The most accurate number for a population in an area is measured by adding the individuals living or born in an area and subtract those who die. So, option C.
The amount of people living in a particular area is called population density.
The majority of the time, it applies to people, but occasionally it also does to other living things. It is a significant geographic term. Population density is the total number of people residing in a certain area per square kilometer, or other units of land area.
Demography is the statistical study of populations and how they change through time.
Population size, or the total number of people, and population density, or the number of people per unit of space or volume, are the two most important measurements of a population.
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Final answer:
The most accurate way to measure population size is by adding the number of births and individuals present, while subtracting the number of deaths (which corresponds to option C). Sampling techniques like quadrats and mark-recapture are often used due to the impracticality of counting all individuals.
Explanation:
In the context of estimating population size, the most accurate measurement for a population in an area would be to add the individuals living or born in an area and subtract those who die (Option C). This method accounts for natural population changes such as births and deaths.
Although counting all individuals would provide the most precise number, this is often not feasible. Instead, scientists often use sampling techniques to estimate population size. For stationary or slow-moving organisms, a quadrat can be used, while for mobile organisms, methods like mark and recapture might be employed.
Carrying capacity is a separate concept indicating how many individuals an area can sustain based on resources. Adjustments to population estimates may be necessary when populations near their carrying capacity, as density-dependent factors might affect population growth.
Part b suppose the magnitude of the gravitational force between two spherical objects is 2000 n when they are 100 km apart. what is the magnitude of the gravitational force fg between the objects if the distance between them is 150 km ? express your answer in newtons to three significant figures. hints fg = 889 n submitmy answersgive up correct significant figures feedback: your answer 890 n was either rounded differently or used a different number of significant figures than required for this part. part c what is the gravitational force fg between the two objects described in part b if the distance between them is only 50 km ?
(b). The gravitational force between the objects when they are 150 km apart is [tex]\boxed{889\,{\text{N}}}[/tex].
(c). The gravitational force between the objects when they are 50 km apart is [tex]\boxed{8000\,{\text{N}}}[/tex] .
Further Explanation:
The gravitational force of attraction between the two bodies is given by the Newton’s Law of Gravitation. According to Newton’s law of Gravitation, the gravitational force between two bodies is directly proportional to the product of their masses and inversely proportional to the square of the distance between them.
The gravitational force is expressed mathematically as:
[tex]F = \dfrac{{G{m_1}{m_2}}}{{{r^2}}}[/tex]
Here, [tex]G[/tex] is the gravitational constant, [tex]{m_1}[/tex] is the mass of first body, [tex]{m_2}[/tex] is the mass of second body and [tex]r[/tex] is the distance between two bodies.
For two bodies kept at a distance of 100 Km , the gravitational force of attraction is 2000 N.
Substitute 200 N for [tex]F[/tex] and 100 Km for r in above equation.
[tex]\begin{aligned}2000=\frac{{G{m_1}{m_2}}}{{{{\left( {100\times {{10}^3}}\right)}^2}}}\hfill\\G{m_1}{m_2} = 2\times {10^{13}}\hfill\\\end{aligned}[/tex]
Part (b):
Now, the force experienced by the bodies when they are 150 Km apart is:
[tex]F = \dfrac{{G{m_1}{m_2}}}{{\left( {150 \times {{10}^3}}\right)}}[/tex]
Substitute [tex]2 \times{10^8}[/tex] for [tex]G{m_1}{m_2}[/tex] in above equation.
[tex]\begin{aligned}F&=\frac{{2 \times {{10}^{13}}}}{{{{\left( {150 \times {{10}^3}}\right)}^2}}}\\&= 888.9\,{\text{N}}\\&\approx {\text{889}}\,{\text{N}}\\\end{aligned}[/tex]
Thus, the gravitational force between the objects when they are 150 Km apart is [tex]\boxed{889\,{\text{N}}}[/tex].
Part (c):
Now, the force experienced by the bodies when they are 50 km apart is:
[tex]F =\Dfrac{{G{m_1}{m_2}}}{{\left( {50 \times {{10}^3}}\right)}}[/tex]
Substitute [tex]2 \times {10^8}[/tex] for [tex]G{m_1}{m_2}[/tex] in above equation.
[tex]\begin{aligned}F &=\frac{{2 \times {{10}^{13}}}}{{{{\left({50 \times {{10}^3}}\right)}^2}}}\\&= 8000\,{\text{N}}\\\end{aligned}[/tex]
Thus, the gravitational force between the objects when they are 50 Km apart is [tex]\boxed{8000\,{\text{N}}}[/tex].
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Answer Details:
Grade: College
Subject: Physics
Chapter: Newton’s law of Gravitation
Keywords: Gravitation, newton’s law, force of attraction, 2000N, 100km, 150 km, 50 km, gravitational force, two spherical objects, 889 N, 8000 N.
Which of the advantages to social media as a new media could also be viewed as a disadvantage
Which of the following is an example of speed?
A) 8m/s
B) 7 m/s north
C) -3 m/s^2 east
D) 5 m/s^2 east
During cooling, the kinetic energy of the molecules falls. Why does this happen?
The correct answer of this question is : Molecular motion or vibration slows down
EXPLANATION :
The kinetic energy of the molecule depends on the molecular motion. Molecules might have different types of kinetic energy depending on the type of substance i.e solid,liquid or gases.
During cooling, we are reducing the temperature of the substance. Due to the decrease of temperature, the molecular speed is also decreased. It is so because the molecular speed is dependent on the temperature of the substance.
Hence, the vibration, rotation or translation motion of the molecule slows down during cooling, which in turn, decreases the kinetic energy of the molecule.
A basket of negligible weight hangs from a vertical spring scale of force constant 1500 n/m . if you suddenly put an adobe brick of mass 3.00 kg in the basket, find the maximum distance that the spring will stretch.
the work a force does on an object depends on
A rocket moves upward, starting from rest with an acceleration of +29.4 for 3.98 s. it runs out of fuel at the end of the 3.98 s but does not stop. m/s2 how high does it rise above the ground?
consider the motion of rocket until it runs out of fuel
v₀ = initial velocity = 0 m/s
v = final velocity when it runs out of fuel = ?
t = time after which fuel is finished = 3.98 sec
a = acceleration = 29.4 m/s²
Y₀ = height gained when the fuel is finished = ?
using the kinematics equation
v = v₀ + a t
v = 0 + (29.4) (3.98)
v = 117.01 m/s
using the equation
v² = v²₀ + 2 a Y₀
(117.01)² = 0² + 2 (29.4) Y₀
Y₀ = 232.85 m
consider the motion of rocket after fuel is finished till it reach the maximum height.
Y₀ = initial position = 232.85 m
Y = final position at maximum height
v₀ = initial velocity just after the fuel is finished = 117.01 m/s
v = final velocity after it reach the maximum height = 0 m/s
a = acceleration due to gravity = - 9.8 m/s²
using the kinematics equation
v² = v²₀ + 2 a (Y - Y₀)
inserting the values
0² = (117.01)² + 2 (- 9.8) (Y - 232.85)
Y = 931.4 m
The total distance traveled by the rocket above the ground is 931.4 m.
The given parameters;
acceleration of the rocket, a = 29.4 m/s²time of motion of the rock, t = 3.98 sThe distance traveled by the rocket during the 3.98 s is calculated as follows;
[tex]h_1 = v_0t + \frac{1}{2} at^2\\\\h_1 = 0 + \frac{1}{2} (29.4)(3.98)^2\\\\h_1 = 232.85 \ m[/tex]
The final velocity of the rocket after 3.98 s is calculated as follows;
[tex]v_i= v_0 + at\\\\v_i= 0 + (29.4 \times 3.98)\\\\v_i = 117.01 \ m/s[/tex]
"when the rocket runs out of fuel, it moves at a constant speed and the acceleration is zero. The rocket will be moving against gravity."
The distance traveled by the rocket when it runs out of fuel is calculated as follows;
[tex]v_f^2 = v_i^2 - 2gh_2[/tex]
where;
[tex]v_f[/tex] is the final velocity of the rocket at maximum height = 0[tex]0 = (117.01)^2 -2(9.8)h_2 \\\\2(9.8)h_2 = (117.01)^2\\\\h_2 = \frac{ (117.01)^2}{2(9.8)} \\\\h_2 = 698.54 \ m[/tex]
Total distance traveled by the rocket above the ground;
H = h₁ + h₂
H = 232.85 m + 698.54 m
H = 931.4 m
Thus, the total distance traveled by the rocket above the ground is 931.4 m.
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12 points. Change of state:
Identify the process that causes each change of sate describe below, Write the appropriate answer on the space provided.
_______a. an ice cube left in a freezer for a month becomes smaller.
_______b. drops of water appear on the side of a glass of ice water.
_______c. a rainy morning turns sunny, and puddles disappear from a sidewalk.
Is it possible to compress an ideal gas isothermally in an adiabatic piston–cylinder device? explain?
Encoding information occurs throughout?
Encoding is a cognitive process happening at all stages of learning - acquisition, storage, and retrieval. It's crucial for learning new information or skills and happens continuously.
Explanation:Encoding information occurs throughout the entire learning process. This cognitive process is essential in enabling us to acquire, store, and retrieve information. For example, while learning a new language, you first encode the foreign words and their meanings (acquisition), then store that encoded information in your memory (storage), and finally recall those words during a conversation (retrieval). Therefore, encoding is a continuous cycle that occurs throughout the process of learning any subject or skill.
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Why is the primary mirror in a telescope curved?
to magnify the image
to direct light rays to a focal point to intensify them
to change the direction of the rays
to bend the rays
to absorb extra light
Answer: to direct light rays to a focal point
Explanation:
A reflecting telescope uses curved mirror as primary and a plane mirror placed at an angle as secondary. A curved mirror is used as primary because this mirror collects the light from distant celestial object and converges its light at focus where the plane mirror is kept at an angle so that the reflected light is received by the eyepiece.
It is used as a curved primary mirror in a telescope because to direct light rays to a focal point.
What lenses are used in the telescope?For the construction of a telescope, the physicist Galileo used a lens of the converging type and a lens of the diverging type. In his telescope, the first lens, called the objective, formed a real image of the object in question.
A reflecting telescope uses curved mirror as primary because this mirror collects the light from distant celestial object and converges its light at focus where the plane mirror is kept at an angle so that the reflected light is received by the eyepiece.
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