which of the diagram below represents the statement. if it is an insect then it has wings

Answers

Answer 1
The diagram that represent the statement is a Venn diagram in which:

An inner circle labeled "insects" is completely included inside an outer circle which is labeled "has wings".

In such diagram all the insects are inside the bigger set of things that have wings. That means that all the insects have wings but not all the things that have wings are insects.

That is exactly what the proposition if it is an insect then it has wings.

As per the proposition, having wings is a necessary condition to be insect, but it is not sufficient.

Related Questions

A cylinder has a radius of 1 inch and height of 1 inch.

What is the approximate volume of a cylinder?

Answers

volume = PI * radius^2* height

3.14 x 1^2 x 1

v=3.14 cubic inches

The answer is 3.14 or C. I just took the test.

Write the standard form of the line that has a slope of - and y-intercept of -2. Include your work in your final answer. Type your answer in the box provided or use the upload option to submit your solution.

Answers

You need to go from slope-intercept ([tex]y=mx+b[/tex]) to standard form ([tex]ax + by = c[/tex]).    

slope-intercept form of your provided values:  
[tex]y=-x-2[/tex]  
now, solve for x and y  
[tex]x+y=-2[/tex]  
  
Your answer is [tex]x+y=-2[/tex].
slpe intercept form is 
y = mx + b  where m=slope and b = y-intercept

so here we have
y = -x - 2

standard form is x + y = -2

A house cost $120,000 when it was purchased. The value of the house increases by 10% each year. Find the rate of growth each month and select the correct answer below.

Answers

well, the house is increasing by 10% each year, so whatever the current price is, the new price is THAT plus 10%, well, since THAT is 100%, shouldn't that be 100% + 10%, or 110%?

[tex]\bf \qquad \textit{Amount for Exponential Growth}\\\\ A=I(1 + r)^t\qquad \begin{cases} A=\textit{accumulated amount}\\ I=\textit{initial amount}\to &120,000\\ r=rate\to 10\%\to \frac{10}{100}\to &0.10\\ t=\textit{elapsed time}\\ \end{cases} \\\\\\ A=120000(1+0.10)^t\implies \begin{array}{lclll} A=120000(&1.1&)^t\\ &\uparrow \\ &rate\\ &of\\ &growth \end{array}[/tex]

1.1 is the decimal format, but you can simply multiply it by 100 to get the percentage, 1.1 * 100 = 110%

Graph the line y = -1/4x+2.

a. Sketch the line that is perpendicular to y = -1/4x+2 that passes through the point (5,5)

b. Write the equation of the perpendicular line.

c. Where do the lines intersect?

Answers

a- in image
b- 4x-15
c- (4,1)

Carmen is going to roll an 8-sided die 200 times. She predicts that she will roll a multiple of 4 twenty-five times. Based on the theoretical probability, which best describes Carmen’s prediction?

Answers

Sample space={1,2,3,4,5,6,7,8} = 8 possible outcomes
multiple of 4 ={4,8} = 2 favorable outcomes:

P(4 OR 8) = 2/8 = 1/4
Expected values after 200 rolls:

200 x P(4 or 8) = 200 x 1/4 = 50
The prediction is 50

Answer:

Carmen's prediction is low because 200 times  is 50.

Step-by-step explanation:

First of all we are going to define the sample space for this exercise.

The sample space is Ω = {1,2,3,4,5,6,7,8}

Given the event A : ''Roll an 8-sided die an get a multiple of 4''

The probability for the event A is

Because they are two numbers (4 and 8) over a total of eight numbers (1,2,3,4,5,6,7,8) that are multiple of 4.

Now, given the random variable X : ''Total of numbers multiples of 4 If she rolls

an 8-sided die 200 times''

X can be modeled as a Binomial random variable.

X ~ Bi (n,p)

X ~ Bi (200,)

In which n is the total times she rolls the 8-sided die and p is the success probability. We define a success as obtain a number multiple of 4.

The mean for this variable is

We answer that Carmen's prediction is low because 200 times  is 50.

An elevator descends into a mine shaft at the rate of 6 m/min. If the descendstarts from 20 meter above the ground level, how long will it take to reach - 340m?

Answers

it has to travel 20 meters before it gets to ground level, then another 340 meters till it reaches -340.....so it has to travel a total of 360 meters

and if it descends at a rate of 6 meters per minute...
360/6 = 60 minutes....or 1 hr to reach -340 <==

Evaluate the function f(x) = 4x -1 when x= -1 ..... f(-1) =___

Answers

4x-1 when x=-1
4(-1)= -4 *bam* That's your answer. 
Final answer:

To evaluate the function f(x) = 4x - 1 for x=-1, you first substitute -1 into the equation, then perform multiplication before subtraction as per the order of operations resulting in f(-1) = -5.

Explanation:

To evaluate the function f(x) = 4x - 1 when x is -1, we simply replace the variable x in the equation with -1. The equation becomes f(-1) = 4(-1) - 1.

Now to perform the operations indicated in the equation, we should start with multiplication before subtraction according to the order of operations.

The multiplication of 4 and -1 gives -4 so the equation becomes f(-1) = -4 - 1.

Finally subtracting 1 from -4 gives -5. Therefore, f(-1) = -5.

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A number is *K* units to the left of 0 on the number line. Describe the location of its opposite

Answers

K units is to the right of 0

Mark owns Siberian Husky sled dogs. He knows from data collected over the years that the weight of the dogs is a normal distribution. They have a mean weight of 52.5 lbs and a standard deviation of 2.4 lbs. What percentage of his dogs would you expect to have a weight between 47.7 lbs and 54.9 lbs?

Answers

Final answer:

To calculate the percentage of dogs with a weight between 47.7 lbs and 54.9 lbs, we need to use the properties of the normal distribution. We can expect that around 82.7% of Mark's dogs would have a weight within this range.

Explanation:

To calculate the percentage of dogs with a weight between 47.7 lbs and 54.9 lbs, we need to use the properties of the normal distribution. We know that the mean weight is 52.5 lbs and the standard deviation is 2.4 lbs.

First, we need to standardize the lower and upper bounds of the weight range using the formula: z = (x - mean) / standard deviation. For the lower bound, z = (47.7 - 52.5) / 2.4 = -1.96. For the upper bound, z = (54.9 - 52.5) / 2.4 = 1.

Next, we can use a standard normal distribution table or calculator to find the percentage of values between -1.96 and 1. The percentage is approximately 82.7%. Therefore, we can expect that around 82.7% of Mark's dogs would have a weight between 47.7 lbs and 54.9 lbs.

Final answer:

Using the normal distribution, calculations of z-scores, and a z-table to determine probabilities, we can expect approximately 81.85% of Mark's Siberian Husky sled dogs to weigh between 47.7 lbs and 54.9 lbs.

Explanation:

To determine the percentage of Mark's Siberian Husky sled dogs that weigh between 47.7 lbs and 54.9 lbs, we need to use the properties of the normal distribution. The mean weight of the dogs is 52.5 lbs and the standard deviation is 2.4 lbs. We can calculate the z-scores for 47.7 lbs and 54.9 lbs:

Z = (X - μ) / σ

For 47.7 lbs:

Z1 = (47.7 - 52.5) / 2.4 ≈ -2.0

For 54.9 lbs:

Z2 = (54.9 - 52.5) / 2.4 ≈ 1.0

Using a z-table or a statistical software, we can find the probabilities corresponding to these z-scores. The probability between Z1 and Z2 is the area under the curve in this range.

The probabilities associated with the z-scores are approximately 2.28% for Z1 (< -2.0) and 84.13% for Z2 (< 1.0). To find the percentage between Z1 and Z2, we subtract the smaller percentage from the larger one:

Percentage between 47.7 lbs and 54.9 lbs = 84.13% - 2.28% = 81.85%

Thus, we would expect that 81.85% of Mark's dogs have a weight between 47.7 lbs and 54.9 lbs.

Solve for w. 3w – 10 = -w – 8 + 3w

Answers

Combine like terms
3w-10=2w-8

Add 10 to both sides
3w= 2w+2

Subtract 2w from both sides
w=2

Final answer: w=2

If tan x° = 11 divided by r and cos x° = r divided by s, what is the value of sin x°?

Answers

[tex]\bf sin(\theta)=\cfrac{opposite}{hypotenuse} \qquad cos(\theta)=\cfrac{adjacent}{hypotenuse} \quad % tangent tan(\theta)=\cfrac{opposite}{adjacent}\\\\ -------------------------------\\\\ tan(x^o)=\cfrac{11}{r}\cfrac{\leftarrow opp}{\leftarrow adj}\qquad cos(x^o)=\cfrac{r}{s}\cfrac{\leftarrow adj}{\leftarrow hyp}\\\\\\ \boxed{sin(x^o)=\cfrac{11}{s}\cfrac{\leftarrow opp}{\leftarrow hyp}}[/tex]

Answer:

[tex]sin x = \frac{11}{s}[/tex]

Step-by-step explanation:

[tex]Tan x = \frac{11}{r}[/tex]

[tex]Cos x = \frac{r}{s}[/tex]

Property : [tex]\frac{sin \theta}{cos \theta}=Tan \theta[/tex]

So, [tex]\frac{sinx}{cosx}=Tan x[/tex]

Substitute the values

[tex]\frac{sinx}{ \frac{r}{s}}=\frac{11}{r}[/tex]

[tex]sinx =\frac{11}{r} \times \frac{r}{s}[/tex]

[tex]sinx =\frac{11}{s}[/tex]

Hence the value of sin x° is [tex]\frac{11}{s}[/tex]

What is the perimeter of a square with a side length of 5x -8 and a bottom length of 3x of a square?

Answers

5x-8=3x               (This is because all sides are equal in a square)
-5x     -5x
-8=-2x
x=4

4(3)=20-8
12=12

12+12+12+12
48

The required perimeter of the square is 48 units as of the given condition.

Given that,
The perimeter of a square with a side length of 5x -8 and a bottom length of 3x of a square is to be determined.


What is the perimeter?

Perimeter is the measure of the figure on its circumference.

What is simplification?

The process in mathematics to operate and interpret the function to make the function or expression simple or more understandable is called simplifying and the process is called simplification.

Here,
The length of all sides of the square is always remains equal,
5x - 8 = 3x
2x = 8
x = 4
Side length,
3x = 3(4) = 12
Now,
The perimeter of the square is 4-time sides,
Perimeter = 4 (12)

Perimeter = 48 units.

Thus, the required perimeter of the square is 48 units as of the given condition.

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Does any one know how to solve this -4n^2-2n=-6-7n-5n^2

Answers

[tex]-4n^2-2n=-6-7n-5n^2 \\ -4n^2-2n+6+7n+5n^2=0\\n^2+5n+6=0 \\ n^2+2n+3n+6=0 \\ n(n+2)+3(n+2)=0 \\ (n+2)(n+3)=0 \\ n+2=0 \ \ \ \ or \ \ \ \ n+3=0\\n=-2 \ \ \ \ \ \ \ \ \ \ \ \ \ n=-3[/tex]

Answer: n=-2, n=-3
-4n^2-2n=-6-7n-5n^2

Add 5n^2 to both sides
n^2-2n=-6-7n

Add 7n to both sides
n^2+5n=-6

Add 6 to both sides to put the equation into quadratic standard form
n^2+5n+6=0

Factor the equation
(n+2)(n+3)=0

3+2=5, 3*2=6

To solve a quadratic equation, find roots using Zero Product Property.
(n+2)=0
n=-2

(n+3)=0
n=-3

Final answers: n=-3, n=-2

what is the answer to this equation 2(3-X)=-16

Answers

2(3 - x) = -16
3 - x = -16/2
3 - x = -8
-x = -8 - 3
-x = - 11
x = 11
[tex]Hello, again \\ 2(3)-x - (-16) \\ -2(x) - 11 \\ x - 11 = 0 ; x +11 = 11x ; 11 + 0 = 11 \\ One SolutionWasFoundInHere [/tex] 
[tex]x = 11 [/tex]

[tex]Good \\ Luck \\ On \\ Your \\Assignment [/tex]

Rationalize the denominator of sqrt of -49 over (7-2i)-(4+9i)

Answers

To rationalize the denominator of the expression will be as follows;
-49/[(7-2i)-(4+9i)
=-49/[7-4-2i+9i]
=-49/[3+7i]
to rationalize the denominator we multiply both the numerator and the denominator by [3-7i]
hence;
-49/[3+7i]*[3-7i]/[3-7i]
=[-49(3-7i]/(9+49]
=(-147+343i)/58
The answer is (-147+343i)/58

When BA = 10 ft, find the area of the region that is NOT shaded. Round to the nearest whole number.

A) 52 ft^2

B) 262 ft^2

C) 43 ft^2

D) 305 ft^2

Answers

(1) Area of the whole circle:
                        A = πr²
Substitute the value of BA to r,
                         A = (π)(10 ft)² = 314.16 ft²

(2) Area of the sector is calculated through the equation,
                       As = πr²(x/360°)
where x is the intercepted angle. Substituting the values,
                       As = π(10 ft)²(60°/360°) = 52.36 ft²

(3) Area of the equilateral triangle BAJ,
                      At = (√3)(a2²/4
where a is also equal to r or BA. Substituting,
                      At = (√3)(10 ft)²/4 = 43.30 ft²

The area of the region not shaded is equal to,
                 = (A) - (As - At)

Substituting,
                 = (314.16 ft²) - (52.36 ft² - 43.30 ft²)
                  Area = 305.10 ft²

Therefore, the answer to this answer is letter D. 

Justin is a software salesman. his base salary is $1500 , and he makes an additional $40 for every copy of english is fun he sells. let p represent his total pay (in dollars), and let n represent the number of copies of english is fun he sells. write an equation relating p to n . then use this equation to find his total pay if he sells 23 copies of english is fun.

Answers

P = total pay
n = number of copies

P = 1,500 + 40n

Therefore, if Justin sells 23 copies, his total pay will be:

P = 1,500 + 40(23)

P = $2,420

Koch's kinky curve is created by starting with a straight segment and replacing it with four segments, each 1/3 as long as the original segment. So, at the second stage the curve has three bends. At the next stage, each segments replaced by four segments, and so on. How many bends does this curve have at the third stage? The fourth stage? The nth stage?

Answers

stage           # segments                     # bends

1st stage      1 segment                      1 - 1 = 0 bends

2nd stage     4*1 segments                 4 - 1 = 3 bends

3rd stage      4*4 = 16 segments        16 - 1 = 15 bends

The number of bends is equal to the number of segments less 1, becasuse two segments are required to make one bend.

4th stage      4*4*4 = 64 segments      64 - 1 = 63 bends.

nth stage      4^(n-1) segments             4^(n-1) - 1 bends

A librarian randomly selects 25 returned books one day and finds that three of them were returned late. based on this sample, how many of the 410 returned books that day are likely to be late returns?

Answers

[tex]\dfrac{3}{25}=\dfrac{x}{410}\\ 25x=1230\\ x\approx49[/tex]

Approx. 49 books.

Why is the mean greater than the median in right skewed?

Answers

Right skewed makes a bar graph table have a right tail, meaning the left-side of the data is higher than that of the left-side. The median does not change based on the size of the data but the mean does because the left-side of the data has grown, when you add them all together and divide by the number of data sets, it will be larger by a certain amount.

A copy center offers its customers two different pricing plans for black and white photocopies of 8.5 in. by 11 in. pages. Customers can either pay $0.08 per page or pay $7.50 for a discount card that lowers the cost to $0.05 per page. Write and solve an equation to find the number of photocopies for which the cost of each plan is the same.

A) .08c .05c - 7.50; c = 250

B) . 05c .08c + 7.50; c = 22.5

C) 7.50 = .08c + 05c; c = 58

D) .08c = .05c + 7.50; c = 250

Answers

Answer: Writting the equation and solving it, the answer is option D) .08c = .05c + 7.50; c = 250


Solution:

If the number of photocopies is c

Plan 1: Customers can pay $0.08 per page

The cost with plan 1 is: C1=0.08c


Plan 2: Customers can pay $7.50 for a discount card that lowers the cost to $0.05 per page.

The cost with plan 2 is: C2=7.50+0.05c


We want to find the number of photocopies for which the cost of each plan is the same, then we equal the cost of each plan:

C1=C2

Replacing C1 by 0.08c and C2 by 7.50+0.05c

0.08c=7.50+0.05c


Solving this equation for c: Subtracting 0.05c both sides of the equation:

0.08c-0.05c=7.50+0.05c-0.05c

Subtracting:

0.03c=7.50

Dividing both sides of the equation by 0.03

0.03c/0.03=7.50/0.03

c=250

Answer:

.08c = .05c + 7.50; c = 250

Step-by-step explanation:

i got a 100 on the test trust!

STVU is an isosceles trapezoid. If SV = 3x + 1 and TU = x + 21, find the value of x.

Answers

Definition of isos trapezoid=> A trapezoid with congruent legs.
Theorem=> Diagonals in a isosceles triangle are congreunt.
Answer=> SV is a diagonal and so is TU therefore they are equal.
Set aside=> 3x+1=x+21
Solve=> 2x=20
x=10

Answer:

The value of x is 10.

Step-by-step explanation:

Given information: STVU is an isosceles trapezoid, SV = 3x + 1 and TU = x + 21.

According to the properties of isosceles trapezoid, then diagonals of an isosceles trapezoid are equal.

SV and TU are diagonals of the isosceles trapezoid, so

[tex]SV=TU[/tex]

[tex]3x+1=x+21[/tex]

Separate like terms.

[tex]3x-x=21-1[/tex]

[tex]2x=20[/tex]

Divide both sides by 2.

[tex]x=10[/tex]

Therefore the value of x is 10.

At a certain time of the day, a tree 15m tall casts a shadow of 12m, while a second tree casts a shadow of 20m. how tall is that?

Answers

the two triangles created by the trees and their shadows are similar triangles. by definition the ratio created by matching sides are equal to the ratio of either of the other matching sides.

so the ratio of the shadow sides is equal to the ratio of the tree sides. the 2 shadow sides are 12 and 20 so 12/20 is the ratio. one tree side is 15 and we will say the other is x so their ratio is 15/x.

since.the 2 ratios are equal we can say:
12/20 = 15/x
12x = 300
x = 25.

so the tree is 25m tall

Students were asked to measure a string as part of a physics experiment. The actual length of the string was 7.35 cm long. Which of the following groups of data show measurements from the most accurate group and why?

7.35 cm, 7.82 cm, 7.12 cm, because one of the measurements is closest to the actual length.
6.95 cm, 6.93 cm, 6.97 cm, because these have the most agreement between the measurements.
7.32 cm, 7.37 cm, 7.39 cm, because this group’s measurements are closest to the actual length. - My answer
7.90 cm, 7.91 cm, 7.89 cm, because these have the most agreement between the measurements.

Answers

We can calculate the average for each data set to check the closest group to the actual measurement

Data set 1: 
Mean= (7.35+7.82+7.12) ÷ 3 = 7.43

Data set 2:
Mean = (6.95+6.93+6.97) ÷ 3 = 6.95

Data set 3:
Mean =  (7.32+7.37+7.39) ÷ 3 = 7.36

Data set 4:
Mean = (7.90+7.91+7.89) ÷ 3 = 7.9

From our calculation, the closest mean value to the actual length is data set 3, hence the data set 7.32, 7.37, 7.39 is the most accurate group

Iliana was part of a group that was working on changing 0.4 repeated to a fraction. Each member of the group had a different answer. Which answer is correct?

Answers

[tex]\bf 0.444444444\overline{4}\impliedby \textit{and keeps on going}\\\\ -------------------------------\\\\ \textit{let's say }\boxed{x=0.444444444\overline{4}}\quad \textit{ thus }10\cdot x=4.44444444\overline{4} \\\\\\ \textit{wait a minute! }4.44444444\overline{4}\textit{ is really just }4+0.444444444\overline{4}[/tex]

[tex]\bf \textit{but we know }x=0.444444444\overline{4} \textit{ so then }4+0.444444444\overline{4}=\boxed{4+x} \\\\\\ \textit{wait a second! }10\cdot x\implies 10x=4.444444444\overline{4}=4+x \\\\\\ thus\qquad 10x=4+x\implies 10x-x=4\implies 9x=4\implies \boxed{x=\cfrac{4}{9}}[/tex]

you can check in your calculator.

anyhow, to get the "recurring decimal to fraction", you start by setting to some variable, "x" in this case, then move the repeating part to the left of the point by multiplying it by some power of 10, and then do the equating.

Iliana was part of a group that was working on changing 0.4 repeated to a fraction. The answer is 2.25.

How to convert percent to fraction and decimal?

Percentage counts the number compared to 100.

So, if we have a%, that means for each 100, there are 'a' parts. If we divide each of them with 100, we get:

For each 1, there are a/100 parts.

Iliana was part of a group that was working on changing 0.4 repeated to a fraction.

Each member of the group had a different answer.

Let x be 0.444444[tex]\bar 4[/tex]

So,

4 / 10 = 0.4

4 / 9 = 0.4444444...

9/ 4 = 2.25

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(05.02)
Two quantities are related, as shown in the table:




x

y

2 3
4 4
6 5
8 6


Which equation best represents the relationship?
y = 1 over 2 x + 2
y = 1 over 2 x + 1
y = x + 2 y = 2x + 1

Answers

first equation y=1/2x +2

x=2 = 1/2(2) +2 =1+2 =3

x=4 = 1/2(4)+2 = 2+2 =4


first equation  is the answer

Answer:

[tex]y=\dfrac{1}{2}x+2[/tex]

A is correct

Step-by-step explanation:

Given: Table of x and y

 x  :  2    4     6     8

 y  :  3    4     5     6

Using two point find the slope:

(2,3) and (4,4)

[tex]Slope=\dfrac{4-3}{4-2}[/tex]

[tex]\text{Slope }=\dfrac{1}{2}[/tex]

Now we find slope using last two point

(6,5) and (8,6)

[tex]\text{Slope }=\dfrac{6-5}{8-6}[/tex]

[tex]\text{Slope }=\dfrac{1}{2}[/tex]

Slope is equal. Thus, The given relation is linear.

[tex]y-3=\dfrac{1}{2}(x-2)[/tex]

[tex]y=\dfrac{1}{2}x+2[/tex]

Hence, The relation represents a linear equation [tex]y=\dfrac{1}{2}x+2[/tex]

juanita and lauren are painting a circular mural on one wall of the community center the area of the mural is 88 square meters what is the radius.

Answers

To set up this equation, you would enter 88=pi times radius^2. Then, you would divide 88 by pi and set it up equal to radius^2. Therefore the radius^2 equals approximately 28.0112. To find the radius, you need to square root that number. 28.0112 square rooted is approximately 5.293. Therefore, 5.293 is the radius length.

Answer:

Radius of circular mural = 5.29 m

Step-by-step explanation:

Area of circle is given by πr².

Juanita and Lauren are painting a circular mural on one wall of the community center the area of the mural is 88 square meters

Area of circle = 88 square meters

That is

        πr² = 88

        [tex]r^2=\frac{88}{\pi}=28.01\\\\r=5.29m[/tex]

Radius of circular mural = 5.29 m

Find the GCF. 18x 3 and 30x 5

A.
6x 5

B.
90x 3

C.
6x 3

D.
90x 5

Answers

18x^3 and 30x^5

To find the GCF, first look at ur coefficients....The GCF of ur coefficients (18 and 30) is 6

now look at ur variables....pick the one with the lowest exponent...that would be x^3

so the GCF of these 2 terms is : 6x^3

The two-way table shows the number of students in a school who have hamsters and/or dogs as pets.








Have Hamsters


Do Not Have Hampsters


Total




Have Dogs

16

24

40




Do Not Have Dogs

25

35

60




Total

41

59

100



How many more students have hamsters than dogs?
1
5
8
9

Answers

Answer:

1

Step-by-step explanation:

There are a total of 16+25 = 41 students that own hamsters.

There are a total of 16+24 = 40 students that own dogs.

This is a difference of 41-40 = 1.

Answer: 1

Step-by-step explanation:

Total number of students that own hamsters 16+25 = 41.

Total of students that own dogs 16+24 = 40.

To get how many more students own hamsters than dogs, we find the difference;

That is 41-40 = 1.

Good luck

Find the distance between the points with coordinates (5, 7) and (-3, 1)

Answers

You would use the function root(Xsub2-Xsub1)^2+(Ysub2-Ysub1)^2.

Now plug in your numbers.

This gives you root(7-1)^2+(5-(-3))^2.

Simplify to root(6)^2+(8)^2. Simplify again to root36+64.

Simplify one more time to root 100. now solve.

Your answer is 10.
Other Questions
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