Which must be the same when comparing 1 mol of oxygen gas, O2, with 1 mol of carbon monoxide gas, CO?

A. the mass

B. the volume

C. the number of molecules

D. the number of oxygen atoms

Answers

Answer 1
A mole is a rather unusual unit of measurement. It is defined by a specific number of particles, molecules, atoms, or any other unit. 
That number happens to be 6.022×10²³. 
When we talk about a mole of water, then, we refer to 6.022×10²³ molecules of water. 

Comparing 1 mole of 02 with 1 mole of CO:
This means means that both quantities will have the same number of molecules. The answer is C.

It may be tempting to select D, since it relates to the number of atoms rather than mass or volume, and moles are related to this idea. However, keep in mind that one mole of O2 will actually have twice as much oxygen atoms as one mole of CO, since there are two oxygen atoms per O2 molecule and only 1 oxygen atom per CO molecule.

Related Questions

Which phrase best defines erosion? A. physically breaking rocks apart B. cementing bits of rock together C. chemically breaking rocks apart D. Moving bits of rock from place to place

Answers

The answer is D. Moving bits of rock from place to place. 
BLACKBEAR301    is correct. The answer is D

How many total atoms are in 0.250g of P2O5?

Answers

1. Calculate no. of moles by dividing  mass given/molar mass 
= 0.250 /283.8 
2. Now multiply no. of moles with avogadro's no.
3. The answer indicates no. of total atoms.. 

Explanation:

According to the mole concept, there are [tex]6.022 \times 10^{22}[/tex] atoms present.

It is given that mass is 0.250 g. And, number of moles are equal to mass divided by molar mass.

Mathematically,       No. of moles = [tex]\frac{mass}{\text{molar mass}}[/tex]

As molar mass of [tex]P_{2}O_{5}[/tex] is 283.88 g/mol. Therefore, putting given values into the above formula as follows.

                 No. of moles = [tex]\frac{mass}{\text{molar mass}}[/tex]

                                       = [tex]\frac{0.250 g}{283.88 g/mol}[/tex]

                                       = 0.0008 mol

Hence, number of atoms present in 0.0008 mol are as follows.

                      [tex]0.0008 mol \times 6.022 \times 10^{22} atoms/mol[/tex]

                     = 0.0048 atoms

Thus, we can conclude that there are 0.0048 atoms in 0.250 g of [tex]P_{2}O_{5}[/tex].

Draw structures for all constitutional isomers with the molecular formula c2h5cl

Answers

Constitutional isomers are compounds that have the same molecular formula but different connectivity.

To determine whether two molecules are constitutional isomers, just count the number of each atom in both molecules and see how the atoms are arranged.
If both molecules have the same count for all of the different atoms, and the atoms are arranged in different ways (i.e. their connectivity is different), then they will be constitutional isomers.

In this case C2H5Cl will not have any constitutional isomer. Because you can attach the Cl on first carbon or second carbon, both structure will be same. There will only exist one structure. Figure is attached
Final answer:

Two constitutional isomers exist for C2H5Cl: 1-chloroethane (ethyl chloride) and 2-chloroethane (chloroethane), with chlorine bonded to different carbon atoms in each isomer.

Explanation:

The student has asked to draw structures for all constitutional isomers with the molecular formula C2H5Cl, which is a chemical exercise focusing on understanding the different ways in which atoms can be rearranged in space to create molecules with the same molecular formula but different structures.

There are actually only two constitutional isomers with the formula C2H5Cl. These isomers are:

1-chloroethane (ethyl chloride): CH3CH2Cl2-chloroethane (chloroethane): CH3ClCH3

In these structures, the chlorine atom is bonded to different carbon atoms, resulting in molecules that have different physical and chemical properties.

Compare the ways in which atoms combine to form molecules and compounds

Answers

Compounds consist of molecules. Molecules consist of more than one type ofatoms bonded to each other. These bonds are created in a variety of ways but they all form when they share or give/take electrons. Electrons that take part in the bonds are in the outer part of the atom.

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in the early studies of chemistry, scientists used properties and changed to help identify compounds. this is still done today. if you were given the following observation about salt water, how would you classify it? “when electricity flows through a flask of salt water, bubbles form in the water. these bubbles, when collected, will burn.”

Answers

The salt water is a mixture because the salt and the water can be separated from each other. The dissolution of salt inside water is a physical change.  At the same time, the salt water is an electrolyte, because it conducts electricity. The electricity that was pass through the water led to the decomposition of the water; those bubbles that form inside the water represent oxygen gas which is a product of decomposition of water, therefore the electricity that was passed through the salt water has caused chemical change to occur inside the salt water.

When aqueous solutions of lead(ii) nitrate (pb(no3)2) and potassium phosphate (k3po4) are mixed, the products are solid lead(ii) phosphate and aqueous potassium nitrate. write the balanced chemical equation for this reaction. (include states-of-matter under the given conditions in your answer. use the lowest possible whole number coefficients.)?

Answers

Hello)
3Pb(NO3)2 + 2K3PO4 = Pb3(PO4)2↓ + 6KNO3

Answer: The balanced chemical equation is written below.

Explanation:

Balanced chemical equation is defined as the equation in which total number of individual atoms on the reactant side will be equal to the total number of individual atoms on the product side. These equations follow law of conservation of mass.

The chemical equation for the reaction of lead (II) nitrate and potassium phosphate follows:

[tex]3Pb(NO_3)_2(aq.)+2K_3PO_4(aq.)\rightarrow Pb_3(PO_4)_2(s)+6KNO_3(aq.)[/tex]

By Stoichiometry of the reaction:

3 moles of aqueous lead (II) nitrate reacts with 2 moles of aqueous solution of potassium phosphate to produce 1 mole of solid lead (II) phosphate and 6 moles of aqueous solution of potassium nitrate.

Hence, the balanced chemical equation is written above.

Describe the four main spheres of Earth. 1. lithosphere: 2. hydrosphere: 3. atmosphere: 4. biosphere:

Answers

HYDROSPHERE: It is the liquid water component of the Earth. It contain seas, lakes, ponds, etc., It covers 70% of the Earth. ATMOSPHERE: It is another outer part of the earth. It contain nitrogen, oxygen, argon and other gases. BIOSPHERE: It is the region of the surface and atmosphere of the earth.

You have a racemic mixture of (+)-2-butanol and (-)-2-butanol. the (+) isomer rotates polarized light by +13.5∘. what is the observed rotation of your mixture?

Answers

 The rotation of the polarized of the light of your mixture is 0, (+) isotopes spins it one way and l spins it equally back the other way. Racemic mixture or racemate is one that has equal amounts right- and left-handed enantiomers of a chiral molecule.

Answer:

The degree of rotation of racemic mixture will equal 0° 

Explanation:

Hello,

(-) isomer is in other words the Enantiomer of (+) isomer and as long as the statement indicates that (+)-isomer optical rotation is + 13.5°, the optical rotation of (-)-isomer will be the same value and degree but with the inverse sign which is -13.5°.

In such a way, the degree of rotation of the taken into account racemic mixture will equal 0° 

This is in this way due to the fact that the racemic mixture has equal amount of both enantiomers.

Best regards.

the degree to which two separate structures that are close together can be distinguished in an image is called__________.       (science)

Answers

The answer to this is: resolution

The degree to which two separate structures that are close together can be distinguished in an image is called resolution.

What is image?

A visual depiction of anything is what an image is. It may be this double, three-dimensional, or feed into to the visual system in another way to provide information.

To be a graphic illustration, a picture does not need to utilise the complete visual system. A common example is a greyscale picture, which use the visual system's responsiveness to brightness throughout all wavelengths without accounting for differing colors. The degree to which two separate structures that are close together can be distinguished in an image is called resolution.

Therefore, the degree to which two separate structures that are close together can be distinguished in an image is called resolution.

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what is the density of an unknown if 7.82g of it occupies a volume of 3.63ml

Answers

just divide 7.82 by 3.63
=2.15 g/ml

If we had 11.3 g of nitrogen and 2 g of hydrogen, how much nitrogen would remain if all the hydrogen was consumed? g

Answers

Hydrogen reacts with nitrogen to produce ammonia based on the following equation:

3H2 + N2 ........> 2NH3

This means that each 6 grams of hydrogen react with 28 grams of nitrogen. To know how many grams of nitrogen are required to react with 2 grams of hydrogen, we will simply do cross multiplication as follows:

mass of nitrogen = (2 x 28) / 6 = 9.334 grams

Therefore, if we have 11.3 grams of nitrogen, 9.334 grams would react with 2 grams of hydrogen.

remaining mass of nitrogen = 11.3 - 9.334 = 1.966 grams


Sodium hydroxide, NaOH; sodium phosphate, Na3PO4; and sodium nitrate, NaNO3, are all common chemicals used in cleanser formulation. Rank the compounds in order from largest mass percent of sodium to smallest mass percent of sodium.

Answers

NaOH:
 (1x23) / (1x23 + 1x16 + 1x1) = 57.5 %

Na3PO4 
 (3x23) / (3x23 + 1x31 + 4x16) = 42.07%

NaNO3
 (1x23) / (1x23 + 1x14 + 3x16) = 27.05%

So, NaOH > Na3PO4 > NaNO3 

The valence shell holds up to two electrons in which 2 elements? a. H and C b. H and Li c. H and He d. He and Be

Answers

The answer is C. H and HE

Answer : The correct option is, (d) He and Be

Explanation :

First we have to determine the electronic configuration of the following elements.

The electronic configuration of hydrogen (H) is:

[tex]1s^1[/tex]

The electronic configuration of carbon (C) is:

[tex]1s^22s^22p^2[/tex]

The electronic configuration of lithium (Li) is:

[tex]1s^22s^1[/tex]

The electronic configuration of helium (He) is:

[tex]1s^2[/tex]

The electronic configuration of beryllium (Be) is:

[tex]1s^22s^2[/tex]

From the electronic configuration of the elements we conclude that, the hydrogen element has '1' valence electron, carbon element has '4' valence electrons, lithium element has '1' valence electron, helium element has '2' valence electrons and beryllium element has '2' valence electrons.

Thus, the helium and beryllium are the elements that holds up to two electrons in their outermost shell.

Hence, the correct option is, (d) He and Be

What are the necessary steps to prevent oxidation during high temperature

Answers

CZTS film remains stoichiometric up to 400C.However, the composition of the thin film becomes Zn-poor above 450 C because Zn vaporizes at the elevated temperatures.This leads to the loss of zinc.It can be compensated by spraying Zn and S vapors. But then the sulphur vapours may oxidize.In order to avoid it, CZTS films are taken out of the deposition chamber and are exposed to the atmosphere before sulphurization is performed to grow thin CZTS polycrystalline thin films. Moisture gets adsorbed on the surface and prohibits oxidation of S. The adsorbed moisture later leaves during annealing.This, IN LINE, sulphurization prevents oxidation.JIMBO ET AL employed this method with sputtered CZTS precursor films to prevent oxidation.

Calculate the coulombic force of attraction between ca2+ and o2− in cao, which has the nacl-type structure

Answers

We determine the Coulombic force using the Coulomb's Law:

F = kQ₁Q₂/d²
where
k is equal to 9×10⁹ N·m²/C²
Q₁ and Q₂ are the charges of the two particles
d is the distance between them

For this problem, Q₁ = +2(0.16×10⁻¹⁸ C) and Q₂ = -2(0.16×10⁻¹⁸ C), because a single electron or proton has a charge of 0.16×10⁻¹⁸ C. The distance between the two ions is the sum of their radii.
d = radius of Ca²⁺ + radius of O²⁻
d = 0.106×10⁻⁹ m + 0.132×10⁻⁹ m
d = 0.238×10⁻⁹ m

F = (9×10⁹ N·m²/C²)(+2(0.16×10⁻¹⁸ C))(-2(0.16×10⁻¹⁸ C))/(0.238×10⁻⁹ m)²
F = 1.017×10¹¹ N

Which of the following is a heterogeneous mixture

Answers

A heterogeneous mixture is one where the different components, or parts, can be easily identified and possibly separated back out. An example would be oil and water. When mixing those to ingredients, it would be easy to look and see the separation of the oil and water.

According to the bohr model of the atom, which electron transition would correspond to the shortest wavelength line in the visible emission spectra for hydrogen? hints

Answers

n = 6 to n = 2

Further explanation  

From several sources, we have prepared the following answer choices:

A. n = 2 to n = 5  

B. n = 6 to n = 4  

C. n = 3 to n = 2  

D. n = 6 to n = 2  

We will determine which electron transition would correspond to the shortest wavelength line in the visible emission spectra for hydrogen.  

The amount of energy released or absorbed by electrons when moving from n₁ level to n₂ level is equal to  

[tex]\boxed{ \ \Delta E = -13.6 \Big( \frac{1}{n_2^2} - \frac{1}{n_1^2} \Big) \ }[/tex]  in eV.

This energy difference is equal to [tex]\boxed{ \ hf = \frac{hc}{\lambda} \ }[/tex], where f and λ are the frequency and wavelength of the radiation emitted or absorbed.

Thus, the wavelength is inversely proportional to the energy difference from the electron transition. To get the shortest wavelength, it is determined by the largest ΔE.  

From the formula above, we practically only need to calculate part [tex]\boxed{ \ \Big( \frac{1}{n_2^2} - \frac{1}{n_1^2} \Big) \ }[/tex] which is directly proportional to ΔE.  Then from the results of the calculation of this section, we will get the shortest wavelength from the largest result..

A. n₁ = 2 to n₂ = 5  

[tex]\boxed{ \ \Big( \frac{1}{5^2} - \frac{1}{2^2} \Big) \ }[/tex]  

[tex]\boxed{ \ -\frac{21}{100} \ }[/tex]

By taking the absolute value, we get [tex]\boxed{ \ 0.210 \ }[/tex]

B. n₁ = 6 to n₂ = 4  

[tex]\boxed{ \ \Big( \frac{1}{4^2} - \frac{1}{6^2} \Big) \ }[/tex]  

[tex]\boxed{ \ \frac{5}{144} \ }[/tex]

We get [tex]\boxed{ \ 0.0347 \ }[/tex]

C. n₁ = 3 to n₂ = 2  

[tex]\boxed{ \ \Big( \frac{1}{2^2} - \frac{1}{3^2} \Big) \ }[/tex]  

[tex]\boxed{ \ \frac{5}{36} \ }[/tex]

We get [tex]\boxed{ \ 0.1389 \ }[/tex]

D. n₁ = 6 to n₂ = 2  

[tex]\boxed{ \ \Big( \frac{1}{2^2} - \frac{1}{6^2} \Big) \ }[/tex]  

[tex]\boxed{ \ \frac{2}{9} \ }[/tex]

We get [tex]\boxed{ \ 0.222 \ }[/tex]

The last calculation above shows the greatest results so that the shortest wavelength is undoubtedly gained from the electron transition n = 6 to n = 2.

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Keywords: according to the Bohr model of the atom, which electron transition would correspond, to the shortest wavelength, the visible emission spectra for hydrogen, energy, inversely proportional

The electronic transition from [tex]\boxed{{\text{D}}{\text{. n}} = {\text{6 to n}} = {\text{2}}}[/tex] corresponds to the shortest wavelength.

Further explanation:

Rydberg equation describes the relation of wavelength of spectral line with the transition values. The expression for Rydberg equation is as follows:

[tex]\dfrac{1}{\lambda } = \left( {{{\text{R}}_{\text{H}}}} \right)\left( {\dfrac{1}{{{{\left( {{{\text{n}}_{\text{1}}}} \right)}^2}}} - \dfrac{1}{{{{\left( {{{\text{n}}_{\text{2}}}} \right)}^2}}}} \right)[/tex]  …… (1)                                                  

Here,

[tex]\lambda[/tex] is the wavelength of spectral line

[tex]{{\text{R}}_{\text{H}}}[/tex] is Rydberg constant that has the value  

[tex]{{\text{n}}_{\text{1}}}[/tex] and [tex]{{\text{n}}_{\text{2}}}[/tex] are the two positive integers, where  .

Rearrange equation (1) to calculate  .

[tex]\lambda = \dfrac{1}{{\left( {1.097 \times {{10}^7}{\text{ }}{{\text{m}}^{ - 1}}} \right)\left( {\dfrac{1}{{{{\left( {{{\text{n}}_1}} \right)}^2}}} - \dfrac{1}{{{{\left( {{{\text{n}}_{\text{2}}}} \right)}^2}}}} \right)}}[/tex]                                        …… (2)

A. n = 2 to n = 5

Substitute 2 for [tex]{{\text{n}}_{\text{1}}}[/tex] and 5 for [tex]{{\text{n}}_{\text{2}}}[/tex] in equation (2).

 [tex]\begin{aligned}\lambda&= \frac{1}{{\left( {1.097 \times {{10}^7}{\text{ }}{{\text{m}}^{ - 1}}} \right)\left( {\frac{1}{{{{\left( 2 \right)}^2}}} - \frac{1}{{{{\left( 5 \right)}^2}}}} \right)}} \\&= 4.34 \times {10^{ - 7}}{\text{ m}}\\\end{aligned}[/tex]

B. n = 6 to n = 4

Substitute 4 for [tex]{{\text{n}}_{\text{1}}}[/tex] and 6 for [tex]{{\text{n}}_{\text{2}}}[/tex] in equation (2).

 [tex]\begin{aligned}\lambda&= \frac{1}{{\left( {1.097 \times {{10}^7}{\text{ }}{{\text{m}}^{ - 1}}} \right)\left( {\frac{1}{{{{\left( 4 \right)}^2}}} - \frac{1}{{{{\left( 6 \right)}^2}}}} \right)}}\\&= 2.63 \times {10^{ - 6}}{\text{ m}}\\\end{aligned}[/tex]

C. n = 3 to n = 2

Substitute 2 for [tex]{{\text{n}}_{\text{1}}}[/tex] and 3 for [tex]{{\text{n}}_{\text{2}}}[/tex] in equation (2).

 [tex]\begin{aligned}\lambda  &= \frac{1}{{\left( {1.097 \times {{10}^7}{\text{ }}{{\text{m}}^{ - 1}}}\right)\left( {\frac{1}{{{{\left( 2 \right)}^2}}} - \frac{1}{{{{\left( 3 \right)}^2}}}} \right)}} \\ &= 6.56 \times {10^{ - 7}}{\text{ m}}\\\end{aligned}[/tex]

D. n = 6 to n = 2

Substitute 2 for [tex]{{\text{n}}_{\text{1}}}[/tex] and 6 for [tex]{{\text{n}}_{\text{2}}}[/tex] in equation (2).

 [tex]\begin{aligned}\lambda&= \frac{1}{{\left( {1.097 \times {{10}^7}{\text{ }}{{\text{m}}^{ - 1}}} \right)\left({\frac{1}{{{{\left( 2 \right)}^2}}} - \frac{1}{{{{\left( 6 \right)}^2}}}}\right)}} \\&= 4.10 \times {10^{ - 7}}{\text{ m}}\\\end{aligned}[/tex]

The value of [tex]\lambda[/tex] for transition from n = 6 to n = 2 is the least and therefore this transition corresponds to the shortest wavelength.

Learn more:

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Answer details:

Grade: Senior School

Subject: Chemistry

Chapter: Atomic structure

Keywords: Rydberg constant, wavelength, n1, n2, positive integers, transition, 2, 6, 3, 5, transition, Rh, spectral line, shortest wavelength.

A compound has a molar mass of 44.01 g/mol. What is its identity?

Answers

Final answer:

The substance with a molar mass of 44.01 g/mol is carbon dioxide (CO2), which can be deduced by calculating the combined molar masses of one carbon atom and two oxygen atoms.

Explanation:

The question concerns the identification of a compound with a molar mass of 44.01 g/mol. One well-known substance with this molar mass is carbon dioxide (CO2). To arrive at this conclusion, one can examine the atomic masses of carbon and oxygen. Carbon has a molar mass of about 12.01 g/mol, while oxygen has a molar mass of about 16.00 g/mol. Given that carbon dioxide is composed of one carbon atom and two oxygen atoms, the total molar mass can be calculated as follows: 12.01 amu (for carbon) + 2 × 16.00 amu (for each oxygen) = 44.01 amu, which corresponds to g/mol when talking about molar mass. Hence, the molecular mass of carbon dioxide is 44.01 g/mol.

If 0.250 g of a gas sample represents 1.05x10–2 mol, what is the molar mass of the gas?

Answers

23.8 g/mol Since the definition of molar mass is mass per mole, just divide the mass of the sample by the number of moles you have. So 0.250 g / 1.05x10^-2 mol = 23.8095 g/mol Since our input data only has 3 significant figures, you need to round the result to 3 significant figures. 23.8095 g/mol rounds to 23.8 g/mol

A dilute solution is prepared by transferring 40.00 ml of a 0.3433 m stock solution to a 750.0 ml volumetric flask and diluting to mark. what is the molarity of this dilute solution?

Answers

We are given with the initial volume of the substance and the molarity. The first thing that needs to be done is to multiply the equation in order to obtain the number of moles such as shown below.
  
    number of moles = (40 mL) x (1 L / 1000 mL) x (0.3433 moles / L)
           number of moles = 0.013732 moles

To get the value of the molarity of the diluted solution, we divide the number of moles by the total volume.
          molarity = (0.013732 moles) / (750 mL / 1000 mL/L) = 0.0183 M

Similarly, we can solve for the molarity by using the equation,
           M₁V₁ = M₂V₂
Substituting the known values in the equation,
     (0.3433 M)(40 mL) = M₂(750 mL)
              M₂ = 0.0183 M

Draw two lewis structures for a compound with the formula c4h10. no atom bears a charge, and all carbon atoms have complete octets.

Answers

There are 2 possible isomers of C4H10. We have to show both. Below is the figure attached.

All the carbon and hydrogen has complete octet.

The two Lewis structure for a compound with the formula [tex]\rm C_4H_{10}[/tex] are shown below in the attached image.

In a Lewis structure, an element's chemical symbol shows its nucleus and inner electrons, while dots or lines represent valence electrons. Valence electrons are the atom's outermost electrons and are important in chemical bonding.

Shown below are the two Lewis structures of the compound with molecular formula [tex]\rm C_4H_{10}[/tex]. The two structures are the isomers of each other.The number of sigma bonds = 5, and number of pi bonds = 3 in the given compound.

Therefore, the two structure of [tex]\rm C_4H_{10}[/tex] are isomers of each other (refer to the attached image).

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How many picograms are in 1 Megagram?

Answers

1 x 10^18 picograms
I hope it helps you

Sodium carbonate (na2co3) is used to neutralize the sulfuric acid spill. how many kilograms of sodium carbonate must be added to neutralize 5.04Ã103 kg of sulfuric acid solution? express your answer with the appropriate units.

Answers

5.45 x 10^3 kg of sodium carbonate is needed to neutralize 5.04 kg of sulfuric acid. For this, I will assume you have pure H2SO4. So first, you need to calculate the molar mass of H2SO4 and Na2CO3. Lookup the atomic weights of all the elements involved. Atomic weight of Sodium = 22.989769 Atomic weight of Sulfur = 32.065 Atomic weight of Carbon = 12.0107 Atomic weight of Oxygen = 15.999 Atomic weight of Hydrogen = 1.00794 Molar mass of H2SO4 = 2 * 1.00794 + 32.065 + 4 * 15.999 = 98.07688 g/mol Molar mass of Na2CO3 = 2 * 22.989769 + 12.0107 + 3 * 15.999 = 105.987238 g/mol The balanced equation for the reaction of Na2CO3 with H2SO4 is Na2CO3 + H2SO4 => Na2SO4 + CO2 + H2O so for every mole of sulfuric acid to be neutralized, you need 1 mole of sodium carbonate. You can determine the number of moles of sulfuric acid you have and then calculate the mass of that many moles of sodium carbonate. But, there's an easier way. Just use the relative mass differences between sodium carbonate and sulfuric acid. So 105.987238 g/mol / 98.07688 g/mol = 1.080655 So that means for every kg of sulfuric acid, you need 1.080655 kg of sodium carbonate. Now do the multiplication. 5.04 x 10^3 kg * 1.080655 = 5.4465 x 10^3 kg. Since you only have 3 significant figures for your data, round the result to 3 significant figures, giving 5.45 x 10^3 kg

If a drop of blood is 0.05 mL, how many drops of blood are in a blood collection tube that holds 2 mL ?

Answers

Just divide the two (2 / 0.05) and you will get your answer; there are 40 drops of bloodin the collection tube.

Final answer:

To find out how many 0.05 mL drops of blood are in a 2 mL blood collection tube, divide the total volume by the volume of one drop. The calculation shows that there are 40 drops in a 2 mL tube.

Explanation:

To determine how many drops of blood are in a blood collection tube that holds 2 mL, we need to understand the relationship between the volume of the drops and the total volume that the tube can hold. Given that each drop of blood is 0.05 mL, we can calculate the number of drops in 2 mL by dividing the total volume by the volume of a single drop.

Here is the step-by-step calculation:

Determine the volume of one drop: 0.05 mL.

Determine the total volume of the collection tube: 2 mL.

Divide the total volume by the volume of one drop: 2 mL / 0.05 mL per drop.

Calculate the number of drops: 40 drops.

You are on an alien planet where the names for substances and the units of measures are very unfamiliar.

Nonetheless, you obtain 29 quibs of a substance called skvarnick.

You can trade this skvarnick for gold coins, but the vendors all measure skvarnick in units of sleps; not quibs.

10 quibs is equal to 4 sleps.

If you have 29 quibs of skvarnick, how many sleps do you have?

Round your answer to the nearest tenth (one decimal place).

Answers

so a quib seems to be a unit of measure

and we have another unit called sleps

so sleps:quibs is some ratio
oh nice, 10quibs:4sleps



yo have 29 quibs

easy

29quibs:?sleps=10quibs:4sleps
ratio and proportion
29/?=10/4
times both sides by 4?
(4)(29)=10?
116=10?
divide both sides by 10
11.6=?


you have 1 11.6 sleps


anohter way

10quibs=4sleps
divide by 10 both sides
1quib=4/10 sleps=2/5 sleps
times 29 both sides
29 quibs=(29*2)/5=58/5=11.6 sleps


yo has 11.6 sleps

Answer:

If we have 29 quibs of skvarnick they will be equal to 11.6 sleps.

Explanation:

Mass of a substance called skvarnick = 29 quibs

10 quibs is equal to 4 sleps. This means that 1 quibs is equal to 0.4 sleps.

10 quibs = 4 sleps

1 quibs = [tex]\frac{4}{10} sleps = 0.4 sleps[/tex]

Then 29 quibs will be:

[tex]29 quibs=29\times 0.4 sleps =11.6 sleps[/tex]

If we have 29 quibs of skvarnick they will be equal to 11.6 sleps.

How many neutrons do (k) potassium-39 and potassium-40 have, respectively?

Answers

Potassium’s atomic number in periodic table is 19, Potassium can only have a mass numbers of 41, 40 and 39. Potassium 39, 40, and 41 are all different isotopes of the element potassium. Each of the isotopes has 19 electrons and 19 protons but the number of neutrons vary. So, in your question Potassium-39 has twenty (20) neutrons, and potassium-40 has 21 neutrons.

blank is defined as the distance something travels divided by the time it takes

Answers

Your answer is speed.

The student's question asks about the definition of average speed, which is the distance traveled divided by the time it takes, and when direction is considered, this measure is referred to as average velocity.

The term the student is asking to define is average speed, which is a fundamental concept in physics. Average speed is calculated by dividing the total distance traveled by the total time it took to travel that distance. When the direction of travel is also taken into account, we refer to this as average velocity, which means that velocity equals displacement (change of position) divided by time.

In practice, if you were traveling in a car and you wanted to figure out your average speed, you would look at the odometer to see the distance covered and then divide by the number of hours or minutes it took to cover that distance.

To put it into symbols, for average speed s, if the total distance traveled is d and the total time taken is t, the average speed is expressed as:

s = d / t

Conversely, average velocity includes direction and is defined by the formula:

v = Δd / Δt

where Δd represents displacement and Δt represents the travel time.

Use the mass spectrum of rubidium to determine the atomic mass of rubidium.

Answers

The mass spectrum is a visual graph that shows a Intensity vs Mass plot, like that shown in the picture. This is an actual mass spectrometer diagram for Rubidium. The mass of the isotopes of the Rb element is along the x-axis, while the y-axis is the relative abundance. The atomic mass is determined to be:

∑(Mass×Intensity) = 85(1-0.38) + 87(0.38) = 85.76 amu
Final answer:

The atomic mass of rubidium can be determined using the mass spectrum of rubidium obtained from a mass spectrometer.

Explanation:

The atomic mass of rubidium can be determined using the mass spectrum of rubidium obtained from a mass spectrometer. In a mass spectrometer, a sample of rubidium is vaporized and exposed to high-energy electrons, causing the rubidium atoms to become charged ions. These ions are then accelerated into a magnetic field, and the extent to which they are deflected depends on their mass-to-charge ratios. By measuring the relative deflections of the ions and analyzing the mass spectrum, chemists can determine the mass of rubidium.

In 1928, 47.5 g of a new element was isolated from 660 kg of the ore molybdenite. the percent by mass of this element in the ore was:

Answers

To take the percent by mass of this element, we use the formula:

% mass = (mass of element / mass of ore) * 100%

% mass = (47.5 g / (660 kg * 1000 g / kg)) * 100*

% mass = 7.20 x 10^-3 %

Answer: The mass percent of element in the ore is 0.0072 %

Explanation:

To calculate the mass percentage of element in ore, we use the equation:

[tex]\text{Mass percent of element}=\frac{\text{Mass of element}}{\text{Mass of ore}}\times 100[/tex]

Mass of element = 47.5 g

Mass of ore = 660 kg = 660000 g    (Conversion factor:  1 kg = 1000 g)

Putting values in above equation, we get:

[tex]\text{Mass percent of element}=\frac{47.5g}{660000g}\times 100=0.0072\%[/tex]

Hence, the mass percent of element in the ore is 0.0072 %

Which statement is an opinion? Different varieties of fruit can have the same color. All raspberries are the same color. Fruit is good for breakfast. Fruit is a good source of nutrition.

Answers

fruit is good for breakfast
I believe it is c because fruit is good nutrition.
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