Which of the following functions have the ordered pair (2, 5) as a solution?
x + 3 = y
7 - x = y
4 + x = y
y = 2 x

[tex]A) -27a^3 b^6 + 8a^9 b^{12}\\D) 27a^3 b^6 + 8a^9 b^{12}[/tex]

Step-by-step explanation:

Here, the given expressions are:

[tex]A) -27a^3 b^6 + 8a^9 b^{12}\\= (-3)^3(a^3)(b^2)^3 + (2)^3(a^3)3(b^4)^3\\= (-3ab^2)^3 +(2a^3b^4)^3[/tex]

So, the above expression is "sum of cubes".

[tex]B) -9a^3 b^6 + a^9 b^{10}\\[/tex]

But (-9) can not be expressed as a Perfect cube root.

So, the above expression is not "sum of cubes".

[tex]C) 9a^3 b^6 + 8a^9 b^{12}\\[/tex]

But (9) can not be expressed as a Perfect cube root.

So, the above expression is not "sum of cubes".

[tex]D) 27a^3 b^6 + 8a^9 b^{12}\\\\= (3)^3a^3(b^2)^3 + (2)^3(a^3)^3(b^4)^3\\= (3ab^2)^3+ (2a^3b^4)^3[/tex]

So, the above expression is  "sum of cubes".

Answer:

B

Step-by-step explanation:

I think this is your full question and hope it is correct.

Which system of equations could be graphed to solve the equation below?

log(2x+1)=3x-2

A. y1=3x, y2=2x

B. y1=log(2x+1), y2=3x-2

C. y1=log2x+1, y2=3x-2

D. y1=log(2x+1+2), y2=3x

My answer:

We know that: log(2x+1)=3x-2  and they are a equation of log and linear so we need to make system of equation.

The left side is: [tex]y_{1}[/tex] => [tex]y_{1} = log( 2x+1)[/tex]

The right side is : [tex]y_{2} = 3x -2[/tex]

The system of equations are:

[tex]\left \{ {{y_{1} =log(3x+1)} \atop {y_{2} =3x -2}} \right.[/tex]

Now we have two new function with x and y.

The inequality is:

[tex]n > \frac{m}{4}[/tex]

Membership of the pool will be less expensive until number of visits to the pool is one fourth of the membership amount

Solution:

Given that,

A pool charges $4 each visit or you can buy a membership

Let "n" be the number of times you visit the pool

Let the membership amount of the pool be "m"

A pool charges $4 each visit

Therefore, cost for "n" visit is: $ 4n

The inequality showing that a membership is less expensive than paying each visit to the pool is:

4n > m

Divide both sides by "4"

[tex]n > \frac{m}{4}[/tex]

Therefore, membership of the pool will be less expensive until number of visits to the pool is one fourth of the membership amount

Answer:

The answer to your question is 2² 3² or (4)(9)

Step-by-step explanation:

Data

factor 36

Process

1.- Divide 36 by prime numbers starting from 2, then 3, 5, 7, etc.

                          36  2

                           18  2

                            9   3

                            3   3

                             1

2.- Write 36 as a composition of prime numbers

                         36 = 2²3²

3.- The prime factors of 36 are 2² x 3²

Answer:

164 pounds

Step-by-step explanation:

Please see attached picture for full solution.

This is a very simple and easy problem. I'm not sure why you need someone else to solve it, but I hope this helps

a. Linear equation:

Let x be amount of movies rented

$8 + ($2.50 * x)

b.

$8 + ($2.50 * 10)

= $8 + $25.0

= $33

Answer:

Step-by-step explanation:

We would apply the formula for

exponential decay which is expressed as

A = P(1 - r)^t

Where

A represents the population after t years.

t represents the number of years.

P represents the initial population.

r represents rate of growth.

From the information given,

P = 1,450,000

r = 0.99% = 0.99/100 = 0.0099

t = x years

Therefore, an exponential equation to represent this situation after x years is

A = 1450000(1 - 0.0099)^t

A = 1450000(0.9901)^t

Answer:

Fruit smoothie: $3.4

Protein bar: $2.5

Step-by-step explanation:

Let x represent cost of fruit smoothie and y represent cost of protein bar.

We have been given that Jake buys a fruit smoothie and a protein bar for​ $5.90. We can represent this information in an equation as:

[tex]x+y=5.90...(1)[/tex]

[tex]x=5.90-y...(1)[/tex]

We are also told that Kobe buys 2 fruit smoothies and 4 protein bars. He pays​ $16.80. We can represent this information in an equation as:

[tex]2x+4y=16.80...(2)[/tex]

Upon substituting equation (1) in equation (2), we will get:

[tex]2(5.90-y)+4y=16.80[/tex]

[tex]11.80-2y+4y=16.80[/tex]

[tex]2y=16.80-11.80[/tex]

[tex]2y=5[/tex]

[tex]y=\frac{5}{2}=2.5[/tex]

Therefore, each protein bar costs $2.5.

Upon substituting [tex]y=2.5[/tex] in equation (1), we will get:

[tex]x=5.90-2.5=3.4[/tex]

Therefore, each fruit smoothie costs $3.4.

Each fruit smoothie costs [tex]3.40\ dollars[/tex], and each protein bar costs [tex]2.50\ dollars[/tex].

To solve for the cost of each fruit smoothie [tex](\( x \))[/tex] and each protein bar [tex](\( y \))[/tex], we'll use the given system of equations:

1. [tex]\( x + y = 5.90 \)[/tex]

2. [tex]\( 2x + 4y = 16.80 \)[/tex]

Let's solve this step by step.

Step 1: Solve the first equation for [tex]\( x \)[/tex]

[tex]\[ x + y = 5.90 \][/tex]

[tex]\[ x = 5.90 - y \][/tex]

Step 2: Substitute [tex]\( x = 5.90 - y \)[/tex] into the second equation:

[tex]\[ 2(5.90 - y) + 4y = 16.80 \][/tex]

[tex]\[ 11.80 - 2y + 4y = 16.80 \][/tex]

[tex]\[ 2y = 16.80 - 11.80 \][/tex]

[tex]\[ 2y = 5 \][/tex]

[tex]\[ y = \frac{5}{2} \][/tex]

[tex]\[ y = 2.50 \][/tex]

Step 3: Substitute [tex]\( y = 2.50 \)[/tex] back into [tex]\( x = 5.90 - y \)[/tex]

[tex]\[ x = 5.90 - 2.50 \][/tex]

[tex]\[ x = 3.40 \][/tex]

Answer:It depends

Step-by-step explanation:

Answer:

Pressure would be approximately 4.66 pounds.

Step-by-step explanation:

Given:

Volume of gas (V) = 25 cubic cm

Pressure of the  gas (P) = 11 pounds

We need to find the pressure when volume is 59 cubic cm.

Solution:

Now Given:

[tex]V[/tex] ∝ [tex]\frac{1}{P}[/tex]

so we can say that;

[tex]V =\frac kP[/tex]

where k is a constant.

When V = 25 cubic cm, P =11 pounds.

[tex]25 = \frac{k}{11}\\\\k= 25\times 11 = 275\ cm^3.pounds[/tex]

So the equation becomes as.

[tex]V = \frac{275}{P}[/tex]

Now we need to find the pressure when Volume is 59 cubic cm.

[tex]59 =\frac{275}{P}\\\\P=\frac{275}{59}\\\\P\approx 4.66\ pounds[/tex]

Hence Pressure would be approximately 4.66 pounds.

Answer:

P ( E_1*E_2*E_3*E_4 ) = 0.1055

Step-by-step explanation:

Given:

- 52 cards are dealt in 1 , 2 , 3 , 4 hands.

- Events:

             E_1       Hand 1 has exactly 1 ace

             E_2       Hand 2 has exactly 1 ace

             E_3       Hand 3 has exactly 1 ace

             E_4       Hand 4 has exactly 1 ace

Find:

p =P ( E_1*E_2*E_3*E_4 )

Solution:

Multiplication rule.

- For n ε N and events E_1 , E_2 , ... , E_n:

P ( E_1*E_2*......*E_n ) = P (E_1)*P(E_2|E_1)*P(E_3|E_2*E_1)*......*(E_n|E_1*E_2...E_n-1 )

- So for these events calculate 4 probabilities:-

-  For E_1, is to choose an ace multiplied by the number of ways to choose remaining 12 cards out of 48 non-aces:

                               P ( E_1 ) = 4C1 * 48C12 / 52C13

- For E_2 | E_1 , one ace and 12 other cards have already been chosen. there are 39C13 equally likely hands. The number of different one ace hand 2 is the number of ways to choose an ace from 3 remaining multiplied by the number of ways to choose the remaining 12 from 36, we have:

                               P ( E_2 | E_1  ) = 3C1 * 36C12 / 39C13

                               P ( E_3| E_2*E_1  ) = 2C1 * 24C12 / 26C13

                               P ( E_4 | E_3*E_2*E_1  ) = 1C1*12C12 / 13C13 = 1

- So the multiplication rule for n = 4 is as follows:

     P ( E_1*E_2*E_3*E_4 ) = P (E_1)*P(E_2|E_1)*P(E_3|E_2*E_1)*P ( E_4 | E_3*E_2*E_1  ) = [ 4C1 * 48C12 / 52C13 ] * [ 3C1 * 36C12 / 39C13 ] * [ 2C1 * 24C12 / 26C13 ]

     P ( E_1*E_2*E_3*E_4 ) = [ 4!*48! / (12!)^4 ] / [ 52! / (13!)^4 ]

     P ( E_1*E_2*E_3*E_4 ) = [ 4!*13^4 / (52*51*50*49) ]

    P ( E_1*E_2*E_3*E_4 ) = 0.1055

The probability that each hand in a deck of 52 cards gets exactly one ace is approximately 10.5%.

To determine the probability that each hand in a randomly divided deck of 52 cards has exactly one ace, we use the concept of conditional probability.
Let's find it step by step

Step 1 : consider the event E1 that the first hand has exactly one ace:

There are 4 aces and 52 total cards. The probabilities for drawing an ace for the first hand are affected by the decreasing number of both aces and cards.

The probability of the first hand receiving one ace is calculated as:

P(E1) = (4/52) * (48/51) * (47/50) * ... * (36/39)

Step 2 : consider the event E2 that the second hand receives exactly one ace, given that the first hand already has one:

With one ace already given to the first hand, there are 3 aces remaining and 39 cards left for the second hand.

The probability is calculated as:

P(E2|E1) = (3/39) * (35/38) * ... * (25/26)

Step 3 : Proceed similarly for the third and fourth hands:

P(E3|E1E2) = (2/26) * ... * (12/13)

P(E4|E1E2E3) = 1 (since only one ace remains for the last hand)

Step 4 : Using the multiplication rule, the overall probability P(E1E2E3E4) is calculated by multiplying the individual probabilities:

P(E1E2E3E4) = P(E1) * P(E2|E1) * P(E3|E1E2) * P(E4|E1E2E3)

Step 5 : After performing the calculations, we find:

The combined probability P(E1E2E3E4) = (4/52)*(3/39)*(2/26)(1/13) after simplifying is approximately 0.105 or 10.5%.

Assuming it is .005y^2 + 10y not .005*y*2 + 10y

Profit = Revenue - Cost

Profit = (.005y^2 + 10y) - (20y + 1,000,000)

Profit at 30,000 cars so y = 30000

Profit = (.005(30000)^2 + 10(30000)) - (20(30000) + 1,000,000)

Profit = $3,200,000

Answer:

The range of values for the sample mean is between a lower limit of 19 and an upper limit of 21.

Step-by-step explanation:

sample mean = 20

sd = 10

n = 25

standard error = 1

Lower limit of sample mean = sample mean - standard error = 20 - 1 = 19

Upper limit of sample mean = sample mean + standard error = 20 + 1 = 21

The range of values for the sample mean is between 19 and 21.

The solution for the equation is [tex]p=\frac{9}{8}[/tex]

Explanation:

The given equation is [tex]p-\frac{1}{4}=\frac{7}{8}[/tex]

We need to solve the equation.

The solution of the equation can be determined by finding the value for p.

Thus, from the equation, let us add both sides of the equation by [tex]\frac{1}{4}[/tex]

Hence, we have,

[tex]p-\frac{1}{4}+\frac{1}{4}=\frac{7}{8}+\frac{1}{4}[/tex]

Simplifying the equation, we get,

[tex]p=\frac{7}{8}+\frac{1}{4}[/tex]

Taking LCM for 4 and 8, we get,

[tex]p=\frac{7+2}{8}[/tex]

Adding the numerator, we have,

[tex]p=\frac{9}{8}[/tex]

Thus, the value of p is [tex]p=\frac{9}{8}[/tex]

Hence, the solution for the equation is [tex]p=\frac{9}{8}[/tex]

Answer:

y = 3.6(sine( 6.2(x-4.2))+4.4

Step-by-step explanation:

(8.2-.6)/2 = altitude = 3.6

6.2 = Wavelength

(8.2+.6)/2 = 4.4 The "line" (the horizontal central line thingy whose name I forgot cuz it's 12:00)

4.2 = x shift

y = 3.6(sine( 6.2(x-4.2))+4.4

Answer:

Step-by-step explanation:

What is the question

Answer:

It is  [tex]11\frac{9}{10}[/tex]  miles far from Chester to Durbin.

Step-by-step explanation:

Given:

Its 10 3/5 miles from Alston to Barton and 12 1/2 miles from Barton to Chester. The distance from Alston to Durbin, via barton and Chester, is 35 miles.

Now, to find the distance from Chester to durbin.

Distance from Alston to Barton = [tex]10\frac{3}{5} =\frac{53}{5} \ miles.[/tex]

Distance from Barton to Chester = [tex]12\frac{1}{2}\ miles =\frac{25}{2} \ miles.[/tex]

As, given the distance from Alston to Durbin, via barton and Chester, is 35 miles.

Thus, the total distance = 35 miles.

So, we add the distance of Alston to Barton and Barton to Chester and get the distance from Alston to Chester:

[tex]\frac{53}{5} +\frac{25}{2}[/tex]

[tex]=\frac{106+125}{10}[/tex]

[tex]=\frac{231}{10} \ miles.[/tex]

Distance from Alston to Chester  [tex]=\frac{231}{10} \ miles.[/tex]

Now, to get the distance from Chester to durbin we subtract distance from Alston to Chester from the total distance:

[tex]35-\frac{231}{10} \\\\=\frac{350-231}{10} \\\\=\frac{119}{10} \\\\=11\frac{9}{10}\ miles.[/tex]

Therefore, it is  [tex]11\frac{9}{10}[/tex]  miles far from Chester to Durbin.

Answer:

[tex]\text{Area of margin}=145\text{ cm}^2[/tex]

Step-by-step explanation:

We have been given that a painting is drawn on a cardboard 22 cm long and 12 cm wide such that there is a margin of 2.5 meter cm along each side. We are asked to find the area of the margin.

The total area of the margin would be equal to area of whole cardboard minus area of painting.

[tex]\text{Area of whole cardboard}=22\text{ cm}\times 12\text{ cm}[/tex]

[tex]\text{Area of whole cardboard}=264\text{ cm}^2[/tex]

Since there is a margin of 2.5 meter cm along each side, so sides of painting would be 2,5 cm smaller on four sides. The sides painting would be [tex]22-5=17[/tex] and [tex]12-5=7[/tex].

[tex]\text{Area of painting}=17\text{ cm}\times 7\text{ cm}[/tex]

[tex]\text{Area of painting}=119\text{ cm}^2[/tex]

[tex]\text{Area of margin}=264\text{ cm}^2-119\text{ cm}^2[/tex]

[tex]\text{Area of margin}=145\text{ cm}^2[/tex]

Therefore, the total area of the margin is 145 squared cm.

Answer: 2.1 feet

Step-by-step explanation:

The ladder forms a right angle triangle with the wall and the ground. The length of the ladder represents the hypotenuse of the right angle triangle. The height from the top of the ladder to the base of the wall represents the opposite side of the right angle triangle.

The distance, d from the bottom of the ladder to the base of the wall represents the adjacent side of the right angle triangle.

To determine the distance, d from the bottom of the ladder to the base of the wall, we would apply we would apply the cosine trigonometric ratio.

Cos θ = adjacent side/hypotenuse. Therefore,

Cos 65 = d/5

d = 5Cos 65 = 5 × 0.4226

d = 2.1 feet

We are given a velocity equation, and from that, we want to find the initial velocity such that we know the velocity for a given time.

We will see that the initial velocity is 124 ft/s

-------------------------------

Let's see how to solve this:

We have that the velocity equation:

v(t) = v₀ - (32 ft/s^2)*t

Where I added the units of the gravitational acceleration, which are in ft over seconds squared.

We want to get the value of the initial velocity, v₀, given that after 3 seconds the velocity is 28ft/s.

This means that:

v(3s) = 28 ft/s = v₀ - (32 ft/s^2)*3s

We can solve this for v₀:

28 ft/s = v₀ - (32 ft/s^2)*3s

28 ft/s + (32 ft/s^2)*3s = v₀

124 ft/s = v₀

So we can see that the initial velocity is 124 ft/s

If you want to learn more, you can read:

https://brainly.com/question/9163788

Answer:

12

Step-by-step explanation:

15000x = 9000x +72000

6000x = 72000

x = 12

Answer: the number of units that must be sold to break even is 12

Step-by-step explanation:

The cost function is expressed as

C(x)= 9000x +72000

The revenue function is expressed as

R(x) = 15000x

Profit = Revenue - cost

At the point of break even, the total revenue is equal to the total cost. This means that profit is zero. The expression becomes

Revenue - cost = 0

Revenue = cost

R(x) = C(x)

Therefore,

15000x = 9000x +72000

15000x - 9000x = 72000

6000x = 72000

x = 72000/6000

x = 12

Answer:

a) P ( E | F ) = 0.54545

b) P ( E | F' ) = 0

Step-by-step explanation:

Given:

- 4 Coins are tossed

- Event E exactly 2 coins shows tail

- Event F at-least two coins show tail

Find:

- Find P ( E |  F )

- Find P ( E | F prime )

Solution:

- The probability of head H and tail T = 0.5, and all events are independent

So,

                    P ( Exactly 2 T ) = ( TTHH ) + ( THHT ) + ( THTH ) + ( HTTH ) + ( HHTT) + ( HTHT)  = 6*(1/2)^4 = 0.375

                    P ( At-least 2 T ) = P ( Exactly 2 T ) + P ( Exactly 3 T ) + P ( Exactly 4 T) = 0.375 + ( HTTT) + (THTT) + (TTHT) + (TTTH) + ( TTTT)

      = 0.375 + 5*(1/2)^4 = 0.375 + 0.3125 = 0.6875

- The probabilities for each events are:

                    P ( E ) = 0.375

                    P ( F ) = 0.6875

- The Probability to get exactly two tails given that at-least 2 tails were achieved:

                    P ( E | F ) = P ( E & F ) / P ( F )

                    P ( E | F ) = 0.375 / 0.6875

                    P ( E | F ) = 0.54545

- The Probability to get exactly two tails given that less than 2 tails were achieved:

                    P ( E | F' ) = P ( E & F' ) / P ( F )

                    P ( E | F' ) = 0 / 0.6875

                    P ( E | F' ) = 0                

Answer:

  -5

Step-by-step explanation:

The power rule can be used.

  f(x) = 5x^-1

  f'(x) = 5(-1)x^(-1-1)

  f'(x) = -5x^-2

Then ...

  f'(-1) = -5(-1)^-2

  f'(-1) = -5

_____

The attached graph shows the value of the derivative at x=-1, along with a tangent line having that slope at the point (-1, f(-1)).

To solve the equation sin 2x - sin 4x = 0, we apply the identity for the difference of two sines and set each term equal to zero. The solutions in the interval [0, 2π) are x = 0, π/6, 5π/6, π.

The equation given is sin 2x - sin 4x = 0. To find the solutions to this equation in the interval [0, 2π), we can use the trigonometric identity for the difference of two sines, sin A - sin B = 2 sin((A - B)/2) cos((A + B)/2). Applying this identity:

2 sin(-2x/2) cos(6x/2) = 0
2 sin(-x) cos(3x) = 0

Since sin(-x) = -sin(x), we can rewrite the equation further:

-2 sin(x) cos(3x) = 0

To find the solutions, set each part equal to zero:

sin(x) = 0

cos(3x) = 0

For sin(x) = 0, the solutions in [0, 2π) are x = 0, π, 2π. However, since the interval is [0, 2π), 2π is not included.

For cos(3x) = 0, the solutions are x = π/6, 5π/6 since cos(x) has a period of 2π and 3x adds additional repetitions of the solutions in the interval.

The complete set of solutions in the interval [0, 2π) are therefore:

0

π/6

5π/6

π

Answer:

Total number of possibilities 2,095,681,645,538.

Step-by-step explanation:

The variables can be 1 to 8 characters long.

The first space can be filled by any of the 26 letters.

The remaining n places can be filled by any of the 26 letters or any of the 10 digits.

For a single character variable the number of ways to select a variable name is,

n (1 character) = 26

For two character variable the number of ways to select a variable name is,

n (2 character) = 26 × 36 = 936

For three character variable the number of ways to select a variable name is,

n (3 character) = 26 × 36 × 36 = 26 × 36² = 33,696

For four character variable the number of ways to select a variable name is,

n (4 character) = 26 × 36 × 36 × 36 = 26 × 36³ = 1,213,056

And so on.

Similarly for the eight character variable the number of ways to select a variable name is,

n (8 character) = 26 × 36 × 36... × 36 = 26 × 36⁷ = 2,037,468,266,496

Total number of possibilities 2,095,681,645,538.

Answer:3

Step-by-step explanation:

Answer:

3

Step-by-step explanation:

khan acadamy hope this helps

The probability of drawing two chips of different colors from the bag is 35/33.

The probability of drawing the chips:

Calculate the total number of ways to draw 2 chips: 12 chips total, so 12C2 = 66 ways.

Calculate the number of ways to draw 2 chips of different colors: (5 blue chips × 7 non-blue chips) + (7 non-blue chips × 5 blue chips) = 70 ways.

Probability = Number of favorable outcomes / Total outcomes = 70/66 = 35/33.

the probability that the two selected chips are of different colors is [tex]\( \frac{94}{144} \), which simplifies to \( \frac{47}{72} \).[/tex]

To find the probability that the two selected chips are of different colors, we can use the concept of complementary probability.

The complementary event of selecting two chips of different colors is selecting two chips of the same color.

Let's calculate the probability of selecting two chips of the same color and then subtract that from 1 to find the probability of selecting two chips of different colors.

1. Probability of selecting two blue chips:

[tex]\[ P(\text{blue, blue}) = \frac{5}{12} \times \frac{5}{12} = \frac{25}{144} \][/tex]

2. Probability of selecting two red chips:

[tex]\[ P(\text{red, red}) = \frac{4}{12} \times \frac{4}{12} = \frac{16}{144} \][/tex]

3. Probability of selecting two yellow chips:

[tex]\[ P(\text{yellow, yellow}) = \frac{3}{12} \times \frac{3}{12} = \frac{9}{144} \][/tex]

Now, let's add these probabilities together because any of these scenarios results in two chips of the same color:

[tex]\[ P(\text{same color}) = P(\text{blue, blue}) + P(\text{red, red}) + P(\text{yellow, yellow}) \]\[ P(\text{same color}) = \frac{25}{144} + \frac{16}{144} + \frac{9}{144} = \frac{50}{144} \][/tex]

Finally, we subtract this probability from 1 to find the probability of selecting two chips of different colors:

[tex]\[ P(\text{different colors}) = 1 - P(\text{same color}) \]\[ P(\text{different colors}) = 1 - \frac{50}{144} = \frac{144}{144} - \frac{50}{144} = \frac{94}{144} \][/tex]

So, the probability that the two selected chips are of different colors is [tex]\( \frac{94}{144} \), which simplifies to \( \frac{47}{72} \).[/tex]

23) x = [tex]\frac{-60}{9}[/tex] = -6.666.

24) x = [tex]\frac{-12}{7}[/tex] = -1.7142.

25) x = [tex]\frac{-37}{5}[/tex] = -7.4.

Step-by-step explanation:

Step 1; For [tex]\frac{x+6}{3}[/tex] = [tex]\frac{x+4}{12}[/tex], we cross multiply the denominators and get,

3 × (x + 4) = 12 × (x + 6),

3x + 12 = 12x + 72.

We take all the x terms to the LHS and keep the constants on the RHS.

3x - 12x = 72 - 12,

-9x = 60, x = [tex]\frac{-60}{9}[/tex] = -6.6666.

Step 2; For [tex]\frac{-5}{x-4}[/tex] = [tex]\frac{9}{x+12}[/tex], we cross multiply the denominators and get,

-5 × (x + 12) = 9 × (x - 4),

-5x - 60 = 9x - 36.

We take all the x terms to the LHS and keep the constants on the RHS.

-5x - 9x = -36 + 60,

-14x = 24, x = [tex]\frac{-24}{14}[/tex] = -1.7142.

Step 3; For [tex]\frac{6}{11}[/tex] = [tex]\frac{x-1}{x-8}[/tex], we cross multiply the denominators and get,

6 × (x - 8) = 11 × (x - 1),

6x - 48 = 11x - 11.

We take all the x terms to the LHS and keep the constants on the RHS.

6x - 11x = -11 + 48,

-5x = 37, x = [tex]\frac{-37}{5}[/tex] = -7.4.

Answer:

[tex]TA=(144+36\sqrt{3})\ units^2[/tex]

Step-by-step explanation:

we know that

The total area or surface area of the regular pyramid is equal to the area of the triangular base plus the area of its three lateral triangular faces

so

step 1

Find the area of the triangular base B

Is an equilateral triangle

Applying the law of sines

[tex]B=\frac{1}{2}(12^2)sin(60^o)[/tex]

[tex]B=\frac{1}{2}(144)\frac{\sqrt{3}}{2}[/tex]

[tex]B=36\sqrt{3}\ units^2[/tex]

step 2

Find the area of the lateral triangular faces

[tex]A=3[\frac{1}{2}(12)h][/tex]

Find the height

Applying the Pythagorean Theorem

[tex]10^2=6^2+h^2[/tex]

[tex]h^2=100-36\\h^2=64\\h=8\ units[/tex]

Find the area of the lateral triangular faces

[tex]A=3[\frac{1}{2}(12)8]=144\ units^2[/tex]

therefore

The total area is

[tex]TA=(144+36\sqrt{3})\ units^2[/tex]