Answer:
Option D.
Step-by-step explanation:
We have to find the equation of the parabola which has vertex at ( 0,3 )
If we write the equation of a parabola in the vertex from then we will write
y = ( x - h )² + (k)²
In this equation ( h, k) will be the vertex.
(a) y = (x-3)² + 0
so ( 3,0) will be the vertex
(b) y = ( x+3)² + 0
or y = [x - (-3)]² + 0
then ( -3,0) will be the vertex
(c) y = (x² - 3)
y = ( x-0 )² + (-3)
then ( 0, -3) is the vertex.
(d) y = x² + 3
y = ( x-0 )² + 3
Then ( 0, 3 ) will be the vertex of this parabola.
Option D. is the answer.
You can buy DVDs at a local store for $15.49 each. You can buy them at an online store for $13.99 each plus $6 for shippimg. How many DVDs can you buy for the same amount at the two stores
To find out how many DVDs you can buy for the same price at both stores, you create a formula incorporating the cost per DVD and the shipping cost at the online store. Solving this equation will give you the number of DVDs where the cost will be equal at both stores. However, this might not always result in a whole number, indicating that there is no exact count of DVDs resulting in the same cost.
Explanation:To determine how many DVDs you can buy for the same amount at both stores, you can set up a mathematical equation accounting for the cost of each DVD and the shipping cost in the online store. The equation would look like this:
15.49 x = 13.99 y + 6
where x and y represent the number of DVDs bought from the local and online store respectively. By solving this equation we're finding out for which number of DVDs the total costs at both stores are equal.
To find the exact number of DVDs where the total cost will be the same, the equation needs to be solved for a whole number. This may result in no exact integer solution, showing that there's no exact number of DVDs for which the cost will be the same at both stores.
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Each side of a square is increasing at a rate of 3 cm/s. at what rate is the area of the square increasing when the area of the square is 16 cm2?
Answer:
The rate of the area increasing for square is 24cm²/ s
Rate of increasing side ?
Changing the length of side with respect to time is the rate of increasing side .
Given each side of square is increasing at a rate 3cm/s.
Area of square = sides²
Side length = a
(dA/dt) = (dA/da)×(da/dt) { chain rule of differentiation}
Differentiation of area w.r.t. t is
dA/da= 2a (da/dt)
dA/dt = 2a *(da/dt)
da/dt = 3 cm/s
When A=16 cm²
16 = a²
a= 4
(dA/dt) = 2x4 x 3
= 24 cm²/ s
Hence, the rate of the area increasing for square is 24cm²/s
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If an equation is an identity, then how many solutions does it have?
Infinite is the answer
What is 25 divided by 28
The solution after divide is,
⇒ 0.893
What is Division method?Division method is used to distributing a group of things into equal parts. Division is just opposite of multiplications. For example, dividing 20 by 2 means splitting 20 into 2 equal groups of 10.
We have to given that;
To divide the numbers,
⇒ 25 divided by 28
Now, We can divide the numbers as;
⇒ 25 divided by 28
⇒ 25 ÷ 28
⇒ 25 / 28
⇒ 0.893
Thus, The solution after divide of the numbers is,
⇒ 0.893
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The ends of a pipe when measured with a tape measure that has marks every millimeter are exactly at the 0 mark and the 15 meter mark. how would you record this measurement keeping the correct number of significant figures.
19. What are the extremes of the following proportion? 3⁄15 = 12⁄60
Explain how you can find 4 × 754 using two different methods
xm-2m if x=-2 and m=-3
xm-2m
x=-2, m = -3
xm = -2 *-3 = 6
2m = 2*-3 = -6
6- -6 = 6+6 = 12
13. Apply the rules for order of operations to simplify 2 + 3 − 4 + (5 × 4). A. 9 B. 24 C. 22 D. 21
what interest rate is needed for $9,500 to earn $900 in 19 months?
Answer:
The interest rate is 5.98%.
Step-by-step explanation:
To find : What interest rate is needed for $9,500 to earn $900 in 19 months?
Solution :
The formula of interest is given by,
[tex]I=P\times R\times T[/tex]
Where,
I is the interest amount I=$900
P is the principle P=$9500
T is the time T=19 months= [tex]\frac{19}{12}[/tex] year.
R is the interest rate
Substitute the value in the formula,
[tex]900=9500\times R\times \frac{19}{12}[/tex]
[tex]R=\frac{900\times 12}{9500\times 19}[/tex]
[tex]R=\frac{10800}{180500}[/tex]
[tex]R=0.0598[/tex]
The rate of interest in percentage is [tex]R=0.0598\times 100=5.98\%[/tex]
Therefore, The interest rate is 5.98%.
To earn $900 from $9,500 in 19 months, an annual interest rate of approximately 5.97% is needed.
To determine the interest rate needed for $9,500 to earn $900 in 19 months, we can use the simple interest formula:
Simple Interest Formula: SI = P × R × T
SI: Simple Interest ($900)
P: Principal ($9,500)
R: Annual Interest Rate (as a decimal)
T: Time (in years)
Convert 19 months into years: 19 months / 12 months/year = 1.5833 years.Substitute the values into the formula: $900 = $9,500 × R × 1.5833.Isolate R: R = $900 / ($9,500 × 1.5833).R = 0.0597, which is approximately 5.97% per year.Mitchell deposited $651.37 in a savings account that earns 3.9% simple interest what is Mitchell's account balance after 15 years?
find the GFC of 18a and 20ab
an appliance store sold 360 microwave ovens last year. Of that amount, 3/8 were apartment-sized models. The number of apartment-sized models sold for the year was what?
multiply:
360 * 3/8 = 360*3 =1080
1080/8 = 135 were apartment sized
estimate the answer to 109 divided by 96
Five sandwich rings are each cut into four pieces you then cut each of the pieces into three servings how many servings do you have
please tell me hown in thw world in the answer key this is 0.45
What's 307, 407 rounded to the nearest thousand?
Assuming that this is a complete, if scrambled, record of Ronald’s May spending and that any overdraft fees incurred do not affect the running total, how many times did Ronald overdraw his account in May
In 2012, the average donation to the help way was $225 with a standard deviation of $45. in 2013, the average donation was $400 with a standard deviation of $60. in which year did the donations show a more dispersed distribution?
Final answer:
The donations in 2012 had a more dispersed distribution than in 2013, as indicated by a higher coefficient of variation of 20% compared to 15% in 2013.
Explanation:
To determine which year had a more dispersed contribution distribution, we examine the coefficient of variation (CV), which is calculated by dividing the standard deviation by the mean and then multiplying by 100 to express it as a percentage. A higher CV indicates a more dispersed distribution.
For 2012:
Mean = $225Standard Deviation = $45CV = ($45 / $225) x 100 = 20%For 2013:
Mean = $400Standard Deviation = $60CV = ($60 / $400) x 100 = 15%Comparing the coefficients of variation, we can conclude that the donations in 2012 had a more dispersed distribution than in 2013 since the CV in 2012 was higher.
What is the contrapositive of the conditional statement? If two variables are directly proportional, then their graph is a linear function.
Estimate square root of 250 to one decimal place
When jumping, a flea rapidly extends its legs, reaching a takeoff speed of 1.0 m/s over a distance of 0.50 mm . part a what is the flea's acceleration as it extends its legs?
The flea's acceleration is 1,000 m/s².
Further explanationThe problem we overlook this time is about uniformly accelerated motion.
The list of variables to be considered is as follows.
[tex]\boxed{u \ or \ v_i = initial \ velocity}[/tex]
[tex]\boxed{u \ or \ v_t \ or \ v_i = terminal \ or \ final \ velocity}[/tex]
[tex]\boxed{a = acceleration \ (constant)}[/tex]
[tex]\boxed{d = distance \ travelled}[/tex]
Given that a take-off speed of 1.0 m/s over a distance of 0.50 mm.
The initial speed was zero from rest. It was asked about flea's acceleration when she extends her legs.
The formula we follow for this problem are as follows:
[tex]\boxed{ \ v^2 = u^2 + 2ad \ }[/tex]
a = acceleration (in m/s²)u = initial velocity = 0 m/sv = take off speed = 1.0 m/sd = distance travelled = 0.50 mmConverted 0.50 mm to meters: [tex]\boxed{0.50 \ mm = 0.50 \times 10^{-3} \ m = 5.0 \times 10^{-4} \ m}[/tex]
Steps:
We set the formula so that the acceleration becomes the subject.
[tex]\boxed{ \ v^2 = u^2 + 2ad \ }[/tex]
[tex]\boxed{ \ v^2 - u^2 = 2ad \ }[/tex]
[tex]\boxed{ \ 2ad = v^2 - u^2 \ }[/tex]
[tex]\boxed{ \ a = \frac{v^2 - u^2}{2d} \ }[/tex]
Substitute all data into equations.
[tex]\boxed{ \ a = \frac{(1.0)^2 - (0)^2}{2(5.0 \times 10^{-4})} \ }[/tex]
[tex]\boxed{ \ a = \frac{1}{10 \times 10^{-4}} \ }[/tex]
[tex]\boxed{ \ a = \frac{1}{1 \times 10^{-3}} \ }[/tex]
[tex]\boxed{ \ a = 1 \times 10^{3}\ = 1,000 \ m/s^2 \ }[/tex]
We get the flea's acceleration, i.e., 1,000 m/s².
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The Flea acceleration as it extends its leg is [tex]\fbox{\begin\\\ 1000\ m/s^{2}\\\end{minispace}}[/tex].
Further explanation:
Given:
The takeoff speed of the flea is [tex]1.0\ \text{m/s}[/tex].
The distance cover by flea is [tex]0.50\ \text{m/s}[/tex].
To find:
The acceleration of the flea as it extended it legs.
Formula used:
The acceleration of the flea can be obtained by the given formula.
[tex]\fbox{\begin\\\ \math v^{2}=u^{2}+2as\\\end{minisapce}}[/tex] ....(1)
Here, [tex]v[/tex] is the final velocity of flea, [tex]u[/tex] is the initial velocity of flea, [tex]a[/tex] is the acceleration of the flea, [tex]s[/tex] is the distance cover by the flea.
Calculation:
The initial velocity of flea is [tex]0[/tex].
The final velocity of flea is [tex]1.0\text{m/s}[/tex].
The distance cover by flea is in millimeter.
Convert millimeter into meter as follows.
[tex]\fbox{\begin\\\ \begin{aligned}0.50 \text{ mm}&=\dfrac{0.50}{1000}\text{ m}\\&=0.0005\text{ m}\end{aligned}\\\end{minispace}}[/tex]
Now substitute [tex]0[/tex] for [tex]u[/tex], [tex]1.0[/tex] for [tex]v[/tex] and [tex]0.0005[/tex] for [tex]s[/tex] in equation (1) to obtain the value of acceleration.
[tex]\begin{aligned}1^{2}&=0^{2}+(2a\times(0.0005))\\1&=0.001a\\a&=\dfrac{1}{0.001}\\a&=1000\end{aligned}[/tex]
Therefore, the acceleration of the flea is as it extends its leg is [tex]\fbox{\begin\\\ 1000\ m/s^{2}\\\end{minispace}}[/tex].
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Answer details:
Grade: Middle school
Subject: Mathematics
Chapter: Speed and distance
Keywords: Flea, jump, legs, takeoff speed, acceleration , distance cover, 0.05 mm, 1000 meter per second square. Initial velocity, Final velocity
When does the proportion form of newton's second law take the form of an equation?
The proportion form of Newton’s second law is when finding the acceleration of a problem as this is the equation suitable of finding the acceleration and to be able to compute the missing answer to the problem. In the form of the equation, it is ‘a + f / m’.
A certain plant grows 1 1/6 inches every week. How long will it take the plant to grow 6 1/6 inches
Answer:
5 weeks 2 days
Step-by-step explanation:
A certain plant grows every week = [tex]1\frac{1}{6}[/tex] = [tex]\frac{7}{6}[/tex] inches
1 week = 7 days
Therefore in 1 day the plant grows = [tex]\frac{\frac{7}{6}}{7}[/tex]
= [tex]\frac{1}{6}[/tex] inch
Now we have to calculate number of days in which the plant grows [tex]6\frac{1}{6}[/tex] inches ≈ [tex]\frac{37}{6}[/tex] inch
Number of days = [tex]\frac{\text{Total growth}}{\text{Growth in one day}}[/tex]
= [tex]\frac{37}{6}[/tex] ÷ [tex]\frac{1}{6}[/tex]
= [tex]\frac{37}{6}[/tex] × 6
= 37 days ≈ 5 weeks and 2 days
It will take the plant 5 weeks 2 days to grow [tex]6\frac{1}{6}[/tex] inches.
If the manager at first city bank surveys a sample of 100 customers to determine how many miles they live from the bank, is the mean travel distance for this sample considered a parameter or a statistic? explain.
The mean travel distance for the sample of 100 customers surveyed by the manager at First City Bank is considered a statistic.
Explanation:The mean travel distance for the sample of 100 customers surveyed by the manager at First City Bank is considered a statistic.
In statistics, a parameter is a numerical characteristic of the whole population that can be estimated by a statistic. Since the manager is surveying only a sample of customers, the mean travel distance calculated from this sample is a statistic, not a parameter.
For example, if the manager had surveyed all customers of First City Bank, then the mean travel distance calculated from that data would be a parameter.
Find examples of decimals in a news paper or magazine,on television,or on the internet.write a real word problem in which multiplies decimals
Decimals can be found in various sources including the internet, and they are used in everyday activities like shopping online. The word problem involves a book sale where a discount is given in decimal form.
Explanation:Decimals are usually found in various sources such as newspapers, magazines, television, and predominantly on the internet. For example, when we read about the latest international currency exchange rates or the percentage rates in the stock market, we encounter decimals.
Let's create a real-world problem involving decimals: Sam is browsing a popular online bookstore. He found a book he wanted to buy for $5.49. However, there is a pop-up stating that for today only, all books are discounted by 0.15 (or 15%). How much would the book cost after the discount?
To find the solution, subtract the discount from the original price in decimal form i.e., $5.49 * 0.15 = $0.82 (approx). Then subtract this amount from the original price, $5.49 - $0.82 = $4.67. So, Sam will pay $4.67 for the book after discount.
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buckets of water dump out at 3:20. one bucket dump out every 16 minute the other every 14 minute. what time will they dump at the same time
a radio commercial for a loan company states: "you only pay for each $500 borrowed." If you borrow $1959 for 251 days, what amount will you repay, and what annual interest rate is the company actually charging? ( assume a 360- day year.)
Joe is playing a game with a regular die. If the number that turns up is even, he will gain 5 times the number that comes up. If it is odd, he will lose 10 times the number that comes up. He tosses a 3. Express the results as an integer.
Nia has number cards for 2,3,8,9 and 5. What are all the different ways Nia can arrange the cards to show only even numbers with the 2 in the ten- thousands place?