

where,

m = mass of the electron = [tex]9.11\times 10^{-28}g=9.11\times 10^{-31}kg[/tex]   (Conversion factor:  1 kg = 1000 g)

v = speed of the electron = [tex]6.00\times 10^6m/s[/tex]

Putting values in above equation, we get:

[tex]E=\frac{1}{2}\times 9.11\times 10^{-31}kg\times (6.00\times 10^6m/s)^2\\\\E=1.64\times 10^{-17}J[/tex]

Hence, the kinetic energy of the electron is [tex]1.64\times 10^{-17}J[/tex]

2.4 atm

At constant temperature;

PV = constant  

P1 = 1.2 atm

V1 = 0.25 L

P2 = ?

V2 = 0.125 L

But;

P1*V1 = P2*V2

Thus;

P2 = P1*V1/V2

     = (1.2 atm)(0.25 L)/(0.125 L)

    = 2.4 atm

The final pressure of the neon gas after it has compressed from 0.250 L to 0.125 L at a constant temperature based on Boyle's law is 2.40 atm.

This question can be answered using Boyle's law which states that the pressure and volume of a gas at a constant temperature are inversely proportional. Therefore if the volume of the neon gas is halved from 0.250 L to 0.125 L at a constant temperature, then the pressure should double from its original value of 1.20 atm. As a result

the final pressure is 2.40 atm.

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Answer:

rate = k*[A]^3

Explanation:

The following information is missing in the question:

Consider the following elementary steps that make up the mechanism of a certain reaction

1. 3A -> B+C

2. B+2D -> C+F

In elementary reactions, the order of each reactant in the rate law is equal to the coefficient in the balanced equation. Therefore, for the first step:

rate = k*[A]^3

The rate law for step 1 of the reaction is rate = k[CH3CH₂Cl]. The rate law is consistent with the experimentally derived rate law for the overall reaction. The rate constant (k) is 1.6 × 10^-6 s^-1.

The rate law for step 1 of this reaction can be determined by comparing experiments and observing how changing the concentration of reactants affects the rate. Comparing experiments 2 and 3 shows that doubling the concentration of [CH3CH₂Cl] doubles the reaction rate. Similarly, comparing experiments 1 and 4 shows that quadrupling the concentration quadruples the reaction rate. This behavior indicates that the reaction rate is directly proportional to [CH3CH₂Cl].

Based on this information, the rate law for step 1 is rate = k[CH3CH₂Cl]. Thus, the rate law for step 1 is consistent with the experimentally derived rate law for the overall reaction, which is rate = k[CH3CH₂Cl].

The rate constant (k) can be calculated using any row in the table. Selecting Experiment 1, we can set up an equation to solve for k:

1.60 × 10^-8 M/s = k(0.010 M)

k = 1.6 × 10^-6 s^-1

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25.9 kJ/mol. (3 sig. fig. as in the heat capacity.)

The process:

[tex]\text{KNO}_3\;(s) \to \text{KNO}_3\;(aq)[/tex].

How many moles of this process?

Relative atomic mass from a modern periodic table:

Molar mass of [tex]\text{KNO}_3[/tex]:

[tex]M(\text{KNO}_3) = 39.098 + 14.007 + 3\times 15.999 = 101.102\;\text{g}\cdot\text{mol}^{-1}[/tex].

Number of moles of the process = Number of moles of [tex]\text{KNO}_3[/tex] dissolved:

[tex]\displaystyle n = \frac{m}{M} = \frac{21.45}{101.102} = 0.212162\;\text{mol}[/tex].

What's the enthalpy change of this process?

[tex]Q = C\cdot \Delta T = 0.505 \times (25.00 - 14.14) = 5.4843\;\text{kJ}[/tex] for [tex]0.212162\;\text{mol}[/tex]. By convention, the enthalpy change [tex]\Delta H[/tex] measures the energy change for each mole of a process.

[tex]\displaystyle \Delta H = \frac{Q}{n} = \frac{5.4843\text{kJ}}{0.212162\;\text{mol}} = 25.8\;\text{kJ}\cdot\text{mol}^{-1}[/tex].

The heat capacity is the least accurate number in these calculation. It comes with three significant figures. As a result, round the final result to three significant figures. However, make sure you keep at least one additional figure to minimize the risk of rounding errors during the calculation.

To calculate the change in enthalpy for the solution process of KNO3, first find the heat transferred, q, through the formula q = m * C * ΔT. Then, calculate ΔH by dividing the heat transferred by the quantity of substance (in moles) involved, obtained from the given mass and the molar mass of KNO3.

To calculate the change in enthalpy (ΔH) in the solution process of KNO3, you first need to figure out the amount of heat transferred during the process. This is done by using the formula: q = m * C * ΔT. In this case, the heat lost to the surrounding (q) equals the mass (m), which here is 21.45 g, times the specific heat capacity (C), which is given as 0.505 KJ/°C, times the change in temperature (ΔT), which is 25.00°C - 14.14°C.

After calculating q, ΔH can be calculated by taking into account the quantity of substance involved, which is the molar mass of KNO3. ΔH is reported in KJ/mol, so to get to ΔH, you'd find the molar mass of KNO3 (101.1 g/mol), figure out how many moles 21.45g represents, and then report the heat per mole. Therefore, the actual ΔH would depend on the specific values you use in these calculations.

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Answer:

[OH⁻] = 1.0 x 10⁻⁹ M.

Explanation:

∵ [H₃O⁺][OH⁻] = 10⁻¹⁴.

∴ [OH⁻] = 10⁻¹⁴/[H₃O⁺] = 10⁻¹⁴/(1.0 x 10⁻⁵) = 1.0 x 10⁻⁹ M.