Which of the sets of ordered pairs represents a function?

A = {(−5, 5), (−2, 2), (2, −2), (5, −5)}

B = {(4, 2), (3, −2), (9, 4), (11, −3)}

Answer:

2o

Step-by-step explanation:

Answer:

Based on the box plot you have given above, the answer would be 20% of the total schools participated for 6 years or more. This is because the part of the box plot wherein it hits 6 years and above is 20%. Thus, if there are 20 schools, then the 20% of it would be 4. In conclusion, there are 4 schools that participated for 6 years or more. Step-by-step explanation:

Orio and Ted buy an equal number of comic books every month. Orio has 9 more comic books than Ted.

Linear equation is equation in which each term has at max one degree.

Linear equation in variable x and y can be written in the form y = mx + c

Linear equation with two variables, when graphed on the cartesian plane with axes of those variables, give a straight line.

Orio and Ted buy an equal number of comic books every month.

The following equation shows the number of comic books, y, that Orio has after x months:

y = 2x + 15

Using the equation y=mx+b to find Orio's number of comic books, we can plug 2 months to substitute for the variable x.

y = 2(2) + 15

y = 4+15,

y = 19.

We know Ted has 10 comics after 2 months from the graph.

19-10= 9

Therefore, Orio has 9 more comic books than Ted.

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To find out how many ants of the same length would fit end-to-end across the length of the picnic table, divide the length of the table by the length of the ant.

To find out how many ants of the same length would fit end-to-end across the length of the picnic table, we need to convert the length of the table and the length of the ant to the same unit. Since the table is 1 meter across and the ant is 1 centimeter in length, we need to convert centimeters to meters.

There are 100 centimeters in 1 meter, so the ant is 1/100 = 0.01 meters in length. Now, we can determine how many ants would fit across the length of the table by dividing the length of the table by the length of the ant: 1 meter / 0.01 meters = 100 ants.

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Consider a real number in two dimensional plane that X axis and Y axis having ordered pair : P(x,y) or (3,4).

To find it's absolute value we will find it's Distance from origin.

As Coordinate of Origin = (0,0)

Absolute Value of OP = [tex]\left | OP \right |[/tex]

     =  [tex]\sqrt{(0-x)^2+(0-y)^2}=\sqrt {x^2+y^2}[/tex]

    If the point is Q(3,4)

[tex]\left | OQ \right |=\sqrt{3^2+4^2}=\sqrt{5^2}=5[/tex]

In case of a complex number :

Z = a + bi , we consider two axes Real Axis and Imaginary Axis.

We represent Z that is (a,b) in the same way that we represent point in two dimensional plane.

To find it's absolute value , we will find it's distance from origin.

[tex]\left | Z \right |= \sqrt{a^2+b^2}[/tex]

If [tex]Z_{1}[/tex] = 6 + 8 i

[tex]\left | Z_{1}\right |=\sqrt{6^2+8^2}=\sqrt{36+64}=\sqrt{100}=10[/tex]

Answer:

A in short is your answer

Step-by-step explanation:

Answer:

probability of getting a tail = 1/2

probability of getting 3 Tails = 1/2 × 1/2 × 1/2

= 1/8

The sum of the alternating subtraction and addition sequence 300-297+294-291+...+6-3 can be calculated by pairing the numbers and determining the partial sums, which consistently equal 3. With 49 complete sets of these operations within the range given, the total sum is 147.

The sequence provided is a series of alternating subtractions and additions of integers in a specific pattern. To determine the sum of such a sequence, we can pair the numbers in such a way that each subtractive pair (e.g., 300-297) is combined with its subsequent additive pair (e.g., 294). This will result in a series of partial sums which are consistently 3 (e.g., 300-297+294 equals 297). As the pattern continues, each group of four numbers adds up to 3.

Since all groups add up to 3, and we know that each set of two operations (a subtraction followed by an addition) gives us 3, we need to find out how many such sets there are. Given that our numbering starts with 300 and ends with 3 (decreasing by 3 every time), we can see there are 99 numbers in the sequence (since (300 - 3) / 3 + 1 = 99). And because every four numbers make up one set, there would be 99 / 2 = 49.5 sets. We only consider the entire sets, which would be 49 in total, ignoring the last number (3) that does not form a complete set.

Therefore, multiplying 49 sets by 3 gives us the total sum of the pattern, which would be 147. It is important to double-check calculations to ensure accuracy when dealing with sequences and series.

2. The Graph Contains The Point (5, 12)

Remember that in a linear function of the form [tex]y=mx+b[/tex], [tex]m[/tex] is the slope/rate of change of the line and [tex]b[/tex] is the y-intercept.

From our equation we can infer that [tex]b=12[/tex], so the y-intercept of our graph is 12 units above the origin on the point (0, 12). Therefore, choice 2 correctly describe the graph of y = 5x + 12

We can also infer that [tex]m=5[/tex], so the slope of our line is 5, which is constant, so our line has a constant rate of change. Also, since every integer can be written as a fraction with denominator 1, we can write our slope as [tex]m=\frac{5}{1}[/tex]. Therefore, choices 1 and 2 correctly describe the graph of y = 5x + 12.

Now, remember that any point on the plane has coordinates [tex](x,y)[/tex], so, to check if a point is on a line, we just need to replace the [tex]x[/tex] and [tex]y[/tex] values in the line equation and check if the equation holds. Our point is (5, 12), so x = 5 and y = 12. Lets replace the values in our line:

[tex]y=5x+12[/tex]

[tex]12=5(5)+12[/tex]

[tex]12=25+12[/tex]

[tex]12\neq 37[/tex]

Since the equation equation doesn't hold (12 is not equal 37), we can conclude that the graph doesn't contain the point (5, 12). Therefore, choice 2 does NOT correctly describe the graph y = 5x +12.

Answer:

The graph contains the point (5,12)

I got it right on t t m

Answer:

the answer is 5.83

Step-by-step explanation:

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Answer:

Soil required = 453 cm³

Step-by-step explanation:

Volume of cone [tex]=\frac{1}{3}\times \texttt{base area}\times \texttt{depth}[/tex]

Base area of cone [tex]=\pi r^2=\pi \times 3^2=9\pi cm^2[/tex]

Depth of cone = 8 cm

Volume of one cone [tex]=\frac{1}{3}\times 9\times \pi \times 8=75.39cm^3[/tex]

Volume of six cones = 6 x 75.39 = 452.39 cm³ = 453 cm³

Soil required = 453 cm³

area = PIr^2

radius = D/2 = 1KM

3.14 x 1^2 =3.14 square km

247 x 3.14 = 775.58 = 776 acres

If the speed of the train is 230 km per hour. Then the time taken by the train from Paris to Nice will be 4 hours.

The distance covered by the particle or the body in an hour is called speed. It is a scalar quantity. It is the ratio of distance to time.

We know that the speed formula

[tex]\rm Speed = \dfrac{Distance}{Time}[/tex]

Lola takes the train from Paris to Nice.

The distance between the two cities is about  920,000 meters.

If the train travels at a speed of 230 kilometers per hour.

Then the time taken by the train from Paris to Nice will be

[tex]\rm Time = \dfrac{Distance}{Speed}\\\\\\\rm Time = \dfrac{920000 \ m}{230\ km/h}\\\\\\Time = \dfrac{920 \ km}{230 \ km/h}\\\\\\Time = 4 \ hours[/tex]

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6) answer is B , random sampling produces a representative sample

7)  0.1 = 10% so the answer is A, he saves 10% of his income

Two consecutive whole numbers that √46 lies between are 6 and 7.

The given surd is √46.

We need to find two consecutive whole numbers that √46 lies between.

Numbers that follow each other in a regular counting order or pattern are called consecutive numbers. They are written in a series where the difference between the numbers is fixed and where no numbers are skipped in between.

Now, 46 is lies between the perfect squares 6²=36 and 7²=49.

Therefore, two consecutive whole numbers that √46 lies between are 6 and 7.

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Answer:

Sample Answer: To draw a trend line with the divide-center method, first exclude any outliers. Draw a vertical line to divide the data cluster into two groups with approximately the same number of points. Find the center of each group and connect those centers to form the trend line.