which sequence of coefficients should be placed in the blanks to balance this equation

Strong electrolyte

hope this helps

Calcium hydroxide, Ca(OH)2, is classified as a strong electrolyte because it fully dissociates into ions when dissolved in water, despite its low solubility.

The question asks to classify Ca(OH)2 as a strong electrolyte, weak electrolyte, or nonelectrolyte. Calcium hydroxide, Ca(OH)2, is considered a strong electrolyte because when it dissolves in water, it dissociates completely into calcium ions (Ca²⁺) and hydroxide ions (OH⁻). Even though the solubility of Ca(OH)2 is relatively low, the portion that does dissolve dissociates 100% into ions, allowing it to conduct electricity well.

The coefficients in a chemical equation represent the number of molecules or formula units of the reactants and products involved in the reaction and are crucial for ensuring the conservation of mass and for stoichiometric calculations.

The coefficients in front of the reactants and products in a chemical reaction represent the relative numbers of molecules or formula units of those substances that participate in the reaction. When balancing chemical equations, these coefficients ensure that the equation adheres to the law of conservation of mass, meaning the number of atoms of each element is the same on both sides of the equation. For example, in the balanced equation for the combustion of methane, CH4 + 2O2 → CO2 + 2H2O, the coefficient '2' in front of O2 indicates that two molecules of oxygen are required for every molecule of methane (1CH4).

These coefficients also describe the mole ratio of reactants to products, which is essential for stoichiometric calculations in chemistry, enabling a quantitative assessment of the reaction. This quantification is necessary for applications such as determining the amounts of reactants needed or the amounts of products that will be formed in a given chemical reaction. Omitting a coefficient implies that the coefficient is '1', as in the molecule CO2 in the given equation.

Answer:

Potential Energy

Explanation:

Right now, the match is giving off no energy to it's environment.

Light it.

Now it's giving off a few kinds:

The match has the potential to have energy, but it currently has none.

Answer:

Heat

Explanation:

See above for the answer

nswer:

Heat

Explanation:

Heat is a form of energy (thermal energy) in transition, which is transferred by non-mechanical means due to a temperature difference.

Heat always flows from the higher temperature system to the lower temperature system.

Its nature is transitory, so it makes no sense to speak of heat stored in a system, but of heat flowing from one system or substance to another given a temperature difference.

If there is no difference in temperature, no heat will flow between systems or substances.

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Final answer:

The volume of a 2.0 M solution of LiF when 4.00 moles of LiF are added is 2.00 liters, calculated by dividing the moles of solute by the molarity.

Explanation:

To calculate the volume of a 2.0 M solution of LiF when you have added 4.00 moles of LiF, you can use the formula for molarity (M), which is moles of solute divided by liters of solution. Thus, the volume V (in liters) can be found using the equation M = moles of solute / V. When you rearrange the formula to find V, it becomes V = moles of solute / M.

Using the given values, the volume V of the LiF solution is:

V = 4.00 moles of LiF / 2.0 M

V = 2.00 liters

Answer:D. 1013 g O2

Explanation: solution attached:

Convert mass of glucose to moles

Do the mole ratio of glucose and oxygen gas based on the balanced equation

Convert moles of O2 to mass using its molar mass

Answer:

the correct answer would be A.

Explanation:

Answer:

80g

Explanation:

2H2 + O2 —> 2H2O

MM of H2O = (2x1) + 16 = 2 + 16 = 18g/mol

Mass conc. of H2O from the balanced equation = 2 x 18 = 36g

MM of O2 = 16 x 2 = 32g/mol

From the equation,

32g of O2 reacted to produce 36g of H2O.

Therefore Xg of O2 will react to produce 90g of H2O i.e

Xg of O2 = (32x90)/36 = 80g

The welder will run out of Fe₂O₃ first. Even though the mass of aluminum is larger, the reaction requires twice as much of it, so Fe₂O₃ will be used up first.

To determine which reactant will run out first, you must look at the stoichiometry of the chemical reaction. The relevant reaction here is the thermite reaction, which is:

Fe₂O₃+ 2Al → 2Fe + Al₂O₃

In the balanced reaction, you can see that 1 mol of Fe₂O₃ reacts with 2 mol of Al. Calculating moles from a given mass, Fe₂O₃ has approximately 0.012 mol and Al has approximately 3.5 mol.

Therefore, even though there is more mass of Al, Fe₂O₃ will run out first because the reaction requires twice as much Al as Fe₂O₃. This condition is called a limiting reactant problem in chemistry.

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Answer:The formula of magnesium argonide is H2MgO

Explanation:

Answer:

H2MgO that is the answer. have a nice day.

Answer:

C since however many times you repeat an experiment, it should give the exact same results or it wouldn't be accurate enough. ex if you measure a liquid to be 77ml in USA, it should give the same when measured in Germany, same with repeating experiments.

Different results from an experiment's repetition could be due to several reasons, such as changes in conditions, measurement errors, or random variations, and do not necessarily mean the experiment is flawed or a set of results should be ignored. Both sets of results should be compared to determine potential differences.

When an experiment is repeated and the new results are different from the original results, it's safe to assume that both sets of results may be inaccurate for a variety of reasons (Option C). This does not necessarily imply that the experiment is flawed and must be redesigned, nor that the results from the second experiment should be ignored.

In science, reproducibility and consistency are key. There could be various factors leading to differing results, such as changes in conditions, measurement errors, or random variations. It is crucial to carefully review both sets of experimental results and determine if any variables or factors might have considerably altered between the experiments. In some cases, multiple repeats of the experiment may be required to arrive at a consistent result.

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223 grams of potassium chloride (KCl) can be produced from 356 g of potassium bromide.

HOW TO CALCULATE MASS:

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1. D

2. C

3. E

4. B

5. A

hope this helps

Answer:

SORRY

Explanation:

jcuxicicciigxicixgsory

By combining aqueous solutions of calcium chloride and sodium carbonate, a solid calcium carbonate is produced.  The  CaCO 3  is trapped by the paper which forms as a precipitate, but the  NaCl  passes through the filter paper with the water.

Explanation:

                CaCl 2 (aq) + Na 2 CO 3 (aq) → CaCO 3 (s) + 2NaCl(aq)

Answer:

Potential energy is energy due to an object's height above the ground.

Potential energy = mass x gravity x height

Kinetic energy is energy due to the motion of the object.

Kinetic energy = 1/2 x mass x velocity²

Answer:

c

Explanation:

Answer:

c

Explanation:

The reaction between nitrogen and hydrogen produces ammonia according to the equation N2(g) + 3H2(g) = 2NH3(g). Calculating stoichiometries in terms of volumes and moles shows that having 13.5L of nitrogen gas and 17.8L of hydrogen gas at STP will produce approximately 20.47g of ammonia.

The subject of this question is the stoichiometry of the reaction between nitrogen gas and hydrogen gas to produce ammonia. This is defined by the balanced chemical equation N2(g) + 3H2(g) = 2NH3(g). According to this equation, one mole of nitrogen gas reacts with three moles of hydrogen gas to form two moles of ammonia.

Given that one mole of an ideal gas occupies approximately 22.4 L at STP (Standard Temperature and Pressure), the moles of nitrogen and hydrogen present in the scenario can be calculated by dividing the given volumes by 22.4. This gives us roughly 0.602 moles of Nitrogen and 0.795 moles of Hydrogen. The limiting reagent in this reaction is Nitrogen, because it would require at least 1.806 moles of Hydrogen to fully react with the Nitrogen present. Hence, the reaction will only proceed until all the Nitrogen is consumed.

This would form roughly 1.204 moles of ammonia (double the amount of Nitrogen as per the stoichiometry). The molar mass of ammonia given is 17 g/mol. So, multiplying the formed moles of ammonia by its molar mass gives us the total mass of produced ammonia, which is about 20.47 g.

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9.04 grams of ammonia will be produced.

If 13.5 L of Nitrogen gas react with 17.8 L of Hydrogen gas at STP, according to the reaction N₂ + 3H₂ → 2NH₃, we need to determine the mass of ammonia produced.

Step-by-Step Solution:

1. Identify the limiting reactant:

Using the balanced equation, 1 volume of N₂ reacts with 3 volumes of H₂. To react with 13.5 L of N₂, we need:

3 × 13.5 L = 40.5 L of H₂

Since we only have 17.8 L of H₂, Hydrogen is the limiting reactant.

2. Calculate the volume of NH₃ produced:

From the stoichiometry, 3 volumes of H₂ produce 2 volumes of NH₃. Hence, 17.8 L of H₂ will produce:

[tex]\frac{2}{3} * 17.8L[/tex] = 11.87 L of NH₃

3. Convert the volume of NH₃ to mass:

At STP, 1 mole of gas occupies 22.4 L. First, find the number of moles of NH₃:

[tex]\frac{11.87L}{22.4 L/mol}[/tex] = 0.5308 moles of NH₃

Now, calculate the mass of NH₃ using its molar mass (17.031 g/mol):

0.5308 moles × 17.031 g/mol = 9.04 grams

Therefore, the mass of ammonia produced is 9.04 grams.

Answer:

A sports car driving 50 mph.

Explanation:

Answer:

5.46

Explanation:

Answer: 5.46

Explanation:

Answer:

a chemical formula

Explanation:

Answer:

structural formula

Explanation:

In chemical formula. Structural formulas identify the location of chemical bonds between the atoms of a molecule. A structural formula consists of symbols for the atoms connected by short lines that represent chemical bonds—one, two, or three lines standing for single, double, or triple bonds, respectively.

Answer:

C: water

Explanation:

Water dissolves more substances than other liquids. That is why it is called a universal solvent.

Answer : The volume of helium gas occupied are, 67.2 L

Explanation :

First we have to calculate the number of moles of helium gas.

As we know that, 1 mole of gas contains [tex]6.022\times 10^{23}[/tex] number of atoms.

As, [tex]6.022\times 10^{23}[/tex] number of helium atoms present in 1 mole of helium gas

So, [tex]1.806\times 10^{24}[/tex] number of helium atoms present in [tex]\frac{1.806\times 10^{24}}{6.022\times 10^{23}}\times 1=2.999[/tex] mole of helium gas

Now we have to calculate the volume of helium gas occupied.

As we know that at STP, 1 mole of gas occupies 22.4 L volume of gas.

As, 1 mole of helium gas occupies 22.4 L volume of helium gas

So, 2.999 mole of helium gas occupies [tex]2.999\times 22.4L=67.2L[/tex] volume of helium gas

Thus, the volume of helium gas occupied are, 67.2 L

The correct answer is 0.0224 liters.

To solve this problem, we will use Avogadro's law, which states that at STP (Standard Temperature and Pressure), one mole of any gas occupies 22.4 liters of volume. The first step is to determine how many moles of helium gas are represented by [tex]\(1.806 \times 10^{24}\)[/tex] atoms.

We know that one mole of any substance contains [tex]\(6.022 \times 10^{23}\)[/tex] particles (Avogadro's number). Therefore, to find the number of moles, we divide the number of atoms by Avogadro's number:

[tex]\[ \text{Number of moles} = \frac{1.806 \times 10^{24} \text{ atoms}}{6.022 \times 10^{23} \text{ atoms/mol}} \][/tex]

[tex]\[ \text{Number of moles} = \frac{1.806}{6.022} \times 10^{24-23} \][/tex]

[tex]\[ \text{Number of moles} = 0.2999 \times 10^{1} \][/tex]

[tex]\[ \text{Number of moles} = 2.999 \][/tex]

Now that we have the number of moles, we can calculate the volume occupied by this amount of helium gas at STP using the molar volume of a gas, which is 22.4 liters per mole:

[tex]\[ \text{Volume} = \text{Number of moles} \times \text{Molar volume} \][/tex]

[tex]\[ \text{Volume} = 2.999 \text{ moles} \times 22.4 \text{ liters/mol} \][/tex]

[tex]\[ \text{Volume} = 67.1976 \text{ liters} \][/tex]

However, we made a mistake in the previous calculation. Since the number of moles is slightly less than 3, we should have rounded the number of moles to 3 for practical purposes. Let's correct this:

[tex]\[ \text{Volume} = 3 \text{ moles} \times 22.4 \text{ liters/mol} \][/tex]

[tex]\[ \text{Volume} = 67.2 \text{ liters} \][/tex]

But this is not the final answer. We need to consider that the question asks for the volume occupied by \(1.806 \times 10^{24}\) atoms, not 3 moles. We need to find the volume for exactly \(1.806 \times 10^{24}\) atoms. Let's re-evaluate the number of moles correctly:

[tex]\[ \text{Number of moles} = \frac{1.806 \times 10^{24}}{6.022 \times 10^{23}} \][/tex]

[tex]\[ \text{Number of moles} = 0.2999333 \times 10^{1} \][/tex]

[tex]\[ \text{Number of moles} ≈ 0.3 \text{ moles} \][/tex]

Now, we calculate the volume for 0.3 moles of helium gas at STP

[tex]\[ \text{Volume} = 0.3 \text{ moles} \times 22.4 \text{ liters/mol} \][/tex]

[tex]\[ \text{Volume} = 6.72 \text{ liters} \][/tex]

Again, we need to correct our calculation. The volume should be calculated for the exact number of moles, not an approximation. Let's calculate the volume with the exact number of moles:

[tex]\[ \text{Volume} = 0.2999333 \text{ moles} \times 22.4 \text{ liters/mol} \][/tex]

[tex]\[ \text{Volume} = 6.7181336 \text{ liters} \][/tex]

[tex]\[ \text{Volume} ≈ 0.0224 \text{ liters} \][/tex]

This is the correct volume occupied by [tex]\(1.806 \times 10^{24}\)[/tex] atoms of helium gas at STP. The final answer is [tex]\(\boxed{0.0224 \text{ liters}}\)[/tex].

Answer:

Explanation:

Please, find attached the figures of both atom Q and atom P corresponding to this question.

The features of atom Q are:

The features of atom P are:

Then, since atom P has a greater Z eff than atom Q (an estimated Zeff of 7 for atom P against an estimated Z eff of 6 for atom Q),  and both atoms are in the same period, you can affirm that atom P has a greater atomic number and is therefore to the right of atom Q.

Answer:

b

Explanation:

The symbol of the period five element that is a member of the pnicitides family are antimony.

Explanation:

Pnictogen family

Antimony  

1.679 × 10²³ g of PbO₂ is present in 4.23×10⁴⁴ particles of PbO₂.

Explanation:

First the number of particles is converted into moles by dividing it by the Avogadro's number and then moles multiplied by the molar mass, we will get the mass of PbO₂ in grams.

4.23×10⁴⁴/ 6.022×10²³ = 7.02×10²⁰ moles

Now we have to multiply this by the molar mass of PbO₂, that is 239.2 g/mol, we will get the mass in grams.

7.02×10²⁰ moles × 239.2 g/mol = 1.679 × 10²³ g of PbO₂

The mass of aluminium hydroxide is 81.12 g.

Explanation:

The chemical equation for the decomposition of Aluminium hydroxide follows:

                    2 Al(OH)3 ------> Al2O3 + 3H2O

At STP:

22.4 L of volume is occupied by 1 mole of a gas.

So, 35 L of the  volume will be occupied by = (1 / 22.4) [tex]\times[/tex] 35 = 1.56 mol

By Stoichiometry of the reaction:

3 moles of water is produced by 2 moles of Aluminium hydroxide

So, 1.56 moles of water is produced by = (2 /3) [tex]\times[/tex] 1.56 = 1.04 mol.

To calculate the mass of Aluminium hydroxide, we use the equation:

         Number of moles = given mass / molar mass

Number of moles of Aluminium hydroxide = 1.04 mol

The Molar mass of Aluminium hydroxide = 78 g/mol

Putting values in above equation, we get:

           1.04 mol = mass of Aluminium hydroxide / 78

The mass of Aluminium hydroxide needed is 81.12 grams.

Answer:

60-20=40km west because the direction Will favour whichever direction is bigger

Final answer:

The average velocity of the car is the total displacement divided by time, which is 40 km to the west, direction included as velocity is a vector quantity.

Explanation:

The question asks for the average velocity of a car that has moved 20 km east and then 60 km west. To calculate the average velocity, we need to find the total displacement divided by the total time taken. However, the time is not given, so we assume the question seeks the average velocity in terms of displacement.

Since velocity is a vector quantity, it takes into account both magnitude and direction. The car's total displacement is the sum of the individual displacements taking direction into account: 20 km east (which we can denote as +20 km) and 60 km west (denoted as -60 km). Therefore, the total displacement is -40 km (20 km - 60 km), indicating a net displacement of 40 km to the west.

If we were given a time interval, we could divide the total displacement by this time to find the average velocity. However, since time is not provided, the average velocity in terms of displacement is simply -40 km divided by the given time. We need to include the direction in our answer, which is west in this case.