Which of the following is NOT a force that influences the wind? A. coriolis effect B. magnetic field C. pressure gradient D. friction

Answers

Answer 1
A magnetic field does not have any influence on wind. The Coriolis effect, pressure gradient, and friction do affect wind.

The solution is B.
Answer 2

Answer: B. magnetic field

Explanation:

Wind blows when there is difference in air pressure i.e. in the area having pressure gradient, wind blows from high pressure area to low pressure area. Force of friction slows the speed of the wind. Thus it is responsible for motion of air. Coriolis effect causes the circular motion of the air. The Coriolis effect changes the direction of the wind.

Thus, from the given options, only the magnetic field does not influence the wind. Magnetic field effects the charged particles or magnetic materials not the wind.  


Related Questions

What is the density of a block of marble that occupies 236 cm3 and has a mass of 824 g? answer in units of g/cm3 ?

Answers

Since the formula is mass/volume the density is 3.4915......g/cm^3

Final answer:

The density of a marble block with a mass of 824 g and volume of 236 cm³ is calculated by dividing mass by volume, resulting in approximately 3.4915 g/cm³.

Explanation:

The density of an object can be calculated using the formula density = mass/volume. In this case, we are given that the mass of the block of marble is 824 grams and it occupies a volume of 236 cm³. To find the density in units of grams per cubic centimeter (g/cm³), we simply divide the mass by the volume.
Using the formula:

Density = mass / volume

Density = 824 g / 236 cm³

Density = 3.4915 g/cm³ (rounded to four decimal places)

Therefore, the density of the marble block is approximately 3.4915 g/cm³.

What is the acceleration of a car moving along a straight-line path that increases its speed from zero to 100 km/hr in 10 s?

Answers

the acceleration is... just wait I have a word document with the answer, just a sec please ;)

The acceleration of a car moving along a straight-line path that increases its speed from zero to 100 km/hr in 10 seconds would be 2.77 m /s² .

What are the three equations of motion?

There are three equations of motion given by  Newton

v = u + at

S = ut + 1/2×a×t²

v² - u² = 2×a×s

As given in the problem, we have to find  the acceleration of a car moving along a straight-line path that increases its speed from zero to 100 km/hr in 10 seconds,

100 km / hr = 100 × 1000 / 3600

                   = 27.77 m / s

By using the first equation of the motion,

v = u + at

27.77 = 0 + 10a

a = 2.77 m /s²

Thus, the acceleration would be 2.77 m /s².

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If a freely falling rock were equipped with a speedometer, by how much would its speed readings increase with each second of fall?

Answers

its speed reading would increase to 10 m/s every second 

In 2.8 s, a car increases its velocity from 20. M/s to 25 m/s. What is the acceleration of the car

Answers

acceleration= change in velocity/time; 5/2.8 , so a=1.785714286

Please helppppp!


When the gas in a balloon is heated, the balloon expands. What are the correct signs of heat and work for this change?
A. +Q, -W
B. -Q, +W
C. +Q, +W
D. -Q, -W


Things that could help:

W=work     Q= Heat


Q= heat                   Work
+ Heat absorbed    + Work done by
- Heat released      - Work done on

Answers

C. +Q, +W

----- apex :)

Final answer:

The correct signs of heat and work when a balloon expands due to heating are +Q for heat absorbed by the gas and -W for work done by the gas on the surroundings, making the correct option A. +Q, -W.

Explanation:

When the gas in a balloon is heated, it expands and does work on its surroundings. According to thermodynamic conventions, when a system (like the gas in a balloon) does work on its surroundings, this work is assigned a negative sign (W < 0). Simultaneously, as the gas is heated, it absorbs heat (Q > 0), which is indicated by a positive sign. Therefore, the correct signs for heat and work for the expanding balloon are +Q for heat absorbed and -W for work done by the gas on its surroundings. The answer that correctly represents these signs is A. +Q, -W.

What are the metric system base units for mass, volume, time, length and temperature?

Answers

mass = kg
volume = cubic meters (m^3)
time = seconds
length = meters
temperature = degrees Celsius

The metric system base units for mass, volume, time, length, and temperature would be kilograms ,meter³,second, meter, and Kelvin respectively.

What is a unit of measurement?

A recognized and accepted standard for measuring other amounts of the same sort is referred to as a unit of measurement. It is predetermined by custom or law.

The metric system base unit for mass would be kilogram.

The metric system base unit for volume would be meter³.

The metric system base unit for time would be second.

The metric system base unit for length would be a meter.

The metric system base unit for temperature would be Kelvin.

Kilograms, meters3, seconds, meters, and Kelvin are the corresponding basic units for mass, volume, time, length, and temperature in the metric system.

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Describe characteristics of the universe in terms of time, distance, and organization

Answers

the sense of time in the universe is that its always expanding to a point then returning( called the Big Bang string theory) the distance of the universe is is forever expanding and retracting( stated in the Big Bang string theory) and the organization is always random as planets are always being made and destroyed, bigger and smaller planets could be the same density (ex a planet far off is made of diamond its gravity so great it crush every thing on earth in seconds but earth is 5x bigger than said planet)

Final answer:

The universe is vast and complex with billions of galaxies and stars. It displays an astonishing degree of order with regular laws governing planetary motion and precise arrangements in living organisms. Dark matter, a mysterious form of matter that does not emit light, is also present in the universe.

Explanation:

The major characteristics of the universe in terms of time, distance, and organization are as follows:

The universe is vast and complex, consisting of approximately 10¹¹ galaxies in the observable part. An average galaxy contains more than 10¹¹ stars, with our Milky Way galaxy being larger than average.

The universe displays an astonishing degree of order, with regular laws governing the motion of planets around the sun and the precise arrangement of animals' parts to serve their purposes.

There is evidence of a large amount of additional matter in galaxies called dark matter, which does not produce light and is still being studied.

These characteristics provide insights into the vastness, orderliness, and complexity of our universe.

When you sneeze, the air in your lungs accelerates from rest to approximately 160 km/hr in about 0.55 seconds . what is the acceleration of the air in m/s2?

Answers

Change in velocity, Δv = 160 km/hr
Change in time, Δt = 0.55 s

Note that 
1 km = 1000 m
1 h = 3600 s
Therefore
Δv = (160,000 m/h)*(1/3600 h/s) = 44.4444 m/s

By definition, the acceleration is
a = Δv/Δt = (44.4444 m/s)/(0.55 s) = 80.808 m/s²

Answer: 80.8 m/s² (nearest tenth)
Final answer:

The acceleration of air when you sneeze, accelerating from rest to approximately 44.44 m/s (160 km/hr) in about 0.55 seconds, is 80.8 m/s².

Explanation:

When you sneeze, the air in your lungs accelerates from rest to approximately 160 km/hr, which is equal to ≈ 44.44 m/s (since 1 km/hr is equivalent to ≈ 0.27778 m/s). To find the acceleration of the air, we use the formula:

a = (v - u) / t

Where a is acceleration, v is final velocity, u is initial velocity (which is 0 m/s in this case, as the air starts from rest), and t is the time over which acceleration occurs. Plugging in the values gives us:

a = (44.44 m/s - 0 m/s) / 0.55 s = 80.8 m/s²

Therefore, the acceleration of the air in m/s² when you sneeze is 80.8 m/s².

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What is the velocity of a quarter dropped from a tower after 10 seconds?

Answers

u = 0, the initial vertical velocity

Assume g = 9.8 m/s² and ignore air resistance.

Use the formula
v = u + gt
where v =  vertical velocity after t seconds.
That is,
v = 0 + (9.8 m/s²)*(10 s) = 98.0 m/s

Answer: 98.0 m/s

Final answer:

To find the velocity of a quarter dropped from a tower after 10 seconds, we use the formula for velocity in free fall, resulting in a final velocity of 100 m/s.

Explanation:

The question is about determining the velocity of a quarter dropped from a tower after 10 seconds. To solve this, we use the formula for velocity in free fall, v = gt, where g is the acceleration due to gravity (approximated as 10 m/s²) and t is the time in seconds. In this case, after 10 seconds, the velocity can be calculated as follows:

g = 10 m/s² (approximation of the acceleration due to gravity)

t = 10 seconds

Substitute the values into the formula: v = gt = 10 m/s² × 10 s = 100 m/s.

Therefore, the velocity of the quarter after falling for 10 seconds is 100 m/s.

How does the temperature of water affect its evaporation science projects?

Answers

Since the kinetic energy of a molecule is proportional to its temperature, evaporation proceeds more quickly at higher temperatures. As the faster-moving molecules escape, the remaining molecules have lower average kinetic energy, and the temperature of the liquid, thus, decreases.

Final answer:

Temperature affects the evaporation rate of water as higher temperatures provide more energy for evaporation. This phenomenon is exemplified by perspiration from the skin which requires more heat input than the latent heat of vaporization at 100 °C, showcasing an effective cooling mechanism in hot weather.

Explanation:

Temperature affects the evaporation rate of water. The higher the temperature, the faster the water molecules move, and the more likely they are to escape and evaporate. This is because the kinetic energy of water molecules increases with temperature, providing more energy for evaporation.

For example, at body temperature, perspiration from the skin requires more heat input than the latent heat of vaporization at 100 °C. This heat comes from the skin, resulting in an effective cooling mechanism in hot weather.

However, it's important to note that temperature is not the only factor that affects evaporation. Other factors like humidity and surface area of contact between air and water also play a role.

A 8.40 g bullet has a speed of 1.33 km/s. (a) what is its kinetic energy in joules?

Answers

KE = Force (in Newtons) x distance (in meters)
To convert mass and velocity into units of force and distance we need to use the standard kinetic energy equation kE = 1/2m x v^2

= 0.00420kg * 1330^2m/s
= 7429.38 j
= 7430 j

Write about a possible scenario where you may be tempted to not use lab safety explain what the correct and most safe choice would be in that situation

Answers

One instance of forgoing lab safety would be a simple drop of a chemical into a test tube, and not wearing protective eye gear. Although it seems irrelevant to put on the goggles just for this matter, it is ultimately the safest option to do so in order to remain unharmed.

How does the resistance of a 100w light bulb compare to the resistance of a 60w light bulb?

Answers

The 100w bulb will have less resistance than a 60w bulb.

Calculate the distance travelled by the van between 16.0s and 23.0s. Give your answer correct to 2 significant figures.

Answers

45.5 meters
Looking at the graph, the van is decelerating at a constant rate from 13 m/s down to 0 m/s over the time interval from 16.0s to 23.0s. The duration of the deceleration is (23.0 - 16.0) = 7.0s. The change in velocity over that interval is 13m/s, so the rate of acceleration is (13.0/7) = -1.857143 m/s^2 (Value is negative since the vehicle is decelerating.
Since d=1/2 A T^2 for constant acceleration, the formula for how far the van travels is
13T - 1/2*1.857143 T^2. = d
Substituting 7 for T gives
13*7 - 1/2*1.857143*7^2 = d
91 - 0.928571*49 = d
91 - 45.5 = d
45.5 = d
Therefore the van moves a total of 45.5 meters over the time interval from 16.0s to 23.0s.

True or false the acceleration of an object is inversely proportional to the net force acting on it

Answers

the answer is true acceleration

The acceleration of an object is not inversely proportional to the net force; it is directly proportional to the net force and inversely proportional to the mass of the object.

The statement that the acceleration of an object is inversely proportional to the net force acting on it is false. According to Newton's second law of motion, the acceleration of an object is directly proportional to the net force acting on it and inversely proportional to its mass. This law is often expressed with the formula a = F/m, where a is acceleration, F is the net force, and m is the mass of the object.

Explain when the median of a data set is a better measure of the center than the mean

Answers

The median is better when there are outliers in the data set because they can throw off the mean by a lot

Answer:

When there is an outlier in the data set, the dot plot or histogram will be skewed. In a skewed representation, the mean is pulled up or down toward the tail of the data. Therefore, skewed data affects the mean more than the median.

Explanation:

The dot plot or histogram will be skewed.

The internal pressure of a cylinder with one ounce of liquid r-410a refrigerant, which has been sitting in a 100 degree fahrenheit truck is ________.

Answers

The substance R-410A is a trademark symbol given to a refrigerant also known as Freon™. Since this is a synthetic substance, known thermophysical conditions are already tabulates as shown in the picture. At a temperature of 100°F, the pressure of the saturated liquid R-410A would be 332.38 psia.

A car initially at rest undergoes uniform acceleration for 6.32 seconds and covers a distance of 120 meters. What is the approximate acceleration of the car?

Answers

In order to answer this problem, let's consider the equations for distance:
Distance = Vi (t) * (1/2) at²
Where Vi is initial velocity, t is time, and a is acceleration
We know acceleration is uniform, so a is just a constant, and initital velocity is zero. 
Therefore:
Distance = 0 + (1/2)a*t²
We can plug in Distance and time to find acceleration
120 = (1/2) *6.32² * a
120 = (1/2) * 39.95 * a        Divide both sides by 39.95/2 (19.97)
6 = a
We get a value of approximately 6 for acceleration.

n Rutherford's gold foil experiment the alpha particles pass through which part of the atom?
A. the nucleus
B. the proton shield
C. the electron cloud
D. the valence electron shell

Answers

It passes through C the Electron Cloud

The Gold foil experiment by Rutherford discovered the atomic nucleus and protons. Protons are positively charged particles and will pass to the negative end. Hence, the alpha particles pass through electron cloud.

What is gold foil experiment?

Gold foil experiment conducted by Rutherford was leading to the discovery  of positively charged particles later called protons and the core of the atom called the nucleus in which protons are located.

Rutherford forwarded an atomic model known as nuclear model. In his experiment, the alpha particles was deviating due to repulsion  from the the metal foil and they passed through the negative charged electron cloud.

Rutherford later called this positively charged particles as protons and he found that they are located in the inner core of the atom called nucleus. Therefore, option C is correct.

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Your body converts chemical energy to all of the following except

Answers

NUCLEAR ENERGY BECAUSE THAT WOULD BE DANGEROUS. 

Which one of the following accurately pairs the device with its function?

A. Bourdon gage—move pistons to create a system of constant pressure
B. Bourdon gage—indicate steam pressure in a furnace
C. manometer—check batteries
D. manometer—determine the specific gravity of a liquid

Answers

Answer;

B. Bourdon gage—indicate steam pressure in a furnace

Explanation;

-Bourdon gauge is an instrument for measuring the pressure of gases or liquids, consisting of a semicircular or coiled, flexible metal tube attached to a gauge that records the degree to which the tube is straightened by the pressure of the gas or liquid inside.

-The Bourdon pressure gauge operates on the principle that, when pressurized, a flattened tube tends to straighten or regain its circular form in cross-section.

-When a gauge is pressurized, the Bourdon creates the dial tip travel to enable pressure measurement. The higher the pressure requirement of the application, the stiffer the Bourdon tube needs to be, which means Bourdon wall thickness and diameter are key considerations for enabling the required tip travel to traverse the necessary movement and, thus, facilitate pressure measurement accuracy.

What is the one thing you can do to control the momentum your car carries in a potential crash?

Answers

I would have to say, Smash the brakes in order to slow the car down and eventually stop it.

To control the momentum your car carries in a potential crash, get your car installed with good quality air bags.

What is momentum?

Momentum is defined as the product of mass and velocity.

Given is to find how to control the momentum your car carries in a potential crash.

The one thing you can do is to get your car installed with good quality air bags. Air bags reduce the momentum of the body by a substantial level.

Therefore, to control the momentum your car carries in a potential crash, get your car installed with good quality air bags.

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The leader of a bicycle race is traveling with a constant velocity of +12.60 m/s and is 11.4 m ahead of the second-place cyclist. the second-place cyclist has a velocity of +9.20 m/s and an acceleration of +1.50 m/s2. how much time elapses before he catches the leader?

Answers

Let the time be t.

so,In time t , distance travelled by 1st cyclist = 12.6 t

distance travelled by 2nd cyclist = 9.2t + 0.5 (1.5) t^2

Now, cyclist 1st is already 11.4 m ahead of 2nd cyclist.

so, 9.2t + 0.5 (1.5) t^2  = 11.4 + 12.6t

find t :

t =  6.77 sec

Final answer:

The problem is a high school level physics kinematics question. It requires setting up two kinematic equations representing the motion of both cyclists and solving for the time when the second cyclist catches up.

Explanation:

The student is asking about the time it will take for a second cyclist to catch up to the leader in a race, given the leader's constant velocity and the second-place cyclist's velocity and acceleration. This is a physics problem involving kinematics, specifically equations of motion.

To solve this problem, you need to set the distances traveled by both cyclists equal to each other and solve for time. Since the first cyclist is moving at a constant velocity, the distance he travels can be represented by d1 = v1*t, where d1 is the distance, v1 is the velocity, and t is time. For the second cyclist with acceleration, you can use the formula d2 = v2*t + 0.5*a*t2, where d2 is the distance, v2 is the initial velocity, a is the acceleration, and t is the time.

Since the second cyclist has to cover an additional 11.4 m to catch up, we modify the equation for d2 to d2 = v2*t + 0.5*a*t2 + 11.4. Now you set d1 equal to d2 and solve for t using quadratic formula or other methods to find when both distances are the same, indicating the second cyclist has caught up.

A rock that forms when magma hardens beneath the earth's surface is called

Answers

The guy  below me is wrong the correct answer is intrusive igneous rock

mason notices that his boat sinks lower into the water in a freshwater lake than in the ocean. what can explain this?

Answers

The effect of how salt in the water can change the boyincy

Answer: the boat is more dense in salt water

Explanation:

Calculate 9 ∙ 10-5 divided by 3 ∙ 10-9. (Box after the "10" in answer is for the exponent.).

Answers

Answer:

3 × 10⁴

Explanation:

We are given two numbers, [tex]n_1=9\times 10^{-5}[/tex] and [tex]n_2=3\times 10^{-9}[/tex]

We have to divide n₁ by n₂. We know that,

[tex]\dfrac{10^n}{10^m}=10^{n-m}[/tex]

Here, n = -5 and m = -9

So on dividing we get :

[tex]\dfrac{9\times 10^{-5}}{3\times 10^{-9}}=3\times 10^{-5+9}=3\times 10^4[/tex]

Hence, on dividing n₁ by n₂ obtained number is 3 × 10⁴.

If μs is greater than some critical value, the woman cannot start the crate moving no matter how hard she pushes. calculate this critical value of μs.

Answers

The critical value of the coefficient of static friction (μs) is calculated by dividing the maximum static friction force by the normal force. This critical value represents the point at which a person is unable to exert enough force to overcome the maximum static friction and initiate movement of the object.

To calculate the critical value of

, we need to understand the relationship between the maximum static frictional force (fs(max)) and the normal force (N). The maximum static friction can be represented as


fs(max) =  N.

This means that static friction increases to match the applied force until it reaches a maximum value, beyond which the object will move. In the provided scenario, the maximum static frictional force required to move the crate is 440 N, with a given normal force due to gravity of 980 N. The coefficient of static friction was given as 0.45. From this, we have the equation 440 N = 0.45 * 980 N.

The critical value  occurs when a person is unable to exert a force greater than the maximum force of static friction. If, for example, a person can only exert a force less than 440 N, the critical coefficient  would have to be such that the maximum static friction force (N) equals the maximum force the person can exert, thus preventing the initiation of motion.

To determine this critical value, we would set the person's maximum possible force to equal fs(max), solving for

as follows: fs(max) =  N. If the maximum possible force exerted by the person is less than 440 N, say 400 N, the critical

would be 400 N / 980 N, which yields a critical value greater than the original  of 0.45.

You are to drive to an interview in another town, at a distance of 270 km on an expressway. the interview is at 11:15

a.m. you plan to drive at around 100 km/h, so you leave at 8:00

a.m. to allow some extra time. you drive at that speed for the first 100 km, but then construction work forces you to slow to 45 km/h for 40 km. what would be the least speed needed for the rest of the trip to arrive in time for the interview?

Answers

Time needed for drive a distance 100 km at 100 km/h: t1 =100/100 = 1 h Time needed for drive a distance 40 km at 45 km/h: t2 =40/45 =0.8 h t3 =3h 15m - 1 h- 0.8 h =1.45 h Distance to town equals: s3 =270-100-40 =130 km Least speed needed to arrive in time for the interview: v3 =130 km/1.45 h =89.65 km/h The answer is 89.65 km/h

A 5kg block of iron is heated to 800degree C.it is placed in a tub containing 2litre of water at 15degree C.Assuming all the water is brought to the boil rapidly calculate the mass of water which boile off.

Answers

Final answer:

To calculate the mass of water that evaporates, we apply energy conservation between the heated iron block and the water. Heat transfers from the iron to the water until the water boils and some evaporates. Specific heat capacities and latent heat values are needed for a numerical solution.

Explanation:

To calculate the mass of water that boiled off when a 5kg block of iron is heated to 800℃ and placed in a tub containing 2 liters of water at 15℃, we apply the concept of conservation of energy. The heat lost by the iron block will be equal to the heat gained by the water, which will result in water reaching its boiling point and some of it evaporating. The specific heat capacity of water, the heat of vaporization of water, and the specific heat capacity of iron are crucial to these calculations.

We can denote the mass of water that evaporates as m, and calculate the heat required to raise the temperature of the remaining water from 15℃ to 100℃ and convert the m grams of water at 100℃ into steam. However, we need additional data such as the specific heat capacities and the latent heat of vaporization for water to provide a concrete answer. Without the specific values, we can only describe the methodology.

What happens in terms of energy when a moving car hit a parked car causing the park card to move?

Answers

its like newtons 3rd law that once in motion a outer force has to stop it

Answer:

The moving car transfers Kinetic Energy to the parked car

Explanation:

Options are not supplied here but I have previously answered this question in a test and these options were supplied.

A) The moving car transfers kinetic energy to the parked car.

B) Kinetic energy in the moving car disappears.

C) Kinetic energy in the parked car is created.

D) The parked car transfers kinetic energy to the moving car.

A) This option provides us with the true outcome, the moving car transfers Kinetic energy to the parked car. This is in agreement with the law of conservation of energy. A transference of energy is the outcome of this event.

B) Kinetic energy cannot disappear, this is because according to the law of conservation of energy, energy can neither be created nor destroyed.

If energy disappears, this would imply that energy is destroyed which is not agreeable.

C) Kinetic energy in the parked car is created... Just like the option B above, and according to the above stated law, energy can neither be created nor destroyed. It is also not agreeable here that energy is created.

D) Energy can be transferred but, "a parked car indicates that the car only has potential energy" and as such cannot transfer kinetic energy to the moving car since it does not possess kinetic energy.

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